What does +2 mean on an ion?

Answer:

Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them. This then continues and passes the energy from the hot end down to the colder end of the substance.

Explanation:

May I have brainliest please? :)

Answer:

Solar eclipses happen only at the new moon phase, when the Moon is between Earth and the Sun. During a solar eclipse, the Moon casts a shadow on Earth, and blocks or partially blocks our view of the Sun

Given data

*The given radius of the wheel is r = 30.0 cm = 0.30 m

*The given angle of the wheel rotates in 1.00 s is

*The angular velocity of the wheel is

The formula for the linear speed of a point on the wheel's rim is given as

Substitute the known values in the above expression as

Hence, the linear speed of a point on the wheel's rim is v = 53.4 m/s

The formula for the wheel's frequency of rotation is given as

Substitute the known values in the above expression as

Hence, the wheel's frequency of rotation is f = 28.34 Hz

The expected chain length (number of repeating units per chain) that would be formed in the experiment, assuming all initiators initiate chains and all monomers add onto the chains can be calculated using the following formula.

Expected chain length = (Number of moles of monomers used/Number of moles of initiators used) + 1Where,+ 1 denotes the length of the initiator's unit and is added to the average number of monomer units. Hence, it indicates the length of the polymer's first unit.The number of moles of monomers used can be determined as follows

The number of moles of initiators used can be determined as follows:Number of moles of initiators = (Mass of initiators used/Molecular weight of initiators)Example:If the mass of monomers used is 0.05 g and the molecular weight of monomers is 100 g/mol, then the number of moles of monomers used

= (0.05/100) mol

= 5 × 10⁻⁴ molIf the mass of initiators used is 0.01 g and the molecular weight of initiators is 200 g/mol

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The resulting signal is s(t) = 2 rect(t/10) sin(2π  500t).Plotting the magnitude spectrum of this signal, we have. The frequency domain plot of the modulated signal is shown above. The bandwidth of the first null is the distance between the first two nulls, which are located at approximately 650 Hz and 1350 Hz. Hence the bandwidth of the first null is 1350 – 650 = 700 Hz.

The seismic magnitude scale is used to describe the overall strength or "size" of an earthquake. It is distinguished from the seismic intensity scale which categorizes the intensity or severity of ground shaking caused by earthquakes at a specific location. the difference between the Richter Scale and amplitude viz. The Ritcher scale uses amplitude, which is the farthest deviation from the vibrational equilibrium point. While the magnitude is based on the calculation of the frequency of ground vibrations. The results of magnitude calculations are often seen as far more accurate, especially for calculating the strength of an earthquake over a large area.

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To design separate oscillators of 97 kHz and 79 MHz using the NE555 timer and a crystal oscillator.

Follow the steps below:

Designing an oscillator with the NE555 timer for a frequency of 97 kHz:

1. Connect pins 1 (Ground) and 8 (Vcc) of the NE555 to the appropriate power supply.

2. Connect pin 4 (Reset) to Vcc to disable the reset function.

3. Connect pin 5 (Control Voltage) to Ground.

4. Connect a resistor (R1) and a capacitor (C1) in series between pins 6 (Threshold) and 7 (Discharge). Choose values for R1 and C1 to set the desired time constant.

5. Connect pin 2 (Trigger) to the junction of R1 and C1.

6. Connect pin 3 (Output) to an appropriate load or circuit.

7. Provide necessary decoupling capacitors and stabilize the power supply.

8. Adjust the values of R1 and C1 to achieve the desired frequency of 97 kHz.

Designing an oscillator with a crystal oscillator for a frequency of 79 MHz:

1. Choose a crystal oscillator with a resonant frequency of 79 MHz.

2. Connect the crystal oscillator component to the appropriate pins of a suitable oscillator circuit or microcontroller.

3. Provide necessary decoupling capacitors and stabilize the power supply.

4. Configure the oscillator circuit or microcontroller to use the crystal oscillator component as the clock source.

5. Program or adjust the oscillator circuit or microcontroller to generate an output signal with a frequency of 79 MHz.

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Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nm, or 4.00 × 10⁻⁷ to 7.00 × 10⁻⁷ m, between the infrared and the ultraviolet.

Explanation:

This is one type of light.

The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.

what do you mean by center of balance and center of gravity ?

A location where an object is balanced in relation to applied forces is known as the center of balance (COB).

The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.

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The focal length of the mirror will be 0.33 m

Focus is defined as the point through which the reflected light rays pass (or appear to pass) when incident light rays are parallel to the principal axis. It is located at the midpoint of pole and center of curvature. The distance between the pole and the focus of the mirror is called the focal length of the mirror.

F =2R or focal length of a mirror is half of its radius of curvature.

The radius of curvature of convex or concave mirror is equal to two times of the focal length of convex or concave mirror. The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature.

F = 1/R

R = 3 m (given )

F = 1 / 3 = 0.33 m

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Take into account that the acceleration of the car can be calculated by using the following expression:

where,

vo: initial speed = 0m/s

v: final speed = 18.4m/s

t: time = 27.8s

Replace the previous values of the parameters into the formula for a and simplify:

Hence, the acceleration of the car is approximately 0.66m/s^2

Answer:

An effect whereby a mass moving in a rotating system experienced a force acting perpendicular to the direction of motion and to the axis of rotation.

Answer:

The particles have more distance in them which impacts the density.

Explanation:

A solid's particles are much more closer together than that of a liquid's particles. Same thing goes for gas particles(they are much more far apart than liquid particles). This is why solids usually are more denser than liquids and gas, due to the way their particles are structured. Hope this helps!

Answer:

Its b because the meteor moving strait.

Explanation:

Answer:

Explanation:

Sphere B and sphere A are touching so they will act as a single body . A positively charged sphere C is brought near sphere B . So there will be induction of charge on sphere B and sphere A . Opposite charge will be induced on nearer sphere and same charge will be induced on distant sphere . Hence sphere B will be negatively charged and sphere A will be positively charged. The amount of charge induced on sphere B and A will be same and it will remain as long as sphere C is kept near sphere B . As soon as sphere C is removed , induced charges will also neutralize each other .

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Answer:

weight on earth is mg

which is 5*9.8

49 Newton

weight on moon is 1/6 th of weight on earth

1/6*49

8.166 Newton..

Answer:

1

For instance, on Earth, a 5.0-kg object weighs 49 N; on the Moon, where g is 1.67 m/s2, the object weighs 8.4 N.

2

The weight of the object on the surface of earth would be 5kg. The weight of the object on the surface of moon would be 5/6= 0.83 as the weight of any object on earth is six times than that on moon.

I need you to make me an invented poem written please not in image

The dog is 14 feet away from the shore at the end of his walk.

Initially, the dog is 20 feet away from the shore on the barge, which is initially touching the shore. When the dog walks 8 feet towards the shore, the boat moves backwards by a certain distance to conserve momentum. We can use the conservation of momentum equation to find the distance the boat moves backward:

m₁v₁ = m₂v₂

where m₁ is the mass of the dog, v₁ is the initial velocity of the system (dog and boat) before the dog walks, m₂ is the mass of the system after the dog walks (dog, boat, and the distance the boat moved), and v₂ is the final velocity of the system after the dog walks.

Since the boat is initially at rest, v₁ = 0. After the dog walks, the mass of the system is 50 lb (dog + boat), and the final velocity can be found using the conservation of energy equation:

mgh = (1/2)mv²

where m is the mass of the system, g is the acceleration due to gravity, h is the distance the system moved, and v is the final velocity of the system.

Using the given information, we can solve for v and find that the boat moved backward by 3.2 feet. Therefore, the distance between the dog and the shore after the dog walks is 20 - 8 + 3.2 = 14 feet.

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Explanation:

The kinetic energy of a moving object is directly proportional to its mass and directly proportional to the square of its velocity. This means that an object with twice the mass and equal speed will have twice the kinetic energy while an object with equal mass and twice the speed will have quadruple the kinetic energy.

Hi there!

Because of Newton's Third Law, the force exerted by the sprinter on the track is equal and opposite to the force exerted by the track on the sprinter.

We can begin by calculating the sprinter's acceleration. Use the equation:

vf² = vi² + 2ad

Rearrange for acceleration:

(vf² - vi²)/2d = a

Plug in values:

(8² - 2²)/2(2.5) = 60/5 = 12 m/s²

Calculate the force:

∑F = ma

∑F = 60 × 12 = 720 N. This is the amount of force exerted by the track on the sprinter in causing him to accelerate forward.

