What effect docs temperature have on the dissolution rate in sugar water?

Answer:

C

Explanation:

Winter in North

Summer in south

Answer: C

Explanation: i just took it

Interpolation refers to determining a value within an established dataset. In the context of the spring stretch experiment, the value 'Force = 4.4 N, stretch = 7.9 cm' is considered an interpolated value as it falls within the used force range (0N to 5N). The other values are either used in the experiment or extrapolations.

In this context, interpolation refers to the process of determining a value within an existing data set or between two known values. In your given data for the spring stretch experiment, the force values used in the experiment range from 0N to 5N. As such, an interpolated value would need to fall within this range.

Given that, the value Force = 4.4 N, stretch = 7.9 cm would be considered an interpolation because it falls within the known values used in the experiment. The rest of the options are either values used in the experiment (0 N, 3 N) or extrapolation (5.2 N) as they are outside of the range of force investigated.

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Considering the values from the experiment, the interpolated value between the known points on the graph is 'Force = 4.4 N, stretch = 7.9 cm', since it falls within the range of given values.

In the context of this laboratory experiment, interpolation refers to predicting a value within a range of known values. From the given points plotted on the graph, the values of force range from 0 N to 5 N, and the corresponding stretch ranges from 0 cm to 9.1 cm. Looking at the listed options, the value Force = 4.4 N, stretch = 7.9 cm falls within these known ranges of both force and stretch, thereby qualifying as an interpolation.

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Answer:

Explanation:

Reduce the fan speed (to lower the power required).

Clean the fan blades to reduce the weight of the fan blades (and reduce the work required to move the blades).

Dehumidify the air to reduce the weight of the air the fan has to move.

Place a bucket of ice in front of the fan as a homemade AC unit.  Cold air is less dense than warm or hot air and requires less work from the fan to circulate it.

The term velocity is the combination of speed and direction.

The total displacement covered by any object per unit of time is known as velocity. The generally considered unit for velocity is a meter per second. It depends on the magnitude as well as the direction of the moving body. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time.

If an object is moving eastwards, then its velocity is expressed as being eastwards. If an object is moving southwards, then its velocity is described as being southwards. So an airplane moving towards the north with a speed of 450 km/hr has a velocity of 450 km/hr northward.

Speed has no effect on direction as the speed of any object or body is a scalar quantity and the velocity at any given time is expressed with the magnitude of velocity as well as with the direction of motion of an object.

The term velocity is the combination of speed and direction. therefore the correct option is option C.

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Even before the advent of the telescope, ancient astronomers were able to observe the following:

1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.

2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.

3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.

4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.

5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.

These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.

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An example of a physical change of matter is (c) Melting ice.

Explanation: Melting ice is an example of a physical change of matter. When ice melts, it undergoes a change in state from a solid to a liquid, but its chemical composition remains the same. The water molecules in ice rearrange themselves to form liquid water, but no new substances are formed. This change can be reversed by cooling the liquid water to below its freezing point, causing it to solidify back into ice. Physical changes do not involve a change in the chemical identity of the substance, only a change in its physical properties, such as shape, size, or state.

In contrast, options a) Burning wood, b) Digesting food, and d) Rusting iron involve chemical changes. Burning wood involves a chemical reaction where wood reacts with oxygen to produce carbon dioxide, water vapor, and ash. Digesting food involves the breakdown of complex molecules into simpler ones through chemical reactions in the body. Rusting iron is a chemical reaction where iron reacts with oxygen and moisture in the air to form iron oxide.

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Note: The complete question is:

Which of the following is an example of a physical change of matter?

a) Burning wood

b) Digesting food

c) Melting ice

d) Rusting iron

Answer:

the first answer is correct

Answer:

the first one is net force and the second is the third one

Answer:It would be unbalanced force

Explanation: Because due to the fact that there're are more people on the right they have a bigger force

Answer:

920000

Explanation:

Each kg contains 1,000 grams

The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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Answer:

C. NonFoliated

Explanation:

Non-foliated textures do not have lineations, foliations, or other alignments of mineral grains. Non-foliated metamorphic rocks are typically composed of just one mineral, and therefore, usually show the effects of metamorphism with recrystallization in which crystals grow together, but with no preferred direction.

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by \(F_{net} = mg + \frac{2mgh}{r}\)

Given the following data:

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Mathematically, centripetal force is given by this formula:

\(F_c = \frac{mv^2}{r}\)     .....equation 1.

Mathematically, gravitational force is given by this formula:

\(F_g= mg\)    ....equation 2.

Where:

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

\(P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh\) .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

\(F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}\)

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

\(W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}\)

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Answer:

a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J

Explanation:

a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.

So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.

So, mgh + 0 = 0 + K'

K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m

So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J

b. Since the kinetic energy of the block K = 1/2mv²  where m = mass of block = 5 kg, v = velocity of block at bottom of curve

So, v = √(2K/m)

= √(2 × 186.2 J/5 kg)

= √(372.4 J/5 kg)

= √(74.48 J/kg)

= 8.63 m/s

c. To find the stopping distance, from work-kinetic energy principles,

work done by friction = kinetic energy change of block.

So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance

ΔK = -fd

K" - K' = - μmgd

d = -(K" - K')/μmg

Substituting the values of the variables, we have

d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)

d = -(- 186.2 J)/(0.98 kg m/s²)

d = 190 m

d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m

So, a = (v² - u²)/2d

substituting the values of the variables, we have

a = (0² - (8.63 m/s)²)/(2 × 190 m)

a = -74.4769 m²/s²/380 m

a = -0.2 m/s²

Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.

t = (v - u)/a

t =(0 m/s - 8.63 m/s)/-0.2 m/s²

t = - 8.63 m/s/-0.2 m/s²

t = 43.2 s

e. The work done by friction W = fd where

= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m

W = 0.02 × 5 kg × 9.8 m/s² × 190 m

W = 186.2 J

The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.

The potential energy of the loss of the block will be equal to the kinetic energy gain.

So,

\(U = mgh\)

Where,

\(U\) - potential energy

\(m\) - mass of block =  5 kg

\(g\) - gravitational  acceleration = 9.8 m/s²

\(h\) = height = radius of curve = 3.8 m

Put the values in the formula,

\(U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J\)

Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.

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Answer:

The value is  \(m = 69.24 \ kg\)

Explanation:

From the question we are told that

   The value of the external force is  \(F = 59.0 \ N\)

    The magnitude of the astronaut's acceleration is  \(a = 0.852 \ m/s\)

Generally Newton's Second Law of Motion from the mass of the astronauts is mathematically represented as

            \(m = \frac{F}{a}\)

=>         \(m = \frac{59 }{0.852 }\)

=>         \(m = 69.24 \ kg\)  

The most denser among the given materials is gold and the least dense one is helium. The order of density from least to most dense is helium, carbon dioxide, water, lead and gold.

Density of a substance is the measure of its mass per unit volume. It describes how  closely packed its particles. density depends on the bond type, temperature and pressure.

The density of helium is very low and it is the lightest element after hydrogen. It density is about 0.00017 g/ml. Density of carbon dioxide is 0.0019 g/ml and the density of water is 1 g/ml.

Gold is a denser metal and its density is about 19.3 g/ml and that of lead is 11.3 g/ml. Hence, the order of density from least to most dense is He < carbon dioxide< water< lead < gold.

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The horizontal distance travelled by the fish when dropped is 131.25 m.

The time of motion of the fish from the given height is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 135 / 9.8 )

t = 5.25 seconds

The horizontal distance travelled by the fish when dropped is calculated as;

X = vt

X = 25 m/s  x  5.25 s

X = 131.25 m

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Given,

The initial velocity of the plane, u=175 m/s

The angle of projection of the plane, θ=35.5°

The time interval, t=48.0 s

The x-component of the initial velocity is,

On substituting the known values,

The y-component of the initial velocity is

On substituting the known values,

The x-component of the final velocity will remain the same as there is no acceleration on the plane in the x-direction.

The y-component of the final velocity can be calculated as,

Here, the acceleration due to gravity will be a negative value, as the gravity will be acting downwards. On substituting the known values,

Therefore the magnitude of the final velocity is given by,

On substituting the known values,

Therefore the final velocity of the plane will be 395 m/s

As the sun is directly above the plane, the distance traveled by the shadow of the plane will be equal to the range of the projectile motion of the plane.

The range is given by,

On substituting the known values,

Therefore the total distance traveled by the shadow is 2954.75 m

The velocity vector is always tangential to the motion path for a particle with curvilinear motion. The velocity of a particle describes the rate of change of its position over time and its direction is always tangent to the path of the particle's motion.

The acceleration vector describes the rate of change of the velocity and its direction can be either tangential or normal to the motion path, depending on whether the particle is changing speed or direction.

Yes, vectors and scalars are different. A scalar is a physical quantity that has only magnitude and no direction. A vector, on the other hand, is a physical quantity that has both magnitude and direction, such as velocity, force, or displacement.

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The Length of the thundercloud lightning bolt is 33.33 m.

This can be defined as the distance between two point.

To calculate the length of the thundercloud, we use the formula below.

Where:

Make L the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The Length of the thundercloud lightning bolt is 33.33 m.

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Answer:

a)   E = K + Φ, b)  ΔE = 1.64 10⁻¹³ J.,  c)    λ = a

Explanation:

a) In this case it is an example of the photoelectric effect that was correctly described by Einstein assuming that the light ray is composed of a series of particles called photons, each one with an energy given by the Planck equation

        E = h f

         c = λ f

substituting

          E = h c /λ

We can see from this equation that as the wavelength of the ray decreases the energy of each photon increases, the moment arrives that the energy is sufficient to remove an electron from the sphere, thus leaving an unbalanced positive charge, this description explains why the positive charge appears on the sphere; the minimum wavelength to remove an electron is

           E = K + Φ

if K = 0

           E =Φ

where fi is the work function of the material.

When the intensity of the ray increases according to Eintein's description, the number of photons increases, so if the number of photons increases, the number of shocks and the number of electrons expelled increases, therefore the unbalanced positive charge also increases.

b) the energy released in collision is the sum of the energy of each particle

for the electron

          E = K + m c² = (pc) ² + (m c²) ²

where the moment is

          p = γ m u

          γ = \(\sqrt{1- (\frac{u}{c})^2 }\)

          γ = \(\sqrt {1- ( \frac{2 \ 10^5}{3 \ 10^8 })^2 } = \sqrt{1- (6.67 \ 10 ^{-4)^2 }\)

          γ ≅ 1

in this case since the speed of the particles is much less than the speed of light,

            E = (m u) ² + (m c²) ²

            E = m² (u² + c²)

            E = 9.1 10⁻³¹ [(2 10⁵) ² + (3 10⁸) ²

            E = 9.1 10⁻³¹   9 10¹⁶

            E = 8.2 10⁻¹⁴ J

the positron has an energy of equal magnitude, so when the two particles annihilate the energy change is

            ΔE = 2E

            ΔE = 2 (8.2 10⁻¹⁴)

            ΔE = 1.64 10⁻¹³ J.

c) the expression that describes the diffraction process is

            a sin θ = m λ

            sin  θ = m λ/ a

where a is the width of the slit and m in diffraction order

The greatest value that the sine function can have is 1

               1 = m λ / a

               λ = a / m

therefore we can see that to see the diffraction phenomenon the width of the slit must be greater than or equal to the wavelength

The net charge when you rub a plastic ruler with fur​ would be infinitesimal or zero

The effect of friction between a plastic ruler and fur is evident when electrons are transferred from the hairy surface to the ruler's plane, ending with the ruler possessing a negative charge while the fur taking on a positive one.

As a result, the whole system presents with a net charge that is negative it converges due to the excess electrons now found on the ruler. However, occasionally, the magnitude of this charge is very small, consequently making it difficult to probe without reliable technology or instruments.

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Explanation:

There are many ways to achieve a healthier lifestyle and increase fitness. Healthy eating and constant exercise are essential for maintaining good physical and mental health. Through effective nutrition the human body is able to function better, there is an increase in disposition, improvement in immunity, improvement in blood rates, etc. Physical exercise, on the other hand, assists in strengthening muscles, controlling blood pressure, preventing cardiovascular disease, greater satisfaction, less stress, etc.

Some simple examples that can assist in improving health and fitness are:

Answer:

 N = 136.77 N

Explanation:

This is an exercise in Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis. In the attachment we can see the applied forces.

Let's use trigonometry to decompose the force F1

           cos θ = F₁ₓ / F₁

           sin θ = F_{1y} / F₁

           F₁ₓ = F₁ cos θ

           F_{1y} = F₁ sin θ

now let's apply Newton's second law to each axis

X axis

        F₁ₓ - F4 = m a

Y axis

        N + F3 + F_{1y} -F₂ -W = 0

the acceleration can be calculated with kinematics

        v = v₀ + a t

since the object starts from rest, the initial velocity is zero v₀ = 0

        a = v / t

        a = 20/3

        a = 6.667 m / s²

we substitute in the equation

        F₁ₓ = F₄ + m a

        F₁ₓ = 42 + 15  6,667

        F₁ₓ = 142 N

        F₁ cos θ = 142

        cos θ = 142/206 = 0.6893

        θ = cos⁻¹ 0.6893

        θ = 46.42º

now let's work the y axis

        N = W + F₂ - F₃ - F_{1y}

        N  = 15 9.8 + 144 -5 - 206 sin 46.42

        N = 286 - 149.23

        N = 136.77 N

Magnitude of vector A is  51.4 m and the angle of vector A with positive x-axis θ is 127.1° .

The quantities which have direction as well as magnitude is known as vector quantities .

We are given that ,

Ax is vector component on x -axis=−31m

Ay is vector component on y -axis=44m

Therefore, the magnitude of the vectors \(A_{x}\) and \(A_{y}\) is \(A\) which is given as,

\(A = \sqrt{A_{x} ^{2} }+ {A_{y} ^{2} }\\A = \sqrt{{-31} ^{2} }+ {41 ^{2} }}\\A = 51.4m\)

Thus, the magnitude of vector A will be 51.4 m

Now calculating the angle(θ) of the vector which make on the positive x axis, is given by the formula,

θ' = \(tan^{-1}\frac{Ax}{Ay}\)

θ' = \(tan^{-1}\frac{-31}{44}\)

θ' = \(-59.9\)°

Thus, here vector A is lies in 2nd quadrant which is  x-component of vector A that is negative and y-component is positive. So that from this to get the angle of vector with positive x-axis,

θ = 180° - θ'

θ=180 °- 52.9°

θ= 127.1°

Hence from above solution, the angle of vector A with positive x-axis θ is 127.1°

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Answer:

x = 4 t + 2 t^2      

the displacement is x which is zero at t = 0 and then increases indefinitely as t increases indefinitely

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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