Answer:
mass or size, distance
Explanation:
using newton's law of of gravity the only values that aren't constants are distance and mass since an objects mass applies to its gravity along with the distance
whound bus is travelling at 60 miles per hour on rte 95 going south west (for example travelling
3) A Greyhound bus is travelling at 60,
from Boston to New York city)
a. what is its velocity component
bat is its velocity component along the south direction?(5 pts)
h what is its component of speed along the west directionale
of speed along the west direction? (5 pts)
Bus travelling south west
Answer:
The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.
Explanation:
Given that,
Speed = 60 miles/hour
Direction = south west
Let the south in y axis and west in x axis.
Angle between x and y will be θ.
The component of speed is \(V_{x}\) of x axis and \(V_{y}\) of y axis.
\(\vect{V}=\vec{V_{x}i}+\vec{V_{y}j}\)
Where,
\(V_{x}=|\vec{V}|\cos\theta\)...(I)
\(V_{y}=|\vec{V}|\sin\theta\)....(II)
We know that,
The south west direction makes 45° with west direction in x axis.
(a). We need to calculate the velocity component in south direction
Using equation (I)
\(V_{x}=|\vec{V}|\cos\theta\)
Put the value into the formula
\(V_{x}=60\times\cos45\)
\(V_{x}=42.42\ miles/hour\)
(b). We need to calculate the velocity component in west direction
Using equation (II)
\(V_{x}=|\vec{V}|\sin\theta\)
Put the value into the formula
\(V_{x}=60\times\sin45\)
\(V_{x}=42.42\ miles/hour\)
Hence, The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.
What device is like the reverse of an electric motor?
a.
Generator
c.
Steam engine
b.
Tesla coil
d.
Battery
Answer:
a. Generator
Explanation:
Answer:
A
Explanation:
A battery derives its energy chemically. D is not the answer.
C develops its energy by burning fuel and transferring the heat energy to make water into steam which is chemical/mechanical. Not C
B A Tesla Coil produces a very high voltage and a low current. Not B.
The answer left is A. It converts mechanical energy into electrical energy. It is the only device listed that does this.
On the weather map, what does the symbol shown below represent?
A circle is shown with a slanting line. There are three ticks at the tip.
Cloud cover
Flurries
Snow
Wind speed
Answer:
wind speed i think where i live?
Answer:
Wind speed.
Explanation:
I took the test and I promise this is right.
Cassie walked to her friend's house with an average speed of 1.40 m/s. The distance between
the houses is 205 m. How long did the trip take her?
Answer:
146.4 s
Explanation:
Distance / rate = time
205 m / 1.4 m/s = 146.4 s
We have a transformer that supplies a microwave with 2.1 kV (rms) via a 120 V (rms) AC electric outlet. The microwave operates at 1100 W of power. 1. Find the ratio of the number of primary to secondary turns within the transformer. 2. Find the current in each coil. 3. Suppose a student says "Step-up transformers violate conservation of energy. We put in a small voltage and get a large voltage, so we're basically getting something from nothing.". Explain why you would agree or disagree.
1. To find the ratio of the number of primary to secondary turns within the transformer, we can use the equation:
V1/V2 = N1/N2
where V1 and V2 are the primary and secondary voltages, and N1 and N2 are the number of turns in the primary and secondary coils, respectively.
We know that V1 = 120 V and V2 = 2.1 kV = 2100 V. We also know that the power output of the microwave is 1100 W. Using the equation:
P = IV
where P is power, I is current, and V is voltage, we can find the current in the secondary coil:
1100 W = I(2100 V)
I = 0.524 A
Now we can use the current and voltage in the secondary coil to find the current in the primary coil:
0.524 A = I(120 V)
I = 0.00437 A
Finally, we can use the ratio equation to find the ratio of turns:
120/2100 = N1/N2
N1/N2 = 0.057
So the ratio of primary to secondary turns is approximately 1:18.
