Answer:
Sun
Explanation:
he sun is a big ball of burning plasma it cuases light the sun is the seco d hottest object in the universe the sun another fact is we learned the sun isn't even a solid it's bassiclly a ball of energy or a constant flaming ball of plasma hydrogen and heluim if the sun went out we would live in darkness forever not to mention we would frezze to death
write down the way you had to behave to illustrate the behavior of particles as a gas condenses to form a liquid
Gases near together and vibrate in position however, don't circulate beyond each other. In a liquid, the particles are interested in every different but now not as a great deal as they may be in a strong.
The particles of a liquid are near together, constantly transferring, and may slide beyond one another. The Kinetic-molecular concept attempts to explain the behavior of fuel molecules based totally on the nature of gasoline. The principle is grounded on simple assumptions
In gases the debris passes swiftly in all directions, regularly colliding with every different facet of the box. With a boom in temperature, the debris gains kinetic strength and passes more quickly. Gasoline is a state of matter that has no constant form and no fixed extent. Gases have a decreased density than other states of the count, together with solids and liquids. there may be a high-quality deal of empty area between debris, that have loads of kinetic energy and aren't especially drawn to one another.
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Classify each property as physical or chemical.
a) the tendency of copper to turn green when exposed to air
b) the tendency of automobile paint to dull over time
c) the tendency of gasoline to evaporate quickly when spilled
d) the low mass (for a given volume) of aluminum relative to other metals.
a) Chemical property
b) Physical property
c) Physical property
d) Physical property
a) The tendency of copper to turn green when exposed to air is a chemical property because it involves a change in the chemical composition of the copper due to a chemical reaction with oxygen in the air.
When copper is exposed to air, it reacts with oxygen and forms a layer of copper oxide on its surface. Over time, this layer of copper oxide can further react with carbon dioxide and moisture in the air to form a green patina known as copper carbonate. The patina not only changes the appearance of copper, but it also protects the underlying metal from further oxidation and corrosion.
The green patina formed on copper has been used for decorative purposes in architecture, sculpture, and art for centuries. It is also commonly seen on copper roofs, statues, and other outdoor copper fixtures.
b) Automobile paint is typically composed of a clear coat layer, a color coat layer, and a primer layer, all of which are designed to protect the underlying metal from corrosion and provide a decorative finish. However, when exposed to oxygen and ultraviolet (UV) radiation from the sun, the molecules in the paint can break down and react with the air, causing the paint to lose its gloss and become dull.
The UV radiation from the sun causes the paint to oxidize, which leads to the formation of tiny cracks and pits in the paint's surface. These cracks and pits scatter the light that falls on the paint, giving it a cloudy and dull appearance. Additionally, exposure to pollutants and contaminants, such as dirt, dust, and salt, can accelerate the oxidation process and further damage the paint.
c) Gasoline is a mixture of hydrocarbons, which are molecules made up of hydrogen and carbon atoms. The hydrocarbons in gasoline have relatively low boiling points, which means that they can easily evaporate into the air. When gasoline is spilled, the hydrocarbons in the liquid begin to vaporize, turning into a gas and escaping into the surrounding air.
The rate at which gasoline evaporates depends on a number of factors, including temperature, humidity, and air flow. In warm, dry conditions with good air flow, gasoline can evaporate quickly, sometimes within minutes. In cooler, more humid conditions with less air flow, evaporation may be slower.
d) Aluminum has a relatively low mass for a given volume compared to other metals due to its low density. The density of aluminum is about one third that of steel, which is a common structural metal. This low density is due to the atomic structure of aluminum, which has a relatively low atomic mass compared to many other metals.
Aluminum has an atomic number of 13, which means it has 13 protons in its nucleus. This gives it a relatively low atomic mass compared to metals like iron, copper, and zinc. In addition, aluminum has a face-centered cubic crystal structure, which allows its atoms to be packed closely together without creating a lot of empty space. This results in a material with a relatively low density, even though it is a metal.
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what volume of 0.100 m na3po4 is required to precipitate
Therefore, 562.5 mL (or 0.5625 L) of the 0.100 M Na₃PO₄ solution is required to precipitate all the lead(II) ions from 150.0 mL of 0.250 M Pb(NO₃)₂.
To determine the volume of 0.100 M Na₃PO₄ needed to precipitate all the lead(II) ions from 150.0 mL of 0.250 M Pb(NO₃)₂, we first need to determine the stoichiometry of the reaction between Na₃PO₄ and Pb(NO₃)₂ and then use the concept of stoichiometry to calculate the volume.
The balanced chemical equation for the reaction between Na₃PO₄ and Pb(NO₃)₂ is:
3Na₃PO₄ + 2Pb(NO₃)₂ → Pb₃(PO₄)₂ + 6NaNO₃
From the equation, we can see that the ratio of Na₃PO₄ to Pb(NO₃)₂ is 3 ratio 2.
To find the number of moles of Pb(NO₃)₂ present in the given volume (150.0 mL), we use the formula:
moles = concentration × volume
moles of Pb(NO₃)₂ = 0.250 M × 0.150 L = 0.0375 moles
According to the stoichiometry, 3 moles of Na₃PO₄ are needed to react with 2 moles of Pb(NO₃)₂.
Therefore, the moles of Na₃PO₄ required would be:
moles of Na₃PO₄ = (3/2) × moles of Pb(NO₃)₂ = (3/2) × 0.0375 = 0.05625 moles
Now, we can use the formula for moles to determine the volume of the 0.100 M Na₃PO₄ solution required.
volume = moles / concentration
volume = 0.05625 moles / 0.100 M = 0.5625 L = 562.5 mL
Therefore, 562.5 mL (or 0.5625 L) of the 0.100 M Na₃PO₄ solution is required to precipitate all the lead(II) ions from 150.0 mL of 0.250 M
Pb(NO₃)₂.
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30.A pharmacist receives an order for 60 mL of an oral solution containing memantine hydrochloride (NAMENDA) 1.5 mg/mL. She has on hand a 360-mL bottle of oral solution containing memantine hydrochloride, 10 mg/5 mL, and a diluent of sorbitol solution. How many milliliters each of the available oral solution and sorbitol solution may be used to fill the order
To make 60 mL of a 1.5 mg/mL solution of memantine hydrochloride, we need to mix 2 mL of the available solution (10 mg/5 mL) with 270 mL of a diluent (sorbitol solution).
The concentration of memantine hydrochloride in the available solution is (10 mg/5 mL). This solution is too strong for the requested concentration of 1.5 mg/mL. Therefore, it must be diluted to obtain the desired concentration. We are asked to determine the amount of diluent and the amount of available solution to be mixed to produce 60 mL of the desired solution containing 1.5 mg/mL. This can be done by using the following equation:
Concentration1 × Volume1 = Concentration2 × Volume2
The total amount of drug (memantine hydrochloride) needed to make 60 mL of a 1.5 mg/mL solution is
1.5 × 60 = 90 mg.
To determine the amount of the available solution to use, we can use the concentration of memantine hydrochloride in the available solution:
10 mg/5 mL = 2 mg/mL
If we add 2 mL of this solution to the diluent, the new concentration of memantine hydrochloride will be
(2 mg/mL)/6 = 0.33 mg/mL.
This new concentration is still too strong, so we will need to add more diluent. We can calculate how much diluent to add by using the following equation:
(2 mL)/(6 mL) = (90 mg)/(V2)
Solving for V2, we find that we need
V2 = 270 mL of diluent to obtain a 1.5 mg/mL solution.
To make 60 mL of a 1.5 mg/mL solution of memantine hydrochloride, we need to mix 2 mL of the available solution (10 mg/5 mL) with 270 mL of a diluent (sorbitol solution).
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How many grams are there in 7.9 X 10^23 molecules of AgNO3?
Answer:$$7.50 x 10^23$$
$$H_2SO_4$$?
Explanation:It is a fact that such a quantity has a mass of
98.08
⋅
g
. Why? Because
6.022
×
10
23
particles SPECIFIES a molar quantity. And we know (or can calculate) that sulfuric acid has a molar mass of
98.08
⋅
g
...
An isotope of an element has:
more protons
less protons
a different atomic mass
the same number of neutrons
Answer:
Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.
Explanation:
empirical formula of c3h12o6
Answer:
\(CH_{4} O_{2}\)
Explanation:
The empirical formula is the simplest whole-number ratio of the elements in a compound to one another. To find the empirical formula given a molecular formula, divide all the subscripts by their greatest common factor.
3, 12, and 6 can all be divided by 3, which makes the empirical formula \(CH_{4} O_{2}\)
Which determines the reactivity of an alkali metal?
its boiling and melting points
the shininess of its surface
the number of protons it has
its ability to lose electrons
Answer:
its ability to lose electron
The reactivity of an alkali metal is determined by its ability to loose electrons.
The alkali metals are highly electropositive. They easily loose electron to form a univalent positive ion.
This ability to form a univalent positive ion increases down the group hence cesium is the most electropositive element in nature.
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what is the effect on the boiling point of a solution produced by an insoluble nonvolatile substance ?
Answer:
nothing
Explanation:
hope this helps ;)
Balance the equation hbr + khco3 > h2o + kbr + co2
Answer:
It is already balanced
Explanation:
hbr + khco3 ===> h20 + kbr + co2 IS BALANCED
What is the general trend for electron affinity values going across a period?
Answer:
increase.
Explanation:
as you cross the period the atomic size decrease makes the atoms to have more affinity to the coming electrons.
When OSHA uses a TLV in regulations,
- The TLV becomes a mandatory PEL
- The PEL is non-mandatory
- It is required that the TLV be updated annually
- Updated TLVs automatically become updated PELs
When OSHA uses a TLV (Threshold Limit Value) in regulations, the TLV becomes a mandatory PEL (Permissible Exposure Limit). This means that employers must ensure workers' exposure to the hazardous substance does not exceed the established PEL, which is based on the TLV. OSHA enforces these PELs to protect workers from potential health hazards in the workplace.
When OSHA uses a TLV in regulations, the TLV becomes a non-mandatory recommendation for occupational exposure limits. OSHA has established its own Permissible Exposure Limits (PELs) which are legally enforceable and mandatory. While OSHA may consider TLVs when establishing or revising PELs, the TLV does not automatically become a PEL. OSHA may also use other sources of information to establish or revise PELs. Additionally, OSHA does not require that TLVs be updated annually, although some organizations that establish TLVs may choose to update them on a regular basis.
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A sample of fluorine gas at STP contains 4.088x10^24 atoms. What is the volume in liters of the sample?
Record your answer to 1 decimal place. Do not put units on your answer.
According to the concept of Avogadro's number and STP conditions volume in liters of the sample is 15,388.7.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number
Number of moles is obtained as, number of atoms/Avogadro's number=4.088×10²⁴/6.023×10²³=6.78 moles on substitution in formula of PV=nRT=V=6.78×8.314×273/1=15,388.7 liters.
Thus, the volume is 15,388.7 liters of the sample.
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how many hydrogen bonds connect adenine and thymine
Answer:
Hydrogen can make two bonds with Adenine and Thymine.
Explanation:
Adenine and thymine similarly pair via hydrogen bond donors and acceptors; however an AT base pair has only two hydrogen bonds between the bases.
Answer:
2 hydrogen bonds.
Explanation:
There are two hydrogen bonds between adenine and thymine.
Question 14 PM2.5 is defined as ________
- the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air greater than or equal to 2.5 micrometers in diameter. Question 15 Carbon dioxide (CO2) is a criteria air pollutant. - True - False Question 16 Roughly percent of emissions of carbon monoxide in Santa Clara County come from mobile sources (select the choice closest to the correct answer). - 50 - 75 - 25 Question 17
The term "photochemical smog" is most synonymous with which of the following criteria air pollutants? - lead (Pb) - carbon monoxide (CO) - sulfur dioxide ( SO2) - ozone (O3) Question 18 "Attainment" of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards. - True - False
: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.
Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.
Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.
Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.
Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.
Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.
Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.
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If 6.97 g of solid calcium metal reacts with 6.97 g of nitrogen gas in a combination reaction (only one product). How many grams of calcium nitride are formed
If 6.97 g of solid calcium metal reacts with 6.97 g of nitrogen gas in a combination reaction. The grams of calcium nitride formed is 0.0579 mol x 148.25 g/mol = 8.59 g.
To find the limiting reactant, the molar masses of calcium and nitrogen are needed. The molar mass of calcium is 40.08 g/mol, and the molar mass of nitrogen is 28.02 g/mol.
Next, the number of moles of each reactant is calculated by dividing the given masses by their respective molar masses. For calcium, 6.97 g / 40.08 g/mol = 0.1738 mol, and for nitrogen, 6.97 g / 28.02 g/mol = 0.2487 mol.
To determine the limiting reactant, the molar ratio between calcium and nitrogen in the balanced chemical equation is examined. The balanced equation for the reaction is:
3Ca + N2 -> Ca3N2
The ratio is 3:1, meaning that 3 moles of calcium react with 1 mole of nitrogen to form 1 mole of calcium nitride.
Comparing the calculated moles, it is evident that the number of moles of calcium is smaller than the number of moles of nitrogen. This indicates that calcium is the limiting reactant.
Using stoichiometry, the number of moles of calcium nitride formed can be calculated based on the limiting reactant. Since the molar ratio is 3:1 between calcium and calcium nitride, the moles of calcium nitride formed is 0.1738 mol x (1 mol Ca3N2 / 3 mol Ca) = 0.0579 mol.
Finally, the grams of calcium nitride formed can be determined by multiplying the moles of calcium nitride by its molar mass. The molar mass of calcium nitride (Ca3N2) is calculated as 148.25 g/mol (the sum of the atomic masses of calcium and nitrogen). Thus, the grams of calcium nitride formed is 0.0579 mol x 148.25 g/mol = 8.59 g.
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A 12.6 g block of a metal intially at a temperature of 94.0 °C is added to a 100.0 g sample of water intially at 21.0 °C. If the final temperature of the water is 25.1 °C, determine the specific heat of the metal. Write all equations or formulas you use, and show as much of your work as you can.
Answer:
The specific heat of the metal is 0.0482 joules per gram-Celsius.
Explanation:
Block of metal is cooled by adding water and thermal equilibrium is reached. According to the First Law of Thermodynamics and by supposing the absence of energy and mass interaction of the system with surroundings, the change in the energy of the system is represented by:
\(\Delta U_{m} + \Delta U_{w} = 0\)
Where \(\Delta U_{m}\) and \(\Delta U_{w}\) are the changes in internal energies of the block of metal and water, measured in joules.
The expression described above is now extended by applying the definition of internal energy for constant mass systems:
\(m_{m}\cdot c_{v,m}\cdot (T_{m,in}-T_{m,out}) + m_{w}\cdot c_{v,w}\cdot (T_{w,in}-T_{w,out})= 0\)
Where:
\(m_{m}\), \(m_{w}\) - Masses of the block of metal and water, measured in grams.
\(c_{v,m}\), \(c_{v,w}\) - Specific heats of the block of metal and water, measured in joules per gram-Celsius.
\(T_{in, m}\), \(T_{in, w}\) - Initial temperatures of the block of metal and water, measured in Celsius.
\(T_{out, m}\), \(T_{out, w}\) - Final temperatures of the block of metal and water, measured in Celsius.
The specific heat of the metal is cleared in the equation:
\(c_{v,m} = -\frac{m_{w}\cdot c_{v,w} (T_{w,in}-T_{w,out})}{m_{m}\cdot (T_{m,in}-T_{m,out})}\)
If \(m_{m} = 12.6\,g\), \(m_{w} = 100\,g\), \(c_{v,w} = 4,186\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{w,in} = 21\,^{\circ}C\), \(T_{m,in} = 94\,^{\circ}C\) and \(T_{m,out} = T_{w,out} = 25.1\,^{\circ}C\), the specific heat of the metal is:
\(c_{v,m} = -\frac{(100\,g)\cdot \left(4,186\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (25\,^{\circ}C-25.1\,^{\circ}C)}{(12.6\,g)\cdot (94\,^{\circ}C-25.1\,^{\circ}C)}\)
\(c_{v,m} = 0.0482\,\frac{J}{kg\cdot ^{\circ}C}\)
The specific heat of the metal is 0.0482 joules per gram-Celsius.
5.00g of calcium carbonate, when heated, produced 2.40 g of calcium oxide. which is the correct expression for the percentage yield of calcium oxide?
The correct expression for the percentage yield of calcium oxide is approximately 4808%.
To find the theoretical yield, we need to calculate the stoichiometric ratio between calcium carbonate (CaCO3) and calcium oxide (CaO). The balanced equation for the reaction is:
CaCO3 → CaO + CO2
From the equation, we can see that one mole of calcium carbonate produces one mole of calcium oxide. We can calculate the molar mass of calcium carbonate and calcium oxide to convert the given masses into moles:
Molar mass of CaCO3 = 40.08 g/mol (calcium) + 12.01 g/mol (carbon) + (3 x 16.00 g/mol) (oxygen) = 100.09 g/mol
Molar mass of CaO = 40.08 g/mol (calcium) + 16.00 g/mol (oxygen) = 56.08 g/mol
Using the molar masses, we can convert the given masses into moles:
Moles of CaCO3 = 5.00 g / 100.09 g/mol = 0.04998 mol
Moles of CaO = 2.40 g / 56.08 g/mol = 0.04281 mol
The theoretical yield of calcium oxide is 0.04998 mol, as determined by the stoichiometry of the balanced equation.
Now, we can calculate the percentage yield using the formula:
Percentage yield = (actual yield / theoretical yield) x 100%
Percentage yield = (2.40 g / 0.04998 mol) x 100% ≈ 4808%
Therefore, the correct expression for the percentage yield of calcium oxide is approximately 4808%. However, it's important to note that a percentage yield above 100% suggests a possible error in the experimental procedure or measurements.
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In which orbitals would the valence electrons for selenium (Se) be placed?
s orbital and f orbital
s orbital only
s orbital and p orbital
d orbital only
Answer:
s orbital and p orbital
Explanation:
Answer:
s orbital and p orbital
Explanation:
Any material that exerts magnetic force is considered a magnet true or false?
Answer:
Any material that exerts magnetic force is considered a magnet.
TRUE
If 0.094 moles of magnesium react with excess oxygen, how many moles of magnesium oxide would be formed?
The equation for this reaction is
\(\text{Mg}+\text{O} \longrightarrow \text{MgO}\)
This means that for every mole of magnesium consumed, 1 mole of magnesium oxide is produced.
So, the answer is 0.094 moles.
What is the value of H-C-H bond angle in ethylene?
The value of the H-C-H bond angle in ethylene is 117°.
The bond angle is a geometric angle that is formed due to the repulsion between atoms or electrons in a bond. The binding angle for a linear molecule is 180°, for a triangular planar molecule it is 120°, and so on.
The size of the bond angle is affected by the magnitude of the repulsive force of electron pairs in the molecule. The lone pair has a slightly stronger repulsive force than the bonding pair. This happens because the lone pair of electrons is only bound to one atom, so the movement is more flexible.
Determine the bond angles using VESPR theory, such as if the shape of the molecule AX means that it is linear with a bond angle of 180 degrees.
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what is the density of a gas at STP that has a molar mass of 50.0 g/mol?
Answer:
2.232 g/L
Explanation:
Assuming 1 mol, volume at STP is 22.4 L so you simply divide 50g by 22.4 L to get density
The density of the given gas is required.
The density of the gas at STP is 2.232 g/L.
M = Molar mass of gas = 50 g/mol
1 mole of any gas at STP occupies 22.4 L.
V = Volume per mole = 22.4 L/mol
Density is given by
\(\rho=\dfrac{M}{V}\\\Rightarrow \rho=\dfrac{50}{22.4}\\\Rightarrow \rho=2.232\ \text{g/L}\)
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A very good example of soft water is A. Distilled water B. Sea water C. Underground water D. Polluted water
Answer:
The answer is option A.
Distilled water
Since all the chemicals that will cause hardness in the water has been removed.
Hope this helps.
How
fast does hydrogen break down in the atmosphere? 1 year 10 years
?
Hydrogen breaks down relatively fast in the atmosphere. In the presence of sunlight, hydrogen breaks down within a few years. However, in the absence of sunlight, it can take up to a decade (10 years) for hydrogen to break down in the atmosphere.
Hydrogen is the first element in the periodic table with the symbol H. It is the most abundant element in the universe, but it is rarely found in its elemental form on Earth. It is often found combined with other elements such as oxygen and carbon. Hydrogen is a colorless, odorless, and highly flammable gas. It is used in a variety of applications, such as fuel for vehicles, electricity production, and chemical manufacturing.
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Based on the periodic table, which of the following groups of elements should have very similar chemical properties?
OA. potassium (K), aluminum (Al), neon (Ne)
OB. carbon (C), iodine (1), hydrogen (H)
OC. lithium (Li), sodium (Na), potassium (K)
OD. manganese (Mn), magnesium (Mg), molybdenum (Mo)
C
Since every element stated in option C is from the same group (alkali metals) they will have the same properties
2. Suppose that the identification labels fell off three of the Beral pipets in the set used in this experiment. You realize that the pipets with the missing labels hold NH,CI, HCI, and NaCl solutions. Describe an experi- ment you could perform, using these three solutions and any two of the indicators used in this experiment, not including the Universal Indicator, that would allow you to correctly relabel the pipets. If the data from your experiment would be inconclusive, state the pH range for which you would need an indicator to make certain of the identifications.
To correctly relabel the pipets, we need to determine the identity of each solution based on its properties. We can use two indicators, bromothymol blue and phenolphthalein, to perform the following experiments:
Add a few drops of bromothymol blue to each solution. NH4Cl solution will turn yellow, NaCl solution will remain unchanged, and HCl solution will turn blue. Based on this, we can label the pipet with the yellow solution as NH4Cl, the unchanged solution as NaCl, and the blue solution as HCl.
Add a few drops of phenolphthalein to each solution. NaCl solution will remain colorless, NH4Cl solution will turn pink, and HCl solution will remain colorless. Based on this, we can label the pipet with the pink solution as NH4Cl, the colorless solution as NaCl, and the colorless solution as HCl.
If the data from these experiments are inconclusive, we would need an indicator that can distinguish between acidic and basic solutions. In this case, we can use methyl red as an indicator. NH4Cl solution will turn red, NaCl solution will remain unchanged, and HCl solution will remain colorless. Based on this, we can label the pipet with the red solution as NH4Cl, the unchanged solution as NaCl, and the colorless solution as HCl.
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Complete each equation and write a balanced net ionic equation for each reaction. Identify the spectator ions in each reaction. Use Solubility Rules.5. BaCl2(aq) + K2SO4 (aq)—--→ 6. Na2S(aq) + Cd(NO3)2(aq) —--→7. Al(s) + H2SO4(aq) —--→8. HCl(aq) + Ba(OH)2 —--→
Explanation:
Given:
\(5.BaCl_{2(aq)}+K_2SO_{4(aq)}\rightarrow\)The complete equation is:
\(BaCl_{2(aq)}+K_2SO_{4(aq)}\rightarrow BaSO_{4(s)}+2KCl_{(aq)}\)The balanced ionic equation for the reaction is:
\(Ba^{2+}+2Cl^-+2K^++SO^{2-}_{4^{}}\rightarrow BaSO^{}_{4(s)^{}}+2K^++2Cl^-\)The BaSO₄ is an insoluble solid, so it will not dissociate into ions.
The spectator ions in the reaction are ions that are present at both the reactant side and the product side.
Hence, the spectator ions are:
\(Cl^-,and\text{ }K^+\)Therefore, the balanced net ionic equation is:
\(Ba^{2+}_{(aq)}+SO^{2-}_{4_{(aq)}^{}}\rightarrow BaSO^{}_{4(s)^{}}\)Rank the following species in order of decreasing boiling point (highest to lowest): O3, N2, H2,CO2, O2
The following species can be listed in order of decreasing boiling point:
CO₂>O₃>N₂>O₂>H₂
The boiling point of gases depends upon the strength of the intermolecular forces of attraction acting between them and the molecular weight of the gaseous species.
CO₂ has polar bonds and also exhibits dipole - dipole interactions.
O₃ also has polar covalent bonds
O₂, N₂ and H₂ are non polar but have london dispersion forces as weak intermolecular forces.
Thus, the order of decreasing boiling point will be -
CO₂>O₃>N₂>O₂>H₂
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How do particles combine to form the variety of matter one observes?
Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, by transferring electron or sharing electrons, particles combine to form the variety of matter.
What is matter?Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.
So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter. By transferring electron or sharing electrons, particles combine to form the variety of matter.
Therefore, by transferring electron or sharing electrons, particles combine to form the variety of matter.
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