what is 37 divided by 3511

Answer:

84.375%

Step-by-step explanation:

2.16 divided by 2.56 is 0.84375

The minimum value of f(x,y) subject to the constraint x²/81 + y²/49 ≤ 1.9 is approximately -25.862, and there is no maximum value.

To find the minimum and maximum of the function f(x,y) = 2x² + 3y² + 8x - 18y + 11 subject to the constraint x²/81 + y²/49 ≤ 1.9, we can use the method of Lagrange multipliers.

First, we write down the Lagrangian function L(x,y,λ) as follows

L(x,y,λ) = f(x,y) - λ(g(x,y) - c)

where g(x,y) = x²/81 + y²/49 and c = 1.9 are the constraint function and constant, respectively. λ is the Lagrange multiplier.

Taking the partial derivatives of L with respect to x, y, and λ and setting them equal to zero, we get the following system of equation

4x + 8 - (2/81)λx = 0

6y - 18 - (2/49)λy = 0

x²/81 + y²/49 - 1.9 = 0

Solving for x and y in terms of λ using the first two equations and substituting into the third equation, we obtain

(16/6561)λ² - 19/6561 = 0

Solving for λ, we get λ = ±√(19/16)×81.

Substituting λ into the first two equations, we can solve for x and y, respectively

x = (-4 ± 6√19)/3

y = (2 ± 3√19)/3

Note that only one of these solutions satisfies the constraint x²/81 + y²/49 ≤ 1.9, namely

x = (-4 + 6√19)/3

y = (2 - 3√19)/3

Substituting x and y into the function f(x,y), we get

f((-4 + 6√19)/3, (2 - 3√19)/3) = 2((-4 + 6√19)/3)² + 3((2 - 3√19)/3)² + 8((-4 + 6√19)/3) - 18((2 - 3√19)/3) + 11

which simplifies to

f((-4 + 6√19)/3, (2 - 3√19)/3) ≈ -25.862

Thus, the minimum value of f(x,y) subject to the constraint x²/81 + y²/49 ≤ 1.9 is approximately -25.862.

To find the maximum value, we need to evaluate the function at the other critical point

x = (-4 - 6√19)/3

y = (2 + 3√19)/3

However, this point does not satisfy the constraint x²/81 + y²/49 ≤ 1.9, so it is not a valid solution.

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The given question is incomplete, the complete question is:

Find the minimum and maximum of f(x, y) = 2x² + 3y² + 8x - 18y + 11 on x²/81 + y²/49 ≤ 1.9

Comparison of Enrollments in Vocational and Theoretical Courses in India

States: Uttar Pradesh and Maharashtra

In Uttar Pradesh, there were more male enrollments in vocational courses than female enrollments in all years. The difference was more pronounced in the early years, but it has narrowed over time. In 2010, there were 2.5 times more male enrollments in vocational courses than female enrollments. By 2020, the ratio had decreased to 1.75.

In Maharashtra, the difference between male and female enrollments in vocational courses was smaller than in Uttar Pradesh. In 2010, there were 1.5 times more male enrollments in vocational courses than female enrollments. By 2020, the ratio had decreased to 1.25.

Age

In Uttar Pradesh, the majority of enrollments in vocational courses were from the 15-29 age group. In Maharashtra, the majority of enrollments in vocational courses were also from the 15-29 age group.

The data also shows that there are some differences in the enrollment patterns between the two states. In Uttar Pradesh, the majority of enrollments are from the 15-29 age group, and the most popular vocational courses are in the areas of IT, engineering, and healthcare. In Maharashtra, the majority of enrollments are also from the 15-29 age group, but the most popular vocational courses are in the areas of IT, hospitality, and manufacturing.

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Answer: x would be 36°

Step-by-step explanation:

Answer:

m<1 = 108°

m<2 = 72°

Step-by-step explanation:

I hope it helped u:)

Answer:

The answer is B. 9.7

Step-by-step explanation:

sin 14°=x/40

=> sin 14° X 40 = x

∴ x = 9.67≈ 9.7

Answer:

Area of panel (Uncovered) = 140 cm²

Step-by-step explanation:

Given:

Length of picture = 40 cm

Width of picture = 28 cm

Length of picture with border = 40 + 1 + 1 = 42 cm

Width of picture border = 28 + 1 + 1 = 30 cm

Find:

Area of panel (Uncovered)

Computation:

Area of panel (Uncovered) = Area of panel - Area of picture

Area of panel (Uncovered) = (42 x 30) - (40 x 28)

Area of panel (Uncovered) = 140 cm²

The least expensive computer after the 20% discount would be $400.

To calculate the price of the least expensive computer after the 20% discount, we need to find 20% of the original price and subtract it from the original price.

Let's assume the original price of the least expensive computer is x. The discount of 20% can be calculated as 0.20 * x. To find the discounted price, we subtract the discount from the original price: x - 0.20 * x = 0.80 * x.

Since we know that the cost of the least expensive computer ranges from $500 to $1000, we can substitute x with $500 and calculate the discounted price: 0.80 * $500 = $400. Therefore, the least expensive computer after the 20% discount would be $400.

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Answer:

the correct answer is

B . 9

9 X 9 = 81

Step-by-step explanation:

Answer:

OPTION(B):Square root of 81 is 9

C: True. The accounting equation, which is the foundation of all accounting principles, is based on the concept that for every debit entry, there must be an equal credit entry. This principle is reflected in T-accounts, which are used to track the financial transactions of a business.

T-accounts are a visual representation of the accounting equation, where debits are recorded on the left side of the T-account and credits are recorded on the right side. The sum of the debits and credits for each account is calculated and displayed at the bottom of the T-account.

If the sum of debits is not equal to the sum of credits, it indicates that an error has occurred in the recording of financial transactions. This is known as an unbalanced entry, and it must be corrected before the financial statements can be prepared accurately.

Therefore, it is always true that across all T-accounts, the sum of debits must equal the sum of credits. This principle ensures that the accounting records are accurate and reliable, providing stakeholders with a clear and complete picture of a company's financial position.

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According to the information we can infer that the greater area is the striped region.

To calculate what is the greater area we have to calculate the area of each segment of the target. Fist we can calculate the area of the striped region.

Then we have to calculate the area of the shaded region with the following procedure:

According to the above, the striped area has the greater area.

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The length of the measure of YZ is 80cm

Perpendicular lines are lines that are at angle 90 degrees to each other. From the given diagram;

WX = 82cm

Required

Length. of YZ

Using the pythagoras theorem

YV = VZ = √41²-9²

YV = VZ = √1600

YV = VZ = 40

Since YZ = YV + VZ

YZ = 40cm + 40cm

YZ= 80cm

Hence the length of the measure of YZ is 80cm

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The sum of -5.5 and 3.7 is -1.8.

Teachers can use a collection of exercises called the Interactive Number Line in which students move a marker down a number line to indicate their responses. With the help of the Interactive Number Line, students may practice various crucial concepts from the primary school arithmetic curriculum.

Zero, a positive natural number, or a negative integer denoted by a minus sign are all examples of integers. The inverse additives of the equivalent positive numbers are the negative numbers. The set of integers is frequently represented in mathematical notation by the boldface Z or blackboard bold mathbb Z.

To find the sum of -5.5 and 3.7 on a number line, draw a number line, and label it with tick marks for the integers.

So, the sum of -5.5 and 3.7 is -1.8.

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Answer: 1.8

Step-by-step explanation:

Answer:

The net tax refund of Harry and Helen is $555.

Step-by-step explanation:

The net tax refund of Harry and Helen is $555.

The marginal tax rate is the tax rate imposed on the additional dollar. In general, as a taxpayer's income rises, so does his or her marginal tax rate. It is also known as progressive taxation since the taxpayer with the highest income pays the highest level of income tax.

As, To calculate their due tax liability, the total withheld amount for the year will be subtracted from the overall tax liability.

So, Due Tax Liability

= Total tax Liability - Total withheld Amount

= 9169 - (187 x 52)

= $55.

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Answer:

v = 66/7

Step-by-step explanation:

Step 1: Write equation

-7v + 3 = -63

Step 2: Solve for v

Subtract 3 on both sides: -7v = -66

Divide both sides by -7: v = 66/7

Step 3: Check

Plug in x to verify if it's a solution.

-7(66/7) + 3 = -63

-66 + 3 = -63

-63 = -63

Answer:

Step-by-step explanation:

-7v+3=-63

-7v=-63-3

-7v=-66

-7v-7=-66÷-7

V=9.4

Answer: D) 15.7

Step-by-step explanation:

Start with the formula C=2 πr

Then solve for r r=C2π = 98.62·π = 15.69(7)204

The radius of the circle is 15.7 mm.

The route or boundary that encircles any shape in mathematics is defined by the shape's circumference.

The measurement of the circle's perimeter, also known as its circumference, is called the circle's boundary. The region a circle occupies is determined by its area. The length of a straight line drawn from the centre of a circle equals the diameter of that circle.

We have,

The circumference of Circle = 2πr

Also, The circumference of a circle is 98.596 millimeters.

So, circumference of Circle = 2πr

98.596 = 2πr

98.596 = 6.28r

r= 98. 596 / 6.28

r = 15.7 mm

Thus, the radius is 15.7 mm.

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a. To solve the given initial value problem (IVP) using Laplace transforms, we can apply the Laplace transform to the differential equation and solve for the Laplace transform of the solution.

Taking the Laplace transform of the equation y'(t) + y(t) = (1-3), we have:

sY(s) - y(0) + Y(s) = (1-3)/s

Substituting the initial condition y(0) = 2, we have:

sY(s) - 2 + Y(s) = (1-3)/s

Now, rearranging the equation to solve for Y(s), we get:

Y(s) = (1-3)/s + 2/(s+1)

Simplifying further, we have:

Y(s) = (-2)/s + 2/(s+1)

b. To obtain the solution y(t), we can apply the inverse Laplace transform to Y(s) obtained in part (a).

Taking the inverse Laplace transform, we have:

y(t) = -2 + 2e^(-t)

Therefore, the solution to the given initial value problem is y(t) = -2 + 2e^(-t).

Explanation:

In the first part, we applied the Laplace transform to the differential equation and obtained the equation in terms of the Laplace transform Y(s). By rearranging the equation, we solved for Y(s) in terms of the given Laplace transform expression.

In the second part, we applied the inverse Laplace transform to Y(s) to obtain the solution y(t). The inverse Laplace transform of -2/s gives us a constant term of -2, while the inverse Laplace transform of 2/(s+1) gives us the exponential term 2e^(-t).

Therefore, the solution y(t) = -2 + 2e^(-t) satisfies the differential equation y'(t) + y(t) = (1-3) and the initial condition y(0) = 2.

a. To find the auxiliary equation for the given differential equation y'' - 4y' + 3y' - 12y = 0, we can substitute y = e^(rt) into the equation, where r is an unknown constant.

Substituting y = e^(rt) into the differential equation, we get:

r²e^(rt) - 4re^(rt) + 3e^(rt) - 12e^(rt) = 0

Factoring out e^(rt), we have:

e^(rt)(r² - 4r + 3 - 12) = 0

Simplifying further, we obtain:

e^(rt)(r² - 4r - 9) = 0

Therefore, the auxiliary equation for the given differential equation is r² - 4r - 9 = 0.

b. The auxiliary equation plays a crucial role in finding the solutions to the given differential equation. By solving the auxiliary equation, we can determine the types of solutions and their behavior.

The auxiliary equation for the given differential equation y'' - 4y' + 3y' - 12y = 0 is r² - 4r - 9 = 0. This is a quadratic equation in terms of the unknown constant r.

To solve the quadratic equation, we can use various methods such as factoring, completing the square, or using the quadratic formula. In this case, the quadratic equation does not factor easily, so we can use the quadratic formula:

r = (-(-4) ± √((-4)² - 4(1)(-9))) / (2(1))

Simplifying further, we have:

r = (4 ± √(16 + 36)) / 2

r = (4 ± √52) / 2

r = (4 ± 2√13) / 2

r = 2 ± √13

Therefore, the solutions to the auxiliary equation are r₁ = 2 + √13 and r₂ = 2 - √13.

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1/2 + 2/2 = 3/2

............................

