Leucine's anticodon is 5'-CAA-3'. Leucine's equivalent codon is 5'-UUG-3'.
How can I locate an anticodon?Simply retranscribe the RNA sequence—that is, write out the complementary bases—to find the total anti-codon sequence that will match a strand of mRNA. The tRNA anti-codon sequence is A-A-T-C-G-C -U-U-A-C-G-A using the mRNA sequence previously mentioned.
What is the lysine anticodon?A codon encoding an amino acid is complemented by an anticodon, which is a three-base sequence. For instance, the anticodon for the amino acid lysine is UUC because it bears the codon AAG. Valine has the anticodons CAA, CAG, CAC, and CAU. This indicates that the valine-encoding codons are GUG, GUA, GUU, and GUC.
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what change occurred in each population of bacteria from the early generation to the later generation ?
The maximal population of some bacterial species at the end of the log phase can reach a density of 10 to 30 billion cells per milliliter under ideal circumstances.
Since the very beginning of life on Earth, bacteria have existed.
There is strong evidence that bacteria have existed since the early Precambrian Period, or roughly 3.5 billion years ago, as evidenced by the discovery of fossilized bacteria in rocks from the Devonian Period (419.2 million to 358.9 million years ago).
At least since the Paleoproterozoic period, which lasted for around 1.8 billion years, when oxygen was produced by cyanobacteria and entered the atmosphere, bacteria have been present in large numbers on Earth.
As a result, bacteria have had plenty of time to evolve into a variety of offspring forms and adapt to their environs.
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9. Which of the following is the independent variable in the experiment?
a. Soil
b. Amount of water
C. Temperature
d. Color of light
Answer:
b
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A molecule of
is shaped like a double helix, which
makes it look like a spiral staircase,
Answer:
DNA
Explanation:
dna has a double helix structure. making it look like a spiral staircase
the study of normal tissue structure is called .the study of normal tissue structure is called .cytologybiopsyautopsyhistology
Answer:
D. histology
Explanation:
The study of normal tissue structure is called Medical Histology.
The White Blood Cell count is elevated, but the patient says that is normal for them. The blood count result belongs where?
As the CC
In the ROS
In the PE
In the Results Section
The answer to the given question is "In the Results Section."The result of White Blood Cell count is elevated, but the patient says that it is normal for them belongs in the Results Section.
What is the Results Section?The Results Section includes a description of all of the findings from lab tests, imaging tests, and any other diagnostic testing that the healthcare provider has requested. It is essential to identify any significant findings from each test to help explain the client's medical problem. As a result, the results area of the medical report is where the findings from the tests requested by the healthcare provider are presented.The Results section of a medical report includes a variety of information, such as the following:Patient’s test results All the test results in comparison to a normal range of resultsInterpretation of the results Patient’s current medicationPatient's vital signs.
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When the concentration of ________ in tissue fluid is too high, intracellular water moves into the extracellular fluid compartment.
When the concentration of electrolytes in tissue fluid is too high, intracellular water moves into the extracellular fluid compartment.
OSMOSIS:
Osmosis is the movement of water molecules from a region of higher concentration to a region of lower concentration through a semipermeable membrane. Osmotic principle is based on concentration gradient i.e. difference in concentration across a membrane. Electrolytes represent solute such as salts, ions, sugar etc. Therefore, when the concentration of electrolytes in tissue fluid is too high, intracellular water moves into the extracellular fluid compartment.Learn more at: https://brainly.com/question/2404589?referrer=searchResults
A cell has 6 chromosomes. How many chromosomes will each daughter cell have if it undergoes mitosis
Answer:
At the end of mitosis, the two daughter cells will be exact copies of the original cell. Each daughter cell will have 30 chromosomes. At the end of meiosis II, each cell (i.e., gamete) would have half the original number of chromosomes, that is, 15 chromosomes.
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Explanation:
The regulation of cerebral blood flow is accomplished through both autoregulation and local regulation. This allows for the brain to meet its metabolic needs. What is the low parameter for arterial blood pressure before cerebral blood flow becomes severely compromised
The low parameter for arterial blood pressure before cerebral blood flow becomes severely compromised is <60 mm Hg.
What is Arterial blood pressure?
This is the force which is exerted by the blood on the walls of the artery during circulation.
