What does the red line in the diagram below represent?

OA. The activation energy
OB. The equilibrium position
C. The potential energy of the reactants
D. The difference in energy between the reactants and products

The incorrect name-formula combination is FeCIO₄ -  Iron(I) perchlorate; option B.

The IUPAC nomenclature of naming compounds refers to the convention of naming compounds using the oxidation states of the elements present in the compound.

The IUPAC nomenclature of the given compounds is given below as follows:

A. Co(CIO₂)₂ - Cobalt(II) chlorite; the oxidation state of cobalt is +2

B. FeCIO₄ -  Iron(I) perchlorate; the formula of the compound is wrong because iron does not exist in the +1 state

C)Mn(CIO4)₂ -  Manganese(II) perchlorate;  the oxidation state of manganes is +2

D) Cr(CIO)₃​ - Chromium(III) hypochlorite ;  the oxidation state of chromium is +3

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The volume of 0.5 M HCOOH required is 50 mL and the volume of 0.5 M HCOONa required is 150 mL.

To prepare a pH 4.50 buffer with a buffer strength of 0.1 M, we need to use a mixture of HCOOH and HCOONa in a specific ratio. The buffer equation for this system is:

\(pH = pKa + log([HCOO-]/[HCOOH])\)

Substituting the given pH of 4.50 and pKa of 3.75:

We can then use the Henderson-Hasselbalch equation:

\([HCOOH]/[HCOO-] = 3.16 \\\\[HCOOH] + [HCOO-] = 0.1 M\)

Solving these equations simultaneously, we get:

\([HCOOH] = 0.0253 M\) and \([HCOO-] = 0.0747 M.\)

Therefore, the volume required is 50 mL and the volume of 0.5 M HCOONa required is 150 mL, to prepare 0.1 L of pH 4.50 buffer with a buffer strength of 0.1 M.

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Stable isotopes are non-radioactive form of atoms.

properties of stable isotopes are :-

Atoms found in nature are either stable or unstable. An atom is stable if the forces among the particles that makeup the nucleus are balanced. An atom is unstable (radioactive) if these forces are unbalanced; if the nucleus has an excess of internal energy.

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this question is incomplete, above content might be helpful

The minimum entropy change of the heat-supplying source is -0.87 kJ/K.

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.

S₁ = 1.485  +  (0.1)(5.6865) = 2.0537 kJ/kg K

The entropy at the final state given the new 40-% quality:

S₂ = 1.4337  +  (0.4)(5.7894) = 3.7495 kJ/kg K

m₁ = 0.026/(0.001057   +  0.1 x 1.002643) = 0.257 kg

m₂ = 0.026/(0.001053   +  0.4 x 1.158347)  = 0.056 kg

ΔS + S₁  - S₂  + S₂m₂  - S₁m₁  -  sfg(m₂  -  m₁)  > 0

ΔS + 2.0537 -  3.7495 + (3.7495 x 0.056)  -   (2.0537 x 0.257)  - 5.6865( 0.056 - 0.257)  >  0

ΔS > -0.87 kJ/K

Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.

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Answer:

yaaaaa babdbabaaaa lolll

Explanation:

Answer:

C. Chemical change

Explanation:

A physical change is where something is changed but it doesnt affect the build up of the chemical. For example, if you broke sticks and threw them on the ground, that would be a physical change because the change is happening to the physical being of the object and not its chemical buildup. However, if you lit those sticks on fire, that would be considered a chemical change because you end up with two substances, ash and the remnants of the stick. A nuclear reaction would result in something blowing up so its not that. And a physical property is like what it looks like or how it smells. Hope I helped you!

Answer:

(i) of protons

(ii) total number of both protons and neutrons

(b)they are neutral or have no overall charge because there are equal numbers of negative electrons to positive protons

Explanation:

Since both charges are equal, the number of positive protons cancels the number of negative electrons, thereby making the atom neutral

1 mL = 0.815 g

11.2 mL = X

X = 11.2 × 0.815

= 9.128 g

mole = 9.128/58

= 0.157 mole

1 mole = 6.02 × 10^23 atoms

0.157 mol = x

X = 0.157/1 × 6.02 × 10^23

= 9.451 × 10^22 atoms of C

please to recheck answers to ensure they are correct

I really hope this helps

Answer:

c. Ralph's classmate observing Daphnia in water at 30oC, 32oC and 34oC

Explanation:

When we talk about replication, we actually mean, repetition of a scientific procedure carried out by another scientist and obtaining the same results as he/she previously did.

Replication is carried out under identical conditions as the first scientist did. If Ralph's classmate wants to replicate Ralph's work, then identical temperature conditions of 30oC, 32oC and 34oC must be used, hence the answer above.

1.267 x 10 ^ 24 is the total number of atoms

The electron geometry is trigonal bipyramidal while the molecular geometry is linear.

We know that the number of electron pairs that surround a chemical species is what determines the electron geometry of the specie. In this case, we have the specie  ICl₂⁻.

We can see that there are five electron pairs that surround the central atom of the specie hence the electron domain geometry would be trigonal bipyramidal. On the other hand there of the electrons are lone pairs and there are only two bond pairs hence the molecular geometry is linear.

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Answer:

3.85

Explanation:

Calculate molar mass, starting with each element, then find grams per mole, then convert.

Scientist who made beam of electrons was J. J. Thomson, particle which is negative in an atom are electrons,alpha particle bounced back in the experiment of Ernest Rutherford, nucleus is  heavier than those electrons.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

The concentration of Oxalic Acid is 0.2625 M.

A kinetic experiment is conducted to determine the rate law of a reaction. The concentration of Oxalic Acid can be calculated using the given amount of the reactants and the volume of the test tube. A balanced chemical equation can be used to find the stoichiometric ratio of the reactants in the given reaction.The balanced chemical equation for the reaction is:5 H2C2O4 + 2 KMnO4 + 3 H2SO4 → 10 CO2 + 2 MnSO4 + 8 H2OThe stoichiometric ratio between Oxalic Acid and Potassium Permanganate is 5:2. The Oxalic Acid is the limiting reactant, and Potassium Permanganate is in excess.The amount of Oxalic Acid in the solution can be calculated using the formula:molarity = moles of solute / volume of solution in L.The moles of Oxalic Acid can be calculated using the formula:moles of H2C2O4 = Molarity of H2C2O4 x Volume of H2C2O4 in L= 0.525 M x 0.006 L= 0.00315 moles.

The volume of the solution after the addition of the reactants is:6.00 mL of 0.525 M Oxalic Acid + 4.00 mL of distilled water + 2.00 mL of 0.200 M KMnO4= 12.00 mLThe concentration of Oxalic Acid in the solution can be calculated using the formula:Molarity of H2C2O4 = moles of H2C2O4 / volume of solution in L= 0.00315 moles / 0.012 L= 0.2625 M.

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

air

Explanation:

Non-rechargeable batteries, also known as primary batteries, are designed with a limited amount of active materials in their electrodes. Once all the active materials are consumed, the battery cannot be recharged. This is because non-rechargeable batteries have significantly different chemistries than rechargeable batteries, despite both being based on reversible redox reactions.

On the other hand, rechargeable batteries, or secondary batteries, are designed to be recharged because they contain more active materials in their electrodes that can be replenished when the battery is charged. Rechargeable batteries also have additional layers to protect their active materials from degrading during the charge and discharge process.

Therefore, the fundamental difference between non-rechargeable and rechargeable batteries is the amount of active materials contained in the electrodes and their corresponding battery chemistries – which results in the limited use of non-rechargeable batteries.

The required partial pressure of argon gas present in the mixture is 1.02 atm.

Dalton's law of gas states that total pressure of any mixture of gas is sum of the partial pressure of all the gases present in that mixture.

Given that,

Total pressure of mixture = 2.4 atm

Partial pressure of argon = ?

Partial pressure of oxygen = 128 mmHg = 0.168 atm

Partial pressure of helium = 167.5 mmHg = 0.220 atm

Partial pressure of neon = 760 mmHg = 1 atm

On putting all these values according to the definition we get the partial pressure of argon gas as:
Partial pressure of argon = 2.4 - (0.168 + 0.22 + 1) = 1.02 atm

Hence required partial pressure of argon gas is 1.02 atm

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Explanation:

Introducción:

La designación de los compuestos orgánicos puede hacerse utulizando alguno de los

siguientes sistemas:

a) Mediante nombres triviales o comunes, que expresen alguna propiedad característica

(sabor, color, acción fisiológica, etc.) o hagan referencia a la materia de la cual se extrajo el

compuesto.

b) Mediante nombres racionales que proporcionen una idea de su constitucion química y

destaquen sus analogías estructurales.

La necesidad de una nomenclatura sistemática, que expresara en forma clara, conforme

a normas precisas, el nombre y la estructura de los compuestos orgánicos, ha sido motivo de

preocupación permanente y observada a través de los numerosos congresos internacionales

que, al efecto, se han realizado en diversas oportunidades.

Las bases del actual sistema de nomenclatura fueron establecidas por una comisión que

se reunió en Ginebra en 1892. Posteriormente, fue perfeccionado y ampliado por el Comité de

Nomenclatura de la Unión Internacional de Química Pura y Aplicada, por lo que se conoce

como sistema I.U.P.A.C. (International Union of Pure and Applied Chemistry).

En las reglas aprobadas se ha tratado de introducir los menores cambios posibles a la

terminología universalmente adoptada. El sistema tiene la necesaria flexibilidad como para

adaptar la forma precisa de las palabras, de las terminaciones, etc. a las características de

distintos idiomas.

El nombre de los hidrocarburos consta de tres partes: a) la raíz, que indica el esqueleto

carbonado; b) la terminación o sufijo, que indica el grado de saturación, y c) el prefijo que

diferencia las distintas estructuras isoméricas (distintas estructuras construidas con exactamente

los mismos átomos).

Ej.: CH3-CH2-CH2-CH2-CH3 pentano (tambien llamado n-pentano)

penta: raíz que señala el número de átomos de carbono que componen la cadena principal

del compuesto.

-ano: sufijo que indica que el hidrocarburo es saturado

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

19.37g

Explanation:

1 mole CH4 gives 4 mole CO2

so 58 g gives 176 g CO2

(58/176)×58.8 g CH4 gives 58.8 g CO2

If we start with 16 pounds of a radioactive substance, the amount that would be left after 3 half-lives will be 2 pounds.

The half-life of a decaying substance is given by the following mathematical expression:

N (t) = \(N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} }\)

Where N(t) is the quantity remaining, \(N_o\) is the initial quantity, t is the time that has elapsed, and \(t_\frac{1}{2}\) is the half-life.

In this case,  \(N_o\) = 16 pounds and \(\frac{t}{t_\frac{1}{2} }\) = 3.

Substituting the values into the equation:

N(3) = \(16(1/2)^3\)

       = 2 pounds

In other words, the amount of a radioactive substance that would remain from an initial amount of 16 pounds after 3 half-lives would be 2 pounds.

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J.J. Thomson discovered electrons and their negative charge through the cathode ray experiment, leading to the development of the plum pudding model of the atom.

J.J. Thomson, a British physicist, was the first to discover electrons in 1897.

He conducted the cathode ray experiment to identify the negatively charged particles.

The cathode ray tube is a vacuum-sealed glass tube with two electrodes at each end: a cathode and an anode.

When a high voltage electrical current is applied to the electrodes, the tube glows, indicating that the cathode rays are being emitted from the cathode and traveling through the tube towards the anode.

The cathode rays were found to have a negative charge, according to Thomson.

These rays were identified as particles by the presence of a magnet, which caused the particles to bend in the direction opposite to the magnet's polarity.

This discovery indicated that the particles had a charge on them because they were deflected by the magnetic field, which is only possible if the particles have an electric charge.

Thomson further concluded that these particles were about 1,000 times smaller than hydrogen atoms because of the degree of deflection they experienced in the magnetic field.

Furthermore, Thomson created the plum pudding model of an atom, in which electrons are dispersed throughout a positively charged matrix, based on his findings.

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