What are the roots?
f(x) = x^2 - 2x – 35

Answer:

80%

Step-by-step explanation:

Answer:

80

Step-by-step explanation:

The proportion equivalent with Two-thirds would be 6/9.

Since we know that the proportion is a fraction of a total amount, and the measures are related using a rule of three.

The relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

We are given that the  proportion with Two-thirds

If you actually divide it’ll make since , so first  we want to divide the 2 , then you want to multiply the third of the two

2/3 x 3/3

6/9

thus, the answer will be 6/9.

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Answer:

K5.60.

Step-by-step explanation:

Answer:

ⁱ ʰᵒᵖᵉ ᵗʰⁱˢ ʷᵒᵘˡᵈ ʰᵉˡᵖ ʸᵒᵘ ᵗᵒ ᵍᵉᵗ ʳᵉᵃˡ ᵃⁿˢʷᵉʳ...

It would take Fran and Denise (working together) approximately \(\frac{24}{7}\) hours to paint the living room.

To solve this problem, we can use the concept of "work rates."

Let's find out how much work Fran and Denise can do individually in one hour.

If Fran takes 6 hours to paint the living room alone, her work rate is \(\frac{1}{6}\) of the room per hour \((\frac{1 room}{6 hours } = \frac{1}{6}room/hour )\).

Similarly, if Denise takes 8 hours to paint the living room alone, her work rate is \(\frac{1}{8}\) of the room per hour \((\frac{1 room}{8 hours } =\frac{1}{8}room/hour )\).

When they work together, their work rates are additive.

So, their combined work rate would be:

\(\frac{1}{6} room/hour+\frac{1}{8} room/hour\)

\(=(\frac{4}{24} )room/hour + (\frac{3}{24} )room/hour\)

\(=\frac{7}{24} room/hour\)

This means that working together, Fran and Denise can paint \(\frac{7}{24}\) of the living room in one hour.

To determine the total time required for them to paint the entire room, we can invert their combined work rate:

\(\frac{(1 room) }{(\frac{7}{24}room/hour) } =\frac{24}{7}hour\)

Therefore, it would take Fran and Denise (working together) approximately \(\frac{24}{7}\) hours to paint the living room.

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Answer:

B. 9\(\frac{1}{2}\)

Step-by-step explanation:

Rewriting the two fractions in the expression:

=\(\frac{[(8)(2)]+1}{8} + \frac{[(8)(7)]+3}{8}\)

=\(\frac{17}{8} + \frac{59}{8}\)

Since the denominators of both the fractions is the same, then the denominator of the resulting simplified fraction will also be the same. In addition, everything written in the numerator level will be copied down as it is:

=\(\frac{17 + 59}{8}\)

=\(\frac{76}{8}\)

Divide the numerator and denominator by the Highest Common Factor '4':

= \(\frac{19}{2}\)

Apply Long Division since:

Choose the highest quotient to be multiplied by 2 to give a number closest to 19 but still less than 19. The quotient turns out to be 9. The remainder is 1

∴ Sum of the expression = 9\(\frac{1}{2}\)

The value of t₄ in the arithmetic sequence is 103/8.To determine the value of t₄ in an arithmetic sequence, we need to use the given information that t₁ = 11 (the first term of the sequence) and S₉ = 243 (the sum of the first 9 terms of the sequence).

We know that the formula for the sum of an arithmetic sequence is Sₙ = (n/2)(2a + (n-1)d), where Sₙ is the sum, a is the first term, n is the number of terms, and d is the common difference.

From the given information, we have S₉ = 243, a = 11, and n = 9. Plugging these values into the sum formula, we can solve for d:

243 = (9/2)(2(11) + (9-1)d)

243 = 9(22 + 8d)

243 = 198 + 72d

45 = 72d

d = 45/72 = 5/8

Now that we have the common difference, we can find t₄ using the formula for the nth term of an arithmetic sequence:

tₙ = a + (n-1)d

t₄ = 11 + (4-1)(5/8)

t₄ = 11 + 3(5/8)

t₄ = 11 + 15/8

t₄ = 88/8 + 15/8

t₄ = 103/8

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Answer:

Probability = number of yellow jellybeans / total number of jellybeans

=  24 / 80

=  3/10.

Step-by-step explanation:

Answer:

15%

Step-by-step explanation:

There are 80 total jelly beans, as stated in the question. Therefore, there are 80 "Total Events".

