Answer:
So -1-9= -10
And if x =4 then 2(4)-4y=20
Y= -3
Step-by-step explanation:
2(4)-4y=20
8-4y=20
-4y=12
y=-3
Answer:
-1 - 9 = -10 &
y = -3
Step-by-step explanation:
2x - 4y = 20
2(4) - 4y = 20
8 - 4y = 20
-4y = 12
y = -3
good luck, i hope this helps :)
Write and solve a proposition that the teacher can use to estimate how many students in the whole school would choose the aquarium.
Answer:
Let's assume that the total number of students in the school is "x". We can create a proportion to estimate how many students would choose the aquarium based on the given information:
Number of students who chose aquarium / Total number of students in the school = Percentage of students who chose aquarium / 100
We can plug in the values we know:
80 / x = p / 100
where "p" is the percentage of students who would choose the aquarium if the entire school were surveyed.
We can solve for "x" by cross-multiplying and simplifying:
8000 = px
x = 8000 / p
Now, we need to estimate the value of "p". We can do this by finding the average percentage of students who chose the aquarium, science center, planetarium, and farm:
(80 + 60 + 30 + 40) / x = (210 / x) = Average percentage of students who chose an attraction
This tells us that, on average, 210 out of every "x" students would choose one of the attractions. We can estimate that a similar percentage of the entire school would choose the aquarium:
p / 100 = 80 / 210
p = 38.1
So, we can estimate that approximately 38.1% of the students in the whole school would choose the aquarium. To find the estimated number of students who would choose the aquarium, we can plug in this value for "p" in our original proportion:
80 / x = 38.1 / 100
Cross-multiplying and solving for "x", we get:
x = 209.71
Rounding to the nearest whole number, we can estimate that approximately 210 students in the whole school would choose the aquarium.
Step-by-step explanation:
Answer:
The teacher surveyed a total of:
80 + 60 + 30 + 40 = 210 students.
If we assume that the sample of 210 students surveyed is representative of the entire population of 1000 students at Lake Middle School, we can use the relative frequency of students choosing the aquarium in the sample to estimate the number of students in the whole school who would choose the aquarium.
The relative frequency of students choosing the aquarium in the sample is:
80/210 = 0.38
This means that approximately 38% of the students in the sample chose the aquarium.
To estimate the number of students in the whole school who would choose the aquarium, we can multiply the relative frequency by the total number of students at the school:
0.38 x 1000 = 380
Therefore, the teacher can estimate that approximately 380 students out of 1000 at Lake Middle School would choose the aquarium for a field trip.
M = I1+I₂ 31 +32 2 Now let's substitute in our given values. (-2 , 2) = ((-5 Find 2 and y2 We will now set up two equations to solve for our two unknowns of x2 and y₂. (-5 X2 (-5+₂) -5+22), (7+)) 2 - +₂)/2 = We will first want to multiply by 2 on both sides and will get −5+₂= -4 Adding 5 to both sides we get = 7 This is the coordinate of point B. Now we will set up the equation to solve for y2 +y2)/2 =
The coordinates of point B are (-3, 17).
The given equation is M = I₁ + I₂ = 31 + 32.
Now let's substitute in our given values:
(-2, 2) = ((-5 + x₂) / 2, (-5 + 2 + y₂) / 2)
We will now set up two equations to solve for our two unknowns, x₂ and y₂:
Equation 1: (-5 + x₂) / 2 = -4
Multiply both sides by 2:
-5 + x₂ = -8
Add 5 to both sides:
x₂ = -3
This gives us the x-coordinate of point B.
Equation 2: (-5 + 2 + y₂) / 2 = 7
Simplify:
(-3 + y₂) / 2 = 7
Multiply both sides by 2:
-3 + y₂ = 14
Add 3 to both sides:
y₂ = 17
This gives us the y-coordinate of point B.
Therefore, the coordinates of point B are (-3, 17).
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2. Abigail and Curtis Siebert: $270,000 mortgage at 7% for 20 years.
M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1). Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.
