what are the products of SeCl6 + O2 = SeO2 + 3Cl2

Answer:

1.3 Pa

Explanation:

from general gas equation

p1v1/TO =P2V2/T2

The anthracite coal price per MMBtu is $3.00/MMBtu. Therefore, the correct option is A.

The heat content of anthracite coal is 15,000 BTU/pound. The question requires the conversion of an anthracite coal price of $90/ton to $/MMBtu. Let us use the given data to solve the problem. 1 ton equals 2000 pounds (lb). Hence,

2000 lb of anthracite coal has a heat content of 2000 lb x 15,000 BTU/lb = 30,000,000 BTU

Thus, the price per MMBtu can be calculated by the given formula;

Price per MMBtu = Price per ton / (BTUs per ton / MMBTUs per ton)

Price per MMBtu = $90 / (30,000,000 / 1,000,000)

Price per MMBtu = $90 / 30

Price per MMBtu = $3.00/MMBtu

Thus, the price per MMBtu of anthracite coal is $3.00/MMBtu. Therefore, the correct answer is option A: $3.00/MMBtu.

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Answer:

the intercepts of a graph are point at which the graph crosses the axes

R(F) = 4F - 160

a. R¹(P) represents the temperature at which a cricket chirps at a rate of P chirps per minute.

b. R(60) refers to the chirping rate of the cricket when the temperature is 60 degrees Fahrenheit, while R¹(60) represents the temperature at which the cricket chirps at a rate of 60 chirps per minute.

The equation R(F) = 4F - 160 represents the relationship between the temperature of the cricket's environment (F) and its chirping rate (R). By plugging in different temperature values, we can determine the corresponding chirping rate.

For example, when we calculate R(60), we find the chirping rate at 60 degrees Fahrenheit.

In this case, R(60) = 4(60) - 160 = 240 - 160 = 80 chirps per minute.

On the other hand, when we calculate R¹(60), we are looking for the temperature at which the cricket chirps at a rate of 60 chirps per minute. Solving the equation 60 = 4F - 160, we find F = 70 degrees Fahrenheit. Therefore, R¹(60) = 70.

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Answer:

10m

Explanation:

time is at the end of the 10 yea

Answer:

Explanation:

To determine the height of the building, we can use the kinematic equation for vertical motion:

h = v₀t + (1/2)gt²

Where:

h is the height of the building

v₀ is the initial velocity of the ball (25 m/s)

t is the time taken for the ball to reach the ground (10 seconds)

g is the acceleration due to gravity (approximately 9.8 m/s²)

Plugging in the values:

h = (25 m/s)(10 s) + (1/2)(9.8 m/s²)(10 s)²

h = 250 m + (1/2)(9.8 m/s²)(100 s²)

h = 250 m + 490 m

h = 740 m

Therefore, the height of the building is approximately 740 meters.

Hope it helps!! :))

Answer:

While measuring the length of a box he should use centimetres if he is using the metric system.

The weight of the box is 120N and work done is 432J.

We know that weight is just the force.

Weight  = F = mg

where, m = mass of the body = 12kg

            g = acceleration due to gravity = 10 m/s^2

Putting these values in above equation we get : F = 120 N

So, the weight of the box is 120N.

We know that work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

Now Work done by an object is given by : W = F.d

where,

F = force acting

d = displacement = 3.6 m

Putting these values in above equation we get: W = 120 * 3.6 = 432J

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Answer:

force increases

Explanation:

Newton's law of universal gravitation states that the force of attraction (gravity) acting between the Earth and all physical objects is directly proportional to the Earth's mass, directly proportional to the physical object's mass and inversely proportional to the square of the distance separating the Earth's center and that physical object.

According to Newton’s law of universal gravitation, as the mass or one or both bodies increases, the force of attraction between the bodies increases.

Mathematically, this is given by the Newton's Second Law of Motion;

Force = mass * acceleration.

Answer: Ernest Rutherford's

Answer:

\(d=0.59m\)

Explanation:

From the question we are told that:

Mass \(m=67.3 kg\)

Spring constant \(\mu=1.23 * 10^3 N/m\)

Fall Height \(h=0.921m\)

Generally the Energy theorem equation for momentum is mathematically given by

Change in KE=Work done by gravity + work done by spring

\(0=mg*(h + d) - \frac{\mu d^2}{2}\)

\(0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}\)

\(0=608.1-660.213d-615d^2\)

Solving Quadratic equation

\(d=0.59m\)

Answer:

100.390407

Explanation:

To find acceleration, you would use the formula a=f/m (acceleration equals force divided by mass) and then once you enter those numbers in the formula, a=180/1.793. Then you divide 180 divided by 1.793 which gets you an answer of 100.390407.

Answer: An object is in motion when its distance from another object is changing . A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving

Explanation:

The point in the cardiac cycle where the SA Node fires is located between numbers E) 1 and 2 on the given EKG.

The SA Node, or sinoatrial node, is responsible for initiating the cardiac cycle by generating an electrical impulse that spreads through the atria, causing them to contract. This electrical activity is recorded on an EKG as the P wave, which appears just before the QRS complex.

In the given EKG, the P wave is located between numbers 1 and 2, indicating the firing of the SA Node and the onset of atrial depolarization.

Therefore, the correct answer is E) 1 and 2.

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Answer:

\(F_r \approx 978.3N\)

\(\theta =44 \textdegree\)

Explanation:

From the question we are told that

Connie pulls with a force of \(F_c=200 N\)

At an angle \(\theta _c=20 \textdegree\)

Randolph pulls with a force of \(F_R=800 N\)

At an angle \(\theta _R=50 \textdegree\)

Generally the horizontal axis  can mathematically be represented as

\(f_x=f_ccos\theta _c+F_Rcos\theta _R\)

\(f_x=200*cos20+800*cos50\)

\(f_x=702.2N\)

Generally the vertical axis  can mathematically be represented as

\(f_y=f_csin\theta _c+F_Rsin\theta _R\)

\(f_y=200*sin20+800*sin50\)

\(f_y=681.24N\)

Generally the resultant force \(F_r\) is mathematically  given by

\(F_r=\sqrt{f_x^2+f_y^2}\)

\(F_r=\sqrt{702.1686119^2+681.2395832^2}\)

\(F_r=978.3230731N\)

\(F_r \approx 978.3N\)

Generally the Direction \(\theta\) of force is mathematically given by

\(\theta =tan^-^1(\frac{f_c}{f_y})\)

\(\theta =tan^-^1(\frac{681.23}{702.16})\)

\(\theta =44 \textdegree\)

Disk 2 has a greater friction force acting upon it as it rolls.

What is Force ?

Any interaction that, when unopposed, alters an object's motion is referred to as a force. An object with mass can change its velocity, or accelerate, as a result of a force.

What is friction ?

Walking - The frictional force is what keeps our feet firmly planted on the ground while we walk on the ground or the floor. Because there is less friction on icy or slippery surfaces, we frequently slip there.

Therefore, Disk 2 has a greater friction force acting upon it as it rolls.

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If the load applied in part b is not large enough to cause plastic deformation, then the bar will return to its original shape and length when the load is removed, and there will be no permanent change in length.

Without knowing the specific material properties of the bar in question, it is difficult to determine the exact permanent change in length that will occur when the bar is unloaded.

However, we can make some general statements based on the behavior of materials under load.

When a material is loaded, it experiences elastic deformation, which means that it deforms under load but returns to its original shape when the load is removed.

However, if the load is large enough, the material may experience plastic deformation, which means that it deforms under load and does not return to its original shape when the load is removed.

Plastic deformation is usually irreversible and results in a permanent change in the shape or dimensions of the material.

In the case of the bar in question, if the load applied in part b is large enough to cause plastic deformation, the bar will experience a permanent change in length even after the load is removed.

The magnitude of this permanent change in length will depend on the specific material properties of the bar and the magnitude of the load applied.

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Answer:

The screw gauge is an instrument used for measuring accurately the diameter of a thin wire or the thickness of a sheet of metal. It consists of a U-shaped frame fitted with a screwed spindle which is attached to a thimble.

Explanation:

Measure the length of the coil with the help of a meter scale. The thickness of the wire can be found by dividing the length of the coil by the number of turns. Measure the diameter with callipers. Place an electrical wire between the jaws of a set of Vernier callipers. Slide the movable jaw around the cable without compressing the insulation and read the measurement where the line from the moving indicator meets the stationary scale for a diameter.

With the use of formula, the frequency of the tuning fork is 13.6 Hz

A tuning fork can be used to determine the speed of sound in air using a resonance tube. The apparatus needed for this experiment are;

The experiment begins when a student holds a pipe vertically, with one end submerged in water while the opposite end is out in the air. Just above the pipe, the student holds a tuning fork. The student carefully moves the pipe up and down, varying the level of water inside of it, until they detect a strong resonant sound.

Given that the student detects this sound when the length of air inside of the pipe measures 56.25 cm, and then again when the length is 68.75 cm. Taking the speed of sound in air to be of 340. m s–1.

The parameters given are:

\(L_{1}\) = 56.25 cm

\(L_{2}\) = 68.75 cm

V = 340 m/s

The formula to use for this question is

V = 2F( \(L_{2}\) - \(L_{1}\) )

340 = 2F (68.75 - 56.25)

340 = 2 x 12.5 x F

340 = 25F

F = 340/25

F = 13.6 Hz

Therefore, the frequency of the tuning fork is 13.6 Hz

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s = voff^2 / (2 * a) = voff^2 / [2 * ((Fthrust / m) - (μr * g))], this is the equation for the minimum length of the airstrip.

A. To determine the minimum length of the airstrip needed for the plane to get airborne, we must use the forces acting on the plane and the given speed of takeoff.

off = takeoff speed of the plane.

θ = angle of the slope

Fthrust = forward force exerted by the engine.

