One child has blonde hair like their mother, and their sibling has brown hair like their father; this is due to genetics. A baby's gender and the reasons why some diseases run in families are also influenced by DNA.
Two illustrations of genes:Many of your characteristics, like your skin and hair colors, are determined by genes that are passed down to you. Perhaps Emma's mother carries both the brown and red hair genes, and she gave Emma the red hair gene.
An alteration to just one copy of the gene results in the autosomal dominant inheritance pattern. Mutations in both copies of the gene pair create the autosomal recessive inheritance pattern.
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Analyze the graph and determine which section of the graph is the car moving the fastest?
Answer:
D
Explanation:
What is the position and kind of image produced by the lens below?
Complete the ray diagram to support your answer.
why do some people suffer for nose bleed at higher altitudes?
Answer:because of small amount of oxygen
Explanation:
If you get higher by the atmosphere the air will start to decrease
a buoy oscillates in simple harmonic motion as waves go past. the buoy moves a total of 14 feet from its high point to its low point, and it returns to its high point every 5 seconds. write and equation that describes the motion of the buoy, where the high point corresponds to the time t
The equation that describes the motion of the buoy in simple harmonic motion can be written as:
y(t) = A * cos(ωt + φ)
Where:
- y(t) is the displacement of the buoy from its equilibrium position at time t.
- A is the amplitude of the motion, which is half the total distance traveled by the buoy, so A = 14 feet / 2 = 7 feet.
- ω is the angular frequency of the motion, which is calculated as ω = 2π / T, where T is the period of the motion. In this case, the period is 5 seconds, so ω = 2π / 5.
- φ is the phase constant, which represents the initial phase of the motion. Since the high point corresponds to the time t = 0, we can set φ = 0.
Therefore, the equation that describes the motion of the buoy is:
y(t) = 7 * cos((2π/5)t)
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In a river of bed width of 600 m and bed slope of 7.5 cm/km, it is found that the bed material just begin to move when the discharge is 120 million m³/day. Assuming the mean velocity to vary with the water depth and slope according to the relation: v = 120 y $2/³, find the bed slope at which the same tractive force on the bed would be produced with a discharge of 365 million m³/day.
The bed slope required to produce the same tractive force on the bed with a discharge of 365 million m³/day can be determined using the given equation for mean velocity variation.
Bed width (B) = 600 m
Initial discharge (Q1) = 120 million m³/day
Initial bed slope (S1) = 7.5 cm/km
The equation for mean velocity (v) = 120 y^(2/3), where y is the water depth.
To find the bed slope (S2) for a new discharge (Q2) of 365 million m³/day, we need to equate the tractive force on the bed for both scenarios.
The tractive force on the bed can be represented as:
Tractive force =\((Rho * g * S * B * v^2) / (R * D50)\)
where:
Rho is the density of water,
g is the acceleration due to gravity,
S is the bed slope,
B is the bed width,
v is the mean velocity, and
R and D50 are constants.
Since we are comparing two scenarios with the same tractive force, the following equation can be formed:
\((Rho * g * S1 * B * v1^2) / (R * D50) = (Rho * g * S2 * B * v2^2) / (R * D50)\)
Simplifying the equation:
\(S1 * v1^2 = S2 * v2^2\)
Substituting the given values:
\(S_1 * (120 y_1^{(2/3))^2 = S_2 * (120 y_2^{(2/3))^2\)
Rearranging the equation:
\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)
We know that Q = B * v * y, where Q is the discharge. Rearranging this equation gives:
\(v = Q / (B * y)\)
Substituting the values for Q1 and Q2, we have:
\(v1 = 120 million / (B * y1)\)
\(v2 = 365 million / (B * y2)\)
Substituting the expressions for v1 and v2 in the equation from step 7:
\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)
\(= S_1 * (120^2 * y_1^{(4/3)}) / (120^2 * y_2^{(4/3)})\)
\(= S_1 * (y_1^{(4/3)} / y2^{(4/3)})\)
Since the bed material just begins to move when Q = 120 million m³/day, the velocity can be expressed as \(v = v_1 = 120 y1^{(2/3)}.\)
Therefore, the equation for S2 becomes:
\(S_2 = S_1 * (y_1^{(4/3)} / y_2^{(4/3)})\)
=\(S_1 * (120^{(4/3)} * y_1^{(4/3) }/ (120 y_2^{(2/3)})^{(4/3))\)
\(= S_1 * (120^{(4/3)} * y1^{(4/3)} / (120^{(4/3)} * y2^{(4/3)}))\)
\(= S_{1 * (y_1^{(4/3)} / y_2^{(4/3)})\)
Finally, substituting the values for y1 and y2:
\(S_2 = S_1 * (y_1^{(4/3) }/ y_2^{(4/3)})\)
= \(S_1 * (y_1^{(4/3)} / (365 / 120)^{(4/3)})\)
Now, you can substitute the values for y1, and S1, and calculate S2 accordingly.
