what is the energy of a photon that, when absorbed by a hydrogen atom, could cause an electronic transition from

1) The speed of the particles would increase when heated

2) The balloon would expand when heated and contract when cooled.

3) On a hot day, the pressure of the gas in a beverage increases

4) The mercury thermometer works by expanding or contracting in response to temperature change.

We know that one of the effects of temperature is that it is able change the molecular motion of an object. Thus the molecules of an object are able to move faster when heat is applied and they are able to slow down when the heat is removed.

This is why a balloon would have a greater volume when the temperature is increased as the gas molecules spread out. The volume would reduce or decrease when the temperature is reduced.

Also, on a hot day, a beverage would tend to be more fuzzy as the pressure of the gas in the beverage would increase as the temperature is increased.

Lastly, when we use the mercury thermometer, the volume of the mercury would increase and this is the reason for the expansion of the mercury during temperature measurement.

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Answer:

the tops ones will be animal and plants

under cells it will be nucleus

the genes

the last three will be eye color, height, and type of fruit

Answer:

Explanation:

7) A block of wood

has a length of 10.2

cm, a width of 6 cm

and a height of 4.1

cm. The wood has

a total mass of 179

grams. What is the

volume of the

wood and what is

the density of the

wood?

volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3

DENSITY = M/V = 179gm/250.92 cm^3

=0.713 gm/cm^3

Answer:

Convection 

is the movement of heat by a fluid such as water or air. The fluid (liquid or gas) moves from one location to another, transferring heat along with it. This movement of a mass of heated water or air is called a current. Radiation is the transfer of heat by electromagnetic waves.

The pressure of \(N_{2}\) will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding \(H_{2}\). The minimum pressure of H2 required to reverse the tendency is 0.01 atm.

The reaction involved is: \(N_{2}\)(g) + 3\(H_{2}\)(g) ⇌ 2\(NH_{3}\)(g)  Hence, when \(H_{2}\) is added to the above system, the \(N_{2}\) and  \(H_{2}\)  will react to produce \(NH_{3}\). This reaction will reduce the amount of \(N_{2}\) present in the system, causing the pressure of \(N_{2}\) to decrease. Therefore, by adding \(H_{2}\)  , we can change the tendency of \(N_{2}\) pressure from rise to fall.To calculate the minimum pressure of  \(H_{2}\)  required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( \(NH_{3}\)) / p(\(N_{2}\)) p3( \(H_{2}\) )

At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of \(H_{2}\)   needed to reverse the tendency. Let's assume that the pressure of \(N_{2}\) has increased by x atm. Therefore, the new pressure of \(N_{2}\) will be (0.0406 + x) atm. At equilibrium, we have:

p2(\(NH_{3}\) ) / p(\(N_{2}\)) p3( \(H_{2}\) ) = 1.7 × 104

On substituting the given values and simplifying, we get:

p2(\(NH_{3}\)) / p(N2) = 6.39 × 10-5

Now, p2(\(NH_{3}\)) = 5.97 atm, and p(\(N_{2}\)) = (0.0406 + x) atm.

On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5

Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of \(H_{2}\)   required to reverse the tendency is 0.01 atm.

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It is important to note that this reaction is specific to the hydrolysis of tannins with Na2CO3.

This equation describes the hydrolysis of one ester group in tannins by Na2CO3. Tannins are a type of polyphenol found in plant tissues, and they contain ester groups that can be hydrolyzed by alkalis such as Na2CO3. In this reaction, the ester group in tannins (C22H18O10) is cleaved by Na2CO3, producing two molecules of benzoic acid (C7H6O2) and two molecules of gallic acid (C9H8O4), along with carbon dioxide (CO2) and water (H2O).

The reaction can be written as:

C22H18O10 + Na2CO3 → 2C7H6O2 + 2C9H8O4 + CO2 + H2O

This equation shows that one molecule of tannin reacts with one molecule of Na2CO3, and produces four molecules of products. The reaction is an example of hydrolysis, which is a chemical reaction that involves the breaking of a chemical bond using water.

It is important to note that this reaction is specific to the hydrolysis of tannins with Na2CO3. Different esters and different alkalis may produce different products.

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Answer:

96 Zr

Explanation:

just took the quiz and that was the right answer

a. The number of grams of sodium oxide produced by 100 g Na would be 134.85 grams while the amount produced by 60 g oxygen would be 232.5 grams.

b. The mass of excess reactant left over at the conclusion of the reaction would be 24.624 grams of oxygen.

