Answer:
Explanation:
Here are some simple do’s and don’ts for kids who refuse to do work: Don’t just punish. If a child or young adult is struggling with some social or emotional challenges at the moment, a punishment is only going to push them away further. Your punishment will appear as harsh, mean, and uncaring.The patient's failure to keep appointments. Patients make appointments, then cancel them at the last minute, or don't show up at all. From the provider's perspective, that means a window of no income in addition to the fact that the patient isn't getting the help he or she needs. A patient's rude or obnoxious behavior.
when a burning stick of increase is moved fast in a circle a circle of red light is seen.
Answer:
The impression of the image on the retina lasts for about 1/16th of a second after the removal of the object. If a burning stick of incense is revolved at a rate of more than sixteen revolutions per second, we see a circle of red light due to persistence of vision.
Explanation:
If the resultant force vector is 10 N magnitude in the positive y axis direction (North), find the equilibrant force.
The equilibrant force is equal in magnitude and opposite in direction to the resultant force.
What is an equilibrant force?Since the resultant force is 10 N in the positive y axis direction (North), the equilibrant force is 10 N in the negative y axis direction (South). An equilibrant force is a force that can balance or counteract the effect of other forces acting on an object.
It has the same magnitude as the resultant force, but it acts in the opposite direction, resulting in a state of equilibrium where the net force acting on the object is zero.
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Numerical Response #5 A 1.50-m-long pendulum has a period of 1.50 s. The acceleration due to gravity at the location of this pendulum is ______ m/s2 .10. In the case of a longitudinal wave, energy is transmitted A. in the direction of particle vibration B. at right angles to particle vibration C. out of phase with particle vibration D. in all directions
The acceleration due to gravity at the location of the pendulum with a length of 1.50 meters and a period of 1.50 seconds is 9.81 m/s².
A pendulum is a system that vibrates in a harmonic motion. The time it takes to complete one cycle of motion is known as the period. The period of a pendulum can be calculated using the formula: T = 2π√(l/g)
Where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity. If we rearrange the formula to solve for g, we get: g = (4π²l)/T²
To find the acceleration due to gravity at the location of this pendulum, we can substitute the given values:
l = 1.50 m, and T = 1.50 s.g = (4π²(1.50 m))/(1.50 s)²= 9.81 m/s²
We are given a pendulum that has a length of 1.50 meters and a period of 1.50 seconds. Using the formula for the period of a pendulum, we can determine the acceleration due to gravity at the location of the pendulum.
The period of a pendulum is determined by the length of the pendulum and the acceleration due to gravity. The formula for the period of a pendulum is T = 2π√(l/g), where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity. By rearranging the formula, we can determine the value of g. The formula is g = (4π²l)/T². Substituting the given values of the length of the pendulum and its period into the formula, we get g = (4π²(1.50 m))/(1.50 s)² = 9.81 m/s². Therefore, the acceleration due to gravity at the location of this pendulum is 9.81 m/s².
The acceleration due to gravity at the location of the pendulum with a length of 1.50 meters and a period of 1.50 seconds is 9.81 m/s². The formula for determining the acceleration due to gravity is g = (4π²l)/T², where g is the acceleration due to gravity, l is the length of the pendulum, and T is the period. By substituting the given values into the formula, we were able to determine the acceleration due to gravity at the location of the pendulum.
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The acceleration due to gravity at the location of the pendulum is \(approximately 9.81 m/s^2\).
What is simple pendulum ?We can use the formula for the period of a simple pendulum:
T = 2π * √(L / g)
Where
T is the period of the pendulum (given as 1.50 s)L is the length of the pendulum (given as 1.50 m)g is the acceleration due to gravity (what we need to find)Rearranging the formula to solve for g:
g = (4π\(^2 * L) / T^2\)
Now we can substitute the given values:
g = (4π\(^2 * 1.50 m) / (1.50 s)^2\)
Calculating this expression, we find:
g ≈ \(9.81 m/s^2\)
So, the acceleration due to gravity at the location of the pendulum is \(approximately 9.81 m/s^2\).
Energy is transported in the case of a longitudinal wave:
A. in the direction of particle vibration
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Cambia las siguientes oraciones a voz pasiva. Aplica las siguiente estructura: sujeto + verbo auxiliar (to be) + participio pasado…
• He ate all the cookies.
• Luis writes a letter.
• Maria cleans the house.
• Marco repaired the car.
• Katty reads the book.
• All the cookies were eaten by him. • A letter is written by Luis. • The house is cleaned by Maria. • The car was repaired by Marco. • The book is read by Katty.
oraciones consist of a subject and a predicate, which contains the verb and provides information about the subject. Sentences can be simple or complex, and they can express statements, questions, commands, or exclamations. In writing and speech, sentences allow us to express our thoughts, share information, tell stories, ask for clarification, give instructions, and much more. They play a crucial role in conveying ideas, conveying emotions, and facilitating effective communication. Sentences provide structure and coherence to our language, allowing us to express ourselves clearly and engage in meaningful interactions with others. They are the building blocks of written and spoken communication, enabling us to express our ideas, thoughts, and experiences in a comprehensive and understandable manner.
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Which of these would have the highest temperature?
ice
water
water vapor
Answer:
Water vapor
Explanation:
Water Vapor has the highest temperature, due to its being in a gas state, and gases usually have very high temperatures, for example steam when you boil pasta.
Hope this helps you! Have a nice day!
What is a valid frame of reference for observing motion if you
are riding on a bus with a friend?
a the bus driver at the front of the bus
b the wastebasket on the bus
c your friend sitting next to you
d objects like trees and houses outside the windows
Answer: D
Explanation:
Magnetic Field on the Axis of a Circular Current Loop Problem Consider a circular loop of wire of radius R located in the yz plane and carrying a steady current I as in Figure 30.6. Calculate the magnetic field at an axial point P a distance x from the center of the loop. Strategy In this situation, note that any element as is perpendicular to f. Thus, for any element, ld5* xf| (ds)(1)sin 90° = ds. Furthermore, all length elements around the loop are at the same distancer from P, where r2 = x2 + R2. = Figure 30.6 The geometry for calculating the magnetic field at a point P lying on the axis of a current loop. By symmetry, the total field is along this axis,
The net magnetic field on the axis of the circular current loop is given by B=(μ0IR2/2)(x2+R2)-3/2 This is the required expression for the magnitude of the magnetic field on the axis of a circular current loop at a point P which is at a distance x from the center of the loop.
Magnetic field on the axis of a circular current loop at point P which is at a distance x from the center of the loop is calculated by the Biot-Savart law. The magnetic field is given by \(B=(μ0/4π)∫dl×r/r3\) where r is the distance between the current element and the point P.
Magnetic field direction is perpendicular to the plane of the loop on the axis of the loop. Let us now find the expression for the magnitude of magnetic field on the axis of a circular current loop.
The geometry for calculating the magnetic field at a point P lying on the axis of a current loop
Let us take the Cartesian coordinate system such that the center of the circular loop is at the origin O. Then the position vector of the current element is \(r’=Rcosθi+Rsinθj\) and the position vector of the point P is \(r=xk\).
Then the vector r’-r is given by r’-\(r=Rcosθi+Rsinθj-xk\)
=(Rcosθi+Rsinθj-xk)
Now the magnitude of this vector is \(|r’-r|=√[(Rcosθ-x)2+(Rsinθ)2]\)
Then, the magnetic field dB due to this current element is given by \(dB=μ0/4π dl/r2\)
where dl=I(r’dθ) is the current element. Now the vector dB can be expressed in terms of its x, y and z components as follows:
\(dB=μ0/4π dl/r2\)
=μ0/4π I(r’dθ)/r2 (Rcosθi+Rsinθj-xk)/[R2+ x2 -2xRcosθ+R2sin2θ]
Taking the x-component of dB we get
dB Bx=μ0I[Rcosθ(R2+x2)-xR2cos2θ-R2x]/[4π(R2+ x2 -2xRcosθ+R2sin2θ)3/2]
Integrating the x-component of dB from θ=0 to θ=2π
we get
\(Bx=∫dBBx\)
=∫μ0I[Rcosθ(R2+x2)-xR2cos2θ-R2x]/[4π(R2+ x2
-2xRcosθ+R2sin2θ)3/2]dθ=0
Therefore, the net magnetic field on the axis of the circular current loop is given by \(B=(μ0IR2/2)(x2+R2)-3/2\)
This is the required expression for the magnitude of the magnetic field on the axis of a circular current loop at a point P which is at a distance x from the center of the loop.
