Answer:
b- how much work can be done in a given time
how much work can be done in a given time
Which ray diagram demonstrates the phenomenon of absorption?
An illustration with a vector pointed right going through an opening in a boundary and splitting into 3 vectors. One up and to the right, one straight and one down to the right.
An illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side.
An illustration with a vector striking a boundary at an angle and a second vector coming off the boundary at the exact same angle.
Answer:
B
Explanation:
on edge
The illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side demonstrates the phenomenon of absorption, so, option B is correct.
What is absorption?Absorption, in wave motion, is the process by which a wave's energy is transferred to matter when the wave travels through it. The energy of an electromagnetic, acoustic, or other wave is related to the square of its amplitude, which is the maximum displacement or movement of a point on the wave.
The amplitude of a wave continuously diminishes as it travels through a substance. The medium is described as being transparent to a specific type of radiation if just a tiny portion of the energy is absorbed, whereas it is described as opaque if all the energy is lost.
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help, Asap!!!!!!!!!!!!!!!!!!
Answer:
0
Explanation:
all of the movement and opposite movement are the same
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
How do wetlands reduce flooding and erosion? (Site 1)
Answer:
Wetlands reduce flooding and erosion by filtering water.
Explanation:
Answer:
Wetlands reduce flooding and erosion by filtering water.
Explanation:
A 24-cm circumference loop of wire has a resistance of 0.14 Ω. The loop is placed between the poles of an electromagnet, and a field of 0.55 T is switched on in a time of 15 ms. What is the induced current in the loop?
Answer:
The induced current in the loop is 1.2 A
Explanation:
Given;
length of the wire, L = 24 cm = 0.24 m
resistance of the wire, R = 0.14 Ω.
magnetic field strength, B = 0.55 T
time, t = 15 ms = 15 x 10⁻³ s
Circumference of a circle is given as;
L = 2πr
0.24 = 2πr
r = 0.24 / 2π
r = 0.0382 m
Area of a loop is given as;
A = πr²
A = π (0.0382)²
A = 0.004585 m²
Induced emf is given as;
\(emf = -\frac{\delta \phi}{dt}\)
Ф = ΔB x A
Ф = ( 0 - 0.55 T) x 0.004585 m²
Ф = -0.002522 T.m²
\(emf = - (\frac{-0.002522}{15*10^{-3}} )\\\\emf = 0.168 \ V\)
According to ohm's law;
V = IR
Where;
I is current
The induced current in the loop is calculated as;
I = V / R
I = 0.168 / 0.14
I = 1.2 A
Therefore, the induced current in the loop is 1.2 A
What is the daughter nucleus (nuclide) produced when bi213 undergoes alpha decay? replace the question marks with the proper integers or symbols.
The equation is;
213/83 Bi ----> 209/81Tl + 4/2 He
What is the alpha decay of Bi-213?In this decay process, the unstable Bi-213 nucleus emits an alpha particle, which consists of two protons and two neutrons (also known as a helium-4 nucleus).
As a result of this emission, the daughter nucleus Tl-209 is formed with a decrease of four in the atomic number and a decrease of eight in the mass number. The alpha particle, He-4, has an atomic number of 2 and a mass number of 4, and is emitted with high kinetic energy.
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A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the velocity of the steel ball?
Answer:
2.22m/s to the left
Explanation:
Given parameters:
Initial position = +125m
Final position = -75m
Motion time = 90s
Unknown:
Velocity of the steel ball = ?
Solution:
The velocity of the steel ball is given as the displacement divided by the time;
Velocity = \(\frac{displacement}{time}\)
The net displacement of the ball = 125- (-75) = 200m to the left
Input the parameters and solve for the velocity;
Velocity = \(\frac{200}{90}\) = 2.22m/s to the left
Two kids are roller skating. Amy, with a mass of 55 kg, is traveling forward at 3 m/s. Jenny, who has a mass of 40 kg, is traveling in the opposite direction at 5 m/s. They crash into each other and hold onto each other so that they move as one mass. How fast are they traveling?
