What are the differences between an element, a compound, a homogeneous mixture, and a heterogeneous mixture?

26.71 g mass of tin would be required to completely react with 1.20 L of 0.750 M HBr.

What is mass ?

Mass is a measure of the amount of matter in an object or substance. It is often expressed in units of grams (g) or kilograms (kg). Mass is a fundamental property of matter and is different from weight, which is the force exerted on an object by gravity and varies depending on the object's location. Mass can be measured using a balance or scale, and is an important factor in many chemical calculations and experiments, such as determining the amount of reactants needed for a reaction or the concentration of a solution.

First, we need to determine the number of moles of HBr in the solution:

moles of HBr = Molarity x Volume

moles of HBr = 0.750 mol/L x 1.20 L

moles of HBr = 0.900 mol

According to the balanced chemical equation, 1 mole of Sn reacts with 4 moles of HBr to produce 1 mole of SnBr₄. Therefore, the number of moles of Sn required can be calculated as:

moles of Sn = (moles of HBr) / 4

moles of Sn = 0.900 mol / 4

moles of Sn = 0.225 mol

The molar mass of Sn is 118.71 g/mol, so the mass of Sn required can be calculated as:

mass of Sn = moles of Sn x molar mass of Sn

mass of Sn = 0.225 mol x 118.71 g/mol

mass of Sn = 26.71 g

Therefore, 26.71 g of tin would be required to completely react with 1.20 L of 0.750 M HBr.

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Complete question is:  26.71 g mass in grams of tin would be required to completely react with 1.20 L of 0.750 M HBr in the chemical reaction. Sn(s) + 4 HBr(aq) → SnBr₄ (aq) + 2 H₂ (g)

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Electrons

Explanation:

The are found in the cloud surrounding the nucleus, but not within

Answer:

electrons as they are found in the outer electron shells

Explanation:

The specific heat capacity of the zinc metal, given that 2.40×10¹ g of zinc metal at 2.10×10¹ °C is added to the water is 0.27 J/gºC

First, we shall obtain the heat absorbed by the water when the zinc metal was added. This is shown below:

Q = MCΔT

= 5.60×10¹ × 4.184 × -2.1

= -492.0384 J

Now, we shall determine the specific heat capacity of the zinc metal. Details below:

Q = MCΔT

492.0384 = 2.40×10¹ × C × 76

492.0384 = 1824 × C

Divide both sides by 1824

C = 492.0384 / 1824

= 0.27 J/gºC

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The options of the question is not given so the options are;

(1) Mn(s)

(2) Cu(s)

(3) Ni(s)

(4) Ba(s)

Answer: Mn(s)

Explanation:

The spontaneous reaction depends on the Eo value. The positive Eo value are spontaneous and the negative Eo values are not spontaneous.

so, here the Eo values are:

Eo Zn2+/Zn = -0.763v

Eo Mg2+/Mg = 2.37v

Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn

=  -0.763 - (-1.18)

 = 0.417v

Whereas, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn

=  -2.37 - (-1.18) = -1.19v

Thus, Mn(s) metal will spontaneously react because it has a positive  Eo value and  Zn2+(aq), but will not spontaneously react with Mg2+(aq) because it has negative Eo value.

The proper numbering is 4, 2, 1, and 3.

The following sequence of actions can be used to describe how an undersea sedimentary rock is formed.

Sedimentary Rock

In a basin, sediments and animal skeletons start to accumulate.

The material that has been deposited starts to become bound together by a glue ingredient brought in by running water, such as calcite or clay. The deposits start to become harder.

The deposits eventually transform into rock that is solid and hard. The new rock is a mixture of several organic and inorganic components.

Existing rocks become sediments as a result of weathering.

What causes sedimentary rocks to form?

Sedimentary rocks are formed when previously existing rocks or pieces of extinct animals accumulate on the surface of the Earth. Sediment that has been buried deeply becomes compacted

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The answer is 3,294,000 m/h.

Explanation: There are 3,600 seconds in an hour, so you would multiply 915 by 3,600.

To convert the speed from m/s to mph, multiply the speed in m/s by the conversion factor of 2.23694.

To convert the speed from meters per second (m/s) to miles per hour (mph), you can use the conversion factor of 2.23694. Multiply the speed in m/s by this conversion factor to get the speed in mph.