The pressure required for blood to reach vital cells and organs must be ≥ 60 mmHg. In cases where it's less, the cells are starved of blood and nutrients thereby leading to their death.
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explain the Big Bang theory. Walk through the process from the Big Bang happening to planets orbiting stars. the following terms must be included in your response :hydrogen,gravity, solar system, planet
Answer:
The "Big Bang" theory does not exist
Explanation:
Which of these is a disadvantage of hydroelectric energy ?
A. Is expensive to build or maintain
B. Has high power plant efficiency
C. Has a long power plant life span
D. Reduces greenhouse gas emissions
Answer:
A. Is expensive to build or maintain
Explanation:
Hydroelectric energy is a type of energy which is generated from the flow of water. In this energy, water is allowed to fall from a certain height on the turbine. The moving of turbine produces energy. The main disadvantage of hydroelectric energy is that it is very expensive and require high amount of money for the construction and maintenance of hydroelectric power plant. The machinery used for the production of hydroelectric energy is very costly.
name the substance produced by type ii alveolar cells that functions in reducing surface tension.
The substance produced by type II alveolar cells that functions in reducing surface tension is called surfactant.
Surfactant is a complex mixture of lipids and proteins that is synthesized and secreted by type II alveolar cells in the lungs. Its primary function is to reduce the surface tension within the alveoli, the tiny air sacs in the lungs where gas exchange takes place.
Surface tension refers to the attractive forces between water molecules at the air-water interface. Without surfactant, the surface tension in the alveoli would be very high, making it difficult for the alveoli to expand during inhalation and preventing efficient gas exchange.
Surfactant molecules are composed of lipids, particularly phospholipids, which have hydrophobic (water-repellent) and hydrophilic (water-attracting) regions.
When surfactant is released into the alveoli, it spreads across the inner lining, creating a thin film that reduces the surface tension.
This allows the alveoli to remain open and expand more easily during inspiration, preventing their collapse and facilitating the exchange of oxygen and carbon dioxide.
Surfactant is particularly important for the proper functioning of the lungs, especially in newborns.
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Why is cell division a necessary part of maintaining multicellular life? Help asap giving brainliest!!!
Answer:
In multicellular animals, mitosis is required to maintain a consistent number of chromosomes in all body cells because it produces diploid daughter cells with genetic makeup that is typically identical to that of the parent cell. Mitosos is responsible for the multicellular organisms' growth. As a cell grows, the ratio between the nucleus and cytoplasm is distributed. Therefore, restoring the nucleo-cytoplasamic ratio is crucial for cell division. Cell repair is a very important mitosis-related function. Plants grow continuously throughout their lives as a result of mitotic divisions in the meristametic tissues, the apical and lateral Meristems.
Explanation:
Which level or organization is higher than the water hole community ?
Answer:
the answer is a
Explanation:
i did that same question in my test
whats the subunits of glucose?
What kind of skeleton is like armor?
Answer:
An exoskeleton is the outermost layer of the skeletal system and the most defensive/resistant to force.
what best describes a rho-independent termination of transcription?
a. DNA sequence is recognized by the termination factor rho (p)
b. an RNA secondary structure is recognized by the termination factor rho (p) c. DNA sequence is recognized by RNA polymerase d. an RNA hairpin structure is formed, triggering the release of RNA polymerase
The best option that describes a rho-independent termination of transcription is d. an RNA hairpin structure is formed, triggering the release of RNA polymerase.
What is rho-independent transcription termination?The rho-independent transcription termination is described as the mechanism of bacterial transcription termination, where the transcription process is terminated by the formation of an RNA hairpin structure. In this mechanism, the RNA hairpin structure forms at the end of the transcription unit, and it functions as a termination signal. The formation of an RNA hairpin structure is necessary to trigger the release of RNA polymerase from the DNA template.
How does rho-independent termination work?Rho-independent termination works by creating an RNA hairpin structure that functions as a signal for RNA polymerase to terminate the transcription process. Here is the process: During transcription, RNA polymerase reads through the DNA template until it reaches the end of the transcription unit. When RNA polymerase reaches the end of the transcription unit, the RNA hairpin structure forms due to the complementary base pairing between the nucleotides of the RNA molecule. The hairpin structure consists of a stretch of U's at the 3' end of the transcript, followed by a GC-rich region that forms a hairpin structure.
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what type of molecule contained within the capsule of some organisms can cleave antibodies, rendering them useless?
The molecule you are referring to is called a "capsule polysaccharide," and it can interfere with the binding of antibodies to the surface of bacteria, rendering them ineffective.
Capsule polysaccharides are complex carbohydrate molecules that are found on the surface of many pathogenic bacteria, including Streptococcus pneumoniae, Haemophilus influenzae, and Neisseria meningitidis. These polysaccharides can inhibit the binding of antibodies to the bacterial surface, making it difficult for the immune system to recognize and eliminate the bacteria. This can be particularly problematic in the case of Streptococcus pneumoniae, which is a major cause of pneumonia and meningitis, especially in young children and elderly individuals.
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did adding animals change the cycling of water in your terrarium? describe what you observed using data from your experiment. if there were changes, why do you think they occured? if no changes occured why do you think there were none?
Generally speaking, the presence of animals in a terrarium can impact the water cycle by increasing the amount of water lost through transpiration and respiration, and by producing waste that can affect the water's chemistry. If changes were observed in the water cycle after adding animals, the causes would need to be determined through careful observation and analysis of the data collected.
The activity of acetylcholine in a synapse is terminated by
C) its active transport across the postsynaptic membrane.
D) its diffusion across the postsynaptic membrane.
E) its degradation by a hydrolytic enzyme on the postsynaptic membrane.
The activity of acetylcholine in a synapse is terminated by E. its degradation by a hydrolytic enzyme on the postsynaptic membrane.
What is degradation by a hydrolytic enzyme?Acetylcholine is a neurotransmitter that is released by neurons and binds to receptors on other neurons. When acetylcholine binds to a receptor, it causes a change in the electrical potential of the postsynaptic neuron. This change in electrical potential can either excite or inhibit the postsynaptic neuron.
The activity of acetylcholine in a synapse is terminated by its degradation by a hydrolytic enzyme called acetylcholinesterase. Acetylcholinesterase is found on the postsynaptic membrane. It breaks down acetylcholine into acetate and choline. Acetate and choline are then recycled by the neuron that released acetylcholine.
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Complete question:
The activity of acetylcholine in a synapse is terminated by
A) its active transport across the presynaptic membrane.
B) its diffusion across the presynaptic membrane.
C) its active transport across the postsynaptic membrane.
D) its diffusion across the postsynaptic membrane.
E) its degradation by a hydrolytic enzyme on the postsynaptic membrane.
What are the two types of crust in the lithosphere?
Answer:
Oceanic crust and continental crust
let-7 mirnas the let-7 family of mirnas regulate insulin resistance, obesity, and diabetes. these mirnas accumulate in human cells with age. overexpression of let-7 mirnas in mice led to insulin-resistance and diabetes in these mice. what strategy involving let-7 mirnas might be a potential treatment for obesity and diabetes?
Treatment with antagomirs specific to let-7 strategy might be a potential treatment for obesity and diabetes.
Let-7 family miRNAs must be the exclusive target of the therapy. Options c and d are so eliminated. Let-7 mRNA expression needs to be reduced in order to treat diabetes and obesity, hence restoration via viral vectors is not a viable approach. Option A is not an option. When let-7 miRNA specific inhibitors are used, their expression will be downregulated and insulin receptor and insulin-like growth factor signaling pathways will be promoted, helping to treat diabetes and obesity.
The Let-7 microRNA precursor was discovered as a result of a research on the timing of development in C. elegans, and it was later established that it belongs to the much wider family of non-coding RNAs known as microRNAs. Let-7 family member and human miR-98 microRNA precursor.
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When cells are going through the steps of mitosis, they are
herpes-infected mucosal cells display notable characteristics in smears.
When examining smears of herpes-infected mucosal cells, there are several notable characteristics that can be observed.
Firstly, the cells may appear swollen and rounded, with a distorted or irregular shape compared to uninfected cells. Additionally, herpes-infected cells often display a characteristic "ground glass" appearance, with a granular and opaque appearance to their cytoplasm.
Another common feature of herpes-infected cells is the presence of intranuclear inclusions, which are aggregates of viral particles that can be seen within the nucleus of the infected cell. These inclusions are often referred to as Cowdry type A inclusions and are a hallmark of herpes infection.
Finally, herpes-infected cells may also display evidence of cellular damage or destruction, such as ruptured membranes or the presence of cellular debris in the surrounding area. Overall, these characteristics are useful diagnostic indicators for identifying herpes infection in mucosal cells and can help guide appropriate treatment and management strategies.
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Frequent earthquakes in an area may indicate
Frequent earthquakes in an area indicates that there are tectonic plates boundaries and there is sudden regression of underground rocks. Through the areas when there is sudden movement and dynamic stress along with the sudden triggering.
What are tectonic plates ?Tectonic plates are larger pieces of earth's crust and uppermost mantle. Tectonic plates movement cause the earthquakes to occur.
The other types of earthquakes are that of volcanic earthquakes, induced earthquakes and collapse earthquakes.
Therefore, earthquakes are mainly due to various conditions and other environmental activities that are not under control.
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How many atoms are in 312 g of oxygen
Answer
1.10 X 10^24
Explanation:
If the sugar concentration in a cell is 4% and the concentration in a cell’s environment is 2%, how can the cell obtain more sugar?
For a cell to obtain more sugar the cell must use active transport to pump the sugar inside it .
Active transport is the movement of molecules across a cell membrane from a region of lower concentration to a region of higher concentration which occur against the concentration gradient . So , it requires cellular energy to achieve this action.
Main function of active transport is involves the movement of molecules from a region of lower concentration to a region of higher concentration with help of energy in form of ATP. examples of active transport include the absorption of glucose in the intestine of the human body and the uptake of minerals or ions into the root hair cells of plants.
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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
THE ANSWER IS C
Explanation:
Publishing results of research projects in peer-reviewed journals enables the scientific and medical community to evaluate the findings themselves. It also provides instructions so that other researchers can repeat the experiment or build on it to verify and confirm the results.
Aunque el oxígeno no participa directamente en el ciclo del ácido cítrico, el ciclo opera únicamente cuando hay O2 presente. ¿Por qué?
why do researchers find the study of fraternal twins important
[Step 1]: Determine from the data (Table 1) whether IGF2 is maternally or paternally imprinted (silenced).
A. Maternal B. Paternal
[Step 2]: In Cross Number 4, what is the expected number of heterozygous (IGF2/Δigf2 ) progeny?
A. 0 B. 12. 5 C. 25 D. 37. 5 E. 50
[Step 3]: To show that the functional allele is reversibly switched by the passage through the germline of the opposite sex, DeChiara et al. Also made intercrosses between heterozygous F1 females and heterozygous F1 males. Based on your determination of how the IGF2 gene is imprinted, determine the expected phenotypic ratio of the progeny from these crosses (Normal : Growth deficient).
A. All Normal B. 3:1 C. 1:1 D. 1:3 E. 1:2:1 F. All dwarf
Step 1: IGF2 is (B) Paternal; Step 2: The expected number of heterozygous (IGF2/Δigf2 ) progeny is (E) 50; Step 3: The expected phenotypic ratio of the progeny from these crosses (Normal : Growth deficient) is (C) 1:1.
Step 1: We must examine the information in Table 1 to establish whether IGF2 is maternally or paternally imprinted (silenced).
We can see from the table that IGF2 expression is only seen when it is inherited from the paternal allele and not from the maternal allele. This indicates that the gene is paternally imprinted, which means that it is silenced when passed down from the mother.
Therefore, the correct option is: B. Paternal.
Step 2: In Cross Number 4, a homozygous IGF2/IGF2 male is crossed with a heterozygous IGF2/Δigf2 female. This means that all children will either inherit the IGF2 or Δigf2 allele from their mother or the IGF2 allele from their father.
A Punnett square can be used to determine the number of heterozygous (IGF2/Δigf2) progeny. The genotypes of the progeny (as obtained from the Punnett square) are: Δigf2, Δigf2, IGF2/Δigf2, IGF2.
Therefore, option (E) 50 is correct since it can be observed that half of the progeny so obtained are heterozygous (IGF2/Δigf2).
Step 3: The progeny of these crossings are predicted to have the following phenotypic ratio:-
If the father is the source of the functional allele: All of the progeny are normal (due to the father's functioning IGF2 allele).If the mother is the source of the functional allele: All of the progeny are growth-deficient (due to the mother's IGF2 allele being silenced).Therefore, a functional allele has a 50% chance of being inherited from the father and a 50% chance of being inherited from the mother. In light of this, the expected phenotypic ratio is (C) 1:1.
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