What do these weapon stats mean?

Idle sway control is measured in Fc???

Flinch resistance is measured in N.

Answer:

you could put the iron filings on the peace of paper and hover a magnet over top of the paper and the iron filings would stand up, or even stick to the magnet

Explanation:

Answer: B

Explanation: B is the correct statement describing the positions of the Moon, the Sun, and the Earth during a new moon. The Moon is between Earth and the Sun.

During a new moon, the Moon is positioned between the Sun and the Earth, with the illuminated side of the Moon facing away from the Earth. This means that the side of the Moon that faces the Earth is not receiving any sunlight, making it invisible to us from Earth. The new moon is the first phase of the lunar cycle and occurs roughly every 29.5 days.

Following are the answers:

1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:

Pressure = force/area

The force is the weight of the water column and the area is the cross-sectional area of the container.

The weight of the water column is given by the mass of the water times the acceleration due to gravity:

mass = density x volume

volume = area x height

So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg

Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N

The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)

So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa

2. To calculate the density of the oil, we can use the formula:

density = mass/volume

Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.

We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:

Pressure = force/area = density x acceleration due to gravity x height

So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.

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Answer:

Explanation:

Answer:

See below

Explanation:

Here are a couple of options..... one where the object slows to a rest and the other where the object stops to a rest instantaneously

Answer:

William Gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

Answer:

william gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

We are given two points on the distance-time graph: (1, 40) and (3,130)

This means that:

At time 1 hour, the distance traveled was 40 km

At time 3 hours, the distance traveled was 130 km

We want to find the average speed during this 2 hour interval (from 1 hour to 3 hours).

Average speed is defined as:

Average Speed = Change in Distance / Change in Time

The change in distance is the distance traveled from 1 hour to 3 hours, which is 130 km - 40 km = 90 km

The change in time is 3 hours - 1 hour = 2 hours

Average Speed = 90 km / 2 hours

= 45 km/hr

Therefore, the average speed during this interval of time is 45 km/hr.

a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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Answer: ummm arent you in my physical fundations class lol

Explanation:

are you or am i tripping? and sorry i dont have the answer :(

Common reasons people give for not being active include not having enough time, finding physical activity inconvenient, lacking self-motivation, etc.

Any consensual bodily mobilization generated by skeletal muscles that necessitate caloric expenditure is characterized as physical activity.

Physical activity includes all activities of any frequency, at any moment of day or night. It incorporates both strength training and incidental activity into the daily routine.

Physical activity can improve your brain health, help you manage your weight, lower your risk of disease, strengthen your bones and muscles, and improve your ability to do everyday tasks.

Adults who sit less and engage in moderate-to-vigorous physical activity reap health benefits.

Internal barriers were classified into three types namely, a lack of energy, a lack of motivation, and a lack of self-efficacy.

External barriers were also classified into three categories namely a lack of resources, a lack of social support, and a lack of time.

Thus, these are some reasons that may not prepare to be safe and comfortable when they participate in physical activity

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Answer:

Angle of incline is 20.2978°

Explanation:

Given that;

Gravitational acceleration on a planet a = 3.4 m/s²

Gravitational acceleration on Earth g = 9.8 m/s²

Angle of incline = ∅

Mass of the stone = m

Force on the stone along the incline will be;

F = mgSin∅

F = ma

The stone has the same acceleration as that of the gravitational acceleration on the planet.

so

ma = mgSin∅

a = gSin∅

Sin∅ = a / g

we substitute

Sin∅ = (3.4 m/s²) / (9.8 m/s²)

Sin∅ = 0.3469

∅ = Sin⁻¹( 0.3469 )

∅ = 20.2978°

Therefore, Angle of incline is 20.2978°

While certain types of glass containers may be suitable for short-term storage of vinegar, it is generally recommended to use non-reactive materials, such as plastic or stainless steel, for long-term storage to avoid any potential chemical reactions or corrosion.

Vinegar is an acidic liquid that contains acetic acid. When vinegar comes into contact with certain types of glass, particularly those made of lead or other reactive materials, a chemical reaction can occur. This reaction can lead to the leaching of potentially harmful substances into the vinegar.

Glass containers made from specific types of glass, such as soda-lime glass, are generally safe for storing vinegar.

However, it is important to note that prolonged storage or exposure to vinegar can still cause the glass to corrode over time. This can result in the deterioration of the glass container, potentially leading to breakage or the release of glass fragments.

To avoid any potential issues, it is recommended to use containers made of non-reactive materials, such as food-grade plastic or stainless steel, for long-term storage of vinegar. These materials do not react with the acidic nature of vinegar and do not pose a risk of leaching harmful substances.

Additionally, it is important to store vinegar in a cool, dark place to maintain its quality and prevent spoilage. Exposure to light and heat can degrade the quality of vinegar over time.

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Answer:

Explanation:

Magnetic field due to a solenoid

B = μ₀ nI  where n is no of turns per unit length and I is current

for outer  layer of turns

B = μ₀  x (250 / .3) x 3

= 4π x 10⁻⁷ x (250 / .3) x 3

= 3.14 x 10⁻³ T  

for inner layer of turns

B = μ₀  x (300 / .3) x 3

= 4π x 10⁻⁷ x (300 / .3) x 3

= 3.77 x 10⁻³ T

Total magnetic field

= (3.14 + 3.77 ) x 10⁻³ T  

= 6.91 x 10⁻³ T  .

The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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Answer: Calculate the energy required in joules to raise the temperature of 450 grams of water from 15°C to 85°C? (The specific heat capacity of water is 4.18 J/g/°C)

Explanation:

The quantity of heat is required to raise the temperature of of water is 94050 joule.

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.

The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that the total energy of the system is conserved in a closed system, also known as an isolated system.

Mass of water: m = 450 grams

Initial temperature of water = 35° C

Final temperature of water = 85° C

Capacity of water is 4.18 J/g °C.

Hence, the  quantity of heat is required to raise = mass × Capacity  × raise in temperature

= 450 × 4.18 × (85 - 35) joule

= 94050 joule.

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Answer:

Explanation:

2.Big bang, 3.contraction of the solar nebula, 5.stellar ignition in our sun, 4.outgassing of earths secondary atmosphere, 1.appearance of the first ocean on earth ,7.evolution of photosynthesis, 6.build- up of oxygen in earths atmosphere.

a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

b) We cannot calculate the work done by the friction force.

c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:

Work_gravity = force_gravity * displacement * cos(theta),

where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).

The weight of the block is given by:

force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.

Plugging in the values, we get:

Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.

The work done on the 6.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.

The negative sign indicates that the tension is in the opposite direction of the displacement.

Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:

Work_net = change_in_kinetic_energy.

Since the block starts from rest, its initial kinetic energy is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.

Solving for velocity, we get:

velocity = sqrt(2 * Work_net / mass).

The net work done on the block is the sum of the work done by gravity and the tension:

Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.

Plugging in the values, we get:

velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.

Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.

The work done on the 8.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.

The work done on the 8.00 kg block by the friction force can be calculated using the formula:

Work_friction = force_friction * displacement * cos(theta),

where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.

(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.

Simplifying, we get:

Work_net = 1/2 * 14.00 kg * velocity^2.

Using the value of velocity calculated in part (a), we get:

Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.

The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:

Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.

The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:

Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.

Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.

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Answer:

Our star is powered by nuclear fusion, and it turns hydrogen into helium in a process that converts mass into energy. Once the fuel supply is gone, the sun will start growing dramatically. Its outer layers will expand until they engulf much of the solar system, as it becomes what astronomers call a red giant.

Explanation:THERE YOU GO

Answer:

Once all the helium disappears, the forces of gravity will take over, and the sun will shrink into a white dwarf. All the outer material will dissipate, leaving behind a planetary nebula. "When a star dies, it ejects a mass of gas and dust — known as its envelope — into space.