Let's calculate the speed in mph:

Speed in m/s = 915.0 m/s
Conversion factor = 2.23694

Speed in mph = 915.0 m/s x 2.23694 = 2044.3437 mph

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The Volume of Stomach acid HCl present in 0.28 mg is 0.076 mL.

Molarity can be defined as the number of Moles present in one liter volume of the solution. It is given as :

Molarity = No. Of Moles / Volume (in L)

No. of Moles =Given Mass / Molar Mass

Here, We are Given, M = 0.1 and mass of HCl = 0.28 mg

We will find no. of moles in 0.28 mg HCl, it will be

Moles = Given Mass (in gram) / Molar Mass

Moles=  \(\frac{0.28 X 10^{-3} }{36.44}\)           \((1 mg =10^{-3}g)\) \((Molar Mass of HCl=36.44 g)\)

Moles = \(7.68 X 10^{-6}\)

Now we will calculate the Volume present in \(7.68 X 10^{-6}\) moles

Molarity = No. Of Moles / Volume (in L)

\(0.1 =\frac{7.68 X 10^{-6} X 10^{3} }{V(in mL)}\)

\(V =7.68 X10^{-4} ( mL)\)

Volume = 0.076 mL.

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Answer:

Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + 3 O₂(g)

Explanation:

Let's consider the unbalanced equation for the decomposition reaction of solid barium nitrate.

Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + O₂(g)

We can see that Ba atoms and N atoms are balanced, but we have 6 O atoms to the left side and 2 O atoms to the right. We can get the balanced equation by multiplying O₂(g) by 3.

Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + 3 O₂(g)

At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.

To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.

First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water

Maximum amount of KNO₃ that can dissolve

= 65 g/100 g x 200 g

= 130 g

This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.

Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.

The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.

To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃

Amount of KNO₃ in 110 g of water

= 65 g/100 g x 110 g

= 71.5 g

This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.

Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.

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Answer:

Yes, Because the dishes that are unwashed have the most bacteria while the soap & water dish has the least bacteria.

Explanation:

Hope this help

Answer:

the correct answer is c two molecules of octane

They are life cycle differences that protect the offspring and help them to survive. The correct option is C.

Some organisms have life cycle features that ensure that their population is perpetuated in subsequent generations.

Such features include ensuring that propagules are only released when they are mature and making sure that eggs are hatched and offspring become viable before they are allowed to move to the environment.

These actions will make sure that the propagules of offspring have what it takes to survive in their new environment.

In other words, these life cycle features are embedded in the genome of organisms as a way to survive the environment.

Thus, the features of the Himalayan balsam plant and that of the Surinam toad are more or less targeted toward the same thing - the survival of their offspring.

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Answer: Option (C) is correct, They are life cycle differences that protect the offspring and help them to survive.

Explanation: Hope it helps!

Good luck!!!

Answer:

In paper chromatography, the wet moving edge of the solvent that progresses along the surface where the separation of the mixture is occurring.

Explanation:

I hope this helps and pls mark me brainliest :)

Answer:

hope it helps..

Explanation:

'Motile' (or moving) cilia are found in the lungs, respiratory tract and middle ear. ... These cilia have a rhythmic waving or beating motion. They work, for instance, to keep the airways clear of mucus and dirt, allowing us to breathe easily and without irritation.

Answer: to keep airway clear of mucus and dirt allowing us to breathe easy

Explanation:

Answer:

Cu²⁺(aq) + S²(aq)⁻ →  CuS(s)

Molarity = 0.88 M

Explanation:

Chemical equation:

Cu(NO₃)₂(aq) + Li₂S(aq)  →  2LiNO₃(aq) + CuS(s)

Ionic equation:

Cu²⁺(aq) + 2NO₃(aq)⁻ + 2Li⁺(aq) + S²(aq)⁻     →   2Li⁺(aq) + 2NO₃⁻(aq)  + CuS(s)

Net ionic equation:

Cu²⁺(aq) + S²(aq)⁻ →  CuS(s)

2)

Given data:

Mass of KBr = 170 g

Volume of solution = 1625 mL (1625 /1000 = 1.625 L)

Molarity of solution = ?

Solution:

First of all we will calculate the number of moles of KBr.

Number of moles = mass/molar mass

Number of moles = 170 g/ 119 g/mol

Number of moles = 1.43 mol

Molarity of solution:

Molarity = number of moles / Volume of solution in L

Now we will put the values.

