what family tends to give away 2 electrons when forming a compoind

Answer:

I'd wanna see whats in the nuclues

Explanation:

Because its interesting to know what and how it really looks like up close. I also wanna know if an electron really has a light mass

Answer:

B

Explanation:

Dicots have a tap root system, while monocots have a fibrous root system and cotyledon produce taproots and Branched have taproot system for short time.

I hope it helps.

Answer:

Any group larger than hydrogen is more stable at the equatorial position. Thus, option D is correct.

Explanation:

The equatorial bonds of cyclohexane are those that extend from the perimeter of the ring.

When groups are axial, the dispersion forces between them are repulsive and thus unstable. There is generally less repulsion when any group larger than hydrogen is equatorial rather than axial and thus more stable.

When one ring substituent group is larger than the other, the larger group equatorial will be more stable due to steric and spacial reasons.

Thus option D is correct which is tertiary and the largest group of all.

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Answer:

Explanation:

pH = -log{H+]

{H+} = 10^(-pH)

pOH = 14 - pH

{OH-} = 10^(-pOH)

pH 2.90 (the approximate pH of lemon juice

{H+} = 10^(-2.9)

pOH = 14 - 2.9 = 11.1

{OH-} = 10^(-pOH) = 10^(-11.1)

pH 3.86 (the approximate pH of sauerkraut)

{H+} = 10^(-3.86)

pOH = 14 - 3.86 = 10.14

{OH-} = 10^(-pOH)  = 10^(-10.14)

pH 10.81 (the approximate pH of milk of magnesia)

{H+} = 10^(-10.81)

pOH = 14 - 10.81 = 3.19

{OH-} = 10^(-pOH) = 10^(-3.19)

pH 4.11 (the approximate pH of orange juice)

{H+} = 10^(-4.11)

pOH = 14 - 4.11 = 9.89

{OH-} = 10^(-pOH) = 10^(-9.89)

pH 11.61 (the approximate pH of household ammonia)

{H+} = 10^(-11.61)

pOH = 14 - 11.61 = 2.39

{OH-} = 10^(-pOH)  = 10^(-2.39)

Answer:

Hey there!

Quantitative measurements have data and statistics. For example, the liquid has a temperature of 55.6 degrees C is a quantitative measurement.

Let me know if this helps :)

1-ethoxybut-2-yne is the desired product of synthesis. using the principles of retrosynthetic design, compounds a and b are attached.

The SN2 reaction process needs a nucleophile attack from the carbon atom's contrary side. As a result, the product moves into the stereochemical location that the departing group had previously held. This is referred to as configuration inversion. A good illustration of a stereospecific reaction, in which several stereoisomers react to produce various stereoisomers of the result, is the SN2 reaction. Additionally, the most typical instance of Walden inversion occurs in the SN2 reaction, in which the configuration of an asymmetric carbon atom is reversed.

In the first step of the given reaction, the SN2 reaction between the compound A and NaCH₂CH₃ gives the product B. In the second step after deprotonation of aikyne, it reacts with CH₃Br to give 1-ethoxybut-2-yne.

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it is AExplanation because a+w=a

Available phosphorus levels decline in lower pH, acidic soils because of the increased fixation of phosphorus by soil minerals.

In acidic soils, the pH is low, which means that the soil is more acidic.

Under these conditions, the availability of phosphorus to plants decreases.

This decrease occurs primarily due to the increased fixation or binding of phosphorus by soil minerals, particularly iron (Fe), aluminum (Al), and calcium (Ca) compounds.

When the soil pH is low, these minerals become more soluble and active in binding phosphorus.

The positively charged surfaces of these minerals attract and bind to the negatively charged phosphate ions (PO4 3-) present in the soil.

This binding process, known as phosphorus fixation, reduces the amount of available phosphorus in the soil solution, making it less accessible to plants.

Additionally, the acidic conditions in the soil can also lead to the formation of insoluble compounds, such as iron and aluminum phosphates, further reducing the availability of phosphorus for plant uptake.

To mitigate the decline in available phosphorus in acidic soils, it is common to apply phosphorus fertilizers to provide an additional source of this essential nutrient for plant growth.

Soil amendments or liming materials can also be used to raise the pH of acidic soils, which helps to reduce phosphorus fixation and improve its availability to plants.

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To produce 5.0 kg of water, you would need approximately 0.555 kg of hydrogen gas and 0.278 kg of oxygen gas.

Water (H₂O) consists of two hydrogen atoms (H) and one oxygen atom (O). To produce 5.0 kg of water, you would need an equal amount of hydrogen gas (H₂) and oxygen gas (O₂) in a 2:1 ratio, as water has the chemical formula H₂O. The molar mass of hydrogen is 2 g/mol, and the molar mass of oxygen is 32 g/mol.

To calculate the total mass of hydrogen and oxygen needed, we can use the molar ratios:

Mass of hydrogen gas (H₂) = (2/18) * 5.0 kg = 0.555 kg

Mass of oxygen gas (O2) = (1/18) * 5.0 kg = 0.278 kg

Therefore, to make 5.0 kg of water, roughly 0.555 kg of hydrogen gas and 0.278 kg of oxygen gas are required.

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Answer:

d. Equinox​

Explanation:

A certain day in spring and autumn where the amount of daytime hours and nighttime hours are the same is called equinox.

Equinox occurs twice in a year on March 20 and September 23rd.

Answer:

135.6

Explanation:

12 * 11.3 = 135.6

To find the mass you have to multiply the density and volume together

If you already have the mass you divide the mass by either the density or volume

Answer:

Your answer is attached DAME!!!

Mass can neither be created nor destroyed.

Mass is described as the quantity of matter in a physical body. It can also be a measure of the body's inertia, the resistance to acceleration when a net force is applied.

The law of conservation of mass helps us to understand that mass can neither be created nor destroyed, although it may be rearranged in space, or the entities associated with it may be changed in form.

According to the law of conservation of mass, the mass of the reactants must be equal to the mass of the products for a low energy thermodynamic process.

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Answer:

Presence of an Electrolyte

Metal Surface

Oxygen or Other Oxidizing Agent

Difference in Potential

Electrochemical Pathway

Explanation:

The Jones reductor is more selective than the Walden reductor in converting hexavalent chromium (Cr(VI)) to trivalent chromium (Cr(III)).

The Jones reductor and the Walden reductor are both chemical reagents used in analytical chemistry. The Jones reductor, also known as chromous chloride, is a strong reducing agent that is commonly used to convert hexavalent chromium (Cr(VI)) to trivalent chromium (Cr(III)). This reduction reaction is important in various analytical techniques, such as the determination of chromium in environmental samples.

On the other hand, the Walden reductor, also known as zinc amalgam, is used to reduce various functional groups, such as carbonyl compounds and nitro groups. It is commonly employed in organic synthesis.

When comparing the selectivity of the two reductors, the Jones reductor is more selective than the Walden reductor in converting hexavalent chromium (Cr(VI)) to trivalent chromium (Cr(III)). This means that the Jones reductor is better suited for analyzing one analyte in a solution containing multiple other species.

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The correct option is D, that is, the Jones reductor is more selective than the Walden reductor, and the Jones reductor is better suited for analyzing one analyte in a solution containing multiple other species.

This is due to the fact that the Jones reductor is capable of reducing a wide range of functional groups to their corresponding hydrocarbons, while the Walden reductor is limited in the types of functional groups that it can reduce.

In addition, the Jones reductor is more effective at reducing polyfunctional molecules and is better suited for analyzing one analyte in a complex mixture due to its selectivity and versatility.

The Jones reductor is a powerful and versatile chemical reagent that can be used to reduce a wide range of functional groups to their corresponding hydrocarbons.

The Walden reductor, on the other hand, is more limited in the types of functional groups that it can reduce. While both reductors are useful tools in the field of organic chemistry, the Jones reductor is generally considered to be more selective and more effective at reducing polyfunctional molecules.

In addition, the Jones reductor is better suited for analyzing one analyte in a complex mixture due to its selectivity and versatility. Therefore, the correct answer is D.

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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Out of the given options, H3PO4 (phosphoric acid) and H2CO3 (carbonic acid) are examples of polyprotic acids.

Phosphoric acid has three acidic hydrogen atoms that can be ionized in aqueous solutions. The three ionization reactions occur stepwise with each successive proton having a lower acid strength. Similarly, carbonic acid has two acidic hydrogen atoms, and the ionization of each occurs stepwise, giving rise to bicarbonate and carbonate ions.

HC2H3O2 (acetic acid) and HNO3 (nitric acid) are not polyprotic acids as they have only one ionizable hydrogen atom. Acetic acid can donate one proton to form an acetate ion, whereas nitric acid can donate one proton to form a nitrate ion.

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Answer:

meter or metric system

Explanation:

Due to its very symmetric structure, BF3 (Boron Trifluoride) is non-polar. Because of its triangular planar structure, the three BF bonds' individual dipole moments cancel out, bringing the compound's overall dipole moment to zero.

Al-Cl, Si-Cl, Ni-P, Cu-Br

The difference in the electronegativity of the components determines the polarity of a bond. The propensity of an atom to gain an electron and form an anion or to have an electron nearby when in a covalent bond (sharing electrons) is known as this attribute.

The atom will find it more challenging to attract an electron the bigger the atomic radius since the attractive force will be less powerful. In the periodic table, the electronegativity rises from left to right and from bottom to top.

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Answer:

Because the toxic waste in it will kill it

To determine the equilibrium concentration of CO2 when a mixture of solid nickel(II) oxide and 0.16 M carbon monoxide is allowed to come to equilibrium at 1500 K, we need to follow these steps:

Step 1: Write the balanced chemical equation
NiO(s) + CO(g) ⇌ Ni(s) + CO2(g)

Step 2: Set up an ICE (Initial, Change, Equilibrium) table

           CO   CO2
Initial:  0.16   0
Change:   -x     +x
Equilibrium: (0.16-x) x

Step 3: Write the equilibrium expression using the balanced equation and equilibrium concentrations
Kc = [CO2]/[CO]

Step 4: Find the equilibrium constant (Kc) value for the reaction at 1500 K. For this problem, the value of Kc is not provided. You'll need the Kc value to determine the equilibrium concentration of CO2.

If the Kc value is given, you can proceed with Step 5.

Step 5: Substitute the equilibrium concentrations and Kc value into the equilibrium expression
Kc = x/(0.16-x)

Step 6: Solve for x, which represents the equilibrium concentration of CO2

Once you have found the value of x, the equilibrium concentration of CO2 will be x M.

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Water different from most substances during phase changes because water changes into gaseous water or steam

Those portion of a system that are physically distinct and mechanically separable from other portion of the system are called phases and a phase change is occurring the liquid water is changing to gaseous water or steam and on molecular level the intermolecular forces between the water molecule are decreasing the heat is providing enough energy for the water molecule to overcome these attractive forces

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Answer:Nitrogen and hydrogen combine to form ammonia via the following reaction: 1 N2 (s) + 3 H2 (g) → 2 NH3 (g)

The empirical formula with whole number subscripts is \(C_3H_3O_1\). Therefore, we need to multiply the subscripts by 1  to get the empirical formula in whole numbers. Option B is correct .

To determine the whole number subscripts of the empirical formula, we need to find the smallest set of integers that can be multiplied to the subscripts to get whole numbers. To do this, we can divide each subscript by the smallest subscript and round to the nearest whole number.

In this case, the smallest subscript is 1, so we can divide each subscript by 1:

C 2.67 ÷ 1 = 2.67 ≈ 3

H 3 ÷ 1 = 3

O 1 ÷ 1 = 1

So, the empirical formula with whole number subscripts is  \(C_3H_3O_1\). Therefore, we need to multiply the subscripts by 1 (option B) to get the empirical formula in whole numbers.

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The synthesis of the following compounds from butanoic acid using reagents from the table can be carried out as follows:

a. Synthesis of 3-hydroxybutanoic acid from butanoic acid using NaBH4 and H3O+ reagents. Synthesis scheme: NaBH4, H3O+

b. Synthesis of butan-1-ol from butanoic acid using LiAlH4 and H3O reagents. Synthesis scheme: LiAlH4, H3O

c. Synthesis of butane from butanoic acid using H2/Pt reagents. Synthesis scheme: H2/Pt

d. Synthesis of butan-1-ol from butanoic acid using BH3/THF and H2O2/NaOH reagents. Synthesis scheme: BH3/THF, H2O2/NaOH

e. Synthesis of butyl bromide from butanoic acid using PBr3 reagent. Synthesis scheme: PBr3Therefore, the correct order of reagents used for the synthesis of the given compounds from butanoic acid are:

a. NaBH4, H3O+b. LiAlH4, H3Oc. H2/Ptd. BH3/THF, H2O2/NaOHe. PBr3

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The helix has a characteristic rise of 5.4 angstroms per turn and an average of 3.6 residues per turn. It can be either right or left-handed, depending on the direction of the helical turn. So, The correct answer is option: d.

However, it is not true that the alpha helix can accommodate only glycine and alanine residues in the center core of the helix. Other residues can also be found in the core, depending on their size and chemical properties. Therefore, the correct answer is (d) can accommodate only glycine and alanine residues in the center core of the helix.

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Answer:

Conduction

Explanation:

Conduction can be regarded as transfer of thermal energy which exist

between two or more objects that are in contact with each other. From the question, the spoon touches the hot liquid and heat is transferred to the spoon through conduction

The number of moles of \(CaCl_2\) produced when 1.8 moles of HCl were used is 0.9 moles. The unit of \(CaCl_2\) is moles (mol).

The balanced chemical equation for the reaction is \(CaCO_3\) + 2HCl → \(CaCl_2\) + \(H_2O\) + \(CO_2\)

The stoichiometry of the reaction indicates that 1 mole of calcium carbonate (CaCO) reacts with 2 moles of hydrochloric acid (HCl) to give 1 mole of calcium chloride (\(CaCl_2\)), 1 mole of water (\(H_2O\)), and 1 mole of carbon dioxide (\(CO_2\)).

Given the number of moles of HCl used is 1.8, we will calculate the number of moles of \(CaCl_2\) that will be produced. This can be done by using stoichiometry.

From the balanced chemical equation, 1 mole of \(CaCO_3\) reacts with 2 moles of HCl to produce 1 mole of \(CaCl_2\).

Thus, using mole ratio, the number of moles of \(CaCl_2\) produced will be

= number of moles of HCl x (1 mole \(CaCl_2\)/2 moles HCl)

= 1.8 moles x (1 mole \(CaCl_2\)/2 moles HCl)

= 0.9 moles

Therefore, the number of moles of \(CaCl_2\) produced when 1.8 moles of HCl were used is 0.9 moles. The unit of \(CaCl_2\) is moles (mol). Thus, the answer is 0.9 mol.

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Answer:

When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.

Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.