What happened when the giraffe stepped on the grape?​

Answers

Answer 1

What are you asking? Is there a unit of measurement/weight for the grape and giraffe?


Related Questions

i need help with this math problem (please ASAP) (30 POINTS)

i need help with this math problem (please ASAP) (30 POINTS)

Answers

Answer:

y = 1/49, missing number is 49

-------------------------

Given

Function y = 7ˣ

Find the value of y when x = - 2

y = 7 ⁻² = 49 ⁻¹ = 1/49

Write an inequality that represents the graph

Write an inequality that represents the graph

Answers

Answer:

y<=-1/2x-2

Step-by-step explanation:

pls answer
8 to 11 asap

pls answer 8 to 11 asap

Answers

Answer:

8) Area of triangle ABC is 60

   Area of triangle XYZ is 540

9) The ratio is 1:9

10) (use Pythagorean theorem)

     BC is 12 \(\sqrt{13^{2}-5^{2} } =12\)

     YZ=39 (the legs are the same because it is an Isosceles triangle)

11) the ratio is 1:3

Step-by-step explanation:

15(n−10)=6−312 what is n

Answers

Answer:

ATQ= 15 is 1/5 and 312 is 3/12 sorry for that

1/5(N-10)=6-3/12

1/5N -2= 6/1 - 3/12

1/5N-2 = 72 -3/12 = 69/12

69/2 = 5.75

1/5N = 5.75-2 = 3.75

N= 3.75/.2

18.75

Step-by-step explanation:

Deshaun invested in a savings bond for 4 years and was paid simple interest at an annual rate of 2%. The total interest that he earned was $160. How much did he invest?

Answers

For a Simple Interest of $160, the amount that he invested is $2000.

Simple interest is a quick and simple formula for figuring out how much interest will be charged on a loan. The daily interest rate, the principle, and the number of days between payments are multiplied to calculate simple interest.

Given:

Simple Interest (S.I.) = $160

Rate of Interest (R) = 2%

Time Period (T) = 4 Years

Let the Principal Amount be $P

We know,

\(S.I. =\frac{P*R*T}{100}\)

Putting the given values in the formula, we get:

\(S.I. =\frac{P*R*T}{100}\\S.I. =\frac{P*2*4}{100} =\frac{P*8}{100}\\ 160 =\frac{P*8}{100} \\P = \frac{160*100}{8} =\frac{16000}{8} = 2000\)

Hence, He Invested $2000

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Answer:

$2,000

Step-by-step explanation:

Simple Interest Formula

\(\large\boxed{\sf I = Prt}\)

where:

I = Total interest accrued.P = Principal.r = Interest rate (in decimal form).t = Time (in years).

Given values:

I = $160r = 2% = 0.02t = 4 years

Substitute the given values into the formula and solve for P:

\(\implies \sf 160=P \cdot 4 \cdot 0.02\)

\(\implies \sf 160=0.08P\)

\(\implies \sf P=\dfrac{160}{0.08}\)

\(\implies \sf P=2000\)

Therefore, the amount Deshaun invested was $2,000.

What is a nonlinear graph called?

Answers

Any function whose graph is NOT a line is said to be nonlinear. It has the equation f(x) = ax + b. With the exception of the form f(x) = ax + b, its equation can take any form. Any two points on the curve have the same slope.

To ascertain whether a table of values is a linear function, follow these steps:

Find the variations between each pair of x numbers that follow.Find the variations between each pair of y values that follow.Discover the matching ratios between y and x differential amounts.Only the function is linear if all ratios are NOT equal.

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Determine the global extreme values of the f(x,y)=11x−5y if y≥x−3,y≥−x−3,y≤11. (Use symbolic notation and fractions where needed.)

Answers

The global extreme values of the function `f(x,y) = 11x - 5y` under given conditions are:`f(x,y) = 16x + 15` (maximum)`f(x,y) = 11x - 55` (minimum).

Given function is `f(x,y)=11x−5y`We need to determine the global extreme values of the given function under the following conditions:y ≥ x - 3y ≥ -x - 3y ≤ 11Now, we need to find the critical points of the given function. For that, we'll calculate partial derivatives of the given function w.r.t x and y.`∂f/∂x = 11``∂f/∂y = -5`As we can see, the partial derivative of the function w.r.t x is positive. Therefore, the critical points of the given function would be the points where `∂f/∂y = -5 = 0`.Since there's no such point satisfying the above equation under given conditions, we can say that there's no critical point under given conditions.Now, let's evaluate the function at the boundaries given:At `y = x - 3`, `f(x,y) = 11x - 5y``= 11x - 5(x - 3)``= 6x + 15`At `y = -x - 3`, `f(x,y) = 11x - 5y``= 11x - 5(-x - 3)``= 16x + 15`At `y = 11`, `f(x,y) = 11x - 5y``= 11x - 5(11)``= 11x - 55`Now, to find the maximum value of `f(x,y)` under given conditions, we need to choose the maximum value among the above calculated values.In this case, `f(x,y)` is maximum at `y = -x - 3`, which is `16x + 15`.Therefore, the maximum value of `f(x,y)` under given conditions is `16x + 15`.Similarly, to find the minimum value of `f(x,y)` under given conditions, we need to choose the minimum value among the above calculated values.In this case, `f(x,y)` is minimum at `y = 11`, which is `11x - 55`.Therefore, the minimum value of `f(x,y)` under given conditions is `11x - 55`.Hence, the global extreme values of the function `f(x,y) = 11x - 5y` under given conditions are:`f(x,y) = 16x + 15` (maximum)`f(x,y) = 11x - 55` (minimum).

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as it reaches the point (1, 5), the y-coordinate is increasing at a rate of 4 cm/s. how fast is the x-coordinate of the point changing at that instant?

Answers

The rate of increase of the y-coordinate as it approaches the point (1, 5) is 4 cm/s.At that instant, the x-coordinate of the point is not changing; it is staying at 1.

When a point reaches a certain coordinate, it means that the point is not changing anymore. In this case, the point has reached the coordinate (1, 5), which means that the x-coordinate (1) is not changing, while the y-coordinate (5) is increasing at a rate of 4 cm/s. Therefore, the x-coordinate of the point is not changing at that instant.

x = 1

Rate of Change (x-coordinate) = 0 cm/s

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Point F° is the image when point F is reflected over the line x = -2 and then over the line y = 3. The location of F° is (5, 7). Which of the following is the location of point F7

A(-5,-7)
B(-9,-1)
C(-1,-3)
D(-1,-13)

Answers

The location of the given point F7 is: B(-9, -1)

How to find the coordinates after transformation?

There are different transformations such as:

Reflection

Translation

Rotation

Dilation

Since Point F' is the image when point F is reflected over the line x= -2 and then over the line y = 3. The location of F' is (5, 7).

So here we have to do graph the points, then connected the points i.e. 5 and 7. And, then reflect it over the line i.e. x = -2, and y = 3

So here the answer should be (-9,-1)

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on a two-week job, a repairman works a total of 70 hours, He charges 75$ plus 40$ per hour. an equation shows this relationship, where x is the number of hours and y is the total fee.which number is the slope of the line shown by the equation?A. 14b. 40c. 70d. 7

Answers

Given:

Total number of hours = 70 hours

Amount he charges (base fee) = $75

Amount he charges per hour =

In the first week of its release, the latest blockbuster movie sold $16. 3 million dollars in tickets. The movie’s producers use the formula Pt=P₀e^-0. 4t , to predict the number of ticket sales t weeks after a movie’s release P₀, where is the first week’s ticket sales. What are the predicted ticket sales to the nearest $0. 1 million for the sixth week of this movie’s release? (Note: t = 0 for the first week. )

( the ₀ is supposed to represent a small zero)

Answers

The equation Pt=P₀\(e^-0\). 4t is used to predict the ticket sales of a movie after its release. For the latest blockbuster movie, the predicted ticket sales for the sixth week of the movie’s release is $7. 9 million to the nearest $0. 1 million.

The formula used to predict the number of ticket sales t weeks after a movie’s release is Pt=P₀\(e^-0\). 4t, where P₀ is the first week’s ticket sales. In the case of the latest blockbuster movie, the first week’s ticket sales was $16. 3 million. To calculate the predicted ticket sales for the sixth week, the time t must be set to 6. The equation then becomes , which simplifies to Pt=7. 9 million. The predicted ticket sales for the sixth week of the movie’s release is therefore $7. 9 million to the nearest $0. 1 million. The equation  is a useful tool for predicting the ticket sales of a movie over time. It reflects the fact that, generally, ticket sales for a movie will steadily decline over time, with the rate of decline being determined by the value of the exponent, -0. 4 in this case. By plugging in different values for t, one can easily calculate the predicted ticket sales for a movie at any given time.

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Which is the better buy?
Frozen Peas
Cost (dollars)
Weight (ounces)
O Brand A
A B
2
16
3
28
O Brand B
O The unit cost is the same.

Answers

The better buy is given by the following brand:

Brand A.

How to obtain the better buy?

The better buy is obtained applying the proportions in the context of the problem.

A proportion is applied as the cost per ounce is given dividing the total cost by the number of ounces.

Then the better buy is given by the option with the lowest cost per ounce.

The cost per ounce for each brand is given as follows:

Brand A: 16/2 = $8 per ounce.Brand B: 28/3 = $9.3 per ounce.

$8 per ounce is a lesser cost than $9.3 per ounce, hence the better buy is given by Brand A.

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The mileage (in 1,000s of miles) that car owners get with a certain kind of radial tire is a random variable having an exponential distribution with a mean of 50.
a. What is the probability that a tire will last at most 40,000 miles? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)
b. What is the probability that a tire will last at least 65,000 miles? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)
c. What is the probability that a tire will last between 70,000 and 80,000 miles? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

Answers

a)  The probability that a tire will last at most 40,000 miles is approximately 0.3297

b) The probability that a tire will last at least 65,000 miles is approximately 0.0656

c)The probability that a tire will last between 70,000 and 80,000 miles is approximately 0.0505...

a. We are given that the mileage that car owners get with a certain kind of radial tire is a random variable having an exponential distribution with a mean of 50. Therefore, the rate parameter λ can be found as follows:

λ = 1/mean = 1/50 = 0.02

Now, we need to find the probability that a tire will last at most 40,000 miles. This can be calculated using the cumulative distribution function (CDF) of the exponential distribution:

P(X ≤ 40) = 1 - e^(-λx) = 1 - e^(-0.02*40) ≈ 0.3297

Therefore, the probability that a tire will last at most 40,000 miles is approximately 0.3297.

b. To find the probability that a tire will last at least 65,000 miles, we can use the same exponential distribution with rate parameter λ = 0.02:

P(X ≥ 65) = e^(-λx) = e^(-0.02*65) ≈ 0.0656

Therefore, the probability that a tire will last at least 65,000 miles is approximately 0.0656.

c. Finally, we need to find the probability that a tire will last between 70,000 and 80,000 miles. This can be calculated using the CDF of the exponential distribution as follows:

P(70 ≤ X ≤ 80) = P(X ≤ 80) - P(X ≤ 70)

= (1 - e^(-λ80)) - (1 - e^(-λ70))

= e^(-0.0270) - e^(-0.0280) ≈ 0.0505

Therefore, the probability that a tire will last between 70,000 and 80,000 miles is approximately 0.0505.

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HELP FAST !!! WILL GIVE BRAINLIEST!!

HELP FAST !!! WILL GIVE BRAINLIEST!!

Answers

Answer:

56 degrees

Step-by-step explanation:

Coz they're corresponding angles

what does it mean to say that an event has a timebox? (choose the best answer) a. the event must happen by a given time. b. the event must happen at a set time. c. the event must take at least a minimum amount of time. d. the event can take no more than a maximum amount of time.

Answers

The correct option d. the event can take no more than a maximum amount of time, described the  an event has a timebox.

Define the term timebox?

A timebox is a set amount of time during which a work must be completed in agile software development.

Timeboxes are frequently employed to control risk in software development. Development teams are frequently given a deadline of a certain number of weeks and requested to produce a releaseable update to software.Giving an activity a set, maximum amount of time is known as timeboxing. A time box is the name of that unit of time. The purpose of timeboxing is to specify and set a time restriction for each task. Timeboxing is a technique used by Scrum to concretely define ambiguous or open-ended tasks as well as for all Scrum events.

Thus, when an event has a timebox, it signifies that the event can only last a certain length of time.

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Find the unit vector in the direction opposite to that of u = (3,0,5)
A)1/34 (3,0,5)
B) -1/√34 (3,0,5) C) =1/√34 (-3,0,5) D) 1/8 (-3,0,–5)

Answers

The unit vector which are in opposite direction of the u = (3,0,5) is given by option B.  -1/√34 (3,0,5) .

Vector u = ( 3, 0, 5 )

Magnitude of u is equal to

|u| = √3² + 0² + 5²

⇒ |u| = √ 9 + 25

⇒ |u| = √34

Let the required unit vector opposite in the direction of u be w

Opposite direction of u is represented by the negation of u

negation of u = ( -3 , 0 , -5 )

⇒ w = ( -3 , 0 , -5 )

Magnitude of w is equal to

|w| = √(-3)² + 0² + (-5)²

⇒|w| = √34

Unit vector w = ( 1/√34)( -3 , 0 , -5 )

Therefore, the required unit vector in the opposite direction of u is equal to option B . ( 1/√34)( -3 , 0 , -5 ).

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what is the answer to the equation 14.95x6.5?

Answers

Answer:

97,175

Step-by-step explanation:

I don't think It's necessary, but I am gonna do it anyways.

15*6=90

15*7=105

105 - 90 =15

15/2 =7,5

90+7,5= 97,5

15*6,5=  97,5

0,05*6,5= 0,325

97,5 - 0,325 =   97,175

Plzzzzzzzzzzz help ​

Plzzzzzzzzzzz help

Answers

Answer:

AAA

Step-by-step explanation:

14 / 19 Marks
61%
.
Some of the children at a school arrive by car.
30% of the children at the school are boys.
• 60% of the boys at the school arrive by car.
• 80% of the girls at the school arrive by car.
What is the probability that a child chosen
at random from the school arrives by car? I
Give your answer as a decimal.

Answers

Answer:

Decimal version: 71%

Percentage version: 0.71

Step-by-step explanation:

You can build a two-way relative frequency table to represent the data:

These are the columns and rows:

              Car         No car      Total

Boys

Girl

Total

Fill the table

30% of the children at the school are boys

            Car         No car      Total

Boys                                       30%

Girl

Total

60% of the boys at the school arrive by car

That is 60% of 30% = 0.6 × 30% = 18%

            Car         No car      Total

Boys      18%                         30%

Girls

Total

By difference you can fill the cell of Boy and No car: 30% - 18% = 12%

            Car         No car      Total

Boy       18%           12%         30%

Girl

Total

Also, you know that the grand total is 100%

            Car         No car      Total

Boy       18%           12%         30%

Girl

Total                                     100%

By difference you fill the total of Girls: 100% - 30% = 70%

            Car         No car      Total

Boy       18%           12%         30%

Girl                                         70%

Total                                     100%

80% of the girls at the school arrive by car

That is 80% of  70% = 0.8 × 70% = 56%

            Car         No car      Total

Boy       18%           12%         30%

Girl       56%                         70%

Total                                     100%

Now you can finish filling in the whole table calculating the differences:

            Car         No car      Total

Boy       18%           12%         30%

Girl        56%         14%         70%

Total     74%          26%      100%

Having the table completed you can find any relevant probability.

The probability that a child chosen at random from the school arrives by car is the total of the column Car: 74%.

That is because that column represents the percent of boys and girls that that  arrive by car: 18% of the boys, 56% of the girls, and 74% of all the the children.

Recall that convex functions satisfy ƒ(0x1₁ + (1 − 0)x2) ≤ 0 ƒ (x1) + (1 − 0) ƒ (x₂) for any [0, 1] and any x₁, x2 in the domain of f. (a) Suppose f(x) is a convex function with x E Rn. Prove that all local minima are global minima. I.e., if there is a point xo such that f(x) ≥ f(xo) for all x in a neighbourhood of xo, then f(x) ≥ ƒ(x) for all x € R". (b) Draw a graph of a (non-convex) function for which the statement in part (a) is not true, and indicate why on the graph.

Answers

(a) If f(x) is a convex function with x ∈ ℝⁿ, then all local minima of f(x) are also global minima. In other words, if there exists a point xo such that f(x) ≥ f(xo) for all x in a neighborhood of xo, then f(x) ≥ f(xo) for all x ∈ ℝⁿ.

(b) A graph of a non-convex function can be visualized to understand why the statement in part (a) is not true. It will show a scenario where a local minimum is not a global minimum.

(a) To prove that all local minima of a convex function are also global minima, we can utilize the property of convexity. Suppose there is a point xo such that f(x) ≥ f(xo) for all x in a neighborhood of xo. We assume that xo is a local minimum. Now, consider any arbitrary point x in ℝⁿ. We can express x as a convex combination of xo and another point y in the neighborhood, using the convexity property: x = λxo + (1 - λ)y, where λ is a scalar between 0 and 1. Using this expression, we can apply the convexity property of f(x) to get f(x) ≤ λf(xo) + (1 - λ)f(y). Since f(x) ≥ f(xo) for all x in the neighborhood, we have f(y) ≥ f(xo). Therefore, f(x) ≤ λf(xo) + (1 - λ)f(y) ≤ λf(xo) + (1 - λ)f(xo) = f(xo). This inequality holds for all λ between 0 and 1, implying that f(x) ≥ f(xo) for all x ∈ ℝⁿ, making xo a global minimum.

(b) A graph of a non-convex function can demonstrate a scenario where the statement in part (a) is not true. In such a graph, there may exist multiple local minima, but one or more of these local minima are not global minima. The non-convex nature of the function allows for the presence of multiple valleys and peaks, where one of the valleys may contain a local minimum that is not the overall lowest point on the graph. This occurs because the function may have other regions where the values are lower than the local minimum in consideration. By visually observing the graph, it becomes apparent that there are points outside the neighbourhood of the local minimum that have lower function values, violating the condition for a global minimum.

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210 suite is marked down by 30%.Find the sale price

Answers

Answer:

$147

Step-by-step explanation:

Solve the inequality.
6x + 10 + 10x < 4(4x + 3)

Answers

Answer:

X = all #'s

why?

6x+10+10x < 4(4x+3)

Combined liked terms

16x + 10 < 16x +12

you can see that there is X on both sides and the lowest one has a +10 and the highest has a +12 so it will always be greater by 2

Answer:

undeterminate (all real numbers are a solution)

Step-by-step explanation:

1) multiply 4 by 4x and 3

6x + 10 + 10x < 16x + 12

2) added up the terms with x

16x + 10 < 16x + 12

3) add at the two members -16x

10 < 12

4) notice the 10 is ever < 12, so the inhequality is undetermined

Find the value of each variable

Find the value of each variable

Answers

The missing sides of the special right triangles are listed below:

Case 1: y = √2 · 13, x = 13

Case 2: x = y = 15√2

Case 3: x = 6, y = 3√3

Case 4: x = 17√3, y = 17

Case 5: x = y = 10

Case 6: x = 50, y = 25

Case 7: x = y = 4√7

Case 8: x = 16√3, y = 8√3

Case 9: x = 11√3, y = 33

Case 10: x = 3√2, y = 2√6

Case 11: x = √10, y = 2√5

Case 12: x = 4√7, y = 8√21

How to find the length of missing sides

Herein we find twelve cases of special right triangles whose missing sides must be determined by using the following rules:

45 - 90 - 45 Right triangle

r = √2 · x = √2 · y

30 - 60 - 90 Right triangle

x = (1 / 2) · r

y = (√3 / 2) · r = √3 · x

Where:

x - Shortest leg.y - Longest leg. r - Hypotenuse.

Case 1

y = √2 · 13

x = 13

Case 2

x = y = 15√2

Case 3

x = 3 / (1 / 2)

x = 6

y = 3√3

Case 4

x = 34 · (√3 / 2)

x = 17√3

y = 34 · (1 / 2)

y = 17

Case 5

x = y = 10

Case 6

x = 25√3 / (√3 / 2)

x = 50

y = 25√3 / √3

y = 25

Case 7

x = y = 2√14 · √2 = 2√28 = 4√7

Case 8

x = 24 / (√3 / 2)

x = 48 / √3

x = 16√3

y = 24 / √3

y = 8√3

Case 9

x = 22√3 · (1 / 2)

x = 11√3

y = 22√3 · (√3 / 2)

y = 33

Case 10

x = √18

x = 3√2

y = √6 / (1 / 2)

y = 2√6

Case 11

x = √10

y = √20

y = 2√5

Case 12

x = 4√21 / √3

x = 4√7

y = 4√21 / (1 / 2)

y = 8√21

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WILL MARK BRAINLIEST IF GOTTTEN RIGHT

WILL MARK BRAINLIEST IF GOTTTEN RIGHT

Answers

Answer:

C. x = 5 and y = 10

Step-by-step explanation:

60/12=5

Half the problem is solved:

100/2=50

50/5=10

I hope I helped!

a computer downloads data at 500 KB per second. How many kilobytes can you download in 5 minutes? answers this as a rate.

Answers

Answer : 150000kilobytes

Known that

500KB = 1 sec

Question

5minutes = ?KB

Way to do

5 minutes × 60 = 300seconds

300seconds × 500KB = 150000KB

Please help me with this Geometry Question

Please help me with this Geometry Question

Answers

The value of x from the given figure is 12 units.

What are similar triangles?

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

From the given figure,

Consider ΔADC and ΔABC,

∠C=∠C (Reflex property)

AC=AC (Reflex property)

∠BAC=∠CDA=90°

By AA similarity, ΔADC ~ ΔABC

So, AC/BC = DC/AC

x/36 = 4/x

x²=36×4

x²=144

x=12 units

Therefore, the value of x from the given figure is 12 units.

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Please help me with this Geometry Question

A scientist invents a car that can travel for many hours without stopp
car travels around a track at 54 miles an hour for 24 hours. At the end of the 24
hours, how far has the car traveled?

Answers

Answer:

Well 51 per hour and there is 24 hours so you just multiply the two together. Which you would get get 1,224 Miles

let f be the function given by and g be the function given by . find the first four nonzero terms and the general term for the power series expansion of f(t) about t

Answers

The Taylor series formula in summation notation f(t) = Σ[n=0 to infinity] { (1/n!)f^n(a)(t-a)^n } where f^n(a) denotes the nth derivative of f(t) evaluated at t = a.

Since the functions f(t) and g(t) have not been given in the question, I cannot provide a specific answer to this question. However, I can provide a general approach to finding the power series expansion of a function about a point.

To find the power series expansion of a function f(t) about a point t = a, we can use the Taylor series formula:

f(t) = f(a) + f'(a)(t-a) + (1/2!)f''(a)(t-a)^2 + (1/3!)f'''(a)(t-a)^3 + ...

where f'(a), f''(a), f'''(a), ... are the first, second, third, and higher-order derivatives of f(t) evaluated at t = a.

To find the first four nonzero terms of the power series expansion, we can calculate the values of f(a), f'(a), f''(a), and f'''(a) at t = a, substitute them into the Taylor series formula, and simplify the resulting expression. The first four nonzero terms will be the constant term, the linear term, the quadratic term, and the cubic term.

To find the general term of the power series expansion, we can write the Taylor series formula in summation notation:

f(t) = Σ[n=0 to infinity] { (1/n!)f^n(a)(t-a)^n }

where f^n(a) denotes the nth derivative of f(t) evaluated at t = a. The general term of the power series expansion is given by the expression in the curly braces. We can use this expression to find any term in the series by plugging in the appropriate values of n and f^n(a).

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a diver was collecting water samples from a lake. he collected a sample at every 3m, starting at 5m below water surface. the final sample was collected at a depth of 35m.how many sample did he collected​

Answers

The diver collected water samples at every 3 meters, starting from 5 meters below the water surface, up to a final depth of 35 meters.

We can find the number of samples collected by dividing the total depth range by the distance between each sample and then adding 1 to include the first sample.

The total depth range is:

35 m - 5 m = 30 m

The distance between each sample is 3 m, so the number of samples is:

(30 m) / (3 m/sample) + 1 = 10 + 1 = 11

Therefore, the diver collected a total of 11 water samples.

Inventory is valued on the basis of equivalent units of inventory i.e. 2 x 500 ml ice cream are valued the same as a 1 litre of ice cream. Variable overheads vary with direct labour hours. Fixed overheads are allocated to products on the number of litres of ice cream produced (all ice cream irrespective of the size of the output).

500ml 1 litre
Sale price of the containers R10 R15
Expected inventories (units) 500ml 1 litre
Opening inventory 50 80
Closing inventory 70 170
Required:

1. Prepare a sales budget for the company in both litres and rands.

Answers

Fixed overheads are allocated to products on the number of litres of ice cream produced, irrespective of the size of the output. Liters Rands Expected Sales :500 ml ice cream = 60,000 litres

= 60,000 x R10

= R 600,0001 litre

ice cream = 80,000

litres = 80,000 x R 15 = R1,200,000

Total expected sales volume 140,000 litres R1,800,000 . From the given question, we are told that inventory is valued on the basis of equivalent units of inventory. Which means that two 500ml of ice cream is valued the same as one litre of ice cream. We are also told that variable overheads vary with direct labour hours. Fixed overheads are allocated to products on the number of litres of ice cream produced, irrespective of the size of the output.

Using this information we can prepare a sales budget for the company by estimating the sales volume in litres for each of the two sizes of ice cream containers and multiplying the sales volume by the respective sale price of each size. Since the number of litres is used to allocate fixed overheads, it is necessary to prepare the budget in litres as well. The total expected sales volume can be calculated by adding up the expected sales volume of the two sizes of ice cream products. The expected sales volume of 500 ml ice cream is 60,000 litres (500 ml x 0.12 million) and the expected sales volume of 1 litre ice cream is 80,000 litres (1 litre x 0.08 million). Adding up the two volumes, we get a total expected sales volume of 140,000 litres.

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