What is 36m : 12km in its simplest form.

We can compute various descriptive statistics such as the mean, median, mode, range, variance, standard deviation, sum of values, and sum of squared deviations.

The sample mean, also known as the average, provides information about the central tendency of the variable X. It represents the typical or average number of coupons used by the shoppers in the sample. In this case, calculating the mean of the given data would provide an estimate of the average number of coupons used over the 6-month period.

The sample standard deviation measures the dispersion or variability of the data points around the mean. It indicates how much the individual observations deviate from the mean value. A higher standard deviation implies greater variability, indicating a wider range of coupon usage among the shoppers in the sample.

By computing the sample mean and standard deviation, we can understand the average coupon usage and the degree of variability in the data. These statistics help us summarize and interpret the characteristics of the variable X, allowing us to make comparisons, identify outliers, assess the spread of the data, and make inferences about the larger population from which the sample was drawn.

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Answer:

16

Step-by-step explanation:

you back track the numbers such as 4 goes back to 2 and 28 goes back to 22 then again and you get x as 9 and y as 16

Answer:

$1615

Step-by-step explanation:

500(1+.05/1)^24

500(1+.05)^24

500*1.05^24

500*3.23

1615

"Statistics: The Art and Science of Learning from Data" (4th edition) is a valuable resource for understanding and applying statistical principles, providing insights into data analysis and decision-making processes.

Statistics is the art and science of learning from data. It involves collecting, organizing, analyzing, interpreting, and presenting data to gain insights and make informed decisions. In the 4th edition of the book "Statistics: The Art and Science of Learning from Data," you can expect to find a comprehensive exploration of these topics.

This edition may cover important concepts such as descriptive statistics, which involve summarizing and displaying data using measures like mean, median, and standard deviation. It may also delve into inferential statistics, which involve making inferences and drawing conclusions about a population based on a sample.

Additionally, the book may discuss various statistical techniques such as hypothesis testing, regression analysis, and analysis of variance (ANOVA). It may also provide real-world examples and case studies to illustrate the application of statistical methods.

When using information from the book, it is important to properly cite and reference it to avoid plagiarism. Be sure to consult the specific edition and follow the guidelines provided by your instructor or institution.

In summary, "Statistics: The Art and Science of Learning from Data" (4th edition) is a valuable resource for understanding and applying statistical principles, providing insights into data analysis and decision-making processes.

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Answer:

n = 3200

Step-by-step explanation:

200 = 1000 - \(\frac{n}{4}\) ( subtract 1000 from both sides )

- 800 = - \(\frac{n}{4}\) ( multiply both sides by 4 to clear the fraction )

- 3200 = - n ( multiply both sides by - 1 )

n = 3200

Answer:

=The opposite angles of a parallelogram are equal

=(3x+4)

=(5x-2)

=-2x=-6

=x=6+2

=x=3=

1st angle=3x+4=13

3rd angle=5x-2=13

=sum of adjacent side of angle is 180°

=Let the adjacent (2nd angle ) be y=

y+13°=180°

=y=180°-13°

=y=167°=

2nd angle=4th angle

=2nd angle=167° 

=4th angle=167°

Step-by-step explanation:

This might be confusing, but I hope it helps <3

Answer:

I'm sure there might be a typo in the question (AKA the slope is -5/2)

but the answer would be

D

Step-by-step explanation:

y= mx+ b

where m is the slope, and b is the y intercept

y= -52x -2

..........

5x + 2y = –4

2y= -5x -4

y= - 5/2x -2

\(y = - \frac{5}{2} x - 2\)

Since it has four sides and four angles, it is also simply called a quadrilateral.

Rick drew a rhombus. Some names that might describe the figure, considering the properties of quadrilaterals, are:
Quadrilateral: A rhombus is a type of quadrilateral, which means it has four sides and four angles.
Parallelogram: A rhombus is also a parallelogram because its opposite sides are parallel to each other.
Square: If the rhombus has four right angles, then it can also be called a square. A square is a specific type of rhombus and a special case of a parallelogram where all angles are right angles.
A rhombus is a type of quadrilateral that has four sides of equal length. It is also classified as a parallelogram because it has two pairs of parallel sides. Additionally, since all angles in a rhombus are equal, it can also be called an equilateral parallelogram. Finally, since it has four sides and four angles, it is also simply called a quadrilateral.
So, Rick's figure can be described as a quadrilateral, parallelogram, and potentially a square depending on its angles.

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u in the plane in set of real numbers rℝcubed3 spanned by the columns, then the one solution matrix is,   \(\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right]\) = \(\left[\begin{array}{ccc}2&\\6.66&\\\end{array}\right]\)

Given data,

Let u [-16 18 10] and A [2 -3 1 -4 5 1]

u in the plane in set of real numbers rℝcubed3 spanned by the columns of A,

So,

We can write,

u = \(\left[\begin{array}{ccc}-16&\\18&\\10&\end{array}\right]\) and A = \(\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right]\)

Then,

AX = b

w = \(\left[\begin{array}{ccc}2&-3&-16\\1&-4&18\\5&1&10\end{array}\right]\)

A = \(\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right]\)

null A = \(\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right]\)

\(\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right]\)    \(\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right]\)= \(\left[\begin{array}{ccc}0&\\0&\\0&\end{array}\right]\)

2\(x_{1}\) - 3\(x_{2}\) = 0

\(x_{1}\) - 4\(x_{2}\) = 0

5\(x_{1}\) + 1\(x_{2}\) = 0

We can solve the equations,

2\(x_{1}\) - 3\(x_{2}\) = 0

\(x_{1}\) - 4\(x_{2}\) = 0

-----------------------

\(x_{1}\) - 7\(x_{2}\) = 0

\(x_{1}\) = 7\(x_{2}\)

We can substitute \(x_{1}\) values,

2\(x_{1}\) - 3\(x_{2}\) = 0

2*7\(x_{2}\) - 3\(x_{2}\) = 0

\(14x_{2}\) - 3\(x_{2}\) = 0

11\(x_{2}\) = 0

\(x_{2}\) = 0

\(\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right]\)    \(\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right]\)= = \(\left[\begin{array}{ccc}-16&\\18&\\10&\end{array}\right]\)

2\(x_{1}\) - 3\(x_{2}\) = -16

\(x_{1}\) - 4\(x_{2}\) = 18

5\(x_{1}\) + 1\(x_{2}\) = 10

We can solve the matrix equations,

2\(x_{1}\) - 3\(x_{2}\) = -16

\(x_{1}\) - 4\(x_{2}\) = 18

--------------------------

\(x_{1}\) - 7\(x_{2}\) = 2

\(x_{1}\) = 2 + 7\(x_{2}\)

\(x_{1}\) = 2 + 7(0)

\(x_{1}\) = 2

2\(x_{1}\) - 3\(x_{2}\) = -16

2*2 - 3\(x_{2}\) = -16

4 - 3\(x_{2}\) = -16

- 3\(x_{2}\) = -16 - 4

- 3\(x_{2}\) = -20

3\(x_{2}\) = 20

\(x_{2}\) = 20/3

\(x_{2}\) = 6.66

Therefore,

u in the plane in set of real numbers rℝcubed3 spanned by the columns, then the one solution matrix is,   \(\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right]\) = \(\left[\begin{array}{ccc}2&\\6.66&\\\end{array}\right]\)

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The probability that a randomly selected student scored between 70 and 84 is 0.8351

Probability is simply how likely something is to happen.

