What is meant by perfect machine​

Answer:

The answer is C.) Lacks all 3 types of antigens.

Answer:

Your average velocity would be 20 m/s.

Explanation:

hope this helped!

Use the definition of average acceleration:

a = ∆v / t

If v is the starting speed, then ∆v = 0 - v, so solve for v :

-6.42 m/s² = (0 - v) / (2.85 s)

v = (6.42 m/s²) (2.85 s)

v ≈ 18.3 m/s

The two basic premises for the special theory of relativity are: The laws of nature are the same for everyone and The speed of light is the same for everyone.

The special theory of relativity, or special relativity is a scientific theory of the relationship which is present between the space and time. In Albert Einstein's original treatment, this theory is based on two postulates including the laws of physics are invariant in all inertial frames of reference and the speed of light in vacuum is the same for all the observers, regardless of the motion of light source or the observer.

This theory applies the principle of relativity only to the inertial frames. Albert Einstein developed general relativity to apply the principle generally, which is, to any frame, and that the theory includes the effects of gravity.

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The electron falls to the third energy level (n=3) after getting excited to an energy level of n=7.ii. To calculate the energy of an electron, use the formula for the energy of an electron in the excited state:En= -2.178 × 10^−18 J × (Z^2/n^2)Where En is the energy of the electron.Therefore, the set of quantum numbers for an electron in 3p orbital is {3, 1, -1, 0, 1}.

Z is the atomic number (1 for hydrogen), and n is the energy level to which the electron jumps. Plugging in the values, we get:En = -2.178 × 10^-18 J × (1^2/7^2) = -0.204 × 10^-18 J(b) i. Orbits are the path that an electron follows around the nucleus. The term orbital refers to the space around the nucleus where an electron is most likely to be found.ii. The electronic configuration of Chromium is [Ar] 3d5 4s1.

The anomalous electronic configuration of chromium arises due to the exchange of an electron from the 4s orbital to the 3d orbital to attain more stability and have a fully filled d subshell.iii. The set of quantum numbers for an electron in the 3p orbital are:n=3, l=1, ml= -1, 0, 1, ms= +1/2 or -1/2.

Chromium is an element that has anomalous electronic configuration. The anomalous configuration arises when an electron from the 4s subshell of the element is excited and moved to the 3d subshell. The ground state electronic configuration of chromium is [Ar] 3d4 4s2. The fourth electron occupies the 4s subshell. It is easier to excite the electron in the 4s subshell and move it to the 3d subshell than removing an electron from the 3d subshell.

This is because the energy required to remove an electron from the 3d subshell is high due to its closeness to the nucleus. Therefore, the configuration becomes [Ar] 3d5 4s1 to attain more stability and have a fully filled d subshell.Quantum numbers for an electron in 3p orbital:The set of quantum numbers for an electron in the 3p orbital are as follows

n = 3 (The principal quantum number which denotes the shell number)l = 1 (The azimuthal quantum number which denotes the sub-shell number and takes values from 0 to n-1)s= +1/2 or -1/2 (The spin quantum number which denotes the spin of the electron)i.e., ml= -1, 0, 1 (The magnetic quantum number which denotes the orientation of the orbitals and takes integer values from -l to +l.)

Therefore, the set of quantum numbers for an electron in 3p orbital is {3, 1, -1, 0, 1}.

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All components of the velocity vector are zero for t = 0, the particle is at rest for t = 0.

For what values of t is the particle at rest?

The position of a particle moving in the xy-plane is given by the parametric equations r = (3t) and v = (2t, 3t², 12t). To find for what values of t the particle is at rest, we need to find when the velocity vector (v) is equal to zero.

The velocity vector v is given by (2t, 3t², 12t). For the particle to be at rest, all components of the velocity vector must be equal to zero.

1. For the x-component (2t) to be zero: 2t = 0. Solving for t, we get t = 0.

2. For the y-component (3t²) to be zero: 3t² = 0. Solving for t, we get t = 0.

3. For the z-component (12t) to be zero: 12t = 0. Solving for t, we get t = 0.

Since all components of the velocity vector are zero for t = 0, the particle is at rest for t = 0.

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Answer:

I'm not to sure but I think the answer is 1.5m/s^2

Explanation:

Acceleration = Change in Velocity over Time.

So we get 15 - 0.0 divided by 10.0 which = 1.5m/s^2

But again I'm no expert I'm learning this stuff just like you guys.

Answ

— How can a small boy balance a big boy on a sea-saw? Show with a diagram. fast please...... Get the answers you need, now!

2 answers

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Explanation:

Answer:

294 mAmps

Explanation:

The two resistors are equal to   22 * 75 / ( 22+ 75) = 17.01 ohm

V = IR

V/R = I

5 / 17.01 = .294 A

Answer:

It depends on the model but these are the watts of each motor

Explanation:

Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).

Answer:

grocery store owner

medical doctor

trial lawyer

When a loose brick is resting on a wall, it has potential energy. When the brick is pushed off the wall and is falling down, the amount of potential energy is decreasing while the amount of kinetic energy is increasing.

Kinetic energy is motion––of waves, electrons, atoms, molecules, substances, and objects. Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy.

Conservation of energy is not saving energy. The law of conservation of energy says that energy is neither created nor destroyed. When we use energy, it doesn’t disappear. We change it from one form of energy into another.

A car engine burns gasoline, converting the chemical energy in gasoline into mechanical energy. Solar cells change radiant energy into electrical energy. Energy changes form, but the total amount of energy in the universe stays the same.

Energy efficiency is the amount of useful energy you get from a system. A perfect, energy-efficient machine would change all the energy put in it into useful work—an impossible dream. Converting one form of energy into another form always involves a loss of usable energy.

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The period of oscillations for the given mass-spring system is approximately 0.350 seconds.

To find the period of oscillations for a mass-spring system, we can use the formula:

T = 2π * √(m / k)

Where:

T is the period of oscillation

π is the mathematical constant pi (approximately 3.14159)

m is the mass of the object (0.820 kg)

k is the spring constant (2620 N/m)

Plugging in the values, we have:

T = 2π * √(0.820 kg / 2620 N/m)

Calculating the square root and simplifying:

T = 2π * √(0.000313) ≈ 2π * 0.017686 ≈ 0.1113π

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Answer:

v = 3.57 m / s

Explanation:

Let's use Newton's second law in the upper part of the circle, with the minimum speed so that the water does not rest on the circle, that is, the normal is zero

          W = m a

acceleration is centripetal

          a = v² / r

let's substitute

         mg = m v² / r

         v = \(\sqrt{r g }\)

let's calculate

        v = \(\sqrt{1.3 \ 9.8}\)ra 1.3 9.8

        v = 3.57 m / s

There are a number of techniques that can be used in the physical sciences to decrease data and analyze faults.

Here are some often employed methods:

1. Averaging: Random mistakes can be minimized by taking numerous measurements of the same amount and averaging the results.

2. Error bars: Using error bars to represent data points gives each measurement's level of uncertainty a visual representation.

3. Error propagation: It's crucial to propagate errors when combining different measurements or employing observed quantities in calculations.

4. Instrument and equipment calibration helps to cut down on systematic mistakes. You may account for and correct any differences in your measurements by comparing them against recognized reference standards.

5. Control experiments: By performing control experiments, the sources of mistake can be found and measured since the variable of interest is consciously left out or maintained constant.

6. Replication: By carrying out experiments more than once, researchers can gauge how reliable and consistent their findings are.

7. Regression analysis and hypothesis testing are two statistical techniques that can be used to discover and quantify error sources, as well as to assess the relevance of the results and the dependability of the data.

8. Conducting an exhaustive uncertainty analysis is essential for comprehending the constraints and potential flaws in the data.

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The complete question is:

What methods can be used to reduce data and analyze errors in the physical sciences?

The percentage of weight that should be in front of the trailer is 60%

According to the GMC Trailering Guide, to get the right trailer tongue weight, you should concentrate about 60% of the load evenly on the front half of the trailer. 60% of the trailer load should be in front of the axle and 40% behind it. This ensures the correct weight of the tongs and prevents the trailer from rocking. Weight distribution should be as efficient as possible by placing 60% of the weight in the front of the trailer and 40% in the rear. There are some additional safety precautions to consider. 

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Answer:

gamma decay

Explanation:

Answer:       gamma decay

Explanation:      I took the test

Answer:

This demonstration is often done following a discussion of the ideal gas equation of state, PV=nRT.

We begin by weighing a balloon, then blowing it up and weighing it again. In the photo shown on right, the mass indication increased from 3.4 to 3.5 grams. At this point, it is important to note that the scale measures force, even though it reports a conclusion about mass based on the force measurement.

One assumption made in reaching the conclusion is that the buoyant force on the object being weighed is negligible. In the case of the balloon, this is incorrect. The buoyant force on this balloon is equal to the weight of the air displaced.

Since the volume of air inside the balloon is essentially the same as the volume of air displaced, we should expect that the buoyant force would support the weight of the air inside the balloon: The reported mass should not go up at all, because the force required of the scale should not change.

The increase in reported mass of .1 gram is attributed to the higher density of the air inside the balloon: The tension in the balloon compresses the air inside, as attested by the pressure required to blow the balloon up. Evidently, for this experiment, the pressure inside is greater than atmospheric by about 2%.

In the picture at right, the balloon is being pressed into a pan of liquid nitrogen. (The pan is the styrofoam lid of a small lunch box.) The balloon floats lightly on the liquid nitrogen unless pressed down. Pressing down places more surface area in contact with the cold nitrogen and speeds the demonstration. It is interesting to note the buoyant force by this liquified constituent of air.

The balloon shrinks dramatically, as indicated below. When left in contact with the liquid nitrogen long enough (perhaps 5 minutes) the oxygen inside the balloon liquifies, and then the nitrogen liquefies also. Close observation of the photo at the upper left corner of the pan shows some liquid nitrogen bubbles may forming above the dark spot in the center of the pan. One can also make out a faint line at the upper left corner of the pan which is the liquid nitrogen surface. The balloon still floats, riding rather high on that surface. Evidently, some of the balloon contents remain in the gas phase, making the mass of the balloon less than the mass of the displaced liquid nitrogen.

Next, we take the shrunken balloon and place it back on the scale, as above. In this instance, the reported mass is 8.7 grams, an increase of 5.2 grams.

A look at the figure on the right shows a faint line near the bottom of the cold balloon. Above that line, the balloon contains gas; below the liquid. That line represents the top surface of the liquid air inside the balloon. With this evidence, the easy thing to say would be, "Of course, liquids are heavier than gases," but that would be incorrect. We assert that the amount of air inside the balloon has not changed and that the mass of that air is not dependent on temperature.

If these assertions are true, then the force of gravity on the balloon has not changed. The scale reading is determined by the force which it must exert on the balloon in order to keep it stationary. Evidently, the required force is larger when the balloon is shrunken. The reason is that the buoyant force (upward) has decreased to practically zero, leaving the scale alone to balance the downward force by gravity.

From the data, we can say that the change in the buoyant force is equal to the weight associated with the apparent change in mass. The weight of 5.2 grams is about .052 newtons. The buoyant force is less now because the balloon displaces less air. If we could measure the change in volume of the balloon as DV, then the buoyant force would be (r g DV) upwards, where r is the density of air that was displaced by the balloon, and g is the gravitational field strength, 9.8 Newton/kg.

Note that the .052 newton force is not the weight of the air inside the balloon. Rather, it is the weight of the air that was displaced by the balloon. If we ignore the compression of air inside the balloon, the two numbers are the same. However, the two samples are completely different.

We can estimate the volume of the balloon by assuming that the hand in the photograph is about .1meters across. For purposes of estimation, we say that the volume shrank to almost zero when the balloon was cold so that the change in volume was nearly equal to the original volume. Plugging in numbers gives fair agreement with the book value of 1kg/cubic meter for the density of air.

The value for the density of air is secondary to two main features of this demonstration:

Large changes in temperature produce the large changes in volume that are indicated by the ideal gas equation.

The mass of air in a volume equal to the volume of a balloon can be determined provided that the buoyant force is understood.

Answer:

The answer is below

Explanation:

The efficiency of a machine is the ratio of its output to its input. The efficiency shows how effective the machine by the way it converts the input energy into work. The higher the efficiency of the machine the more effective it is. The efficiency is usually less than 1.

Given that the machine uses diesel oil (input) that can produce 3.0 x 10⁹ J of energy while the work performed by the machine (output) is 2.7 x 10⁸ J. The efficiency is given as:

Efficiency = output / input = 2.7 x 10⁸ J / 3.0 x 10⁹ J = 0.09 = 9%

This means that the machine is not effective because of its low efficiency

The time taken to reach the highest point, given that the rocket was fired with a velocity of 29 m/s is 2.96 s

First, we shall list the various parameters obtained from the question. Details below:

v = u - gt

0 = 29 - (9.8 × t)

0 = 29 - 9.8t

Collect like terms

0 - 29 = -9.8t

-29 = -9.8t

Divide both side by -9.8

t = -29 / -9.8

= 2.96 s

Thus, the time taken is 2.96 s

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Answer:

Biodiversity is the biological variety and variability of life on Earth. Biodiversity is a measure of variation at the genetic, species, and ecosystem level. Terrestrial biodiversity is usually greater near the equator, which is the result of the warm climate and high primary productivity.

Answer:

Bio means life

Explanation:

Biodiversity means life on earth.

Given data:

* The force applied on the ball is F = 900 N.

* The time of contact between Bob and the ball is t_1 = 0.3 s.

* The time of contact between Jill and the ball is t_2 = 0.6 s.

Solution:

The impulse applied by the bob is,

The impulse applied by Jill is,

Thus, the impulse applied by Jill is more than the impulse applied by Bob.

Hence, 4th option is the correct answer.

Answer:

609.6 cm is the answer

Answer:

Lookback time explains that the farther away something is, farther in the past we see it. The Sun's light takes about 8 minutes to reach our eyes. So in reality, we see the Sun as it was 8 minutes ago.

Explanation:

The mallet in contact with the ball is 2.4 milliseconds.

The amount of time that the mallet was in contact with the ball can be calculated using the equation for impulse, which is equal to the change in momentum. Force and time combine to create an impulse.. Mathematically, it can be expressed as:

Impulse = Change in Momentum = F * t

Change in momentum is the product of mass and change in velocity.Therefore, the time that the mallet was in contact with the ball can be calculated as follows:

\(t = \frac{Impulse }{F }\\ \\= \frac{(0.45 kg * 1.3 m/s) }{ 83 N }\\\\= 2.4 milliseconds\)

Therefore,The mallet in contact with the ball is 2.4 milliseconds.

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The final velocity of the red-blue carts system is 5 cm/s.

The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.

Pi = Pf

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

m₁u₁ + 0 = v ( m₁ + m₂ )

m₁u₁ = v ( m₁ + m₂ )

v = ( m₁u₁ ) / ( m₁ + m₂ )

The final velocity of the red-blue carts system is calculated as;

v = ( 50 kg cm/s ) / ( 5 kg + 5kg )

v = 5 cm/s

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The complete question is below:

A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.

When two disks of identical mass but different radii are brought slowly together while spinning on frictionless bearings at the same angular speed but in opposite directions, the resulting frictional force increases due to the increase in angular velocity caused by the change in moment of inertia of the system.

Angular momentum is given by the equation L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia of a rotating object depends on its mass and how that mass is distributed around its axis of rotation.

In this scenario, the disks have the same mass but different radii. The moment of inertia of a disk is given by the equation I = (1/2)mr^2, where m is the mass and r is the radius. Since the disks have the same mass, their moments of inertia will be proportional to their radii squared.

Since the disks are rotating in opposite directions, the change in angular momentum due to their interaction will be the sum of their individual angular momenta. The change in angular momentum is given by ΔL = Lfinal - Linitial.

As the disks are brought closer, their moments of inertia decrease. Therefore, in order to conserve angular momentum, the angular velocity ω will increase. This increase in angular velocity results in an increase in frictional force between the disks.

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Explanation:

A. Something that occupies a volume of space and also has mass