Answer:
A
Step-by-step explanation:
Well pretty simple the percent means 0.02/100 move the decimal point to the left by 2 places to get 0.0002 Hope this is helpful!
If profits decrease by 13.8% when the degree of operating
leverage (DOL) is 3.8, then the decrease in sales is:
A) 0.28%
B) 0.52%
C) 3.63%
D) 10%
E) 52.44%
Given that profits decrease by 13.8% when the degree of operating leverage (DOL) is 3.8.
The decrease in sales is: We have to determine the percentage decrease in sales Let the percentage decrease in sales be x.
Degree of Operating Leverage (DOL) = % change in Profit / % change in Sales3.8
= -13.8% / x Thus, we have: x
= -13.8% / 3.8
= -3.63%Therefore, the decrease in sales is 3.63%.Hence, the correct option is C) 3.63%. Percentage decrease in sales = % change in profit / degree of operating leverage
= 13.8 / 3.8
= 3.63% The percentage decrease in sales is 3.63%.
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The velocity of a particle. P. moving along the x-axis is given by the differentiable function v, where (t) is measured in meters per hour and r is measured in hours. V() is a continuous and decreasing function Selected values of v(f) are shown in the table above. Particle P is at the t= 30 at time t = 0. T(hours) 0 2 4 7 10 V(t) (meters/hour) 20.3 14.4 10 7.3 5 (a) Use a Right Riemann sum with the four subintervals indicated by the data in the table to approximate the displacement of the particle between 0 hr to 10 hr. What is the estimated position of particle Pat t=10? Indicate units of measure. (b) Does the approximation in part (a) overestimate or underestimate the displacement? Explain your reasoning (c) A second particle, Q. also moves along the x-axis so that its velocity for O<=T<= 10 is given by VQ(t) = 35✓t cos( 0.06t^2) meters per hour. Find the time interval during which the velocity of particle vo(t) is at least 60 meters per hour. Find the distance traveled by particle Q during the interval when the velocity of particle Q is at least 40 meters per hour. (d) At time t = 0, particle Q is at position x = -90. Using the result from part (a) and the function vo(t) from part (c), approximate the distance between particles P and Q at time t = 10.
The velocity of a particle. P. moving along the x-axis is given by the differentiable function v, where (t) is measured is given by:
A differential function v gives the velocity of a particle P travelling down the x-axis, where v(t) is measured in metres per hour and t is measured in hours. v(t) is a declining function that is continuous. The table below shows several examples of v(t) values.
T [hours] 0 2 4 7 10
v(t) [meters/hour] 20.3 14.4 10 7.3 5
a) We know that the particle's displacement is the area under the curve v(t). We can calculate the particle's displacement by integrating v(t). Because v(t) is a monotonous (constantly declining) differentiable function, it is also Riemann Integrable. There are now five non-uniform subdivisions:
Partition t0 t1 t2 t3 t4
T [hours] 0 2 4 7 10
v(t) [meters/hour] 20.3 14.4 10 7.3 5
Using Right Riemann sum to approximate the displacement of particle between 0 hr and 10 hr is given by:
\(\sum_{n=1}^{4}v(t_n)\Delta t_n=v(t_1)(t_1-t_0)+v(t_2)(t_2-t_1)+v(t_3)(t_3-t_2)+v(t_4)(t_4-t_3) \\=(14.4)(2)+(10)(2)+(7.3)(3)+(5)(3) \\=28.8+20+21.9+15 \\=85.7\)
Therefore, the total displacement between 0 hr and 10 hr is is 85.7 meters.
The estimated position of particle P at time t = 10 hour is 115.7 (= 30 +85.7) meters.
b) Because the function v(t) is decreasing and we are estimating the integral using the Right Riemann sum, the approximation in part(a) underestimates the displacement.
c) A second particle Q also moves along the x-axis so that its velocity is given by :
\(V_Q(t)=35\sqrt{t}\cos(0.06t^2)\text{ meters per hour for }0\leq t\leq 10.\)
Hence, the time interval during which the velocity of a particle is atleast 60 meters per hour is [9.404, 10].
Now, the time periods during which a particle's velocity is at least 40 metres per hour are [1.321,4.006] and [9.218, 10]. The distance travelled by the particle Q when its velocity is at least 40 metres per hour is then calculated. :
\(\int_{1.321}^{4.006}v_Q(t)dt+\int_{9.218}^{10}v_Q(t)dt\\\\=\int_{1.321}^{4.006}35\sqrt{t}\cos(0.06t^2)dt+\int_{9.218}^{10}35\sqrt{t}\cos(0.06t^2)dt\)
d) At time t = 0, particle Q is is at position x = -90.
We know that P is at xp = 115.7 meters.
Now, The position of Q at t = 10 hr is xq:
\(x_q=-90+\int_{0}^{10}v_Q(t)dt=-90+\int_{0}^{10}35\sqrt{t}\cos(0.06t^2)dt\)
And the distance between Q and P is given by :
\(|x_p-x_q|=|115.7-(-90+\int_{0}^{10}35\sqrt{t}\cos(0.06t^2)dt)|\)
\(\\=|205.7-\int_{0}^{10}35\sqrt{t}\cos(0.06t^2)dt|\)
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An elephant at an animal sanctuary weighs 5.5 tons. He receives a daily nutritional supplement. The instructions say to give 1 fluid ounce of supplement for every 250 pounds of body weight.
How many fluid ounces of supplement should the elephant receive?
Step-by-step explanation:
1 louis rose his bicycle 1/2km to school 3/4 km to a ball field and 7/10 km home
Louis total distance of 8/5 km. Louis rose his bicycle a total distance of 8/5 km.
Louis rose his bicycle a total distance of 1/2 km + 3/4 km + 7/10 km.
To find the total distance, we need to find a common denominator for the fractions: 2, 4, and 10.
The least common denominator is 20.
So, 1/2 km can be written as 10/20 km, 3/4 km can be written as 15/20 km, and 7/10 km remains the same.
Adding these fractions together, we have:
10/20 km + 15/20 km + 7/10 km = 32/20 km
Simplifying this fraction, we get:
32/20 km = 8/5 km
Therefore, Louis rose a total distance of 8/5 km.
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Louis rode a total distance of 8/5 km or 1 and 3/5 km
Louis rode his bicycle a total of 1/2 km to school, 3/4 km to a ball field, and 7/10 km back home. To find the total distance Louis traveled, we need to add up these three distances.
First, let's add 1/2 km and 3/4 km. To add fractions with different denominators, we need to find a common denominator. The least common multiple of 2 and 4 is 4.
Converting 1/2 to have a denominator of 4, we get 2/4. Now we can add 2/4 + 3/4, which equals 5/4.
Next, we need to add 5/4 km and 7/10 km. To add fractions with different denominators, we need to find a common denominator. The least common multiple of 4 and 10 is 20.
Converting 5/4 to have a denominator of 20, we get 25/20. Now we can add 25/20 + 7/10, which equals 32/20.
To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 4. Dividing 32/4 and 20/4, we get 8/5.
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A data set contains three unique values. Which of the following must be true?
mean = median
median = midrange
median = midrange
none of these
If a data set contains three unique values, none of the given statements must be true.
The mean is the average of a data set, calculated by summing all values and dividing by the number of values. In a data set with three unique values, the mean will not necessarily be equal to the median, which is the middle value when the data set is arranged in ascending or descending order.
The median is the middle value in a data set when arranged in order. With three unique values, the median will not necessarily be equal to the midrange, which is the average of the minimum and maximum values in the data set.
Therefore, none of the statements "mean = median," "median = midrange," or "median = midrange" must hold true for a data set with three unique values.
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Can someone please explain how I’m supposed to do this?
Answer:
Add Everyone's Goals
and then Divide Steeler's goal with Everyone's Goal.
Then Mutiply with 100 to get percentage.
Ans: 14.6%
Feri invests some money.
The rate of interest for the first year is 2.5%.
At the end of the second year the overall percentage increase of Feri's investment is 6.6%.
Find the rate of interest for the second year.
The rate of interest for 2nd year is 4.1%
How to find the interest rate for the second yearFrom the given parameters;
Rate of interest for 1st year = 2.5
As we know the formula for Simple interest is given by
=> I = (PTR)/100
We will use this formula in the following problem
Let 100 be Feri's investment
At the Rate of interest of 2.5
Interest on 100 = [(100(1)(2.5)]/100 = 2.5
Total amount at end of 1st year = 100 + 2.5 = 102.5
Let x be the rate of interest for 2nd year
At the rate of interest of x
interest on 100 = [(100(1)(x)]/100 = x
Total amount at end of 2st year = 102.5 + x
Given that, at end of the 2 years, the rate of interest becomes 6.6%
Interest on 100 at the rate of 6.6%
=> [(100(1)(6.6)]/100 = 6.6
=> total amount = 100 + 6.6 = 106.6
As we know in both cases, the amount must be equal
=> 102.5 + x = 106.6
=> x = 4.1
Therefore, The rate of interest for 2nd year = 4.1
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what is the appoximate distance between points d and e round your answer to the nearest hundreth
use the multiplier method to £258 by 43%
Answer:
110.94
Step-by-step explanation:
All you have to do is change 43% to .43 then multiply by 258
Find g(x), where g(x) is the translation 3 units left of f(x)=|x|.
Thus, the function g(x) is the absolute value of the quantity (x + 3), which means that it takes any input value of x, adds 3 to it, and then takes the absolute value of the resulting quantity.
What distinguishes a function?If any created vertical line may cross a graph just once, it is said to be a function. If there are any points on the graph where a vertical line can pass through more than once, it is not a function.
To find the function g(x) that is a translation 3 units left of f(x) = |x|, we can start with the function f(x) = |x| and make the following transformation:
Move 3 units to the left: This means we need to subtract 3 from the input of f(x), so we get f(x + 3).
Therefore, the function g(x) can be defined as:
g(x) = f(x + 3) = |x + 3|
Thus, the function g(x) is the absolute value of the quantity (x + 3), which means that it takes any input value of x, adds 3 to it, and then takes the absolute value of the resulting quantity.
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The function g(x), where g(x) is the translation 3 units left of f(x)=|x| is:
g(x) = |x+3|.
What is meant by a function?
The characteristic that every input is associated with exactly one output defines a function as a relationship between a set of inputs and a set of allowable outputs. In mathematics, a function is indicated by a mapping or transformation. Often, these functions are identified by letters like f, g, and h. The collection of all the values that the function may input while it is defined is known as the domain. The entire set of values that the function's output can produce is referred to as the range. The set of values that could be a function's outputs is known as the co-domain.
Given that the function g(x) is the translation of 3 units left of f(x) = |x|.
To the left means that the translation is horizontal translation.
For any horizontal translation of a graph by a value of x units, the new function can be written as:
g(x) = f(x ± k)
Now for a translation to the left side,
g(x) = f(x + k)
This is because more units are added to x values.
So for the given question, we can write that
g(x) = f(x+3) = |x+3|.
Therefore the function g(x), where g(x) is the translation 3 units left of f(x)=|x| is:
g(x) = |x+3|.
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A bridge is 100 metres wide. From the one end of the bridge a person spots a boat with an angle of depression of 35 degrees. From the other end of the bridge another person spots the same boat with an angle of depression of 65 degrees. Find the vertical height of the bridge.
Solution
- The sketch of the scenario is
- We can find the value of x using the sine rule. This is done below:
\(\begin{gathered} \frac{x}{\sin115}=\frac{100}{\sin30} \\ \\ \therefore x=\frac{100\times\sin115}{\sin30} \\ \\ x=181.26156m \end{gathered}\)- After finding the value of x, we can apply SOHCAHTOA, as follows:
\(\begin{gathered} \sin35=\frac{h}{x}=\frac{h}{181.26156} \\ \\ \therefore h=181.26156\times\sin35 \\ \\ h=103.9674m \end{gathered}\)Final answer
The vertical height of the bridge is 103.9674m
(WORTH 20 POINTS) Please help I don't know how to do this
In your own words, what do the terms sales tax and discount mean? Is a 5 percent sales tax a percent of increase or decrease? What about a 15 percent discount?
lol help-
Answer:
Sales tax is an increase in the price of the item while a discount is the decrease of the price. A 5% sales tax is an increase since your paying an extra 5% of the item price. 15% discount is a decrease since your now only paying 85% of the original price. Hope that helps
Answer: In layman's terms, that means if the original price of something you sell was $100, but you offer a 50% discount, then the taxable price is $50. Sale Price = original price – (% of discount * original price)
Sales Tax = Sales Tax rate * Sale Price.
Sales Tax = 0.05 * $17.21 = $0.8605 = $0.86. How do I add 5% to a number?
Divide the number you wish to add 5% to by 100.
Multiply this new number by 5.
Add the product of the multiplication to your original number.
Enjoy working at 105%!
please help and explain what
\(\sf\huge \green{\underbrace{\red{Answer}}}:\)
y = 4
Correct option is (C)
Step-by-step explanation:
-2x - 5y = -2 {taking minus(-) common}
⠀
2x + 5y = 2 [equation 1]
⠀
3x + 6y = -3 {taking 3 common}
⠀
x + 2y = -1 [equation 2]
⠀
{taking 2y of equation 2 on RHS}
⠀
x = -1 - 2y [equation 3]
⠀
{substituting of equation 3 in equation 1}
⠀
2(-1 - 2y) + 5y = 2
- 2 - 4y + 5y = 2
y - 2 = 2
y = 2 + 2
⠀
y = 4
A student has 8 pints of iced tea in a pitcher. The amount of iced tea in the pitcher is a function of x, the amount of iced tea she has poured from the pitcher, y. What is the domain of this function? a \large 0\le x\le8 b \large \left\{1,2,3,4,5,6,7,8\right\} c \large 0\le y\le8 d \large \left\{0,1,2,3,4,5,6,7,8\right\}
Answer: The domain is:
0 pints ≤ x ≤ 8 pints.
Step-by-step explanation:
When we have a function:
y = f(x)
The domain is the set of the possible values of x (the possible inputs).
In this case, the value of x represents the amount of tea that she has poured from the pitcher.
Now, initialy the pitcher has 8 pints, so the smallest possible value of x is 0 pints (when she has not pured anithing) and the maximum value of x is 8 pints (when she has poured all the 8 pints).
So we have the domain:
0 pints ≤ x ≤ 8 pints
Please give a valid complete answer with steps.
Given the information below, what is m ∠CBE?
Answer:
\(42 + 5 x + 7x + 6 = 180 \\ 48 + 12x = 180 \\ 12x = 132 \\ x = 11 \\ 7x + 6 = 77 + 6 = 83\)
Four students are planning a camping trip for Labor Day weekend. They are expecting 8 additional friends to attend. Refer to the information above. The camping trip costs a total of $330.60. Approximately how much is this per person?
What is the measure of ∠ABD?
Answer:
m∠ABD = 114°
Step-by-step explanation:
Given measurements of interior angles are:
m∠D = 2n°
m∠C = 60°
m∠ABD = (4n+6)°
The measurement of exterior angle of a triangle is equal to the sum of two opposite interior angles.
This can be mathematically expressed as:
m∠ABD = m∠C+m∠D
Putting the respective values
\(4n+6 = 2n+60\\4n-2n+6 = 60\\2n+6 = 60\\2n = 60-6\\2n = 54\\\frac{2n}{2} = \frac{54}{2}\\n = 27\)
Putting n=27 in (4n+6)°
\(=4(27) + 6\\= 108+6 = 114\)
Hence,
m∠ABD = 114°
Factor Completely
5x^2 + 15x - 140
•prime
•5(x - 4) (x + 7). •5(x-7)(x + 4)
•5(x - 14) (x + 2)
Answer:
5(x + 7)(x - 4).
Step-by-step explanation:
5x^2 + 15x - 140
= 5(x^2 + 3x - 28)
= 5(x + 7)(x - 4).
The eccentricity of the conic section below is
A. Closer to 0 than 1
B. Closer to 1 then 0
The eccentricity of the conic section below is: A. closer to 0 than 1.
What is a conic section?In Euclidean geometry, a conic section can be defined as a curve that is generated as the intersection of the surface of a right circular cone with a plane.
In Mathematics, there are four (4) types of conic section and these include the following with their eccentricity:
Hyperbola: its eccentricity is greater than one (1).Parabola: its eccentricity is equal to one (1).Ellipse: its eccentricity is 0 < e < 1.Circle: its eccentricity is equal to zero (0).In this context, we can reasonably infer and logically deduce that the eccentricity of the conic section is closer to zero (0) than one (1) because it represents a circle.
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IF YOU ANSWER ALL OF THESE QUESTIONS WILL GIVE BRAINLIEST---- 100 POINTS (PLEASE PUT REAL ANSWERS AND DONT JUST USE THE POINTS)
-5 - 9x - 8x + 2 = ?
6k - k = ?
4 - 5(-8 + 2w) = ?
8n + 2n - 3 = ?
-5(7p - 3) - 2 = ?
The answer to the expressions are
-5 - 9x - 8x + 2 = -3 -17x
6k - k = 5k
4 - 5(-8 + 2w) = 44 - 10w
8n + 2n - 3 = 10n -3
-5(7p - 3) - 2 = -35p + 13
To solve the question, we will simplify all of the expressions.
For the first expression, -5 - 9x - 8x + 2 = ?First, collect like terms
-5 + 2 - 9x - 8x = -3 -17x
∴ -5 - 9x - 8x + 2 = -3 -17x
For the second expression, 6k - k = ?6k - k = 5k
For the third expression, 4 - 5(-8 + 2w) = ?First, clear the brackets
4 - 5(-8 + 2w) = 4 + 40 -10w
= 44 - 10w
∴ 4 - 5(-8 + 2w) = 44 - 10w
For the fourth expression, 8n + 2n - 3 = ?8n + 2n - 3 = 10n -3
∴ 8n + 2n - 3 = 10n -3
For the fifth expression, -5(7p - 3) - 2 = ?First, clear the bracket
-5(7p - 3) - 2 = -35p + 15 -2
= -35p + 13
∴ -5(7p - 3) - 2 = -35p + 13
Hence, the answer to the expressions are
-5 - 9x - 8x + 2 = -3 -17x
6k - k = 5k
4 - 5(-8 + 2w) = 44 - 10w
8n + 2n - 3 = 10n -3
-5(7p - 3) - 2 = -35p + 13
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let y be an independent standard normal random variable. use the moment gener- ating function of y to find e[y 3] and e[y 4].
This means that the expected value of y cubed is 1, while the expected value of y to the fourth power is 0.
\(E[y^3] = 1\\\E[y^4] = 0\)
The moment generating function (MGF) of a standard normal random variable y is given by \(M(t) = e^{\frac{t^2}{2}}\). To find \(E[y^3]\), we can differentiate the MGF three times and evaluate it at t = 0. Similarly, to find \(E[y^4]\), we differentiate the MGF four times and evaluate it at t = 0.
Step-by-step calculation for\(E[y^3]\):
1. Find the third derivative of the MGF: \(M'''(t) = (t^2 + 1)e^{\frac{t^2}{2}}\)
2. Evaluate the third derivative at t = 0: \(M'''(0) = (0^2 + 1)e^{(0^2/2)} = 1\)
3. E[y^3] is the third moment about the mean, so it equals M'''(0):
\(E[y^3] = M'''(0)\\E[y^3] = 1\)
Step-by-step calculation for \(E[y^4]\):
1. Find the fourth derivative of the MGF: \(M''''(t) = (t^3 + 3t)e^(t^2/2)\)
2. Evaluate the fourth derivative at t = 0:
\(M''''(0) = (0^3 + 3(0))e^{\frac{0^2}{2}} \\\)
\(M''''(0) =0\)
3. E[y^4] is the fourth moment about the mean, so it equals M''''(0):
\(E[y^4] = M''''(0) \\E[y^4] = 0.\)
In summary:
\(E[y^3]\) = 1
\(E[y^4]\) = 0
This means that the expected value of y cubed is 1, while the expected value of y to the fourth power is 0.