For every integer n > 7, we have shown that there exist positive integers a' and b' such that n = 2a' + 3b'.

An integer is a mathematical concept used to represent whole numbers, both positive and negative, without any fractional or decimal parts. Integers include zero (0) and the positive and negative counting numbers (1, 2, 3, ... and -1, -2, -3, ...). Integers can be expressed as numbers on the number line that extend infinitely in both the positive and negative directions.

To prove that for every integer n > 7, there exist positive integers a and b such that n = 2a + 3b, we can use the concept of the Chicken McNugget theorem, also known as the Frobenius coin problem.

The Chicken McNugget theorem states that for any two relatively prime positive integers a and b, the largest integer that cannot be expressed as a non-negative integer combination of a and b is ab - a - b.

In our case, a = 2 and b = 3 are relatively prime since their greatest common divisor (GCD) is 1.

Let's consider the number 6. We can express 6 as 2 * 1 + 3 * 2, so it is possible to represent 6 using positive integers a and b.

Now, let's consider any number n > 7. We know that n - 6 is a positive integer greater than or equal to 2. Therefore, n - 6 can be expressed as a non-negative integer combination of 2 and 3, using the Chicken McNugget theorem.

So, n - 6 = 2a + 3b, where a and b are positive integers. Adding 2 * 1 + 3 * 2 to both sides of the equation, we get:

n = 2a + 3b + 6

We can see that by choosing a = a + 1 and b = b + 2, we can rewrite the equation as:

n = 2(a + 1) + 3(b + 2) = 2a' + 3b',

where a' and b' are positive integers.

Therefore, for every integer n > 7, we have shown that there exist positive integers a' and b' such that n = 2a' + 3b'.

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The measure of angle y is 52.81 degrees.

In this geometry problem, we are asked to determine the measure of angle y. After performing the necessary calculations, we find that the measure of angle y is 52.81 degrees. This answer has been rounded to the nearest hundredth.

To arrive at this result, we likely had access to a diagram or description of the given angles and their relationships. By applying the appropriate geometric principles, such as the properties of supplementary or complementary angles, we were able to identify the relevant information needed to find the measure of angle y.

It is important to note that without a specific diagram or further context, it is challenging to provide a detailed explanation of the specific steps involved in solving this problem. The answer of 52.81 degrees represents the final outcome based on the given information, calculations, and rounding instructions.

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we need to know how many students each circle represents to calculate how many chose chicken Maybe try 4 3/4 but im not quite sure

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

24 students said veggie and there is 6 circles in the pictogram for veggie so we can divide 24 by 6 to find the value of one circle.

\(\frac{24}{6} = 4\)

Now we have the value of a circle we can figure out how many students chose chicken.

There are 4 full circles which is \(4*4 = 16\)

Finally, there is a 3/4 of a circle which is \(4*\frac{3}{4} = 3\)

Then we add all the values together to find the number of students who chose chicken.

16+3=19

Hope this helps!

Brainliest is much appreciated!

Answer:

It is not proportional because it does not pass through the origin (0,0)

Answer:

45.00%

Step-by-step explanation:

The total answers count 40 - it's 100%, so we to get a 1% value, divide 40 by 100 to get 0.40. Next, calculate the percentage of 18: divide 18 by 1% value (0.40), and you get 45.00% - it's your percentage grade.

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Answer:

4

Step-by-step explanation:

The amount of milk remaining is equivalent to 4 gallons.

Given is that Jansen family has 2 1/2 gallons of milk. Each of the 3 family members drinks 1 1/2 cups of milk a day.

1 gallon = 16 cups

2\(\frac{1}{2}\) gallons = 2\(\frac{1}{2}\) x 16 = 5/2 x 16 = 5 x 8 = 40 cups

Now -

Total milk consumed in 1 day = 3 x 3/2 cups = 9/2 cups = 4.5 cups.

In 8 days, the amount of milk consumed will be = 4.5 x 8 = 36 gallons.

Remaining amount = 40 - 36 = 4 gallons.

Therefore, the amount of milk remaining is equivalent to 4 gallons.

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Using concepts of proportional relationships, it is found that the solution of the system is (0,0).

\(y = kx\)

In this problem, the system consists of two different proportional relationships, that is:

\(y = k_1x\)

\(y = k_2x\)

\(k_1 \neq k_2\)

Hence, equaling both equations for y, we have that:

\(k_1x = k_2x\)

Simplifying by x:

\(k_1 = k_2\)

Which is never true, hence, the only solution is (0,0).

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Answer:

boys=112

Step-by-step explanation:

g+b=208

6b=7g

6b=7(208-b)

6b=1456-7b

6b+7b=1456

113b=1456

divide both of them by 13 it gives 112 boys

Answer

it's 1 9/20. hope this helps :)

Answer:

\({ \tt{ {4x}^{6} - {16x}^{2} = {(2x {}^{3}) }^{2} - {(4x)}^{2} }} \\ \)

• from difference of squares:

\({ \boxed{ \rm{( {a}^{2} - {b}^{2} ) = (a - b)(a + b)}}}\)

• a → 2x³

• b → 4x

\({ \underline{ \underline{ \tt{ = \: (2 {x}^{3} - 4x)(2 {x}^{3} + 4x) \: }}}}\)

Answer:

rectangular garden

Step-by-step explanation:

the best estimate of the half-life, combining the two results, is approximately 13.7421 days with an uncertainty of approximately 1.3772 days.

To determine the best estimate of the half-life by combining the two results, we can use the weighted average method. The weights assigned to each measurement are inversely proportional to the squares of their uncertainties. Here's how to calculate the combined result:

Step 1: Calculate the weights for each measurement.

  w1 = 1/σ1^2

  w2 = 1/σ2^2

  Where σ1 and σ2 are the uncertainties associated with each measurement.

Step 2: Calculate the weighted values.

  w1 * t1 = w1 * (15.5 days)

  w2 * t2 = w2 * (16.2 days)

Step 3: Calculate the sum of the weights.

  W = w1 + w2

Step 4: Calculate the weighted average.

  T = (w1 * t1 + w2 * t2) / W

Step 5: Calculate the combined uncertainty.

  σ = √(1 / W)

The best estimate of the half-life is given by the value of T, and the combined uncertainty is given by the value of σ.

Let's calculate the best estimate using the given values:

For the first measurement:

σ1 = 2.3 days

For the second measurement:

σ2 = 1.5 days

Step 1:

w1 = 1/σ1^2 = 1/(2.3^2) ≈ 0.1949

w2 = 1/σ2^2 = 1/(1.5^2) ≈ 0.4444

Step 2:

w1 * t1 ≈ 0.1949 * 15.5 ≈ 3.0195

w2 * t2 ≈ 0.4444 * 16.2 ≈ 7.1993

Step 3:

W = w1 + w2 ≈ 0.1949 + 0.4444 ≈ 0.6393

Step 4:

T = (w1 * t1 + w2 * t2) / W ≈ (3.0195 + 7.1993) / 0.6393 ≈ 13.7421 days

Step 5:

σ = √(1 / W) ≈ √(1 / 0.6393) ≈ 1.3772 days

Therefore, the best estimate of the half-life, combining the two results, is approximately 13.7421 days with an uncertainty of approximately 1.3772 days.

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the equation of the tangent line is: y = -25x - 16TTo find the slope (m) of the tangent line to the curve y = √(6 - 75x) at the point (-1, 9), we first need to find the derivative of the curve with respect to x.

Let's differentiate y with respect to x using the chain rule:

dy/dx = d(√(6 - 75x))/dx = (1/2)(6 - 75x)^(-1/2) * (-75)

Now, we can find the slope of the tangent line at the point (-1, 9) by evaluating the derivative at x = -1:

m = (1/2)(6 - 75(-1))^(-1/2) * (-75) = (1/2)(81)^(-1/2) * (-75)

m = -25

Now we have the slope of the tangent line, m = -25. To find the equation of the tangent line, we can use the point-slope form of a linear equation: y - y1 = m(x - x1). We have the point (-1, 9) and the slope -25, so:

y - 9 = -25(x - (-1))

Simplify the equation:

y - 9 = -25(x + 1)

y = -25x - 25 + 9

Therefore, the equation of the tangent line is:

y = -25x - 16

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