what is 2(x + 4) equivalent to

The missing premise is "all dogs are non-cats." Therefore, the argument is true.

The given information and analyze the argument step-by-step.

1. Some non-poodles are not non-cats: This statement means that there are some animals that are not poodles and are also cats.

2. No cats are dogs: This statement means that there is no overlap between cats and dogs.

Now, let's try to determine if "some poodles are dogs" can be concluded from these premises:
Since no cats are dogs, it doesn't matter whether some non-poodles are not non-cats. Poodles are a breed of dog, so it's already a fact that poodles are dogs.

So, the answer is True: some poodles are dogs.

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The intensity will be 304R, the correct option is d. 304R

An attribute of being intense or the quantifiable amount of a property, such as force, brightness, or a magnetic field, are both considered to be intensities.

The intensity of a source follows the inverse square law, which states that the intensity is inversely proportional to the square of the distance from the source.

Let's denote the initial distance as d1 (15 inches) and the initial intensity as I1 (10R). Let d2 (45 inches) be the new distance, and we need to find the new intensity, denoted as I2.

According to the inverse square law:

I1 / I2 = (d2 / d1)²

Plugging in the values:

10R / I2 = (45 inches / 15 inches)²

Simplifying:

10R / I2 = 3²

10R / I2 = 9

Now, solve for I2:

I2 = 10R / 9

So, the intensity at 45 inches (I2) will be 10R divided by 9.

Therefore, the answer is:

d. 304R

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It is expected that a vowel will be spun approximately 15 times.

To determine how many times is it expected that a vowel will be spun, taking into account that between the A and the J there are 3 vowels (A, E and I), the following calculation must be made:

Therefore, it is expected that a vowel will be spun approximately 15 times.

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Answer:

15

Step-by-step explanation:

Step-by-step explanation:

Adair earns 6% commission, and his total sales last week were $ 14,560. How much straight commission did Adair earn?

6% = 0.06

0.06 * $14,560 = $873.60 commission

The system of equations can be written as:-

10x + 4y = 42

6x + 8y = 14

A system of equations, also known as a set of simultaneous equations or an equation system, is a finite set of equations for which we sought common solutions in mathematics. A system of equations can be classified in the same way that a single equation can.

Given that in an online quiz, positive points are awarded for a correct answer, and negative points are awarded for an incorrect answer. Elena answers 10 questions correctly and 4 incorrectly and scores 42 points. Kiran answers 6 questions correctly and 8 incorrectly and scores 14 points.

The system of equations can be written as:-

10x + 4y = 42

6x + 8y = 14

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we need to multiply this number by 100 to get the  as a percentage:

0.1806 * 100 = 18.06%

The probability of choosing a senior can be calculated using the formula:

P(senior) = (102/562) * 100

P(senior) = 18.06%

This means that there is an 18.06% chance of choosing a senior if a student is randomly selected from the school.

First, we need to calculate the total number of students in the school by adding together the number of students in each class:

Total = 165 + 145 + 114 + 102 = 562

Next, we need to calculate the probability of choosing a senior by taking the number of seniors enrolled in the school (102) and dividing it by the total number of students in the school (562).

102/562 = 0.1806

Finally, we need to multiply this number by 100 to get the probability as a percentage:

0.1806 * 100 = 18.06%

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Answer:

The Answer To Your To Your Question Is SAS (Side-Angle-Side) Theroem

Answer:

Side angle side Theorem

Step-by-step explanation:

The number of the seats within the 25th row is 227.

According to the statement

We have to seek out that the quantity of seats are within the twenty-fifth row of the left section.

So, For this purpose, we all know that the

According to the information:

The number of seats within the first row of the left section of the Ming-Sun Theater is 9.

As with the middle section, the amount of seats in each succeeding row is 2 over the row ahead of it.

From this information, the equation become to search out the seats is:

Number of seats within the given row(x) = 9x+2

And the number of seats is: Number of seats within the 25th row(25) = 9(25)+2

Number of seats within the 25th row(25) = 225+2

Number of seats within the 25th row(25) = 227.

So, The amount of the seats within the 25th row is 227.

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In order to make an algebraic equation, we use variables to denote unknown numbers. Besides there are numbers and mathematical signs used.

It is defined by a mathematical expression consist of a number of terms shows the equality. There are different algebraic equations such as linear equation, quadratic polynomial equation, cubic polynomial equation and so on.

We use algebraic equation to state the equality of two mathematical expressions and the equation is developed based on the proposed statement. The equation contains any number such as 1,2,3 and variables x,y,a,b are used to denote an unknown value. Besides, x, +, -,=,±, ÷, √ etc signs are used according to the statement. But equal sign is mandatory for making an equation.

Now we will make an equation based on a mathematical statement

the statement says that 10 is subtracted from 5 times of an unknown number and the result is 20.

the equation will be 5x-10 =20, x is the unknown number

we can determine the value of x by solving the equation above.

hence, we can make algebraic equation by combining one or more number, variables and mathematical signs.

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Answer:

21x

Step-by-step explanation:

5x+14=19x

3x-5=-2x

-2x-19x=21x

Answer:

16

Step-by-step explanation:

Therefore:

Weight of flour used for muffin =Total weight of flour-(Weight of flour used for bread+Leftover)

=45-(15.6+18.04)

=45-33.64

=11.36 oz

Since each muffin is made with 0.71 oz of flour

Number of muffins made=11.36/0.71

=16

16 muffins were made.

Answer:

Yes it is absolutely right.

Answer:

Any bolt length lesser than 4.90 cm or greater than 9.10 cm will be destroyed

Explanation:

Given that:

Mean length = 7 cm

Standard deviation = 1.10 cm

Any bolt outside 2 standard deviations is to be destroyed

The bolt lengths that will be destroyed is obtained as shown below:

This therefore means that any bolt length lesser than 4.90 cm or greater than 9.10 cm will be destroyed

Answer:

they played 20 games together

Step-by-step explanation:

use percentages

Let x be the number of total games.

If 60% is won games then 40% is lost games.

(8/x)*100 = 40

8/x = 4/10

80 = 4x

X = 80/4

Therefore the number of games is 20

The unknown angle x in the triangle is 80 degrees

From the question, we have the following parameters that can be used in our computation:

The triangle

The unknown angle x is calculated using the sum of angles in a triangle theorem

So, we have

x + 60 + 40 = 180

Evaluate the like terms

x + 100 = 180

So, we have

x = 80

Hence, the unknown angle x is 80 degrees

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We are given with a limit and we need to find it's value so let's start !!!!

\({\quad \qquad \blacktriangleright \blacktriangleright \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}}\)

But , before starting , let's recall an identity which is the main key to answer this question

Consider The limit ;

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}}\)

Now as directly putting the limit will lead to indeterminate form 0/0. So , Rationalizing the numerator i.e multiplying both numerator and denominator by the conjugate of numerator

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}\times \dfrac{\sqrt{x}+\sqrt{3\sqrt{x}-2}}{\sqrt{x}+\sqrt{3\sqrt{x}-2}}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-\sqrt{3\sqrt{x}-2})(\sqrt{x}+\sqrt{3\sqrt{x}-2})}{(x^{2}-4^{2})(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Using the above algebraic identity ;

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x})^{2}-(\sqrt{3\sqrt{x}-2})^{2}}{(x-4)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-(3\sqrt{x}-2)}{(x-4)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}+2}{\{(\sqrt{x})^{2}-2^{2}\}(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}-2}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Now , here we need to eliminate (√x-2) from the denominator somehow , or the limit will again be indeterminate ,so if you think carefully as I thought after seeing the question i.e what if we add 4 and subtract 4 in numerator ? So let's try !

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{x-3\sqrt{x}-2+4-4}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(x-4)+2+4-3\sqrt{x}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Now , using the same above identity ;

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)+6-3\sqrt{x}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)+3(2-\sqrt{x})}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Now , take minus sign common in numerator from 2nd term , so that we can take (√x-2) common from both terms

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)(\sqrt{x}+2)-3(\sqrt{x}-2)}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Now , take (√x-2) common in numerator ;

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-2)\{(\sqrt{x}+2)-3\}}{(\sqrt{x}-2)(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Cancelling the radical that makes our limit again and again indeterminate ;

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{\cancel{(\sqrt{x}-2)}\{(\sqrt{x}+2)-3\}}{\cancel{(\sqrt{x}-2)}(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}+2-3)}{(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

\({:\implies \quad \displaystyle \sf \lim_{x\to 4}\dfrac{(\sqrt{x}-1)}{(\sqrt{x}+2)(x+4)(\sqrt{x}+\sqrt{3\sqrt{x}-2})}}\)

Now , putting the limit ;

\({:\implies \quad \sf \dfrac{\sqrt{4}-1}{(\sqrt{4}+2)(4+4)(\sqrt{4}+\sqrt{3\sqrt{4}-2})}}\)

\({:\implies \quad \sf \dfrac{2-1}{(2+2)(4+4)(2+\sqrt{3\times 2-2})}}\)

\({:\implies \quad \sf \dfrac{1}{(4)(8)(2+\sqrt{6-2})}}\)

\({:\implies \quad \sf \dfrac{1}{(4)(8)(2+\sqrt{4})}}\)

\({:\implies \quad \sf \dfrac{1}{(4)(8)(2+2)}}\)

\({:\implies \quad \sf \dfrac{1}{(4)(8)(4)}}\)

\({:\implies \quad \sf \dfrac{1}{128}}\)

\({:\implies \quad \bf \therefore \underline{\underline{\displaystyle \bf \lim_{x\to 4}\dfrac{\sqrt{x}-\sqrt{3\sqrt{x}-2}}{x^{2}-16}=\dfrac{1}{128}}}}\)

We can transform the limand into a proper rational expression by substitution.

Let y = √x. Then as x approaches 4, y will approach √4 = 2. So

\(\displaystyle \lim_{x\to4}\frac{\sqrt x - \sqrt{3 \sqrt x - 2}}{x^2 - 16} = \lim_{y\to2} \frac{y - \sqrt{3y-2}}{y^4 - 16}\)

Now let z = √(3y - 2). Then as y approaches 2, z will approach √(3•2 - 2) = 2 as well. It follows that y = (z² + 2)/3, so that

\(\displaystyle \lim_{y\to2} \frac{y - \sqrt{3y-2}}{y^4-16} = \lim_{z\to2} \frac{\frac{z^2+2}3 - z}{\frac{(z^2+2)^4}{81}-16} \\\\ = \lim_{z\to2} \frac{27(z^2+2)-81z}{(z^2+2)^4 - 1296} \\\\ = 27 \lim_{z\to2} \frac{z^2 - 3z + 2}{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280}\)

Plugging z = 2 into the denominator returns a value of 0, which means z - 2 divides z⁸ + 8z⁶ + 24z⁴ + 32z² - 1280 exactly. Polynomial division shows that

\(\dfrac{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280}{z-2} \\\\ = z^7+2z^6+12z^5+24z^4+72z^3+144z^2+320z+640\)

and it's easy to see that the numerator is also divisible by z - 2, since

\(z^2 - 3z + 2 = (z - 1) (z - 2)\)

So, we can eliminate the factor of z - 2 and we're left with

\(\displaystyle 27 \lim_{z\to2} \frac{z^2 - 3z + 2}{z^8 + 8z^6 + 24z^4 + 32z^2 - 1280} = 27 \lim_{z\to2}\frac{z-1}{z^7+\cdots+640}\)

The remaining limand is continuous at z = 2, so we can evaluate the limit by direct substitution:

\(\displaystyle 27 \lim_{z\to2}\frac{z-1}{z^7+\cdots+640} = \frac{27}{3456} = \boxed{\frac1{128}}\)

The valid assumptions for constructing a confidence interval for the difference between two population means are: Data is Quantitative, Random Sample and Both sample sizes are greater than 30 or the data is from a Normal Distribution.

To answer your question, when constructing a confidence interval for the difference between two population means, certain assumptions must be met. These assumptions include:

1. Data is Quantitative: Since we are dealing with population means, the data should be quantitative, meaning it consists of numerical values. This is a correct assumption.
2. Data is from a Convenience Sample: This is not a valid assumption. To ensure the reliability of the confidence interval, data should be collected through random sampling, which ensures that each individual in the population has an equal chance of being included in the sample.
3. Random Sample: This is a correct assumption. A random sample is necessary to ensure the sample's representativeness and accuracy in estimating the population means.
4. Both sample sizes are greater than 30 or the data is from a Normal Distribution: This is a valid assumption. If both sample sizes are greater than 30, the Central Limit Theorem can be applied, which states that the sampling distribution of the sample means will be approximately normal. If the data is already from a normal distribution, the normality assumption is met.
5. Data is Categorical: This assumption is incorrect. As previously mentioned, the data should be quantitative for this analysis.
6. There are at least 15 successes and 15 failures: This assumption is not relevant for confidence intervals for the difference between two population means. This criterion is related to proportions rather than means.

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So, the number of students in Band, Art, Music and Journalism are 2n, 7n+6, 4n-2 and 2(4n+6) respectively.

Since the number of students enrolled in Art and Music is equal to the number of students enrolled in Band and Journalism, we have the equation

7n + 6 + (4n-2) = 2n + 2(4n+6).

We now expand the brackets :
7n + 6 + 4n - 2 = 2n + 8n + 12
-> 11n + 4 = 10n + 12
-> 11n + 4 - 10n - 12 = 0
-> n - 8 = 0
-> n = 8.

Therefore, the number of students that enrolled in :
Band : 2n = 16 students.
Art : 7n + 6 = 62 students.
Music : 4n - 2 = 30 students.
Journalism : 8n + 12 = 76 students.

76 = 16 = 62 + 30 = 92, satisfying the requirement.

A possible unit vector that makes an angle of 45° with 9i + 4j is

\(v = (-9/\sqrt{(97)} )i + (0.933)j\)

Let's call the two unit vectors we're looking for as u and v.

We know that they make an angle of 45° with the vector 9i + 4j.

First, we need to find the unit vector in the direction of 9i + 4j. We can do this by dividing the vector by its magnitude:

\(|9i + 4j| = \sqrt{(9^2 + 4^2)} = \sqrt{(97)}\)

So the unit vector in the direction of 9i + 4j is:

\(u_0 = (9i + 4j) / \sqrt{(97)}\)

Now, we can use the dot product to find two unit vectors that make an angle of 45° with  \(u_0.\)

Let's call the first unit vector u.

We know that the dot product of u and \(u_0\) must be:

u . u_0 = |u| |u_0| cos(45°)

\(= (1)(1/ \sqrt{(97)} )(\sqrt{(2) /2)\)

\(= \sqrt{(2)} / (2 \sqrt{(97)} )\)

We also know that u must be a unit vector, which means its magnitude is We can use this information to solve for the components of u:

\(u . u_0 = (u_x)i + (u_y)j . (9/\sqrt{(97)} )i + (4/\sqrt{sqrt(97)} )j = \sqrt{(2) } / (2 \sqrt{(97)} )\)

Solving for the components of u, we get:

\(u_x = (9\sqrt{(2)} + 4\sqrt{(2)} ) / (2\sqrt{(97)} ) = 0.933\)

\(u_y = (4\sqrt{(2)} - 9\sqrt{(2)} ) / (2\sqrt{(97)} ) = -0.359\)

So one possible unit vector that makes an angle of 45° with 9i + 4j is:

u = 0.933i - 0.359j

To find the second unit vector, let's call it v, we know that it must be orthogonal to u (since the angle between u and v is 90°) and it must also be orthogonal to \(u_0\) (since the angle between \(u_0\) and v is also 90°).

We can use the cross product to find such a vector.

\(v = u_0 * u\)

\(v_x = (u_0)_y u_z - (u_0)_z u_y = (4/\sqrt{(97)} )(0) - (9/\sqrt{(97)} )(1) = -9/\sqrt{(97)}\)

\(v_y = (u_0)_z u_x - (u_0)_x u_z = (1/\sqrt{(97)} )(0.933) - (0/\sqrt{(97)} ) = 0.933\)

\(v_z = (u_0)_x u_y - (u_0)_y u_x = (0/\sqrt{(97)} )(-0.359) - (4/\sqrt{(97)} )(0.933) = -4/\sqrt{(97)}\)

We don't need the z-component of v, since we're working in 2-space.

So a possible unit vector that makes an angle of 45° with 9i + 4j is:

\(v = (-9/\sqrt{(97)} )i + (0.933)j\)

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The code defines a method `sumDigits` that takes two integers `numX` and `numY` as input and returns the count of numbers whose digits add up to `numY` for the given number `numX`.

Here's the corrected code to find the number of integers less than or equal to X whose digits add up to Y:

import java.util.Scanner;

public class Solution {

   public static int sumDigits(int numX, int numY) {

       int count = 0;

       for (int i = 1; i <= numX; i++) {

           int temp = i;

           int tempSum = 0;

           while (temp != 0) {

               tempSum += temp % 10;

               temp /= 10;

           }

           if (tempSum == numY) {

               count++;

           }

       }

       return count;

   }

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int numX = in.nextInt();

       int numY = in.nextInt();

       int result = sumDigits(numX, numY);

       System.out.println(result);

   }

}

This code defines a method `sumDigits` that takes two integers `numX` and `numY` as input and returns the count of numbers whose digits add up to `numY` for the given number `numX`. The main method takes input for `numX` and `numY`, calls the `sumDigits` method, and prints the result.

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Answer: This is gonna be a long one

1)Winston grows green dragon apples. This year, he shipped 80%of these apples to sell at supermarkets and kept the rest to make cider. Of all the green dragon apples he sold to the supermarkets, only 60% of them were bought. If a total of 420 green dragon apples were bought, how many green dragon apples did Winston keep to make cider?

 Call the number he shipped to the store, N

So .

60N  = 420   divide both sides by  ,60

420 / .60  = N  = 700 were shipped to the stores

But this number was  80%  of the total he grew = T

So

.80T  = 700   divide both sides by  .80

700/.80 = T  = 875

But..he kept 20% of these =   875 * .20  = 175

2)Ms. Forsythe gave the same algebra test to her three classes. The first class averaged 80%, the second class averaged 85%, and the third 89%. Together, the first two classes averaged 83%, and the second and third classes together averaged 87%. What was the average for all three classes combined? Express your answer to the nearest hundredth.

The average  =  total points / number of students

So....total points = average*number of students

Let the total number of students in  each class = x , y  and z

The total number of points the first class amassed  was   80x

The total number of points amased by the second class was  85y

The total number of points amassed by the third class = 89z

So...for the first two classes we have

[ 80x + 85y ] / [ x + y] = 83

80x + 85y = 83x + 83y  subtract  80x, 83y from both sides    

3x = 2y

x = 2/3y

And,,,for the second two classes we have

[ 85y + 89z ]  / [ y + z ]  =  87  

[  85y + 89z ]  = 87 [y + z]

85y + 89z = 87y + 87z      subtract  85y, 87z from both sides

2z = 2y  

y  = z

So...for the three classes.....

Total points by all three classes /  number of class members  = the average for all three classes

[ 80x + 85y  + 89z ] /  [ x + y + z ]   =

[sub for  x and z ]  

[80 (2/3)y  + 85y  + 89y]  /  [ (2/3)y  + y  + y ]  

y [ 80 (2/3)  + 85  + 89 ]  / [  y [( 2/3) + 1 + 1] ]       [cancel the y's ]

[ 80 (2/3) + 85 + 89]  [  8/3 ]

[ 160/3 + 85 + 89 ] /  [8/3] =

[ 160/3  + 255/3 + 267/3]  / [8/3]     multiply  top/bottom by 3

[160 + 255 + 267 ] / 8  =  

85.25  = average for all three classes

Step-by-step explanation:

Hope it helps

Pls mark me as brainliest

Peace out

Answer:

Subtracting a negative number from a negative number – a minus sign followed by a negative sign, turns the two signs into a plus sign. So, instead of subtracting a negative, you are adding a positive. Basically, - (-4) becomes +4, and then you add the numbers. For example, say we have the problem -2 - –4.

After combining like terms to create equivalent expression we get (-1.9 + 1.2) + (5.1 - 3.6)t. Simplifying further, we get: -0.7 + 1.5t.

To combine like terms, we add or subtract the coefficients of the same variables. In this case, the variables are t and the constant terms (without variables) are -3.6, -1.9, and 1.2.

So the equivalent expression after combining like terms is:

(-1.9 + 1.2) + (5.1 - 3.6)t

Simplifying further, we get:

-0.7 + 1.5t

A coefficient is a numerical factor that is multiplied by a variable in an algebraic expression. It tells you how many times the variable appears in the expression. For example, in the expression 3x + 2, the coefficient of x is 3. Variables are symbols used to represent unknown quantities in mathematical equations or expressions. They can take on different values, and their value can be solved for using algebraic techniques. Equivalent expressions are expressions that have the same value for all possible values of the variables involved. For example, 2x + 4 and 4 + 2x are equivalent expressions since they simplify to the same value. Equivalent expressions can be useful in simplifying and solving algebraic equations.

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Complete Question

Combine like terms to create an equivalent expression. −

3. 6−1. 9+1. 2+5. 1 −3. 6−1. 9t+1. 2+5.

Answer:

Yes, Amanda has enough materials to make the concrete mix.

Step-by-step explanation:

Total units = 1+3+5

                 = 9

9 units = 630kg

1 unit = 630kg ÷ 9

        = 70kg (Less than 80kg of cement, more than enough)

3 units = 3 × 70kg

           = 210kg (Less than 215kg of sand, more than enough sand)

5 units = 5 × 70kg

           = 350kg (Less than 370kg of gravel, more than enough gravel)

Answer:

Step-by-step explanation:

Step 1: we write 23% in decimal form: 23%=0.23.Step 2: we find the multiplier. Since we're increasing by 23%, we add 0.23 to 1: 1+0.23=1.23.Step 3: we multiply 80 by the multiplier 1.23: 80×1.23=98.4

So that means your answer is 1.23

The graph of the parabola (x- 5 )²/25 - (y + 3)²/36 = 1 is added as an attachment

From the question, we have the following parameters that can be used in our computation:

(X-5)2/25 - (y+3)2/36 = 1.

Express the equation properly

So, we have

(x- 5 )²/25 - (y + 3)²/36 = 1

The above expression is a an equation of a conic section

Next, we plot the graph using a graphing tool

To plot the graph, we enter the equation in a graphing tool and attach the display

See attachment for the graph of the function

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Answer:

6. E

7. D

8. 5,-8,34

Step-by-step explanation:

A. Parallel to the y-axis and passes through the point (3,5)

For it to be parallel to the y-axis, what this means is that it has an x-intercept and no y intercept.

So what this means is that x = 3 is our line so E is correct

B. Perpendicular to the y-axis means it is parallel to the x-axis

It means is has no x intercept and thus its x value at any point in time is zero

So the equation is y = -5

or simply y + 5 = 0 which means D is correct

C. It is parallel to the line 5x -8y + 12 = 0

Thus: 8y = 5x + 12

dividing both sides by 8

y = 5x/8 + 12/8

y = 5x/8 + 3/2

y = 5x/8 + 1.5

Comparing this with the general equation of a straight line ;

y = mx + c

where m is that slope, this means that 5/8 is the slope of the line

Mathematically if two lines are parallel, they have equal slopes.

So we can say the slope of the other line too is 5/8

Now to find the equation of the other line, we can use the point-slope method

y-y1 = m(x-x1)

where (x1,y1) in this case is (-2,3)

So we have;

y-3 = m(x-(-2))

y-3 = 5/8 (x + 2)

8(y-3) = 5(x + 2)

8y -24 = 5x + 10

5x + 10 + 24 -8y = 0

5x -8y + 34 = 0

So A, B, C = 5, -8, 34

The arithmetic mean for the given data is 69.5, obtained by summing the products of midpoints and frequencies and dividing by the total frequency.

To find the arithmetic mean, we need to calculate the sum of all the values in the data set and then divide it by the total number of values. In this case, we have the class frequencies and the midpoints of each class interval. To calculate the sum, we multiply each class frequency by its corresponding midpoint and then add all the values together.

For example, for the first class interval (50-54), the midpoint is 52, and the frequency is 7. So, the contribution of this interval to the sum is 52 * 7 = 364. We do the same calculation for each interval and add them up to get the total sum.

Next, we divide the total sum by the sum of all the frequencies, which in this case is 50. So, the arithmetic mean is 69.5 (total sum divided by the total number of values).

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Answer:

the median is 8

Step-by-step explanation:

hope this helps!

2,5,6,7,8,10,11,12,14

Answer:

8

Step-by-step explanation:

Rearrange to 2 5 6 7 8 10 11 12 14 in ascending order

Take the center number