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during which lunar phase does every solar eclipse occur?
Answer:
It has to be the "New Moon" because that is when the moon is between the sun and the earth.
A lunar eclipse can occur when the earth is between the sun and the moon.
a car rounds a curve at a steady 50 km/h. if it rounds the same curve at a steady 70 km/h, will its acceleration be any different? explain.
Answer:
Acceleration would be \(1.96\) times the initial value.
Explanation:
The vehicle is in a centripetal motion as it rounds the circular curve. Acceleration of the vehicle during the motion would be:
\(\displaystyle a = \frac{v^{2}}{r}\),
Where:
\(v\) is the speed of the vehicle, and\(r\) is the radius of the curve.In this question, \(r\) stays the same since the vehicle is rounding the same curve. Acceleration of the vehicle would be proportional to the square of velocity.
The new velocity of the vehicle is \((70 / 50)\) times the original one. Hence, the new acceleration would be \((70 / 50)^{2} = 1.96\) times the original value.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for: A) photon effect. B) atmospheric window effect. C) greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect, which is a key contributor to global warming and climate change. The atmospheric window effect and photon effect are related phenomena but do not directly contribute to the greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect. This effect occurs when gases such as carbon dioxide, water vapor, and methane trap heat from the sun in the Earth's atmosphere, preventing it from escaping into space. This trapped heat leads to an increase in the average temperature of the Earth's surface, causing global warming and climate change.
The atmospheric window effect, on the other hand, refers to the phenomenon where certain wavelengths of radiation are not absorbed by the Earth's atmosphere, allowing them to pass through and escape into space. This occurs in the region of the electromagnetic spectrum where the atmosphere is relatively transparent, such as in the visible and near-infrared portions.
The photon effect, on the other hand, refers to the behavior of photons, which are packets of energy that make up electromagnetic radiation. The absorption of radiation by gases in the atmosphere occurs through the interaction of photons with molecules in the air. When a photon is absorbed, its energy is transferred to the molecule, causing it to vibrate and rotate. This can lead to changes in the temperature and chemical composition of the atmosphere.
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if an object orbits the sun at an average distance of 32 AU
(astronomical units), what would its orbital period be in Earth
years?
If an object orbits the Sun at an average distance of 32 astronomical units (AU), the question is asking for the orbital period of this object in Earth years.
The orbital period of a planet or any object orbiting the Sun can be determined using Kepler's Third Law of Planetary Motion. According to Kepler's Third Law, the square of the orbital period is directly proportional to the cube of the semi-major axis of the orbit.
In this case, the average distance of the object's orbit is given as 32 AU. The semi-major axis of an elliptical orbit is equal to the average distance, so we can consider the semi-major axis as 32 AU.
Using the relationship from Kepler's Third Law, we can set up the following equation:
(T₁ / T₂)² = (a₁ / a₂)³
Letting T₁ represent the orbital period in Earth years and a₁ represent the average distance in AU, we have:
(T₁ / 1 year)² = (32 AU / 1 AU)³
Simplifying the equation, we find:
(T₁ / 1)² = 32³
T₁² = 32³
Taking the square root of both sides, we get:
T₁ = √(32³)
Calculating the value, the orbital period in Earth years would be approximately 165.77 years.
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on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
What is horizontal distance?
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
The projectile's horizontal range is the distance it travels while in flight. Since there is no acceleration in the horizontal direction, the greatest distance traveled in the horizontal direction is what is meant by this definition.
Therefore,
on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
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Answer:
lionel should hit the ball at 46m/s
34. Identify the bond in SO3.
a. covalent
b. ionic
c. metallic
d. metalloid
Answer:
The answer is A.) Covalent
Explanation:
They share a double covalent bond.
-Hope This Helps!
-Justin ! :)
three students make the following claims about determining the average speed and average velocity of the object over the entire time interval depicted in the graph below … which claim is correct?
Answer:
D. none of them po
Explanation:
pl give me points 73
an electrically charged object can be used to attract:
An electrically charged object can be used to attract any object with an opposite charge.
This is due to the fundamental principle that opposites attract and repel in physics.
Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.
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If a planet we same massas Earth were discovered orbising Barnard's Suarat the same distance
at Earta is orbiting the Son, why would there be less gravitational action between his new planet
and Barmand's Sarthen there is between Earth and the Sun

Calculate the momentum of a 450 kg bear riding a 17 kg bike, moving at 9 m/s
A force of 20 N is applied to accelerate a 9.0 kg wagon at 2.0 m/s^2 along the sidewalk. How large is the force of friction?
Draw and label the free body diagram!
Explanation:
\(Σf = ma\)
This means the sum of all forces acting on an object = mass times accleration so first, let find the ma.
The mass is 9 kg and the acclereation is 2.0 m/s^2.
\(Σf = 9(2)\)
which equals
18 N.
So the mass times accleration equal 18 N.
So now what are forces acting on the box?
Since the box isn't levitationg nor falling, the vertical forces, mg and normal force cancel out to 0. so we only have horinzontial forces.
The push force is 20 N and the friction force is considered negative so we have
\(p - f = 18\)
p is 20 so we get
\(20 - f = 18\)
\( - f = - 2\)
\(f = 2\)
So the friction force is 2 N
p is the push force and that us
For the free body diagram, draw a square, and draw arrows from the center of the square in all 4 ways.
Make sure the vertical arrows are equal in length to show they cancel out.
The right horinzontial arrow should be 20 N and the left arrow should be 2 N
The force of friction on the wagon is equal to 2.0 N.
What is frictional force?Frictional force can be defined as the force generated by two surfaces that contact and slide against each other. Frictional forces are affected by the angle, the surface texture, and the position of the object.
Friction can be defined as the force that slows down the movement when one surface comes in contact with another surface. The mechanical advantage decreases by friction the ratio of output to input is reduced because of friction.
The fractional force can be expressed as follows:
F = μ mg
Given, the mass of the wagon, m = 9.0 Kg
The acceleration of the wagon, a = 2.0 m/s²
The applied force on the wagon, F = 20 N
The frictional force can be calculated as:
\(F - F_k = ma\)
\(F_k= F-ma\)
\(F_k\) = 20 - 9 × 2.0
\(F_k = 2.0 N\)
Therefore, the force of friction is 2.0 N.
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State the career function of mining engineering
Answer:Mining engineers are responsible for the effective, safe and profitable operation of mining undertakings. They are mining experts and engineers and have a background in geology as well as civil, mechanical and electrical engineering.
Explanation:
How are suspensions, solutions, and colloids related?
Answer:
A solution is always transparent, light passes through with no scattering from solute particles which are molecule in size. ... A colloid is intermediate between a solution and a suspension. While a suspension will separate out a colloid will not. Colloids can be distinguished from solutions using the Tyndall effect.
Explanation:
When a suspension is allowed to stand, the particles separate. A colloid is a substance that exists between a solution and a suspension. A colloid will not separate from a suspension. The Tyndall effect can be used to distinguish colloids from solutions.
What is suspension?In chemistry, a suspension is a heterogeneous mixture of a fluid containing solid particles large enough to settle.
A suspension is a complex blend in which the solute particles do not disintegrate but rather become suspended throughout the bulk of the solvent and float freely in the medium.
A solution is a uniform mixture of one or more dissolved solutes in a solvent.
A solvent is a substance that dissolves a solute to produce a homogeneous mixture. The substance that dissolves in a solvent to form a homogeneous mixture is referred to as a solute.
A colloid is a mixture in which one substance is suspended throughout another, consisting of microscopically dispersed insoluble particles.
Larger particles in a suspension settle out, block or scatter light, and can be filtered out.
A colloid contains particles that are between the sizes of a solution and a colloid; they are not heavy enough to settle or be filtered out, but they still scatter light.
Thus, this way these three are related.
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rank the light intensity, from largest to smallest, at the point p in the figures.
The light intensity from largest to smallest ranking will be :B > D > A=C > E. where the area is measured on the plane perpendicular to the direction .
In physics, the intensity is the amount of energy that is transmitted per unit area, and the area is measured on a plane perpendicular to the direction that the energy equation will propagate. I = P/ 4(d2), with P denoting power. Let power of 1 bulb equal = P where I = intensity, d = distance at which the intensity must be determined.
case A = I = P / (1) (1) 1 = P case with 2 = P In the situation B = I = 2P/(0.5)2 = 8P C = I = 4P / (2) (2) ^2 = P case Case (1)2 = 3P: D = I = 3P E = I = 2P /(1.5) (1.5) ^2 = 0.8 P
B > D > A=C > E will be the order of light intensity, from greatest to least.
rank the light intensity, from largest to smallest, at the point p in the figures?
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A man carry a load on his head doesn't do work .Explain
Carrying a load on one's head can indeed be considered as a form of work. Work, in physics, is defined as the transfer of energy from one object to another, resulting in the displacement of the second object in the direction of the applied force.
When a person carries a load on their head, they are exerting force against the gravitational pull on the load, which requires energy expenditure. Although it may not be the traditional notion of work, such as performing a job or physical labor, carrying a load on the head still involves the application of force over a distance. The person's muscles are engaged, and energy is expended to maintain balance, support the load, and resist the force of gravity acting on it. Furthermore, carrying a load on the head requires coordination and skill to maintain equilibrium, ensuring that the load does not fall off or cause any harm. Therefore, it can be considered a form of physical work, albeit in a different context than what we typically associate with employment or labor.For such more questions on work
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why is it more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity?
It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity because of static friction.
Static friction refers to the resistance encountered when attempting to initiate the movement of two objects that are in contact with each other but not currently in motion relative to each other. When an object is at rest, the force of static friction acts in the opposite direction to any force applied to it.
In this case, the force applied to the carton is the force needed to start moving it from rest. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it. The only force acting on the carton is the force that is applied to keep it moving at a constant velocity. This force is equal to the force of kinetic friction which is less than the force of static friction.
To summarize, the initial effort required to overcome the static friction between a heavy carton and its resting position is greater compared to the continuous force needed to maintain its constant velocity. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it, and the only force acting on the carton is the force that is applied to keep it moving at a constant velocity.
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A fisherman in a row boat notices that one wave crest passes his fishing line every 5 seconds. he estimated the distance between the crests to be 1.5 meters and estimates that the crests of the waves are 0.5 meters above the troughs.
Using the data find the frequency of the wave divide how many wave crests pass every 5 seconds
Answer:
amplitude = 0.5 m 4 2 = 0.25 m
Explanation:
In which type of modulation does data hop to other frequencies to avoid interference that might occur over a frequency band?
The type of modulation where data hops to other frequencies to avoid interference that might occur over a frequency band is known as frequency-hopping spread spectrum (FHSS).
FHSS is a technique that uses a narrowband carrier that changes frequency according to a certain sequence or hop pattern. The hopping sequence is prearranged and follows a known path so that the receiver can precisely calculate the frequency of the carrier. The goal of this modulation technique is to make the signal extremely hard to intercept and hard to jam.
FHSS is frequently used in military and commercial applications because it can avoid most jamming attempts by automatically shifting frequencies many times each second.
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Five workers from the same factory developed angiosarcoma, a rare cancer of the veins and arteries. Which part of the scientific method is this? Group of answer choices conclusion experiment observation none of these hypothesis
Answer:
a
Explanation:
i took the test
Five workers from the same factory developed angiosarcoma, a rare cancer of the veins and arteries. This is observation of the scientific method.
What is scientific method?Since at least the 17th century, the scientific method—an empirical approach to learning—has guided the advancement of science. Since one's interpretation of the observation may be distorted by cognitive presumptions, it requires careful observation and the application of severe skepticism regarding what is observed.
It entails developing hypotheses through induction based on these observations, testing the validity of those hypotheses through experimental and measurement-based statistical testing of the inferences made from them, and then fine-tuning (or discarding) those hypotheses in light of the experimental results.
These are the guiding principles of the scientific process, as opposed to a predetermined set of steps that apply to all scientific endeavors.
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A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?
1) 750 j
2) 75 J
3) no work was done
4) 7500 J
Answer:750
Explanation:
50 times 15
Answer:
750 j
Explanation:
I took the test in k12
Given the following data for the reaction board procedure, calculate the distance from the platform support to the subject's COG: RF2= 400N, 1= 2.5m, wt=600N
Using the formula for equilibrium, the distance from the platform support to the subject's COG is approximately 0.67 meters.
To calculate the distance from the platform support to the subject's COG, we can use the formula for equilibrium:
Sum of torques = 0
Let x be the distance from the platform support to the subject's COG. The torque due to RF2 is RF2 * 1, and the torque due to the subject's weight (wt) is wt * x.
RF2 * 1 - wt * x = 0
Substitute the given values:
400N * 1 - 600N * x = 0
Now, solve for x:
400N = 600N * x
x = 400N / 600N
x = 2/3 m or approximately 0.67 m
So, the distance from the platform support to the subject's COG is approximately 0.67 meters.
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The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines called the Lyman series. Calculate the wavelengths of the first four members of the series.
the wavelengths in the hydrogen spectrum of the first four members of the series where m=1, the first four members have the wavelength of \(1.464 * 10^7 m,\) \(1.231 * 10^7 m,\) \(1.164 * 10^7 m,\) and \(1.097 * 10^7 m.\)
The wavelengths of the spectral lines in the Lyman series of the hydrogen spectrum can be calculated using the Rydberg formula:
1/λ = \(R * (1/n1^2 - 1/n2^2)\)
Where λ is the wavelength of the spectral line, R is the Rydberg constant (approximately \(1.097 * 10^7 m^-^1)\), and n1 and n2 are positive integers representing the energy levels of the electron in the hydrogen atom.
For the Lyman series, we have m = 1, which means the electron transitions from higher energy levels (n2) to the first energy level (n1 = 1).
Let's calculate the wavelengths for the first four members of the Lyman series:
For n2 = 2:
1/λ = \(R * (1/1^2 - 1/2^2)\)
1/λ = \(R * (1 - 1/4)\)
1/λ = \(R * (3/4)\)
λ = \(4/3R\)
Substituting the value of the Rydberg constant:
λ = \((4/3) * (1.097 × 10^7 m^-^1)\)
λ ≈ \(1.464 * 10^7 m\)
For n2 = 3:
1/λ = \(R * (1/1^2 - 1/3^2)\)
1/λ = \(R * (1 - 1/9)\)
1/λ = \(R * (8/9)\)
λ = \(9/8R\)
Substituting the value of the Rydberg constant:
λ = \((9/8) * (1.097 * 10^7 m^-1)\)
λ ≈ \(1.231 * 10^7 m\)
For n2 = 4:
1/λ = \(R * (1/1^2 - 1/4^2)\)
1/λ = \(R * (1 - 1/16)\)
1/λ = \(R * (15/16)\)
λ = \(16/15R\)
Substituting the value of the Rydberg constant:
λ = \((16/15) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.164 * 10^7 m\)
For n2 = 5:
1/λ = \(R * (1/1^2 - 1/5^2)\)
1/λ = \(R * (1 - 1/25)\)
1/λ = \(R * (24/25)\)
λ = \(25/24R\)
Substituting the value of the Rydberg constant:
λ = \((25/24) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.097 * 10^7 m\)
Therefore, the wavelengths of the first four members of the Lyman series are approximately:
\(1.464 * 10^7 m,\)
\(1.231 * 10^7 m,\)
\(1.164 * 10^7 m,\)
and \(1.097 * 10^7 m.\)
Learn more about Lyman series here:
https://brainly.com/question/31856036
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A child drops a ball from a window. The ball strikes the ground in 3 seconds. What is the velocity of the ball the instant before it hits the ground?
Answer:
29.4 m/s
Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3 s
Find: v
v = at + v₀
v = (9.8 m/s²) (3 s) + 0 m/s
v = 29.4 m/s