The unbalanced equation goes thus: \(Na + O_2 -- > Na_2O\)

First, we need to balance the equation of the reaction. This balanced equation is written as:

\(4 Na + O_2 -- > 2Na_2O\)

From the equation:

With 100 g Na:

Mole = 100/23

        = 4.35 moles

Equivalent mole of \(Na_2O\) = 4.35/2

                                          = 2.175 moles

Mass of 2.175 moles of \(Na_2O\) = 2.175 x 62

                                                 = 134.85 grams

Thus, 134.85 grams of \(Na_2O\) will be produced with 100g of Na.

With 60 g of oxygen:

Mole = 60/32

        = 1.875 moles

Equivalent moles of \(Na_2O\) = 1.875 x 2

                                           = 3.75 moles

Mass of 3.75 moles \(Na_2O\) = 3.75 x 62

                                           = 232.5 grams.

Thus, 232.5 grams of \(Na_2O\) will be produced with 60 g of oxygen.

To get the excess reactant:

Mole of 100 g Na = 4.35 moles

Mole of 60 g oxygen = 1.875 moles

Mole ratio of Na to oxygen = 4:1

Thus the excess reactant is oxygen.

Actual amount of oxygen = 4.35/4

                                           = 1.0875 moles

Excess mole of oxygen = 1.857 - 1.0875

                                       = 0.7695 moles

Mass of excess oxygen = 0.7695 x 32

                                       = 24.624 grams

Thus, the mass of the excess reactant left over after the conclusion of the reaction is 24.624 grams of oxygen.

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Answer:

46.A 47.B 48.B 49.A.50.A.51.B.52.B

The answer of the questions  serially is  true, false,false ,true,true,false and false where blood is  a tissue which circulated by the pumping organ that is heart.

Heart is a muscular organ which is present in most of the animals , it is responsible for pumping blood via the blood vessels to the entire body.The blood which is pumped carries oxygen and nutrients along with it.Along with it on it's way back to heart it carries carbon dioxide to the lungs.

Heart has an approximate size of a closed fist and is present between the lungs in the middle compartment of the chest. It is divided in to for chambers , the upper chambers called atria and lower ones called ventricles.

The wall of the heart is made up of three layers : epicardium,myocardium and endocardium. It pumps blood with a rhythm which is determined by a group of cells which are called the pacemaker cells present in the sinoatrial node.

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To find the final number of moles of gas in a balloon after deflation, you can use the ideal gas law equation, which is PV = nRT

PV = nRT

where P is the  pressure of a  gas , V is the volume of the gas , n is the number of moles of gas, R is the gas constant, and T is the gas's temperature.

If you know the initial pressure, volume, temperature, and number of moles of gas, and the final pressure and volume after deflation, you can use the equation to calculate the final number of moles of gas in the balloon at final pressure .

Here's an example:

Initial conditions: P1, V1, T1, n1

Final conditions: P2, V2, T2, n2

We know that T1 = T2 (the temperature is constant)

So, we can substitute these values into the ideal gas law equation:

P1V1 = n1RT

P2V2 = n2RT

Solving for n2, we get:

n2 = (P1V1) / RT = (P2V2) / RT

Therefore, the final number of moles of gas in the balloon after deflation can be determined by using this equation.

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When diluting a strong acid with water, it is recommended to add the acid to the water and not the other way around. The statement is true.

This is because adding water to the acid can cause a rapid and exothermic reaction, leading to splattering and potential injury.

When the acid is added to the water, the heat generated is absorbed by the water, reducing the potential for splattering. Additionally, adding the acid to water allows for better mixing and reduces the risk of creating concentrated acid pockets that can be dangerous.

Overall, it is important to follow safe laboratory practices when working with acids and to consult with a trained professional if you are unsure about the proper procedures.

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The accurate description of a geocentric solar system is the earth as a reference point.

The solar system refers to the arrangement of the sun and the planets. The description of the solar system in which the earth constitutes the center or reference point is called the geocentric model.

An alternative and more accurate model devised by Copernicus is the heliocentric model in which the sun lies at the center of the solar system.

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The mass of \(Na_3PO_4\) to make 4.5 L of solution is 78.75 grams

The recommended concentration is 1.75% m/v.

This means that 1.75 grams of  \(Na_3PO_4\) is dissolved in 100 mL of water.

In order to make 4.5 L of the solution, 4.5 L of water will be needed.

4.5 L of water is equivalent to 4,500 mL of water.

If 1.75 g is required for 100 mL of water to make 1.75% m/v, then the amount required for 4,500 mL of water will be:

                         1.75 x 4500/100 = 78.75 grams

Thus, the amount of  \(Na_3PO_4\) needed will be 78.75 grams.

