what determines the types of chemical reactions that an atom participates in? what determines the types of chemical reactions that an atom participates in? the number of protons it contains its atomic number the number of electrons in the outermost electron shell the number of electrons in the innermost electron shell its atomic mass

The solid with the smaller lattice energy will be more soluble in water.

This is because the lattice energy represents the energy required to break apart the ionic solid and separate the ions. Therefore, the larger the lattice energy, the stronger the bonds between the ions and the more difficult it is for water molecules to break them apart and dissolve the solid. On the other hand, the smaller lattice energy means weaker bonds between the ions, making it easier for water molecules to interact with and dissolve the solid. So, solubility is inversely proportional to lattice energy.

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Answer: 15 mol

Explanation:

From the equation, we know that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

So, the answer is 5(3) = 15 mol

Answer:

drops a glass cup of water outcome mad parents

Explanation:

Mad pagents mean death no surviva.

Answer: —The processes of seafloor spreading, rift valley formation, and subduction (where heavier tectonic plates sink beneath lighter ones) were not well-established until the 1960s. These processes were the main geologic forces behind what Wegener recognized as continental drift.

Explanation:

Answer:

2.068

Explanation:

D = M/V

3.04 /1.47

= 2.068

In two moles of NH3, there are 12.04 × 10²³ molecules. Ammonia is a gas that is colorless, extremely unpleasant to breathe, and causes choking.

Concentrations exceeding 5000 ppm typically result in abrupt respiratory arrest, while concentrations between 2500 and 4500 ppm can be lethal in about 30 minutes. Skin injury can be induced by anhydrous ammonia at concentrations higher than 10,000 parts per million.

80% of the ammonium produced by businesses is employed as fertilizer for agriculture. Ammonia is also used to create polymers, explosives, textiles, pesticides, dyes, and other compounds in addition to its various applications.

6.02×10²³ atoms, molecules

one mole NH₃

= 6.02×10²³ molecules

= 2 × (6.02×10²³ )

= 12.04 × 10²³ molecules.

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Answer:

god loves you i love u

everybody loves you

Answer:

Did you put that in right because i've never heard of a compound called that nor is there a compound called that on the internet

Explanation:

You must of put that in wrong

Carrier proteins serve many purposes in the purposes in the attempt to move molecules across a plasma membrane.

Carrier proteins are proteins which are found n the surfaces of cell membranes which serve the function of transporting molecules across the cell membrane barrier.

The carrier proteins transport various molecules across the cell membrane.

Carrier proteins transport such molecules as sugars, proteins, ions, lipids across the membrane.

Some carrier proteins expend energy in the form of ATP when they transport molecules across the cell membrane.

Some use the concentration gradient of cells to transport molecules across the cell membrane.

The carrier proteins which expend energy to transport molecules are involved in active transport.

The carrier proteins that do not expend energy are involved in passive transport.

In conclusion, carrier proteins are essential in the transport of molecules across the plasma membrane.

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A certain reaction has an activation energy of 58.74 kj/mol. At 507 kelvin temperature, the reaction proceed 7.00 times faster than it did at 337 k.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances. The most popular scales are the Kelvin scale (K), which is mostly used for scientific purposes, the Fahrenheit scale (°F), and the Celsius scale, which has the unit symbol °C.

1/T2 - 1/T1 = -Ea/(R×ln(k2/k1))

1/T2 - 1/T1 = -Ea/(R×ln7)

T2 = 1/(1/T1 - Ea/(Rln(7)))

T2 = 1/(1/337 - 58.74/(8.314×1.94591)) = 507 K

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Answer:

CuO + H2SO4 = CuSO4 + H2O  

Reaction type: double replacement

Answer:

A

Explanation:

........................

Answer:

push or pull i think..okay?

Answer:

3.495

Explanation:

pH = -log of H⁺ concentration, so the answer is 3.495

The pressure exerted by the neon gas, when the volume is increased from 7.2 mL to 28.8 mL at constant temperature, can be calculated using Boyle's Law. The pressure exerted by the neon gas, when the volume is increased to 28.8 mL at constant temperature, is 0.375 atm.

Boyle's Law states that at constant temperature, the product of the pressure and volume of a gas remains constant. Mathematically, it can be expressed as P₁V₁ = P₂V₂. This law allows us to calculate the change in pressure when the volume changes.

In this case, the initial volume (V₁) is given as 7.2 mL, and the initial pressure (P₁) is 1.5 atm. The final volume (V₂) is 28.8 mL. By substituting these values into Boyle's Law equation, we can solve for the final pressure (P₂).

When we perform the calculations, we find that the pressure exerted by the neon gas, when the volume is increased to 28.8 mL, is 0.375 atm. As the volume increases, the pressure decreases due to the inverse relationship between pressure and volume.

Using Boyle's Law: P₁V₁ = P₂V₂

Given:

Initial volume (V₁) = 7.2 mL

Initial pressure (P₁) = 1.5 atm

Final volume (V₂) = 28.8 mL

To find the final pressure (P₂):

P₂ = (P₁ * V₁) / V₂

  = (1.5 atm * 7.2 mL) / 28.8 mL

  = 0.375 atm

Therefore, the pressure exerted by the neon gas, when the volume is increased to 28.8 mL at constant temperature, is 0.375 atm.

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Answer: jongho

Explanation:

Answer:

Choi JongHo

Explanation:

Answer:transfer oxygen through your blood

Explanation:

Answer:

coordinate the muscles that control breathing

hope this helps ⭐

In 1933, the initial rock sample contained 11.29 grains of strontium-90.

The half-life of strontium is 28.8 years. Therefore,

1999 - 1943 = 56 years.

1.94 half-lives for 56 / 28.8

As a result, for each half-life that passes, the radioisotope's remaining amount will double. time-traveling backward.

The quantity left will therefore increase by 1.94 times when time is advanced by 1.94 half-lives.

Consequently, the amount left over in 1943 is

3.0 × (1.94)² = 11.29 grams

Nuclear fallout contains the radioactive element strontium-90, a byproduct of nuclear reactors. The half-life of it is 28 years.

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Answer:

0.60g of the fungus can be allowed

Explanation:

The maximum concentration of the fungus that can be allowed is 25 ppb, that is 25mg/t.

As the peanuts are 24t, the mass of fungus that can be allowed is:

24t * (25mg/t) = 600mg of the fungus can be allowed. In grams are:

600mg * (1g/1000mg) =

Answer:

0.5g of toxin

Explanation:

ppb = mass of solute/ mass of solution x 10^9

ppb = mass of fungus/ mass of peanuts x 10^9

25ppb = (x/2 x 10^7g) x 10^9

x = (25)(2 x 10^7g)/ 10^9

x = 0.5g of toxin

x represented the unknown mass of solute (fungus), in which we solved for. We already knew we were using the ppb formula, which is mass of solute/ mass of solution x 10^9, because the question mentions that there are 25ppb of peanuts in the shipments. In the calculations, you can see that I substituted the mass of peanuts with 2 x 10^7g. I did this because the question mentions that there are 20t of peanuts and since each t = 1000kg, I multiped 20 x 1000 to get 20 000kg. In my formula for ppb, I know that I have to use grams of solution, not kilograms. Knowing this, we follow the formula for ppb and substitute our known values and solving for unknown values.

The standard cell potential for this constructed cell is 0.44 V.

To calculate the standard cell potential (E°cell) of this particular cell, we need to use the equation E°cell = E°cathode - E°anode.

In this case, the silver electrode (Ag) is the cathode and the copper electrode (Cu) is the anode. Therefore, E°cathode = E°Ag/Ag = 0.80 V and E°anode = E°\(\frac{Cu}{Cu_{2} }\)+ = 0.36 V.

Substituting these values into the equation, we get E°cell = 0.80 V - 0.36 V = 0.44 V.

Therefore, the standard cell potential for this constructed cell is 0.44 V.

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Answer:

because the lighted splint is burnt and the water and carbon dioxide starts to explode

Answer:

C

Explanation:

I am not 100% sure, but it might be the answer.

Resistance to certain pests, diseases, or environmental variables as well as resistance to chemical treatments are frequently a living thing whose genome contains foreign DNA.

Genetically modified organisms are described as having had their DNA altered via genetic engineering techniques (GMO). Over thousands of years, mankind have modified species using breeding methods. Years of selective breeding have been used to breed dogs, cattle, and even corn to produce particular desirable traits .

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Answer:

The atom that loses the electrons becomes a positively charged ion, while the one that gains them becomes a negatively charged ion

A decomposition reaction is a chemical reaction in which one reactant breaks down into two or more products.

A metathesis reaction is a chemical reaction in which the positive ions and negative ions present in the reactants appear to exchange partners.

assuming all of the xenon has reacted, The formula of the product is XFe2

In this situation, xenon and fluorine are reacting to form a binary compound. The reaction can be viewed by the below balanced chemical equation:

Xe + 2F2 -> XeF2

The reactants, xenon and fluorine, are initially present at partial pressures of 1.24 atm and 10.10 atm, respectively.Since the reactants are initially present at a total partial pressure of 1.24 atm + 10.10 atm = 11.34 atm, and the final partial pressure of fluorine is 7.62 atm, the partial pressure of the xenon fluoride compound must be 11.34 atm - 7.62 atm = 3.72 atm.

we can set up the following equation:1.24 atm + 10.10 atm = 3.72 atm + 7.62 atm

Solving for the number of moles of fluorine gives:

10.10 atm - 3.72 atm = 7.62 atm

= 6.38 atm

Since the pressure of a gas is directly proportional to the number of moles of the gas present,

n = P / (R * T

= 6.38 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.5 molThe number of moles of xenon present can be calculated in a similar way:

n = P / (R * T

= 1.24 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.05 mol

Since the ratio of moles of xenon to moles of fluorine in the product is 1:2, the formula of the product must be XeF2.

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Answer:

are you sure it is 95%?????

Explanation:

Answer:

35.5 this is the answer ok

Answer:

A= 2.3g

B= 1.2L

Explanation:

a) Find the mass of the reacted metal

2Na    +     Cl2     →    2NaCl

46               71                 117

X                                   5.85

From the chemical equation

117/5.85 = 46/x

X= (46x5.85)/117

 = 2.3g

So, the mass of the reacted metal is 2.3g

b) Find the volume of the reacted gas at STP

at STP: 71g of CL2 has 22.4l

              Y  of Cl2 has V

V= (Y x 22.4L) / 71                   where y=?

From the chemical equation

117 / 5.85 = 71 / Y

Y= (71x5.85) / 117

  = 3.55

V= (3.55x22.4) / 71

 = 1.12L

So, the volume of the reacted gas at STP is 1.12L

Answer:

72.66g of Fe2O3 are produced.

Explanation:

1st) From the balanced equation we know that 2 moles of Fe2O3 are produced from 4 moles of iron (Fe). With a mathematical rule of three we can calculate the moles of Fe2O3 that will be produced from 0.89 moles of iron:

Now we know that 0.455 moles of Fe2O3 are produced.

2nd) Now we have to convert 0.455 moles of Fe2O3 into grams, by using the molar mass of Fe2O3 (159.7g/mol):

So, 72.66g of Fe2O3 are produced.

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)   

\(\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles\)

The balanced chemical equuation is:

\(4Al+3O_2\rightarrow 2Al_2O_3\)  

According to stoichiometry :

4 moles of \(Al\) produce == 2 moles of \(Al_2O_3\)

Thus 0.556 moles of \(Al\) will produce=\(\frac{2}{4}\times 0.556=0.278moles\)  of \(Al_2O_3\)

Mass of \(Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g\)

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.