Molarity = 1.43 mol/ 1.625 L

Molarity = 0.88 M

The expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P\(r^4\))/(8ηl) ∆t.

To derive an expression for the volume of liquid flowing per unit time through a cylindrical tube, we can apply the principles of fluid mechanics, considering the pressure gradient, viscosity coefficient, and tube radius.

The volume flow rate (Q) is defined as the volume of fluid passing through a cross-sectional area per unit time. In this case, we will consider the flow through a cylindrical tube of radius r and length l.

The Hagen-Poiseuille equation describes the flow rate in terms of the pressure gradient (∆P), viscosity coefficient (η), and tube dimensions:

Q = (π∆P \(r^4\))/(8ηl)

where k = π/8 is a constant.

To derive the expression for the volume of liquid flowing per unit time (∆V/∆t), we need to multiply the flow rate (Q) by the time interval (∆t):

∆V/∆t = Q ∆t

= (π∆P \(r^4\))/(8ηl) ∆t

Now, if we assume a constant pressure difference (∆P) and substitute k = π/8, the expression becomes:

∆V/∆t = (k∆P \(r^4\))/(ηl) ∆t

Simplifying further:

∆V/∆t = (π∆P\(r^4\))/(8ηl) ∆t

So, the expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P \(r^4\))/(8ηl) ∆t.

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Answer:

1. To find the pH of a 0.1 M solution of HNO₂, we first need to calculate the concentration of H+ ions in the solution using the dissociation constant K.

HNO₂ ⇌ H+ + NO₂-

K = [H+][NO₂-]/[HNO₂]

We know that the initial concentration of HNO₂ is 0.1 M, and that the dissociation constant K is 4.5×10^-4. Let x be the concentration of H+ ions in the solution.

K = [H+][NO₂-]/[HNO₂]

4.5×10^-4 = x(0.1-x)/0.1

Simplifying the equation gives us:

x^2 - 4.5×10^-5x + 4.5×10^-6 = 0

Using the quadratic formula, we get:

x = (4.5×10^-5 ± √(4.5×10^-5 - 4(1)(4.5×10^-6))) / 2(1)

x = 1.5×10^-3 or 3×10^-4

Since the concentration of H+ ions must be less than 0.1 M, we reject the larger value and take x = 3×10^-4 M.

To calculate the pH, we use the formula:

pH = -log[H+]

pH = -log(3×10^-4) = 3.52

2. To find the pH of a 0.05 M solution of NHẠOH, we first need to calculate the concentration of OH- ions in the solution using the dissociation constant K.

NHẠOH ⇌ NH₂- + OH-

K = [NH₂-][OH-]/[NHẠOH]

We know that the initial concentration of NHẠOH is 0.05 M, and that the dissociation constant K is 1.8×10^5. Let x be the concentration of OH- ions in the solution.

K = [NH₂-][OH-]/[NHẠOH]

1.8×10^5 = x(0.05-x)/0.05

Simplifying the equation gives us:

x^2 - 1.8×10^-3x + 9×10^-6 = 0

Using the quadratic formula, we get:

x = (1.8×10^-3 ± √(1.8×10^-3 - 4(1)(9×10^-6))) / 2(1)

x = 9.0×10^-3 or 1×10^-3

Since the concentration of OH- ions must be less than 0.05 M, we reject the larger value and take x = 1×10^-3 M.

To calculate the pOH, we use the formula:

pOH = -log[OH-]

pOH = -log(1×10^-3) = 3

To calculate the pH, we use the formula:

pH + pOH = 14

pH = 14 - pOH = 11

3. To find the pH of a 0.3 M solution of H₂S, we first need to calculate the concentration of H+ ions in the solution using the dissociation constant K.

H₂S ⇌ H+ + HS-

K = [H+][HS-]/[H₂S]

We know that the initial concentration of H₂S is 0.3 M, and that the dissociation constant K is 1.0×10^-7. Let

Explanation:

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Hydrated ionic compounds have water molecules incorporated into their structure. Heating removed the volatile component, water, from the Epsom salt sample, which is magnesium sulfate.

Hydrated ionic compounds have water molecules incorporated into their structure. In the case of Epsom salt, it is magnesium sulfate heptahydrate which means there are seven water molecules incorporated in it. On heating the Epsom salt sample, the volatile component that is removed from it is water.

An example of a hydrated ionic compound is magnesium sulfate heptahydrate (\(MgSO_{4} 7H_{2} O\)). Heating the Epsom salt sample will remove the water molecules from the hydrated compound, resulting in the formation of an anhydrous ionic compound, \(MgSO_{4}\).

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There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.

First, we need to find the mass of water in the bottle:

Mass = Density * Volume

Mass = 0.967 g/mL * 499.8 mL = 483.9 g

Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Moles = Mass / Molar mass

Moles = 483.9 g / 18.015 g/mol = 26.88 mol

Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules = Moles * Avogadro's number

Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules

Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

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Answer: (e) the number of neutrons in the nucleus of an atom of the element

Explanation: The given information tells us how many electrons the atom has, and since the atom is neutral then the atomic number is the same as the total number of electrons. This rules out answer a. It also tells us that the element has a full set of valence electrons, making it a noble gas and ruling out answer b because noble gasses are known to act differently to other elements. c is ruled out because we are given the number of electrons, allowing us to figure out how many electrons are in s orbitals. The same goes for option d. This leaves option e. e is the correct answer because the number of neutrons in the nucleus of an atom does not affect the number of electrons or the charge of the atom, meaning we have no way of finding it.

The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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The most reactive element based on the given data among the given options is option c) Element J.  

This can be determined based on their placement on the periodic table. The reactivity of an element is dependent on its position on the periodic table, particularly its electron configuration and the number of valence electrons it has. For instance, elements located in the top left corner of the periodic table are typically the most reactive.

They have fewer electrons in their outermost shell and have a tendency to lose them or combine with other elements in order to obtain a full outer shell or achieve stability.In this case, Element J is most likely located in the far left of the periodic table, most likely in the alkali metals group, which contains some of the most reactive metals.

Alkali metals are highly reactive because they only have one valence electron, making it easy for them to give it up and form positive ions. As a result, Element J is the most reactive among the given elements.The correct answer is c.

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Explanation:

basically first you have to understand these definitions

*mass number ( e.g. where it says oxygen 16 or 17 - it's basically that number at the top)

mass number is the 'number of protons + number of neutrons'

now this will help you do the first question

if you do 16 -8 = 8 ( that's how she got 8 neutrons)

another thing you need to know is that all the time the number of protons = the number of electrons ( they are the same)

this will help you answer table 2

for fluorine it says there are 9 electrons, you automatically have to think 9 electrons means 9 protons too, ( I think she has got that wrong, it's supposed to be 9 protons not 19)

if you have 9 protons and the given 10 neutrons and add them together you will get the mass number which is supposed to be 19

then if you try out the same rules for argon you will see they work - the number of electrons and protons are same and when you find out the protons, you can just take that away from the mass number ( which is number of protons + neutrons) to get just the number of neutrons.

Hope this helps you :)

According to reaction

Mols of H_2O

\(\\ \tt\rightarrowtail 4.35(0.6)\)

\(\\ \tt\rightarrowtail 2.61mol\)

According to law of conservation of mass, 4.35 moles of water are produced when 2.80 moles of hydrogen  and 1.55 moles of oxygen react.

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.As 2.80 moles of hydrogen react with 1.55 moles of oxygen 2.80+1.55=4.35 moles of water are produced.

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Explanation:

If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.

- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B

Answer:

9.93712g

Explanation:

You have 10mL of water at 33 degrees, so you want to look at the density of water at 33 degrees. Then you multiply that density (.993712) by 10 and the mL cancel out and you are left with 9.93712g.

Hope this helps!

Answer: B) 2.17 moles P

Explanation:

To determine the number of moles of Phosphorous needed to completely react with 3.25 moles of Calcium, we need to look at the balanced chemical equation for the reaction:

2 P + 3 Ca → Ca3P2

From the equation, we see that two moles of Phosphorous are needed for every three moles of Calcium. To calculate the number of moles of Phosphorous needed for 3.25 moles of Calcium, we divide the number of moles of Calcium by 3 and multiply by 2:

3.25 moles Ca / 3 moles Ca/2 moles P * 2 moles P/1 mole Ca = 2.17 moles P

So, 2.17 moles of Phosphorous are needed to completely react with 3.25 moles of Calcium.