what describes the wave used? check all that apply. transverse longitudinal heat electromagnetic sound

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

No, a liter is equal to 1000 milliliters

ITS FALSE DUDE ......

HOPE THIS HELPS

when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.  Check the picture below.

\(\cfrac{x}{11}~~ = ~~\cfrac{4}{x}\implies x^2=44\implies x=\sqrt{44}\implies x=2\sqrt{11}\)

Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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On a velocity-time graph, the object's displacement is indicated by the area under the line. The distance is the zone under a speed-time graph.

Displacement is the outcome of velocity and time. The area of our graph is obtained by multiplying the velocity and time, which is virtually equivalent to multiplying two lengths. The solution to estimating displacements from a velocity-time graph.

The amount of acceleration will be determined by the graph's slope. Example If a particle's acceleration is constant (k) and positive, its starting velocity is zero, and it grows linearly from there. The acceleration will be determined by the velocity-time graph's slope.

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The anticipated time when he will appear again is 5:17 pm

The given parameters;

your speed, \(V_a\) = 3 m/s

the runner's speed, \(V_b\) = 14 m/s

the diameter of the lake, d = 2 miles = 3218.69 meters

The circumference of the lake is calculated as;

\(C = \pi d\\\\C = 3.142 \times 3218.69 = 10,113.12 \ m\)

Apply concept of relative velocity to determine the time, in which he will appear again.

By the time he appears again;

the distance you moved + distance he moved = circumference of the circle

\(V_at + V_bt = 10, 113.12\\\\(V_a + V_b)t = 10,113.12\\\\(3 + 14) t = 10,113.12\\\\17t = 10,113.12\\\\t = \frac{10,113.12}{17} \\\\t = 594.89 \ s = 9.92 \ \min \ \approx 10 \ \min\)

\(t\ \approx \ \ 5:17 \ pm\)

Thus, the anticipated time when he will appear again is 5:17 pm

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Aacording to the data given in the question the length of the object by using the metric ruler is  5.2 centimeters.

In Figure 1, the metric ruler is provided, and by aligning it with the object in Figure (a), we can determine its length. Looking closely at the ruler, we can observe that the left end of the object aligns with the 5-centimeter mark, while the right end aligns just a little past the 7-centimeter mark. The small tick marks on the ruler represent millimeters, and we can estimate that the object extends approximately halfway between the 7-centimeter mark and the next millimeter mark, which is 0.2 centimeters. Therefore, the total length of the object is 5 centimeters + 0.2 centimeters = 5.2 centimeters. As for the estimated digit, since the measurement falls exactly on the 0.2-centimeter mark, we consider it as an integer value. Therefore, the estimated digit for the measurement in Part A is 5.

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Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

Tan theta = 9 / 90 = .1      so theta = 5.71 deg

The time for the monkey to reach the ground is

t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec

So the horizontal speed of the dart must be at least

Vx = 90 m / 1.36 sec = 66.4 m/s

Vx = V cos theta

V = 66.4 m/s / cos 5.71 = 66.7 m/s

The angle of projection of the tranquilizer dart is 5.7⁰

The horizontal speed of the tranquilizer dart is 66.5 m/s

The given parameters;

The angle of projection of the tranquilizer dart is calculated as;

\(tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0\)

The speed of the tranquilizer dart is calculated as;

X = v₀ₓt

where;

t is the time to reach maximum height

X is the horizontal displacement = 90 m

The time to reach maximum height is calculated as;

\(h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s\)

The horizontal speed of the tranquilizer dart is calculated as;

\(X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s\)

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Answer:

Explanation:

57.8 m/s

The terminal speed of a raindrop is proportional to the square of the radius.

If the radius is doubled, the terminal speed will quadruple.

The terminal speed of a raindrop is the speed at which the drag force from air resistance balances the force of gravity. The drag force is given by F = pACv^2/2, where p is the density of air, A is the cross-sectional area, C is the drag coefficient, and v is the speed.

The cross-sectional area of a spherical raindrop is A = πr^2, where r is the radius of the raindrop.

The force of gravity is given by F = mg, where m is the mass of the raindrop and g is the acceleration due to gravity.

For a raindrop to reach its terminal speed, the drag force must equal the force of gravity. This means that pACv^2/2 = mg.

Solving for v, we get v = (2mg)/(pCπr^2).

The terminal speed is proportional to the square of the radius. This means that if the radius is doubled, the terminal speed will quadruple.

v = (2mg)/(pCπr^2)

If r = 2r, then v = (2mg)/(pCπ(2r)^2) = 4 * (2mg)/(pCπr^2) = 4v

Therefore, the terminal speed will quadruple.

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Answer:

2. 1000N to the west

3. unbalanced

Answer:

The horizontal distance is 136.6 m.

Explanation:

Given that,

Initial speed = 38 m/s

Angle = 34°

Suppose, Calculate the horizontal distance \(x_{max}\) in meters the ball has traveled when it returns to ground level.

We need to calculate the horizontal distance

Using formula of range

\(R=\dfrac{v_{0}^2\sin(2\theta)}{g}\)

Where, v= speed

g = acceleration due to gravity

Put the value into the formula

\(R=\dfrac{(38)^2\sin(2\times34)}{9.8}\)

\(R=136.6\ m\)

Hence, The horizontal distance is 136.6 m.

The value is equal to 18.26*10^6 dollars/ounces.  

To find the answer, we have to know about the Cullinan diamond.

                     \(21.9 Ounce= 621.35g=400*10^6 dollars\\\\value=\frac{400}{21.9} *10^6dollars/ounce=18.26*10^6dollars/ounce\)

Thus, we can conclude that, the value is equal to 18.26*10^6dollars/ounces.                  

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Answer: a fuse wire is a wire of high resistance and low melting point.

Answer:

When I gently push the end of the ruler down then let go, I heart and feel a slight vibration from the ruler. When I push it down harder, I feel and hear the same thing, just at a more intense frequency.

—--------------------------------------------------------------------------------------------------------------

Dog Barking

Timer

Microwave

Voice

Knocking on door

Car Coming Down Driveway

Typing

Foot Steps

Mouse clicking

Breathing

These were mostly easy except thinking of the last few were a little harder, it wasn't hard to organize them because I just had to think of the intensity of the sounds and rank them from loudest to softest.

Explanation:

Hope this helps!

(1) Ruler Experiment and Explanation: You may make a faint sound by allowing the ruler to vibrate while you slowly lower the end of the ruler over the edge of a table. Changes in the sound's energy, amplitude, intensity, and decibel level are what cause the difference:

Energy: Injecting additional energy into the ruler by pulling it more firmly. The ruler vibrates more as a result of the increased energy, which increases the number of sound waves produced.

Amplitude: The largest displacement of an object, while it is vibrating, is referred to as its amplitude. Higher sound waves are produced when the pull is stronger, since this causes greater vibrations with a higher amplitude.

Intensity: The amount of energy that sound waves carry per unit area is known as their intensity. A stronger draw causes more energy to be transferred to the air, boosting the sound's volume.

Decibel (dB):  unit is used to measure the strength of sound. The sound gets louder and the decibel level rises as you pull the ruler further. Decibel measurements can be used to compare the two pulls' sound intensities.

Hence, due to energy, the ruler vibrates more, amplitude gives the displacement of the ruler, intensity is increased due to higher draw, and decibel measure, the strength of sound.

(2) Listening to Environmental Sounds

Depending on a person's knowledge of musical concepts and their capacity to discern between high and low frequencies, ranking sounds by pitch might be very simple or complex. Ten sounds are listed below, ranked from the highest pitch to the lowest pitch:

Whistle

Birds singing

dogs bark

Auto horn

Doorbell

musical note

music note

singing voice of a human

A drumbeat

a hefty item thudding

It could be difficult for someone who isn't used to recognizing frequency variances to rank sounds by pitch. Higher-pitched sounds are simpler to distinguish for people with musical training or a great sense of hearing. It might be more difficult for people who aren't as knowledgeable about musical details to distinguish between some sounds, especially if the pitch variances are slight.

Hence, it could be difficult for someone who isn't used to recognizing frequency variances to rank sounds by pitch. Higher-pitched sounds are simpler to distinguish for people with musical training or a great sense of hearing.

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When the net magnetic field is zero at a certain point, a neutral point is created. 

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A section of a sphere is mirrored on both sides. If the magnification of an object is +3.70 the magnification is -4.70.

The magnification of an object at the same distance in front of the convex side of the mirrored section of a sphere can be found using the mirror equation:
1/f = 1/di + 1/do
where f is the focal length of the mirror, di is the distance of the object from the mirror, and do is the distance of the image from the mirror.
Since the section is mirrored on both sides, the focal length of the concave and convex sides will be the same. Therefore, we can use the magnification equation:
m = -di/do

where m is the magnification.
We know that when the section is used as a concave mirror, the magnification is +3.70. Therefore,
+3.70 = -di/do

Solving for do, we get
do = -di/3.70
Now, substituting this value of do into the mirror equation, we get
1/f = 1/di - 3.70/di
Simplifying this equation, we get
f = di/4.70
Therefore, the magnification of an object at the same distance in front of the convex side of the mirrored section will be
m = -di/(di/4.70)
m = -4.70

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Answer: C. They are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere

Explanation:

Sunspots appear dark because they are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere.

Sunspots are typically cooler than their surroundings. For example, the temperature of a large sunspot can be about 4,000 Kelvin which is lower than the temperature of the photosphere around it which is about 5,800 Kelvin.

3 electrical equipments consider for this circuit diagram are,

1. Ammeter

2. Resistance

3. Resistance

The circuit diagram with 6 lamps and 3 electrical equipments and 1 power source with open circuit form is represented as,

1. ∑F=m.a

60 - 45 = 100 . a

a = 0.15 m/s²

2. the force of pushing up canceled by the force of gravity pulling the car down, so the force must gravity pull down on the car > 782 N

if the weight of the sdof is 20 kips and the stiffness is 50 kips/in, the natural frequency period of the structure is  12.5 seconds.

In structural dynamics, the natural frequency of a Single Degree of Freedom (SDOF) system is a characteristic property that describes how quickly the system oscillates or vibrates. The natural frequency is determined by the mass of the system and its stiffness.

To calculate the natural frequency, we need to convert the weight to mass and use the formula:

fn = 1 / (2π) * √(k / m)

First, let's convert the weight to mass:

Weight = mg

20 kips = m * 386.4 in/s² (acceleration due to gravity)

m = 20 kips / 386.4 in/s²

m = 51.73 lb/s²

Now, we can calculate the natural frequency:

fn = 1 / (2π) * √(k / m)

fn = 1 / (2π) * √(50 kips/in / 51.73 lb/s²)

fn ≈ 0.080 Hz

Finally, we can calculate the natural frequency period:

Period (T) = 1 / fn

T ≈ 1 / 0.080 Hz

T ≈ 12.5 seconds

Therefore, the correct natural frequency period of the SDOF structure is approximately 12.5 seconds.

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Answer:

9.26 km/h

Explanation:

Applying,

V' = D'/t'............... Equation 1

Where V' = Average speed, D' = Total distance, t' = total time.

Given: D' = 5 km

But,

v = d/t............ Equation 2

Where v = speed , d = distance, t = time

t = d/v............ Equation 3

Given: d = 4.5 km, v = 9 km/h, and d = 0.5 km, v = 12.5 km/h

Therefore,

t₁ = 4.5/9 = 0.5 hours

t₂ = 0.5/12.5

t₂ = 0.04 hours

Therefore,

V' = 5/(0.5+0.04)

V' = 5/0.54

V' = 9.26 km/h

Answer:

Protons and Electrons

For every proton in an atomic center, somewhere, in an orbital, there will be an electron. A proton carries a positive charge (+) and an electron carries a negative charge (-), so the atoms of elements are neutral, all the positive charges canceling out all the negative charges.

Explanation:

thank me later

The resistance of the electric heating element can be determined using Ohm's law, which states that resistance (R) is equal to voltage (V) divided by current (I). In this case, the voltage across the element is given as 232 volts and the current flowing through it is 19 amperes. The correct option is 12 ohms.

Applying Ohm's law, we calculate the resistance as:

R = V / I

R = 232 volts / 19 amperes

R ≈ 12 ohms

Therefore, the resistance of the element is approximately 12 ohms. This means that for every ampere of current flowing through the element, there is a voltage drop of 12 volts. The resistance value of 12 ohms indicates that the element has a moderate level of electrical resistance, which allows it to generate heat efficiently when current flows through it. Thus, the correct option is 12 ohms.

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Answer:

77.8 g potassium bromide can be dissolved in 100 grams of water at 40°C.

Explanation:

In a given a line of KBr is straight.

One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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True, when a boxer hits a punching bag, the strength of his punch does depend on the force the bag exerts on the boxer's fist.

This concept can be explained using Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.When the boxer's fist makes contact with the punching bag, the fist exerts a force on the bag. Simultaneously, the bag exerts an equal and opposite force back onto the fist. This force experienced by the fist is what determines the strength of the punch.

The magnitude of the force exerted by both the fist and the bag is determined by various factors such as the mass of the boxer's arm, the speed of the punch, and the material and mass of the punching bag. A greater force exerted on the bag will result in a greater force exerted back onto the fist, thus increasing the strength of the punch.

In conclusion, the statement is true; the strength of a boxer's punch is dependent on the force exerted by the punching bag on the boxer's fist, which is a result of the equal and opposite reaction dictated by Newton's Third Law of Motion.

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The wavelength of tuba note which having frequency of 9. 18 Hz and velocity 343 m/s is 37.36 m

A waveform signal's wavelengths, which is the distance between two identical locations (consecutive crests) in successive cycles, determines whether it is sent through space or via a wire. For wavelength, a Greek letter λ is frequently used. In wireless systems, this length is often specified in meters (m), centimetre (cm), or millimetre (mm) (mm).

Given data -

frequency (f) = 9. 18 Hz

velocity (v) = 343 m/s

By using the relation -

v = f × λ

Where 'λ' is wavelength

λ = v / f

λ = 343 / 9.18

λ = 37.36 m

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