What happens after excitation in spectroscopy.
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Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃   ΔH = –183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O     ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂  ΔH = 183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O     ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

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It is possible to synthesize acetophenone from benzene via Friedel-Crafts acylation reaction using acetyl chloride and a Lewis acid catalyst such as aluminum chloride.

What is an acylation reaction?

The reaction would proceed as follows:

1. Acetyl chloride is reacted with aluminum chloride to form the acylium ion, \(CH_{3}CO^{+}\).

2. The acylium ion is then attacked by benzene, forming a resonance-stabilized intermediate.

3. Protonation and deprotonation steps lead to the formation of the final product, acetophenone.

The overall reaction can be represented as:

\(C_{6}H_{6}\) + \(CH_{3}COCl\) + \(AlCL_{3}\) → \(C_{6}H_{5}COCH_{3}\) + \(HCl_{}\) + \(AlCl_{4}^{-}\)

Note that this reaction is not a conversion of sodium benzoate to acetophenone, but rather a synthesis of acetophenone from benzene.

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The mass, in grams, of oxygen that will be produced from the reaction to two significant figures, will be 0.17 grams.

Mercury oxide decomposes to liquid mercury and oxygen gas. The equation for the decomposition reaction is represented below:

\(2HgO + heat --- > 2Hg + O_2\)

Mole of 2.25 g mercury oxide = mass/ molar mass

                = 2.25/216.59

                       = 0.0104 moles

Mole ratio of mercury oxide that decomposes and oxygen gas produced = 2:1.

Equivalent moles of oxygen gas produced = 0.0104/2

                                 = 0.0052 moles

Mass of 0.0052 moles oxygen gas = mole x molar mass

                                 = 0.0052 x 32

                                         = 0.1664 grams

To 2 significant figures, the amount of oxygen gas produced is 0.17 grams.

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Answer:ccccccccccccccccccccccccccccccccccccccc

Explanation:

Answer:

Networking; Repeat job; Investment; Constructive feedback.

Explanation:

Networking: Word of mouth is a great method to get yourself out there and gain more customers. Consider it free advertising.

Repeat job: Customers who feel they have a good relationship with you will come back, even if it means going out of their way to do so.

Investment: They may invest or offer to invest in your work.

Constructive feedback: Investment is not always financial, it can also be investing their time and knowledge in providing you with valuable feedback and tips.

Positive customer relations help you to connect with your customers more efficiently. It tells you about their requirements, helps you to resolve their problems, and create mutual understanding with them so we can conclude that building positive relationships with customers is very important.

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Answer:

It's because the NaCl and MgCl2 is shorter and easier to remember

Answer:

H2O- hydrogen bonding

CaCl2- ion-ion interaction

CH3CH(CH3)OH- hydrogen bonding

CH4- dispersion forces

NH3- hydrogen bonding

Explanation:

Intermolecular forces are secondary bond forces that hold the molecules of a substance together in a given state of matter.

Intermolecular forces account for quite a number of the observed physical properties of a substance such as the boiling and melting point.

If a compound contains hydrogen atom bonded to a highly electronegative element, hydrogen bonding becomes the most dominant intermolecular force, e.g in water and ammonia.

For nonpolar molecules, dispersion forces are the most dominant intermolecular forces. In ionic substance, ion-ion interaction becomes quite prominent.

Sharla finds a container labeled tungsten and Sharla found 2.05 moles of tungsten in the container.

Mole is the amount of substance of a system that contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12 and its symbol is “mol”. One mole of substance is equal to the value of 6.023 x 10^23 (Avogadro's number). It can be used to measure the products obtained from chemical reaction.

As, number of moles is mass / molar mass

so, molar mass of tungsten is 183.84 g/mol.

the number of moles of tungsten that Sharla found would be:

number of moles = 377.64 g / 183.84 g/mol = 2.05 mol

Therefore, Sharla found 2.05 moles of tungsten in the container.

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In English, you're asked to write a reflective narrative about a life event with a deeper impact than initially visible. Describe the event, your reaction, its deeper meaning, and how it shaped you.

This question pertains to reflective writing, a style typically used in English subject coursework. The task is about developing a narrative based on a memorable experience in your life that had a deeper impact than initially visible. Begin by selecting an event, which while appearing simple, had profound implications in retrospect. Describe the event in detail (who, what, where, when), discussing your personal reaction at the time. Then, explain its deeper meaning or the impact it had on you. Drawing conclusions about how this event shaped your perspectives or behaviours would constitute the reflective element of your narrative.

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There are several methods that can be used to separate zinc from brass. One method is to use a chemical process called solvent extraction, which involves dissolving the brass in a chemical solvent that will selectively extract the zinc. Another method is to use electroplating, which involves using an electric current to coat the brass with a layer of pure zinc. Once the zinc has been separated from the brass, it can be recovered by heating the brass to a high temperature, causing the zinc to vaporize and be collected.

Answer:

what are you trying say about BLANK 7 times?????????!!!!!!!!!!!!!!

Answer:

The correct answer is blank

Explanation:

plato

The limiting and excess reactant can be obtained as follow:

2Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted with 32 g of O₂

Therefore,

62.1 g of Mg will react with = (62.1 × 32) / 48 = 41.4 g of O₂

We can see from the above that only 41.4 g of O₂ is required to react completely with 62.1 g of Mg.

Thus, the limiting reactant is magnesium, Mg and the excess reactant is oxygen, O₂

The mass of the excess reactant remaining can be obtained as shown below:

Mass of excess reactant remaining = Mass given - mass reacted

Mass of excess reactant remaining = 100 - 41.4

Mass of excess reactant remaining = 58.6 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted to produce 80 g of MgO

Therefore,

62.1 g of Mg will react to produce = (62.1 × 80) / 48 = 103.5 g of MgO

Thus, the mass of product, MgO produced is 103.5 g

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Complete question:

If 62.1 grams of magnesium react with 100.0 grams of oxygen, how many grams of product are produced?

Which is the Limiting reactant?

Which is the Excess reactant?

How many grams of excess reactant remain?

It is best to fill the pipet to a point just above the calibration line, then adjust the volume by slowly releasing liquid, which will help to be more successful when working with a pipet.

To use a pipet successfully, it is important to ensure that the tip of the pipet is kept submerged when filling, as this will help to prevent air from getting into the pipet. Once the pipet is filled, it is best to fill it to a point just above the calibration line, then adjust the volume by slowly releasing liquid. This will help to reduce the chances of overfilling or spilling the liquid.

It is also important to be gentle when placing the pipet bulb on the pipet, as aggressive movements can cause the bulb to come loose or even break, resulting in injury. Additionally, the blue bulbs used in the lab are not meant to be attached to the pipet, but rather simply rest on top of it.

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Answer:

\(pH=11\)

Explanation:

Hello there!

In this case, since the ionization of the described base is:

\(base+H_2O\rightarrow OH^-+baseH^+\)

Thus, the equilibrium expression in terms of the reaction extent is:

\(Kb=5.86x10^{-6}=\frac{x^2}{0.187-x}\)

Thus, by solving for x we obtain:

\(5.86x10^{-6}({0.187-x})=x^2\\\\1.10x10^{-6}-5.86x10^{-6}x-x^2=0\)

So the values of x are:

\(x_1=0.0010M\\x_2=-0.0010M\)

So the feasible answer is 0.0010 M, thus we compute the pOH:

\(pOH=-log(0.0010M)=3\)

And therefore the pH:

\(pH=14-pOH=14-3\\\\pH=11\)

Best regards!

\(K_{sp}\) of the compound is found to be  5.04 ×\(10^{-10}\).

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = \([A^{+} ]^{a}\) \([B^{-} ]^{b}\)

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × \(10^{-2}\) g/L

molar mass = 288 g/ mol

∴ s= 3.60 × \(10^{-2}\) g/L ÷ 288 g/ mol = 1.25 ×\(10^{-4}\) mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

\(K_{sp}\) =[ \(M^{+3}\)] [ \(X^{-1}\)\(]^{3}\) = solubility product

∴ \(K_{sp}\) =\([s]^{} [3s]^{3}\)

∴ \(K_{sp}\) = 3 \(s^{4}\)

∴ \(K_{sp}\) = 3 × (3.60 × \(10^{-2}\) \()^{4}\)

∴ \(K_{sp}\) = 503.8848 ×\(10^{-8}\)  = 5.04 ×\(10^{-10}\)

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The number of moles of NaCl dissolved in the water to make the given solution is 1 mole.

A mole can be described as a unit that is employed to calculate the count of particles. The particles which are counted are usually identical entities, individually distinct.

The amount of chemical substance can be measured in the terms of the mole and the number of entities in one mole is approximately equal to 6.023 × 10 ²³.

Given, the one liter of a 1 M solution of NaCl.

The concentration of the NaCl solution = 1 M

The molarity of the given solution, \(M = n/V\)

The number of moles of NaCl, n = M ×V = \(\displaystyle {1 mol L^{-1}}\times{1L}\) = 1 mol

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The concentration of lead in the solution is 4.8 ppm.