There are 12 yellow jellybeans in the bowl. Therefore, there are 12 preferred events, since the question asks the probability of pulling one yellow jellybean randomly.

\(\frac{\text{Preferred Events}}{\text {Total Events}} =\frac{12}{80}\)

I do not know what form the question prefers, so I did the probability in all forms.

Divide 12 by 80.

\(12/80 = 0.15\)

There is a 0.15 chance that Ricky would pull out a yellow bean.

Divide 12 by 80.

\(12/80=0.15\)

Convert into a percent. Multiply 0.15 by 100.

\(0.15*100=15\)

There is a 15% chance that Ricky would pull out a yellow bean.

Simplify 12/80.

\(\frac{12/2}{80/2} =\frac{6/2}{40/2} =\frac{3}{20}\)

There is a \(\frac{3}{20}\) chance that Ricky would pull out a yellow bean.

Brainilest Appreciated!

5 servings = 2 cups of milk

1 serving = 2/5 cups of milk

do not worry about the fraction of milk for now!!

8 servings = 2/5 × 8 cups of milk

= 3.2 cups of milk

= 3 cups (rounded down)

The expenditure of Saturday is Rs 45 /-

Given that,

Average expenditure = 111 /-

Sunday, Monday, Tuesday, Wednesday, Thursday and Friday are 140/-,125/-, 155/-, 70/-, 84/- and 98/- respectively.

Average = Sum of all Numbers/ Number of addends

Expenditure on Saturday = x

Sum of expenditure on other 6 days = 621/-

Total expenditure = 621 + x

Average,

⇒  (621+x)/6 = 111

⇒  621+x = 111×6

⇒  621+x = 666

⇒  621+x = 666

⇒  x = 666- 621

⇒ x = 45 /-

Thus, Saturday's expenditure =  Rs 45 /-

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Answer:

( x + y + z )( x^2 + y^2 + z^2 - xy - yz - zx )

Step-by-step explanation:

Use Identity to factor this long expression.

Hope this helps.

Answer: It would be 7.5.

Answer:

the answer would be 7 1/2

Step-by-step explanation:

convert the mixed number into fractions so it would become :

3/1 ÷ 2/5

multiply :

3/1 × 2/5 which equals 15/2

simplify and get : 7 1/2

The correct ways to represent 2.56 are options 1 and 3: 2 ones + 5 tenths + 6 hundredths and 2 ones + 50 tenths + 6 hundredths.The representation of the number 2.56 can be expressed in different ways depending on the place value of each digit.

Let's evaluate each option:

2 ones + 5 tenths + 6 hundredths: This representation correctly shows 2 ones, 5 tenths, and 6 hundredths, which sums up to 2.56.

02 ones + 56 tenths: This representation is not accurate since the leading zero in the ones place does not affect the value of the number. Therefore, this option is incorrect.

2 ones + 50 tenths + 6 hundredths: This representation is accurate as it includes 2 ones, 50 tenths, and 6 hundredths, which totals to 2.56.

25 tenths + 6 hundredths: This representation is incorrect as it only accounts for tenths and hundredths, not including the ones place. Thus, this option does not correctly represent the number 2.56.

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To help us to graph the 3x + 4y = 12, we can isolate y

Therefore it's a line with equation

We have y = 3 when x = 0, and x = 4 when y = 0, therefore

Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance          $56,500

Dec. 31 Bad Debts Expenses                   $55,470

Totals                                        $116,005  $116,005

Accounts Receivable

Accounts                                          Debit               Credit

Jan. 1 Beginning balance           $2,290,000

Jan. 19 Allowance for Doubtful           2,560

Jan. 19 Cash                                                            $2,560

Apr. 3  Allowance for Doubtful                                14,670

July 16  Allowance for Doubtful                              19,725

July 16  Cash                                                             6,575

Nov. 23  Allowance for Doubtful         4,175

Nov. 23 Cash                                                             4,175

Dec. 31  Allowance for Doubtful                             25,110

Dec. 31   Sales Revenue            8,020,000

Dec. 31   Cash                                               $8,944,420

Dec. 31 Ending balance                                 $1,299,500

Totals                                        $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance           $40,100

Dec. 31 Bad Debts Expenses                  $39,070

Totals                                        $99,605   $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

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Answer: 12b+6c+18. Here is your Answer thankyou very much for asking

3x + 2y = 18

2x + 5y = 14 are both linear equations

The system of linear equations in two variables is an equation with two different variables. Any equation with different variables can be in this system.

