what is the effective spring constant k of the two-spring system? express the effective spring constant in terms of k 1 and k 2 .

Answer:

Principle Archimedes is applied in building a ship and submarine using the manipulating that buoyancy, is controlled the ballast tank system.

Explanation:

Submarine is rather had they focused on main parts of the submarine,he is complex and long process implementation,the most submarine design like submarine stability.

Submarine stability is complete and the fundamental Archimedes principle to arrive the weight of submarine is equal to buoyancy force.

Submarine into the parts and components of ballast tank the sequence in diving and surfacing,there two vital parts:-  flood parts and air vents

flood parts:- at the bottom position and allow water to enter or leave that tank.

air vents:- air vents at the top of the pressure hall,and that they submarine dive.

this time submarine is most modern system is depth is 300 to 450 meters,high pressure  air is 15 bar is tank air valve.

submarine is basic of the effective volume of all the submarine surfaced condition,submarine minus to the free water flood is equal to the fully pressure hull,submarine is the surfaced condition.

Answer:

As rainwater falls, it is naturally soft. However, as water makes its way through the ground and into our waterways, it picks up minerals like chalk, lime and mostly calcium and magnesium and becomes hard water. ... Even hair washed in hard water may feel sticky and look dull.

Explanation:

The box accelerates down the inclined plane at a rate of approximately 2.93 m/s².

To calculate the rate at which the box accelerates down the inclined plane, we need to consider the forces acting on the box. These forces include the gravitational force and the force of kinetic friction.

Given:

Mass of the box (m) = 6.0 kg

Angle of the inclined plane (θ) = 39°

Coefficient of kinetic friction (μ) = 0.40

First, we determine the gravitational force acting on the box. The gravitational force can be calculated using the formula:

Force_gravity = m × g

Force_gravity = 6.0 kg × 9.8 m/s²

            = 58.8 N

Next, we calculate the force of kinetic friction using the formula:

Force_friction = μ × Force_normal

The normal force (Force_normal) is the component of the gravitational force perpendicular to the inclined plane. It can be calculated as:

Force_normal = Force_gravity × cos(θ)

Force_normal = 58.8 N × cos(39°)

                     ≈ 45.0 N

Substituting this value into the formula for the force of kinetic friction:

Force_friction = 0.40 × 45.0 N

              = 18.0 N

The net force acting on the box down the inclined plane can be calculated as:

Net_force = Force_gravity × sin(θ) - Force_friction

Net_force = 58.8 N × sin(39°) - 18.0 N

         ≈ 35.6 N - 18.0 N

         ≈ 17.6 N

Finally, we calculate the acceleration (a) using Newton's second law:

Net_force = m × a

17.6 N = 6.0 kg × a

a ≈ 2.93 m/s²

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Answer:

Explanation:

The area of the floor covered by his both feet can be found by using the formula

\(a = \frac{f}{p} \\ \)

f is the force

p is the pressure

From the question we have

\(a = \frac{400}{400} = 1 \\ \)

We have the final answer as

Hope this helps you

Answer:

See below

Explanation:

A ) distance = 1/2 a t^2    <==== when starting from rest

          20    = 1/2 (a) (3.5^2)      shows a = 3.27 m/s^2

B)   Velocity(at 3.5 s)   =   a t   = 3.27 * 3.5 = 11.42 m/s

C)    3.5 seconds      +    80 m / 11.42 m/s = 10.5 s

Given data:

* The distance traveled by the air conditioner is,

Solution:

As the air conditioner is falling freely under the action of gravity.

Thus, the acceleration of the air conditioner is equal to the acceleration due to gravity.

As the air conditione ris falling itself from the height.

Thus, the initial velocity of the air conditoner is,

By the kinematics equation, the final velocity of the air conditioner is,

Substituting the known values,

Thus, the final velocity of the air conditioner is 21.69 m/s.

By the kinematics equation, the time taken by the air conditioner,

where t is the time taken by the air conditioner to reach the ground,

Substituting the known values,

Thus, the time taken by the air conditioner ot reach the ground is 2.21 seconds.

OPTION  B IS THE ANSWER

Answer:

The real answer is A 2023 answer -_-

Explanation:

Answer:

a. gravity & hand on book

b. yes - 3rd law

c. no, the are acting on the same object

Hope this helped!

Answer:

The first force is your hand holding the book up, and the other one is gravity pulling the book down. Hope i helped :D

Explanation:

The maximum intensity "w" of the uniform distributed load that can be applied to the beam without risking strut buckle depends on the factor of safety (f.s.) used.

Determining the maximum intensity of the load that a beam can withstand without causing strut buckling requires considering the factor of safety. The factor of safety is a design parameter used to ensure that a structure can handle loads safely without failure.

To calculate the maximum intensity "w," we need to determine the critical load that causes buckling and then divide it by the factor of safety. Buckling occurs when a slender strut subjected to compressive forces becomes unstable and fails under the applied load.

The specific calculation to determine the maximum load will depend on the beam's geometry, material properties, and the boundary conditions. It involves analyzing the Euler buckling equation, which relates the critical buckling load to the beam's length, area moment of inertia, and material properties.

By dividing the critical load by the factor of safety, we ensure that the load applied to the beam remains within a safe range, reducing the risk of buckling or structural failure.

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Answer:

30,000

Explanation:

1 gig is 1000 megabytes

Answer:

20kg

Explanation:

ΣF = ma

500N = 25m

m = 20kg

a. The total electric flux density for point P1(4, -3, 2) is X units.

b. The magnitude of the vector from point A to point D is Y units.

a. The total electric flux density for point P1(4, -3, 2) can be calculated using Gauss's Law. Gauss's Law states that the electric flux passing through a closed surface is proportional to the charge enclosed by that surface. In this case, we have three point charges located at A(5, -1, 5), B(8, -1, 2), and C(3, 7, -2), each with their respective magnitudes of charge. To find the total electric flux density at point P1, we need to consider the electric fields generated by each of these charges and their distances from P1. By summing up the contributions of these electric fields, we can determine the total electric flux density at P1.

b. To find the magnitude of the vector from point A to point D, we need the coordinates of point D. However, the coordinates of point D have not been provided in the given question. Without the coordinates of point D, it is not possible to calculate the magnitude of the vector from point A to point D accurately.

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Answer:

1.8 seconds

Explanation:

Ignoring air friction

d = 1/2 at^2

15    = 1/2 (9.81) t^2    shows  t = 1.75 = 1.8 seconds

Answer:

W = 66 J

Explanation:

Given that,

The weight of the box, W = 44 N

It is placed on a shelf that is 1.5 m above the ground.

We need to find the work done in lifting the box.

We know that,

Work done, W = Fd

So,

W = 44 N × 1.5 m

= 66 J

So, the required work done is equal to 66 J.

Statement A, "Neither X-rays nor radio waves can penetrate Earth's atmosphere" is not true.

X-rays and radio waves are two different forms of light or electromagnetic radiation. Both forms are used in medical imaging and have different properties. X-rays have shorter wavelengths and higher frequency than radio waves. They are also more energetic and can penetrate solid objects. On the other hand, radio waves have longer wavelengths and lower frequency than X-rays. They are used for communication purposes such as radio and TV broadcasting, and can easily penetrate through the Earth's atmosphere. Therefore, the statement A, "Neither X-rays nor radio waves can penetrate Earth's atmosphere" is not true.

Neither X-rays nor radio waves can penetrate Earth's atmosphere is a false statement, as radio waves can easily penetrate through the Earth's atmosphere.

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Answer:

\(2 \: cm\)

Explanation:

Total diameter:

\(12 - 4 = 8 \: cm\)

Diameter of 1 ball:

\( \frac{8}{4} = 2 \: cm\)

Explanation:

To solve this problem, we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the linear expansivity coefficient of brass, L is the original length of the brass rod, and ΔT is the change in temperature.

Given:

α = 2.0 × 10^-5 K^-1 (linear expansivity coefficient of brass)

L = 10.0 m (original length of the brass rod)

ΔT = 41°C - 30°C = 11°C (change in temperature)

Using the formula:

ΔL = αLΔT

ΔL = (2.0 × 10^-5 K^-1) × (10.0 m) × (11°C)

ΔL = 0.0022 m

Therefore, the new length of the brass rod at 30°C will be:

L' = L + ΔL

L' = 10.0 m + 0.0022 m

L' = 10.0022 m

So, the new length of the brass rod at 30°C will be approximately 10.0022 meters.

Answer:

c

Explanation:

The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.

Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.

The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.

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Answer:

lol i know - i was rushing -_-

he= male

her=female

One word with both is heroin but Im not 100% sure

Aswer:

False, the values ​​of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.

Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.

xXCherryCakeXx.

Answer:

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If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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Answer:

In nuclear physics and nuclear chemistry, nuclear fission is a nuclear reaction or a radioactive decay process in which the nucleus of an atom splits into two or more smaller, lighter nuclei. ... Fission is a form of nuclear transmutation because the resulting fragments are not the same element as the original atom.

Explanation:

Plz mark brainliest thanks

Answer:

According to me, I think this is the answer

Explanation:

initial position= -22 meters.

this indicates that object is in the negative direction as a negative sign is used to represent the location.

displacement is indicated as -10.4 meters. this is also in the negative direction.

initial + displacement= final

= -22 + (-10.4)

= -32.4 meters

this would be the final position, away from the origin.

displacement is a vector quantity; both magnitude and direction matter.

The option that does not accurately describe what we observe toward the Galactic center is, at optical wavelengths, we see a cluster of old, red stars. Option C.

This is because at optical wavelengths, the light is blocked by dust and gas in the Galactic center, and hence, we are not able to observe the old, red stars. However, at radio wavelengths, we see giant gas clouds threaded by powerful magnetic fields, which are responsible for the formation of stars in the center. At infrared wavelengths, we see a massive stellar cluster, which includes young, massive stars that emit a lot of infrared radiation.

At X rays, we see faint emission from an accretion disk around a black hole, which is the result of material being pulled into the black hole and emitting X-rays. Thus, all the other options accurately describe what we observe toward the Galactic center, except for option C.

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Electrons are one of the constituents of atoms. It is negatively charged particles and the atom has the same number of protons and electrons.

Matter is made up of atoms. Atoms are made up of protons, electrons, and neutrons. The protons are positively charged particles, electrons are negatively charged particles, and neutrons are neutrally charged particles. Protons and neutrons are present inside the atoms from the nucleus. The electrons are revolving around the nucleus due to attractive force.

The characteristics of the electrons are: Electrons are identified by J.J Thomson by using cathode rays. The electrons are negatively charged particles. The mass of an electron is 9.11×10⁻³¹Kg and the charge of an electron is 1.6×10⁻¹⁹C. They are the fundamental block of all atoms. Cathode beams are the source of electrons.

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1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.

1b) The height of the tank is 2 m.

2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.

3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.

3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.

3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

1a) To calculate the amount of energy stored in the three weights, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

For the 4.5 kg weight:

E = 4.5 x 10 x 0.7 = 31.5 J

For each of the 3.5 kg weight:

E = 3.5 x 10 x 0.7 = 24.5 J

Thus, the total energy stored when all three weights are raised by 70 cm is:

31.5 J + 24.5 J + 24.5 J = 80.5 J

1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:

E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)

To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:

E = mgh

Where,E = Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:

Mass = 200 kg

The height of the tank is 2 m.

Therefore, the gravitational potential energy stored in the water in the tank is:

E = mgh = 200 x 10 x 2 = 4000 J

Assumptions made in the answer:

We have assumed that the tank is full.

2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:

PE = KEPE = mghKE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:

PE = mgh = 200 x 10 x 2 = 4000 J

The potential energy is converted into kinetic energy when the water flows out of the taps.

Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)

3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:

Mass = Volume x Density

Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg

3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:

E = mgh

Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J

3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:

PE = KEP

E = mgh

KE = 1/2mv²

Where,PE = Potential Energy (Joules)

KE = Kinetic Energy (Joules)

m = Mass (kg)

g = Gravity (10 N/kg)

h = Height (m)

v = Velocity (m/s)

Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,

PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s

3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.

3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:

Power = Energy / Time

Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)

The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.

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Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

Answer:

nm i believe pls crown

Explanation: