what is the answer of these two according to this piecewise function?
f(1)=?
f(5)=?​

The rule of inference being used here is Modus Tollens. Modus Tollens is a valid deductive argument form that states if a conditional statement "If P, then Q" is true and the consequent Q is false, then the antecedent P must also be false.

In the given scenario, the conditional statement is "If the guard dog doesn't know a person, then it barks."

The observation that the dog didn't bark (Q is false) leads to the conclusion that the dog must have known the person (the antecedent P is false).

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Answer: Deonn gives 1/2 of the pie away.

Step-by-step explanation:

If you figure that each of the 2 equal parts are now each 1/2 (in other words 1 pie / 2 pieces) then when you give one of the parts away, you are giving 1/2 of the pie away.

The expression 4 - 5(7 - 3x) simplifies to -26 + 15x.


To remove the brackets and simplify the expression 4 - 5(7 - 3x), we can use the distributive property of multiplication over subtraction. The distributive property states that a multiplication of a sum or difference by a number can be done by multiplying each term inside the brackets by the number outside the brackets. So, we get: 4 - 5(7 - 3x) = 4 - 5 × 7 + 5 × 3x.

Simplifying the above expression, we get:4 - 35 + 15x = -31 + 15x. Therefore, the expression 4 - 5(7 - 3x) simplifies to -26 + 15x.

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The possible length of the rectangular field as represented by an inequality is; l ⩾ 322 centimetres

The perimeter of a rectangular field is;.

However; the perimeter of the field is at least 684 centimetres.

Therefore;

\(perimeter \geqslant 684cm\)

Therefore;

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0.16 liters in terms of mililiters is equal to 160 ml

The unitary method is a method in which you find the value of a unit and then the value of a required number of units.

Given here: 0.16 liters

Now we know 1 liter= 1000 ml

Thus 0.16 liter would be equal to 0.16×1000=160 ml

Hence, 0.16 liters in terms of mililiters is equal to 160 ml

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The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

\(72 = 2^3 * 3^2\\\\48 = 2^4 * 3\\\\48 = 2^4 * 3\\\\48 = 2^4 * 3\\\\\)

The GCD of the crayons is \(2^3 * 3\), which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = \(2^3 * 3 * 5\)

The GCD of the drawing paper is also \(2^3 * 3\), which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

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Answer:

x = 12/7

Step-by-step explanation:

You put:                         What you should have had is:

13x - 3y = 12                   13x - 3y = 12

- x + 3y = 12                    + x + 3y = 12

Now that we have that, we can do

14x = 24

Than, divide 24 by 14

x = 24/14

which we can simplify by dividing both by 2

x = 12/7

We can't simplify it down anymore, so this is our answer.

The allowance time, if the standard time is 234.15 minutes and the basic time is 233.4 minutes is 0.75 minute

To calculate the allowance time, we can use the following formula:

Allowance time = Standard time - Basic time

Thus, Allowance time = 234.15 minutes - 233.4 minute = 0.75 minutes

Therefore, the allowance time is 0.75 minutes.

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Answer:

Step-by-step explanation:

The attachment will help you with your question:

The best estimate of the product is b) 1 times 10.

The expression (7/8)8(1/10) can be simplified by canceling out the factor of 8 in the numerator and denominator. This yields the expression 7/10. Therefore, the best estimate of this expression would be 1 times 10, since 7/10 is closest to 1 when rounded to the nearest whole number, and 10 is the closest whole number to the denominator of 7/10.

Thus, the answer is option b, 1 times 10. It is important to note that when estimating products or other mathematical expressions, it is important to consider the context and choose an estimate that is reasonable and makes sense in the given situation.

Correct Question :

Which expression is the best estimate of the product of (7/8)8(1/10)?

a) 0 times 8

b) 1 times 10

c) 7 times 8

d) 1 times 8

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Answer:

691,2

Step-by-step explanation:

i found that

is it true ?

i hope it helps ! ?

Answer:

No comprendo espanol. Yo se un muy poco.

Step-by-step explanation:

a. The median number of calls = 55

b. The first and third quartiles, Q1 = 48 and Q3 = 66

c. The first decile and the ninth decile, D1 = 45 and D9 = 71.

d. The 33rd percentile = 52.5

To answer the questions, let's first organize the data in ascending order:

38 40 41 45 48 48 50 50 51 51 52 52 53 54 55 55 55 56 56 57 59 59 59 62 62 62 63 64 65 66 66 67 67 69 69 71 77 78 79 79

(a) The median is the middle value of a dataset when arranged in ascending order.

Since we have 40 observations, the median is the value at the 20th position.

In this case, the median is the 55th visit.

(b) The quartiles divide the data into four equal parts.

To find the first quartile (Q1), we need to locate the position of the 25th percentile, which is 40 * (25/100) = 10.

The first quartile is the value at the 10th position, which is 48.

To find the third quartile (Q3), we need to locate the position of the 75th percentile, which is 40 * (75/100) = 30.

The third quartile is the value at the 30th position, which is 66.

Therefore, Q1 = 48 and Q3 = 66.

(c) The deciles divide the data into ten equal parts.

To find the first decile (D1), we need to locate the position of the 10th percentile, which is 40 * (10/100) = 4.

The first decile is the value at the 4th position, which is 45.

To find the ninth decile (D9), we need to locate the position of the 90th percentile, which is 40 * (90/100) = 36.

The ninth decile is the value at the 36th position, which is 71.

Therefore, D1 = 45 and D9 = 71.

(d) To find the 33rd percentile, we need to locate the position of the 33rd percentile, which is 40 * (33/100) = 13.2 (rounded to 13). The 33rd percentile is the value at the 13th position.

Since the value at the 13th position is between 52 and 53, we can calculate the percentile using interpolation:

Lower value: 52

Upper value: 53

Position: 13

Percentage: (13 - 12) / (13 - 12 + 1) = 1 / 2 = 0.5

33rd percentile = Lower value + (Percentage * (Upper value - Lower value))

                = 52 + (0.5 * (53 - 52))

                = 52.5

Therefore, the 33rd percentile is 52.5.

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Answer:

(a)  The dependent variable = The total number of new appetizer recipe Tara knows = y

The dependent variable = The total number of new appetizer recipe Tara learns = A

The independent variable = Number of weeks she is in school = x

(b) A = 3 × x

(c) 58 recipes

(d) The total number of recipes Tara knows after 18 weeks = The new recipes she learns during the 18 weeks of school + The number of recipes Tara already knew

Step-by-step explanation:

The given parameters are;

The number of appetizer recipes Tara already knew = 4

The number of new appetizer recipe she will learn each week of school = 3

(a) The dependent variable = The total number of new appetizer recipe Tara knows = y

The dependent variable = The total number of new appetizer recipe Tara learns = A

The independent variable = Number of weeks she is in school = x

The added constant term = The number of appetizer recipes Tara already knew = 4

(b) The equation for the number of appetizer, A, she will learn during school is give as follows;

The number of new appetizer recipe Tara learns in school = 3 × Number of weeks she is in school +

A = 3 × x

(c) The total number of recipes, y, that Tara will knows after 18 weeks in school is therefore;

y = A(18) + The number of appetizer recipes Tara already knew

A(18) = 3 × 18 = 54

y = 54 + 4 = 58 recipes

(d) The total number of recipes Tara knows after 18 weeks is the sum of the new recipes she learns during the 18 weeks of school and the number of recipes Tara already knew.

Answer:

Simple Interest Formula

step 1: multiply the given principal sum P, interest rate R in percentage & time period in years together. step 2: for yearly interest payable, divide the result of above multiplication (P x R x T) by 100 gives the simple interest.

The Graph is not linear.

To graph f, we graph the equation y = f(x). To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x-intercepts, we set y = 0. Since y = f(x), this means f(x) = 0. f(x) = x2−x−6 0 = x2−x−6 0 = (x−3)(x+2) factor x−3=0 or x+2=0 x = −2,3 So we get (−2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x = 0. Using function notation, this is the same as finding f(0) and f(0) = 02 − 0 − 6 = −6. Thus the y-intercept is (0, −6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right. y x f(x) (x, f(x)) −3 6 (−3,6) −2 0 (−2,0) −1 −4 (−1,−4) 0 −6 (0, −6) 1 2 3 4 5 6 7 −3−2−11 2 3 4 1 −6 (1, −6) 2 −4 (2, −4) 3 0 (3, 0) 4 6 (4, 6)

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\((\stackrel{x_1}{-5}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{7}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{(-5)}}} \implies \cfrac{4 -7}{-2 +5}\implies \cfrac{-3}{3}\implies \text{\LARGE -1}\)

Answer:

Hint: Use the Angle Addition Theorem and the fact that a line is made up of two opposite rays. Given: m∠1 = 62° and lines t and l intersect

Step-by-step explanation:

Step-by-step explanation:

Given: m∠1 = 62° and lines t and l intersect

Prove: m∠4 = 62°

Proof:

Statement                                        Reason

m∠1 = 62°                                         Given

m∠1 , m∠2 are supplementary       t is a straight line hence linear pair.

m∠4 , m∠2 are supplementary       r is a straight line hence linear pair.

