What is Motion Under Gravity.​

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:

True

Explanation:

have a good day:)

Answer: This statement is True

Answer:

B.) These elements are high in electronegativity

Explanation:

As you move right on the periodic table, the atoms get bigger. Atoms with more electrons have more shells. As the number of shells increase, the outermost electrons get further from the nucleus. As they get further from the nucleus, the protons have less of a hold on the electrons. This means they are more easily removed.

The elements on the top right of the table are smaller, and this means that the protons exert a greater force on their electrons. These factors make it difficult to remove their outermost electrons, increasing ionization energy.

Answer:

A. their atomic radius is small

and

D. they have fewer electron shells to shield the protons from the electrons

Explanation:

Got it right on test.

While certain types of glass containers may be suitable for short-term storage of vinegar, it is generally recommended to use non-reactive materials, such as plastic or stainless steel, for long-term storage to avoid any potential chemical reactions or corrosion.

Vinegar is an acidic liquid that contains acetic acid. When vinegar comes into contact with certain types of glass, particularly those made of lead or other reactive materials, a chemical reaction can occur. This reaction can lead to the leaching of potentially harmful substances into the vinegar.

Glass containers made from specific types of glass, such as soda-lime glass, are generally safe for storing vinegar.

However, it is important to note that prolonged storage or exposure to vinegar can still cause the glass to corrode over time. This can result in the deterioration of the glass container, potentially leading to breakage or the release of glass fragments.

To avoid any potential issues, it is recommended to use containers made of non-reactive materials, such as food-grade plastic or stainless steel, for long-term storage of vinegar. These materials do not react with the acidic nature of vinegar and do not pose a risk of leaching harmful substances.

Additionally, it is important to store vinegar in a cool, dark place to maintain its quality and prevent spoilage. Exposure to light and heat can degrade the quality of vinegar over time.

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To calculate the final temperature of an air-metal mixture, we need to use the principle of heat transfer.

The heat transfer equation states that the heat gained by the metal is equal to the heat lost by the air. This equation can be written as:

mcΔT = mairCpΔT

To make a prediction of the final temperature, we need to consider factors such as the thermal conductivity of the metal and air, the specific heat capacities of the materials, and the heat transfer coefficients at the metal-air interface. Additionally, the shape and size of the metal object and the surrounding environment can affect the final temperature.

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Solution :

Let \($d_1=\frac{5.5}{2}\)

          = 2.75 m

\(d_2 = 0.21 \ m\)

And \($d=|d_1-d_2|$\)

       \($d=(d_1+d_2) - (d_1-d_2)$\)

       \($d=(2.75+0.21) - (2.75-0.21)$\)

       \($d = 2.96-2.54$\)

       \(d = 0.42 \ m\)

a). At minimum,

\($d=\frac{\lambda}{2}$\)

\($\lambda = 2d$\)

  = 2 x 0.42

  = 0.84 m

Frequency, \($\nu = \frac{v}{\lambda}$\)

                      \($=\frac{340}{0.84}$\)

                      = 404.76 Hz

Therefore, the frequency of he sound, \($\nu$\) = 404.76 Hz

b). At maximum, λ = d = 0.42 m

Therefore, the frequency, \($\nu = \frac{v}{\lambda}\)

                                             \($=\frac{350}{0.42}$\)

                                             = 809.52 Hz

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

Explanation:

Let the spring constant of spring A and B be k₁ and k₂ . Mass of box X and Y be m₁ and m₂ .

Force created in spring which is stretched by d is kd where k is spring constant .

At her lab in Orlando, Florida,

k₁ x .0204 m = m₁ g where g is acceleration due to earth's gravity

k₁ = 49 m₁ g

At a research station on the moon

k₁ x .34 x 10⁻² m = m₁ g₁ where g₁ is acceleration due to gravity at moon

k₁  = 294 .11 m₁ g₁

49 m₁ g = 294 .11 m₁ g₁

g = 6.0022  g₁

At a research station on the moon

k₁ x .54 x 10⁻² m = m₂ g₁

k₁ = 185.18 m₂ g₁

294 .11 m₁ g₁ = 185.18 m₂ g₁

1.588 m₁ =  m₂

1 )

At her lab in Orlando, Florida,

k₁ x d  = m₂ g , where d is the new stretch that is to be calculated .

185.18 m₂ g₁ d =m₂ g

185.18 d  g₁ = g

185.18 d  g₁ = 6.0022  g₁

d = .03241 m

= 3.24 cm .

2 )

At a research station on the moon

when Block Y is hanging from Spring B

k₂ x .013   = m₂ g₁

k₂ = 76.92 m₂ g₁

At her lab in Orlando, Florida,

Spring B stretch when Block X is hanging from it

k₂ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ 6.0022  g₁

76.92 m₂  d₁ = m₁ 6.0022  

12.815  x  1.588 m₁ x  d₁ = m₁

d₁ = .049 m

= 4.9 cm .

In this exercise we have to use the knowledge of springs to calculate the distance from it, that way:

A)d=3.24 cm

B)d=4.9 cm

So, before starting the calculations, we have to organize the values ​​and put everything in function of a single unknown such as:

\(k_1 * 0.34 * 10^{-2} m = m_1 g_1\\ k_1 = 294 .11 m_1 g_1\\49 m_1 g = 294 .11 m_1 g_1\\g = 6.0022 g_1\\k_1 *0 .54 * 10^{-2} m = m_2 g_1\\k_1 = 185.18 m_2 g_1\\294 .11 m_1 g_1 = 185.18 m_2 g_1\\1.588 m_1 = m_2\)

A) By calculating the distance we find that:

\(k1_1 * d = m_2 g\\185.18 m_2 g_1 d =m_2 g\\185.18 d g_1 = g\\185.18 d g_1 = 6.0022 g_1\\d = 0.03241 m= 3.24 cm\)

B) So now calculating the distance from the lab to the moon, so:

\(k_2* 0.013 = m_2 g_1\\k_2 = 76.92 m_2 g_1\\k_2 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_16.0022 g_1\\76.92 m_2 d_1 = m_1 6.0022\\12.815 * 1.588 m_1 * d_1= m_1\\d_1 = 0.049 m = 4.9 cm\)

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Mass of the second object located at a distance r from the origin, r^ is the unit vector in the radial direction, and the negative sign indicates that the force

The System can refer to a set of interacting or interdependent components forming an integrated whole. The term can be applied to various fields, including physics, engineering, biology, and social sciences, among others. In physics, a system typically refers to a collection of objects or particles that are studied together, often with the goal of understanding the behavior of the system as a whole. In engineering, a system can refer to a group of components that work together to perform a specific function, such as an electrical power grid or an automobile engine. In biology, a system can refer to an organism or group of organisms that interact with their environment, such as an ecosystem or the human body.

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Answer:

A

Explanation:

1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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Answer:

11

Explanation:

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:

F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N

The acceleration of the train is given by the formula:

a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²

Therefore, the acceleration of the train is 0.3 m/s².

(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:

Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z

(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:

R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N

The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:

a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²

Therefore, the new acceleration of the train is 0 m/s².

(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:

F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N

The force in the coupling between trucks Y and Z is a tension.

When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:

F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N

The force in the coupling between trucks Y and Z is a thrust.

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The energy input at aphelion (farthest from the sun) is 92% of the intensity at perihelion (closest to the sun) because of the inverse-square law, which states that the intensity of radiation decreases with the square of the distance from the source.

However, the difference in energy input does not solely explain the difference in surface temperature from winter to summer.

Other factors, such as the Earth's axial tilt, atmospheric composition, and cloud cover also play a role in determining the surface temperature.

Evidence from climate models and observations indicate that changes in these factors, especially changes in the number of greenhouse gases in the atmosphere, can have a significant impact on global temperature patterns.

In conclusion, while the inverse-square law affects the intensity of solar radiation, it is not the sole factor in determining surface temperature, and the role of other factors must be considered to fully understand seasonal and climatic variations.

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Answer:

new vibration frequency is 3/2 times the original frequency, and the new 3rd harmonic frequency is 9/2 times the original frequency

in 3rd harmonic 260hz = 780 hertz ~384.349305 kilometers

Explanation:

wave speed equation

Assuming the original length of the string is L and its vibration frequency is 260 Hz, the speed of sound in the string can be calculated as follows:

v = fλ

where v is the speed of sound, f is the vibration frequency, and λ is the wavelength of the standing wave.

For the fundamental frequency (1st harmonic), the wavelength is twice the length of the string:

λ1 = 2L

So, we have:

v = f1 λ1

f1 = v/λ1 = v/(2L)

For the new length of the string (2/3 L), the wavelength of the fundamental frequency is:

λ'1 = 2/3 L

The new vibration frequency (f') can be calculated as follows:

v = f' λ'1

f' = v/λ'1 = v/(2/3 L) = 3v/(2L)

So, the new vibration frequency is:

f' = 3f1

Substituting f1 = v/(2L) into the above equation gives:

f' = 3v/(2L)

Now, we can calculate the new 3rd harmonic frequency (f'3) using the formula:

f'3 = 3f'

Substituting f' = 3v/(2L) into the above equation gives:

f'3 = 9v/(2L)

Therefore, the new vibration frequency is 3/2 times the original frequency, and the new 3rd harmonic frequency is 9/2 times the original frequency.

chatgpt

Here is how you can tell if a fat is saturated or not:

It has to stay normal at room temperature and melt when heated.

Here is an example for you:

If there is a fat that stays normal when it is outside, but melts when heated, it is a saturated fat. It did what every other saturated fat would do.

Carry on Learning!

A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

It is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

A metallic rod of mass 150 g (m) absorbs 82.5 cal of heat (Q) and its temperature raises from 20 °C to 25 °C. We can calculate the specific heat (c) of the metal using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 82.5 cal / 150 g × (25 °C - 20 °C) = 0.11 cal/g.°C

A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

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Answer:

The two poles closest to each other are opposite magnetic poles

Explanation:

Just took the test

Answer:

its all of them

Explanation:

Answer:

2 m/s².

Explanation:

The following data were obtained from the question:

Mass (m) of hammer = 5 Kg

Mass (m) of nail = 0.25 kg

Force (F) applied = 10 N

Acceleration (a) of nail = 40 m/s².

Acceleration (a) of hammer =?

From Newton's third law which states that to every action, there is an equal but opposite reaction. This implies that the force applied by the hammer on the nail is exactly the force applied by the nail on the hammer. Thus, we can obtain the acceleration of the hammer as follow:

Mass (m) of hammer = 5 Kg

Force (F) applied = 10 N

Acceleration (a) of hammer =?

F = ma

10 = 5 × a

Divide both side by 5

a = 10/5

a = 2 m/s²

Thus, the acceleration of the hammer is 2 m/s².

The object requires the MOST power to lift  a 2 kg box 2 m in 1 s. Hence, option (B) is correct.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.

Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.

Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.

Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.

So, The most power required in  lifting a 2 kg box 2 m in 1 s.

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The total distance moved or the total path covered by the dog is 34 m.

The given parameters;

initial distance of the dog, = 14 m east

final distance of the dog, = 20 m west

Distance is defined as the total path covered by an object. It is a scalar quantity because it can only be represented in magnitude only.

The total distance moved by the dog is calculated as follows;

distance = 14 m + 20 m

distance = 34 m

Thus, the distance moved or the total path covered by the dog is 34 m.

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Answer:

1.) Q T U W 

Explanation:

1.) QTUW

2.) UW

3.) QU

4.) QTUC

According to first law of thermodynamics

dU = Q - W

Where

dU = change in internal energy

Q = heat added

W = work done by the system

2.) UW

Work is been done on the system. The pressure will surely distort the internal energy of the system

Pressure = Force/area.

3.) QU

The melting process begins because the air temperature around the ice cubes is warmer

The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another.

4.) Chemical reaction can be exothermic or endothermic which involves absorption or release of heat. Since it is subjected to small spark, there is definitely a change in internal energy.

In this exercise we have to have knowledge about thermodynamics in order to identify the alternatives that are correctly classified, so we can say that:

1.) QTUW

2.) UW

3.) QU

4.) QTUC

According to first law of thermodynamics:

\(dU = Q - W\)

Where:

1.) The first alternative corresponds to:

In other words QTUW.

2.) The second alternative corresponds to:

Work happen been finished ahead of the system. The pressure will without doubt deform the internal strength of bureaucracy:

\(Pressure = Force/area\)

In other words UW.

3.) The third alternative corresponds to:

The softening process begins cause the air coldness of some degree around the frozen water cubes happen warmer The complete frozen water particles take in heat strength from the warmer air, bestowing the piece energy and allowing to happen them to move out each one.

In other words QU.

4.) The fourth alternative corresponds to:

Chemical reaction maybe exothermic or endothermic that involves assimilation or release of heat. Since it happen commit small spark, skilled happen certainly a change in within strength.

In other words QTUC

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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The focal length of the curved mirror is 6.67 meters.

The focal length of a curved mirror can be calculated using the mirror equation:

1/F = 1/Do + 1/Di

Where:

F = focal length of the mirror,

Do = distance of the object from the mirror and

Di = distance of the image from the mirror

In the given case, the object is located 2 meters in front of the mirror and the image is located 1.3 meters behind the mirror. Therefore:

according to the given data:

Do = 2 m

Di = -1.3 m (negative sign indicates that the image is behind the mirror)

Substituting in the equation, we get:

1/f = 1/2 - 1/1.3

Simplifying:

1/f = 0.15

Multiplying both sides by f:

= 6.67 meters

Therefore, the focal length of the curved mirror is 6.67 meters.

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The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.

Answer:

The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.

Question:

Why did you lie about being in college?

Answer:

The pole stores gravitational potential energy because it is bent from its natural shape when off the ground.

Explanation: i took the test

Given the mass of the object, m = 2 kg

Distance between point A and B, h= 20 m

(a) To find work done in moving the object from A to B

Work done is

Here, g is the acceleration due to gravity whose value is 9.8 m/s^2.

Substituting the values, we get

(b) To find work done in moving the object from A to C

Gravitational force is a conservative force and work done depends only on the initial and final position and not on the path.

So, the work done will be