What is cylopasm?

A. The center of control for a cell.

B. The organelle that create protein for a cell.

C. The membrane that surrounds a cell.

D. The substance that holds the organelle of a cell in place.

To find the density of the unknown piece of metal, we can use the formula:

Density = mass / volume.

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Answer:

They are multicelled

Explanation:

I just did a quiz on it UwU

Answer: 1.4666667e+14

Explanation:

A solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

We must first convert the amount of nitrate(V) ions in drinking water to moles per litre since the threshold concentration over which "Blue-Baby" Syndrome might manifest is 0.05 mg/cm3.

It is necessary to know the molar mass of nitrate(V) ions in order to convert from mg/cm3 to moles per litre (NO3-).

The formula below can be used to determine NO3-'s molar mass:

N: 14.01 g/mol for the atomic mass

O: 16.00 g/mol is the atomic mass (3 oxygen atoms in NO3-)

NO3-'s total molar mass is equal to 14.01 + 16.00 x 3 = 62.01 g/mol.

Let's now translate the specified concentration from mg/cm3 to moles/liter (M).

As 1 g = 1000 mg, 1 mg/cm3 is 0.001 g/cm3.

1 cm3 = 0.001 g/mL multiplied by 0.001 g/cm3

1 L/1000 mL x 0.001 g/mL = 0.001 g/L

We must change the grams into moles using the molar mass in order to get the molarity:

1.61 × 10-5 mol/L = 0.001 g/L / 62.01 g/mol

As a result, a solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

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Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

a

Explanation:

The correct statement about semi-empirical methods is

It combines a theoretically sound model of bonding with some experimentally determined parameters.

These methods are typically referred to by acronyms which encode some of the underlying theoretical assumptions.

The maximum allowable annual dose of radiation has been set at 1000 uSv by the worldwide commission on radiological protection. At this threshold or lower, there is no risk.

What is S(sievert)?

Here are some details concerning the risks increasing radiation levels cause to our health:

Therefore the correct choice is an option (A).

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Answer:

Answer D

Explanation:from founders Edtell :

A dose of 1000 uSv is believed to carry a 1/100,000 risk of getting cancer over 40 years due to your exposure to radiation. The average dose is around 2400 uSv.

Answer:

The answer is C) Gravity keeps all matter on Earth.

Explanation:

I took the test and this was correct!

(Not a fake answer like some, I promise!)

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

For this question, the 2 actions that increase the rate of solute dissolving in a solvent are:

Crushing a solute: For example, if you put granulated sugar in a glass of iced tea, it will dissolve more quickly than the same amount of sugar in a cube. Then we have more surface area exposed.

Rising the temperature: If we increase the temperature of the solvent, we will have more kinetic energy. The increased rapid motion means that the solvent molecules collide with the solute with greater frequency and that the collisions occur with more force.

Answer: b. Crushing the solute and raising the temperature

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer

The final volume, V₂ the gas occupies = 8.81 L

Explanation

Given data:

Initial temperature, T₁ = 31 °C = 31 +273 K = 304 K

Initial volume, V₁ = 7.74 L

Final temperature, T₂ = 73 °C = 73 + 273 K = 346 K

Note: The pressure is kept constant.

What to find:

The final volume, V₂ the gas occupies.

Step-by-step solution

Using Charle's law:

To get V₂, substitute the given parameters into the equation above:

The final volume, V₂ the gas occupies is 8.81 L

In Atlanta, GA, certain seasons are associated with poorer air quality due to various factors such as weather conditions, human activities, and geographical location.

Typically, the seasons with the worst AQI in Atlanta, GA, are summer and early fall. This is primarily due to the combination of high temperatures, stagnant air masses, and increased pollution from various sources.

During the summer months, Atlanta experiences hot and humid weather, which can contribute to the formation of ground-level ozone. Ozone is a harmful pollutant that is created when pollutants from vehicles, power plants, and industrial activities react with sunlight and heat. High levels of ozone can cause respiratory issues and other health problems.

In addition to ozone, Atlanta also experiences increased levels of particulate matter (PM) during the summer and early fall. PM refers to tiny particles suspended in the air, which can come from sources such as vehicle exhaust, industrial emissions, and wildfires.

These particles can be inhaled into the lungs and can have detrimental effects on respiratory health.

It's important to note that air quality can vary from year to year and is influenced by various factors. Local regulations, weather patterns, and changes in pollutant emissions can all impact the AQI during different seasons.

Monitoring air quality reports and taking necessary precautions such as reducing outdoor activities during times of poor air quality can help individuals stay informed and protect their health.

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We have a crucible and we don't heat it enough to remove all the volatile impurities. For example:

mass of crucible empty = 100 g

mass of impurities = 1 g

mass of crucible + impurities = 101 g

The real mass of the crucible is 100 g but we didn't remove all the impurities so when we weigh it we get a reading of 101 g.

We add a sample of a salt that weighs 20 g. We heat it and after that we measure the crucible and the sample weighs 115 g.

mass of sample before heating = 20 g

mass of sample + crucible after heating = 115 g

We can say that 5 g of water were vaporized but we had 1 g of impurities that also vaporized so actually they were 4 g.

So the answer is: b) your sample will weigh less than it is supposed to after heating, causing the mass of water to be higher than it is supposed to be

[H₃O⁺] = 8.86 x 10³ M

The dissociation of water :

H₂O(l)⇒H⁺+OH⁻

Hydrogen ions H⁺ bond with H₂O to form H₃O⁺ ions(hydronium ion)

When acid(Hbr acid) is in the presence of water(dissociates), the H⁺ ions bond with water molecules to form hydronium, the reaction :

HBr(aq)+H₂O→H₃O+(aq)+Br−(aq

So Ionization of HBr :

\(\tt HBr\rightarrow H_3O^++Br^-\)

[HBr]= 8.86 x 10³,

From equation ratio [H₃O⁺] : HBr = 1 : 1, so

\(\tt [H_3O^+]=8.86\times 10^3\)

Answer:

Explanation:

The principal reason why these statements are equivalent and identical is that there can be a progressional flow of heat from a hot object item to a cold object because of this entropy is increasing and expanding Δg < 0 but stream flow from cold to hot is nonspontaneous as Δg > 0.

e.g \(dS = \dfrac{\delta Q}{T}\)

As found in heat engines and refrigerators.

Answer:

The result of a chemical reaction between the silver and sulfur-containing substances in the air. The silver is actually combining with sulfur and forming silver sulfide. When a thin coating of silver sulfide forms on the surface of silver, it darkens the silver.

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The percent yield of the reaction is 45.44%

Percentage yield is basically,

 \(\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100\)

2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

To calculate the theoretical yield, consider the stoichiometry of the reaction.

2 moles of NaOH reacts with 1 mole of H₂SO₄ to give 1 mole of Na₂SO₄ and 2 moles of H₂O. The mole ratio of H₂SO₄ and Na₂SO₄ is 1:1

For this mole ratio to be useful, convert the given concentration of H₂SO₄ into moles.  

     \(\rm Molarity\ =\ \frac{No.\ of\ moles}{Volume\ of\ solution (L)}\)

            \(\rm 3.10\ =\ \frac{No.\ of\ moles}{0.125}\)

\(\rm No.\ of\ moles\ =\ 3.10 \times 0.125\\)

                     \(=\ 0.38\)

Since, mole ratio of H₂SO₄ and Na₂SO₄ is 1:1

Amount of Na₂SO₄ formed would be also 0.38 mol

Convert this amount in moles to amount in grams

\(\rm No.\ of\ moles\ =\ \frac{Mass\ formed\ }{Molecular\ mass}\)

\(\rm Mass\ formed\ =\ No.\ of\ moles\times molecular\ mass\)

                     \(\rm =\ 0.38\times 142.04\)

                     \(\rm =\ 53.97\ grams\)

Theorical yield of Na₂SO₄ is 53.97 grams

Therefore,   \(\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100\)

                                          \(\rm =\ \frac{24.5}{53.97}\times 100\)

                                          =  45.44%

The percent yield of the reaction is 45.44%

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The expression 7.0x\(10^7\) ÷ 2.0x\(10^4\) can be expressed in proper scientific notation as 3.5x10^3.

To express the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) in proper scientific notation, we need to perform the division and adjust the result to the appropriate format.

Dividing the numbers, we get:

7.0x\(10^7\) ÷ 2.0x\(10^4\)= 3.5x\(10^{(7-4)\)= 3.5x\(10^3\)

The result of the division is 3.5, and we adjust the exponent by subtracting the exponent of the divisor from the exponent of the dividend (7 - 4 = 3).

Therefore, the proper scientific notation representation of the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) is 3.5x\(10^3\).

Scientific notation is a way to express numbers using a coefficient (in this case, 3.5) multiplied by a power of 10 (in this case, 10^3). It allows for more concise representation of very large or very small numbers.

In this case, the division resulted in a number that is smaller than the dividend and has a positive exponent, indicating a smaller magnitude compared to the original numbers. The coefficient represents the significant digits of the result, while the power of 10 represents the scale or magnitude of the number.

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Answer:

its sodium hydroxide

Explanation:

Answer:

The formula for volume of a rectangle is length multiply by width multiply thus, 0.25 m multiply 6.1 m multiply by 4.9 m = 7.5m^3.

Explanation:

the least number of significant figures is 2 thus the final answer will have the same number of significant figures. 7.5m^3

There are approximately 2.8939 x\(10^2^4\) carbon atoms in 0.37 mol of procaine.  The molecular formula of procaine (C₁₃H₂₀N₂₀₂), one can see that there are 13 carbon atoms (C13) in one molecule of procaine.

Avogadro's number (6.022 x \(10^2^3\)) represents the number of particles (atoms, molecules, or formula units) in one mole of a substance

The number of molecules of procaine in 0.37 mol:

Number of molecules = 0.37 mol x (6.022 x\(10^2^3\) molecules/mol)

Number of carbon atoms = Number of molecules x 13 carbon atoms/molecule

Number of molecules = 0.37 mol x (6.022 x \(10^2^3\)molecules/mol)

= 2.22614 x \(10^2^3\)molecules

Number of carbon atoms = 2.22614 x \(10^2^3\) molecules x 13 carbon atoms/molecule

= 2.8939 x \(10^2^4\)carbon atoms

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The term that the scientist would use in this case is partial pressure. Option D

The pressure that one particular gas component within a mixture of gases exerts is referred to as partial pressure. It is the pressure that the gas would experience at the same temperature if it were the only thing in the entire volume.

When researching gas mixtures, such as in gas laws, gas phase equilibria, and gas collecting methods, partial pressures are extremely crucial for the gas.

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Answer:

1.3

Explanation:

Answer:

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

light

Explanation: