Answer:
3 ≥ n > 2
Step-by-step explanation:
Step 1: Add 12 to all sections.
\(-33 + 12 \leq -7n - 12 + 12 < -26 + 12\) \(-21\leq -7n < -14\)Step 2: Divide all sections by -7 and flip the signs.
\(\frac{-21}{-7} \leq \frac{-7n}{-7} <\frac{-14}{-7}\) \(3 \geq n > 2\)The equation and graph of a polynomial are shown below. The graph reaches its minimum one the value of X is 4. What is the y-value of this minimum?
Solution
The y-value of this minimum
when x=4
We need to substitute to the polynomial equation
\(\begin{gathered} y=2x^2-16x+30 \\ \text{Let substitute for x } \\ y=2(4)^2-16(4)\text{ +30} \\ y=2(16)-64+30 \\ y=32-64+30 \\ y=-2 \end{gathered}\)The y-value of this minimum is -2
The blue dot is at what value on the number line?
10 +
2.
Answer:
-10
Step-by-step explanation:
We can figure out that the number line is by four.
How?
There is one line between 10 and 2. Sooo:
10 - 2 = 8
8 / 2 = 4
If we check it (10 - 4 - 4 = 2) it checks out!
Using this information we can figure out what the blue dot is.
2 (given) - 4 (incriments of number line) - 4 - 4 = - 10
There is our answer, -10!
On October 1, Nadia starts a push-up challenge by doing 18 push-ups. On October 2, she does 21 push¬ups. On October 3, she does 24 push-ups. She continues until October 16, when she does the final push-ups in the challenge. a. Write an explicit definition to model the number of push-ups Nadia does each day. b. Write a recursive definition to model the number of push-ups Nadia does each day. c. How many push-ups will Nadia do on October 16? d. What is the total number of push-ups Nadia does from October 1 to October 16?
Answer:
\(\textsf{a)} \quad a_n=3n+15\)
\(\textsf{b)} \quad \begin{cases}a_n=a_{n-1}+d\\a_1=18\end{cases}\)
\(\textsf{c)} \quad 63\)
\(\textsf{d)} \quad 648\)
Step-by-step explanation:
Part (a)An explicit formula for an arithmetic sequence allows you to find the nth term of the sequence.
Explicit Formula
\(\boxed{a_n=a+(n-1)d}\)
where:
\(a_n\) is the nth term.a is the first term.n is the number of the term.d is the common difference.Given information:
October 1 = 18 push-upsOctober 2 = 21 push-upsOctober 3 = 24 push-upsNadia increases the number of push-ups each day by 3. Therefore:
a = 18d = 3Substitute the values of a and d into the formula to create an explicit formula to model the number of push-ups Nadia does each day:
\(\implies a_n=18+(n-1)3\)
\(\implies a_n=18+3n-3\)
\(\implies a_n=3n+15\)
Part (b)A recursive formula for an arithmetic sequence allows you to find the nth term of the sequence provided you know the value of the previous term in the sequence.
Recursive Formula
\(\boxed{a_n=a_{n-1}+d}\)
where:
\(a_n\) is the nth term.\(a_{n-1}\) is the (n-1)th term.d is the common difference.We already know the common difference from the previous calculations.
Therefore:
\(\implies a_n=a_{n-1}+3\)
When giving a recursive rule we have to define the first term of the sequence, as it is not part of the formula. Therefore, the full recursive rule for the given scenario is:
\(\begin{cases}a_n=a_{n-1}+d\\a_1=18\end{cases}\)
Part (c)To calculate how many push-ups Nadia will do on October 16, substitute n = 16 into the recursive formula from part (a):
\(\implies a_{16}=3(16)+15\)
\(\implies a_{16}=48+15\)
\(\implies a_{16}=63\)
Therefore, Nadia will do 63 push-ups on October 16.
Part (d)Sum of the first n terms of an arithmetic series:
\(\boxed{S_n=\dfrac12n(a+a_n)}\)
To find the total number of push-ups Nadia does from October 1 to October 16, substitute n = 16, a = 18 and a₁₆ = 63 into the formula:
\(\implies S_{16}=\dfrac12(16)(18+63)\)
\(\implies S_{16}=8(81)\)
\(\implies S_{16}=648\)
Therefore, Nadia does a total number of 648 push-ups from October 1 to October 16.
