Find the volume of the cylinder given: r = 5 and h = 7.
Use 3.14 as the value for π.
a 769.3 cubic units
b 549.5 cubic units
c 183.17 cubic units
d 219.8 cubic units
(GIVING BRAINLIEST!!!!!!)
An equilateral triangle as a side of 35 cm what is the distance around the triangle
Answer:
Step-by-step explanation:
To find the perimeter of an equilateral triangle is equalled to 3s.
35 x 3
105
Collect the information from top 5 states in India which have the highest literacy rate as on 1st May 2021.
Answer:
Step-by-step explanation:
There are many states in India, of course not everyone has the same literacy rates as some are higher than the others, while some are lower than the others. All in all, the literacy of states in India can be ranked as listed below, from the highest to the lowest.
Kerala
Delhi
Uttarakhand
Himachal Pradesh
Assam
I could really use some help !
Finding the numeric value for the given function, we have that:
a) The angle of elevation in the first day of summer is of 87.5º and of winter is of 40.9º.
b) The angle of elevation in the first day of summer is of 49.5º and of winter is of 2.9º.
c) Both cities have the same change in the angle of elevation.
How to find the numeric value of a function/expression?To find the numeric value of a function, we replace each instance of the variable by the desired value. This also is true for a function of multiple variables, in which each value is replaced by it's attributed value.
For this problem, the function for the angle of inclination is given as follows:
A(L,N) = 90 - L - 23.5cos[360(N + 10)/365]
In which:
L is the latitude.N is the day of the year.For item a, we have that the latitude is of L = 26, hence on the first day of summer, the angle is given by:
A(26, 172) = 90 - 26 - 23.5cos(360 x 182/365) = 90 - 26 + 23.5 = 87.5º.
On the first day of winter, the angle is given by:
A(26, 355) = 90 - 26 - 23.5cos(360 x 355/365) = 90 - 26 - 23.1 = 40.9º.
The angle of elevation in the first day of summer is of 87.5º and of winter is of 40.9º.
For item b, we have that the latitude is of L = 64, hence on the first day of summer, the angle is given by:
A(26, 172) = 90 - 64 - 23.5cos(360 x 182/365) = 90 - 64 + 23.5 = 49.5º.
On the first day of winter, the angle is given by:
A(26, 355) = 90 - 64 - 23.5cos(360 x 355/365) = 90 - 64 - 23.1 = 2.9º.
The angle of elevation in the first day of summer is of 49.5º and of winter is of 2.9º.
The changes are given as follows:
Brownsville: 87.5 - 40.9 = 46.6º.Nome: 49.5 - 2.9 = 46.6º.Both cities have the same change in the angle of elevation.
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solve each inequality. 7^(3x-1)>=21
Therefore , the solution of the given problem of inequality comes out to be x >= 0.818.
What is an inequality?Although there isn't an equal symbol in algebra, the difference can be expressed by a partner or collection of numbers. Equity usually comes after equilibrium. When ideals continue to diverge, expression inequality results. Fairness and disparity are not the same. We used our most widely used symbol even though pieces usually aren't connected or near to one another. (). Any variation, no matter how slight, may be utilized to assess value.
Here,
Using logarithms, we can eliminate this inequality:
=> \(7^{3x-1}\) >= 21
Using base 7, take the logarithm of both sides:
=> 7(3x-1) log_7 >= log_7(21)
=> (3x-1) >= log_7(21)
To both ends, add one:
=> 3x >= log_7(21) + 1
multiply both parts by three.
=> x >= (1/3) * (log_7(21) + 1)
=> x >= 0.818
The following is how the disparity can be resolved:
=> x >= 0.818.
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Consider the following linear programming problem: Maximise profit = 2X₁ - X₂ + 2X3 Subject to: 2X₁ + X₂ + 0x3 ≤10 X₁ + 2X₂ - 2X3 ≤ 20 0X₁ + X₂ + 2X3 ≤ 5 X₁ ,X2, X3 > 0 Change the objective function and constraints to simplex format by including the necessary additional variables.
Solve the problem above using the simplex method.
The linear programming problem is to maximize the profit function, given constraints, using the simplex method.
To convert the problem into the simplex format, we introduce slack variables to transform the inequality constraints into equalities. Let S₁, S₂, and S₃ be the slack variables for the three constraints, respectively. The converted objective function becomes Z = 2X₁ - X₂ + 2X₃ + 0S₁ + 0S₂ + 0S₃. The constraints in the simplex format are:
2X₁ + X₂ + 0X₃ + S₁ = 10,
X₁ + 2X₂ - 2X₃ + S₂ = 20,
0X₁ + X₂ + 2X₃ + S₃ = 5.
Now we can construct the initial simplex tableau:
┌─────────┬───────┬───────┬───────┬───────┬───────┬───────┬───────┐
│ Basis │ X₁ │ X₂ │ X₃ │ S₁ │ S₂ │ S₃ │ RHS │
├─────────┼───────┼───────┼───────┼───────┼───────┼───────┼───────┤
│ Z │ 2 │ -1 │ 2 │ 0 │ 0 │ 0 │ 0 │
│ S₁ │ 2 │ 1 │ 0 │ 1 │ 0 │ 0 │ 10 │
│ S₂ │ 1 │ 2 │ -2 │ 0 │ 1 │ 0 │ 20 │
│ S₃ │ 0 │ 1 │ 2 │ 0 │ 0 │ 1 │ 5 │
└─────────┴───────┴───────┴───────┴───────┴───────┴───────┴───────┘
Using the simplex method, we perform iterations until we obtain the optimal solution. In each iteration, we select the most negative coefficient in the Z row as the pivot column and apply the minimum ratio test to determine the pivot row. The pivot element is chosen as the value where the pivot column and pivot row intersect. We then perform row operations to make the pivot element equal to 1 and all other elements in the pivot column equal to 0.
After performing the necessary iterations, we reach the optimal solution with a maximum profit of 55 units. The values for the decision variables are X₁ = 0, X₂ = 5, and X₃ = 10. The final simplex tableau is:
┌─────────┬───────┬───────┬───────┬───────┬───────┬───────┬───────┐
│ Basis │ X₁ │ X₂ │ X₃ │ S₁ │ S₂ │ S₃ │
RHS │
├─────────┼───────┼───────┼───────┼───────┼───────┼───────┼───────┤
│ Z │ 0 │ 0 │ 1 │ 0.5 │ -1 │ -0.5 │ 55 │
│ X₂ │ 0.5 │ 0 │ 0 │ 0.5 │ -0.5 │ 0 │ 5 │
│ S₂ │ 0.5 │ 1 │ 0 │ -0.5 │ 0.5 │ 0 │ 15 │
│ X₃ │ -0.5 │ 0 │ 1 │ 0.5 │ 0.5 │ -0.5 │ 0 │
└─────────┴───────┴───────┴───────┴───────┴───────┴───────┴───────┘
Therefore, the optimal solution to the linear programming problem is X₁ = 0, X₂ = 5, and X₃ = 10, with a maximum profit of 55 units.
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can please solve this? x⁴+2x³-13x²+24=0
Answer:
1. x = 4
2. x = 2
3. x = -1
4. x = -3
Step-by-step explanation:
1. (x4)-(2•(x3)))-13x2)+14x)+24 = 0
2. ((x4) - 2x3) - 13x2) + 14x) + 24 = 0
3. Find roots (zeroes) of : F(x) = x4-2x3-13x2+14x+24
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 24.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,8 ,12 ,24
please someone help me to prove this.
We know that,
\(\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}\)
\(\dag\bf\:sin2A=2sinA\:cosA\)
___________________________________
Now, Let's solve !
\(\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}\)
\(\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}\)
\(\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}\)
\(\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}\)
\(\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}\)
\(\leadsto\:\bf{tan(A+B)}\)
Answer: see proof below
Step-by-step explanation:
Use the Power Reducing Identity: sin² Ф = (1 - cos 2Ф)/2
Use the Double Angle Identity: sin 2Ф = 2 sin Ф · cos Ф
Use the following Sum to Product Identities:
\(\sin x - \sin y = 2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x - \cos y = -2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\)
Proof LHS → RHS
\(\text{LHS:}\qquad \qquad \qquad \dfrac{\sin^2A-\sin^2B}{\sin A\cos A-\sin B \cos B}\)
\(\text{Power Reducing:}\qquad \dfrac{\bigg(\dfrac{1-\cos 2A}{2}\bigg)-\bigg(\dfrac{1-\cos 2B}{2}\bigg)}{\sin A \cos A-\sin B\cos B}\)
\(\text{Half-Angle:}\qquad \qquad \dfrac{\bigg(\dfrac{1-\cos 2A}{2}\bigg)-\bigg(\dfrac{1-\cos 2B}{2}\bigg)}{\dfrac{1}{2}\bigg(\sin 2A-\sin 2B\bigg)}\)
\(\text{Simplify:}\qquad \qquad \dfrac{1-\cos 2A-1+\cos 2B}{\sin 2A-\sin 2B}\\\\\\.\qquad \qquad \qquad =\dfrac{-\cos 2A+\cos 2B}{\sin 2A - \sin 2B}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 2B-\cos 2A}{\sin 2A-\sin 2B}\)
\(\text{Sum to Product:}\qquad \qquad \dfrac{-2\sin \bigg(\dfrac{2B+2A}{2}\bigg)\sin \bigg(\dfrac{2B-2A}{2}\bigg)}{2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\sin \bigg(\dfrac{2A-2B}{2}\bigg)}\)
\(\text{Simplify:}\qquad \qquad \dfrac{-2\sin (A + B)\cdot \sin (-[A - B])}{2\cos (A + B) \cdot \sin (A - B)}\)
\(\text{Co-function:}\qquad \qquad \dfrac{2\sin (A + B)\cdot \sin (A - B)}{2\cos (A + B) \cdot \sin (A - B)}\)
\(\text{Simplify:}\qquad \qquad \quad \dfrac{\cos (A+B)}{\sin (A+B)}\\\\\\.\qquad \qquad \qquad \quad =\tan (A+B)\)
LHS = RHS: tan (A + B) = tan (A + B) \(\checkmark\)
If x/y + y/x = -1 , find the value of x^3 - y^3
Answer:
0
Step-by-step explanation:
Multiplying the first equation by xy, we have ...
x^2 +y^2 = -xy
Factoring the expression of interest, we have ...
x^3 -y^3 = (x -y)(x^2 +xy +y^2)
Substituting for xy using the first expression we found, this is ...
x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0
The value of x^3 -y^3 is 0.
Which set of data contains two outliers? 113, 115, 103, 114, 109, 111, 119 141, 151, 138, 142, 149, 140, 150 99, 113, 91, 104, 109, 114, 97 101, 135, 131, 99, 138, 136, 140
Answer: 99,113,91,104,109,114,97
Step-by-step explanation:
Got 100% on the quiz :)
Answer:
D: 101, 135, 131, 99, 138, 136, 140
Step-by-step explanation:
edg2021 (do not get this confused with the question: "which set contains no outliers" hope this helps, please mark me brainliest if it does
Question2 of 25If ASTU AABC, which congruences are true by CPCTC? Check all that apply.
If triangle STU ≅ triangle ABC, then ∠T ≅ ∠B, ∠S ≅ ∠A, and segment TU ≅ Segment BC are true by CPCTC. Option A, option B, and option D are correct.
Let's understand what is the congruence of the triangle.
If all three corresponding sides are equal and all three corresponding angles are identical in measure, two triangles are said to be congruent. These triangles can be moved, rotated, flipped, and turned to look exactly the same.
CPCTC stands for corresponding parts of congruent triangles are congruent.
Let's check in the triangle STU and triangle ABC;
triangle STU ≅ triangle ABC
So,
∠S ≅ ∠A
∠T ≅ ∠B
∠U ≅ ∠C
segment ST ≅ Segment AB
segment TU ≅ Segment BC
segment SU ≅ Segment AC
Thus, if triangle STU ≅ triangle ABC, then ∠T ≅ ∠B, ∠S ≅ ∠A, and segment TU ≅ Segment BC are true by CPCTC. Option A, option B, and option D are correct.
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Lou and Jacob sold 200 pieces of jewelry. If 20% of Lou's sales were rings, and Jacob sold 35 rings, who sold more rings? How many more?
A. Jacob sold 5 more rings than Lou
B. Lou sold 5% more rings than Jacob
C. Jacob sold 5% more rings than Lou
D. Lou sold 5 more rings than Jacob
Show workk!!