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EASY QUESTION!!Example 3:
A soccer ball will not move until a player kicks it.
Group of answer choices
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
Give evidence or explain your reasoning for your answer to example #3:
Answer:
this is Newton's first law
Step-by-step explanation:
the soccer ball when kicked keep going forward until friction a person or another object like a wall stops it when the soccer ball is resting non-moving on the ground or stay like that until someone kicks it or another Force acts upon it
Convert the decimal number 431 to binary in two ways: (a) convert directly to binary; (b) convert first to hexadecimal and then from hexadecimal to binary. which method is faster?
The conversion of decimal number directly to binary number will be faster.
What is a conversion of the number system?The number conversion deals with the operation to change the base of the number.
Binary number - It contains only 2 numbers that are 1 and 0.
Decimal number - It contains 10 numbers that are from 0 to 9.
Hexadecimal number - It contains 16 numbers that are from 0 to F.
Convert the decimal number 431 to binary will be
431 / 2 = 215 with 1 remainder
215 / 2 = 107 with 1 remainder
107 / 2 = 53 with 1 remainder
53 / 2 = 26 with 1 remainder
26 / 2 = 13 with 0 remainder
13 / 2 = 6 with 1 remainder
6 / 2 = 3 with 0 remainder
3 / 2 = 1 with 1 remainder
1 / 2 = 0 with 1 remainder
The decimal number 431 to binary number will be 110101111.
Convert first to hexadecimal and then from hexadecimal to binary. Then we have
(431)₁₀ = (1AF)₁₆ = (110101111)₂
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Students arrive at the Administrative Services Office at an average of one every 12 minutes, and their requests take on average 10 minutes to be processed. The service counter is staffed by only one clerk, Judy Gumshoes, who works eight hours per day. Assume Poisson arrivals and exponential service times. Required: (a) What percentage of time is Judy idle? (Round your answer to 2 decimal places. Omit the "%" sign in your response.) (b) How much time, on average, does a student spend waiting in line? (Round your answer to the nearest whole number.) (c) How long is the (waiting) line on average? (Round your answer to 2 decimal places.) (d) What is the probability that an arriving student (just before entering the Administrative Services Office) will find at least one other student waiting in line? (Round your answer to 3 decimal places.)
The probability that an arriving student will find at least one other student waiting in line is approximately 0.167.
To solve this problem, we'll use the M/M/1 queueing model with Poisson arrivals and exponential service times. Let's calculate the required values: (a) Percentage of time Judy is idle: The utilization of the system (ρ) is the ratio of the average service time to the average interarrival time. In this case, the average service time is 10 minutes, and the average interarrival time is 12 minutes. Utilization (ρ) = Average service time / Average interarrival time = 10 / 12 = 5/6 ≈ 0.8333
The percentage of time Judy is idle is given by (1 - ρ) multiplied by 100: Idle percentage = (1 - 0.8333) * 100 ≈ 16.67%. Therefore, Judy is idle approximately 16.67% of the time. (b) Average waiting time for a student:
The average waiting time in a queue (Wq) can be calculated using Little's Law: Wq = Lq / λ, where Lq is the average number of customers in the queue and λ is the arrival rate. In this case, λ (arrival rate) = 1 customer per 12 minutes, and Lq can be calculated using the queuing formula: Lq = ρ^2 / (1 - ρ). Plugging in the values: Lq = (5/6)^2 / (1 - 5/6) = 25/6 ≈ 4.17 customers Wq = Lq / λ = 4.17 / (1/12) = 50 minutes. Therefore, on average, a student spends approximately 50 minutes waiting in line.
(c) Average length of the line: The average number of customers in the system (L) can be calculated using Little's Law: L = λ * W, where W is the average time a customer spends in the system. In this case, λ (arrival rate) = 1 customer per 12 minutes, and W can be calculated as W = Wq + 1/μ, where μ is the service rate (1/10 customers per minute). Plugging in the values: W = 50 + 1/ (1/10) = 50 + 10 = 60 minutes. L = λ * W = (1/12) * 60 = 5 customers. Therefore, on average, the line consists of approximately 5 customers.
(d) Probability of finding at least one student waiting in line: The probability that an arriving student finds at least one other student waiting in line is equal to the probability that the system is not empty. The probability that the system is not empty (P0) can be calculated using the formula: P0 = 1 - ρ, where ρ is the utilization. Plugging in the values:
P0 = 1 - 0.8333 ≈ 0.1667. Therefore, the probability that an arriving student will find at least one other student waiting in line is approximately 0.167.
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Storytelling (x+1)^2020 how many terms
Step-by-step explanation:
there are 2021 terms
yep
the above image says that the number of terms is always n+1 when it involves(a+b)^n
Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation.
(9, 12); y=13x−4
Answer:
\(\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}\)
Step-by-step explanation:
Equation of line in slope-intercept form: y = mx + bHere m is the slope and b is the y-intercept.
y = 13x - 4
m₁ = 13
Product of slope of the Perpendicular line m * m₁ = -1
\(\sf m = \dfrac{-1}{m_1}\\\\m = \dfrac{-1}{13}\)
Equation of the line:
\(\sf y = \dfrac{-1}{13}x+b\)
The point (9,12) passes through the line. Substitute the coordinates in the above equation and find the value of 'b'.
\(\sf 12 = \dfrac{-1}{13}*9+b\\\\\)
\(\sf 12 + \dfrac{9}{13}=b\\\\ \dfrac{156}{13}+ \dfrac{9}{13}=b\\\\\boxed{b= \dfrac{165}{13}}\)
Equation of line:
\(\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}\)
Point B' is the image of point B after a reflection in a line. Write the equation of the line.
B(2,-4), B'(6,-4)
Thanks! <3
The slope and intercept of the line are -2 and 0. The equation of the line is y = -2x
Equation of LineTo find the equation of line, we have to find the slope of the equation and its y-intercept.
The slope of a line can be calculated as
\(m = \frac{y_2 - y_1}{x_2 - x_1} \\m = \frac{-4 - (-4)}{6 - 2}\\m = \frac{-8}{4} \\m = -2\)
The slope of the line is equal to -2.
Lets find the intercept of the line;
The line of an equation is given as
\(y = mx + c\)
We can pick point A and substitute its values to find c
\(y = mx + c\\- 4 = -2(2) + c\\-4 = -4 + c\\c = -4 + 4\\c = 0\)
The equation of the line is y = -2x
Learn more on equation of a line here;
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Help please thanks don’t know how to do this
Answer:
a = 11.71 ; b = 15.56
Step-by-step explanation:
For this problem, we need two things. The law of sines, and the sum of the interior angles of a triangle.
The law of sines is simply:
sin(A)/a = sin(B)/b = sin(C)/c
And the sum of interior angles of a triangle is 180.
45 + 110 + <C = 180
<C = 25
We can find the sides by simply applying the law of sines.
length b
7/sin(25) = b/sin(110)
b = 7sin(110)/sin(25)
b = 15.56
length a
7/sin(25) = a/sin(45)
a = 7sin(45)/sin(25)
a = 11.71
5/8 multiplied by 3/4 + 1/2
Answer:
31/32 or 0.96875
Step-by-step explanation:
first you muliply 5/8 by 3/4 then the answer add it to 1/2
please help me find x if you have done geometry or are in geometry
Answer:
x = 5
Step-by-step explanation:
By the property of intersecting chords inside a circle:
\((x - 2)(x + 7) = 4(2x - 1) \\ \\ {x}^{2} + 7x - 2x - 14 = 8x - 4 \\ \\ {x}^{2} + 5x - 14 - 8x + 4 = 0 \\ \\ {x}^{2} - 3x - 10 = 0 \\ \\ {x}^{2} - 5x + 2x - 10 = 0 \\ \\ x(x - 5) + 2(x - 5) = 0 \\ \\ (x + 2)(x - 5) = 0 \\ \\ x + 2 = 0 \: \: or \: \: x - 5 = 0 \\ \\ x = - 2 \: \: or \: \: x = 5 \\ \\ \because \: length \: can \: not \: be \: - ve \\ \\ \therefore \: x \neq - 2 \\ \\ \implies \: x = 5\)