2. We already found the current in each coil in part 1. The current in the secondary coil is 0.524 A, and the current in the primary coil is 0.00437 A.
3. The student's statement is incorrect. Step-up transformers do not violate the conservation of energy because the input power equals the output power (minus some small losses due to heat and other factors). In this case, the input power is 120 V * 0.00437 A = 0.524 W, and the output power is 2.1 kV * 0.524 A = 1100 W. The transformer simply increases the voltage while decreasing the current, so the power remains the same. The transformer is not creating energy out of nothing, it is simply transforming it from one form to another.
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For an ideal gas in a sealed container, if you double the pressure and double the volume, while keeping everything else the same, what has happened to the temperature?
A. The temperature is one-quarter of its original value.
B. The temperature is now four times its original value.
C. The temperature is equal to its original value.
D. The temperature is now double its original value.
E. The temperature is now half its original value.
For an ideal gas in a sealed container, if pressure and volume are made double, then : B.) temperature is now four times its original value.
What happens when pressure and volume are doubled?Ideal gas is an hypothetical condition of gas state where molecules of the gas are spaced widely apart that is the inter molecular force of attraction is negligible. It obeys the equation,
PV = n RT
Here, P is the absolute pressure of the gas
V is Volume occupied by the gas
n is number of moles of gas
R is Gas constant
T is Absolute temperature of the gas
Ideal gas at two different states are given as:
((P1).(V1))/(T1) = ((P2).(V2))/(T2)
Given, P2 = 2*P1, V2 = 2*V1
So, ((P1).(V1))/(T1) = ((2*P1).(2*V1))/(T2)
1/T1 = 4/T2
T2 = 4 times of T1
Temperature of the gas becomes four times on doubling the absolute pressure and temperature of gas.
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What is surface tension and what phase of matter creates it?
Answer:
The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension.
If i'm wrong correct me.
Lamar is testing several solutions to identify which ones are acids, which ones are bases, and which one is water. He hypothesizes that solution number 3 is water. For Lamar’s hypothesis to be supported by his data, which of the following pH values must solution number 3 be near? SC.8.N.1.3
A
1.0
B
9.0
C
7.0
D
12.0
A blue car travels at a constant velocity of 24 m/s on a hot 100 degree summer day and has a momentum of 28,800 kg-m/s. What is the mass of the car? Data Formula Work
Answer:
the mass of the car is very big
Explanation:
its heavy
You need to repair a broken fence in your yard. The hole in your fence is around 3 meters in length and for whatever reason, the store you go to has oddly specific width 20cm wood. Each plank of wood costs $16.20, how much will it cost to repair your fence?
The correct answer is $243
Explanation:
The hole in the fence is 3 meters, this means it is necessary to buy wood that covers this distance. Now, each meter is equal to 100 centimeters, this means 3 meters is equivalent to 300 centimeters ( 100 cm in each meter x 3). Besides this, it is known each plank covers 20cm and costs $16.20. In this context, the next step is to find how many planks are needed. The process is shown below:
300 cm (total width) ÷ 20 cm (width of 1 plank) = 15 planks
This means 15 planks are needed. Finally, fin the total cost
15 planks x $16.20 (cost of 1 plan) = $243
. as outlined below, a 2-kg bob is compressed 60-cm against a 50 n/m spring while on the other side a 3-kg block is placed 4-m up along a 30 degree incline. both objects are then released from rest. assuming all surfaces are frictionless: a. what will be the velocity of each object before they collide? (10pts) b. if the collision between the objects is elastic, what will be the velocity of each object after the collision? (10pts) c. if either (or both) of the objects moves toward the spring after the collision, determine how much the spring will be compressed by the object(s) (10pts) d. if either (or both) of the objects moves toward the incline after the collision, determine how far up the incline the object(s) will travel (10pts)
a. To determine the velocity of each object before they collide, we can apply conservation of mechanical energy.
For the 2-kg bob compressed against the spring, the potential energy stored in the spring when compressed is given by:
PE_spring = 0.5 * k * x^2,
where k is the spring constant (50 N/m) and x is the compression distance (0.6 m).
PE_spring = 0.5 * 50 N/m * (0.6 m)^2 = 9 J
The potential energy is converted entirely into kinetic energy before the collision:
KE_bob = PE_spring = 9 J
Using the formula for kinetic energy:
KE = 0.5 * m * v^2,
where m is the mass and v is the velocity, we can solve for the velocity of the 2-kg bob:
9 J = 0.5 * 2 kg * v^2
v^2 = 9 J / 1 kg
v = √(9 m^2/s^2) = 3 m/s
Therefore, the velocity of the 2-kg bob before the collision is 3 m/s.
For the 3-kg block on the incline, we can determine its velocity using the conservation of potential and kinetic energy.
The potential energy at the top of the incline is given by:
PE_top = m * g * h,
where m is the mass (3 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (4 m).
PE_top = 3 kg * 9.8 m/s^2 * 4 m = 117.6 J
The potential energy is converted into kinetic energy:
KE_block = PE_top = 117.6 J
Using the formula for kinetic energy, we can solve for the velocity of the 3-kg block:
117.6 J = 0.5 * 3 kg * v^2
v^2 = 117.6 J / 1.5 kg
v = √(78.4 m^2/s^2) ≈ 8.85 m/s
Therefore, the velocity of the 3-kg block before the collision is approximately 8.85 m/s.
b. If the collision between the objects is elastic, the total momentum before the collision is equal to the total momentum after the collision.
Total momentum before the collision:
P_before = m1 * v1 + m2 * v2,
where m1 and m2 are the masses, and v1 and v2 are the velocities.
P_before = (2 kg * 3 m/s) + (3 kg * 8.85 m/s)
P_before ≈ 36.55 kg·m/s
Since the collision is elastic, the total momentum after the collision remains the same.
Total momentum after the collision:
P_after = (2 kg * v1') + (3 kg * v2'),
where v1' and v2' are the velocities after the collision.
We need to solve this equation for v1' and v2'. More information is required about the nature of the collision (head-on or at an angle) to determine the specific velocities after the collision.
c. To determine how much the spring will be compressed by the object(s) after the collision, we need to consider the conservation of mechanical energy.
The total mechanical energy after the collision is equal to the sum of potential and kinetic energy:
Total Energy_after = PE_spring + KE_bob,
where PE_spring is the potential energy stored in the spring and KE_bob is the kinetic energy of the 2-kg
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What is the acceleration of a car that goes from zero to 60m/s in 15s?
Answer:What is the acceleration of a car that moves from rest to 15.0 m/s in 10.0 s? Vi=0, vf= 15.0 m/s,t=10.0s, a=? a= vf =vi/tA=15.0m/s-0m/s/10.0s = 15.0s/10.0s m/s*1/s =1.50 m/s^2 11.
Explanation:
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? Show all calculations and use SALT to describe the image.
Answer:
The height of the image of the candle is 20 cm.
Explanation:
Given that,
Size of the candle, h = 12 cm
Object distance from the candle, u = -6 cm
Focal length of converging lens, f = 15 cm
To find,
The height of the image of the candle.
Solution,
Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.
\(\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\)
v is image distance
\(\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm\)
If h' is the height of the image. Magnification is given by :
\(m=\dfrac{h'}{h}=\dfrac{v}{u}\)
\(h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm\)
So, the height of the image of the candle is 20 cm.
The foot of a 60 kg sprinter is on the ground for 0.40 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?
We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.
To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.
Mass of the sprinter,
m = 60 kgTime the sprinter's foot is on the ground,
t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,
v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:
v = final velocity of the sprinter, which is 2.0 m/s
u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s
Substituting these values, we get:2.0
= 0 + a(0.40)Simplifying, we get:
2.0 = 0.4a
Dividing both sides by 0.4, we get:
a = 5 m/s² Substituting the values, we get:
F = 60 × 5F = 300 N
Therefore, the magnitude of the friction force is 300 N.
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Albert has an impulse of 29 newton seconds and an impact time of 12 seconds.
What is the force experienced?
Your answer
Choose to complete either the abstract or the real world problem for the following
2 problems.
The force experienced, given the data from the question is 2.42 N
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
With the above formula for impulse (Impulse = force × time), we can determine the force experienced by Albert. Details below:
Data obtained from the questionFrom the question given above, the following data were obtained:
Impulse = 29 NsTime (t) = 12 sForce (F) =?How to determine the force experiencedThe force experienced can be obtained as follow:
Impulse = force × time
29 = force × 12
Divide both sides by 12
Force = 29 / 12
Force = 2.42 N
Thus, the force experienced by Albert is 2.42 N
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difference between input work and output work with table
Answer:
Explanation:
Input work is the work done on a machine as the input force acts through the input distance. ... Output work is the work done by a machine as the output force acts through the output distance. The machine does to the object to increase the output distance.
Pls help me!!!!!!!!!!!!!!!!!
Answer:they are a renewable source
Explanation: because they come from the ocean and the ocean is 75% of the world so there will always be waves.
which concept was demonstrated by rutherford's gold foil experiment? mastering chem
Answer: the atom is mostly empty space with a tiny, dense, positively-charged nucleus
Explanation: Rutherford's gold foil experiments involved firing positively charged alpha particles at a piece of gold/metal foil. The alpha particles that were fired at the gold foil were positively charged. Most of the time, the alpha particles would pass through the foil without any change in their trajectories, which is what was expected if JJ Thomson's plum pudding model of the atom was correct. However, occasionally the alpha particles would be deflected to some degree, and sometimes an alpha particle would bounce back directly toward the experimenter. Rutherford likened this to firing a 15-inch artillery shell at a sheet of tissue paper and the shell came back to hit you.
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Rutherford's gold foil experiment demonstrated the concept of the nucleus of the atom.What is Rutherford's gold foil experiment?
Rutherford's gold foil experiment is an experiment that was conducted by Ernest Rutherford in 1911 to determine the structure of the atom. Rutherford bombarded alpha particles at thin gold foil and noted their trajectory and path.The experiment was conducted to answer the prevailing model of the atom's structure, which was the Thomson atomic model.
According to the Thomson atomic model, the atom's positive charge is evenly distributed throughout the atom, like raisins in a pudding. Rutherford's experiment refuted this hypothesis and provided a new model that supported his findings.
The findings of the gold foil experiment:
Rutherford's experiment led him to conclude that the positive charge of the atom is concentrated in the nucleus, a central part of the atom. In this model, electrons orbit the nucleus, like planets orbiting the sun.
Rutherford's gold foil experiment demonstrated that the atom is made up of mostly empty space, with a small, dense, and positively charged nucleus at the center. This discovery paved the way for further research into atomic structure and the discovery of subatomic particles like protons and neutrons.
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Need help with this problem. Trying to find all the values and explanations how to get it.
Thank you.
Answer:
c d
Explanation:
Metal bar 1
Metal bar 2
Ray has two metal bars. He knows Metal bar 1 is a magnet.
How could he use Metal bar 1 to find out if Metal bar 2 is a magnet?
What would he observe if Metal bar 2 is a magnet?
Ray could use Metal bar 1 to find out if Metal bar 2 is a magnet by bringing them close to each other. If Metal bar 2 is a magnet, it will be attracted to Metal bar 1.
Ray can also try to move Metal bar 1 along the length of Metal bar 2. If Metal bar 2 is a magnet, it will induce a magnetic field in Metal bar 1, causing it to experience a force as it moves. Alternatively, when Ray moves Metal bar 1 along the length of Metal bar 2, he would observe a force acting on Metal bar 1 as it moves. This is because the magnetic field produced by Metal bar 2.
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A steel bridge is 500.0 m long when the temperature is 25.00 OC. What is the length on a cold day when the temperature is minus 20.0 oC? The coefficient of expansion for steel is 12 * 10-6.
Answer:
499.73 m
Explanation:
We'll begin by calculating the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 25 °C
Final temperature (T₂) = –20° C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = –20 – 25
ΔT = –45 °C
Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:
Length at 25°C (L₁) = 500 m
Coefficient of linear expansion (α) = 12×10¯⁶ /°C
Change in temperature (ΔT) = –45 °C
Length at –20 °C (L₂) =?
α = L₂ – L₁ / L₁ΔT
12×10¯⁶ = L₂ – 500 / (500 × –45)
12×10¯⁶ = L₂ – 500 / –22500
Cross multiply
L₂ – 500 = 12×10¯⁶ × –22500
L₂ – 500 = –0.27
Collect like terms
L₂ = –0.27 + 500
L₂ = 499.73 m
Therefore, the length on a cold day at –20° C is 499.73 m.
A 9V battery is attached to 6Ω and 3Ω resistor. What is the voltage going to the 3Ω resistor?
1 V
3 V
9 V
2 V
4.5 V
It is a short circuit
Answer:
Voltage across 3 resistor =13.5v
Explanation:
Voltage=resistance *Current
But we don't have total current, so we must find total current
Current =v/R
Current=9/2
Current =4.5I
From
V=R*I
V=3*4.5
V=13.5v
Do any individual air molecules travel the length of the tube? how do you know?
When a gas is inside the tube, the individual air molecules travel the length of the tube.
What is molecules?The individual particle of a gas element moving randomly inside the element structure.
When the gas contained in a container, the molecules move randomly inside it. According to the kinetic theory of gases, molecules travel the mean distance. The air molecules vibrates horizontally parallel to the length of the tube.
In an open tube, air molecules are distant from each other. So, they can travel the length of the tube.
Thus, individual air molecules travel the length of the tube.
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what is the action force of a bug hitting a windshield?
Answer:
In the interaction between the bus and the bug, we can call the force "bus pushes bug" the action force. Then the force "bug pushes bus" is the reaction force. Since these forces are a Newton's Third Law action/reaction force pair, they are exactly the same size.
Explanation:
Newtons 3rd law
What is the frequency of a simple pendulum 2.0m long (a) in a room, (b) in an elevator accelerating upward at a rate of 2.0m/s2 and (c) in free fall?
The frequency of a simple pendulum depends on its length and the gravitational acceleration. In a room, the frequency can be calculated using the standard formula for a pendulum. In an elevator accelerating upward, the frequency decreases due to the reduced effective gravitational acceleration. In free fall, where there is no gravitational acceleration acting on the pendulum, the frequency becomes zero.
The frequency of a simple pendulum is determined by the length of the pendulum and the acceleration due to gravity. The formula for the frequency (f) of a pendulum is given by f = 1 / (2π) * √(g / L), where g is the acceleration due to gravity and L is the length of the pendulum.
(a) In a room, assuming a standard acceleration due to gravity of approximately 9.8 m/s^2, and a length of 2.0 m for the pendulum, we can calculate the frequency using the formula. Plugging in the values, we have f = 1 / (2π) * √(9.8 m/s^2 / 2.0 m) ≈ 0.222 Hz.
(b) In an elevator accelerating upward at a rate of 2.0 m/s^2, the effective gravitational acceleration experienced by the pendulum is reduced. The new effective gravitational acceleration is given by g' = g - a, where a is the acceleration of the elevator. Substituting the values, g' = 9.8 m/s^2 - 2.0 m/s^2 = 7.8 m/s^2. Using the same length of 2.0 m, we can calculate the frequency as f' = 1 / (2π) * √(7.8 m/s^2 / 2.0 m) ≈ 0.197 Hz.
(c) In free fall, there is no gravitational acceleration acting on the pendulum. Therefore, the frequency becomes zero as there is no force to cause the pendulum to oscillate.
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30. 0 gram of Aluminum at 80. 0 °C is added to 30. 0 g of water at 10 °C. Predict the final temperature
of the water and explain your reasoning. (no math, just logic!)
When the aluminum and water are mixed together, heat transfer occurs between the two substances until thermal equilibrium is reached. The aluminum, initially at a higher temperature of 80.0 °C, will transfer heat to the water, which is initially at a lower temperature of 10.0 °C.
Since aluminum has a higher specific heat capacity than water (0.897 J/g°C for aluminum compared to 4.186 J/g°C for water), it can hold more heat energy per gram per degree Celsius. This means that the aluminum will transfer its heat energy to the water, causing its temperature to increase.
Based on the given information, we can expect that the final temperature of the water will be somewhere between 10.0 °C and 80.0 °C. However, without knowing the exact values of the specific heat capacities of aluminum and water, as well as the amount of heat transferred between them, it is not possible to predict the final temperature accurately. In real-world scenarios, the final temperature will depend on several factors, such as the exact masses of aluminum and water, their specific heat capacities, and the heat transfer mechanism (e.g., conduction). To determine the final temperature accurately, precise measurements and calculations involving heat transfer equations would be necessary.
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a) at what time and (b) where does the particle (momentarily) stop? at what (c) negative time and (d) positive time does the particle pass through the origin?
The particle :a) At time t = 2 s, the particle momentarily stops at x = 6 m. b) The particle passes through the origin at t = 1 s and t = 5 s.c) At negative time t = -3 s, the particle is at x = -12 m. d) At positive time t = 7 s, the particle is at x = 12 m.
a) At what time and where does the particle momentarily stop? The particle momentarily stops at the point where the velocity of the particle becomes zero, i.e., at the point where the particle changes its direction from left to right. Thus, the particle stops momentarily at time t = 2 s and x = 6 m. b) At what negative time and positive time does the particle pass through the origin?We know that the particle passes through the origin when x = 0. At negative time t, the particle is at the left side of the origin, i.e., x < 0. The particle passes through the origin at time t = 1 s. At positive time t, the particle is at the right side of the origin, i.e., x > 0. The particle passes through the origin again at time t = 5 s. Therefore, at negative time t = -3 s, the particle is at x = -12 m, and at positive time t = 7 s, the particle is at x = 12 m.
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Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls from the top of a shelf to the ground?
Answer:
The force is of the weight 862,4 Newtons.
Explanation:
We have the formula:
w = m * g
Data:
w = weight = ¿?
m = mass = 88 kg
g = gravity = 9,8 m/s
Replacing according formula:
w = 88 kg * 9,8 m/s
Resolving:
w = 862,4 N
The region of a sound wave where the molecules are spread out is represents where medium become
Answer:
Sound waves are the longitudinal waves which are made of compression and rarefaction. So the compression is the region where the molecules compress so the ANSWER should be rarefaction region as the molecules spread out or expand.
How much does a 200 kg car weigh?
Answer:
42,000 lbs
Explanation:
100 kg is 210 lbs.
200 x 210 lbs =
42,000 lbs
The weight of the car is product of its mass and acceleration due to gravity of earth. Hence, the weight of the 200 kg car is 1960 N.
What is acceleration due to gravity ?The gravitational force of an object is the force by which attracts other objects into its center of mass. Earth attracts every objects into its center and that is why we are all standing on the ground.
The weight we experience on earth is due to this gravitational force and it decreases when we move far from earth. The acceleration due to gravity is the acceleration by which an object accelerates downwards due to earth's gravity (g).
Weight of an object = mass × g
g for earth = 9.8 m/s²
mass of the car = 200 Kg.
then, weight = 200 kg × 9.8 m/s² = 1960 N.
Therefore, the weight of the car is 1960 N.
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