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what is the answer to -24 = 36x
devide both sides by 36
-24/36 = x
reduce
-2/3
if the linear dimensions of the cube double, what is the total electric flux through the cubic surface now?
If the linear dimensions of the cube double, the total electric flux through the cubic surface will double as well.
The total electric flux through a closed surface is equal to the charge enclosed within the surface divided by the permittivity of free space. The electric flux is given by the dot product of the electric field and the area vector of the surface, integrated over the surface.
When the linear dimensions of a cube double, the surface area of the cube increases by a factor of eight (2^3). This means that there is more surface area over which to integrate the electric flux, and therefore the total electric flux through the surface increases. However, the electric field inside the cube does not change when the dimensions double.
Therefore, the total electric flux through the surface increases as the cube's dimensions double, because there is more surface area over which to integrate the constant electric field. The increase in total electric flux is proportional to the increase in surface area, which is a factor of eight.
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a. Find the linear approximating polynomial for the following function centered at the given point a.
b. Find the quadratic approximating polynomial for the following function centered at the given point a.
c. Use the polynomials obtained in parts a. and b. to approximate the given quantity.
f(x) = 16x^3/2 a = 4; approximate 16 (4.1^3/2)
a. p_₁(x) = ______
b. p_₂(x) = _______
c. Using the linear approximating polynomial to estimate, 16 (4.1^3/2) is approximately ______
(Simplify your answer.)
Using the quadratic approximating polynomial to estimate, 16(4.1^3/2) is approximately _________
(Simplify your answer.)
The answer to b. p₂(x) = 6(x - 4)² + 48(x - 4) + 128. The answer to c, Using the quadratic approximating polynomial to estimate, 16(4.1^3/2) is approximately 190.06.
We are to find the linear approximating polynomial for the function f(x) = 16x^(3/2) centered at the given point a = 4To find the linear approximating polynomial we use the formula P1(x) = f(a) + f'(a)(x-a)Where f'(a) is the first derivative of f(x) evaluated at x = a, which is given by; f(x) = 16x^(3/2)f'(x) = 24x^(1/2)Now, f(4) = 16(4)^(3/2) = 128P1(x) = 128 + 24(√4)(x - 4)P1(x) = 128 + 48(x - 4)P1(x) = 48x - 32We are to find the quadratic approximating polynomial for the function f(x) = 16x^(3/2) centered at the given point a = 4To find the quadratic approximating polynomial we use the formula P2(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)²/2Where f''(a) is the second derivative of f(x) evaluated at x = a, which is given by;f(x) = 16x^(3/2)f'(x) = 24x^(1/2)f''(x) = 12x^(-1/2).
Now, f(4) = 16(4)^(3/2) = 128f'(4) = 24(√4) = 48f''(4) = 12(√4)^-1 = 6P2(x) = 128 + 48(x - 4) + 6(x - 4)²P2(x) = 6(x - 4)² + 48(x - 4) + 128We will now use the polynomials obtained in parts a and b to approximate the given quantity. 16(4.1^3/2)Using the linear approximating polynomial, we have;P1(4.1) = 48(4.1) - 32P1(4.1) = 182.8We can say that 16(4.1^3/2) ≈ 182.8Using the quadratic approximating polynomial, we have;P2(4.1) = 6(4.1 - 4)² + 48(4.1 - 4) + 128P2(4.1) = 190.06We can say that 16(4.1^3/2) ≈ 190.06The answer to a. p₁(x) = 48x - 32The answer to b. p₂(x) = 6(x - 4)² + 48(x - 4) + 128The answer to c. Using the linear approximating polynomial to estimate, 16 (4.1^3/2) is approximately 182.8.The answer to c. Using the quadratic approximating polynomial to estimate, 16(4.1^3/2) is approximately 190.06.
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the
net migration is confusing me. i thought of using the formula:
[ (births + immigration) - (deaths + emmigration)] / total
population • 100 but im not sure how to do it with net migration?
do i p
The value of the rate of growth in Japan is - 0.55.
