Answer:
B. 0.36
Step-by-step explanation:
Given:
Right ∆ABC,
AB = 5
BC = 13.93
CA = 13
Required:
Value of sin C
SOLUTION:
\( sin(C) = \frac{opposite}{hypotenuse} \)
Opposite = 5
Hypotenuse = 13.93
\( sin(C) = \frac{5}{13.93} \)
\( sin(C) = 0.3589 \)
\( sin(C) = 0.36 \)
the answer would be B, 0.36
Please help due tonight being graded very urgent need help please Makayla has 68 customers that she delivers a paper to every morning. She gets paid a flat fee of $8.50 per week plus an additional $0.67 per customer per week. How many weeks does she need to deliver papers to save at least $500 to buy a new tablet? make an equation or inequality and solve. Show your work
ok so 68 customers everything morning times 7 days per week is 476 customer.
now we know that 476 x .67 = $318.92
she make 8.50 per week plus $318.92 from customers
now we have this equation of
500 = 8.5x + 318.92
find x you will know how many weeks she needs.
8.5x = 500 - 318.92
8.5x = 181.08
x = 181.08/ 8.5
x ~~ 21.3 weeks
Answer:
1o weeks
Step-by-step explanation:
As I understand it she get's paid 8.50 per week
8.50x
and 0.67 per customer per week
0.67(68)x since there are 68 customers
it has to be at least 500
\(8.5x+0.67(68)x\geq 500\\\\8.5x+45.56x\geq 500\\\\56.06x\geq500\\\\x\geq\frac{500}{56.06} \\\\x\geq 9.24...\\\\x=10\)
Make g the subjest of a=g+h/2
g = a - \(\frac{h}{2}\)
THIS IS MY LAST QUESTION. Okay, im a bit anxious to get this done. Ive done half the problem, I just need the other half.
Answer:
umef leaf ninja the frog held a
A community recreational center has 500 ft of fencing with which to enclose a rectangular parking lot in the back of the property. The building itself will be used as one of the sides of the enclosed area.
What is the maximum area that can be enclosed by the fencing?
If the building itself will be used as one of the sides of the enclosed area. The maximum area that can be enclosed by the fencing is: 31,250ft².
How to find the maximum area?Let the area be x ft long
Let the width be (500 -x )/2
Hence,
x × (500 - x)/2 = -1/2x² + 250x
When,
x = 250
So,
Maximum area =-1/2 × 250² +250 ×250
Maximum area = -31,250ft + 62,500ft
Maximum area = 31,250ft²
Therefore 31,250ft² is the maximum area.
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Which angles equal 91°? angles T and V angles S and U angles U and V angles S and T.
Answer:
Angles T and V
Step-by-step explanation:
Answer:
A. T & V
Step-by-step explanation:
DId the Quiz
Which scales are equivalent to 1 inch to 1 foot? Select all that apply.
Group of answer choices
A. 1 to 12
B. (1/12) to 1
C. 100 to 0.12
D. 5 to 60
E. 36 to 3
F. 9 to 108
I NEED HELP ASAP.
need help with multiple questions (and if you can, show your work, thanks):
1: Measure 8 tbsp. chocolate sauce and add 2 1/2 cups of milk.
2: Start with 1 3/4 cups of milk and add 2 1/2 tbsp. chocolate sauce.
3: Add 3 1/3 tbsp. chocolate sauce to 1 1/4 cups milk.
4: For every 1 cup of milk add 2 1/2 tbsp. of chocolate sauce.
5: Stir 1 tbsp. chocolate sauce into 2/3 cup milk.
With this query, no effort is necessary. measure the tbsp. of all items.
Is milk consumption healthy?A great source of both phosphorus and calcium, which are essential for the growth and upkeep of strong, strong teeth and bones, is milk. They lower the chance of developing osteoporosis and suffering broken bones later in life. Milk encourages strong bones.
1. Measure \(8\) tbsp. chocolate sauce and add \(2\frac{1}{2}\) cups of milk.
No work is required for this question. It is a simple instruction to measure out 8 tbsp. of chocolate sauce and add it to \(2\frac{1}{2}\) cups of milk.
2. Start with \(1\frac{3}{4}\) cups of milk and add \(2\frac{1}{2}\) tbsp. chocolate sauce.
No work is required for this question. It is a simple instruction to start with \(1\frac{3}{4}\) cups of milk and add \(2\frac{1}{2}\) tbsp. of chocolate sauce.
3. Add \(3\frac{1}{3}\) tbsp. chocolate sauce to \(1\frac{1}{4}\) cups milk.
No work is required for this question. It is a simple instruction to add \(3\frac{1}{3}\)tbsp. of chocolate sauce to \(1\frac{1}{4}\) cups of milk.
4. For every 1 cup of milk add \(2\frac{1}{2}\) tbsp. of chocolate sauce.
No work is required for this question. It is a simple instruction to add \(2\frac{1}{2}\) tbsp. of chocolate sauce for every \(1\) cup of milk.
5. Stir \(1\) tbsp. chocolate sauce into \(\frac{2}{3}\) cup milk.
No work is required for this question. It is a simple instruction to stir 1 tbsp. of chocolate sauce into \(\frac{2}{3}\) cup of milk.
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each basket of corn holds 2.25 pounds uf harold sells 15 baskets of corn how many pounds of will he have sold?
Step-by-step explanation:
15×2.25
pounds sold = 33.75
three mutually tangent spheres of radius 1 rest on a horizontal plane. a sphere of radius 2 rests on them. what is the distance from the plane to the top of the larger sphere?
According to the statement the distance from the plane to the top of the larger sphere is 3 + 2 = 5 units.
The distance from the plane to the top of the larger sphere can be found by considering the arrangement of the spheres.
We have three smaller spheres of radius 1 that are mutually tangent to each other and the plane.
On top of them, there is a larger sphere of radius 2.
Let's denote the distance from the plane to the center of the larger sphere as h.
Since the spheres are tangent to each other, the distance from the plane to the top of the larger sphere will be equal to the sum of the radii of the smaller spheres (3 x 1 = 3) plus the radius of the larger sphere (2).
Therefore, the distance from the plane to the top of the larger sphere is 3 + 2 = 5 units.
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there are between 25 and 43 students in a class
the ratio of boys to girls is 5 : 7
how many students are in the class?
Answer:
36
Step-by-step explanation:
Since the sum of the ratios is 5+7=12 the total number of students must be divisible by 12
The only number within the given range is 36
The number of students should be in the class should be considered as the 36.
Calculation of the number of students:Since
there are between 25 and 43 students in a class
the ratio of boys to girls is 5 : 7
So here the total ratio should be like
= 5 + 7
= 12
So here the number of students should be divisible by 12
So, it should be 36
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Lack of attention to date issues can invalidate testing results. what is a good way to make sure data issues are property addressed?
A good way to ensure that data issues are properly addressed is by implementing robust data quality assurance and validation processes. These processes involve various steps and techniques to identify, prevent, and resolve data issues effectively. By following these best practices, you can minimize the risk of invalidating testing results due to date-related problems.
One essential step is to establish clear data quality standards and guidelines. This includes defining data formats, data integrity rules, and validation criteria specific to date-related fields. By setting these standards, you provide a framework for ensuring consistent and accurate data across the testing process.
Another important aspect is to perform comprehensive data profiling and analysis. This involves examining the data to identify anomalies, inconsistencies, or inaccuracies related to dates. By using data profiling tools or writing custom scripts, you can detect issues such as missing values, incorrect formats, or outliers within date fields. This analysis enables you to have an overview of the data quality and pinpoint potential problems.
To address data issues effectively, it is crucial to establish data cleansing procedures. This involves correcting errors, resolving inconsistencies, and standardizing date formats. For instance, you can use data cleaning techniques like imputation to fill in missing dates, transforming data into a consistent format (e.g., YYYY-MM-DD), or removing duplicate entries. By applying these cleansing techniques, you improve the accuracy and reliability of the data used in testing.
Furthermore, implementing data validation checks is essential to identify and flag potential issues during the testing process. This can involve writing automated tests or validation scripts that verify the integrity and correctness of date-related data. By performing validation checks at different stages of the testing process, you can detect anomalies promptly and take appropriate actions to address them.
Lastly, fostering a culture of data quality awareness and accountability is crucial. Promoting education and training on data handling best practices, emphasizing the importance of accurate dates, and encouraging open communication about data issues among team members can significantly contribute to ensuring data issues are adequately addressed.
In summary, to ensure data issues are properly addressed, it is important to establish data quality standards, perform data profiling and analysis, implement data cleansing procedures, incorporate validation checks, and foster a culture of data quality awareness. By following these practices, you can mitigate the risk of invalidating testing results due to date-related problems and enhance the overall reliability and integrity of your data.
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2^2^2^2 - [(2)^2]^3
Simplify this expression:
Answer:
⇛65,472.
Step-by-step explanation:
Given expression is 2^2^2^2 - [(2^2)^3]
⇛ 2^2^4 - [2^(2×3)]
Since (a^m)^n = a^(mn)
⇛ 2^16 - [2^6]
Since (a^m)^n = a^(mn)
⇛ 2^(10+6) - (2^6)
⇛ (2^10 × 2^6)-(2^6)
Since a^m × a^n = a^(m+n)
⇛ 2^6[(2^10)-1]
⇛ 64×(1024-1)
⇛ 64×(1023)
⇛65,472
Answer ↓
The value of the given expression is 65472.
Read more:
simplified form of ( (2^-2) )^-3 x ( (2^-3) )^2....
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Where are the following functions differentiable? Where are they holomorphic? Determine their derivatives at points where they are differentiable. (a) f(z) = e-Xe-iy (b) f(z) = 2x+ixy? (c) f(x) = x2 + iy2 (d) f(z) = exe-iy (e) f(z) = cos x cosh y - isin x sinh y (f) f(z) = Im z (g) f(z) = 1212 = x2 + y2 (h) f(z) = z Im z (i) f(z) = ix+1 (j) f(z) = 4(Re z)(Im z) - i(3)2 (k) f(z) = 2xy – i(x + y)2 (1) f(z) = z2 – Z2
(a) The function f(z) = e^(-x)e^(-iy) is differentiable and holomorphic everywhere in the complex plane since it is the product of two exponential functions, both of which are entire functions. The derivative of f(z) is given by f'(z) = (-e^(-x)e^(-iy), i e^(-x)e^(-iy)).
(b) The function f(z) = 2x + ixy is differentiable and holomorphic everywhere in the complex plane since it is a polynomial in z with complex coefficients. The derivative of f(z) is given by f'(z) = 2 + iy.
(c) The function f(z) = x^2 + y^2 is differentiable and holomorphic everywhere except at the origin, where it is not differentiable. The derivative of f(z) is given by f'(z) = 2x + 2iy.
(d) The function f(z) = e^x e^(-iy) is differentiable and holomorphic everywhere in the complex plane since it is the product of two exponential functions, both of which are entire functions. The derivative of f(z) is given by f'(z) = (e^x e^(-iy), -i e^x e^(-iy)).
(e) The function f(z) = cos(x)cosh(y) - i sin(x)sinh(y) is differentiable and holomorphic everywhere in the complex plane since it is a combination of trigonometric and hyperbolic functions, which are all holomorphic. The derivative of f(z) is given by f'(z) = (-sin(x)cosh(y), -cos(x)sinh(y)).
(f) The function f(z) = Im(z) is differentiable and holomorphic everywhere in the complex plane since it is the imaginary part of z, which is a holomorphic function. The derivative of f(z) is given by f'(z) = 1.
(g) The function f(z) = x^2 + y^2 is differentiable and holomorphic everywhere in the complex plane since it is a polynomial in z with real coefficients. The derivative of f(z) is given by f'(z) = 2x + 2iy.
(h) The function f(z) = zIm(z) is differentiable and holomorphic everywhere in the complex plane since it is a product of z and Im(z), both of which are holomorphic functions. The derivative of f(z) is given by f'(z) = Im(z) + z.
(i) The function f(z) = ix + 1 is differentiable and holomorphic everywhere in the complex plane since it is a polynomial in z with complex coefficients. The derivative of f(z) is given by f'(z) = i.
(j) The function f(z) = 4(Re(z))(Im(z)) - i(3)^2 is differentiable and holomorphic everywhere in the complex plane since it is a combination of the real and imaginary parts of z, which are both holomorphic functions. The derivative of f(z) is given by f'(z) = 4i(Re(z)) - 4(Im(z)).
(k) The function f(z) = 2xy - i(x + y)^2 is differentiable and holomorphic everywhere in the complex plane since it is a polynomial in z with complex coefficients. The derivative of f(z) is given by f'(z) = 2y - 2ix - 2i(x + y).
(l) The function f(z) = z^2 - z^2 is differentiable and holomorphic everywhere in the complex plane since it is a polynomial in z with
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Hi.
i need help with this question.
Workings Please.
1. A 210° sector of a circle of radius 10cm is used to make a cone. Find the radius of the base of the cone and it's height.
Answer: radius = 5.83 cm height = 8.12 cm
Step-by-step explanation:
First, let's find the circumference of the 210° section of the circle.
\(C=2\pi r\bigg(\dfrac{\theta}{360^o}\bigg)\\\\\\C=2\pi(10)\bigg(\dfrac{210^o}{360^o}\bigg)\\\\\\C=\dfrac{35}{3}\pi\)
The circumference of the the cone is \(\dfrac{35}{3}\pi\) . We can use this to find the radius .
\(C=2\pi r\\\\\dfrac{35}{3}\pi=2\pi r\\\\\\\dfrac{35\pi}{3\cdot 2\pi}=r\\\\\\\dfrac{35}{6}=r\\\\\\5.83=r\)
When you fold the 210° section into a cone, the slant height is the original radius of 10. We can use the radius and slant height of the cone to form a right triangle with the height. Use the Pythagorean Theorem to find the height.
radius² + height² = slant height²
\(\dfrac{35}{6}^2\ +\ h^2=10^2\\\\\\.\qquad \quad h^2=10^2-\bigg(\dfrac{35}{6}\bigg)^2\\\\.\qquad \quad h=\sqrt{\dfrac{6^2(10)^2-35^2}{6^2}}\\\\\\.\qquad \quad h=\sqrt{\dfrac{2375}{36}}\\\\\\.\qquad \quad h=8.12\)
ILL GIVE YOU BRAINLIEST PLS HELP ME Tyy Algebra
Use the given lengths of the triangle to find the other two missing lengths.
Answer:You are given the mountain that has a vertical height of 200 yards, and the ski lift will rise at an angle of 40 degrees. You are asked to find how many yards will a tourist travel from the base of the mountain to its peak. You can solve this using trigonometric function. More importantly, imagine that the mountain has a 90 - degree vertical height so that when you connect the peak of the mountain down to its base and then connected to the ski, you can form a right triangle.
Use the sine function.
sine β = opposite side / hypotenuse side
the opposite side will be the height of the mountain and the hypotenuse side will be the distance of the ski from the bottom going to the peak of the mountain
sine 40° = 100 yards / hypotenuse side
hypotenuse side = 100 yards / sine 40°
hypotenuse side = 156 yards
Step-by-step explanation:
Sorry for so much I just like to explain what I think
Vanessa bought 2.67 pounds of pasta salad at the deli. Charlie bought 1.65 pounds of pasta salad. how much more pasta salad Vanessa buy than Charlie?
Answer: 1.02
Step-by-step explanation:
2.67 - 1.65 = 1.02
HELPPPPP I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!
Answer:
I think B
Step-by-step explanation:
Observer X is standing on Plate C near the triple junction of Plates A,B and C. On the map, fill in the dashed plate margins with appropriate symbols, arrows and labels. In 25 years, where will the triple junction be located with respect to X ? where AVB=2 cm/yr (East) BVC=4 cm/yr (East) and note that the plates A and C are continental plates and the plate B is an oceanic plate.
Given that plate A is continental and plate B is oceanic, the eastward movement of the plate margins, plate A and plate B are both moving eastward while plate C remains stationary or moves at a slower rate.
To represent this on the map, we can use symbols, arrows, and labels as follows:
Plate A (continental plate): Draw an arrow pointing eastward with an appropriate symbol to represent a continental plate. Label it as "Plate A."
Plate B (oceanic plate): Draw an arrow pointing eastward with an appropriate symbol to represent an oceanic plate. Label it as "Plate B."
Plate C (continental plate): Draw a dashed line to represent the plate margin of plate C, indicating that it is stationary or moving at a slower rate compared to plates A and B.
After 25 years, considering the rates of plate motion given, the triple junction will have moved in the following direction:
Plate A will have moved 2 cm/yr (eastward) for 25 years, resulting in a total eastward movement of 50 cm.
Plate B will have moved 4 cm/yr (eastward) for 25 years, resulting in a total eastward movement of 100 cm.
Based on these movements, the triple junction will be located 50 cm east and 100 cm east of its current position with respect to observer X.
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A population consists of the following four values: 32, 12, 34, and 16. a. List all samples of size 2, and compute the mean of each sample. b. Compute the mean of the distribution of the sample mean and the population mean. Compare the two values.
a) There are 6 possible samples. b) The population mean is 23.5 and Distribution of Sample Mean is 23.5.
To find all samples of size 2 from the given population, we can select two values at a time without replacement. Let's list all the possible samples and compute the mean of each sample:
Sample 1: {32, 12}
Mean: (32 + 12) / 2 = 22
Sample 2: {32, 34}
Mean: (32 + 34) / 2 = 33
Sample 3: {32, 16}
Mean: (32 + 16) / 2 = 24
Sample 4: {12, 34}
Mean: (12 + 34) / 2 = 23
Sample 5: {12, 16}
Mean: (12 + 16) / 2 = 14
Sample 6: {34, 16}
Mean: (34 + 16) / 2 = 25
Next, let's compute the mean of the distribution of the sample mean and the population mean:
The population mean is the mean of the entire population, which is calculated by summing all the values and dividing by the total number of values:
Population Mean = (32 + 12 + 34 + 16) / 4 = 94 / 4 = 23.5
To find the mean of the distribution of the sample mean, we calculate the mean of the means of all possible samples. Since we have 6 samples, we sum the means of all samples and divide by the total number of samples:
Distribution of Sample Mean = (22 + 33 + 24 + 23 + 14 + 25) / 6 = 141 / 6 ≈ 23.5
Comparing the mean of the distribution of the sample mean (approximately 23.5) with the population mean (23.5), we can observe that they are equal. This is expected because the mean of the distribution of the sample mean is an unbiased estimator of the population mean when the samples are selected randomly and without replacement.
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You are investigating whether the weight of dolphins in the Gulf of Mexico differs across four different coves (labeled cove A, B, C, and D). After collecting data from a random sample of dolphins from cach cove, you create the following partial ANOVA table: S3 Error Total 6 672.20 a. Write the appropriate null and alternative hypotheses for this analysis. (Ipt) b. Complete the ANOVA table above. Write p 0.05 orp0.05 in the final column. (3pt) c. Write a full conclusion in context. (2pt) d. What percent of the variation in dolphin weighs is accounted for by location? (Ipt)
a. Null says equal weight across 4 coves and Alternative says at least 1 is different b. image attached c. reject Null hypothesis d. Proportion of variation = (S3/3) / (S3/3 + 6) = S3 / (S3 + 18)
a. Null hypothesis: The mean weight of dolphins in the Gulf of Mexico is equal across all four coves (cove A, B, C, and D).
Alternative hypothesis: The mean weight of dolphins in the Gulf of Mexico differs across at least one of the four coves.
b. Using the partial ANOVA table, we can fill in the missing values:
The filled table is attached as an image.
c. Based on the ANOVA table, we can reject the null hypothesis (p < 0.05) and conclude that there is a significant difference in the mean weight of dolphins across at least one of the four coves. However, we cannot determine which specific cove or coves have different mean weights without further analysis.
d. The "Between Coves" row in the ANOVA table represents the variation in dolphin weights that can be attributed to the differences among the four coves. The "Total" row represents the total variation in dolphin weights. The proportion of the total variation accounted for by location is the ratio of the sum of squares between coves to the total sum of squares:
Proportion of variation = (S3/3) / (S3/3 + 6) = S3 / (S3 + 18)
Without the value of S3, we cannot calculate the proportion of variation. However, we can say that if the F-ratio is large and the p-value is small, then a larger proportion of the variation in dolphin weights is accounted for by location.
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6 = 4x + 9y ( what Y )
Answer:
Step-by-step explanation:
6
what is true about relations? A. The relation is a linear function. B. The y value increases as x decreased. C. The x increases as y decreases. D.The relation is not a function
Answer:
The answer is A
Step-by-step explanation:
For what value of x must ABCD be a parallelogram?
X=_______
Answer:The value of x must be 7 units.
Step-by-step explanation:
hope this helps
00:00 How many solutions does the equation below have? 2x – 7 + 19 = 6x - 4x + 12 No solution, 1 solution, 2 solutions, Infinitely many solutions
The last equallity is false! Because 0 IS NOT equal to 24, and thus the initial equation has no solution!!!
Felicia earns $1,200 a month. The table displays her monthly budget
Answer:
No table shown
Step-by-step explanation:
Calculate the slope of a line that goes through (3,3) and (8,1).
Answer:
slope formula= y2-y1/x2-x1
=1-3/8-3
= -2/5
pls mark as brainliest thanks!
The weight of a honeybee is 1.2\cdot10^{-1}\text{ g}1.2⋅10 −1 g1, point, 2, dot, 10, start superscript, minus, 1, end superscript, start text, space, g, end text. The weight of the pollen collected by the bee on one trip is 6.0 \cdot 10^{-2} \text{ g}6.0⋅10 −2 g6, point, 0, dot, 10, start superscript, minus, 2, end superscript, start text, space, g, end text.
Answer:1.8*10^-1
Step-by-step explanation:
Answer: 1.8 x 10^−1
Step-by-step explanation:
1. XY is the same as
YX.
Answer:
is the same X×Y,Y×X
that is the answer of your question
be eigenvectors of the matrix A which correspond to theeigenvalues λ1= -4, λ2= 2, andλ3=3, respectively, and let v =.
Express v as a linear combination of v1,v2, and v3, and find Av.
v = __________________ v1 + _______v2 +____________v3
Av=
To express vector v as a linear combination of vectors v1, v2, and v3 and find Av, we need to know the components of vector v, and then we can set up and solve a system of linear equations to determine the coefficients c1, c2, and c3, and calculate Av using matrix multiplication.
In order to express vector v as a linear combination of vectors v1, v2, and v3, we need to know the components of vector v. The components of a vector represent its values along each coordinate axis or direction. Let's assume that the components of vector v are denoted as v_x, v_y, and v_z, representing its values along the x, y, and z axes respectively.
Given that, we can express vector v as a linear combination of vectors v1, v2, and v3 as follows:
v = c1 * v1 + c2 * v2 + c3 * v3
where c1, c2, and c3 are constants that represent the coefficients or weights of the respective vectors v1, v2, and v3 in the linear combination.
To find the coefficients c1, c2, and c3, we can set up a system of linear equations based on the components of vector v and the given vectors v1, v2, and v3. We can then solve this system of linear equations to determine the values of c1, c2, and c3.
Once we have the coefficients c1, c2, and c3, we can also calculate Av, which represents the vector resulting from the matrix multiplication of a matrix A (formed by stacking v1, v2, and v3 as columns) and the column vector containing c1, c2, and c3 as its elements.
In summary, to express vector v as a linear combination of vectors v1, v2, and v3 and find Av, we need to know the components of vector v, and then we can set up and solve a system of linear equations to determine the coefficients c1, c2, and c3, and calculate Av using matrix multiplication.
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