what is one major limitation of using solar energy for electricity production? responses solar energy can never be used in areas where it rains or snows. solar energy can never be used in areas where it rains or snows. solar energy cannot be transferred directly into electrical energy. solar energy cannot be transferred directly into electrical energy. solar energy must be stored or supplemented for electrical use at night. solar energy must be stored or supplemented for electrical use at night. solar energy can never be used outside the tropics, where the sun is most intense.

Answer:

the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

Explanation:

Answer:

The drum drill is just one option in stride frequency development. Most of the time, the drum drill can be seen as just a rhythm drill that allows an athlete to relax and experiment with the right range of motion and bounce. A solid background in floating drills and developing reactivity should help athletes mold their stride into a balanced motion that maximizes their speed.

I have used frequency drills for years and now understand the nature of stride development mainly from shaping the stride parameters we all have known about for a long time. The drum drill is a special exercise that can make a great change in athletes who are receptive to improving and with a coach who is worth their salt in instruction. The drum drill is just one option for improving an athlete, and it’s more than fine to use any method you see fit that helps improve stride frequency.

Explanation:

Explanation:

Most of the time, the drum drill can be seen as just a rhythm drill that allows an athlete to relax and experiment with the right range of motion and bounce. A solid background in floating drills and developing reactivity should help athletes mold their stride into a balanced motion that maximizes their speed

We break down a UK drill beat, a genre that rapidly became one of the ... Beat Dissected is a regular series in which we deconstruct drum patterns, ... an 808 bass line with plenty of glides and a piano played back in halftime.

As you descend into a lake from just below the surface to 10 feet under the surface, the net pressure force on your body increases while your weight stays the same. This is because the deeper you go, the more water there is above you, creating more weight and pressure.

The net pressure force on your body is the difference between the pressure on your skin from the water pushing down and the pressure inside your body pushing out. The deeper you go, the greater the pressure from the water pushing down on your body. However, your weight stays the same because the water you displace (the water you push out of the way as you descend) weighs the same as your body.

Therefore, the correct answer is that the net pressure force on your body increases and your weight stays the same as you descend from just below the surface to 10 feet under the surface. It's important to note that this increase in pressure can have physiological effects on your body, such as changes in heart rate and breathing, which is why it's important to take precautions when diving or spending extended periods of time underwater.

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Answer:

1.667 m/s ^2

Explanation:

we use the formula F=ma

F= 12.5 N

m= 7.5 kg

a=?

F=ma

12.5= 7.5 x a

a= 12.5/7.5

a= 1.667 m/s^2

The capacitor is the energy storage device in the form of electrical energy and the capacitance is the ratio of charge and potential difference between capacitors.

The capacitance in the parallel plate capacitor is directly proportional to the area of the conductor and inversely proportional to the distance between the capacitors. The unit of capacitance is Farad(F).

1) Capacitance of the parallel plate capacitor is directly proportional to the area of the conductors and hence Area increases, the capacitance also increases.

2) Capacitance is inversely proportional to the distance between the capacitors and hence distance between the capacitors increases, Capacitance decreases.

3)  C = ε₀A/d, where A is the area of the capacitor and d is the distance between the capacitor, and C is the capacitance of the capacitor. The capacitance of the parallel plate capacitor is directly proportional to the area of the parallel plate capacitor and d is the distance of separation of plates.

4) If two identical capacitors are connected in parallel, the potential across the capacitors are same and the charge in the capacitors is different.

5) If the system has two capacitors connected in parallel, the charges remain unchanged and hence the net charge is equal to the individual charges of the capacitors. The net charge of the system is, Q = Q₁+Q₂. Q₁=C₁V and Q₂=C₂V, Q = V(C₁+C₂).

6) The device used to measure the decay of voltage in an RC circuit is the voltmeter. Voltmeter is a device used to measure the potential difference between two points.

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The Rio Grande is one of the largest river systems in the United States, running over 3,000 kilometers from the mountains of Colorado to the Gulf of Mexico. The river flows from north to south and passes through several states, including Colorado, New Mexico, and Texas.

A comparison of the discharge of the Rio Grande at Albuquerque and at Otowi Bridge (located upstream, near Santa Fe) is as follows: Albuquerque: It is the largest city in New Mexico, situated in the central part of the state. The Rio Grande flows through the city, where it is dammed to form a large lake known as Elephant Butte Reservoir. The discharge of the Rio Grande at Albuquerque is around 100 cubic feet per second (cfs) during normal conditions.

This means that the river has twice the volume of water at Otowi Bridge than at Albuquerque.During times of drought, the river's discharge can drop to dangerously low levels, affecting wildlife and human communities that rely on the river for water. The river's discharge can also increase during periods of heavy rainfall or snowmelt, leading to flooding in downstream communities.

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Answer:

It takes 1.14 s to move the box 4.20 m.

Explanation:

Using Newton's second law we have:

\(Fcos(35)-F_{f}=ma\)

\(Fcos(35)-\mu mg=ma\)

F is the force exerted and m the mass of the books

\(Fcos(35)-\mu mg=ma\)

\(477cos(35)-(0.58*315)=\frac{315}{9.81}a\)

So, the books accelerate at:

\(a=6.48\: m/s^{2}\)

We know that the initial velocity is zero, so using the kinematic position equation, we have:

\(x=\frac{1}{2}at^{2}\)

So, we just need to solve the equation for t.

\(4.2=\frac{1}{2}6.48t^{2}\)

\(t=\sqrt{\frac{2*4.2}{6.48}}\)

Taking the positive value of t:

\(t=1.14\: s\)

Therefore, it takes 1.14 s to move the box 4.20 m.

I hope it helps you!

Answer:

i believe the answer is c

The work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min would be 196000 kJ.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force ×  Displacement

As given in the problem we have to calculate the work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min.

The weight of the 100 kg = 100 × 9.8

                                          = 980 N

The work done = 980 × 200 × 1000

                          = 196000000

                          = 196000 kJ

Thus, the work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min would be 196000 kJ.

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Explanation:

Underneath the blade of skates, there is a thin layer of water from the melted ice. ... This water then acts as a lubricant (something whose purpose is decreasing friction), resulting in a smooth motion of the skates over the ice.

The magnetic field in the solenoid is 0.028 T. To calculate the magnetic field in the solenoid, we can use the formula B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current.

First, we need to calculate the number of turns per unit length. We know that the solenoid has 200 loops and is 60 cm long, so the number of turns per unit length (n) is:

n = N / L
n = 200 / 0.6
n = 333.33 turns/m

Next, we can substitute the values into the formula:

B = μ₀nI
B = (4π x 10^-7 Tm/A) x (333.33 turns/m) x (1.2 A)
B = 0.028 T

Therefore, the magnetic field in the solenoid is 0.028 T.

The magnetic field in a solenoid with 200 loops and a length of 60 cm and a current of 1.2 A is 0.028 T. This can be calculated using the formula B = μ₀nI, where n is the number of turns per unit length and I is the current. The number of turns per unit length is calculated by dividing the number of loops by the length of the solenoid. The magnetic field can then be calculated by substituting the values into the formula.

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They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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The ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 will be the ratio of the angular velocity.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices.

It should be noted that the tangential speed can alternatively be represented as;

\(\rm v_t= r\frac{d\theta}{dt}\)

where,

θ  is the comet's position angle with respect to some given direction.

The amount dθ/dt is known as angular speed

The ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 IS;

\(\rm \frac{v_1}{v_2} = \frac{\frac{d \theta_1}{dt_1} }{\frac{d \theta_2}{dt_2} } \\\\\ \frac{v_1}{v_2} =\frac{\omega_1}{\omega_2}\)

Hence,the ratio v1/v2 of the speed of the comet at position 1 to the speed at position 2 will be the ratio of the angular velocity.

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image is formed at a distance 10 cm in front of the mirror

the focal length of concave mirror is 8cm.

What is concave mirror ?

A concave or converging mirror has a reflective surface that is recessed inward (away from the incident light). A concave mirror reflects light inwards towards a focal point. They are used to focus light. Unlike convex mirrors, concave mirrors display different types of images depending on the distance between the object and the mirror.

The mirror is called a "collecting mirror". This is because they tend to collect the light that hits the mirror and refocus the parallel incident rays to a focal point. This is because the normal to the mirror surface is different at each point, so light is reflected at different angles at different points on the mirror.

Given u=40 cm (negative)

m=14 (negative for the real image)

a. From m=−vu,−14=−v(−40) or v=-10 cm

Thus the image is formed at a distance 10 cm in front of the mirror.

b. Now from relation 1u+1v=1f

1f=1(−40)+1(−10)

=−540

or f=−405=−8cm

i.e., the focal length of concave mirror is 8cm.

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To find the unit time for the 4th and 6th units when unit 1 has a learning rate of 87% and 18,000 hours, we can use the learning curve formula. The formula is:
Unit Time = First Unit Time * (Unit Number)^(log₂(learning rate))
The unit time for the 4th unit is approximately 14,859.2 hours, and the unit time for the 6th unit is approximately 13,355.5 hours.

For the 4th unit, we can calculate the unit time as follows:
Step 1: Unit Number = 4 (since we want the 4th unit)
Step 2: First Unit Time = 18,000 hours (given in the question)
Step 3: Learning Rate = 0.87 (87% as a decimal)
Now, plug these values into the formula:
4th Unit Time = 18,000 * (4)^(log₂(0.87))
4th Unit Time ≈ 18,000 * (4)^(-0.1843)
4th Unit Time ≈ 14,859.2 hours
For the 6th unit, follow the same process:
Step 1: Unit Number = 6 (since we want the 6th unit)
Now, plug these values into the formula:
6th Unit Time = 18,000 * (6)^(log₂(0.87))
6th Unit Time ≈ 18,000 * (6)^(-0.1843)
6th Unit Time ≈ 13,355.5 hours
So, the unit time for the 4th unit is approximately 14,859.2 hours, and the unit time for the 6th unit is approximately 13,355.5 hours.

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Answer: tendons connect muscles to bones

Explanation:

The Michaelis constant (Km) is the substrate concentration at which the initial velocity of an enzyme-catalyzed reaction is half of the maximal velocity (Vmax). the Michaelis constant (Km) can be found from a saturation plot by C) "It is the substrate concentration at 1/2 Vmax."

Therefore, it can be obtained from the saturation curve at half of the Vmax. Substrate concentration is plotted on the X-axis of a Michaelis–Menten curve, and reaction velocity is plotted on the Y-axis. The Michaelis constant Km is given by the equation:

Vmax = [E] kcatwhere kcat is the turnover number and [E] is the enzyme concentration. The turnover number represents the number of substrate molecules that can be transformed into products by each active site per second at a maximum catalytic activity. The maximum velocity (Vmax) is reached when all enzyme active sites are fully saturated with substrate. The Michaelis constant can be determined from the saturation curve at half the Vmax.

The answer is that the Michaelis constant (Km) can be found from a saturation plot by C) It is the substrate concentration at 1/2 Vmax.

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Answer:

Its  answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

An object accelerates at 32 m/s² when a force of 71 N is applied to it. The object’s mass is calculated as 2.21 kg.

To find the mass, the given values are,

Acceleration = 32 m/s²

Force = 71 N.

Here, the object's mass can be calculated using the formula,

Mass = force/acceleration

        = 71/32

        = 2.21 kg

Hence, the object's mass is 2.21 kg.

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These are Some climates

Tropical.

Dry.

Temperate.

Continental.

Polar.

And these are some biomes

aquatic, grassland, forest, desert, and tundra,

The average force exerted on the bullet by the ammunition is 1215.88N

From the question above, It is given that,

Mass of the bullet, m = 7.50 g

Initial speed of the bullet, u = 0          

Final speed of the bullet, v = 555 m/s

We need to find the force exerted on the bullet while it was traveling down the 0.950m length of the barrel of the rifle. Let:

a is the acceleration of the bullet. So,

v² - u² = 2ad

v² = 2ad

a = v²/2d

a = 555²/2*0.950

a = 162118.42m/s²

Let F be the force exerted. It is given by:

F = Ma

F = 7.5 * 10⁻³ * 162118.42

F = 1215.88N

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F = 1590.87 N

So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.                                                  

 Here  the answer = 0.0080 .

Based on stokes law,

 v = g * D^2 *(d p - d m) / (18 V)

v = terminal velocity

D =  diameter of particle

V  =  Viscosity

dp =  density of particle

dm =  density of medium.

Here density of ball = 1.42 gm/cc

By substituting,

v = 9.81 x 9.52 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0

=5.92x10^-4

 v(t) =0 .99 x Vtrm

  =0 .99 x  0.0059

  = 0.00059 m/s

  v(t)/Vterm =1-e^(-t/r)

  0.99 = 1 - e ^ (-t / 9.52 x 10^-3)

  e ^ (-t / 9.52 x 10^-3) = 0.01

Taking log

 -t / 9.52 x 10^-3 = -4.6

  t = 0.0438 s

Then smaller ball

v = 9.81 x 2.38 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0

= 0.000037 m/s

v(t) / Vterm = 1-e^(-t/r)

0.99 = 1 - e ^ (-t / 2.38 x 10^-3)

e ^ (-t / 2.38 x 10^-3) = 0.01

Taking log

-t / 2.38 x 10^-3 = -4.6

  t = 0.0109 s

Here Reynolds number is,

R= rho vd / mu

= 1420 x  0.00059 x 9.52 x 10^-3 x / 1.0

= 0.0080

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Answer:

Isn't it technically your brain? Because it's always in your skull and when you're younger you have cracks in your skull but as you grow, your skull fossilizes to mend those cracks. IT FOSSILIZES!

Explanation:

When an electron in a hydrogen atom jumps from n = 3 to n = 2, the frequency of the emitted electromagnetic radiation is approximately 19.65 x 10^7 H

To calculate the frequency of electromagnetic radiation emitted when an electron in a hydrogen atom jumps from energy level n = 3 to n = 2, you can use the Rydberg formula:

1/λ = R_H × (1/n_final^2 - 1/n_initial^2)

where λ is the wavelength of the radiation, R_H is the Rydberg constant for hydrogen (approximately 1.097 x 10^7 m^-1), and n_final and n_initial are the final and initial energy levels, respectively.

To find the frequency (f) of the radiation, you can use the equation:

f = c / λ

where c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s).

Given:

n_final = 2

n_initial = 3

Let's calculate the frequency:

Using the Rydberg formula:

1/λ = R_H × (1/n_final^2 - 1/n_initial^2)

1/λ = 1.097 x 10^7 m^-1 × (1/2^2 - 1/3^2)

1/λ = 1.097 x 10^7 m^-1 ×(1/4 - 1/9)

Calculating the result:

1/λ = 1.097 x 10^7 m^-1 × (9/36 - 4/36)

1/λ = 1.097 x 10^7 m^-1 × (5/36)

1/λ = 0.1526 x 10^7 m^-1

Now, let's calculate the frequency using the equation f = c / λ:

f = c / λ

f = (3.00 x 10^8 m/s) / (0.1526 x 10^7 m^-1)

f = 19.65 x 10^7 Hz

Therefore, when an electron in a hydrogen atom jumps from n = 3 to n = 2, the frequency of the emitted electromagnetic radiation is approximately 19.65 x 10^7 Hz.

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An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.

While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.

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Answer:

A centripetal force

Explanation:

The type of force in the given scenario is tension. The correct option is c.

Tension is defined in physics as the pulling force conveyed axially by a string, cable, loop, or similar material, or by every end of a rod, truss member, or similar three-dimensional object.

Tension can also be defined as the action-reaction pair of forces acting at each end of said elements.

Newton's second law states that the tension in the rope must equal the weight of the backed mass.

Tension, the normal force, and friction are all examples of contact forces.

Since the weight is not moving, the acceleration is zero. Even if the acceleration is not zero, this equals zero.

Thus, the correct option is c.

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Your question seems incomplete, the missing options are:

Answer:

attractive/magnetic

mark me brainliestt :))

To maximize the objective function p with the given constraints, we use linear programming by identifying the feasible region.

Finding corner points, evaluating p at each point, and selecting the point with the maximum value of p.In this case, the given constraints are x = 0, y = 0, 2x + 2y = 4, and x + y = 8. To maximize the objective function p, we follow these steps:Identify the feasible region by graphing the constraints on a coordinate plane.

The corner points, which represent the vertices of the feasible region.Evaluate the objective function p at each corner point.Select the point with the maximum value of p as the optimal solution that maximizes p while satisfying the given constraints.

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If the oscillation amplitude is 0.22m, from a 0.29kg harmonic oscillator which has a total of mechanical energy 3.6j, the oscillation frequency is 4.141Hz.

It is a number of oscillations in the one-time unit, says per second. For example, a pendulum that takes 0.5s to make one full oscillation has a frequency of 1 oscillation per 0.5s or 2 oscillations / second.

How to calculate the oscillation frequency?

mass (m) = 0.29kg

Total energy (E) = 3.6j

amplitude (x) = 0.22m

E = 1/2 k*x^2

k = 2*E / x^2

= 2 * 3.6 / 0.22^2

= 148.76 N/m

Frequency (v) = 1/2π √k/m

= 1/2*3.14 * √148.76 / 0.22

= 4.141Hz

Therefore, the oscillation frequency is 4.141Hz.

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The static thrust of the turbojet engine mounted on a stationary test stand at sea level, with inlet and exit areas at 1.0 atm and 800 K respectively, is b.) Thrust 32680N.

To calculate the static thrust of the engine, we can use the ideal rocket equation:

Thrust = mass flow rate * exhaust velocity

The mass flow rate can be calculated using the equation:

mass flow rate = air density * inlet area * inlet velocity

The exhaust velocity can be approximated as the exit area times the exit velocity.

Given that the engine is mounted on a stationary test stand at sea level, we can assume the inlet velocity is zero. Additionally, we know the inlet and exit areas, as well as the atmospheric pressure at sea level.

By calculating the mass flow rate and the exhaust velocity using the provided information and plugging them into the ideal rocket equation, we arrive at the static thrust of approximately 32680N.

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