what is the average acceleration of a car if a car rest from 0m/s and reaches a final velocity is 50m/s in 10m/s

Answers

Answer 1

Answer:

Assuming that you meant the final velocity of 50 m/s was reached in 10 s, the answer would be 5 m/s^2.

Explanation:

\(V_{f} = V_{i} + at\)

So we update that with the values that we have.

\(50 = 0 +a(10)\)

then simplify that using algebra to solve for a and we get 5 m/s^2


Related Questions

Answer this question fast please​

Answer this question fast please

Answers

Answer:

A. Strain

Explanation:

(no explanation)

please someone help me with the questions. I asked earlier Thank you.​

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Answer:

Mark me as brainliest as i need it ..

I will answer your questions

A. A star was observed to have a planet orbiting it at a distance of 7.70×107 km. The orbital period of the planet is 329 days. Calculate the mass of the star.
B. How many solar mass is the star? I.e., find the ratio of the star's mass to that of the Sun.

Answers

A. The mass of the star is 1.84 × 10^30 kg. B. The star has a mass of approximately 0.924 solar masses.

A. The mass of the star can be calculated using the third Kepler's law, which relates the orbital period of a planet around a star to the distance between them and the mass of the star.

We have, T² = (4π²/GM)*r³

where T is the orbital period of the planet (329 days), r is the distance between the planet and the star (7.70×10⁷ km), G is the gravitational constant (6.674×10⁻¹¹ N m²/kg²), and M is the mass of the star (in kg).

Converting the units of r to meters and T to seconds, we get:

T = 329 * 24 * 3600 = 28,465,920 s

r = 7.70×10⁷ * 1000 = 7.70×10¹⁰ m

Substituting the values in the above equation and solving for M, we get:

M = (4π²/G) * (r³/T²)

= (4 * (3.1416)²) / (6.674×10⁻¹¹) * ((7.70×10¹⁰)³ / (28,465,920)²)

= 1.84 × 10³⁰ kg

Therefore, the mass of the star is 1.84 × 10³⁰ kg.

B. To find the number of solar masses, we need to divide the mass of the star by the mass of the Sun.

Using the standard value for the mass of the Sun (M☉ = 1.98847 × 10³⁰ kg), we get:

1.84 × 10³⁰ kg / 1.98847 × 10³⁰ kg = 0.924

Therefore, the star has a mass of approximately 0.924 solar masses.

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what mechanism causes hair cell depolarization as stereocilia bend in response to sound waves?

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The mechanism that causes hair cell depolarization as stereocilia bend in response to sound waves is the tip links that connect adjacent stereocilia stretch, opening cation channels and allowing potassium ions to enter the cells, causing depolarization.

The auditory system's sensory receptors, hair cells, transform mechanical vibrations into electrical impulses the brain can understand. The hair cell membrane becomes depolarized due to the stereocilia of the hair cells bending in response to sound waves, which starts an action potential.

The basilar membrane's movement in the cochlea causes the stereocilia to bend in response to sound waves. The tallest stereocilia, known as "kinocilia," are positioned at one end of each row where the stereocilia are grouped in rows.

Positively charged ions, including potassium (K+), enter the cell when the channels open, depolarizing the membrane potential.

Nonetheless, it is evident that the mechanical stresses applied to the stereocilia are essential in starting the process. Research is still being done to determine the precise mechanism of ion channel opening and the nature of the channels involved in hair cell depolarization.

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Which waves can travel through space?

electromagnetic waves only
mechanical waves only
electromagnetic and mechanical waves
longitudinal and electromagnetic waves

Answers

Answer:

Electromagnetic waves only

Only electromagnetic waves can travel through space. hence option A is correct.

What is Electromagnetic waves ?

Electromagnetic waves are the waves associated with photon. Photons carry  electromagnetic waves. it has both electric field and magnetic field perpendicular to each other.

when input of the Dipole antenna is connected to the electric signals having certain frequency. on first half cycle one pole is on positive potential and other is on negative potential. The pole which is at negative potential attracts all the electrons towards it and the pole which is at positive potential attracts positive holes. In the second half cycle polarity of the poles changes and it happen repeatedly, Due to change in polarity of the dipole of the antenna, electrons in the antenna produces electromagnetic waves which we use it for our radio station and mobile phones.

Electromagnetic waves does not require any medium to travel, it can travel through space(vacuum). Waves travels in the medium but there is no medium in the space, but electromagnetic waves are able to travel in the vacuum so scientist named the space as medium of ether.

Hence option A is correct.

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A bullet is fired through a board 10 cm thick in such a way that the bullet's line of motion is perpendicular to the face of the board. If the initial speed of the bullet is 400 m/s and it emerges from the other side of the board with a speed of 300 m/s, what is the total time the bullet is in contact with the board? Label your answer. To write an exponent in your answer, please type it like this: 10^3.

Answers

The total time the bullet is in contact with the board is 8 x 10^-5 seconds

How to calculate?

V1 = 400ms − the initial velocity of the bullet;

V2 = 300 ms− final velocity of the bullet;

d = 10cm = 0.1m − thickness of the board;

a − acceleration inside the board.

t − total time that the bullet is in contact with the board

To find the total time that the bullet is in contact with the board we can use formula :

t =  V1 -V2 / a

where a has been found to be 1.25 x 10^6 m/s²

Substituting the values, we have that total time that the bullet is in contact with the board = 8 x 10^-5 seconds

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A fisherman sees 7 wave crests go by in 10.0 s. The crests are 2.43 m apart. Find the frequency of the wave. (Unit = Hz)​

Answers

Answer: 0.7

Explanation:

A fisherman sees 7 wave crests go by in 10 s, with wavelength (λ) ia 2.43 m has the frequency of the wave is 0.7 hertz.

What is a wave?

A wave is defined as the propagation of distrubance from one place to another. It can carries energy when it propagates into the medium without the net movement of the particles.

It refers to the variations or flow of energy without the transfer of mass of particles or matter. The waves can be visible or invisible. Light and sound are travel in the form of waves.

In waves, the wavelength, frequency, wavespeed and time period can be identified. Frequency refers to the number of oscillations takes place per unit time. It is measured in hertz (Hz).

Wavelength(λ) defines the distance travelled by the wave in a particular time in one vibration. It is also defined as the spatial period of the wave. It can be obtained by taking ratio between wavespeed and frequency. The unit of wavelenght is meter(m).

Wavespeed of the wave equals the wavelength and frequency. It defines the distance travelled/ number of meter covered by given time. Wavespeed (v) = wavelength (λ) / frequency (f). Its unit is m/s.

Time period is inversely proportional to the frequency (f). The time taken by the wave to complete its one oscillation is called time period. Time period = 1 / f . Its unit is seconds (s).

From the given,

time = 10 secs

no of waves = 7

wavelength = 2.43 m

To obtain frequency from the givens, the formula for frequency is:

frequency = no.of.cycles of waves / time taken

                 = 7 / 10

          f     = 0.7 hertz.

Hence, the frequency of the wave is 0.7 Hz for 7 waves and given time 10 s.

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If a pendulum system was established on the Moon, how long would the pendulum be to obtain a period of 3.5 seconds

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To establish a pendulum system on the Moon with a period of 3.5 seconds, the pendulum would need to have a length of approximately 1.11 meters.

A pendulum is a weight suspended from a pivot so that it can swing freely. When a pendulum is displaced to one side of its equilibrium position and then released, it will swing back and forth, and the motion will continue until friction (or drag) causes the oscillations to gradually dampen and come to a halt. The time it takes for one complete oscillation, or period, of a pendulum is determined by its length and the force of gravity on it.

                     In the case of a pendulum on the Moon, the period would be longer than it would be on Earth because the force of gravity is weaker on the Moon. To determine the length of the pendulum needed for a 3.5 second period on the Moon, we can use the following formula:

T = 2π√(L/g)

Where: T = period of the pendulum L = length of the pendulum g = acceleration due to gravity On the Moon, the acceleration due to gravity is about 1.6 m/s², so we can plug in the given period of 3.5 seconds and solve for the length :L = (T²g)/(4π²) = (3.5² × 1.6)/(4π²) ≈ 1.11 meters

Therefore, the pendulum would need to be approximately 1.11 meters long to achieve a period of 3.5 seconds on the Moon.

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On a box are the words 12 Volt : 50 mA
What is the resistor in Kilo-Ohm?

Answers

Answer:

R = 0.24 kilo-ohm

Explanation:

Given that,

Voltage, V = 12 volt

Current, I = 50 mA = 0.05 A

We need to find the resistance of the resistor. We can find it using Ohm's law. So,

V = IR

\(R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.05}\\\\R=240\ \Omega\)

or

R = 0.24 kohm

So, the value of resistance is 0.24 kilo-ohm.

14. the source of a sound wave has a power of 1.00 mw. if it is a point source, (a) what is the intensity 3.00 m away and (b) what is the sound level in decibels at that distance? (c) another identical source is located the same distance away (you are equidistant from both sources). what will the sound level be at your location when both sources play?

Answers

The source of a sound wave has a power of 1.00 mw. if it is a point source, below calculations are based on an ideal point source, which is a theoretical concept that describes a point in space from in an isotropic way(uniform) .

A) The intensity of a sound wave at a distance r from a point source is given by the formula I = P / (4πr^2), where P is the power of the source and r is the distance from the source. So, at a distance of 3.00 m from the source, the intensity would be I = 1.00 mW / (4π(3.00 m)^2) = 0.079 mW/m^2.

B) The sound level in decibels (dB) at a distance of 3.00 m from the source can be calculated using the formula:

L = 10 log(I / I_o)

So, L = 10 log(0.079mW/m^2 / 10^-12 W/m^2) = 70.5 dB

C) when two identical sound sources are located equidistant from a listener, the sound level increases by 3 dB. So, the sound level at your location when both sources play would be 70.5 dB + 3 dB = 73.5 dB

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Which statement describes an example of static electricity?
O A. A person rubs a shoe on a rug, causing extra electrons to be
transferred to the shoe.
O B. Electric charges move from a position of higher potential energy
to a position of lower potential energy.
O C. Electrons flow from an outlet into a toaster, causing it to heat a
slice of bread.
O D. A conductor allows electrons to flow through it.

Answers

I think the answer would be b

The burning of fossil fuels has added pollutants that contain sulfur atoms to the air. These pollutants have contributed to which of the following

A. Drought

B. temperature inversions

C. Tornadoes

D. Acid rain

Answers

D. Sulfur atoms in the air react with oxygen and water in moist air to make acid rain so I would think it’s D

Suggest two uses of pulleys.

Answers

Answer: Elevators use pulleys to function.

A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.

Explanation:

A hockey puck slides with constant velocity. Which claim about the forces acting on the hockey puck must be true? Choose 1 answer: Choose 1 answer: (Choice A) A There is not enough information. (Choice B) B There is no net force on the hockey puck. (Choice C) C There is a net force on the hockey puck. (Choice D) D There are no forces on the hockey puck.

Answers

Answer:

Choice B) B There is no net force on the hockey puck.

Explanation:

In case when the hockey puck the slides with the same velocity or constant velocity so the force with respect to the hockey should contain that there is no net force as if the body moves along with the same velocity or the constant velocity so in this case the body acceleration is zero

And according to the newton second law i.e.

F = ma

In case when the acceleration is zero so the net force is zero

Therefore the option b is correct

What are the main 7 forms of energy?

Answers

Mechanical, chemical, electrical, electromagnetic, thermal, acoustic, and radioactive energy are examples of different types of energy.

What transpires to the energy when a person passes away?

To avoid energetic connection with other individuals, there may be some compacting—holding back—of energy in the heart centre, and the energy field begins to divide during the early stages of death. The bottom three bodies (energy field layers) separate and disintegrate.

According to experts, energy conservation does not equate to energy savings. Energy is neither generated nor destroyed, according to the rule of conservation of energy. Energy doesn't evaporate when it is used by people. Energy may transform from one kind of energy into another.

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Forms of energy include mechanical, chemical, electrical, electromagnetic, thermal, sound, and nuclear energy.

Chemical energy is the power stored in the bonds between atoms and molecules. Things like batteries, biomass, oil, natural gas, and coal all contain chemical energy. Chemical energy is converted into thermal energy, for example, when people burn wood in a fireplace or gasoline in a car's engine.

Tension in objects is a form of mechanical energy. Rubber bands that have been stretched and compressed are two examples of mechanical energy that has been stored.

The energy that an atom's nucleus stores and uses to preserve its structural integrity is known as nuclear energy. Significant amounts of energy may be released during the joining or splitting of the nuclei.

Electrical energy is produced by tiny charged particles called electrons, which typically move along a wire. a specific instance of electrical energy in nature is lightning.

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When a marble is at rest what happened

Answers

The marble will stay in place until another force pushes it

Answer: the marble will remain in place at a constant velocity of zero

Explanation:

Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force

A cross-country skier moves 36 meters eastward, then 44


meters westward, and finally 22 meters eastward.


For this motion, what is the distance moved?


Tap button at left to enter


Distance = 102


answer using our built-in


number pad.


What is the magnitude and direction of the


displacement?


Magnitude =


Tap button at left to enter


answer using our built-in


number pad


Dir'n =


(Tap field to change.)


Check Answers

Answers

Answer:

a) 102 meters

b) 14 meters

c) The direction is eastward.

Explanation:

Distance is said to be the length between two points. It is a scalar quantity.

a) The distance moved = 36 + 44 + 22

                                       = 102 meters

b) Displacement is the distance moved in a specified direction.

Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22

/Displacement/ = +36 -44 +22

                         = +58-44

                         = 14

The magnitude of the displacement is 14 meters.

c) The direction is eastward.

So that the magnitude of displacement and his direction is 14 meters eastward.

Question 4: In a city the traffic lights on the main road are set up so that traffic lights are green for 55 seconds, red for 48 seconds, and amber for 17 seconds (the city is in California, so no one stops on amber).
(a) What is the chance that you will have to stop at a particular traffic light?
(b) Suppose that there are 10 traffic lights in the main street. What is the expected amount of time you are likely to be stopped at traffic lights if you drive all the way down the main street?

Answers

The probability of stopping at a traffic light is about 47.22%.

With 10 traffic lights, expect to be stopped for approximately 5 minutes and 45 seconds along the main street.

(a) To calculate the probability of stopping at a particular traffic light, we need to consider the cycle time of the traffic lights. The cycle time is the total time taken for one complete sequence of green, amber, and red signals. In this case, the cycle time is 55 + 17 + 48 = 120 seconds.

The probability of stopping at a particular traffic light can be calculated by dividing the red signal duration by the cycle time. Therefore, the probability is 48/120 = 0.4 or 40%.

However, in California, no one stops on amber, so we need to exclude the amber duration from the calculation. Therefore, the probability becomes 48/(55 + 48) ≈ 0.4722 or 47.22%.

(b) If there are 10 traffic lights on the main street, we can calculate the expected amount of time spent stopped at traffic lights by multiplying the probability of stopping at each traffic light by the average duration of being stopped.

The average duration of being stopped at a traffic light is the sum of the red signal duration and half of the amber signal duration. So, the average duration is (48 + 17/2) = 56.5 seconds. To find the expected amount of time stopped at traffic lights, we multiply the average duration by the number of traffic lights: 56.5 seconds * 10 = 565 seconds.

Therefore, if you drive all the way down the main street, the expected amount of time you are likely to be stopped at traffic lights is approximately 565 seconds, which is equivalent to 5 minutes and 45 seconds.

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A car is launched by a spring and goes to the top of a loop. Fill in the energy bar chart by drawing a vertical bar(s) in the correct position (both Initial & Final conditions).

Answers

Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

         

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

A 10.0 kg rock is at the top of a 20.0 m. tall hill. How much potential energy does it have?

Answers

Answer:

2000 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 10 × 10 × 20 = 2000

We have the final answer as

2000 J

Hope this helps you

Answer:

\(\boxed {\boxed {\sf 1,960 \ J}}\)

Explanation:

Potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

\(PE= mgh\)

The mass (m) of the rock is 10.0 kilograms. The rock is on top of a hill that is 20.0 meters tall (h). Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared (g).

m= 10.0 kg g= 9.8 m/s²h= 20.0 m  

Substitute the values into the formula.

\(PE= (10.0 \ kg)(9.8 \ m/s^2)(20.0 \ m)\)

Multiply the first two values together.

\(PE=(98 \ kg*m/s^2)(20.0 \ m)\)

Multiply again.

\(PE= 1960 \ kg*m^2/s^2\)

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 1960 kg*m²/s² is equal to 1960 J.

\(PE= 1960 \ J\)

The rock has 1,960 Joules of potential energy.

A toy car is moved 8m, right, then 1.5m, right, and finally 3.0m, left. If it took 5.0 seconds total for the car to travel its 3 routes, then what is the average speed of the toy car?

Answers

Answer:

2.7

Explanation:

V=s÷t

v=13.5÷5.0

V=2.7

Willy is driving 15m/s in a 10m/s zone. Officer Wheeler is sitting at the corner and begins to chase Willy immediately. If the police cruiser accelerates at 2m/s/s,
A) How long does it take for Officer Wheeler to catch up to Willy?
B) How far from the corner is the catch up point?
C) Are the two cars going the same speed at the catch up point?

Answers

Answer:

Explanation:

Given:

V = 15 m/s

a = 2 m/s²

__________

A) t - ?

B) D - ?

С) V₁ - ?

   V₂ - ?

A) Willy equation of motion:

X₁ = V·t

Wheeler's equation of motion:

X₂ = a·t² / 2

X₁ = X₂

V·t = a·t² / 2

V = a·t / 2

Time:

t = 2·V / a = 2·15 / 2 = 15 s

B)

Distance:

D = a·t² / 2 = 2·15² / 2 = 225 m

C)

Speed Willy:

V₁ = 15 m/s

Speed Wheeler:

V₂ = a·t = 2·15 = 30 v/s

V₂ > V₁

What’s the total net charge ?

*20 points!!*

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Whats the total net charge ?*20 points!!*spam/ unrelated content= reporting

Answers

Answer:

-7

Explanation:

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Determine the force (in N) exerted by only the fluid on the window of an instrument probe at this depth if the window is circular and has a diameter of 3.10 cm.

Answers

The force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

To determine the force exerted by only the fluid on the window of an instrument probe, we need to use the equation for pressure:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the distance from the surface of the fluid to the window of the instrument probe.

Assuming that the fluid is water, with a density of 1000 kg/m³, and that the instrument probe is at a depth of 10 meters, we can calculate the pressure:

pressure = 1000 kg/m³ x 9.81 m/s² x 10 m
pressure = 98,100 Pa

To find the force exerted on the circular window, we need to calculate the area of the window:

area = π x (diameter/2)²
area = π x (3.10 cm/2)²
area = 7.55 cm²

Now we can calculate the force:

force = pressure x area
force = 98,100 Pa x 7.55 cm²
force = 740 N

Therefore, the force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

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PLEASE HELP!!!!!

The time needed for a water wave to change from the equilibrium level to the crest is 0.5731 s.
1. What is the period of the wave? Answer in units of s.
2. What is the frequency of the wave? Answer in units of Hz.

Answers

The time taken to reach one crest is 0.5731 s. Then the time period of the wave is 1.146 s. The frequency is the inverse of the period that is 0.87 Hz.

What is period of wave ?

The time period of a wave is the time required to complete one wave cycle. For a transverse wave the period of the wave is the time required to reach from one crest to the next crest of the wave.

Given that, time to reach one crest = 0.5731 s.

then the time for to the next crest from the equilibrium position is :

T = 0.5731 s× 2 = 1.146 s.

Frequency of a wave is the number of wave cycles per second. It is the inverse of time period of the wave.

Hence, frequency = 1/T

ν = 1/ 1.146 s = 0.87 Hz.

Therefore, the period of the wave is 1.14 s and frequency is 0.87 Hz.

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if e is a unit vector directed along an equipotential line, what is the scalar produce e•E? (where E is electric field)

Answers

The angle between e and E is 90 degrees, the cosine of the angle is zero, which means that the scalar product is also zero. In other words, e•E = 0 when e is a unit vector directed along an equipotential line.

If e is a unit vector directed along an equipotential line, then it is perpendicular to the electric field E at every point along that line. This is because equipotential lines represent a constant electric potential, which means that there is no change in potential along that line. Since the electric field is the negative gradient of the potential, it is always perpendicular to the equipotential lines. Therefore, the scalar product e•E between the unit vector e and the electric field E is zero. The scalar product is defined as the product of the magnitudes of the two vectors and the cosine of the angle between them. Since the angle between e and E is 90 degrees, the cosine of the angle is zero, which means that the scalar product is also zero. In other words, e•E = 0 when e is a unit vector directed along an equipotential line.

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Fluffy, a greyhound travels 15 m in 2 s while another greyhound, Tiberius, travels 20 m in 5 s. Construct a distance-time graph comparing the two dogs.

Answers

Answer:

3

Explanation:

dogs

what is the process of subduction

Answers

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.

Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)

Answers

a) Two other forces that act on thee sled are the weight of the daughter and the drag force

b) The drag force slows down the sled while the weight presses it down.

What is motion?

We know that motion is the result of the action of unbalanced forces. From the Newton's third law, we know that if the forces that are acting on an object are balanced that the object is not going to move from its state of rest.

In this case, we are told that a  father pushes his daughter and son on a sled down a hill. The fact that the led is moving is due to the fact that there are forces that are acting on the sled.

The forces that are acting on the sled apart  from the force that was applied in pushing the sled is the drag force and the weight of the son.

The drag force would determine how fast that the sled would move because it acts in opposition to the forward force and tries to slow down the sled as it is moving. The weight of the son does press the sled downwards.

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assuming the batteries are fully charged, how long can the car maintain this speed at that angle?

Answers

The car could maintain its speed for approximately 250 hours, assuming the batteries are fully charged.

To determine how long a car can maintain a certain speed while driving at an angle, we would need additional information regarding the car's specifications, such as its power, battery capacity, energy consumption rate, and efficiency. Without these details, it's not possible to provide a specific answer.

However, I can give you a general concept. The time the car can maintain a certain speed will depend on the available energy stored in the batteries and the rate at which the car consumes energy while driving at that speed and angle.

If we know the car's energy consumption rate (measured in units such as watt-hours per kilometer or kilowatt-hours per mile), and the battery capacity (measured in units such as kilowatt-hours), we can estimate the time the car can maintain the speed.

For example, if we know the car's energy consumption rate is 200 watt-hours per kilometer and the battery capacity is 50 kilowatt-hours, we can calculate the time as follows:

Time (in hours) = Battery Capacity (in kilowatt-hours) / Energy Consumption Rate (in kilowatt-hours per hour)

In this example:

Time = 50 kilowatt-hours / 0.2 kilowatt-hours per hour

Time = 250 hours

So, the car could maintain its speed for approximately 250 hours.

Please note that this is a simplified example, and in reality, there are various factors that can affect the range and duration of an electric vehicle, such as terrain, driving conditions, temperature, and driving style. Additionally, electric cars often have sophisticated energy management systems that optimize efficiency and range.

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