The ppm (parts per million) is a unit used to express the concentration of a solution. It is defined as the number of parts (by mass) of a solute per million parts (by mass) of the solution. To convert from grams per 100 grams to ppm, we can use the following formula:

ppm = (mass of solute/mass of solution) x 10^6

In this case, the mass of solute (lead) is 0.00048 g, and the mass of solution is 100. g. Plugging these values into the formula, we get:

ppm = (0.00048/100) x 10^6

ppm = 4.8

Therefore, the concentration of lead in the solution is 4.8 ppm.

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The right answer is capillaries that metabolites like salts and food molecules are exchanged in capillaries together with waste products, oxygen, and carbon dioxide.

In the capillaries, waste, nutrients, and gases are delivered from the blood to the tissue.  Little blood arteries called capillaries create networks surrounding body cells by branching off from arterioles.

It is supplied to the blood during gas exchange from the lungs. Both the lungs and blood exchange carbon dioxide at the same time. The capillaries, a network of tiny blood veins found in the walls of the alveoli, are where this occurs in the lungs in between the individual alveoli.

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Answer:

Coeficient: 70219691

Exponent: 0

Explanation:

3.687×10⁵ = 0.3687×10⁶

Then:

2.589 × 10⁶ ÷ 3.687 × 10⁵ = 2.589 × 10⁶ ÷ 0.3687 × 10⁶

= (2.589/0.3687) × (10⁶ / 10⁶)

= 7.0219691 × 1

= 7.0219691 × 10⁰

Note:

10⁰ = 1

a. If XF is covalent, X couldn't be a metal. Because covalent bonding occurs between nonmetals. So this alternative is False.

b. If XF is ionic, X could be a nonmetal. Also False. Ionic bonding occurs between a metal and a nonmetal. In this case, we already have a nonmetal, which is F.

c. If XF is covalent, the name uses prefixes. True. When we have a covalent compound, the name of the nonmetal on the left has a prefix indicating the number of atoms of it.

d. If XF is covalent, X has a charge of +1. False. This would happen if it was ionic.

Answer: Alternative "C"

Answer:

Lysosomes are predominantly found in eukaryotic animal cells and are responsible for breaking down cellular debris

Explanation:

The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:

The southern hemisphere is currently experiencing "Summer"

Explanation:

The Southern hemisphere is experiencing summer because it is closer to the sun than the Northern Hemisphere and also, direct light is more hotter than indirect light.

So, first, let's try an EXPERIMENT!

Take a VERY bright flashlight or a very small laser that can't harm you or just burn a paper in 1 second.

Then, take a piece of paper, or maybe just your skin, (like your hand) and place it under the light or laser, (for the laser, you should probably take the paper), and place the light source right above your skin, then, after some time, when it gets hot, measure the temperature. (around like 30 seconds later),

Note down the temperature...

Now, do the same thing, accept, do it in a very weird angle, face it towards your paper or hand, but, do it in an angle. More than like 30 degrees. Then, after some time, note down the temperature.

You probably, noticed, that the direct light (the one with the straight light facing your paper or skin, was hotter). Look at the image below, and you can understand better.

So, the same thing applies to the earth. The southern hemisphere in this picture is facing more directly to the sun than the northern hemisphere. That is why your answer is

Thank you! Please mark me Brianliest!

Remember to have fun, and a nice day!

Answer:   summer

Explanation:

Mass of the pure silver deposited on a metal object made into the cathode of the cell is calculated to be 0.0217 gm.

The process of using electrodeposition to coat an object in a layer of metal is called electroplating .

As we know that, Q = I * t

=0.270 * 72

= 19.44 C

Here Q is quantity of electricity , I is current in amperes = 0.270 A (given)

t is time in seconds (72.0 sec)

As 96500 Coulomb of electricity electrolyzes 1 mole of Ag

then,19.44 C of electricity deposits,

=1/96500 * 19.44

= 0.000201 moles of Ag

Mass of Ag is = number of moles * molar mass

= 0.000201 * 108

= 0.0217 gm

Thus, mass of pure silver deposited on a metal object made into the cathode of the cell is  0.0217 gm.

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Answer:

I believe its C but it could be B

Answer:A

Explanation:  i would say the first one

K is an metal from the first group on the periodic table, while S is a nonmetal from the 16th group.

The K atom can easily lose one electron, so its valence orbital stays with no electrons.

S is similar to O, it only needs two electrons to complete its valence orbital, so it can easily attract two electrons.

Thus, the atom K will form a cation K⁺ while the atom S will form an anion S²⁻.

When putting them together, they will form an ionic compound, and it has to have a neutral charge. Since K is 1+ and S is 2-, we will need 2 K for each S, so the compound formed will be:

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.