Answer:
-7/19
Explanation:
A flywheel with radius of 0.400 mm starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2rad/s2. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Throwing a discus. Part A For a point on the rim of the flywheel, what is the magnitude of the tangential acceleration after 2.00 ss of acceleration
Answer: \(0.00024\ m/s^2\)
Explanation:
Given
Radius of flywheel is \(r=0.4\ mm\)
Angular acceleration \(\alpha=0.6\ rad/s^2\)
For no change in radius, tangential acceleration is given as
\(\Rightarrow a_t=a\lpha \times r\)
Insert the values
\(\Rightarrow a_t=0.6\times 0.4\times 10^{-3}\ m/s^2\\\Rightarrow a_t=2.4\times 10^{-4}\ m/s^2\ \text{or}\ 0.00024\ m/s^2\)
language uses_ to quickly express concepts and ideas
a. emotions
b. letters
c. strings
d. symbols
Answer:
i try B
Explanation:
Which trait do you think is most important for a boss or supervisor to have?
Answer:
A high EQ (emotional intelligence)
In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).
Explanation:
hope it helps you
A 5kg monkey is running with a velocity of 5 m/s to the right
The momentum of the monkey of mass 5 kg is 25 kgm/s.
What is Momentum?Momentum is the product of mass and velocity.
To calculate the momentum of the monkey, we use the formula below.
Formula:
M = mv..................... Equation 1Where:
M = Momentum of the monkeym = Mass of the monkeyv = Velocity of the monkeyFrom the question,
Given:
m = 5 kgv = 5 m/sSubstitute these values into equation 1
M = 5×5M = 25 kgm/sHence, the momentum of the monkey is 25 kgm/s.
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Complete question: A 5kg monkey is running with a velocity of 5 m/s to the right. Find the momentum of the monkey
Match the Science Terms with their definitions.
To match the science terms with their definitions, I'll provide you with a list of terms and their corresponding definitions. Please note that since you didn't provide the specific terms you need, I will provide some common science terms as examples:
1. Atom: The smallest unit of a chemical element that retains the properties of that element.
2. Molecule: A group of two or more atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.
3. Photosynthesis: The process by which green plants and some other organisms use sunlight to synthesize foods with the help of chlorophyll pigments, converting light energy into chemical energy.
4. Gravity: The force that attracts two bodies toward each other, proportional to their masses and the distance between them.
5. Evaporation: The process by which a liquid changes into a vapor, usually as it is heated or its pressure is reduced.
6. Ecosystem: A biological community of interacting organisms and their physical environment, including both living (biotic) and nonliving (abiotic) components.
7. DNA: Deoxyribonucleic acid, the hereditary material in humans and almost all other organisms that carries genetic information in cells.
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Does the weight of the projectile affect the horizontal range?
Answer:
no
Explanation:
This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.
Runners in the 100 metre dash have complained that the runner nearest the gun has an unfair advantage.
What might this advantage be?
The advantage that the runner nearest the gun in the 100-meter dash might have is known as the "reaction time advantage."
What is reaction time advantage?A reaction time advantage is known to allow runners in a race to be agile and efficient when it comes to responding to stimuli in situations like driving, playing sports, or even having a conversation.
It is believed that the runner closest to the gun has a shorter distance for the sound wave to travel which might result in a slightly quicker reaction time in comparison to the other runners.
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Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____
The evaluation of the capacitor (in series) network is as follows;
Part A
Q = 3.2 μC
Part B
Q₁ = 3.2 μC
Part C
Q₂ = 3.2 μC
Part D
U = 76.8 μJ
Part E
U₁ = 34 2/15 μJ
Part F
U₂ = 53 1/3 μJ
Part G
V₁ = 21 1/3 V
Part H
V₂ = 26 2/3 V
What is a capacitor?A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.
The specified parameters are;
The voltage across ab = 48 V
The capacitance of the first capacitor, C₁ = 150 nF
Capacitance of the second capacitor, C₂ = 120 nF
Part A
The total charge in a capacitor network can be found as follows;
\(C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF\)
\(C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF\)
\(Q_{eq} = C_{eq}\times V_{ab}\)
Therefore;
\(Q_{eq}\) = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC
The total charge in the circuit is 3.2 μCPart B
The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;
Q = C₁V₁ = C₂V₂
The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC
The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC
Q₁ = 3.2 nCPart C
The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.
Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC
Q₂ = 3.2 μF
Part D
The total energy stored in the network can be obtained using the formula;
U = (1/2)·C·V²
Where;
U = The energy in the capacitor
C = The equivalent capacitance of the network = 66 2/3 nF
V = The voltage
Therefore;
\(U = \dfrac{1}{2} \times C_{eq}\times V^2\)
\(U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8\)
The total energy in the circuit, U = 76.8 μJPart E
The energy stored in the 150 nF capacitor is found as follows;
\(Q_{eq}\) = Q₁ = C₁ × V₁
V₁ = \(Q_{eq}\) ÷ C₁
Therefore;
V₁ = 3.2 μC ÷ 150 nF = \(21\frac{1}{3}\) V
U₁ = 0.5×C₁×V₁²
U₁ = 0.5 × 150×10⁻⁹ × \(\left(21\frac{1}{3} \right)^2\) = 34\(\frac{2}{15}\) μJPart F
The energy stored in the 120 nF capacitor, U₂, can be found as follows;
V₂ = 3.2 μC ÷ 120 nF = \(26\frac{2}{3}\) V
U₂ = 0.5 × 150 nF × \(\left(26\frac{2}{3} \, V\right)^2\) = \(53\frac{1}{3}\, \mathrm{ \mu J}\)
The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJPart G;
The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V
V₁ = 21 1/3 VPart H
The potential difference across the 120 nF, obtained in part F, is 26 2/3 V
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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1. Define the law of conservation of momentum in your own words.
2. Which of Newton's laws explains how momentum is conserved in all interactions between objects?
3. What do you know about the forces involved in an interaction between two objects?
4. Is momentum a vector or a scalar quantity? Based on your answer, which other value is important
besides the numerical value of momentum?
5. How do you find the total momentum of objects in a system?
6. If objects are traveling in opposite directions, what do you know about the signs of their momenta?
7. What characteristics are required for a system to be considered closed and isolated?
8. What forces are considered when we examine interactions between two objects in a closed, isolated
system?
9. If two objects begin at rest, what is the total momentum of the system before they push off from one
another? What is the momentum of the system after they push off from one another?
1. Total momentum of an isolated system before collision is always equal to total momentum after collision is called conservation of momentum.
2. Newton's third law explains how momentum is conserved in all interaction between objects.
3. Force is an unopposed interaction between two or more bodies that apply the shift in the objects state of motion. The action and reaction are two interacting forces that we called as Newton's third law of motion. There are two forces acting on two interacting objects in any interaction.
4. Momentum is a vector quantity and has the same direction as velocity. It is the product of mass (a scalar quantity) and velocity (a vector quantity).
5. To find total momentum of the system , add their individual momentums together. Calculate momentum for each object by using formula P=mv, where P is momentum, m is mass, v is velocity.
6. If the objects are travelling in opposite direction, then the overall momentum will be zero. They have same mass and velocity, when their momentum vectors add up to exactly zero when added together.
7. Closed system in which the exchange of only energy with its surroundings takes place. An isolated system in which no exchange of matter or energy takes place.
8. The internal forces are considered when we examine interaction between two objects in a closed and isolated system because these forces cause momentum of the system to be transferred between one object to another.
9. Before the push-off, the total initial momentum is zero. The total momentum after the push-off should also be zero.
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a wave where particles move parallel to its energy is
Any wave in which the motion of the medium's particles is parallel to the wave's direction is referred to as a longitudinal wave.
Imagine that a slinky is stretched out horizontally across the classroom, and that the left end of the slinky receives a pulse from the left and right vibrations of the first coil. From left to right, energy will start to move through the slinky. The individual coils of the medium will be shifted left and right as the energy moves from left to right. The medium's particles in this instance travel in a direction parallel to the pulse's. A longitudinal wave is this kind of wave. Particle motion is consistently parallel to wave motion in longitudinal waves.
A well-known example of a longitudinal wave is a sound wave moving through air.
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give 3 example of right quantities that have no unit
Answer:
velocity ratio
mechanical advantage
Relative density
What is the period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth)?
When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.
Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.
Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.
To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²
Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds
Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
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If an object is placed between a convex lens and its focal point, which type of image will be produced?
A squirrel drops an acorn onto the head of an unsuspecting dog. The acorn falls 4.0 meters before it lands on the dog. We can ignore air resistance.
How many seconds did the acorn fall?
Answer:
66
Explanation:
How has information technology impacted the economy? Choose three answers.
Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.
The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.
This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.
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--The complete question is, How has information technology impacted the economy?--
A common technique in analysis of scientific data is normalization. The purpose of normalizing data is to eliminate irrelevant constants that can obscure the salient features of the data. The goal of this experiment is to test the hypothesis that the flux of light decreases as the square of the distance from the source. In this case, the absolute value of the voltage measured by the photometer is irrelevant; only the relative value conveys useful information. Suppose that in Part 2.2.2 of the experiment, students obtain a signal value of 185 mV at a distance of 4 cm and a value of 82 mV at a distance of 6.2 cm. Normalize the students' data to the value obtained at 4 cm. (Divide the signal value by 185.) Then calculate the theoretically expected (normalized) value at 6.2 cm.
Answer:
V₂ = 0.4432
Explanation:
The normalize procedure is widely used in science, in this case we are going to normalize to the voltage value that exists 4 cm away
Vₙ= V_{measured} / V₀
where the voltage at the desired distance is V₀ = 185 mV = 0.185 V
the normalized voltage are
forr x = 4 cm
V₁ = 185/185
V₁ = 1
for x = 6.2 cm
V₂ = 82/185
V₂ = 0.4432
pls help its already late lol
Answer:
Temperature
Explanation:
Answer:
Gravity
Explanation:
Gravity has nothing to do with weather. Temperature means hot or cold, water is rain and thunder, and wind is if it's in the winter or something like that
Suppose your bicycle tire is fully inflated, with an absolute pressure 4.00 x 10^5 Pa at a temperature of 15.0 °C. What is the pressure after its temperature has risen to 40.0 °C? Assume that there are no appreciable leaks or changes in volume.
The pressure after the temperature has risen to 40.0 °C, assuming that there are no appreciable leaks or changes in volume is 4.35×10⁵ Pa
How do I determine the pressure at 40.0 °C?From the question given above, the following data were obtained:
Initial pressure (P₁) = 4.00×10⁵ Pa Initial temperature (T₁) = 15 °C = 15 + 273 = 288 K New temperature (T₂) = 40 °C = 40 + 273 = 313 KVolume = ConstantNew pressure (P₂) = ?The pressure the temperature has risen to 40 °C can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
Volume = contant
P₁ / T₁ = P₂ / T₂
4.00×10⁵ / 288 = P₂ / 313
Cross multiply
P₂ × 288 = 4.00×10⁵ × 313
Divide both sides by 288
P₂ = (4.00×10⁵ × 313) / 288
P₂ = 4.35×10⁵ Pa
Thus, the pressure at 40 °C is 4.35×10⁵ Pa
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A ball is thrown directly downward with an initial speed of 7.30 m/s, from a height of 29.0 m. After what time interval does it strike the ground?
Time taken by the ball to reach the ground is 1.8s.
What is free falling?When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.
A ball is thrown directly downward with an initial speed of 7.30 m/s, from a height of 29.0 m
Using the second equation of motion,
s = ut + 1/2 at²
Plug the values, we get
29 = 7.3t + 1/2 x9.81t²
4.905t² + 7.3t -29 =0
t =1.79871 or −3.28699
As time can't be negative, time taken to strike the ground is approximately 1.8 s.
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Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
If you pull a resistant puppy with its leash in a horizontal direction, it takes 80 N to get it going. You can then keep it moving at constant speed across the floor with a constant, horizontal force of 70 N. The puppy has a weight of 110 N. What is the coefficient of static friction between the puppy and the floor
Answer:
The coefficient of static friction between the puppy and the floor is 0.7273.
Explanation:
The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:
\(F_s = \mu_s*N\)
Where \(F_s\) is the static friction force, \(\mu_s\) is the coefficient of static friction and \(N\) is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, \(N = 110\text{ N}\), to make the puppy moving we need to use a force of 80 N, therefore, \(F_s = 80 \text{ N}\), so we can solve for the coefficient as shown below:
\(80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\\)
The coefficient of static friction between the puppy and the floor is 0.7273.
A block with mass 0.50 kg
is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m
(Figure 1). When released, the block moves on a horizontal tabletop for 1.00 m
before coming to rest. The spring constant k
is 100 N/m
What is the coefficient of kinetic friction μk
between the block and the tabletop?
Answer:100
Explanation: