what is the chemical formula for dinitrogen tetroxide?

Answer:

Because they usually are eager to give electron so number of electrons will decrease and number of protons will increase and net charge of the element will be positive and will form positive ions

Explanation:

above

According to the electronic configuration, metal atoms tend to loose electrons to form cations and form electropositive elements.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

the answer is A 1s22s22p6

Answer:

C: checking your email

Explanation:

I believe that C would be impossible, as you cannot use wireless networks without radio waves

Answer:

Cac2 is a answer please mark me brainliest

The correct statements about the energy levels of electrons in shells are the following:

They are the energy charge that an electron possesses, where in each period (in each shell) only a certain number of electrons fit.

Therefore, we can conclude that the electrons of an atom have different energy levels, so they are classified by the energy level in which each of them is located.

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Answer: green house affect is the sun on plants it is transfering energy to the plants to help them grow same with every plant, tree, fruit tree. everything needs sun.

Explanation:  look up there.

Answer:

The greenhouse effect is the warming of climate that results when the atmosphere traps heat radiating from Earth towards space. Certain gases in the atmosphere allow sunlight to pass into the "greenhouse effect," but blocking Earth's from escaping into space. Basically, greenhouse gases are airborne chemicals that contribute to the greenhouse effect by absorbing infrared radiation

Explanation:

Hope this helps

Answer:

sediments consist of rocks and minerals, as well as the remains of plants and animals

Explanation:

The number of mole present in the aluminum foil, given that the foil has a thickness of 1.0 mm is 0.7 mole

We'll begin by obtaining the mass of the aluminum foil. Details below:

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of aluminum = 2.702 × 7

Mass of aluminum = 18.914 g

Finally, we shall determine the number of mole present. Details below:

Mole = mass / molar mass

Number of mole of aluminum = 18.914 / 27

Number of mole of aluminum = 0.7 mole

Thus, the number of mole is 0.7 mole

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A. In this solution, water is the solvent and NaBr is the solute. The water molecules surround the Na+ and Br- ions, dissolving them and keeping them in a homogeneous mixture.

B. In this solution, both ethanol and water are solvents, and they are miscible. Ethanol molecules are surrounded by other ethanol molecules, and water molecules are surrounded by other water molecules. Therefore, each solvent dissolves in the other, and there is no clear distinction of solute and solvent.

C. In this solution, water is the solvent and AgNO3 is the solute. The water molecules surround the Ag+ and NO3- ions, dissolving them and keeping them in a homogeneous mixture.

A. In the solution containing 25.0 g of NaBr and 100.0 g of water, water is the solvent and NaBr is the solute. This is because water is present in greater quantity and serves as the medium in which the NaBr is dissolved.

B. In the solution containing 30.0 mL of ethanol and 20.0 mL of water, ethanol is the solute and water is the solvent. This is because water is present in greater quantity and serves as the medium in which the ethanol is dissolved.

C. In the solution containing 0.5 g of AgNO3 and 15 mL of water, water is the solvent and AgNO3 is the solute. This is because water is present in greater quantity and serves as the medium in which the AgNO3 is dissolved.

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Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

Li would attain the noble-gas configuration of helium (1s²), Na would attain the noble-gas configuration of neon (2s²2p⁶), Br would attain the noble-gas configuration of krypton (3s²3p⁶3d¹⁰4s²4p⁶) and Sr would attain the noble-gas configuration of krypton (4s²3d¹⁰4p⁶).

When atoms of certain elements react to form an ionic compound, they tend to lose or gain electrons in order to achieve a stable electronic configuration similar to that of a noble gas.

The noble gases have completely filled outermost electron shells and are thus chemically inert. Therefore, in order to achieve a similar electronic configuration, atoms of other elements tend to gain or lose electrons to either achieve a completely filled outer shell or an empty outer shell.

a. Lithium (Li) has one valence electron and is likely to lose it to attain the stable electron configuration of helium (He).

b. Sodium (Na) has one valence electron and is likely to lose it to attain the stable electron configuration of neon (Ne).

c. Bromine (Br) has seven valence electrons and is likely to gain one electron to attain the stable electron configuration of krypton (Kr).

d. Strontium (Sr) has two valence electrons and is likely to lose them to attain the stable electron configuration of krypton (Kr).

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Answer:

Explanation:

NaNO3

Just do a double displacement reaction, this is what you get (plus water)

The reaction shifts to the left, and the concentrations of SO2(g) and O2(g) increase.

Simply put, the system will seek to stay at equilibrium by shifting to compensate for change.

Complicatedly put, consider the fact that K (the equilibrium constant) is the concentration of products raised to their coefficients over the concentration of the reactants raised to their coefficients. If we write an expression for K, we get this:

\(K=\frac{[SO_3]^2}{[SO_2]^2[O_2]}\)

If we assume that, at equilibrium, all of the substances have a concentration of 1 molar, we get that

\(K=\frac{[1]^2}{[1]^2[1]}=1\)

If we increase SO3, K will increase. This means the system has now been removed from equilibrium. For example, if you add another mole of SO3, you get

\(Q=\frac{[2]^2}{[1]^2[1]}=4\)

(Q is just K, but not at equilibrium.)

Since the system wants to stay at equilibrium, it will work to restore equilibrium. The only way to do this is to increase the value of the reactants (the bottom numbers), meaning the reaction will shift to the left. Worded differently, when Q>K, the reaction will shift left.

Answer:

going up the slope takes more effort because you are using more of your energy to go up something than going down because of gravity. Gravity wants to pull things down so if you are trying to go up there is more weight than going down.

The can be said about the mass of the 1M HCl and 1 M NaOH after they were combined

The combined mass of the 1 M HCl and 1 M NaOH was the sum of their respective masses.

So, hydrochloric acid reacts with sodium hydroxide approach to form sodium chloride and water. This response can be represented as: Hydrochloric acid + Sodium hydroxide → Sodium chloride + Water.

The mass of the 1.0 M HCl and 1.0 M NaOH solutions after they were combined is 76.5g.

HCl  +  NaOH ⇄ NaCl + H₂O

1 mole of HCl produces 1 mole of NaCl

36.5g of HCl produces= 58.5g of NaCl

36.5g of HCl produces= 18g of H₂O

Total mass after combining = 58.5g + 18g = 76.5g

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          HOOC--CH₂--C(=O)--C(CH₃)(OH)--CH₂--C(=O)--CH₃

Mevalonate is a key intermediate in the biosynthetic pathway that leads to the production of cholesterol, which is a vital component of cell membranes and is used to synthesize hormones and other important molecules. Mevalonate is produced through a series of enzymatic reactions starting from acetyl-CoA, and is eventually converted to the 5-carbon isoprene unit, which serves as the building block for cholesterol and other important molecules.

The enzyme HMG CoA reductase plays a crucial role in this pathway, as it converts HMG CoA to mevalonate, and is the target of many cholesterol-lowering drugs such as statins. Understanding the biosynthesis of mevalonate and cholesterol is important for the development of drugs to treat diseases such as high cholesterol and atherosclerosis.

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The volume that is occupied by the gas is obtained as  56 L.

We know that from the Avogadro's law, the volume that can be occupied by one mole of a gas is obtained as 22.4 L. This implies that we have to find the number of moles in the 70 g of the CO and then obtain the corresponding volume by simple proportion.

Number of moles of CO = 70.0 g/28 g/mol

= 2.5 moles

If 1 mole of the gas occupies 22.4 L

2.5 moles of the gas occupies 2.5 * 22.4/1 mole

= 56 L

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\(KO_2\) can not be formed due to its reactivity, instability, and high formation energy under normal conditions.

\(KO_2\) is a powerful oxidizing agent and for that reacts vigorously with moisture  and carbon dioxide  which are  present in the atmosphere.

This reaction produces oxygen gas and potassium hydroxide of which the  reaction is spontaneous and exothermic, releasing heat.

\(KO_2\)  is also thermodynamically unstable. The high reactivity of the superoxide ion makes it susceptible  to decomposition.

