What is the equation of the line shown in the graph?

Answer:

Yes

Step-by-step explanation:

On my worksheet

Answer: Yes

Step-by-step explanation:

You asked if the line was linear not passing through the origin. The line is linear because it has a slope that is constant. Therefore, it will be drawn as a line, so it is linear.

Answer:

Step-by-step explanation:

1

The difference in the account balances at the end of the loan terms is given as follows:

$1,686.87.

The amount of money earned, in compound interest, after t years, is given by:

\(A(t) = P\left(1 + \frac{r}{n}\right)^{nt}\)

In which:

The parameters for the offer 2 are given as follows:

P = 75000, r = 0.035, n = 12, t = 62/12.

Hence the balance of the offer 2 is given as follows:

B = 75000 x (1 + 0.035/12)^(12 x 62/12)

B = $89,842.51.

The balance of Offer 1 is of $91,529.38, hence the difference in the balances is given as follows:

91529.38 - 89842.51 = $1,686.87.

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Answer:

10bags

Step-by-step explanation:

Answer:

10 bags.

Step-by-step explanation:

I got it right on my quiz- Edge2020

Answer:

C.

Step-by-step explanation:

The random variable W is Normal, with a mean of 28 ounces and a standard deviation of four ounces.  

mean of total = 7+7+7+7 = 28

Variance of total = 4+4+4+4 = 16

SD of total = sqrt(16) = 4

The trader could sell 4 covered call contracts on half of her shares, covering a total of 400 shares (4 contracts * 100 shares per contract), leaving her with 452 shares remaining uncovered.

To determine the number of covered call contracts a trader could sell when owning 852 shares of a stock and planning to cover half of her shares, we need to consider that each standard covered call contract typically covers 100 shares of the underlying stock.

Since the trader plans to sell covered calls on half of her shares, we can calculate the number of shares she wants to cover as 852/2 = 426 shares.

To determine the number of covered call contracts, we divide the number of shares to be covered by the number of shares covered per contract:

Number of contracts = Number of shares to be covered / Number of shares covered per contract

                  = 426 shares / 100 shares per contract

                  = 4.26 contracts.

Since contracts are usually traded in whole numbers, the trader could sell 4 covered call contracts. However, it's important to note that fractional contracts are generally not available, so in practical terms, the trader would likely round down to the nearest whole number.

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In the C-Chart, the value of the C-bar, representing the average count of nonconformities per unit, does not have to be an integer. So, the statement 'In the C-Chart, the value of C-bar must be an integer' is false.

In the C-Chart (also known as the Count Chart), the value of C-bar does not necessarily have to be an integer.

C-bar represents the average count of nonconformities per unit. It can be a decimal value, especially when dealing with continuous data or when the sample size is large.

The C-Chart is a statistical process control chart used to monitor the count of nonconformities in a process. It helps to determine if the process is in control or if there are any unusual patterns or trends in the nonconformity counts. The C-bar value is typically calculated as the total number of nonconformities divided by the number of units or observations.

So, the value of the C-bar in the C-Chart can be a decimal or fractional value, not necessarily an integer.

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The answer to the inequality is expressed as x< 1 and x< -4

Inequalities are mathematical expressions having both sides unequal or rather not equivalent to each other.

Given the inequality;

4x (x+3) < -24

First, expand the bracket

4x² + 12x < -  24

Let's turn to quadratic inequality

4x² + 12x - 24 < 0

Factorize further

4 ( x² + 3x - 4) < 0

4 ( x² + 4x - x - 4) < 0

4 ( x(x + 4) - 1 (x + 4) ) < 0

4(x - 1) ( x + 4) < 0

expand the bracket

4x - 4 < 0

x < 1

And

4x + 16 < 0

x < -4

Thus, the answer to the inequality is expressed as x< 1 and x< -4

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Answer:

y=3x-7

Step-by-step explanation:

Choose 2 points.

(3, 2) and (4, 5)

Use slope formula.

y2-y1/x2-x1

5-2/4-3=

=3/1=3

Slope is 3.

The y-intercept is when x is 0. The y-intercept was already given. It is -7.

Y-intercept is -7.

Now you can use the slope-intercept formula.

y=mx+b

m=slope=3

b=y-intercept=-7

y=3x-7

Hope this helps!

Please mark as brainliest if correct!

Answer:

Around 376.99

Step-by-step explanation:

the formula is 2πrh+2πr²

so if we plug in everything we get 2π(4)(11)+2π(4)²

When we simplify that, we would get 376.99

60% of the people in the room are married men.

We can use the information that the probability of a randomly selected woman being single is 2/5 to find the fraction of people in the room who are married men.

Let's call the fraction of people in the room who are married men x. The fraction of people in the room who are single women is (2/5) and the fraction of people in the room who are married men and their wives is (1-x)

Since there are only single women and married men with their wives at the party, we know that the sum of the fractions of single women and married men and their wives must be 1.

(2/5) + (1-x) = 1

We can solve this equation for x:

x = 1 - (2/5) = 3/5

So the fraction of people in the room who are married men is 3/5 or 0.6

So, 60% of the people in the room are married men.

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Answer:4.62x10^13

Step-by-step explanation:

∫[C] (1/2 * x * dy) = ∫[0 to 1] [(1/2 * x(t) * dy(t))dt] + ∫[0 to 1] [(1/2 * x(t) * dy(t))dt] + ∫[0 to 1] [(1/2 * x(t) * dy(t))dt]. Calculating the three integrals separately and summing them up will give us the area of the region R.

To find the area of the region R bounded by the graphs of y = 1/3x, y = 4 - x, and y = x using a line integral, we can integrate a suitable expression over a closed curve that encloses the region R. First, let's determine the points of intersection of the three curves. Setting y = 1/3x and y = 4 - x equal to each other: 1/3x = 4 - x, x = 12/7. Substituting this value of x into y = 1/3x, we find: y = 1/3 * (12/7) = 4/7. So, one point of intersection is (12/7, 4/7).

Setting y = 1/3x and y = x equal to each other: 1/3x = x, 1 - 3x = 0, x = 1/3. Substituting this value of x into y = 1/3x, we find: y = 1/3 * (1/3) = 1/9. So, another point of intersection is (1/3, 1/9). Setting y = 4 - x and y = x equal to each other: 4 - x = x, 4 = 2x, x = 2. Substituting this value of x into y = 4 - x, we find: y = 4 - 2 = 2. So, the third point of intersection is (2, 2). Now, we need to choose a closed curve that encloses the region R. In this case, we can choose the triangle formed by the three curves as our closed curve.

Let C be the closed curve defined by the line segments connecting the three points of intersection: (12/7, 4/7), (1/3, 1/9), and (2, 2). To calculate the area of region R using a line integral, we can integrate the expression 1/2 * x * dy over the curve C. ∫[C] (1/2 * x * dy). Parametrizing the curve C, we have:x = x(t), y = y(t). For the line segment from (12/7, 4/7) to (1/3, 1/9): x(t) = (12/7 - 1/3) * t + 1/3 y(t) = (4/7 - 1/9) * t + 1/9, where 0 ≤ t ≤ 1

For the line segment from (1/3, 1/9) to (2, 2): x(t) = (2 - 1/3) * t + 1/3, y(t) = (2 - 1/9) * t + 1/9, where 0 ≤ t ≤ 1. For the line segment from (2, 2) to (12/7, 4/7):

x(t) = (12/7 - 2) * t + 2, y(t) = (4/7 - 2) * t + 2, where 0 ≤ t ≤ 1.

Now, we can compute the line integral using these parametric equations:

∫[C] (1/2 * x * dy) = ∫[0 to 1] [(1/2 * x(t) * dy(t))dt] + ∫[0 to 1] [(1/2 * x(t) * dy(t))dt] + ∫[0 to 1] [(1/2 * x(t) * dy(t))dt]. Calculating the three integrals separately and summing them up will give us the area of the region R.

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Answer:

2/3

Step-by-step explanation:

The slope of a line given two points is

m = (y2-y1)/(x2-x1)

   = (4-2)/(0 - -3)

   = (4-2)/(0+3)

    = 2/3

Answer:

definitely 2/3

Step-by-step explanation:

you should know that

Consequently, when a1 is provided as 3 and the expression for the following term is a = 5an-1 + 1, the value of a5 is 2031.

An algebraic progression is when there is a continual difference between terms that follow each other in an series. For illustration, the decimal number 5, 7, 9, 11, 13, and 15 is an example of an algebraic expression with a tolerance of two. A advance with a set tolerance among any two consecutive numbers is referred to as a "arithmetic progression" (A.P.). Two types of algebraic progression are plausible: series in mathematics with a finite length A finite geometric evolution is a series with just a finite number of terms. The early, late, allowance, and frequency of terms may all be calculated using the terms in the series.

given

a1 = 3

a2 = 5 * 3 + 1 = 16

a3 = 5 * 16 + 1  = 81

a4 = 5* 81 + 1 = 406

a5 = 5* 406 + 1 = 2031

Consequently, when a1 is provided as 3 and the expression for the following term is a = 5an-1 + 1, the value of a5 is 2031.

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(a) The values of f(0) = 3 and g(2) = 2.

(b) The values of x for which f(x) = g(x) are -2, 2.

(c) The solutions of the equation f(x) = −1 are x = -3, 4.

(d) The interval on which f is decreasing is [0, 4].

(e) The domain and range of f are:

domain = [-4, 4].

range = [-2, 3].

(f) The domain and range of g are:

domain = [-4, 3].

range = [-0.5, 4].

In Mathematics and Geometry, a function is an equation which defines and represents the relationship that exist between two or more variables.

Part a.

By critically observing the graph of f(x) and g(x) shown in the image attached below, the corresponding output values are as follows:

f(0) = 3.

g(2) = 2.

Part b.

The values of x for which f(x) is equal to g(x) are x = -2 and x = 2;

f(-2) = g(-2) = 1.

f(2) = g(2) = 2.

Part c.

The estimated solutions of the equation f(x) = −1 are as follows;

f(-3) = -1

f(4) = -1

Therefore, x = -3, 4.

Part d.

The function f(x) is decreasing over this interval [0, 4].

Part e.

By critically observing the graph of f(x) shown in the image attached below, we can logically deduce the following domain and range:

domain = [-4, 4].

range = [-2, 3].

Part f.

By critically observing the graph of g(x) shown in the image attached below, we can logically deduce the following domain and range:

domain = [-4, 3].

range = [-0.5, 4].

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Let the speed of the slower ship be x kph and let the speed of the faster ship be y kph.

Therefore, according to the problem we have the following equations:

Equation 1: x + 10 = y (since both ships differ in average speed by 10 kph)

Equation 2: 240/x = 200/y - 2 (since the slower ship takes 2 hours longer to travel a 240-kilometer route than for the faster ship to travel a 200-kilometer route)

Now we will solve the system of equations:

Substitute Equation 1 in Equation 2:240/x = 200/(x + 10) - 2

Simplify and bring x to one side:

240/x - 200/(x + 10) = 2Multiply by x(x + 10) to both sides:

240(x + 10) - 200x = 2x(x + 10)

Expand:240x + 2400 - 200x = 2x² + 20x

Simplify:

40x + 2400 = 2x² + 20x

Rearrange to get quadratic equation:

2x² - 20x - 2400 = 0

Simplify the quadratic equation:

x² - 10x - 1200 = 0

Factorize the quadratic equation

:(x - 40)(x + 30) = 0So x = 40 or x = -30

But we know that x should be a positive value since it is a speed.

Therefore, x = 40 kph is the speed of the slower ship.

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The estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

To estimate the area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints, we can use the right Riemann sum method.

The width of each rectangle, Δx, is given by the interval width divided by the number of rectangles.

In this case, Δx = (π/2 - 0)/4 = π/8.

To calculate the right endpoint values, we evaluate f(x) at the right endpoint of each rectangle.

For the first rectangle, the right endpoint is x = π/8.

For the second rectangle, the right endpoint is x = π/4.

For the third rectangle, the right endpoint is x = 3π/8.

And for the fourth rectangle, the right endpoint is x = π/2.

Now, let's calculate the area for each rectangle by multiplying the width (Δx) by the corresponding height (f(x)):

Rectangle 1: Area = f(π/8) * Δx = 5cos(π/8) * π/8

Rectangle 2: Area = f(π/4) * Δx = 5cos(π/4) * π/8

Rectangle 3: Area = f(3π/8) * Δx = 5cos(3π/8) * π/8

Rectangle 4: Area = f(π/2) * Δx = 5cos(π/2) * π/8

Now, let's calculate the values:

Rectangle 1: Area = 5cos(π/8) * π/8 ≈ 0.2887

Rectangle 2: Area = 5cos(π/4) * π/8 ≈ 0.3142

Rectangle 3: Area = 5cos(3π/8) * π/8 ≈ 0.2887

Rectangle 4: Area = 5cos(π/2) * π/8 ≈ 0

Finally, to estimate the total area, we sum up the areas of all four rectangles:

Total Area ≈ 0.2887 + 0.3142 + 0.2887 + 0 ≈ 0.8916

Therefore, the estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

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The image of v is (1, 17).

The preimage of w is (12, -7).

To find the image of v and the preimage of w using the given function T(V₁, V₂) = (V₁ + V₂, V₁ - V₂), we substitute the coordinates of v and w into the function.

Given:

v = (9, -8)

w = (5, 19)

Image of v:

To find the image of v, we substitute its coordinates into the function:

T(9, -8) = (9 + (-8), 9 - (-8))

= (1, 17)

Therefore, the image of v is (1, 17).

Preimage of w:

To find the preimage of w, we need to solve the function for V₁ and V₂ when the result is equal to w = (5, 19).

V₁ + V₂ = 5

V₁ - V₂ = 19

To solve this system of equations, we can add the two equations:

(V₁ + V₂) + (V₁ - V₂) = 5 + 19

2V₁ = 24

V₁ = 12

Substitute V₁ = 12 into one of the equations to find V₂:

12 - V₂ = 19

V₂ = -7

Therefore, the preimage of w is (12, -7).

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Answer:

2, 3 , 5/6, b

Step-by-step explanation:

Usando medidas proporcionales, se encuentra que tardarán 50 días en construila.

----------------------------------

El voluma de agua es directamente proporcional a el número de días, el número de horas diárias y a el número de obreros, o sea:

\(V = kdho\)

En que k es la constant de proporcionalidad.

De esto, encuentra-se el valor de k.

\(V = kdho\)

\(80000 = k(40)(10)(15)\)

\(6000k = 80000\)

\(k = \frac{80000}{6000}\)

\(k = 13.33\)

O sea

\(V = 13.33dho\)

\(V = 13.33dho\)

\(40000 = 13.33d(6)(10)\)

\(d = \frac{40000}{60 \times 13.33}\)

\(d = 50\)

Tardarán 50 días en construila.

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Answer:

Step-by-step explanation:

so to get the answer, we just add the number of bones in your hands and bones in your skull1/4 (bones in hands) + 1/10 (bones in skull)we can only add fractions that have the same denominator (bottom number in a fraction) so we change the numbers to have a common denominator:5/20 + 2/20 = 7/20so 7/20 of your bones are in your hands or skull

Answer:

It is a rational number

Step-by-step explanation:

3/8 = 0.375

The set of rational numbers is of measure zero on the real line, so it is "small" compared to the irrationals and the continuum.

Any rational number is trivially also an algebraic number.

Answer:

4/5 I THINK

Step-by-step explanation:

you take -1/5 and divide it by -1/4

The probability of rolling a prime number is  1/6, according to the question.

Probability is computed by dividing the number of possible outcomes by the total number of possible outcomes. Probability and odds are two distinct ideas. Odds are calculated by dividing the chance of something happening by the probability of it not happening.

To get the total number of outcomes for two or more events, multiply the total number of outcomes for each event. Because it includes multiplication to find a product, this is known as the product rule for counting. Possible Outcomes – a list of all the possible outcomes of an event. For example, while rolling a dice, the possible results are 1, 2, 3, 4, 5, 6.

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Answer:

distance = 25

Step-by-step explanation:

Answer:

B) 1/44

3/22 divided by 6 = 0.022727...

0.022727 as a fraction is 1/44.

Step-by-step explanation:

Hope it helps! =D