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You have a working electrical parallel circuit with three light bulbs, then 1 bulb burns
out.
Describe how electric current flows through the parallel circuit after 1 of the 3 bulbs
burns out?
Answer:
but the answer should be no as if 3 bulbs are connected together if one burns out the whole circuit will stop .hope you understood
please mark me as brainlist
A police officer on a mountain bike is cruising at a speed of 3.50m/s, when he sees a wanted
criminal, standing on a corner, 75m ahead of him. If the police officer accelerates at a rate of
2.00m/s^2, how much time will he take to reach the corner?
Answer:
7 seconds
Explanation:
please see paper!
vf² = vo²+2ad
vf=vo+at
vf²=3.5²+2.2.75
vf²=312.25
vf=17.67 m/s
vf=vo+at
17.67 = 3.5 +2t
t=7.085 s
A 16.0 kg child on roller skates, initially at rest, rolls 2.0 m down an incline at an angle of 20.0° with the horizontal. If there is no friction between incline and skates, what is the kinetic energy of the child at the bottom of the incline?
The kinetic energy of the child at the bottom of the incline is 106.62 J.
The given parameters:
Mass of the child, m = 16 kgLength of the incline, L = 2 mAngle of inclination, θ = 20⁰The vertical height of fall of the child from the top of the incline is calculated as;
\(sin(20) = \frac{h}{2} \\\\h = 2 \times sin(20)\\\\h = 0.68 \ m\)
The gravitational potential energy of the child at the top of the incline is calculated as;
\(P.E = mgh\\\\P.E = 16 \times 9.8 \times 0.68\\\\P.E = 106.62 \ J\)
Thus, based on the principle of conservation of mechanical energy, the kinetic energy of the child at the bottom of the incline is 106.62 J since no energy is lost to friction.
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How can one decrease power output while still doing the same amount of work
To decrease power output while still doing the same amount of work, one can increase the time it takes to complete the task. This means that the work is being spread out over a longer period of time, reducing the amount of power required to complete it.
There are several ways to increase the time it takes to complete a task, such as taking more breaks, slowing down the pace of work, or breaking the task up into smaller parts. For example, if you are lifting weights, you can decrease the power output by doing more repetitions with a lighter weight, or by taking longer breaks between sets. This will still allow you to achieve the same amount of work, but with less power output.
Another way to decrease power output is to use more efficient equipment or techniques. For example, if you are using a lawn mower, switching to a more energy-efficient model or using a mulching blade can reduce the amount of power needed to mow the lawn. Additionally, adjusting the technique used to complete a task can also make it more efficient and require less power.
In conclusion, decreasing power output while still doing the same amount of work can be achieved by increasing the time it takes to complete the task, using more efficient equipment or techniques, or breaking the task up into smaller parts.
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Power requires strength and speed? True or false
Answer:
True
Explanation: How are you gonna kick a ball if you have no power (strength) and how you gonna kick it if you dont have enough move your leg fast (speed) towards the ball
Which diagram shows the most likely effect when a rock is weathered by water flowing over its entire surface
Answer:
the answer to this would be D.
Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck
Explanation:
The acceleration reaches its minimal value of zero at the top of the trajectory. *
True
False
it is true. the trajectory reaches the value of zero at the top
Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
The diagram below represents a 155-newton box
on a ramp. Applied force F causes the box to
slide from point A to point B.
What is the total amount of gravitational potential
energy gained by the box?
155-newton box going up a ramp. The gravitational potential energy in the universe totals 279J, which is what causes the box to move from point A to point B when force F is applied.
How is gravitational potential energy calculated?The formula for gravitational force is P.E. = mgh, whereby g is the force caused by gravity (9.8 m/s2 at the earth's surface) and h is the elevation in metres. The units for gravitational potential energy are kg m2/s2, which are the same as those for kinetic energy.
Which of the following points has the object's gravitational potential energy at its lowest?The amount of gravitational potential energy an object has depends on how high it is above the surface whenever the height is the smallest. Point B in the given diagram is the lowest point and is closest to the Earth's surface vertically.
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People often use simple machines like pulleys, levers, and ramps because they say the machine “makes the work easier.” Which of the following statements about simple machines is true?
a.
Simple machines often reduce the amount of work to move an object.
b.
Simple machines often reduce the energy required to move an object.
c.
Simple machines often reduce the power consumed when moving an object.
d.
Simple machines often reduce the force needed to move an object.
Usain Bolt runs at 200 meters in 20.0 seconds. How fast does he run? speed = distance / time
Answer:
22.369363 mi/h
Explanation:
Average Speed Calculation - suppose we want to calculate Usain Bolt's average speed during his world record winning 100 m sprint race in Berlin on August 16, 2009. What do we know?
We want to calculate Bolt's average speed
The distance was, of course, 100 meters
Bolt ran the distance in 9.58 seconds.
Bolt ran 11.42 yards per second during the race. Setting meters per second, you get 10.44 mp/s; miles per hour - 23.35 mph; kilometers per hour - 37.58 km/h; etc.
Travel Time Calculation - Suppose, you drove 21 miles with an average speed of 45 miles per hour. How long did you drive?
You traveled 28 minutes.
Distance Calculation - Let's calculate, how many miles you can travel, driving 2 hours and 30 minutes with an average speed of 55 miles per hour?
As you can see, the answer is 137.5 miles or 221.28 kilometers or 119.48 nautical miles, etc.
Assume, V - stands for average speed (velocity), T - stands for traveling time, and D - stands for traveled distance.
Average speed can be calculated by using the formula: V = D/T
The traveled distance can be calculated as D = V*T
Traveling time can be calculated using: T = D/V
Using the formulas remember about the units. For example, if the distance is given in meters and the time is given in seconds, the calculated average speed is given in meters per second. To convert it to other units of measurement, you can use our speed converter. If the distance is given in yards and speed is given in miles per hour, to get time in hours, you HAVE TO convert yards to miles or miles per hour to yards per hour first.
HELP ME! PLEASE! SOMEONE! THIS QUESTION IS VERY HARD! THERE ARE 3 ANSWERS! HELP ME PLEASE! MAKE SURE TO EXPALIN
Question:
The teacher told Fatima that all types of energy are kinetic energy, potential energy, or both. Fatima drew this diagram to help her organize this information. She then sorted each type of energy into its correct category: chemical, electrical, electromagnetic, mechanical, nuclear, and thermal.
Three of the types of energy can be either kinetic or potential energy. Identify these three types. For each type, explain why it can be either kinetic or potential.
Answer:
search up the kinetic energy and potential energy etc. then take them and look at the characteristica are they the same? What makes them similar? Why are they different ? How? Then add the chemical nuclear and electrical changes it creates. Now the rest! There you’ve got this! If you need support I’m here! Hope this helped!
Explanation:
a copper wire has a diameter of 1.700 mm. what magnitude current flows when the drift velocity is 1.40 mm/s? (see example 20.3 of the textbook for useful information.)
To determine the magnitude of current flowing through a copper wire, we can use the equation that relates current, drift velocity, and the cross-sectional area of the wire.
In Example 20.3 of the textbook, it is stated that the current (I) is given by the equation:
I = n * A * v * q
Where:
I is the current,
n is the number density of charge carriers (electrons in this case),
A is the cross-sectional area of the wire,
v is the drift velocity of the charge carriers,
q is the charge of an electron.
Given that the drift velocity (v) is 1.40 mm/s and the diameter of the wire is 1.700 mm, we can calculate the cross-sectional area (A) of the wire. The diameter of the wire is twice the radius, so the radius (r) is 1.700 mm / 2 = 0.850 mm = 0.850 × 10^(-3) m.
The cross-sectional area (A) of the wire can be calculated using the formula for the area of a circle:
A = π * r^2
Substituting the values, we have:
A = π * (0.850 × 10^(-3))^2
Now we can calculate the current (I) using the known values for the number density (n) and the charge of an electron (q):
I = n * A * v * q
Remember to convert all units to SI units (meters and coulombs) for accurate calculations.
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A woman does 236 J of work
dragging her trash can 24. 4 m to
the curb, using a force of 18. 9 N.
At what angle was her force
directed?
(Unit = degrees)
According to the given statement is the 59.21° angle was her force directed.
What is a force?The word "force" has a specific meaning in science. At this level, calling a force a shove or a pull is entirely appropriate. A charge is not really something an object "has in it" or that it "contains." One thing experiences a force from another. Living organisms or inanimate objects are not the only things that can be considered forces. Every time two items interact, a force is exerted on every one of the objects. The force is no longer felt by the two objects when the interaction ends.
Briefing:Work done = force × distance
236J = 18.9cos(o) × 24.4
236/24.4 = 18.9cos(o)
(0.5117)cos^-1 = (o)
59.21°
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30 points plz help ill do anything... literally anything.
A car moving at 10 m/s slows to a stop.
It moves 25 meters forward while braking.
1. How much time does it take to slow to a stop? Explain how you found your answer.
2. What is its braking acceleration? Explain how you found your answer.
Answer:
1. 2.5s
Explanation:
1. For time, divide Distance / speed
25m / 10
=2.5s
classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine force A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on
a) A point charge of 2
×
10
−
9
C
2×10−9 C is located at the origin. What is the magnitude of the electric field at location ⟨
0.4
,
0
,
0
⟩
m
⟨0.4, 0, 0⟩ m?
b) Next, a short, straight, thin copper wire 8
m
m
8 mm long is placed along the x-axis with its center at location ⟨
0.2
,
0
,
0
⟩
m
⟨0.2, 0, 0⟩ m. What is the approximate change in the magnitude of the electric field at location ⟨
0.4
,
0
,
0
⟩
m
⟨0.4, 0, 0⟩ m? (Approximate the polarized charges on the short copper wire as a dipole, and when calculating your answer, take the center of the wire as the point at which the net electric field is zero.)
As a result, the short copper wire's effect on the electric field's magnitude at the specified place is approximately 0.019 N/C.
a) Using Coulomb's law, we may determine the electric field at the specified point:
E = k * Q / r^2. Here, Q equals 2 10-9 C and r equals 0.4 m. Using these numbers as inputs, we obtain E = (8.99 109 N*m2/C2) * (2 × 10^-9 C) / (0.4 m)^2\sE ≈ 1.125 N/C
b) It is possible to think of the short copper wire as an electric dipole with the dipole moment defined by: p = 2 * L * q B = * I / (2 * * r).
q ≈ 1.26 × 10^-6 C/m
E = (1 / (4 * )) * (p / r 3) * (2 * x / d) / (0.2 m) / (E 0.019 N/C) E = (1 / (4 * 8.85 10-12 F/m)) * (2 * 0.008 m * 1.26 10-6 C/m) Hence, the approximate change in the electric field's strength at the specified position as a result of the short copper wire's effect on the electric field's magnitude at the specified place is approximately 0.019 N/C.
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Una mujer recorre una trayectoria rectilínea en su camioneta primera una velocidad constante de 50 km/h luego a 70 km/h y después de 60 km/h durante su trayecto a su trabajo ¿cuál será la velocidad promedio?
Answer:6/1 %50 x11
Explanation:
25-45
what is the speed in km/hr of a car traveling 144 km in 90 minutes?
Answer
96mph
Explanation:
You are given "144 miles in 90 minutes" and what you need to figure out is "144 km in X hours." To go from 90 min to hours, you can do 90 min * 1hr/60min = 1.5 hrs or 144 km in 1.5 hrs or 144 km per 1.5 hours. 144/1.5 = 96.
Which option is an example of a conceptual model?A. mental image of gas molecules as tiny ballsB. A weather map created by Doppler radarC. A clay ball with a slice cut out, showing the layers of EarthD. A diagram of a flagpole and its shadow with measurements provided to calculate the length of the shadow
From the given options let's select the example which shows a conceptual model.
A conceptual model can be said to be a model which shows an abstract representation of any concept which can be visualized or imagined than other models.
It is a model which the designers want users to understand.
From the list, the best option which is an example of a conceptual model is a mental image of gas molecules as tiny balls.
Let's say, for example, you imagine or have a mental picture of gas molecules using your imagination, it helps to understand how a vacuum system works and you can easily solve the problem if something goes wrong.
Therefore, the example of a conceptual model is:
A mental image of gas molecules as tiny balls.
• ANSWER:
A. mental image of gas molecules as tiny balls
Part A) What is the speed of a particle whose momentum is mc? Give your answer as a fraction of c.
Part B) A 2.4 g particle has momentum 410,000 kgm/s. What is the particle's speed? Give your answer as a fraction of c.
Part A)
The momentum of a particle of mass m traveling at velocity v can be expressed as p = mv. Solving for v, we get:
v = p/m
Substituting the momentum of the particle as mc, we get:
v = mc/m = c
Therefore, the speed of a particle whose momentum is mc is c, which is the speed of light in a vacuum.
Part B)
The momentum of a particle with mass m and velocity v can be expressed as p = mv. Solving for v, we get:
v = p/m
Substituting the given values, we get:
v = (410,000 kgm/s)/(2.4 g) = (410,000 kgm/s)/(0.0024 kg) = 170,833,333.33 m/s
Expressing this speed as a fraction of c, we get:
v/c = (170,833,333.33 m/s) / (299,792,458 m/s) = 0.5704
Therefore, the speed of the particle is approximately 0.5704 times the speed of light in a vacuum.
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All of the noble gases have _______ electrons in their outer shell
Answer:
8
Explanation:
All noble gasses have 8 electrons in their outer shell
Explain how the values and needs of contemporary society influence the focus of research into car safety. Using Newton’s laws of motion, describe three key safety features in the design of cars that help reduce personal injury in a car crash.
500 words please
Sir Isaac Newton's three laws of motion are manifested in nearly every activity of everyday life including traffic accidents. From flying birds to racing cars these laws of motion are everywhere. In fact, nearly 99% of all activity in our physical world is usually governed by these laws.
Newton's laws of motion are very important when engineers design airplanes sports equipment cars train toys and more. This article describes Newton's three laws of motion in car accidents. Newton's first law of motion states that when an object is in motion, it will move at the same speed and in the same direction, or if it is at rest, it will continue to move until acted upon by an external force. In other words, objects have a natural tendency to continue doing what they were doing until they respond.
In the absence of an external force, a moving object maintains its original state of motion or remains stationary. This law is usually called the law of inertia. Newton's second law of motion states that an object subjected to a force experiences an acceleration such that the force is equal to the mass times the acceleration. Mathematically this is expressed as . In other words, the force exerted during a collision is proportional to the mass of the colliding vehicle. This means that the more force a car collides with the more force it applies which means more destruction. The opposite is also true If the mass of the colliding vehicle is less, less force will be applied and there will generally be less destruction.
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How much work W must be done on a particle with a mass of m to accelerate it from a speed of 0.910 c to a speed of 0.984 c
The work done on the particle with mass 'm' to accelerate it from a speed of 0.910c to a speed of 0.984 c is equal to (0.0778mc²).
When mass is represented as a variable, the work done on the particle can be expressed as:
W = ΔKE = (1/2) × m × ((v_final)² - (v_initial)²)
Given:
Initial speed (v_initial) = 0.910 c
Final speed (v_final) = 0.984 c
Substituting these values into the equation, we have:
W = (1/2) × m × ((0.984 c)² - (0.910 c)²)
Simplifying further:
W = (1/2) × m × ((0.984² - 0.910²) × c²)
W = (1/2) × m × (0.1556 × c²)
W = (0.0778mc²).
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Which of the following is NOT an example of acceleration?
A car is traveling 33 km/h and slows down to 25 km/h.
B.
A car is driving straight at 50 mi/h.
A car is traveling 33 km/h and speeds up to 45 km/h.
A car is traveling 33 km/h north and turns east.
Answer:
B
explanation:
The car is not making a change in speed.