What is the diferrence between shear stress and shear strain

Answers

Answer 1

For a small stress, the relation between stress and strain is linear. ... Shear strain is the deformation of an object or medium under shear stress. The shear modulus is the elastic modulus in this case. Shear stress is caused by forces acting along the object's two parallel surfaces.


Related Questions

draw a molecule of carbon monoxide, CO, has ____ atoms.

Answers

2 atoms, 1 carbon and 1 oxygen

3. A car traveling initially at 7.0 m/s accelerates uniformly until it reaches 80.0 m/s. If the car
took 245 s to accelerate, what is its acceleration?

Answers

Answer:

1.1111.22222

Explanation:

A student uses a ruler to measure the length and width of a small rectangular metal
plate. What is the area of the plate in om?
metal plate

a 14.0
b
160
c)
14.7
d)
16.8

Answers

The answer is d. I hope that helps.

A student uses a ruler to measure the length and width of a small rectangular metal plate. 14.7 \(\rm cm^2\) is the area of the plate. Therefore, the correct option is option C.

The size or extent of a two-dimensional surface is described by the mathematical concept of area. It is a measurement of the area contained by a closed figure on a flat surface, such as a square, rectangle, circle, triangle, or other. Depending on the measurement system being used, the area of a form is often stated in square units, such as square metres (m2), square feet (ft2), square centimetres (cm2), or square inches (in2).

Length, l=4.2 cm

width, w=3.5 cm

Area, A=lw

=3.7×3.5

=14.7 \(\rm cm^2\)

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Your question is incomplete but most probably your full question was,  

A student uses a ruler to measure the length and width of a small rectangular metalplate. What is the

A 1,500-kg truck has a net force of 4,200 N acting on it . What is the trucks' acceleration

Answers

Answer:

2.8 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{4200}{1500} = \frac{42}{15} \\ = 2.8\)

We have the final answer as

2.8 m/s²

Hope this helps you

A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse

Answers

The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s  is 720 J/s.

What is power?

Power is the work done by a body in one second.

To calculate the work done by the horse in one seconds, we use the formula below

Formula:

P = Fv................ Equation 1

Where:

P = work done on the horse in one secondF = Force of the horsev = Velocity of the wagon

From the question,

Given:

F = 1800 Nv = 0.4 m/s

Substitute these values into equation 1

P = 1800×0.4P = 720 J/s

Hence, the amount of work done per second by the horse is 720 J/s.

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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.

PLEASE HELP

A planet's distance from _____ and its _____ both determine its overall gravity.
A) the sun; mass
B) the Kuiper belt; diameter
C) Mars; temperature
D) the Milky Way; perimeter

Answers

It is A, sun and mass is what gets us gravity
The answer would be A

Describe the setup of the electromagnet. Why does the wire need to be a conductive material?

Answers

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.

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What do you picture in your mind when you read this simile?

Bolt runs as fast as lighting.

Bolt runs very fast.
Bolt runs in a straight line.
Bolt runs in a wavy manner.
Bolt's each step produces thunder.

Answers

When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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We believe that chains of comet fragments like Comet Shoemaker-Levy 9’s have collided not only with the jovian planets, but occasionally with their moons. What sort of features would you look for on the outer planet moons to find evidence of such collisions?

Answers

For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.

What took place when comet shoemaker-Levy 9 hit Jupiter?

Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.

Why did astronomers consider the Shoemaker 9 impact on Jupiter to be so significant?

Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.

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A 5.1 g experimental dart is fired into a block
of wood with a mass of 27.5 g. The wood
block is initially at rest on a 2.4 m tall post.
After the collision, the wood block and dart
land 2.1 m from the base of the post.
Find the initial speed of the dart.
Answer in units of m/s.

PLSSSS NEED URGENT

Answers

To find the initial speed of the dart, we need to use the principle of conservation of momentum. This principle states that in an isolated system, the total momentum of the system remains constant. In this case, the system consists of the dart and the wood block, so the total momentum of the system before and after the collision must be the same.