The compound decomposes into potassium oxide (K2O) and oxygen gas (O2) even at room temperature.

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The Ksp of AgCl can be calculated using the formula Ksp = [Ag+]2[Cl-]. Since the AgCl solution is saturated, the concentration of both Ag+ and Cl- ions are equal to the initial concentration of Ag+, which is 1.25×\(10^{-5}\)M. Thus, the Ksp of AgCl is equal to 1.5625×\(10^{-10}\):

Ksp = [Ag+]2[Cl-]

= (1.25×\(10^{-5}\))2

= 1.5625×\(10^{-10}\)

This value of Ksp indicates that the solubility of AgCl in the solution is very low, which means that the solution is saturated with AgCl and no more AgCl can be dissolved in the solution. This also implies that the solution is at equilibrium, with the concentration of all the species in the solution being constant.

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False. The flammability of the cosmos does not decrease in a system where H2 burns in O2 to generate h2o (l). H2 does not catch fire.

Among the most typical dangerous compounds discovered in a laboratory are flammable liquids. The main danger posed by flammable liquids is that they easily ignite and burn. A flammable liquid, according to the National Fire Protection Association (NFPA), is one whose flash point is less than 100°F (38°C).

They consist of petroleum-based fuels like gasoline and kerosene as well as fossil fuels including coal, natural gas, and petroleum. Paper and cardboard are examples of materials produced of wood .

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The concentration of the solution is 1.416 x 10^-6 M. The graph of absorbance versus concentration is typically linear. The balanced equation shows that the stoichiometric ratio of NaOH to HCV is 1:1. Therefore, the limiting reagent is the one that is present in the lower amount. The graphs of concentration versus time for zero-, first-, and second-order reactions.

1.To calculate the concentration of the solution, we can use the formula:

C1V1 = C2V2

where C1 and V1 are the initial concentration and volume of the solute, and C2 and V2 are the final concentration and volume of the solution after dilution.

In this case, we have:

C1 = 1.00 x 10^-5 M

V1 = 3.54 mL = 0.00354 L

V2 = 25 mL = 0.025 L

We can rearrange the formula to solve for C2:

C2 = (C1V1) / V2

= (1.00 x 10^-5 M)(0.00354 L) / 0.025 L

= 1.416 x 10^-6 M

Therefore, the concentration of the solution is 1.416 x 10^-6 M.

2. The graph of absorbance versus concentration is typically linear, and its slope is proportional to the molar absorptivity of the substance at a given wavelength. The axes of the graph are:

x-axis: concentration (in M or mM)

y-axis: absorbance (unitless)

The reaction between sodium hydroxide (NaOH) and crystal violet (CV) is a simple acid-base reaction:

NaOH + HCV → NaCV + H2O

3. We can calculate the number of moles of NaOH and HCV using their concentrations and the volume of the solution:

moles of NaOH = concentration of NaOH x volume of solution

= 1.0 M x V

moles of HCV = concentration of HCV x volume of solution

= 1.00 x 10^-3 M x V

where V is the volume of the solution in liters.

Since the stoichiometric ratio of NaOH to HCV is 1:1, the limiting reagent is the one that produces fewer moles of product. In this case, we see that the number of moles of NaOH is equal to the number of moles of HCV, so neither reactant is limiting.

Therefore, all of the NaOH and HCV will react, and there will be no excess reagent remaining after the reaction.

4. The graphs of concentration versus time for zero-, first-, and second-order reactions are shown below:

Zero-order reaction: The concentration of the reactant decreases at a constant rate. The slope of the graph is equal to the negative of the rate constant.

First-order reaction: The concentration of the reactant decreases exponentially with time. The slope of the graph is proportional to the negative of the rate constant.

Second-order reaction: The concentration of the reactant decreases at a rate that is proportional to the square of its concentration. The slope of the graph is proportional to the rate constant.

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In this reaction, the theoretical yield of aluminum oxide is 77.27 g. The percent yield of aluminum oxide is 78.7%, which is calculated by dividing the actual yield (61.0 g) by the theoretical yield (77.27 g) and multiplying by 100.

The percent yield of a reaction is an important measure of its efficiency. It is calculated by dividing the actual yield of a product by the theoretical yield and multiplying by 100. A higher percent yield indicates that more of the desired product was produced in the reaction, and that the reaction was more efficient.

The percent yield of a reaction can be affected by several factors, such as the amount of reactants present, the temperature at which the reaction is conducted, and the presence of catalysts or other substances that can affect the rate of the reaction.

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Answer:

Yes, you can apply water-based polyurethane over oil-based stain.

Explanation:

is OK to use a water-based polyurethane over an oil-based finish in good condition. You should remove grease, dirt and wax by scrubbing the surface with a wood prep/cleaner/de-glosser, or mineral spirits and synthetic steel wool. ... Apply the new water-based finish per label directions

UV active compounds are those that fluoresce when exposed to a UV lamp. Upon exposure to UV light, these compounds absorb energy and promote an electron from the HOMO to the LUMO. Consider which wavelengths are included in the UV range. CH2=CH2, CH2=CH-CH=CH-CH=CH, CH2=CH-CH=CH-CH=CH-CH=CH, CH2=CH-CH2-

CH=CH, and CH, =CH-CH=CH are all examples of UV active compounds.


The UV active compounds in the given list are CH2=CH-CH=CH-CH=CH, CH2=CH-CH=CH-CH=CH-CH=CH, and CH2=CH-CH2-CH=CH. These compounds will **fluoresce** when exposed to a **UV lamp** and absorb energy to promote an electron from the HOMO to the LUMO.

To determine if a compound is UV active, consider the presence of **chromophores** within the molecule. Chromophores are functional groups that absorb UV light, typically containing conjugated double bonds or aromatic rings. In this case, the first three compounds have conjugated double bonds, making them UV active. The fourth compound, CH=CH-CH=CH, lacks sufficient conjugation to be UV active.

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The half-life of the reaction is 101.9 min

When a reaction's pace and reactant concentration are inversely correlated, the process is known as a first-order reaction. To put it another way, the reaction rate doubles when the concentration does. One or two reactants can be present in a first-order reaction, as in the case of the decomposition process.

The amount of time it takes for the initial concentration of the reactant(s) to decrease by half is known as the half-life of a chemical reaction (abbreviated as "t1/2").

a→b

25% reacted means 75% remains

t=42 min

Rate constant

k=(2.303/t)(log a/a-x)

k=(2.303/42)(log 100/100-25 )

k=(0.054) (log 100/75)

k=(0.054)(0.1249)

k=0.0068 per min

half life

t1/2=(0.693/k)

     =(0.693/0.0068)

     =101.9 min

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The empirical formula of the compound is CS₂

The molecular formula of the compound given that its vapour density is 38 is CS₂.

The mole ratio of the elements on the compound is calculated as follows:

Moles of carbon = 0.33/ 12

Moles of carbon = 0.0275 moles

Mass of sulfur = 2.12 - 0.33 g

mass of sulfur = 1.79 g

Moles of sulfur = 1.79 / 32

Moles of carbon = 0.056 moles

The mole ratio of carbon to sulfur = 1 : 2

The empirical formula of the compound is CS₂

Empirical weight = 12 + (32 * 2)

Empirical weight = 76

Mole weight of compound = 38 * 2 = 76

ratio of molecular weight and empirical weight, n = 76/76

ratio of molecular weight and empirical weight, n= 1

Molecular formula = n (CS₂)

Molecular formula = 1 (CS₂)

Molecular formula = CS₂

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-246 K-

________________

Answer:

I would say B

Explanation:

If I'm wrong I apologize, have a good day

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Answer:

presence or absence of a nucleus

Explanation:

These classification of organisms into broad domains is based on the present or absence of nucleus in the cell of an organism.

The archaea are prokaryotes and they lack a distinct cellular nuclei.

Bacteria are similar to archaea but bacteria have only one RNA polymerase

Eukarya have true nucleus and membrane bound organelles .

So, the variations in their cells are used to classify organisms into the broad categories