From the question above, :Birth rate = 7.7 per thousand
Death rate = 9.8 per thousand
Net migration = 0.55 per thousand
The rate of growth can be calculated using the following formula:
r = (birth rate - death rate) + net migration
Where,r = rate of growth
birth rate = number of live births per thousand in a population in a given year
death rate = number of deaths per thousand in a population in a given year
net migration = the difference between the number of people moving into a country (immigrants) and the number of people leaving a country (emigrants) per thousand in a given year
Putting the values in the formula we get,r = (7.7 - 9.8) + 0.55r = - 1.1 + 0.55r = - 0.55.
Therefore, the rate of growth in Japan is - 0.55.
Your question is incomplete but most probably your full question was:
thenet migration is confusing me. i thought of using the formula:[ (births + immigration) - (deaths + emmigration)] / total
population • 100 but im not sure how to do it with net migration.
Japan's birth rate is 7.7 per thousand and its death rate is 9.8 per thousand with a net migration of 0.55 ner thousand. Calculate r for Japan
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Find the measure of
major arc FGH.
(21x-2
.
Ін
F
38x + 5
go to (-3, 4)
А
go to (-8,4)
a) 2330
b) 124°
c) 300°
d) 1220
e) 2389
go to (5,3)
go to (4.6)
go to (-7, -1)
Answer:
E is the answer
Step-by-step explanation:
This is a cyclic quadralterial so 21x-2 and 38x+5 is supplementary since they are opposite angles.
\(21x - 2 + 38x + 5 = 180\)
\(59x + 3 = 180\)
\(59x = 177\)
\(x = 3\)
Substitute 3 into angle A
\(38(3) + 5 = 119\)
Since HA, is the intercepted arc of Angle G Angle G is twice the size of Arc HA,
Angle G=238
The sum of three consecutive odd integers is 3. Find the value of the greatest of the three.
Answer:
3
Step-by-step explanation:
You want the greatest of three consecutive odd integers that have a sum of 3.
AverageThe average of the integers is their sum divided by their number:
average = 3/3 = 1
This is the value of the middle of the three integers, so they are ...
-1, 1, 3
The greatest of the three is 3.
Can someone help me out and show work please
The function is assigning to each element of one set exactly one element from the other set.
First table represent a function.
Second table not represent a function (for -1 are four different numbers).
Third table represent a function.
Fourth table not represent a function (for -6 are two differen numbers 5 and 9)
Can you guys help i’m kinda struggling
Answer:
The answer is 20.
Step-by-step explanation:
The side that equals 4 is conguent to the line QR, the side that equals 6 is congruent to the line NP. Add the whole line up then it would equal 20.
The population on a certain island increased from 1500 in 2000 to 1577 in 2001 a. Determine the growth rate b. Write a general equation for the popolation p(t) c. Estimate the population in 2010 d. How many years will it take for the population to double?
Therefore, it will take approximately 13.7 years for the population to double.
a. To determine the growth rate, you need to calculate the percentage increase in population. The formula for growth rate is:
Growth Rate = (New Value - Old Value) / Old Value * 100
Using the given values, we have:
Growth Rate = (1577 - 1500) / 1500 * 100
Growth Rate = 77 / 1500 * 100
Growth Rate ≈ 5.13%
b. To write a general equation for the population, you can use the formula:
p(t) = p(0) * (1 + r/100)^t
where p(t) is the population at time t, p(0) is the initial population, r is the growth rate, and t is the number of years.
c. To estimate the population in 2010, we need to find the population at time t = 2010 - 2000 = 10 years. Using the general equation from part b, and substituting the given values:
p(10) = 1500 * (1 + 5.13/100)^10
p(10) ≈ 1500 * (1.0513)^10
p(10) ≈ 1500 * 1.6436
p(10) ≈ 2465.4
Therefore, the estimated population in 2010 is approximately 2465.
d. To find out how many years it will take for the population to double, we need to solve the equation:
2 * p(0) = p(0) * (1 + r/100)^t
Simplifying the equation, we have:
2 = (1 + r/100)^t
Taking the logarithm of both sides, we get:
log(2) = t * log(1 + r/100)
Finally, solving for t, we have:
t = log(2) / log(1 + r/100)
Substituting the growth rate from part a, we have:
t = log(2) / log(1 + 5.13/100)
t ≈ log(2) / log(1.0513)
t ≈ 13.7 years
Therefore, it will take approximately 13.7 years for the population to double.
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Using +- 3o limits, calculate the LCL and UCL for these data A) UCL=7.437;LCL=−2.237 B) ∪CL=7.82;LCL=0 C) UCL=8.382;LCL=0 D) UCL=7.82;LCL=−2.22 E) UCL=9.112;LCL=0
The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated for different data sets, as specified in the given values.
The UCL and LCL are statistical control limits used in process control to determine if a process is in a stable and predictable state. These limits define the range within which data points should fall if the process is under control.
In each case provided (A, B, C, D, E), the UCL and LCL values are given. These values represent the calculated control limits for the respective data sets.
To calculate the control limits, a specific statistical method such as the ± 3σ (sigma) method may have been used. This method sets the UCL and LCL at three standard deviations above and below the mean.
The UCL represents the upper threshold or upper boundary, while the LCL represents the lower threshold or lower boundary. These limits help identify any potential deviations or out-of-control situations in the data.
By applying the given values, the corresponding UCL and LCL for each data set can be calculated. These limits are important for quality control and process monitoring, ensuring that the data falls within acceptable ranges.
To calculate the UCL and LCL using ±3σ limits, we use the following formulas:
UCL = Mean + 3σ
LCL = Mean - 3σ
Here, σ represents the standard deviation of the data set. The ±3σ limits provide a range that encompasses most of the data points in a normal distribution, with approximately 99.7% of the data falling within this range.
A) For data set A:
UCL = 7.437
LCL = -2.237
B) For data set B:
UCL = 7.82
LCL = 0
C) For data set C:
UCL = 8.382
LCL = 0
D) For data set D:
UCL = 7.82
LCL = -2.22
E) For data set E:
UCL = 9.112
LCL = 0
The ±3σ limits are derived from the standard deviation (σ) of the data set. Unfortunately, the standard deviation is not provided in the given information. If you have the standard deviation available, we can proceed to calculate the UCL and LCL using the formulas UCL = Mean + 3σ and LCL = Mean - 3σ.
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Question - What are the upper control limit (UCL) and lower control limit (LCL) using a ±3σ limit for the given data sets?
A) For data set A, the UCL is 7.437 and the LCL is -2.237.
B) For data set B, the UCL is 7.82 and the LCL is 0.
C) For data set C, the UCL is 8.382 and the LCL is 0.
D) For data set D, the UCL is 7.82 and the LCL is -2.22.
E) For data set E, the UCL is 9.112 and the LCL is 0.
Shade 3/4 on the grid
A couple ordered 54 ounces of pate for their engagement party of 27 people. The pate was such a hit that the couple decided to serve it again at their wedding reception. How many ounces of pate should they order for 398 people?
Based on the calculation below, the number of ounces of pate that should be ordered for 398 people is 796 ounces.
How do we calculate a number of units to order?The number of ounces of pate that should be ordered for 398 people can be calculated as follows:
Number of ounces of pate previously ordered per person = Total number of ounces of pate previously ordered / Number of people at the engagement party = 54 / 27 = 2 ounces per person
Number of ounces of pate that should be ordered = Number of ounces of pate previously ordered per person * Number of people = 2 * 398 = 796 ounces
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∠A and \angle B∠B are vertical angles. If m\angle A=(4x+6)^{\circ}∠A=(4x+6) ∘ and m\angle B=(2x+18)^{\circ}∠B=(2x+18) ∘ , then find the value of x. Answer: attempt 2 out of 2 Deyvi Simon macario Angle Terminology with Equations Mar 28, 8:46:10 AM Watch help video \angle A∠A and \angle B∠B are vertical angles. If m\angle A=(4x+6)^{\circ}∠A=(4x+6) ∘ and m\angle B=(2x+18)^{\circ}∠B=(2x+18) ∘ , then find the value of x.
The value of the variable x = 6, when ∠A and ∠B are vertical angles.