The solution for this type of equation by solving and getting two different values for both x and y but the same values are used in both equations.

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The linear function for the total cost C is:

A function is an expression, rule, or law that defines a relationship between one variable.

Example:

\(f(\text{x}) = 2\text{x} + 1\)

\(f(1) = 2 + 1 = 3\)

\(f(2) = 2 \times 2 + 1 = 4 + 1 = 5\)

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The total cost for x cubic yards.

\(\bold{C = 28 + 48x}\)

Thus, the function is C = 28 + 48x.

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Answer:a

a

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

\(p_1=X_1/n_1=82/135=0.607\)

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

\(p_2=X_2/n_2=41/92=0.446\)

The difference between proportions is (p1-p2)=0.162.

\(p_d=p_1-p_2=0.607-0.446=0.162\)

The pooled proportion, needed to calculate the standard error, is:

\(p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542\)

The estimated standard error of the difference between means is computed using the formula:

\(s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067\)

Then, we can calculate the z-statistic as:

\(z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014\)

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

\(\text{P-value}=2\cdot P(z>2.4014)=0.0171\)

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

\(MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735\)

Then, the lower and upper bounds of the confidence interval are:

\(LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335\)

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Answer:

8(x^2-3)

Step-by-step explanation:

I used a math app

The probability that Alphonso gets ticket 14 and Cordell gets ticket 23 is = 1/2450

Alphonso can pick a ticket from 50 tickets in 50 ways;

When Alphonso pick a ticket, then Cordell can pick a ticket in 49 ways;

Total number of ways = 50 × 49 = 2450;

Alphonso can get ticket 14 and Cordell can get ticket 23 in only one way;

So, the probability that Alphonso gets ticket 14 and Cordell gets ticket 23 is = 1/2450;

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The unknown angle in the cyclic quadrilateral is as follows:

∠R = 86 degrees

The diagram above is cyclic quadrilateral. A cyclic quadrilateral is a four sided shape that can be inscribed into a circle.

The sum of angles in a cyclic quadrilateral is 360 degrees. The opposite angles in a cyclic quadrilateral is supplementary.

Hence, let's find the unknown angle.

∠R = 1 / 2 (92 + 80)

∠R = 1 / 2 (172)

∠R = 86 degrees

Therefore, the unknown angle is 86 degrees.

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Answer:

those are called quarters

Answer:

Well Caden has 3 quarters (which . 75 cents since they are .25 cents a piece ), he also has a dime, (which is .10 cents ) and also a nickel. ( which is .5 cents)

Caden: .75+.10+.5= $1.00

Eden has a quarter (.25 cents), 2 dimes (.20 cents) and 2 nickels ( .10 cents )

Eden : .25+.20+.10= .55 cents

Harper has 2 quarters (.50 cents), 2 dimes ( .20 cents) and 2 nickels( .10 cents)

Haper: .50+.20+.10= .80cent s

Step-by-step explanation:

I hope this helps and if it does please mark me the brainliest! Peace and love

Answer:

It would be Linear

Step-by-step explanation:

Answer:

i think its quadratic because the graph isnt straight and has different slopes between the x,y.

Step-by-step explanation:

Answer:

She worked a total of 12 hours

Step-by-step explanation:

$152 - $50 in commission = $102

$102 / $8.50 = 12

what were the times she went to bed and woke up?

Answer: x > 24

Step-by-step explanation: -12x/-1/2x = 24. 24 is the given when dividing. The sign is flipped after dividing negatives.

Answer:

x < 0

Step-by-step explanation:

it's the same thing just with that slash( / ).........

Answer:

A, B, and D good luck

Step-by-step explanation:

Answer:

The correct answer would include A,B, and D

Step-by-step explanation:

HAVE A GOOD DAY!

A graph of the given piecewise-defined function is shown in the image below.

In Mathematics and Geometry, a piecewise-defined function simply refers to a type of function that is defined by two (2) or more mathematical expressions over a specific domain.

Generally speaking, the domain of any piecewise-defined function simply refers to the union of all of its sub-domains. By critically observing the graph of this piecewise-defined function, we can reasonably infer and logically deduce that it is constant over several intervals or domains such as x > 2 and x < -2.

In conclusion, this piecewise-defined function has a removable discontinuity.

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