μr = coefficient of rolling resistance.

m = mass of the plane.

Let's make a sketch.

Position, velocity, and time at two locations are represented by symbols.

B. Free-body diagrams for the x and y axes of the plane, as it moves along the airstrip, are shown below.
Since there is no vertical acceleration, there are no vertical forces acting on the plane, so the weight is equal to the normal force acting upwards, and friction is the force acting in the opposite direction to the plane's direction of motion.

C. Newton's second law in the x and y direction can be written as:

Fx = max

Fy = may

We'll substitute all known quantities and relationships.

We know that frictional force is μr multiplied by the normal force. So,

Friction = μr * N = μr * m * g

For the y direction:

Fy = may = 0,

so

N - mg = 0N = mg

For the x direction:

Fx = max

Fthrust - friction = max

Fthrust - μr * m * g = max

D. We can calculate the acceleration of the plane using the x direction equation from step C:

a = (Fthrust - μr * m * g) / ma = (Fthrust / m) - (μr * g)

Yes, the acceleration is constant, since the thrust is constant and the frictional force is proportional to the normal force, which is constant as there is no vertical acceleration.

Therefore, the net force acting on the plane is constant, and so is the acceleration.

E. For the minimum length, we can use the one-dimensional kinematics equation:

v^2 = u^2 + 2as,

where u = 0 (initial velocity), a is the constant acceleration we found in part D, and s is the distance required.

Let's substitute: voff^2 = 2 * a * s

We need to solve for s,

so:s = voff^2 / (2 * a) = voff^2 / [2 * ((Fthrust / m) - (μr * g))]

This is the equation for the minimum length of the airstrip.

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Answer:

49,000 Pa

49 kPa

Explanation:

P (pressure)= hρg, where h= height, ρ=density, and g= acceleration due to gravity.

50 m * 1000kg/m³ * 9.8 m/s²

=49,000 kg*m⁻¹s⁻² OR 49,000 Pa OR 49 kPa

The maximum tension the string can withstand is approximately 50.265 Newtons.

To find the maximum tension the string can withstand, we can use the centripetal force equation:

F = \((m * v^2) / r\)

where F is the tension in the string, m is the mass, v is the linear velocity, and r is the radius of the circular path.

First, we need to find the linear velocity (v) of the mass. The linear velocity is given by the formula:

v = (2πr) / T

where T is the period of revolution.

Given that the period of revolution is 0.25 seconds and the radius of the circular path is 40 cm (0.4 m), we can calculate the linear velocity:

v = (2π * 0.4 m) / 0.25 s

v ≈ 10.053 m/s

Now, we can substitute the values into the centripetal force equation:

F =\((m * v^2) / r\)

Given that the mass is 200 grams (0.2 kg) and the radius is 40 cm (0.4 m), we can calculate the maximum tension:

F = \((0.2 kg * (10.053 m/s)^2) / 0.4 m\)

F ≈ 50.265 N

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The average velocity is 1 km/hr.

Velocity is the speed of a body in a given direction.

Velocity can also defined as the displacement of body with time.

The average velocity will be be the ratio of the total displacement with time.

Taking the right direction as positive and the direction to the left as negative:

displacement of the body = (4.0 - 2.5) km

displacement of the body = 1.5 km

Average velocity = 1.5 km/ 1/5 hours

Average velocity = 1 km/hr

In conclusion, the average velocity is obtained from the displacement and time taken.

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Answer:

Energy is: the ability to do work

The formula for energy is: power x time = energy

Explanation:

Hope this helps (there isn't really an explanation)

TRUE

Explanation:

BECAUSE IT IS LIKE THE KEY WORD IN THAT SENTENCE.

The final parameters of the problem are the conservation of charge and the definition of capacitance.

According to the conservation of charge, the total charge in the system before and after the capacitors are connected in parallel must be the same. Therefore, the total charge stored by the capacitors is the same before and after the connection.

According to the definition of capacitance, the capacitance of the equivalent parallel combination of the capacitors is the sum of the individual capacitances. Therefore, the final capacitance of the parallel combination can be calculated as the sum of the capacitances of the individual capacitors.

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The electrically charged particles that produce electric currents and therefore magnetic fields when they move inside Uranus and Neptune are primarily ionized gases, specifically a mix of hydrogen, helium, and methane ions.

Both Uranus and Neptune have magnetic fields that are tilted with respect to their rotation axes, and they also exhibit periodic variations in their magnetic fields. These phenomena are thought to be caused by the motion of electrically charged particles in their interiors.

The interiors of Uranus and Neptune are believed to consist of a rocky core surrounded by layers of liquid water, methane, and ammonia. Above these layers lies a thick atmosphere consisting mainly of hydrogen and helium with traces of methane.

Due to the extreme pressure and temperature within their interiors, the hydrogen and methane in these atmospheres become ionized, meaning they lose or gain electrons and become electrically charged. These ionized gases then move and flow, creating electric currents and magnetic fields.

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Answer:

because of the gravity of the earth