What is one way the lack of gravity in space affects the human body?
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The enthalpy change is the difference in the energy of formation of the products minus that of the reactants, we have the following formula:

ΔHr = Σn*ΔH (products) - Σn*ΔH (reactants)

Now, we are given the values for the energy of formation of all the compounds that participate in the reaction. We must always make sure that the reaction equation they give us is balanced, in this case, it is balanced since the atoms of each element are the same on each side of the reaction.

Now, let's calculate the energy of the formation of the products and reactants separately.

For the products we will have to:

For the reactants we will have to:

So, the change of enthalpy will be:

Enthalpy change is 992kJ

Based on the calculations, the pH of this solution is equal to 1.9208.

pH is literally the power of hydrogen ions and it can be defined as a measure of the molar concentration of hydrogen ions in a given solution.

Mathematically, the pH of this solution can be calculated by using this formula;

pH = -log[H⁺]

Where:

H⁺ represents the hydrogen ion concentration of a solution.

Given the following data:

Concentration of hydrogen ion (H⁺) = 1.2 × 10⁻² M.

Substituting the given parameters into the formula, we have;

pH = -log(1.2 × 10⁻²).

pH = -(-1.9208)

pH = 1.9208

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The temperature inside the freezer is approximately -164°C.

To solve this problem, we can use the combined gas law equation:

\((P1V1)/T1 = (P2V2)/T2\)

where P is the pressure, V is the volume, and T is the temperature of the gas.

We know that the initial volume of the balloon is 145 mL and the final volume is 35 mL. We also know that the initial temperature is 25°C or 298 K, and we need to find the final temperature.

Assuming the pressure of the gas remains constant, we can rearrange the combined gas law equation to solve for the final temperature:

\(T2 = (P2V2/T1)(P1/V1)\)

Plugging in the values we know, we get:

\(T2 = (1 atm * 35 mL/298 K)(1 atm/145 mL) = 0.0808 atm/mL\)

Multiplying both sides by 298 K and dividing by 0.0808 atm/mL, we get:

T2 = 109.15 K or approximately -164°C

Therefore, the temperature inside the freezer is approximately -164°C.

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The combining capacity of an atom of the element by either sharing, gaining or loosing electrons is known as valency.

_______

RainbowSalt2222 ☔

Answer:

d

Explanation:

i looked it up

Mechanical energy is not a form of kinetic energy. Hence, option D is correct.

Kinetic energy is a form of energy that an object or a particle has by reason of its motion.

Mechanical energy is the sum of the kinetic energy, or energy of motion, and the potential energy, or energy stored in a system by reason of the position of its parts.

Hence, option D is correct.

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Based on the definition of equivalence point and the data provided;

The equivalence point of a reaction is the point at which equal amounts of both acid and base have reacted.

Equation of the reaction is as follows:

HCl + Ca(OH)2 ---> CaCl2 + 2 H20

Moles of HCl reacted = molarity × volume in L

Moles of HCl reacted = 0.05 M × 16/1000 = 0.0008 moles

Therefore, moles of OH- present = 0.0008 moles

Also, moles of Ca2+ present = 0.0008/2 = 0.0004 moles

The molar solubility product Ksp of calcium hydroxide is calculated as follows.

volume of solution = 36 mL = 0.036 L

[Ca2+] = 0.0004 / 0.036 = 0.011 M

[OH] = 0.0008 / 0.036 = 0.022 M

Ksp = (0.011)^2 × 2(0.022)

Ksp = 5.324 × 10^-8

Therefore, the moles of OH- present is 0.0008 moles and the moles of Ca2+ present is 0.0004 moles.

The Ksp of calcium hydroxide 5.324 × 10^-8

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When there are two bond pairs and one lone pair, the molecule will have a bent molecular shape.

The shape of a molecule depends on the orientation and number of electron pairs on the valence shell of the central atom in the molecule. This is based on the postulates of the valence shell electron pair repulsion theory.

When there are two bond pairs and one lone pair, the molecule will have a bent molecular shape.

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The equilibrium constant, K, is \(8.24\) with 3 sig figs.

A mole of naturally occurring potassium has a mass of\(39.098 grams\)

The equilibrium constant, K, for the reaction

BaCl2 (aq) + K2SO4 (aq) → BaSO4 (s) + 2KCl (aq)

can be calculated using the following equation:

K = \(\frac{[BaSO4]*[2KCl]}{[BaCl2]*[K2SO4]}\)

K = \(\frac{3.71 mol/L * (2*4.65 mol/L)}{(2.78 mol/L * 3.25 mol/L)}\)

K =\(8.24\)

Using the values provided, we can determine that K = 8.24.

Thus, the equilibrium constant, K, is 8.24 with 3 sig figs.

This is because a mole of potassium atoms is made up of 39.098 grams of K-39 atoms, 20.042 grams of K-20 atoms and 0.950 grams of K-41 atoms. The atomic number of all potassium isotopes is 19, which means they all have 19 protons. The number of neutrons in each isotope differs. K-39 has 20 neutrons, K-20 has 18 neutrons and K-41 has 22 neutrons. K-39 is the most abundant potassium isotope, making up 93.2581% of naturally occurring potassium.

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complete question:

For the reaction below, the amounts at equilibrium in a 1.0 L container at a certain temperature are: 2.78 moles BaCl2, 3.25 moles K2SO4, 3.71 moles BaSO4, and 4.65 moles KCl. What is the equilibrium constant, K? Enter your answer with 3 sig figs.

BaCl2 (aq) + K2SO4 (aq) ----> BaSO4 (s) + 2KCl (aq)

On Earth, naturally occurring potassium contains 3 isotopes:

39K, 20K, and 41K.Select ALL of the following that are true for a sample of naturally occurring potassium.

a.A mole of naturaly occurring potassium has a mass of 39.098 grams  K-41 has 41 electrons

b.All of the potassium isotopes have more neutrons than protons

c.All potassium isotopes have an atomic number of 19 K−39 is the most abundant potassium isotope

d.A mole of K-39 atoms has a mass of 39.098 grams

Potassium 41 has 19 protons and 22 neutrons

To prepare 12 capsules each containing 80 mg of morphine sulfate and 3.2 mg of naltrexone hydrochloride, the following calculations can be used:

Calculate the total weight of the morphine sulfate and naltrexone hydrochloride: 80 mg + 3.2 mg = 83.2 mg

Calculate the weight of the diluent required: 12 capsules * 83.2 mg/capsule = 999.6 mg

Calculate the volume of the diluent required based on its density (assume a density of 0.9 g/mL for lactose): 999.6 mg / (0.9 g/mL) = 1.11 mL

Calculate the weight of the diluent required based on its volume: 1.11 mL * 0.9 g/mL = 1 g

Calculate the amount of the diluent required based on the sensitivity of the prescription balance: 1 g / (6 mg/g) = 166.7 mg

The amount of the diluent required according to this calculation is 166.7 mg. This amount should be rounded up to the nearest whole number (167 mg) to account for the 4% error tolerance. The final aliquot would therefore contain 167 mg of lactose, 80 mg of morphine sulfate, and 3.2 mg of naltrexone hydrochloride.

Answer:

1.6

Explanation:

velocity=distance/time

=8/5

Answer:

C.

Explanation:

✿————✦————✿————✦————✿

Why C? Because-

Answer:

NaOH is the limiting reactant.

Explanation:

Hello there!

In this case, since the reaction taking place between sodium hydroxide and chlorine has is:

\(NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O\)

Which must be balanced according to the law of conservation of mass:

\(2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O\)

Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:

\(n_{NaOH}=0.85molCl_2*\frac{2molNaOH}{1molCl_2}\\\\n_{ NaOH}=1.7molNaOH\)

Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.

Regards!

No. of atoms in 39.1g of P is 7.59× 10²³ atoms.  No. of atoms in 8.97g of Bi is 2.58 × 10²² atoms

1. Given,

 we have to find number of atoms in 8.97g of Bi

Now,

Molecular weight of Bi = 209g

 Hence,

 1 mole of Bi = 209g

209 g of Bi = 6.022 × 10²³ atoms

Hence,

  8.97 g of Bi = 6.022 × 10²³ × 8.97 / 209 atoms

Number of atoms in 8.97g of Bi = 2.58 × 10²² atoms

2.  we have to find number of atoms in 39.1g of P

Now,

Molecular weight of P = 31g

 Hence,

 1 mole of P = 31g

31 g of P= 6.022 × 10²³ atoms

Hence,

 39.1 g of P = 6.022 × 10²³ × 39.1/31 atoms

No. of atoms in 39.1g of P = 7.59× 10²³ atoms

Thus, from the above conclusion we can say that , No. of atoms in 39.1g of P is 7.59× 10²³ atoms.

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Answer:

I RFID not understand the question?

The number of mole of HNO₃ that will be produced from the reaction of 57.0 g of NO₂ with excess water is 0.826 mole

First, we shall obtain the number of mole in 57.0 g of NO₂. This shown below:

Mole = mass / molar mass

Mole of NO₂ = 57 / 46

Mole of NO₂ = 1.239 mole

Finally, we shall determine the number of mole of HNO₃ produced. Details below:

3NO₂(g) + H₂O(l) → 2HNO₃(g) + NO(g)

From the balanced equation above,

3 moles of NO₂ reacted to produce 2 moles of HNO₃

Therefore,

1.239 mole of NO₂ will react to produce = (1.239 × 2) / 3 = 0.826 mole of HNO₃

Thus, we can conclude that the number of mole of HNO₃ produced is 0.826 mole

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The classification of the substances are as follows;

1) C

2) MOE

3) MOEAC

4) MOC

5) E

6) C

7) E

8) MOEAC

9) MOE

10) MOEAC

11) C

12) MOC

13) MOC

14) MOC

15) MOC

An element is a pure substance that cannot be broken down into simpler substances by chemical means. Elements are composed of only one type of atom, and they are listed on the periodic table. For example, oxygen, gold, and carbon are all elements.

A compound is a substance composed of two or more elements chemically combined in a fixed ratio. The properties of a compound are different from those of the elements that make it up. For example, water is a compound made up of two elements, hydrogen and oxygen, and has different properties than its constituent elements.

A mixture is a combination of two or more substances that are not chemically combined. Mixtures can be composed of elements, compounds, or both, and they can be separated by physical means.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

c are there 93.5 of c yan siguro

The given compound, 0 \(CH_2CH_3CH_2CH_3\), is not an aromatic compound. It has a straight chain and no ring structure.

Hence, option (b) is correct choice.

If we consider the compound \(CH_3CH_2CH_2C_6H_4CH_2CH_3\), it is an aromatic compound with a benzene ring and two ethyl groups attached to it.

The correct name of this compound is B. p-diethylbenzene, as the two ethyl groups are attached to the para position of the benzene ring.

Option A is incorrect because "1,5-diethylbenzene" would mean the ethyl groups are attached to the 1 and 5 positions, which is not the case in the given structure.

Option C is incorrect because "o-diethylbenzene" would mean the ethyl groups are attached to the ortho position, which is also not the case in the given structure.

Option D is incorrect because "1,3-diethylbenzene" would mean the ethyl groups are attached to the 1 and 3 positions, which is not the case in the given structure.

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The osmotic pressure of the system is 17.1 atm.

Osmotic pressure is the pressure that must be applied to a solution in order to prevent the flow of solvent from a region of higher concentration to a region of lower concentration across a semi-permeable membrane. A semi-permeable membrane allows only solvent molecules to pass through, while preventing the passage of solute molecules.

π=i c R T

π= osmotic pressure

i = Van't Hoff factor

c = concentration

R = gas constant

T = temperature

π= 1 * 0.85 * 0.08206 * 245

= 17.1 atm

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Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the  pH of a 0.01 M acetic acid.

Any hydrogen that comprises a material capable of giving a proton (a hydrogen ion) to another chemical is defined as acid. A base is indeed a molecule or ion that can receive a hydronium ion from just an acid.

1)Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. The pH value of stronger acid is lower.

2)CH\(_3\)COOH + H\(_2\)O  ⇄ CH\(_3\)COO⁻+  H\(_3\)O⁺

 0.01             0               0

 -x              +x                +x

 0.01-x           +x        +x

Ka=[ CH\(_3\)COO⁻][H\(_3\)O⁺]/[CH\(_3\)COOH]

1.8×10⁻⁵ = [x][x ]/[  0.01-x ]

x=1.34×10⁻³

pH = -log[H⁺]

     =  -log[1.34×10⁻³]

     =2.88

Therefore, because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the   pH of a 0.01 M acetic acid.

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The reaction of 2,2-dichloro-3-methylbutane with water results in the formation of 3-methyl-2-butanol, which can react with OH- in a nucleophilic substitution reaction to form 3-methyl-2-butyl alcohol and water.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

The reaction of 2,2-dichloro-3-methylbutane with water can result in the formation of an alcohol and a hydrogen ion. The product of this reaction is 3-methyl-2-butanol.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

In this reaction, one of the chlorine atoms from 2,2-dichloro-3-methylbutane is replaced by a hydroxyl group (-OH) from water, resulting in the formation of an alcohol group (-OH) in the product, 3-methyl-2-butanol. The other chlorine atom remains as an ion, Cl-.

The product, 3-methyl-2-butanol, can react with OH- in a nucleophilic substitution reaction. In this reaction, the hydroxide ion (OH-) acts as a nucleophile and attacks the carbon atom that is attached to the leaving group (the -OH group) in the 3-methyl-2-butanol molecule. The leaving group then departs with its pair of electrons, forming a new bond with the nucleophile (OH-). The result is the formation of a new alcohol molecule.

The reaction can be represented by the following equation:

3-methyl-2-butanol + OH- → 3-methyl-2-butyl alcohol + H2O

In this reaction, the -OH group of 3-methyl-2-butanol is replaced by the hydroxide ion (OH-) to form 3-methyl-2-butyl alcohol, and a water molecule is formed as a byproduct.

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Double bond in ethene is made up of sigma and Pi bonds.

The covalent bond will be formed by the lateral overlap of the atomic orbitals is known as pi bond. For example, ethylene molecule contain 5 sigma bonding as well as 1 pi bonding in it. Pi bond formation will takes place by the parallel orientation of the two p orbitals in an adjacent atoms by proper sideways overlap. Thus in any molecule in which pi bond formation will takes place at all the atoms must be having in the same plane. Thus in pi bond carbon carbon double bond rotation is restricted due to the maximum overlap of the p orbitals. Example : Ethene molecule

Sigma bond (σ bond): A covalent bond will be formed by the overlap of atomic orbitals and/or hybrid orbitals along with the bond axis (i.e., along a line connected to the two bonded atoms). The sigma bond in the hydrogen molecule is formed by overlap of a pair of 1s orbitals, one from each hydrogen atom.

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Answer:

Substance C

Explanation:

Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.

Answer:

Explanation:

Total Ratio, thus 2+3 = 5 = 2,350,000

2/5 × 2,350,000 = 940,000

3/5 × 2,350,000 = 1,410,000

Therefore the money was shared at GHS 940,000 and GHS 1,410,000 among the two.

Answer:

compound

Explanation:

because h is hydrogen, then O is oxygen