Whenever we’re unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are. The analysis of events governed by probability is called statistics.

given that:

mean = 80

standard deviation = 4

now we need to find the probability of students scored between 70 and 84

P(70<X<84) = P(X<84) - P(X>70)

                   = P(Z<(84-80)/4)-P(Z>(70-80)/4)

                   =P(Z<1) - P(Z>-2.5)

                   = 0.8413-0.0062

                   = 0.8351

the probability that a randomly selected student scored between 70 and 84 is 0.8351

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For the observed test statistics provided, the bounds on the P-value can be calculated as follows:

a. The bounds on the P-value for t0 = 2.30 are approximately 0.020 < P-value < 0.050.

b. The bounds on the P-value for t0 = 3.41 are P-value < 0.010.

c. The bounds on the P-value for t0 = 1.95 are approximately 0.050 < P-value < 0.100.

d. The bounds on the P-value for t0 = -2.45 are approximately 0.010 < P-value < 0.020.

To find the bounds on the P-value for the observed values of the test statistic, we need to refer to the t-distribution with (n1 + n2 - 2) degrees of freedom.

Step 1: Determine the degrees of freedom:

The degrees of freedom are calculated as (n1 + n2 - 2) = (12 + 12 - 2) = 22.

Step 2: Consult the t-distribution table or use statistical software:

Using the t-distribution table or statistical software, we can find the corresponding P-values for the observed test statistics.

a. t0 = 2.30:

The bounds on the P-value for t0 = 2.30 are approximately 0.020 < P-value < 0.050.

b. t0 = 3.41:

The bounds on the P-value for t0 = 3.41 are P-value < 0.010.

c. t0 = 1.95:

The bounds on the P-value for t0 = 1.95 are approximately 0.050 < P-value < 0.100.

d. t0 = -2.45:

The bounds on the P-value for t0 = -2.45 are approximately 0.010 < P-value < 0.020.

Therefore, for the given observed test statistics, these are the bounds on the P-value based on the assumptions provided.

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Answer:

I don't know how to explain this cause i can't like draw on the pic but I'll try my best.

The point G would be at the coordinate (6, 8) (6 on the x-axis and 8 on the y)

The point H is on (7,8)

The point F is on (6,3)

The point E is on (7, 3)

Step-by-step explanation:

The appropriate measure of variability for the given data is the IQR, and its value is 16.

Based on the given stem-and-leaf plot, which represents the scores earned in a flower-growing competition, we can determine the appropriate measure of variability for the data.

The stem-and-leaf plot shows the individual scores, and to measure the spread or variability of the data, we have two commonly used measures: the range and the interquartile range (IQR).

The range is calculated by subtracting the smallest value from the largest value in the dataset. In this case, the smallest value is 20, and the largest value is 65. Therefore, the range is 65 - 20 = 45.

The interquartile range (IQR) is a measure of the spread of the middle 50% of the data. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). Looking at the stem-and-leaf plot, we can identify the quartiles. The first quartile (Q1) is 25, and the third quartile (Q3) is 41. Therefore, the IQR is 41 - 25 = 16.

In this case, both the range and the IQR are measures of variability, but the IQR is generally preferred when there are potential outliers in the data. It focuses on the central portion of the dataset and is less affected by extreme values. Therefore, the appropriate measure of variability for the given data is the IQR, and its value is 16.

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Answer:

118.3

Step-by-step explanation:

The formula for the area is a triangle is base*height/2

Area = 18.2*13/2 = 118.3

Answer:

118.3

1/2b×h

1/2(13)x18.2

6.5×18.2

118.3m^2

The perfect square equation is f(x) = (x + 7/2)^2 - 9/4

The equation of the function is given as

f(x) = x^2 + 7x + 10

Rewrite the equation as

x^2 + 7x + 10 = 0

Subtract 10 from both sides of the equation

So, we have

x^2 + 7x = -10

-----------------------------------------------------------------------

Take the coefficient of x

k = 7

Divide by 2

k/2 = 7/2

Square both sides

(k/2) = 49/4

-----------------------------------------------------------------------

Add 49/4 to both sides of the equation

So, we have

x^2 + 7x + 49/4 = -10 + 49/4

Express as a perfect square

So, we have

(x + 7/2)^2 = -10 + 49/4

Evaluate the sum

So, we have

(x + 7/2)^2 = 9/4

This gives

(x + 7/2)^2 - 9/4 = 0

So, we have

f(x) = (x + 7/2)^2 - 9/4

Hence, the perfect square equation is f(x) = (x + 7/2)^2 - 9/4

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Therefore, the width of the box is approximately 0.529 angstroms.

The energy of an electron in a rigid box is given by the equation:

E = (n^2 * h^2) / (8mL^2)

where n is the quantum number, h is Planck's constant, m is the mass of the electron, and L is the width of the box.

The energy difference between the ground state (n = 1) and the excited state (n = 2) is given by:

ΔE = E2 - E1

= [(2^2 * h^2) / (8mL^2)] - [(1^2 * h^2) / (8mL^2)]

= (3/8) * (h^2 / mL^2)

We know that the photon absorbed has an energy of 9 eV. We can convert this to joules using the conversion factor 1 eV = 1.602 x 10^-19 J:

9 eV * (1.602 x 10^-19 J/eV) = 1.443 x 10^-18 J

We can set this energy equal to the energy difference between the ground and excited states and solve for L:

(3/8) * (h^2 / mL^2) = 1.443 x 10^-18 J

L^2 = (3 * h^2) / (8m * 1.443 x 10^-18 J)

Taking the square root of both sides, we get:

L = sqrt[(3 * h^2) / (8m * 1.443 x 10^-18 J)]

Substituting the values for h and m (Planck's constant and the mass of an electron) and simplifying, we get:

L = 0.529 Å

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Answer:

Step 3:

Explanation:

Step 3 is incorrect because we actually need to divide both sides by -8

but instead, we have divided the equation by -8x.

p(10) is 20%

Probability is a measure of the likelihood of an event to occur.

Probability measures the chance of an event happening.

Therefore, the probability of getting a 10 can be calculated as follows:

The cards are five in number. The cards are numbered 6, 7, 8, 9 and 10.

Therefore,

p(10) = 1 / 5

Hence,

p(10) =  1 / 5 × 100

p(10) = 100 / 5

p(10) =  20%

Therefore, p(10) is 20%

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The cοrrect answer is the average temperature in Tampa, Flοrida, during July, and the number οf typοs fοund οn a randοmly selected page οf this test bank.

The number οf custοmers whο visit a department stοre between 10:00 a.m. and 11:00 a.m. οn Mοndays and the number οf students whο will get financial assistance in a grοup οf 50 randοmly selected students are discrete randοm variables because they can οnly take οn specific, cοuntable values (e.g., 0 custοmers, 1 custοmer, 2 custοmers, etc.).

On the οther hand, the average temperature in Tampa, Flοrida, during July can be measured as a cοntinuοus quantity (e.g., 80.2 degrees Fahrenheit), sο it can be represented by a cοntinuοus randοm variable.

Similarly, the number οf typοs fοund οn a randοmly selected page οf this test bank can be measured as a cοntinuοus quantity (e.g., 0.5 typοs, 1.2 typοs, etc.) if we cοnsider fractiοnal οr decimal values, sο it can alsο be represented by a cοntinuοus randοm variable.

Therefοre, the cοrrect answer is the average temperature in Tampa, Flοrida, during July, and the number οf typοs fοund οn a randοmly selected page οf this test bank.

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The average number of trees planted by students at Arlington High School decreased by 20% when comparing the first planting session (5 trees per participant) to the upcoming session (4 trees per participant).

To calculate the percent of decrease, we can use the following formula:

Percent decrease = ((Initial value - Final value) / Initial value) * 100

For the first planting session, the initial value is 5 trees per participant, and for the upcoming session, the final value is 4 trees per participant. Plugging these values into the formula:

Percent decrease = ((5 - 4) / 5) * 100 = (1 / 5) * 100 = 20%

Therefore, the percent of decrease in the average number of trees planted is 20%. This means that the average number of trees planted per participant decreased by 20% from the first planting session to the upcoming session

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Answer:

x = 3

Step-by-step explanation:

This is an isosceles triangle.  Two angles (D and F) are equal because the sides opposite them are equal (or vice versa).

Thus, side DE = side EF, or

12x - 8 = 4x + 16

Combining like terms:  8x = 24

Thus, x = 24/8 = 3

x = 3

The number of ways to select a simple random sample of size 5 from a population of 7 children in a family is equal to 21ways.

As given in the question,

Number of children in the family 'n' = 7

Number of simple random sample of size  = 5  ( without replacement )

Number of ways to select the children defines a population

= ⁷C₅

= ( 7! ) / ( 7 - 5 )! ( 5! )

= ( 7 × 6 × 5! )/ ( 2! ) ( 5! )

= 7 × 3

= 21 ways

Therefore, the number of ways to select children of simple random sample of size 5 is equal to 21ways.

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The points would you find on the graph for |x| +1 < 3 are -1, 0 and 1

The inequality is given as:

|x| + 1 < 3

Subtract 1 from both sides

|x| < 2

This means that the absolute value of x is less than 2

From the list of options, the true values are -1, 0 and 1.

Because their absolute values are less than 2

Hence, the points would you find on the graph for |x| +1 < 3 are -1, 0 and 1

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Answer:

8

Step-by-step explanation:

absolute value of z-18 = z + 18

z + 18

-15

______

z + 3

z + 3 - 3 = -5 - 3

z = -8

|z| = |-8|

z = 8

hope this helped ^^

No, it is not possible for each person to shake hands with exactly 3 other people in a group of 25.

In order for each person to shake hands with exactly 3 other people, the total number of handshakes would need to be (25 * 3) / 2 = 37.5, which is not a whole number.

Therefore, it is not possible for each person in a group of 25 people to shake hands with exactly 3 other people.

This is because in order for each person to shake hands with 3 others, there would need to be a total of 75 handshakes (since each handshake involves 2 people). However, in a group of 25 people, there are only 24 possible handshakes for each person to make (since they cannot shake hands with themselves), resulting in a maximum of 24 handshakes per person and a total maximum of 600 handshakes for the entire group. Therefore, it is mathematically impossible for each person to shake hands with exactly 3 other people.

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Answer:

850

Step-by-step explanation:

500 times 0.7 plus 500

Answer:

AB = 47 (answers may vary)

Step-by-step explanation:

BC = 35

AC = 52

C, in fact, can be any number you choose less than 35;

For example,

C= 20

35 - 20 = 15

B = 15

52 - 20 = 32

A = 32

AB = 32 + 15 = 47

Answer:

80

Step-by-step explanation:

48/60 = 4/5

The four levels of measurement for which data can be qualitative are nominal, ordinal, interval, and ratio. Qualitative data are pieces of information that describe the quality or characteristics of an object or phenomenon.

The levels of measurement are based on the degree of variation and consistency in the measured data, and they influence the statistical methods that can be used to analyze the data.

1. Nominal level of measurement: Nominal data refers to categorical data that are labeled using a set of symbols or names that do not have any intrinsic order or hierarchy.

The symbols or names used to label the categories are merely identifiers that can be used to differentiate between different groups or objects.

For example, blood type, gender, and color can be nominal data.

2. Ordinal level of measurementOrdinal data are qualitative or categorical data that can be arranged in an ordered sequence based on a specific characteristic or attribute.

This implies that the data have a clear ranking system in which they can be arranged based on their level of severity, frequency, or magnitude, but the differences between the values cannot be measured.

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Answer:

SLOPE=7 Y-INTERCEPT=0

Step-by-step explanation:

First you find the rise over run. In this case it is 14/2 (it is hard to see, but that is what it looks like.)

Then divide 14/2 which equals 7.

Therefore the slope is 7.

The line intersects the y-intercept at the point 0.

So therefore the answer is 0.

The equation for this line would be y=7x+0 or just y=7x

This would mean that the graph is proportionate.

Hope this helps!