what is electronic logic​

Answer:

R₈₀ = 146.43 Ω

Explanation:

The resistance of a resistor depends upon many factors. One of the main factors of the change in resistance of a resistor is the change in temperature. The formula for the resistance at a temperature other than 20°C is given as follows:

R₈₀ = R₀(1 + αΔT)

where,

R₈₀ = Resistance of wire at 80°C = ?

R₀ = Resistance of wire at 20° C = 104 Ω

α = Temperature coefficient of resistance for copper = 0.0068 °C⁻¹

ΔT = T₂ - T₁ = 80°C - 20°C = 60°C

Therefore,

R₈₀ = (104 Ω)[1 + (0.0068°C⁻¹)(60°C)]

R₈₀ = 146.43 Ω

Answer:

14

70g/(35mL-30mL)=14g/mL

Explanation:

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

1. The density of the cube is 1.03 g/mL.

2. Dish soap

Explanation:

1. Determination of the density of the cube.

From the question given above, the following data were obtained:

Mass (m) of cube = 21.7 g

Volume (V) of cube = 21 mL

Density (D) of cube =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Thus, density can be expressed mathematically as:

Density (D) = mass (m) / volume (V)

D = m / V

With the above formula, we can obtain the density of the cube as follow:

Mass (m) of cube = 21.7 g

Volume (V) of cube = 21 mL

Density (D) of cube =?

D = m / V

D = 21.7 / 21

D = 1.03 g/mL

Thus, the density of the cube is 1.03 g/mL.

2. Determination of the layer of density the cube will settle in.

From the question given above,

Subtance >>>>>>>> Density

Vegetable oil >>>>> 0.91 g/mL

Grape juice >>>>>> 0.97 m/L

Water >>>>>>>>>>> 1 g/mL

Dish soap >>>>>>>> 1.03 g/mL

Maple syrup >>>>>> 1.37 g/mL

Comparing the density of the cube (i.e 1.03 g/mL) with those in the table able, we can conclude that the cube will settle in the DISH SOAP layer since they both have the same density.

A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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(a) The position where particle Q and P meet is 68.75 m.

(b) The velocity with which particle Q is shot is 15 m/s.

The time elapsed before the two particles meet is calculated as follows;

Distance Q - Distance P = Distance between them

Trise = (V - V₀)/g

Trise = (0 - 40) / -10

Trise = 4.0 s

Hmax = V₀t + 0.5gt²

Hmax = 40 x 4 - (0.5)(10)4²

Hmax = 80 m.

h = Hmax - (V² - V₀²)/2g

h = 80 - ((15)²- 0) / 20

h = 68.75 m.

Thus, the position where particle Q and P meet is 68.75 m

Tfall = (V - V₀)/g = (15-0) / 10

Tfall = 1.5 s

Fall time. = Rise time  for Q.

h = V₀t + 0.5gt²

h = 80 - 68.75

h = 11.25

V₀ x 1.5 - 5(1.5)² = 11.25

V₀ x 1.5 - 11.25 = 11.25

V₀ x 1.5 = 22.5

V₀ = 22.5 / 1.5

V₀ = 15 m/s

Thus, the velocity with which particle Q is shot is 15 m/s.

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We can start by finding the acceleration of the car:a = Δv/Δt = (96.5 km/h)/(2.4 s) = 40.21 m/s^2

Next, we can find the force required to accelerate the car:F = ma = (1961 kg)(40.21 m/s^2) = 78914.81 N

Finally, we can find the power of the car:P = Fv = (78914.81 N)(96.5 km/h) = 2.84 x 10^6 W

Therefore, the power of the car is approximately 2.84 megawatts.

Answer:

The image is virtual

number-4

The time taken is √3 s and the velocity with he lands is 17.3 m/s.

In this case, we have to use the equations of kinematics as it has to do with motion under gravity. We know that;

h = ut + 1/2gt^2

h = height

u = initial velocity

g = acceleration due to gravity

t = time taken

Given that u = 0 m/s because the object was dropped from a height.

h = 1/2gt^2

t = √2h/g

t = √2 * 15/10

t = √3 s

The velocity with which he falls is obtained from;

v = u + gt

v = gt

v = 10 m/s^2 * √3 s

v = 17.3 m/s

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Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.

We can use the formula Q = I * t,

where;

Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:

I = Q / t = 6.4 C / 2 s = 3.2 A

So, the current through the conductor is 3.2 A.

To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:

Q = I * t = 3.2 A * 60 s = 192 C

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Answer:

A.) 4.52s

B.) 44.3 m/s

Explanation:

Given that a cargo of mass 50kg fall freely from rest at a height of 100m and came to rest having penetrated 5.0cm of the ground

The total height = 100 + 5/100

The total height = 100 + 0.05

The total height = 100.05 m

Since the cargo fall from rest, the initial velocity U will be equal to zero. That is,

U = 0

Use second equation of motion

h = Ut + 1/2gt^2

Substitutes g = 9.8 and others parameters into the formula

100.05 = 0 + 1/2 × 9.8 × t^2

100.05 = 4.9t^2

t^2 = 100.05/4.9

t^2 = 20.42

t = sqrt( 20.42)

t = 4.52 s

B.) To calculate the velocity of the body when it hits the ground,

You can achieve it by first calculating its kinetic energy. Or by using the first equation of motion.

So, let use first equation of motion

V = U + at

But U = 0

Substitute the time and g into the formula

V = 9.8 × 4.52

V = 44.29 m/s

Therefore, the velocity of the body when it hits the ground is 44.3 m/s approximately.

Answer:

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Explanation:

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Answer:

24 cm/s

Explanation:

Applying

Pythagoras theorem,

a² = b²+c²............. Equation 1

Where a = resultant, b = vertical component, c = horizontal component

From the question,

Given: a = 26 cm/s, c = 10 cm/s

Substitute these values into equation 1

26² = b²+10²

676 = b²+100

b² = 676-100

b² = 576

b = √576

b = 24 cm/s

Answer:

a. Stored energy is potential energy, and energy of motion is kinetic energy

Explanation:

The correct option is - a. Stored energy is potential energy, and energy of motion is kinetic energy.

Reason -

Potential energy is stored energy, whereas kinetic energy is the energy of moving things.

Answer: 0.390625 grams

Explanation:

A half-life of an element is the amount of time that it takes for half the mass of the element to decay.

Gold-198 having a half-life of 2.5 days therefore means that every 2.5 days, the mass is cut in half.

If there are 20 days, find out how many half-life periods there are:

= 20 / 2.5

= 8 periods

The half life is:

= Original mass * 0.5^number of half-life periods

= 100 * 0.5⁸

= 0.390625 grams

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

The average force exerted by the golf club on the golf ball is equal to 1769.2N.

Force acting on an object can be described as the influence that changes the state of the object of motion or rest. The S.I. unit of force is Newton (N) and force is a vector parameter.

The mathematical formula of the 2nd law of motion for force is written as follows:

F = ma

Given the mass of the ball, m= 0.046 Kg

The golf club was in contact with the ball for time, t = 1.3 ms = 1.3 ×10⁻³s

The speed of the golf ball, v = 50 m/s

We know that, equation of motion: \(v = u + at\)

50 = 0  + a (1.3 ×10⁻³)

a = 38.46 ×10³ m/s²

The average force on the golf ball will be:

F = ma = 0.046 ×38.46 ×10³

F = 1769.2 N

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The cardinality of R₁ \ (R₁ intersection A) is 4. The given polynomial (2x² + y² + 22 - 8x + 2y - 2xy + 2xz-16z + 35) cannot be solved for x, y, and z due to insufficient equations.

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The magnitude of the force and the impulse applied to the car are  85714 N and  30000 N-s respectively.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

The magnitude of the force applied to the car = change in momentum/time interval

= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second

= 85714 N.

The impulse applied to the car = change in momentum

= (1200 kg × 25 m/s - 1200 kg×0)

= 30000 N-s.

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Answer:

 i₃ >  i₁ > i₂

Explanation:

For this exercise we use the resistance ratio

        R = ρ \(\frac{l}{A}\)

where ρ is the resistivity of the wire, in this case it is the same for all three cases, l the length and A the area of ​​the wire.

We have three cases

a) length    l = L

  area       A = A

b) length   l = 2L

    area    A = A

c) length  l = L

   area    A = 2A

we calculate the resistance for each case

a) R₁ = ρ  L / A

b) R₂ = ρ 2L / A

   R₂ = 2 ρ L / A

   R₂ = 2 R₁

c) R₃ = ρ  L / 2A

   R₃ = ½ ρ L / A

   R₃ = 0.5 R₁

therefore when the connect of the circuit is carried out we can use ohm's law

         V = i R

          i = V / R

whereby

a)  i₁ = V / R₁

b)  i₂ = V / 2R₁

    i₂ = ½ i₁

    i₂ = 0.5 i₁

c)  i₃ = V / 0.5 R₁

    i₃ = 2 I₁

the order from highest to lowest in the current is

           i₃ >  i₁ > i₂

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

The student does zero work on the backpack because the upward force applied by the student is acting perpendicular to the backpack's displacement parallel to the ground.

Explanation:

Friction acts between two surfaces in contact only and opposes the movement of one body with respect to another. Therefore friction is a force which opposes the relative motion between two bodies. If a body is moving it is slowed down by frictional force applied on it by the surface on which it is moving.

Answer:

r = 1.07 m

Explanation:

The maximum radius of the propeller that can be allowed is given by the following formula:

\(v = r\omega\\\\r = \frac{v}{\omega}\)

where,

r = maximum possible radius of the propeller = ?

v = maximum possible linear speed of the propeller = 270 m/s

ω = angular speed of the propeller = (2400 rpm)(2π rad/1 rev)(1 min/60 s)

ω = 251.33 rad/s

Therefore,

\(r = \frac{270\ m/s}{251.33\ rad/s}\)

r = 1.07 m

Answer:

y = 1.75 cm

Explanation:

In the double-slit experiment the equation for destructive interference is

           d sin tea = (m + ½)

λ

let's use trigonometry to find the angle

         tan θ = y / L

as all the experiment does not occur at small angles

          tan θ = sin θ / cos θ = sin θ = y / L

we substitute

        y = (m + 1/2 ) λ  L / d

we calculate

         y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³

         y = 1.75 10⁻² m

         y = 1.75 cm

The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.

Time can be defined as the calculable measure of motion with respect to before and afterness.

To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the time taken for the bicycle to stop completely is 27 seconds.

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Explanation:

Recreational water activities can have substantial benefits to health and well-being. Swimming pools, beaches, lakes, rivers and spas provide environments for rest and relaxation, physical activity, exercise, pleasure and fun. Yet they also present risks to health.

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