what is fmin,1, the lowest frequency that will produce the maximum intensity (imax) at the observer, assuming the observer would still hear the intensity of 6 w/m2 when either s1 or s2 is sounded alone?

Answer: The area of brick in contact with the floor is 1539 \(cm^{3}\).

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

\(Area = length \times width \times height\)

Substitute the values into above formula as follows.

\(Area = length \times width \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}\)

Thus, we can conclude that area of brick in contact with the floor is 1539 \(cm^{3}\).

The answer is 60. Second is 120.

Answer:

A

Explanation:

Only a small portion of the energy that reaches the Earth's surface is reflected. The atmosphere or the surface of the Earth together absorb around 70% of the incoming radiation, while about 30% is reflected.

Usually, the thermal energy from the absorbed sunlight causes the thing to heat up. The incident energy, nevertheless, can occasionally be absorbed and changed into an other kind of energy. In photovoltaic cells found in solar panels, this is the case.

The earth's surface, which includes the land and oceans, absorbs around 50% of a incoming energy. The albedo of the earth, which is typically 0.3, is reduced by clouds, the surface of the earth, and various gases and atmospheric particles to approximately 30%. Clouds and the atmosphere absorb 20% of the energy.

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Answer:

if it were submerged 1000 m in the ocean it would be crushed because of the differences of the air and water pressure.

If it were taken 10,000 m (higher than Mt Everest) it would explode due to the differences of external and internal air pressures.

Answer: no

Explanation: every action has an equal and opposite reaction

Answer:

Because of the Cohesion

If A 6.3 kg ball moving at 0.6 m/s collides with a 4.8 kg ball at rest. If the heavier ball moves at 0.25 m/s after the collision, then the lighter ball moves at 0.459 m/s after the collision.

To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system.

The momentum of an object is defined as the product of its mass and velocity. Mathematically, momentum (p) is calculated as:

p = mass × velocity

Before the collision, the total momentum is given by:

Total momentum before = (mass of ball 1 × velocity of ball 1) + (mass of ball 2 × velocity of ball 2)

Total momentum before = (6.3 kg × 0.6 m/s) + (4.8 kg × 0 m/s) (since the second ball is at rest)

Total momentum before = 3.78 kg·m/s

After the collision, the total momentum is given by:

Total momentum after = (mass of ball 1 × velocity of ball 1) + (mass of ball 2 × velocity of ball 2)

Total momentum after = (6.3 kg × 0.25 m/s) + (4.8 kg × velocity of ball 2)

Total momentum after = 1.575 kg·m/s + (4.8 kg × velocity of ball 2)

According to the conservation of momentum principle, the total momentum before the collision is equal to the total momentum after the collision:

Total momentum before = Total momentum after

3.78 kg·m/s = 1.575 kg·m/s + (4.8 kg × velocity of ball 2)

Simplifying the equation:

3.78 kg·m/s - 1.575 kg·m/s = 4.8 kg × velocity of ball 2

2.205 kg·m/s = 4.8 kg × velocity of ball 2

Dividing both sides of the equation by 4.8 kg:

velocity of ball 2 = 2.205 kg·m/s / 4.8 kg

velocity of ball 2 ≈ 0.459 m/s

Therefore, the lighter ball (ball 2) moves at approximately 0.459 m/s after the collision.

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Answer:

This is one of  the mysteries  of quantum mechanics - a  single photon in classical mechanics is sent out in a circular arc - but when the arc interacts with a distant object the entire wave front collapses and delivers the entire energy of the photon to the object in question.

An analogy has been give as a pop  bottle thrown into the water in New York with its energy spreading out in a circular arc and at some time later  the wave front strikes a pop bottle in the water in Japan with the result of the wave front delivering its entire energy to the bottle with the bottle jumping out of the water.

Answer:

11 hours and 15 minutes.

Explanation:

I did the math and that was my answer.

Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.

Explanation:

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

\(3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]\)

High mass stars are much less common than low mass stars due to the nature of their formation and lifespan. High mass stars are formed in dense molecular clouds that are found in regions of active star formation, and these clouds are much rarer compared to the diffuse gas clouds where low mass stars are formed.

Moreover, high mass stars consume their fuel at a much faster rate and have shorter lifespans, which means they are more likely to die before they can contribute to the formation of new stars. Additionally, high mass stars have higher rates of stellar winds and explosions, which can disrupt the molecular clouds and prevent new star formation. The rarity of high mass stars is also reflected in the distribution of stars in our galaxy, with the majority of stars being low mass stars. Therefore, high mass stars are much less common than low mass stars due to their formation in dense molecular clouds, shorter lifespans, and disruptive effects on the star-forming environment.

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Answer:

The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

Answer:

WDYM?

Explanation:

Answer: Get therapy (not like actually lol but like you know...)

Explanation: Listen to calming music or your favorite music, read, draw, color, literally anything that makes you calm

(A) The power output of the speaker is approximately 0.892 W. (B) The sound level of 82 dB will be achieved at a distance of approximately 3330.44 meters from the speaker.

Here is the explanation :

Part A:

To calculate the power output of the speaker, we can use the inverse square law for sound intensity. The inverse square law states that the intensity of sound decreases inversely with the square of the distance from the source.

The equation for the inverse square law is:

\(\[\frac{I_1}{I_2} = \left(\frac{r_2}{r_1}\right)^2\]\)

where I₁ and I₂ are the intensities at distances r₁ and r₂ from the source, respectively.

Given:

Intensity at the reference level (I₁) = 1.0×10⁻¹² W/m²

Sound level at 2.1 m in front of the speaker (L₁) = 134 dB

Converting the sound level to intensity:

\(\[I_1 = 10^{\frac{L_1 - L_0}{10}} \cdot I_0\]\)

where L₀ is the reference sound level (0 dB) and I₀ is the reference intensity (1.0×10⁻¹² W/m²).

Plugging in the values:

\(\[I_1 = 10^{\frac{134 - 0}{10}} \cdot 1.0\times10^{-12}\]\)

Calculating I₁:

I₁ ≈ 2.512×10⁻² W/m²

Now, we can use the inverse square law to find the power output (P) of the speaker:

P = I₁ * 4πr₁²

where r₁ is the distance from the speaker.

Given:

r₁ = 2.1 m

Plugging in the values:

P = 2.512×10⁻² * 4π(2.1)²

Calculating P:

P ≈ 0.892 W

Therefore, the power output of the speaker is approximately 0.892 W.

Part B:

To determine the distance at which the sound level is 82 dB, we can use the inverse square law and the same formula as in Part A.

Given:

Sound level (L₂) = 82 dB

Converting the sound level to intensity:

\($I_2 = 10^{\frac{L_2 - L_0}{10}} \times I_0$\)

Plugging in the values:

\($I_2 = 10^{\frac{82 - 0}{10}} \times 1.0 \times 10^{-12}$\)

Calculating I₂:

I₂ ≈ 1.0×10⁻⁸ W/m²

Now, we can use the inverse square law to find the distance (r₂) at which the sound level is 82 dB:

\($I_2 = I_1 \times \left(\frac{r_1}{r_2}\right)^2$\)

Plugging in the values:

\($1.0 \times 10^{-8} = 2.512 \times 10^{-2} \times \left(\frac{2.1}{r_2}\right)^2$\)

Simplifying the equation:

\($\left(\frac{r_2}{2.1}\right)^2 = \frac{2.512 \times 10^{-2}}{1.0 \times 10^{-8}}$\)

\($\left(\frac{r_2}{2.1}\right)^2 \approx 2.512 \times 10^6$\)

Taking the square root of both sides:

\($r_2/2.1 \approx \sqrt{2.512 \times 10^6}$\)

\($r_2 \approx 2.1 \times \sqrt{2.512 \times 10^6}$\)

Calculating r₂:

r₂ ≈ 2.1 * 1584.97

r₂ ≈ 3330.44 m

Therefore, the sound level will be 82 dB at a distance of approximately 3330.44 meters away from the speaker.

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The overall energy transformation that occurs in a coal-fired power plant is 2. chemical to electrical. The energy transformation in a coal-fired power plant is used to generate electrical energy from thermal energy. The energy that is transformed comes from the chemical potential energy stored in coal.

The chemical energy is converted into thermal energy, which is then converted into mechanical energy that drives a generator. The overall process involves the combustion of coal in a furnace, which generates heat energy. This heat energy is then transferred to the water that is present in the boiler. The water is converted into steam due to the heat energy and this steam is used to turn the turbines. The turbines convert the thermal energy into mechanical energy, which is then used to drive the generator. The generator then converts the mechanical energy into electrical energy.

Therefore, the energy transformation that occurs in a coal-fired power plant is from chemical potential energy in coal to thermal energy, then to mechanical energy, and finally to electrical energy. The correct option is (2).

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Answer:

Explanation:

The independent variable of an experiment is the part that the experimenter is changing and can control. The dependent variable is the part of the experiment that is affected by the change.

For example, with a plant, if you water a plant, that is an independent experiment, dependent on you actually watering the plant. The dependent variable is the plant's condition. It is dependent on being watered.

The velocity with which the rock initially kicked if the cliff is 5 m high and the rock lands 7m from the base of the cliff is 6.93 m / s

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

In vertical motion,

s = 5 m

u = 0

a = 9.8 m / s²

5 = 0 + ( 1 / 2 * 9.8 * t² )

t² = 1.02

t = 1.01 s

In horizontal motion,

s = 7 m

a = 0 ( Since velocity is constant )

7 = 1.01 u + 0

u = 7 / 1.01

u = 6.93 m / s

Therefore, the velocity with which the rock initially kicked is 6.93 m / s

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Answer:poop

from ur stomach to the toilet duh that's logical

Explanation:

Heat is energy transferred from one place to another. You can transfer  sound, which is wave, from one place to another.

Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another.

Energy is always assigned based on its nature once it has been transmitted. Thus, heat transferred may manifest as thermal energy while work performed may result in mechanical energy.

A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

Hence, you can transfer  sound, which is wave, from one place to another.

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The speed of the motorcycle and rider is 20 m/s.

To solve this problem, we can use the formula for kinetic energy, which relates the kinetic energy of an object to its mass and velocity. The formula is:

KE = 1/2 * m *\(v^2\)

where KE is the kinetic energy, m is the mass of the object, and v is its velocity.

To solve for v, we can rearrange the equation as follows:

\(v^2\)= 2 * KE / m

v = sqrt(2 * KE / m)

Substituting the given values into the equation, we get:

v = sqrt(2 * 60200 J / 302 kg)

Simplifying the equation, we get:

v = \(sqrt(400 m^2/s^2)\)

Taking the square root of 400, we get:

v = 20 m/s

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Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.

Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.

We can use the distancе formula to determine the object's diameter from its origin (0, 0):

Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:

= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.

Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.

Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.

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Velocity of the satellite that is orbiting earth is 83.45m/s, which makes the velocity of the rivet relative before striking also 83.45m/s and the time duration of collision is 4.53× 10⁻⁵ s. The avg force that is exerted by the rivet on the satellite is 9.27N and the energy that is generated by the collision is 1.63J.

a) Velocity of the satellite in an orbit 900 km above Earth's surface can be calculated as follows: Formula: `v = sqrt(GM/r)` Where,v = velocity, M = Mass of Earth, r = radius of the orbit (r = R + h)R = radius of the Earth = 6.37 × 10⁶ mh = height above Earth's surface = 900 km = 9 × 10⁵ mG = 6.67 × 10⁻¹¹ N m²/kg²By substituting the given values, we getv = sqrt((6.67 × 10⁻¹¹ × 5.97 × 10²⁴)/(6.37 × 10⁶ + 9 × 10⁵))= sqrt(6.965 × 10³) = 83.45 m/s.

Therefore, the velocity of the satellite in an orbit 900 km above Earth's surface is 83.45 m/s.

b) Velocity of the rivet relative to the satellite just before striking it can be calculated as follows: Velocity of the rivet, `v_rivet = v_satellite * sin(θ)`Where, v_satellite = 83.45 m/sθ = 90°By substituting the given values, we getv_rivet = 83.45 * sin 90°= 83.45 m/s.

Therefore, the velocity of the rivet relative to the satellite just before striking it is 83.45 m/s.

c) The time duration of collision, `Δt` can be calculated as follows:Δt = (2 * r_rivet)/v_rivet, Where,r_rivet = radius of the rivet = 3/2 × 10⁻³ m. By substituting the given values, we getΔt = (2 * 3/2 × 10⁻³)/83.45= 4.53 × 10⁻⁵ s.

Therefore, the time duration of collision is 4.53 × 10⁻⁵ s.

d) The average force exerted by the rivet on the satellite, `F` can be calculated as follows: F = m_rivet * Δv/ΔtWhere,m_rivet = mass of the rivet = 0.5 g = 0.5 × 10⁻³ kgΔv = change in velocity of the rivet = 83.45 m/sΔt = time duration of collision = 4.53 × 10⁻⁵ sBy substituting the given values, we get F = (0.5 × 10⁻³ * 83.45)/4.53 × 10⁻⁵= 9.27 N.

Therefore, the average force exerted by the rivet on the satellite is 9.27 N.

e) The energy generated by the collision, `E` can be calculated as follows: E = (1/2) * m_rivet * Δv²Where,m_rivet = mass of the rivet = 0.5 g = 0.5 × 10⁻³ kgΔv = change in velocity of the rivet = 83.45 m/s. By substituting the given values, we getE = (1/2) * 0.5 × 10⁻³ * 83.45²= 1.63 J.

Therefore, the energy generated by the collision is 1.63 J.

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Answer:

uxjdkddoedlkfkkllllllllo

The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

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