Angle 2=180-62 = 118                      Definition of supplementary angles

Angle 4 = 180-118 =62                     -do-

Angle 1 = Angle 4                            Equality property

Hence proved

Therefore , the solution of the given problem of unitary method comes out to be a 2-liter soda costs $4.98 and a platter of nachos costs $11.99.

The measurements taken from this femtosecond section must be multiplied by two in order to complete the task using the unitary variable technique. In essence, the characterised by a group and the hue groups are both removed from the unit approach when a desired object is present. For example, 40 pens with a expression price will indeed cost Inr ($1.01). It's possible that one country will have total influence over the approach taken to accomplish this. Almost every living creature has a distinctive quality.

Here,

Let's use "N" for the price of a platter of nachos and "S" for the price of a 2-liter soda.

The first aspect of the issue reveals that:

=> 5N + 2S = 67.87

The second component of the issue reveals the following to us:

=>2N + S = 27.94

=> S = 27.94 - 2N

When we use this expression in place of S in the first equation, we obtain:

=> 5N + 2(27.94 - 2N) = 67.87

When we simplify and account for N, we obtain:

=> 5N + 55.88 - 4N = 67.87\sN = 11.99

We can determine S by substituting this number for N in the second equation:

=> 2(11.99) + S = 27.94\sS = 4.98

As a result, a 2-liter soda costs $4.98 and a platter of nachos costs $11.99.

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Answer: 10.02222222

Step-by-step explanation:

We can just add the 2 numbers together to get: 10.02222222

Answer:

A overly complicated triangle.

Step-by-step explanation: Good luck...

Answer:

Looks like it could be a Scalene( all the sides are different lengths) or it could be an obtuse (one angle is more than 90 degrees)

Step-by-step explanation:

I hope that helps

a) The transition matrix for the Markov chain representing the end of a volleyball game can be constructed based on the given states. The matrix will have dimensions 6x6, with each element representing the probability of transitioning from one state to another. The transition probabilities depend on the probabilities of winning rallies for each team. The resulting transition matrix is as follows:

[ 0 0 0 0 1 0 ] [ 0 0 0 0 0 1 ] [ p 0 0 0 0 1-p ] [ 0 q 0 0 1-q 0 ] [ 0 0 0 0 1 0 ] [ 0 0 0 0 0 1 ]

In this matrix, each row represents a current state, and each column represents a possible next state. The element in the i-th row and j-th column represents the probability of transitioning from state i to state j.

b) To find the probability that the game will not be finished after three rallies when team B is serving and both teams are tied 15-15, we need to calculate the probability of being in the states "tied - B serving" after three rallies. Using the given transition matrix and probabilities p = q = 0.65, we can perform matrix multiplication to obtain the state probabilities after three transitions.

Starting with an initial state vector [0 0 0 1 0 0], representing being in the state "tied - B serving," we multiply it by the transition matrix three times to find the state probabilities after three rallies. The probability of the game not being finished is the sum of the probabilities in the states "tied - B serving," "A ahead by 1 point - A serving," and "B ahead by 1 point - B serving."

Performing the calculations, the probability that the game will not be finished after three rallies is approximately 0.1721 or 17.21%.

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The transition matrix for the Markov chain representing the end of a volleyball game, considering rally point scoring, can be derived based on the six states described: 1) tied - A serving, 2) tied - B serving, 3) A ahead by 1 point - A serving, 4) B ahead by 1 point - B serving, 5) A wins the game, and 6) B wins the game.

.

(a) To construct the transition matrix for the Markov chain, we consider the possible transitions between the six states. The matrix will have dimensions 6x6, with each element representing the probability of transitioning from one state to another. For example, the probability of transitioning from state 1 (tied - A serving) to state 2 (tied - B serving) can be calculated based on the probabilities p and q mentioned in the problem statement. By considering all possible transitions, the complete transition matrix can be obtained.

(b) In this scenario, we start with state 2 (tied - B serving) and need to find the probability that the game will not be finished after three rallies. To calculate this probability, we can use the transition matrix obtained in part (a) and perform matrix multiplication. By multiplying the initial state vector (corresponding to state 2) with the transition matrix three times, we can find the probabilities of ending up in each state after three rallies. The probability of the game not being finished after three rallies would be the sum of the probabilities in states 1 and 2, which represent tied scores.

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Answer:

Step-by-step explanation:

Statement 1 is false because the domain of f is all real numbers since the function is quadratic.

Statement 2 is true.

Statement 3 is true because when we graph f, it is a parabola opening upwards with vertex (3, -1). Since it is opening upward, then the value of x from -∞ to 3 is decreasing while increasing from 3 to ∞.

Statement 4 is false because we just stated above that f is decreasing from -∞ to 3. Hence, f is also decreasing from -1 to 3. Hence, f is not increasing from -1 to ∞.

Statement 5 is false because the axis of symmetry is x = 3.

Statement 6 is true.

it requires a detailed analysis of multiple transactions and the preparation of journal entries. This type of task is better suited for an accounting professional who can thoroughly review the provided information and accurately apply the relevant accounting principles.

However, I can provide a general overview of the journal entries that may be required based on the information given:

January 1, 2020:

Debit: Investment in Kinman Company (40% of cash paid)

Credit: Cash (Amount paid for the acquisition)

Recording Equity in Earnings for 2020:

Debit: Investment in Kinman Company (40% of net loss)

Debit: Investment in Kinman Company (40% of other comprehensive loss)

Credit: Equity in Earnings of Kinman Company

December 31, 2020:

Debit: Investment in Kinman Company (40% of dividend received)

Credit: Dividend Income

January 1, 2021:

Debit: Investment in Kinman Company (40% of additional investment)

Credit: Cash

Recording Equity in Earnings for 2021:

Debit: Investment in Kinman Company (40% of net income)

Credit: Equity in Earnings of Kinman Company

December 31, 2021:

Debit: Investment in Kinman Company (40% of dividend received)

Credit: Dividend Income

Please note that the above entries are a general guideline and may not capture all the necessary transactions. It is advisable to consult with an accounting professional or refer to the specific accounting standards applicable in your jurisdiction for a more accurate and comprehensive answer.

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Answer:

To write and solve an inequality that can be used to determine the number of 50-kilogram crates that can be loaded into the shipping container, we need to first find the total weight of the crates that can be loaded into the container. The maximum weight that can be loaded into the container is 27500 kilograms, and other shipments weighing 9500 kilograms have already been loaded, so the total weight of the crates that can be loaded is 27500 kilograms - 9500 kilograms = 18000 kilograms.

Next, we need to divide the total weight of the crates that can be loaded by the weight of each crate to find the number of crates that can be loaded. Since each crate weighs 50 kilograms, the number of crates that can be loaded is 18000 kilograms / 50 kilograms = 360 crates.

To express this as an inequality, we can use the following equation:

x <= 360

This inequality states that the number of crates that can be loaded into the shipping container (x) must be less than or equal to 360. Therefore, the number of 50-kilogram crates that can be loaded into the shipping container is x <= 360.

Step-by-step explanation:

For the vector field F = √(√(x² + y²)), the circulation and outward flux are calculated for the boundary of the given half annulus region.


To compute the circulation and outward flux for the vector field F = √(√(x² + y²)) on the boundary of the half annulus region, we can use the circulation-flux theorem.

a. Circulation: The circulation represents the net flow of the vector field around the boundary curve. In this case, the boundary of the half annulus region consists of two circular arcs. To calculate the circulation, we integrate the dot product of F with the tangent vector along the boundary curve.

b. Outward Flux: The outward flux measures the flow of the vector field across the boundary surface. Since the boundary is a curve, we consider the flux through the curve itself. To calculate the outward flux, we integrate the dot product of F with the outward normal vector to the curve.

The specific calculations for the circulation and outward flux depend on the parametrization of the boundary curves and the chosen coordinate system. By performing the appropriate integrations, the values of the circulation and outward flux can be determined.

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