Thus, the backward force exerted by the sprinter on the track is the opposite, or -720 N.

Whenever an increasing temperature leads to a quicker movement of elementary particles and a collision, Thermal energy occurs. The hypothesis as per the given statement is provided below.

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Answer:

Different masses will change tempurature at different rates when exposed ti the same amount of thermal energy. This is because the amount if mass affects ab objects ability to absorb thermal energy.

Explanation:

sample response for edge

The relationship between a magnetic field and an electric current can be described using these terms: magnetic field, electric current, electromagnetism, and the right-hand rule.

A magnetic field is a region around a magnet where magnetic forces can be felt. An electric current is a flow of electric charge, typically through a conductor such as a wire.

The relationship between a magnetic field and an electric current is described by the concept of electromagnetism.

When an electric current flows through a conductor, it generates a magnetic field around it. This phenomenon is known as the magnetic effect of current or electromagnetism.

The direction and strength of the magnetic field produced by an electric current can be determined using the right-hand rule. If you point your thumb in the direction of the current flow and curl your fingers around the conductor, your fingers will point in the direction of the magnetic field lines.

In summary, the relationship between a magnetic field and an electric current is based on electromagnetism, where an electric current flowing through a conductor generates a magnetic field around it. The right-hand rule can be used to determine the direction and strength of the magnetic field produced by the electric current.

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E1=E4>E5>E2=E3 is the correct order of magnitudes induced in the loop. Region I has a magnetic field that is neither uniform nor steady and points out of the page. Disregard any communication between loops.

In terms of physics, magnitude is just "distance or quantity." In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope .In physics, the term "magnitude" often refers to a size or amount.

The definition of magnitude is "how much of a quantity." The magnitude, for instance, can be utilized to explain the contrast between the speeds of a car and a bicycle.

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(A) This box glides, then slides up to 4.74 m before stopping . (B) The friction coefficient at the point of halting is 0.537. (C) The box would have slid 101.25 meters before coming to a stop if the coefficient of friction had stayed unchanged.

To solve this problem, we can use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK.E.

We can break the motion of the box into two parts: before and after the rough section. Before the rough section, the box is moving with a constant velocity, so the net work done on it is zero. After the rough section, the box slows down and comes to a stop, so the net work done on it is equal to its initial kinetic energy:

Net work = -K.E.

(A) To find how far the box slides before stopping, we need to find the distance over which the box is acted upon by the increasing frictional force. Let's call this distance x.

W (friction) = ∫₀ˣ F f(x') dx'

here,

F f(x') is frictional force at a distance x' from point P.

Since the coefficient of friction increases linearly with distance, we can express F f(x') as:

F f(x') = μ₀ + (μ f - μ₀) * (x'/x f)

here,

μ₀ is initial coefficient of friction at point P,

μ f is final coefficient of friction at distance x f = 12.5 m, and

x' ranges from 0 to x.

Reserving expression of F f(x') into the integral for W (friction):-

W (friction) = μ₀ * x + (μ f - μ₀) * (x²/2x f)

Express initial kinetic energy as:-

K.E. = (1/2) * m * v²

here,

m is mass of the box and

v is its initial velocity of 4.50 m/s.

Setting the net work equal to the change in kinetic energy:-

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= (1/2) * m * v²

= x² - 2x f * [(μ f - μ₀)/μ₀] * x - 2x f * (K.E./(μ₀ * m))  

= 0

Putting given values of μ₀, μ f, x f, m, and v:-

x = 4.74 m

Therefore, the box slides for a distance of 4.74 m before coming to a stop.

(B) To find the coefficient of friction at the stopping point, we can use the same equation we derived earlier for W (friction) and solve for μ f:-

= W (friction)

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= -K.E.

= μ f

= (2 * K.E. + μ₀ * x * (μ f - μ₀)/x f) / x²

Putting given values of K.E., μ₀, μ f, x f, and x:-

μ f = 0.537

Therefore, the coefficient of friction at the stopping point is 0.537.

(C)  If the coefficient of friction remained constant at μ₀ = 0.1000, then we can simplify the equation we derived for x by setting μ f = μ₀:

= μ₀ * x + (μ₀ - μ₀) * (x²/2x f)

= (1/2) * m * v²

Simplifying the second term:-

μ₀ * x = (1/2) * m * v²

Solving for x:-

x = (m * v²) / [2 * μ₀ * W (friction)]

here,

W (friction) is work done by friction.

To find W (friction), we can integrate the frictional force over the entire distance traveled by the box:-

= W (friction)

= ∫₀ˣ F f(x') dx'

here,

F f(x') is constant frictional force of μ₀.

Reserving this expression for W friction into the equation for x:-

x = (m * v²) / (2 * μ₀ * F f * x)

here,

F f is constant frictional force of μ₀.

Simplifying:-

x = (m * v²) / (2 * μ₀ * F f)

Putting given values of m, v, μ₀, and F f:-

x = 101.25 m

Therefore, if the coefficient of friction had remained constant at μ₀ = 0.1000, the box would have slid for a distance of 101.25 m before coming to a stop.

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Given data

*The half-life of iodine-131 is t = 8.07 days

*The amount of quantity left is N = 0.25 g

*The number of days is T = 40.35 days

The expression for the radioactivity decay is given as

Substitute the values in the above expression as

Answer:

See below

Explanation:

40.35 days / (8.07 day per half life) = 5 half lives

.25 = x ( 1/2)^5

.25 / ( 1/2)^5 = x = 8 gm originally

Answer:

C.  240 N

Explanation:

I think you have the third answer choice incorrect. It should be 240N because that is the correct answer

From newtons law of gravitation, the gravitational force equation between two objects is given by

\(F = \dfrac{Gm_1m_2}{r^2}\)

where m₁ and m₂ are the masses of the two objects, G = gravitational constant and r the distance between the objects

If we double m₁ and m₂, the new gravitational force becomes

\(F = \dfrac{G(2m_1)(2m_2)}{r^2} = \dfrac{4Gm_1m_2}{r^2}\\\\\)

which is 4 times the original force

So if original force = 60 N, then resultant force after doubling both the masses = 4 x 60 =240N

To determine the resistance of a resistor in a circuit using Ohm's law, we need to know the voltage across the resistor and the current flowing through it. Ohm's law states that the resistance (R) of a component is equal to the voltage (V) across it divided by the current (I) flowing through it:

R = V / I

Ohm's law is a fundamental principle in electrical engineering and physics that describes the relationship between voltage, current, and resistance in an electrical circuit. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, while inversely proportional to the resistance of the conductor. Mathematically, Ohm's law is expressed as:

V = I * R

Where:

V represents the voltage across the conductor (measured in volts, V)

I represents the current flowing through the conductor (measured in amperes, A)

R represents the resistance of the conductor (measured in ohms, Ω)

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Its closest distance from the Sun is about 4.44×10^12 meters, and its farthest distance is about 7.38×10^12 meters for Pluto's orbital period.

To calculate Pluto's orbital period in seconds, we will use Kepler's Third Law:

T^2 = (4 * π^2 * a^3) / (G * M)

Where:
- T is the orbital period in seconds
- a is the semi-major axis (5.91×10^12 m)
- G is the gravitational constant (6.674×10^-11 N(m/kg)^2)
- M is the mass of the Sun (1.989×10^30 kg)

1. Plug in the values: T^2 = (4 * π^2 * (5.91×10^12)^3) / (6.674×10^-11 * 1.989×10^30)
2. Solve for T: T ≈ 7.82×10^15 seconds

To convert this to Earth years, we can use the conversion factor of 1 year = 3.1536×10^7 seconds:

Pluto's orbital period in Earth years = (7.82×10^15 seconds) / (3.1536×10^7 seconds/year) ≈ 248 years

To find Pluto's closest and farthest distances from the Sun, we will use the formula:

d = a * (1 ± e)

Where:
- d is the distance from the Sun
- a is the semi-major axis (5.91×10^12 m)
- e is the eccentricity (0.249)

Closest distance (periapsis): d = 5.91×10^12 * (1 - 0.249) ≈ 4.44×10^12 meters
Farthest distance (apoapsis): d = 5.91×10^12 * (1 + 0.249) ≈ 7.38×10^12 meters

In summary, Pluto's orbital period is approximately 7.82×10^15 seconds or 248 Earth years. Its closest distance from the Sun is about 4.44×10^12 meters, and its farthest distance is about 7.38×10^12 meters.

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