What are vertical angles?Vertical angles are fοrmed when twο lines meet each οther at a pοint. They are always equal tο each οther. In οther wοrds, whenever twο lines crοss οr intersect each οther, 4 angles are fοrmed. We can οbserve that twο angles that are οppοsite tο each οther are equal and they are called vertical angles. They are alsο referred tο as 'Vertically οppοsite angles' as they lie οppοsite tο each οther.
We know that vertical angles are equal, thus:
m∠A = m∠B
We have given that
m∠A = (4x+6)°
and
m∠B = (2x+18)°
Then,
(4x+6)° = (2x+18)°
4x + 6 = 2x + 18
4x - 2x = 18 - 6
2x = 12
x = 12/2
x = 6
The value of the variable x = 6, when ∠A and ∠B are vertical angles.
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Complete correct question:
∠A and ∠B are vertical angles. If m∠A=(4x+6)° and m∠B=(2x+18)°, then find the value of x.
What percentage of the core are within one tandard deviation of the mean (1)? Pleae include the range of value for thi deviation and the exact value from the data et that are included in thi range
Answer:
The grand pacer test stated that the percentage of the core would be 50%
SThe range of tep-by-step explanation:
What is this expression in simplified form?
Answer:
\(15\sqrt{5}\)
Step-by-step explanation:
simplify \(\sqrt{20}\) and \(3\sqrt{50}\)
\(\sqrt{20}\) simplifies into \(\sqrt{5}\)
so \(\sqrt{20}\) = \(\sqrt{4} \sqrt{5}\)
we can simplify \(\sqrt{4\) into a whole number
\(\sqrt{4\) =2
= 2\(\sqrt{5}\)
\(\sqrt{50\) simplifies into \(\sqrt{2\)
so \(\sqrt{50\) =3( \(\sqrt{25} \sqrt{2}\))
we can simplify \(\sqrt{25}\) into a whole number
\(\sqrt{25\) = 5
= 15\(\sqrt{2\)
then we add these simplified roots back into the question
2\(\sqrt{5}\) + \(5\sqrt{2\) -\(2\sqrt{5\)
we simplify again as \(2\sqrt{5\) cancels out
to get a final answer of:
\(15\sqrt{5}\)
Three equidistant dots on each of two parallel lines are joined in all possible ways, how many triangles can be formed ?
Answer:
only one triangle can be formed ...
please help I will give you brainliest
Answer:
Both the line right before the 2 and the line right before the one
Step-by-step explanation:
What is the value of P(20) = 1.50x - 25
The value of the given function P(20) = 1.50x - 25 is 5.
What is a function?A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variables. This ultimately implies that, a function is typically used for mapping an input variable to an output variable.
The types of function.In Mathematics, there are different types of function and these include the following;
Periodic functionInverse functionModulus functionSignum functionPiece-wise defined function.Logarithm functionNext, we would evaluate the given function by substituting the value of x as follows:
P(20) = 1.50x - 25
P(20) = 1.50(20) - 25
P(20) = 30 - 25
P(20) = 5.
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PLEASE HELP ASSP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
A: 2/9
Step-by-step explanation:
let p be the price of an item. the unit sales of the item are 200 - 5p. what is the correct formula for the revenue generated by the item?
The correct formula for the revenue generated by the item is Revenue = 200p - 5p^2.
The revenue generated by the item can be calculated by multiplying the price (p) by the unit sales (200 - 5p). Therefore, the correct formula for the revenue generated by the item is:
Revenue = Price x Unit Sales
Revenue = p(200 - 5p)
Revenue = 200p - 5p^2
The revenue generated by the item is a quadratic function of the price (p). To find the maximum revenue, we need to differentiate the function with respect to p and set it equal to zero:
dRevenue/dp = 200 - 10p = 0
10p = 200
p = 20
Therefore, the maximum revenue is generated when the price of the item is $20. Substituting p = 20 in the revenue formula, we get:
Revenue = 200(20) - 5(20^2) = $2000
Hence, the correct formula for the revenue generated by the item is Revenue = 200p - 5p^2, and the maximum revenue is achieved when the price of the item is $20, generating a revenue of $2000.
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1.What is the approximate diameter of a sphere with a volume of 128π cubic inches?
Answer:
diameter = \(8\sqrt{6}\) inches
Step-by-step explanation:
The formula for the volume of a sphere:
\(V = \frac{4}{3} \pi r^{2}\)
Plug in known variable, V
\(128\pi = \frac{4}{3} \pi r^{2}\)
divide by pi
\(128 = \frac{4}{3}r^2\)
divide by 4/3
\(96 = r^2\)
take the square root to isolate r
\(r = \sqrt{96}\)
\(r = \sqrt{4 * 4 * 6}\)
r = \(4\sqrt{6}\)
double r for diameter
\(4\sqrt{6} * 2 = 8\sqrt6\)
what is the asymptotic slope of the best-fit line for the equation, y = 5x^4 3y=5x 4 3, when plotted on a log-log plot?
The asymptotic slope of the best fit line for the equation y = 5x^4 + 3 when plotted on a log-log plot is 4.
To find the asymptotic slope of the best fit line for the equation y = 5x^4 + 3 when plotted on a log-log plot, we first need to rewrite the equation in logarithmic form.
Taking the logarithm of both sides with base 10, we get
log(y) = log(5x^4 + 3)
Using the logarithmic rule for multiplication, we can simplify this to
log(y) = log(5) + 4log(x) + log(3)
Now, we can plot log(y) as a function of log(x) on a graph and find the best fit line using linear regression. The slope of the best fit line will give us the power-law exponent for the relationship between y and x.
The general formula for the slope of a line on a log-log plot is
slope = Δlog(y) / Δlog(x)
where Δlog(y) is the change in log(y) and Δlog(x) is the change in log(x) between any two points on the line.
Since we want to find the asymptotic slope, we need to look at the behavior of the line as x approaches infinity. This means we need to choose two points on the line that are far apart in the x-direction, but still lie on the line.
Let's say we choose two points (x1, y1) and (x2, y2) such that x2 = 10x1. Then, we can calculate the slope of the line between these two points as
slope = (log(y2) - log(y1)) / (log(x2) - log(x1))
Substituting the logarithmic form of the equation for y, we get
slope = (log(5x2^4 + 3) - log(5x1^4 + 3)) / (log(x2) - log(x1))
Plugging in x2 = 10x1 and simplifying, we get
slope = (4log(10) + log(5x1^4 + 3) - log(5x1^4 + 3)) / (log(10x1) - log(x1))
Simplifying further, we get
slope = 4log(10) / log(10)
slope = 4
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The given question is incomplete, the complete question is:
What is the asymptotic slope of the best fit line for the equation, y = 5x^4+3, when plotted on log-log plot?
what is the slope of this line?? someone please help
Answer:
-2.5
Step-by-step explanation:
Please help me on this question
Answer:
√20
Or
2√5
Step-by-step explanation:
It is very easy just substitute
It will be:
A candy bar manufacturer is interested in trying to estimate how sales are influenced by the price of their product. To do this, the company randomly chooses 6 small cities and offers the candy bar at different prices. Using candy bar sales as the dependent variable, the company will conduct a simple linear regression on the data below: What is the estimated average change in the sales of the candy bar if price goes up by $1.00?
Answer:
-48.19
Step-by-step explanation:
Given the data:
City Price ($) Sales
River Falls 1.30 100
Hudson 1.60 90
Ellsworth 1.80 90
Prescott 2.00 40
Rock Elm 2.40 38
Stillwater 2.90 32
We could obtain a simple regression model of the data above using a linear regression calculator :
The regression model obtained is :
ŷ = -48.19277X + 161.38554
The change in sales per unit change in price is the value of the slope or gradient :
From the general linear regression equation :
y = mx + c
m = slope ;
Slope = - 48.19 ; hence, there is a drop in sales by about 48 units as the change in sales as the price of candy bar goes up by about $1.00
 can anyone please help me I really need help please help me thank you
Answer:
so length is a and width is b
2(a+b)=82
a+b=41
2b+3=41
b=19
a=22
16/17 as a decimal rounded to the nearest hundredth
Answer:
the answer is 0.94
Step-by-step explanation:
16/17 = 0.941176470588
the hundreths place is where the 4 is, and to the right of the 4 is a one, if its under 5 then dont round up so your answer will remail 0.94.
hope this helps have a great day!