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Answer:

The right answer is "74.516 kPa".

Explanation:

The given values are:

V₁ = 21.5 L

V₂ = 32.6L

P₁ = 107 kPa

T₁ =27.2°C+273

T₂ = 44.1 °C+273

As we know,

⇒  \(\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}\)

then,

⇒  \(P_2=\frac{P_1V_1T_2}{T_1V_2}\)

On substituting the given values, we get

⇒       \(=\frac{107\times 21.5\times (44.1+273)}{(27.2+273)\times 32.6}\)

⇒       \(=\frac{107\times 21.5\times 317}{300.2\times 32.6}\)

⇒       \(=\frac{729258.5}{9786.52}\)

⇒       \(=74.516 \ kPa\)

The pH of the solution containing an amphetamine concentration of 219 mg/L is approximately 11.21.

To calculate the pH of a solution containing amphetamine, we first need to determine the concentration of hydroxide ions (OH-) in the solution. We can do this by using the p_Kb value and the concentration of amphetamine.

Given:

Amphetamine concentration = 219 mg/L

To convert the concentration from milligrams per liter (mg/L) to moles per liter (M), we need to know the molar mass of amphetamine. The molar mass of amphetamine (C9H13N) is calculated as follows:

C (carbon) = 12.01 g/mol x 9 = 108.09 g/mol

H (hydrogen) = 1.01 g/mol x 13 = 13.13 g/mol

N (nitrogen) = 14.01 g/mol x 1 = 14.01 g/mol

Total molar mass of amphetamine = 108.09 g/mol + 13.13 g/mol + 14.01 g/mol = 135.23 g/mol

Now, let's calculate the concentration of amphetamine in moles per liter (M):

Concentration (M) = (219 mg/L) / (135.23 g/mol)

= 1.62 mmol/L

= 1.62 x 10^-3 mol/L

Since amphetamine is a weak base, we can assume that most of it will react with water to produce hydroxide ions (OH-). This means that the concentration of hydroxide ions is equal to the concentration of amphetamine.

Concentration of hydroxide ions (OH-) = 1.62 x 10^-3 mol/L

Now we can calculate the pOH using the formula:

pOH = -log10 [OH-]

pOH = -log10 (1.62 x 10^-3)

= 2.79

To calculate the pH, we use the equation:

pH + pOH = 14

pH = 14 - pOH

= 14 - 2.79

= 11.21

Therefore, the pH of the solution containing an amphetamine concentration of 219 mg/L is approximately 11.21.

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Answer:

the answer is C which says 1 and 2

The amount of landfill space saved by recycling paper products in 2010 in the United States is 2.31 times the total amount of MSW recycled in that year.

To calculate the amount of landfill space saved by recycling paper products in 2010 in the United States, we need to find out the number of paper products that were recycled. We can do that by using the data on the total MSW recycled and the percentage of that which was accounted for by paper products.

Percentage of total MSW recycled accounted for by paper products in 2010 = 33%

Amount of landfill space saved per metric ton of paper products recycled = 7 m³

We need to determine the amount of landfill space saved by recycling paper products in 2010 in the United States.

Therefore, Let's assume that the total amount of MSW recycled in 2010 was x metric tons. Then, the number of paper products recycled = 33% of x= (33/100) x metric tons = 0.33x metric tons

Therefore,

The amount of landfill space saved by recycling paper products in 2010 = Amount of paper products recycled × Landfill space saved per metric ton of paper products recycled= 0.33x metric tons × 7 m³/metric ton= 2.31x m³

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Along the coast, its always colder near water

Answer:

They will stay too hot.

Explanation:

You would burn yourself on the mug and your drink would be too hot to drink.

To find the percent composition of Carbon in a substance, you need to calculate the percent of the total mass that is made up of Carbon.

The first step is to add up the masses of all the elements in the substance to get the total mass:

2.59 g Carbon + 39.56 g Sulfur + 43.03 g Oxygen = 85.18 g

Next, divide the mass of Carbon by the total mass and multiply by 100 to get the percent of the total mass that is Carbon:

(2.59 g Carbon / 85.18 g) * 100 = 3.03% Carbon

So, the percent composition of Carbon in the substance is 3.03%.

Given the equation :

CH3OH +Cl2 →← 2 CH3CL + 2OH ^-1

at equilibrium concentration, we have:

(1.5 -2x )/ 5L + (1.0 -x )/5L =2x /5L + 2x /5L

→ (1.5-2x+ 1 -x )/ 5L = 4x /5L

→(0.5 -3x)/5L = 4x/5L (5L in the Left hand side cancels 5L inthe right hand side)

→ 0.5 = 4x +3x

0.5 = 7x

x = 0.5/7

x = 0.071

( Extra note : Now lets test and see if this balances ):

LHS : (1.5 -2x )/ 5L + (1.0 -x )/5L = 0.5 -3x)/5L

= 0.5 - 3(0.071)/5

= 0.287 /5 = 0.05

RHS :4(x) /5 = 4(0.071) /5

= 0.28/5 = 0.05

at equlibrium , LHS = RHS therefore our x value is 0.07

Answer:

B) 4.152 x 10^5

Explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Answer:

D) Chromatography

Explanation:

Answer: It is D. chromatography.

Step-by-step explanation:

when water or dye passes through a medium and changes color then that means it must be chromatography.

Rain freezing is a condition of "exothermic" process. The freezing rain emits thermal energy, which is then transmitted to the earth. The earth will receive thermal energy if the rain loses thermal energy. As a result, the ground's temperature rises.

Due to the salt in saltwater, it freezes at a lower temperature than fresh water, approximately 28.4 degrees Fahrenheit (ca. -2 °C). However, because only the water portion of saltwater freezes, very little salt is present in the ice when it is formed. Water may be made from it by melting it down.

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The empitical formula shows the simplest ratio of elements in a compound (not the total number of atoms in the molecule).

So to find the empirical formula we need to calculate how many moles of each atom we have in this sample. Then we will see the ratio of each element.

We are given the mass, so to convert it to moles we use the molar mass. For this we go to the periodic table and see that the values for each element are:

Na (sodium): 22,99 g/mol

H (hydrogen): 1 g/mol

P (phosphorus): 25,81 g/mol

So we calculate the moles of each element as follows:

And as we see, for every 0.833 moles of Na we have the same number of moles of P, so the ratio of these elements in the molecule is 1 to 1.

As for the hydrogen:

So the ratio Na to H is 1 to 2.

Now we can write the empirical formula as follows=

Nanoscience is a branch of science that focuses on the study of phenomena at the nanoscale, typically between 1 and 100 nanometers. This field encompasses a wide range of scientific disciplines, including physics, chemistry, biology, and engineering. The study of nanoscience involves investigating the unique properties and behaviors that occur at the nanoscale, which can differ significantly from those at larger scales.

Nanoscience is not limited to the study of single atoms or electrons, although these are certainly important areas of investigation within the field. Rather, it is a more broad and interdisciplinary approach to exploring the properties and behavior of matter at very small scales. For example, nanoscience may involve studying how the structure and composition of materials change at the nanoscale, or how the interactions between nanoparticles can lead to new and interesting phenomena.

The study of nanoscience has important implications for a wide range of fields, including medicine, electronics, and energy. By better understanding the unique properties of materials and systems at the nanoscale, researchers can develop new technologies and applications that can revolutionize our world.

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High-quality scientific research is characterized by several key criteria. Three examples of such criteria include: rigorous experimental design and methodology, reliable data analysis and interpretation, and clear and transparent reporting of results.

These criteria ensure that research is conducted in a systematic and reliable manner, leading to trustworthy and valid findings.

Rigorous Experimental Design and Methodology: High-quality scientific research requires a well-designed experimental approach. This involves careful planning, proper control groups, randomization, and replication. A rigorous methodology ensures that experiments are conducted under controlled conditions, minimizing bias and confounding variables, and allowing for accurate and reliable data collection.

Reliable Data Analysis and Interpretation: After data collection, high-quality research involves thorough and appropriate analysis of the data. This includes using appropriate statistical methods to evaluate the significance of the results and drawing valid conclusions. Proper data analysis helps researchers identify patterns, trends, and relationships, supporting or refuting their hypotheses in an objective and reliable manner.

Clear and Transparent Reporting of Results: High-quality research demands transparent reporting of the methods, procedures, and findings. This includes providing detailed descriptions of the experimental setup, data collection processes, and statistical analyses used. Clear reporting allows other researchers to replicate the study and verify its results. Additionally, complete reporting ensures that readers can understand the research methodology and draw their own conclusions based on the evidence presented.

By adhering to these criteria, high-quality scientific research maintains integrity, credibility, and reproducibility. It fosters trust among the scientific community and facilitates the advancement of knowledge by building upon reliable foundations.

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