We can find the momentum of the dart by using the formula p = mv, where p is the momentum, m is the mass, and v is the velocity. Before the collision, the dart has a mass of 5.1 g and is at rest, so its momentum is 0. After the collision, the dart has a velocity of 2.1 m/s and a mass of 5.1 g, so its momentum is 10.7 kg*m/s.

We can also find the momentum of the wood block by using the same formula. Before the collision, the wood block has a mass of 27.5 g and is at rest, so its momentum is 0. After the collision, the wood block has a velocity of 2.1 m/s and a mass of 27.5 g, so its momentum is 57.9 kg*m/s.

Since the total momentum of the system must remain constant, the momentum of the dart and the wood block after the collision must add up to 0. We can set up the following equation to solve for the initial velocity of the dart:

10.7 kgm/s + 57.9 kgm/s = 0

Solving for v, we find that the initial velocity of the dart is -5.37 m/s. This is the negative of the final velocity of the wood block, indicating that the dart and the wood block moved in opposite directions after the collision.

The final answer is 5.37 m/s.

Why hurricane is dangerous?

Answers

Because you can die from the hurricane that’s why it is dangerous

Answer:

Hurricanes are dangerous because they often carry high winds, in which destroy our homes and other recreational buildings. They also cause flooding, which is a threat to crops, animals, and shelters.

Explanation:

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~Kai~

Calculate the ratio of H+ ions to OH– ions at a pH = 8. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide. Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 8. Are they the same? Why or why not? Record your explanation in Table A. What is the concentration of H+ ions at a pH = 8? mol/L What is the concentration of OH– ions at a pH = 8? mol/L What is the ratio of H+ ions to OH– ions at a pH = 8? :1 OR 1:

Answers

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

Remember the experiment done by Arthur Holly Compton that demonstrated the particle nature of light (X-rays) definitively. The reaction was:γ+e→γ+e (1) where the outgoing gamma was an X-ray of aa. higher?b. lower?frequency than the initial gamma. Circle your choice.

Answers

The correct option is (b)

The outgoing gamma rays are of lower frequency than that of the initial gamma-ray. While investigating the scattering of X-rays, Compton observed that the outgoing rays lose some of their energy in the scattering process and emerge with slightly decreased frequency.

Right answer b
The outgoing rays lose some of their energy.

Suppose a clay model of a koala bear has a mass of 0.235 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.305 kg. Both being soft clay, they naturally stick together. What is their final velocity (in m/s)

Answers

Answer:

The value is  \(v = 0.3133 \ m/s\)

Explanation:

From the question we are told that

     The mass  of the first  model is  \(m_1 = 0.235 \ kg\)

      The sliding speed is \(u_1 = 0.720 \ m/s\)  

       The mass of the second model is  \(m_2 = 0.305 \ kg\)

       

Generally from the law of momentum conservation w have that

                \(m_1 * u_1 + m_2 * m_2 * u_2 = (m_1 + m_2 ) v\)

Here \(u_2\) is the velocity of the second model and given that it is  motionless at it initial state the value will be  \(u_2 = 0 \ m/ s\)

 So  

                \(0.235 * 0.720 + 0.305 * 0 = (0.235 + 0.305 ) v\)

=>              \(v = 0.3133 \ m/s\)

First consider an infinite one-dimensional PE well of
width 1 nm. Calculate the energies of the first three levels. Consider a finite PE well with the same
width (1 nm). The height of the barrier is 2.0 eV. There are only three energy levels E1= 0.23 eV,
E2= 0.89 eV, and E3= 1.81 eV. Are the finite PE well levels higher or lower than the correspond-
ing infinite well levels? Find the electron penetration depth into the barrier for each of the three energy
levels. What is your conclusion?

Answers

ANSWER -

For an infinite one-dimensional potential energy (PE) well of width 1 nm, the energies of the first three levels can be calculated using the Schrödinger equation for a particle in a box. The solutions of the equation give us the allowed energy levels of the particle in the well. The first three energy levels are given by the equation E_n = (h^2/8mL^2) * n^2, where h is Planck's constant, m is the mass of the particle, L is the width of the well, and n is an integer starting from 1, representing the level number.

For a finite PE well, the energy levels are different from the infinite well due to the presence of the barrier. The finite well levels will be lower than the corresponding infinite well levels. The electron penetration depth into the barrier for each of the three energy levels can be calculated using the formula for transmission probability T = (2m/h^2) * (E_incident - E_barrier)^1/2, where E_incident is the energy level of the electron and E_barrier is the height of the barrier.

In conclusion, the energy levels of a finite PE well are lower than those of an infinite well, and the penetration depth into the barrier depends on the energy level of the electron.

A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km. What is the frequency of the waves in such a tsunami?.

Answers

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

What is wavelength, frecuency and propagation speed

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

Frequency of the waves in the tsunami

In this case, you know:

v=700 km/h= 0.194 km/sf= ?λ= 750 km

Replacing:

0.194 m/s=f× 750 km

Solving:

f= 0.194 m/s ÷ 750 km

λ= 2.59×10⁻⁴ Hz

In summary, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

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A sprinter with a mass of 70 kg accelerates at a rate of 5 m/s2. What force is the sprinter exerting?

Answers

Answer:

The force exerted by the sprinter can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration:

F = m * a

where:

F is the force

m is the mass of the object (70 kg)

a is the acceleration (5 m/s^2)

Plugging in the values, we get:

F = 70 kg * 5 m/s^2

F = 350 N

So, the sprinter is exerting a force of 350 N. This is the force that the sprinter's legs are applying to the ground, propelling them forward and producing the acceleration.

A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the cart’s displacement after the first 4.0 s of its motion?
What is your car's initial velocity?

How long is the cart accelerating for?

What is the acceleration of the cart?

Write the equation you will use to solve this problem.

What is the displacement of the shopping cart?
32 m
10 m
55 m
80 m

Answers

Final Velocity = 14m/s

Displacement = 56m

Explanation:

U (initial velocity) = 2m/s

A (acceleration) = 3m/s^2

T (time) = 4s

v (final velocity) = ?

S (displacement) = ?

FIRST FIND FINAL VELOCITY:

\(a = \frac{v - u}{t} \)

(i) Multiply both sides by t:

\(a \times t = v - u\)

(ii) Add u to both sides:

\((a \times t) + u = v\)

(iii) rearrange formula:

\(v = (a \times t) + u\)

v = ( 3 × 4 ) + 2

v = 12 + 2

v = 14m/s

SECOND FIND DISPLACEMENT:

\(v = \frac{s}{t} \)

(i) Multiply both sides by t:

\(v \times t = s\)

(ii) Rearrange formula:

\(s = v \times t\)

s = 14 × 4

s = 56m

Not sure why it isn't one of the options but im pretty sure I did all the steps right...

a cube totally submerged in water . calculate the buoyant force acting on this cube . given : g=10N/kg , volume of the cube =24m3 , density of water = 1000 kg/m3?

Answers

Answer:

\(F_B=235200\ N\)

Explanation:

Given that,

The volume of the cube, V = 24 m³

The density of water, d = 1000 kg/m³

We need to find the buoyant force acting on this cube when it totally submerged in water. The formula for the buoyant force is given by :

\(F_B=dgV\)

Substitute all the values,

\(F_B=1000\times 9.8\times 24\\\\F_B=235200\ N\)

So, the required force is equal to 235200  N.

Find the acceleration for a force of 2 N acting on 2 kg.

Answers

Answer:

The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

Problem #2.3
A sphere of radius i rotates with an angular velocity of 2 about the axis Oz. The surface
charge density c is constant. Find the vector potential and intensity of the magnetic
field inside and outside the sphere.

Problem #2.3A sphere of radius i rotates with an angular velocity of 2 about the axis Oz. The surfacecharge

Answers

The vector potential inside the sphere is μ₀cπ, and the magnetic field inside the sphere is zero. Outside the sphere, the magnetic field intensity is given by B = (μ₀cR²/r²), where R is the radius of the sphere and r is the radial distance from the center of the sphere.

To find the vector potential and intensity of the magnetic field inside and outside a rotating sphere with a constant surface charge density, we can use the Biot-Savart law and Ampere's law.

Inside the sphere:

Inside the sphere, the radial distance r is less than the radius R of the sphere. We consider a circular current loop of radius r within the sphere.

Using the Biot-Savart law, the vector potential (A) at a point inside the sphere due to the circular current loop can be expressed as:

A = (μ₀/4π) ∫(Idl × r)/r²

Since the charge density is constant, the current (I) flowing through the circular loop is proportional to the area of the loop, which can be expressed as I = c × πr².

Substituting this expression for I into the equation for A, we get:

A = (μ₀c/4) ∫(dl × r)/r²

By integrating around the loop, we find that the integral term is equal to 2π, and simplifying further, we obtain:

A = (μ₀c/2r) ∫dl

The integral term on the right-hand side is simply the circumference of the loop, which is 2πr. Substituting this back into the equation, we get:

A = (μ₀c/2r) × 2πr = μ₀cπ

The magnetic field (B) can be obtained from the vector potential using the equation B = ∇ × A. Since the vector potential A is independent of position, the curl of A is zero. Therefore, the magnetic field inside the sphere is zero.

Outside the sphere:

Outside the sphere, the radial distance r is greater than the radius R of the sphere. Using Ampere's law, we can find the magnetic field.

Around a circular loop outside the sphere, the magnetic field is given by:

B = (μ₀I/2πr)

Since the current I is proportional to the area of the loop, which is πR², we have I = cπR². Substituting this expression for I into the equation for B, we get:

B = (μ₀cR²/2πr³) × 2πr = (μ₀cR²/r²)

Therefore, the intensity of the magnetic field outside the sphere is given by B = (μ₀cR²/r²).

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7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.​

Answers

Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

How to determine kinetic energy and speed?

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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the mass of an object is 10 kg and the velocity is 4 m/s, what is the momentum?

Answers

The answer is 40 kg. m/s.

Formula for momentum:

p=mv

p=(10 kg.)(4 m/s)

So, therefore, the final answer is p=40 kg. m/s.

I hope this helped answer your question. Enjoy your day, and take care!

Answer: its 400 n/s

Explanation:

cus my thing said it was right

A sound wave produced by a clock chime is heard 400 m away 2.0 s later. The sound wave has a frequency of 512 Hz. What is its period?

Answers

Answer:

\(\frac{1}{512}\) seconds

Explanation:

T = 1 / f

    where T is the period and f is frequency.

Here the frequency is 512 Hz.

Using the formula:

                                  T = \(\frac{1}{512}\) seconds

Do you think that something can freeze when it is hot? Why or why not?​

Answers

Answer:

yes

Explanation:

because if you put a hot object in a cold place the energy from the hot object transfers to the cold air around it and will eventually get such a low temperature that it freezes.

If the Hawaiian Islands were formed from a moving crustal plate over a hot spot, which direction was the plate
moving?
O East
O West
O Southwest
Northwest

Answers

The answer is Northwest

the lanthanides and actinides belong to the

Answers

Answer:

Inner Transition Metals

Explanation:

The lanthanides and actinides belong to the inner transition metals.

Answer:

inner transition elements

Explanation:

In the periodic table to which the lanthanides and actinides metals belong to is inner transition elements because these elements are present in between transition elements.

Explain the advantages in having the meter officially
defined in terms of the distance light travels in a
given time rather than as the length of a specific metal bar

Answers

Answer:

Thermal expansion causes the bar to expand in length (also, thermal contraction causes the bar to shrink). Having the meter measured in this way allows for consistency and can be easily converted.

Explanation:

Question 1 An object of mass 20kg accelerates from rest to a velocity of 10m/s in 5 sec. calculate the distance covered by the object ​

Answers

Answer:

25 m

Explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)

Now we can write the equation of motion

\(s(t)= s_0 + v_0t + \frac12at^2\)

where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)

Other Questions
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