what is energy? list the three mechanical forms of energy and their associated equations. ​

Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.

Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.

To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.

The work done by the air can be calculated using the equation:

Work = Force * Distance * cos(θ)

Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.

In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:

Work = Force * Distance * 0

Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.

However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.

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Answer:

60 km/hr

Explanation:

Looking for km / hr

12 km / (.20 hr) =   60 km/hr

Answer:

loyalty

Explanation:

The electric heater draws a current of 4.5 amps.

Using Ohm's Law, we can calculate the current drawn by the electric heater. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) applied to the conductor divided by its resistance (R):

In this case, the voltage (V) is 120 V and the power (P) of the electric heater is 540 W. We can use the formula P = VI, where P is the power in watts, V is the voltage in volts, and I is the current in amperes. Solving for I, we get:

Therefore, the electric heater draws a current of 4.5 amperes (A) when operated at 120 volts (V).

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Answer:

\( {3}^{n} \)

Explanation:

https://www.doubtnut.com/question-answers/a-cellphone-weighs-about-28x10n-pounds-which-value-of-n-is-most-reasonable-a-3-b-2-c-0-d-1-433477

\(\\ \bull\sf Frequency=f=6\times 10^{14}Hz\)

\(\\ \bull\sf Wavelength=\lambda=3.75\times 10^{-7}m\)

Now

\(\\ \sf\longmapsto v=f\lambda\)

\(\\ \sf\longmapsto v=6\times 10^{14}s^{-1}\times 3.75\times 10^{-7}m\)

\(\\ \sf\longmapsto v=22.5\times 10^7ms^{-1}\)

Answer:

velocity=v = 22.5 * 10⁷ m s ^ - 1

Explanation:

\(\sf\longmapsto \: Frequency = 6 * 10 ^ {14 } H z\)

\(\sf\longmapsto \: Wavelength = 3.75 \times 10 {}^{-7} m\)

Now let's solve out!!

\(\sf\longmapsto \: velocity = frequency \lambda\)

\(\sf\longmapsto \: velocity=6 \times 10 {}^{14} s {}^{ - 1} \times \ 3.75 \times 10 {}^{ - 7} m\)

\(\sf\longmapsto \: velocity= 22.5 \times 10 ^ 7 m s ^ { - 1}\)

Note:

\(\lambda\) is the Greek letter known as lambda.

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Given

distance of the object  u = -40 cm.

radius of curvature of the refracting surface  R = -20 cm.

The height of the object  h = 1 cm.

To Find

The size of the image

Solution

We will now write the following data using the sign convention:

The object's distance is u = -40 cm.

The refracting surface has a radius of curvature of R = -20 cm.

The object's height is h = 1 cm.

We know that the lens maker formula is: n2vn1u=n2n1R.

v denotes the image formation distance.

The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.

In the preceding equation, we will now substitute the known values.

1.33v−1−40cm=1.33−1−20cmv=32.05cm

We know that the magnification ratio can be expressed as vu=Hh.

H denotes the height of the created image.

We'll now swap the given and obtained values.

⇒32.05cm divide by 40cm=H divide by 1cm

⇒H=0.6cm

As a result, the best choice is (B).

Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.

The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images.  A virtual and magnified picture is generated when the object is placed very close to the mirror.

The complete question is -

Find the size of the image formed in the situation shown in figure.

photo

A) 0.5 cm

B) 0.6 cm

C) 1.2 cm

D) 1 cm

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One support of the behavioral perspective is how  B. F. skinner’s ideas have brought to light how the environment and learning influence personality.

The behavioral perspective on personality and individual variations places an emphasis on quantifiable behaviors influenced by the environment and the results that follow.

The theoretical aim of behaviorism is the prediction and control of behavior given its natural science methodology.

Skinner's theories have made it clear how learning and the environment affect personality, which is one argument in favor of the behavioral approach.

One support of the behavioral perspective is how  B. F. skinner’s ideas have brought to light how the environment and learning influence personality.

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The velocity when the pumpkin strikes the ground if it takes 3.2 seconds for it to fall: 50.78 m/s

From the definition of velocity, we can find the velocity of a falling object is:

v = v₀ + gt

Here

v₀ - 19.4 m/s , t - 3.2  seconds , g - 9.80665 m/\(s^2\\\)

v = 19.4 + (9.86 x 3.2)

v = 50.78 m/s

Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the fastest when their motion is in the other direction. The concept of velocity is useful in these circumstances. Learn about the definition of velocity in this article as well as the distinction between speed and velocity.

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Answer:  (x - 4)² + (y - 7)² = 9

Explanation:

The equation of a circle is: (x - h)² + (y - k)² = r²    where

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

     -4y = -3x - 1

        \(y=\dfrac{3}{4}x-1\)

              \(m=\dfrac{3}{4}\)      -->      \(m_{\perp}=-\dfrac{4}{3}\)

\(y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}\)

Use substitution to find the point of intersection:

\(x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6\)

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

\(r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3\)

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

The minimum streamflow immediately prior to the rising limb is used as the constant value.

Here the constant value is taken as 25cfs which is at 2nd hour just before the rise of hydrograph.

The direct runoff discharge starts from 2nd hour and ends at 36th hour.

from the trapezoidal formula, The runoff discharge = (0+72+173+295+419+510+559+495+397+266+167+110+7 2+47+27+19+12+(8/2)) * 2 * 3600 = 26236800 cubic feet. The area of the catchment = 2000 acres. = 2000* 43560 =87120000 ft^2

The depth of runoff (discharge / area) = 0.266 feet = 0.266* 12 inches 3.2 inches.

Stream flow or channel outflow is the flow of water in streams and other channels and is a major component of the hydrological cycle. This is one component of water movement from land to water, and another component is surface runoff. The water flowing through the channel comes from surface runoff from adjacent hillsides, groundwater flowing from the ground, and water drained from pipes. The flow rate of water flowing through a canal can be measured with a hydrometer or estimated using Manning's equation. A record of flow over time is called a hydrograph. Flooding occurs when the volume of water exceeds the capacity of the canal.

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Answer:

I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.

Explanation:

I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!

Answer:

Answer is B!

Explanation:

I took the cumulative exam and got 100%

Answer:

I think it's b

Explanation:

Answer: i think its b

Explanation:

The length of the rod at 60 degree Celsius is 1.010025m.

It defines the material's property of expanding when temperature is increased.

The change in length related to the coefficient of linear expansion is given by

ΔL = αLΔT

where ΔT is the change in temperature, L is the original length and ΔL is the change in length.

Substitute the values from question, we get the coefficient of linear expansion as

α = ΔL /LΔT

α = (1.005-1) / 1 x(40-20)
α= 2.5 x 10⁻⁴ /°C

Length at 60°C, L' =1.005 [1 + 2.5 x 10⁻⁴x (60-40)]

L' = 1.010025 m

Thus, the length at 60°C is 1.010025 m

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d = v·t + (1/2)·a·t^2

a = 10m/s^2. t = 10s

v = 0m/s. Initial velocity

d = 0·10 + 10/2 · 10^2 = 0 +5·100

d = 500m

a. When the force = 12 N, mass = 6 kg, the acceleration is a = 2 m/s²

b. When the force = 48 N, mass = 6 kg, the acceleration is a = 8 m/s².

The acceleration of the body is calculated by applying Newton's second law of motion as follows;

F = ma

where;

a = F / m

when the force = 12 N, mass = 6 kg, the acceleration is calculated as;

a = 12 N / 6 kg

a = 2 m/s²

when the force = 48 N, mass = 6 kg, the acceleration is calculated as;

a = 48 N / 6 kg

a = 8 m/s²

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Answer:

Volume of Sand = 0.4 m³

Radius of Sand Sphere = 0.46 m

Explanation:

First we need to find the volume of gold sphere:

Vg = (4/3)πr³

where,

Vg = Volume of gold sphere = ?

r = radius of gold sphere = 2 cm = 0.02 m

Therefore,

Vg = (4/3)π(0.2 m)³

Vg = 0.0335 m³

Now, we find mass of the gold:

ρg = mg/Vg

where,

ρg = density of gold = 19300 kg/m³

mg = mass of gold = ?

Vg = Volume of gold sphere = 0.0335 m³

Therefore,

mg = (19300 kg/m³)(0.0335 m³)

mg = 646.75 kg

Now, the volume of sand required for equivalent mass of gold, will be given by:

ρs = mg/Vs

where,

ρs = density of sand = 1602 kg/m³

mg = mass of gold = 646.75 kg

Vs = Volume of sand = ?

Therefore,

1602 kg/m³ = 646.75 kg/Vs

Vs = (646.75 kg)/(1602 kg/m³)

Vs = 0.4 m³

Now, for the radius of sand sphere to give a volume of 0.4 m³, can be determined from the formula:

Vs = (4/3)πr³

0.4 m³ = (4/3)πr³

r³ = 3(0.4 m³)/4π

r³ = 0.095 m³

r = ∛(0.095 m³)

r = 0.46 m

the weigth of the student on earth is 610 Newtons

the weigth on the moon is 99 Newtons

Explanation

Step 1

find the weigth on earth

the weigth on earth is given

let

then, let

m= 61 kg

g= 10 m/s^2

replace,

therefore, the weigth of the student on earth is 610 Newtons

Step 2

Now, the expression to gravitacional force between two objects is given by:

then , to find the G on the moon

let

Step 3

finally, we have the force and the mass, so we can get the g value on the moon

I hope this helps you

Answer:

We conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.

Explanation:

Given

To determine

We know that a body can possess energy due to its movement — Kinetic Energy.

The speed with which a body moves can be determined using the formula

\(K.E=\frac{1}{2}mv^2\)

\(v=\sqrt{\frac{2\times \:K.E}{m}}\:\:\:\)

substituting m = 25 and K.E = 2500 in the formula

\(v=\sqrt{\frac{2\times 2500}{25}}\)

\(v=\sqrt{\frac{5000}{25}}\)

\(v=\sqrt{200}\)

\(v=14.14\) m/s

Therefore, we conclude that the speed of a 25 kg object that has 2500 J of kinetic energy is 14.14 m/s.

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer:

Hurricane

Explanation:

Hurricane can be described as a huge storm that came with a strong and harsh wind. This wind tends to move in a circular motion over warm ocean water that are found in tropical regions.

Hurricane comes with strong winds that move at the rate of over 60 miles per hour, this results in the formation of a heavy rainfall. Hurricanes are also referred to as cyclones depending on where they take place. In places like Florida, which is surrounded by the Atlantic ocean the type of natural hazard that occurs there is known is hurricane.

Hurricane is formed when warm air that emanates from the ocean begins to rise up to a very high temperature, When it comes across a much more cooler air the steam condenses and results in a heavy downpour.

Answer:

Hurricanes

Explanation:

Hurricanes are a form of natural hazard that usually come with very strong rotating  winds, thunderstorms and heavy rainfall. In meteorology, they are said to have a low pressure center and a close low level circulation

Answer:

1. Mass

2. Weight

Explanation:

1. All the physical quantities that exist in the universe that have mass, are measurable because they can be measured on instruments such as scales. For this example, the amount of food can be measured on a scale and its mass determined in grams or ounces.

2. When we talk about a mass of a body influenced by gravity we are talking about weight, weight is a force that points in the direction of Earth's gravitational acceleration. That is, weight depends on the gravitation that interacts with the body. For the example we have that the weight of the dog is equal to the product of the mass of the dog by the gravity of the Earth.

Answer:

A Impulse = – 25 Ns

B. Time = 5 s

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

Time (t) =?

A. Determination of the Impulse.

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

I = Ft = M(v – u)

I = M(v – u)

I = 5 (3 – 8)

I = 5 × – 5

I = – 25 Ns

NOTE: the negative sign indicates that the net force is acting in the negative direction.

B. Determination of the time.

Impulse (I) = 25 Ns

Force (F) = 5 N

Time (t) =?

I = Ft

25 = 5 × t

Divide both side by 5

t = 25 / 5

t = 5 s

Thus, it will take 5 s for the box to slide through the 15 m long ramp.

Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

Answer:

29

Explanation:

I just took a test! not only that but the other person who answered this question had the corrected answer.

Answer:

W = 5593.3 J

Explanation:

The work can be calculated as

W = Fdcosθ

Where F is the force, d is the distance and θ is the angle.

So, replacing F = 156N, d = 45.5 m and θ = 38, we get:

W = (156N)(45.5m)(cos38)

W = (156N)(45.5m)(0.788)

W = 5593.3 J

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer: 10 kg

Explanation:

Using dimensional analysis, we can find the unit of mass in the given system:

Force (F) = mass (m) × acceleration (a)

In the given system, the unit of force is 100 N, which can be written as:

100 N = (100 kg · m/s²) × (10 m/s²)

Thus, we can see that the unit of force is equivalent to 100 kg·m/s².

Now, we can rearrange the equation to solve for mass (m):

m = F/a

Substituting the units:

m = (100 kg·m/s²) / (10 m/s²)

m = 10 kg

Therefore, the unit of mass in the given system is 10 kg.

The speed of the wave from the calculation that we have done is 14 m/s

To find the wave speed, we need to know the frequency and wavelength of the wave. These values can be measured experimentally or calculated based on the properties of the medium through which the wave is traveling.

For example, the wavelength of a sound wave can be determined by measuring the distance between two consecutive points of maximum compression or rarefaction, while the frequency can be measured using a frequency meter or calculated based on the properties of the sound source.

We know that;

Frequency = 7 cycles/s

Wavelength = 2 m

Wave speed = λf

= 7 cycles/s * 2 m

= 14 m/s

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