Abigail and Curtis Siebert have a $270,000 mortgage at an interest rate of 7% for a term of 20 years.
To calculate the monthly mortgage payment, we can use the formula for an amortizing mortgage:
M = P * (r * (1 + r)^n) / ((1 + r)^n - 1),
where M is the monthly mortgage payment, P is the principal amount (loan amount), r is the monthly interest rate, and n is the total number of monthly payments.
First, we need to convert the annual interest rate to a monthly interest rate. Since there are 12 months in a year, the monthly interest rate is 7% divided by 12, which is approximately 0.5833%.
The total number of monthly payments is the term of the mortgage multiplied by 12. In this case, it's 20 years * 12 months, which equals 240 months.
Now, we can substitute the values into the formula:
M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1).
Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.
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When do you say that a given quadrilateral is a parallelogram?
Answer:
If in a quadrilateral, each pair of opposite angles is equal, then it is a parallelogram. Given : ABCD is a quadrilateral in which ∠A = ∠C and ∠B = ∠D. We know that the sum of the angles of a quadrilateral is 360o.
Step-by-step explanation:
hope that helps
A new LED TV currently cost 1,300 when paid in full. There is also a payment plan available where the customer must pay a monthly payment of $72 for 2 years. How much more will a customer who pays in monthly installments end up paying for the LED TV than a customer who pays the 1,300 in full?
Answer:
$428
Step-by-step explanation:
you can do 72*24= the 2 year period and then you get 1728
you then do 1728-1300 and you will get $428 more
(Order statistics and independence) Let X be the minimum and Y the maximum of two independent, nonnegative random variables S and T with common continuous density f. Let Z denote the indicator function of the event (S > 2T). Vhat is the distribution of Z? b) Are X and Z independent? Are Y and Z independent? Are (X, Y) and Z independent? c) Is X independent of Y?
a. P(Z = 1) = ∫G(s)f(s)ds is the distribution of Z.
b. X and Z are independent.
c. X and Y are not independent.
a) We have Z = I(S > 2T), where I is the indicator function. Then,
P(Z = 1) = P(S > 2T) = ∫∫(s > 2t) f(s) f(t) ds dt
Using the fact that S and T are independent, we get
∫∫(s > 2t) f(s) f(t) ds dt = ∫∫f(s)ds ∫∫f(t)I(s > 2t)dt ds
Letting G(s) = ∫f(t)I(s > 2t)dt, we get
P(Z = 1) = ∫G(s)f(s)ds
b) We have X = min(S,T) and Z = I(S > 2T). To check whether X and Z are independent, we compute their joint distribution:
P(X > x, Z = 1) = P(S > 2T, S > x, T > x) = ∫∫(s > 2t) f(s) f(t) ds dt ∫\(x^\infty\)f(u)du
= ∫\(x^\infty\)f(u)du ∫\((u/2)^x\) f(t) dt ∫\(t^\infty\) f(s) ds
= 1/2 ∫\(x^\infty\)f(u) ∫\(t^\infty\) f(s) ds dt
= 1/2 ∫\(x^\infty\)f(u) G(t) dt
= 1/2 ∫\(x^\infty\)f(u) ∫f(t)I(u > 2t)dt du
= ∫\(x/2^\infty\) f(u) ∫f(t)I(u > 2t)dt du
= P(X > x)P(Z = 1), using the fact that S and T are independent.
Therefore, X and Z are independent. Similarly, we can show that Y and Z are independent and (X, Y) and Z are independent.
c) X and Y are not independent, since the event {X > x} implies that both S and T are greater than x, which means that the event {Y > y} is more likely to occur for larger values of y.
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10. Two stores are having deals on video games.
Store A: 5 video games for $8.95
0:23
Store B: 7 video games for $10.50. Find the price per video game for store A. Round to the nearest cent. SHOW YOUR WORK.
The calculated price per video game for store A is $1.79 per game
How to find the price per video game for store A.From the question, we have the following parameters that can be used in our computation:
Store A: 5 video games for $8.95Store B: 7 video games for $10.50The price per video game for store A is calculated as
Price per video game = Total price/Number of games
using the above as a guide, we have the following:
Price per video game = 8.95/5
Evaluate the quotient
So, we have
Price per video game = 1.79
Hence, the price per video game for store A is $1.79 per game
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What’s the length of kL?
Applying the intersecting secants theorem, the length of segment KL is approximately, 45.8.
What is the Intersecting Secants Theorem?According to the intersecting secants theorem, if two lines from a point outside a circle intersect the circle, then the product of the length of one line segment and its portion outside the circle is equal to the product of the length of the other line segment and its portion outside the circle.
Using the theorem, we have:
MN * MO = ML * MK
Substitute:
21 * 48 = 22 * KL
1,008 = 22KL
1,008/22 = KL
KL = 45.8 (nearest tenth)
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What is the solution to the given system of equations
Y= 4x-28
Y= 1.5x - 18
-12,4
4,-12
7,0
7.5,2
Answer:
Point Form:
(4,−12)(4,-12)
Equation Form:
x=4,y=−12
Cuanto es El doble de 0.5
Answer:
Respuesta certificada por un experto
El doble de 0.25 es 0.50. El doble de 0.50 es 1.00.
Step-by-step explanation:
[ ] ÷258=45 what is the missing value
We will investigate the missing value under division operation.
The missing value will be represented as a variable ( x ). We can then write down the division of two numbers as follows:
\(\frac{x}{258}\text{ = 45}\)We are to solve the above equation by manipulating the entire equation. We will try to isolate the vairable ( x ) on the left hand side of the " = " sign! To do that we will multiply the entire equation by the denominator value as follows:
\(258\cdot\frac{x}{258}\text{ = 45}\cdot258\)Simplify the left hand side of the " = " sign as follows:
\(\begin{gathered} x\text{ = 45}\cdot258 \\ x\text{ = 11,610} \end{gathered}\)Therefore, the solution to the missing value is:
\(11,610\ldots\text{ Answer}\)A survey was conducted to compare the mean cost of a meal at fast food restaurants in two different cities.
City n x s
A 26 $4.05 $0.55
B 32 $5.15 $0.85
Assume that the population variances of both groups are different. Test if there is sufficient evidence that the mean costs of a meal at fast food restaurants in two different cities are different. Conduct the hypothesis testing (optional) in paper.
Answer:
We reject the Null and conclude that the mean costs of a meal at fast food restaurants in two different cities are different.
Step-by-step explanation:
Given :
City n x s
A 26 $4.05 $0.55
B 32 $5.15 $0.85
H0 : μ1 - μ2 = 0
H0 : μ1 - μ2 ≠ 0
n1 = 26 ; x1 = 4.05 ; s1 = 0.55
n2 = 32 ; x2 = 5.15 ; s2 = 0.85
Tstatistic :
(x1 - x2) / √(s1²/n1 + s2²/n2)
(4.05 - 5.15) / √(0.55²/26 + 0.85²/32)
-1.1 / 0.1849668
= - 5.947
Using the smaller n;
df = n - 1 ; 26 - 1 = 25
Pvalue = (-5.947, 24)
Pvalue = 0.000001
Since Pvalue < α ; We reject the Null and conclude that the mean costs of a meal at fast food restaurants in two different cities are different.
I need help as soon as posible pls
Given the number pattern:
20; 18: 14; 8;
a) Determine the nth term of this number pattern.
b) Determine the value of T12 in this number pattern.
c) Which term in this number pattern will have a value of - 36?
A quadratic number pattern has a second term equal to 1, a third term equal to -6 and a fifth term equal to - 14.
a) Calculate the second difference of this quadratic number pattern.
b) Hence, or otherwise, calculate the first term of this number pattern.
Answer:
\(\textsf{a)} \quad T_n=-n^2+n+20\)
\(\textsf{b)} \quad T_{12}=-112\)
\(\textsf{c)} \quad \sf 8th\;term\)
a) Second difference is 2.
b) First term is 10.
Step-by-step explanation:
The given number pattern is:
20, 18, 14, 8, ...To determine the type of sequence, begin by calculating the first differences between consecutive terms:
\(20 \underset{-2}{\longrightarrow} 18 \underset{-4}{\longrightarrow} 14 \underset{-6}{\longrightarrow}8\)
As the first differences are not the same, we need to calculate the second differences (the differences between the first differences):
\(-2 \underset{-2}{\longrightarrow} -4 \underset{-2}{\longrightarrow} -6\)
As the second differences are the same, the sequence is quadratic and will contain an n² term.
The coefficient of the n² term is half of the second difference.
As the second difference is -2, the coefficient of the n² term is -1.
Now we need to compare -n² with the given sequence (where n is the position of the term in the sequence).
\(\begin{array}{|c|c|c|c|c|}\cline{1-5}n&1&2&3&4\\\cline{1-5}-n^2&-1&-4&-9&-16\\\cline{1-5}\sf operation&+21&+22&+23&+24\\\cline{1-5}\sf sequence&20&18&14&8\\\cline{1-5}\end{array}\)
We can see that the algebraic operation that takes -n² to the terms of the sequence is to add (n + 20).
\(\begin{array}{|c|c|c|c|c|}\cline{1-5}n&1&2&3&4\\\cline{1-5}-n^2&-1&-4&-9&-16\\\cline{1-5}+n&0&-2&-6&-12\\\cline{1-5}+20&20&18&14&8\\\cline{1-5}\sf sequence&20&18&14&8\\\cline{1-5}\end{array}\)
Therefore, the expression to find the the nth term of the given quadratic sequence is:
\(\boxed{T_n=-n^2+n+20}\)
To find the value of T₁₂, substitute n = 12 into the nth term equation:
\(\begin{aligned}T_{12}&=-(12)^2+(12)+20\\&=-144+12+20\\&=-132+20\\&=-112\end{aligned}\)
Therefore, the 12th term of the number pattern is -112.
To find the position of the term that has a value of -36, substitute Tₙ = -36 into the nth term equation and solve for n:
\(\begin{aligned}T_n&=-36\\-n^2+n+20&=-36\\-n^2+n+56&=0\\n^2-n-56&=0\\n^2-8n+7n-56&=0\\n(n-8)+7(n-8)&=0\\(n+7)(n-8)&=0\\\\\implies n&=-7\\\implies n&=8\end{aligned}\)
As the position of the term cannot be negative, the term that has a value of -36 is the 8th term.
\(\hrulefill\)
Given terms of a quadratic number pattern:
T₂ = 1T₃ = -6T₅ = -14We know the first differences are negative, since the difference between the second and third terms is -7. Label the unknown differences as -a, -b and -c:
\(T_1 \underset{-a}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-b}{\longrightarrow}T_4 \underset{-c}{\longrightarrow} -14\)
From this we can create three equations:
\(T_1-a=1\)
\(-6-b=T_4\)
\(T_4-c=-14\)
The second differences are the same in a quadratic sequence. Let the second difference be x. (As we don't know the sign of the second difference, keep it as positive for now).
\(-a \underset{+x}{\longrightarrow} -7\underset{+x}{\longrightarrow} -b \underset{+x}{\longrightarrow}-c\)
From this we can create three equations:
\(-a+x=-7\)
\(-7+x=-b\)
\(-b+x=-c\)
Substitute the equation for -b into the equation for -c to create an equation for -c in terms of x:
\(-c=(-7+x)+x\)
\(-c=2x-7\)
Substitute the equations for -b and -c (in terms of x) into the second two equations created from the first differences to create two equations for T₄ in terms of x:
\(\begin{aligned}-6-b&=T_4\\-6-7+x&=T_4\\T_4&=x-13\end{aligned}\)
\(\begin{aligned}T_4-c&=-14\\T_4+2x-7&=-14\\T_4&=-2x-7\\\end{aligned}\)
Solve for x by equating the two equations for T₄:
\(\begin{aligned}T_4&=T_4\\x-13&=-2x-7\\3x&=6\\x&=2\end{aligned}\)
Therefore, the second difference is 2.
Substitute the found value of x into the equations for -a, -b and -c to find the first differences:
\(-a+2=-7 \implies -a=-9\)
\(-7+2=-b \implies -b=-5\)
\(-5+2=-c \implies -c=-3\)
Therefore, the first differences are:
\(T_1 \underset{-9}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-5}{\longrightarrow}T_4 \underset{-3}{\longrightarrow} -14\)
Finally, calculate the first term:
\(\begin{aligned}T_1-9&=1\\T_1&=1+9\\T_1&=10\end{aligned}\)
Therefore, the first term in the number pattern is 10.
\(10 \underset{-9}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-5}{\longrightarrow}-11 \underset{-3}{\longrightarrow} -14\)
Note: The equation for the nth term is:
\(\boxed{T_n=n^2-12n+21}\)
the difference between twice a number and a number that is 5 more than it is 3. What is the number?
Answer:
4?
Step-by-step explanation:
Answer:
2n-(n+5)=3
Step-by-step explanation:
Factor completely.
x3 + x2 – 25x – 25
what’s the answer
Answer:
(x+1)(x+5)(x-5)
Step-by-step explanation:
Unions, intersections, and complements involving 2 sets
Sets B and C are subsets of the universal set U.
These sets are defined as follows.
U={f, k, m, s, x, y, z)
B={k, s, y}'
C={s,z}
(a) B'UC' = 1
(b) B'nc =
Intersection of B'∩C = {k, y}
To find the intersection of B' and C, we need to first find the complement of set B (B') and then find the intersection between B' and C.
1. Complement of set B (B'):
The complement of set B (B') consists of all elements in the universal set U that are not in set B. From the given information, set B is defined as {k, s, y}', which means it contains all elements in U except for k, s, and y. Therefore, the complement of set B is {f, m, x, z}.
2. Intersection between B' and C:
Now, we need to find the intersection between B' (complement of B) and set C. From the given information, set C is defined as {s, z}. To find the intersection, we need to identify the common elements between B' and C.
The elements present in both B' and C are k and y. Therefore, the intersection of B' and C is {k, y}.
So, the answer to (b) is B'∩C = {k, y}.
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the length of the arc intercepted by a central angle of 3 radians in a circle of radius 76 is . the length of the arc intercepted by a central angle of in a circle of radius 15 is
The length of the arc intercepted by a central angle of 3 radians in a circle of radius 76 is 228 and the length of the arc intercepted by a central angle of 2 radians in a circle of radius 15 is 30.
Explain:
The following formula determines the length of an arc that a circle's central angle intercepts:
Arc length is equal to (central angle / 2) 2r r r
where r denotes the circle's radius. We can determine the length of the two arcs using the following formula:
For the first circle, with a radius of 76 and a center angle of 3 radians:
Arc length = 3 x 76 = 228
Therefore, in a circle with a radius of 76, the length of the arc that is intercepted by a central angle of 3 radians is 228.
For the second circle, whose radius is 15, and whose center angle is 2 radians:
Arc length = 2 x 15 = 30
As a result, the length of the arc in a circle with a radius of 15 is 30 when it is intercepted by a central angle of 2 radians.
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A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 19 phones from the manufacturer had a mean range of 1160 feet with a standard deviation of 32 feet. A sample of 11 similar phones from its competitor had a mean range of 1130 feet with a standard deviation of 30 feet.
Required:
Do the results support the manufacturer's claim?
Complete question is;
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 19 phones from the manufacturer had a mean range of 1160 feet with a standard deviation of 32 feet. A sample of 11 similar phones from its competitor had a mean range of 1130 feet with a standard deviation of 30 feet. Required:
Do the results support the manufacturer's claim?
Let μ1 be the true mean range of the manufacturer's cordless telephone and μ2 be the true mean range of the competitor's cordless telephone. Use a significance level of α = 0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed
Answer:
We will fail to reject the null hypothesis as there is no sufficient evidence to support the manufacturers claim.
Step-by-step explanation:
For the first sample, we have;
Mean; x'1 = 1160 ft
standard deviation; σ1 = 32 feet
Sample size; n1 = 19
For the second sample, we have;
Mean; x'2 = 1130 ft
Standard deviation; σ2 = 30 ft
Sample size; n2 = 11
The hypotheses are;
Null Hypothesis; H0; μ1 = μ2
Alternative hypothesis; Ha; μ1 > μ2
The test statistic formula for this is;
z = (x'1 - x'2)/√[(σ1)²/n1) + (σ2)²/n2)]
Plugging in the relevant values, we have;
z = (1160 - 1130)/√[(32)²/19) + (30)²/11)]
z = 2.58
From the z-table attached, we have a p-value = 0.99506
This p-value is more than the significance value of 0.01,thus,we will fail to reject the null hypothesis as there is no sufficient evidence to support the manufacturers claim.
URGENT: Given the following information about an ellipse, write its equation: Foci: (3, 1), (3, 5) Endpoints of minor axis: (7, −2), (–1, −2)
The equation of the ellipse is \((x - 3)^2 / 16 + (y - 3)^2 / 64 = 1.\)
To determine the equation of the ellipse, we need to find its major and minor axes, as well as the distance from each focus to the center.
Given that the foci of the ellipse are located at (3, 1) and (3, 5), we can determine that the center of the ellipse is at the midpoint between these two foci, which is (3, 3).
The endpoints of the minor axis are (7, -2) and (-1, -2), which tells us that the length of the minor axis is 7 - (-1) = 8 units.
Now, let's calculate the distance from the center to one of the foci. Using the distance formula, we have:
sqrt((3 - 3)^2 + (3 - 1)^2) = sqrt(0 + 4) = 2.
Since the foci are vertically aligned, the major axis is vertical. Therefore, the length of the major axis is twice the distance from the center to one of the foci, which gives us 2 \(\times\) 2 = 4 units.
Using the standard form of the equation for an ellipse centered at (h, k), with a horizontal major axis of length 2a and a vertical minor axis of length 2b, the equation is:
\((x - 3)^2 / 4^2 + (y - 3)^2 / 8^2 = 1.\)
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1. Evaluate 7m + 3mn; when m=8 and n=14?
2. Simplify: 675 ÷ (6+9 ÷ 3)
3. (3x - 2)(4x +1)
Answer:
1. 392
2. 75
3. \(12x^{2} - 5x -2\)
Step-by-step explanation:
1. 7×8 + 3×8×14 = 56 + 336 = 392
2. 675 ÷ (6 + 3) = 675 ÷ 9 = 75
3. \(12\)\(x^{2}\) + \(3x -\) \(8x - 2\) = \(12x^{2} -5x-2\)
Find the unknown coordinate so the line through the
points has the given slope
Answer:
#1 (0,-4)
#2 (5,0)
#3 (3,1)
Step-by-step explanation:
#1. (-3, 2) (0, y) slope = -2
slope = rise/run therefore slope = -2/1 or down 2 and over 1
so from -3 to 0 you are going over 3 units (or 3 times) Therefore to find y at x=0, you have to move three steps, or 3 times -2 = -6 so 2-6 = -4
so y intercept (b) = -4 0r (0,-4)
#2 (-7,-4) (x,0) slope (m) = 1/3 -7+12=5 x=5
#3 (4,-3) (x, 1) slope (m) = -4 (4/-1) Moving one unit in slope means
-3=4=1 for Y and 4-1=3 for X therefore the point is (3, 1)
Please look at the picture
Answer:
1.5
Step-by-step explanation:
Vertical angles are congruent so:
7x=8x-12
Subtract 7x from both sides:
0=8x-12
Add 12 to both sides:
8x=12
Divide both sides by 8:
x=1.5 or
x= 3/2
A house is infested with mice and to combat this the householder acquired four cats cyd, Greg, Ken, and Rom, The householder observes that only half of the creatures caught are mice. A fifth are voles and the rest are birds. 20% of the catches are made by Cyd, 45% by Greg, 10% by Ken and 25% by rom. a) What is the probability of a randomly selected catch being a mouse caught by Cyd? b) Bird not caught by Cyd? c) Greg's catches are equally likely to be a mouse, a bird or a vole. What is the probability of a randomly selected d) The probability of a randomly selected catch being a mouse caught by Ken is 0.05 . What is the probablity that a catch being a mouse caught by Greg? e) Given that the probability of a randomly selected catch is a mouse caught by Rom is 0.2 verify that the catch made by Ken is a mouse? probability of a randomly selected catch being a mouse is 0.5 . f) What is the probability that a catch which is a mouse was made by Cyd?
Note that the probabilities are given below.
a) the probability of a randomly selected catch being a mouse caught by Cyd
p(Catching a mount) x p(Cyd made the catch)
= 0.5x .2
= 0.1
b) the probability of a bird not caught by Cyd is 0.5 x 0.8 = 0.4.
Thus
P(that a catch is a bird) x p(the Cyd didn't make the catch)
= 0.3 x 0.8
=0.24
c) The probability of a randomly selected catch being caught by Greg is 0.45
To calculate, we say
(0.5 x0.45) + (0.3 x 0.45) + (0.2 x .45)
= 0.45.
d)
P (mouse caught by Greg) = (0.45 x 0.5) / 1
= 0.225.
e) P(catch is a mouse caught by Ken and catch is a mouse)
= P(catch is a mouse | catch is made by Ken) x P(catch is made by Ken)
= 0.05 x 0.1
= 0.005
f)
P (catch made by Cyd | catch is a mouse)
= 0.1 x 0.2 / 0.5
= 0.04
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What happens to the graph of f(x) = 3(.96)when a constant is added
to it and it becomes f(x) = 3(.96)X + 12?
Answer:
The graph of the function gets vertically shifted upwards by 12 units.
Step-by-step explanation:
The diagonals of a rhombus are 4 inches and 18 inches. How long are the sides?
For each function, do the signs of the first and second derivatives of the function appear to be positive or negative over the given interval? (Answer positive or negative.)
x 11.1 1.2 1.3 1.4 1.5
f(x) 7.1 6.1 5.0 3.8 2.5 1.1
(a) (1 point) f'(x) appears to be
(b) (1 point) f"(x) appears to be
The first and second derivatives of the function are both negative over the interval [1.1, 1.5].
To find the first derivative, we need to calculate the slope of the function at each point. We can do this by taking the difference between two consecutive y-values and dividing it by the difference between the corresponding x-values:
f'(1.2) = (6.1 - 7.1)/(1.2 - 1.1) = -1
f'(1.3) = (5.0 - 6.1)/(1.3 - 1.2) = -1.1
f'(1.4) = (3.8 - 5.0)/(1.4 - 1.3) = -1.2
f'(1.5) = (2.5 - 3.8)/(1.5 - 1.4) = -1.3
From these calculations, we can see that the first derivative of the function appears to be negative over the entire interval.
To find the second derivative, we need to calculate the rate of change of the first derivative. We can do this by taking the difference between two consecutive first derivative values and dividing it by the difference between the corresponding x-values:
f''(1.3) = (-1.1 - (-1))/ (1.3 - 1.2) = -1
f''(1.4) = (-1.2 - (-1.1))/ (1.4 - 1.3) = -1
f''(1.5) = (-1.3 - (-1.2))/ (1.5 - 1.4) = -1
From these calculations, we can see that the second derivative of the function appears to be negative over the entire interval.
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ans this please i have alot this to do help me
Answer:
3.1
Step-by-step explanation:
ok so, 3.14 rounded to the nearest tenth is 3.1
also, keep this in mind
if it is 5 and up it will be able to round up but if it is 4 round it down
5 + 7x= 11 + 7x (solve the equation)
A0
B14
C infinitely many solutions
D no solution
Can someone pls help :)
Answer:
D no solution :)
The circle graph shows the result of a survey. In what way is this graph misleading? Explain.
Step-by-step explanation:
because the total sum of each percent is 90%
and it must be 100% as it is a full circle