Answer:
below
Step-by-step explanation
If they EACH sold 200 pieces
then Lou sold 200 x 20% = 200 x .20 = 40 rings which is 5 more than Jacob
The area of triangle DEF is 2050mm2. Work out the value of x.
Does anyone know how to get the answer?
Use both the definition of derivative and the alternate definition of derivative to find the derivativef(x)=1/1-x
Given the function
\(f(x)=\frac{1}{1-x}\)The derivative of the function will be as follows:
\(\begin{gathered} f^{\prime}(x)=\frac{(1-x)\cdot0-1\cdot(0-1)}{(1-x)^2} \\ \\ f^{\prime}(x)=\frac{1}{(1-x)^2} \end{gathered}\)Another alternate method:
the limit definition of the derivative will be as follows:
We will find f(x+h)
so,
\(f(x+h)=\frac{1}{(1-x-h)}\)We will the difference between f(x+h) and f(x)
\(\begin{gathered} f(x+h)-f(x)=\frac{1}{1-x-h}-\frac{1}{1-x} \\ f(x+h)-f(x)=\frac{(1-x)-(1-x-h)}{(1-x-h)(1-x)} \\ f(x+h)-f(x)=\frac{1-x-1+x+h}{(1-x-h)(1-x)} \\ f(x+h)-f(x)=\frac{h}{(1-x-h)(1-x)} \end{gathered}\)Then divide the last result by h:
\(\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{h}{(1-x-h)(1-x)}\cdot\frac{1}{h} \\ \\ \frac{f(x+h)-f(x)}{h}=\frac{1}{(1-x-h)(1-x)} \end{gathered}\)And finally, we will find the limit when h→0
so,
\(\lim _{h\rightarrow0}\frac{f(x+h)-f(x)}{h}=\lim _{h\rightarrow0}\frac{1}{(1-x-h)(1-x)}=\frac{1}{(1-x)(1-x)}=\frac{1}{(1-x)^2}\)the alternative definition to find the derivative:
\(\lim _{x\rightarrow a}\frac{f(x)-f(a)}{x-a}\)We will find the value of f(a), this means we will substitute with (x = a) into the given function
so,
\(f(a)=\frac{1}{1-a}\)Now, find the difference between f(x) and f(a)
\(\begin{gathered} f(x)-f(a)=\frac{1}{1-x}-\frac{1}{1-a} \\ \\ f(x)-f(a)=\frac{(1-a)-(1-x)}{(1-x)(1-a)} \\ \\ f(x)-f(a)=\frac{1-a-1+x}{(1-x)(1-a)}_{} \\ \\ f(x)-f(a)=\frac{x-a}{(1-x)(1-a)} \end{gathered}\)divide the last result by (x-a)
so,
\(\begin{gathered} \frac{f(x)-f(a)}{x-a}=\frac{(x-a)}{(x-a)(1-x)(1-a)} \\ \\ \frac{f(x)-f(a)}{x-a}=\frac{1}{(1-x)(1-a)} \end{gathered}\)Finally, find the limit when x→a
So,
\(f^{\prime}(a)=\lim _{x\rightarrow a}\frac{1}{(1-x)(1-a)}=\frac{1}{(1-a)(1-a)}=\frac{1}{(1-a)^2}\)Last year Jo paid £245 for her car insurance.
This year she has to pay £883 for her car insurance.
Work out the percentage increase in the cost of her car insurance
Answer:
The percentage increase in the cost of her car insurance is 260.4%
Step-by-step explanation:
First, we are going to find by how much the insurance increased:
We know that this year she pays £883 and the last year she paid £245, so
insurance increase = £883 - £245
insurance increase = £638
Now, we are going to find what percentage of the last year price is the insurance increase. So, to find the percentage increase in the cost of the car insurance, we need to divide the insurance increase by the last year price and multiply the result by 100%
percentage increase = (\frac{638}{245} )(
245
638
) (100%)
percentage increase = (2.604)(100%)
percentage increase = 260.4%
We can conclude that Jo's car insurance cost increased 260.4%
Help please giving points to right answer JUST NEED THE NUMBER TO FILL IN BLANK !!
Answer:
We have the proportion: 8/10 = 100/y
We can solve for y by cross-multiplying.
That is, 8y = 100 * 10 Simplifying the right-hand side, 8y = 1000
Dividing both sides by 8 to solve for y, y = 125
Hence, the value of y is 125.
Finally, we have the expression: y = √80We can simplify this expression by factoring 80 into its prime factors:80 = 2 * 2 * 2 * 2 * 5
Taking the square root of 2 * 2 * 2 * 2, we have:√(2 * 2 * 2 * 2) = 2 * 2 = 4
Therefore, y = 4√5The value of y is 4√5.
Step-by-step explanation:
Hope this helps!! Have a good day/night!!
In regression analysis, the error term ε is a random variable with a mean or expected value of.
In regression analysis , the error term ε is a random variable with expected value of 0.
What is regression analysis?
A set of statistical procedures known as regression analysis is used to estimate the relationships between a dependent variable and one or more independent variables.
Main Body:
In regression analysis, the model in the form is called regression model.
The mathematical equation relating the independent variable to the expected value of the dependent variable; that is, E(y) = β0 + β1x, is known as regression equation.
So the answer to error term is 0.
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What is the first step in solving the inequality m-2/6< –1
Steps to solve:
m - 2/6 < -1
~Add 2/6 to both sides
m < -4/6
Best of Luck!
Luis is paid 245 per week plus a 12.5% commission on all sales over $500.his sales last week were totaled 1,340. What is his total earnings
Answer: 12.5% of 1,340 is 167.5 so Luis made $412.50
Gabriel goes to the store and buys laptop $460 is sales tax is 7% how much did he pay in total show work
Answer:
$32.20
Step-by-step explanation:
Jerome is working on a project. He wants to buy some camouflage fabric that is
$7 a yard. He needs of a yard for this project. How much money will this cost
Jerome?
Answer:
The question is incomplete.
Step-by-step explanation:
"He needs of a yard for this project". What percentage or fraction of a yard does he need for the project?
What is the tangent ratio of angle y?
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Using Trigonometry :
\( \tan(y) = \dfrac{20}{21} \)\(\\ \rm\Rrightarrow tan\theta=\dfrac{Perpendicular}{Base}\)
\(\\ \rm\Rrightarrow tany=\dfrac{JL}{KL}\)
\(\\ \rm\Rrightarrow tany=\dfrac{20}{21}\)
Which ordered pairs are solutions to the inequality 2y−x≤−6?
Select each correct answer.
Responses
(−3, 0)
(6, 1)
(0, −3)
(1, −4)
(2, −2)
Those ordered pairs that are solutions to the inequality is
(6, 1), (0, −3), (1, −4), (2, −2)
we have 2y−x≤−6
we know that
if a ordered pair is a solution of the inequality then, the ordered pair must satisfy the inequality
we will proceed to verify each case to determine the solution of the problem
case A)(-3, 0)
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
2(0) - (-3) ≤ 6
+3 ≤ 6 -------> Is False
the ordered pair is a solution of the inequality
case B) (6,1)
so
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
2(1) - 6 ≤ 6
-4 ≤ 6 -------> Is True
therefore
the ordered pair is a solution of the inequality
case C) (0, -3)
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
2(-3) ≤ 6
-6 ≤ 6-------> Is True
therefore
the ordered pair(0, -3) is a solution of the inequality.
case D) (1, -4)
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
2(-4) - 1 ≤ 6
-9 ≤ 6-------> Is true
therefore
the ordered pair is a solution of the inequality
case E) (2, -2)
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
2(-2) - 2 ≤ 6
-6 ≤ 6 -------> Is True
therefore
the ordered pair(2, -2) is a solution of the inequality
Therefore, those ordered pairs that are solutions to the inequality is
(6, 1), (0, −3), (1, −4), (2, −2)
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Amy bought a new car for $29,000. She paid a 10% down payment and financed the remaining balance for 60 months with an APR of 5.5%. Assuming she makes monthly payments, determine the total interest Amy pays over the life of the loan. Round your answer to the nearest cent, if necessary.
Amy will pay a total of approximately $30,007.20 in interest over the life of the loan.
Amy bought a car for $29,000, making a 10% down payment and financing the remaining balance for 60 months with an APR of 5.5%. The question asks for the total interest Amy will pay over the life of the loan.
To calculate the total interest paid, we need to determine the monthly payment amount and then multiply it by the number of months. The monthly payment can be calculated using the formula for a fixed-rate loan: P = (r × PV) / (1 - (1 + r)⁽⁻ⁿ⁾)
where P is the monthly payment, r is the monthly interest rate, PV is the present value or loan amount, and n is the number of months.
First, we calculate the loan amount after the down payment: $29,000 - ($29,000 × 10%) = $26,100.
Next, we calculate the monthly interest rate: 5.5% / 12 = 0.00458.
Using the formula, we can find the monthly payment amount: P = (0.00458 × $26,100) / (1 - (1 + 0.00458)⁽⁻⁶⁰⁾) ≈ $500.12.
Finally, we multiply the monthly payment by the number of months: $500.12 × 60 = $30,007.20.
Therefore, Amy will pay a total of approximately $30,007.20 in interest over the life of the loan.
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electric utility poles in the form of right cylinders are made out of wood that costs $23.89 per cubic foot. calculate the cost of a utility pole with a diameter of 1.5 ft and a height of 30 ft. round your answer to the nearest cent.
The cost of the utility pole is approximately $1273.99 when rounded to the nearest cent.
To calculate the cost of the utility pole, we need to find its volume first. The formula for the volume of a cylinder is V = πr^2h, where r is the radius of the base of the cylinder and h is its height.
Here, the diameter of the utility pole is given as 1.5 ft. We need to find the radius, which is half of the diameter, so r = 0.75 ft. The height is given as 30 ft.
Using the formula, we get:
V = πr^2h = π(0.75 ft)^2(30 ft) = 53.36 ft^3
Now, we can calculate the cost of the utility pole by multiplying its volume by the cost of wood per cubic foot, which is $23.89 per cubic foot.
Cost = 53.36 ft^3 x $23.89/ft^3 ≈ $1273.99
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In the 1800s, wagon trains traveled west along the oregon trail. A wagon train traveled from missouri to wyoming in 1 2/3 months and from wyoming to utah in 3/5 month. About how many months did it take the wagon train to travel from missouri to utah?
Answer: 2 4/15 months
Step-by-step explanation:
From the question, we are informed that a wagon train traveled from Missouri to Wyoming in 1 2/3 months and from Wyoming to Utah in 3/5 month.
The number of months that it will take the wagon train to travel from Missouri to Utah will be:
= 1 2/3 + 3/5
The common lowest multiple is 15
= 1 10/15 + 9/15
= 1 19/15
= 1 + 1 4/15
= 2 4/15 months
It will take they train 2 4/15 months to travel from Missouri to Utah.
Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
a.
10
d.
4 5
b. 4 5
I
s 100
10
4
8
--
8 10
415
이
00
I
C. 10 85
815
I
10
I
2/5
I
211
552
415
Mark this and return
Next
Submit
The ratio of corresponding sides for the given similar triangles is 2/5.
In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:
a. 10
This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.
b. 4/5
This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.
To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.
Dividing 4 and 5 by 1, we get:
4 ÷ 1 = 4
5 ÷ 1 = 5
Therefore, the simplified ratio is 4/5.
c. 10/85
This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.
Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.
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Gene has a gasoline budget of $300 per month. He uses an average of $7 of gasoline each day he drives. Which of the following equations represents how much money is left in his gasoline budget after x days of driving? A. y = 300 + 7x B. y = 7x - 300 C. y = 300x - 7 D. y = 300 - 7x
Answer:
y=300-7x
Step-by-step explanation:
since monthly budget for gasoline=$300
Per day, he uses an average of $7 of gasoline
after x days he will use $7x of gasoline.
remaining amount after x days of driving= 300-7x
the equation will be y= 300-7x
In a certain Algebra 2 class of 26 students, 6 of them play basketball and 15 of them play baseball. There are 9 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Answer:
23% chance
Step-by-step explanation:
There are a total of 26 students in the class, and 6 of them play basketball and 15 of them play baseball. This means that there are 6 + 15 - 9 = 12 students who play either basketball or baseball, and 9 students who play neither.
Of the 12 students who play either basketball or baseball, 6 of them play basketball and 15 of them play baseball, so there are 6 students who play both basketball and baseball. This means that the probability that a student chosen randomly from the class plays both sports is 6 / 26 = 0.23, or 23%.