what is the formula of magnetic force ​

Hello some data related to your question is missing attached below is the missing data

From the Table If Brown produces only Corn he will produce 50 but to produce some tobacco Brown will produce 40 Corn and 10 Tobacco to ensure the efficiency of production.

PPF ( production possibility frontier ) is a curve that shows/represent the production of various quantities of two(2) different commodities with the same limited amount of resource. In PPF the efficiency of production is not affected because the Increase in the production of a certain commodity will be balanced with a decrease in production of the other commodity. and The slope of PPF is the Marginal rate of transformation. and opportunity cost is kept constant.

Learn more : https://brainly.com/question/14482480

reduction

deflation

these are examples of the opposite of enlarged to make something smaller is really the key thing here

I'm the youngest rapper in brooklyn, yeah yeah

Answer:

what's the question

........

(a)

In order to calculate the resistance, we can use Ohm's Law:

(b)

To calculate the power, we can use the formula below:

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

For more such information on: pressure

https://brainly.com/question/28012687

#SPJ8

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

To know more about work-energy theorem here

https://brainly.com/question/30236175

#SPJ1

Answer:

D. Acrostic

Explanation:

Answer:

D.

acrostic

Explanation:

Answer:

170 m

Explanation:

force = ma

here a acceleration is unknown

but a = velocity/time = distance/(time)^2

255 = 500*d/(18.3)^2

d = 170 m

If a 100 N force accelerates an object and then a second 100 N force in the opposite direction cancels it, the object will either come to rest rapidly, continue at its initial velocity, or accelerate in the direction of the second force.The motion of the object will depend on the mass of the object and the direction of the second force.

If the mass of object is such that the net force on the object is zero after the second force is applied, then the object will continue at the same velocity it had before the second force was applied. This is because the object was already moving with a certain velocity, and the first force was accelerating it in a certain direction. When the second force is applied, it cancels out the first force, but the object still has the same velocity as before. Therefore, it will continue at that velocity.

If the mass of the object is such that the net force on the object is zero after the second force is applied, and the second force is in the direction opposite to the direction of motion, then the object will be brought to rest rapidly. This is because the first force was accelerating the object in one direction, and the second force is decelerating it in the opposite direction. Since the net force is zero, the object will come to rest.

If the second force is in the same direction as the direction of motion, then the object will be brought to rest and then accelerate in the direction of the second force. This is because the first force was accelerating the object in one direction, and the second force is accelerating it in the opposite direction. When the second force is applied, it cancels out the first force, and the net force on the object is zero. However, since the object was already moving, it will continue to move for a short distance due to its inertia before coming to rest. Then, it will accelerate in the direction of the second force.

To know more about force:

https://brainly.com/question/7362815

#SPJ4

Answer: c. 40m

Explanation:

See picture

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

For more such questions on force, click on:

https://brainly.com/question/12785175

#SPJ8

Answer:

Star 1 2 hours

35

Explanation:

Answer:

the answer would be 35 degrees :))))

Explanation:

it was the correct on the quiz,,, good luckk :3!!

Answer:

salt

Explanation:

To encourage children to eat, create a pleasant and distraction-free mealtime environment, serve a variety of visually appealing and small portions of favorite foods, involve them in meal planning and preparation, provide a relaxed and comfortable atmosphere, and avoid using food as a reward or punishment. Appropriate snack foods from each food group for school-age children can be selected from fruits, vegetables, grains, protein, and dairy. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food choices, and avoiding using food as a reward or punishment.

1. To create an atmosphere that encourages children to eat, several features can be used, such as:

A pleasant and inviting mealtime environment that is free of distractions such as television, mobile phones, or tablets.

Serve a variety of colorful, visually appealing foods in small portions, making sure to include favorite foods of the child.

Involve children in meal planning and preparation, giving them the opportunity to select foods and participate in simple meal preparation tasks.

Provide a relaxed and comfortable atmosphere by allowing enough time for meals and offering positive reinforcement for good eating behaviors.

Avoid using food as a reward or punishment and ensure that mealtimes are stress-free and enjoyable for children.

2. MyPlate is a visual representation of the five food groups that form a healthy and balanced diet. Appropriate snack foods from each food group for school-age children could include:

Fruits: apple slices, berries, bananas, or orange wedges.

Vegetables: carrot sticks, cherry tomatoes, cucumber slices, or celery sticks.

Grains: whole-grain crackers, granola bars, rice cakes, or air-popped popcorn.

Protein: hard-boiled eggs, cheese sticks, nut butter, or hummus.

Dairy: yogurt, milk, or cheese cubes.

3. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by:

Modeling healthy eating behaviors and food choices themselves.

Encouraging children to try new foods and flavors, involving them in grocery shopping, and meal planning.

Making meals enjoyable and fun by creating a positive mealtime environment and involving children in meal preparation tasks.

Providing healthy food choices and limiting the availability of unhealthy options at home and school.

Offering regular mealtimes and avoiding using food as a reward or punishment.

Hence, Encourage children to eat by providing a pleasant and distraction-free mealtime environment, serving a variety of visually appealing and small portions of favorite foods, involving them in meal planning and preparation, providing a relaxed and comfortable environment, and avoiding using food as a reward or punishment. Fruits, vegetables, grains, protein, and dairy are examples of appropriate snack foods from each food group for school-age children. Adults can assist children in learning to enjoy nutritious food and develop healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food options, and avoiding using food as a reward or punishment.

To learn more about the benefits of soy click:

https://brainly.com/question/13283520

#SPJ1

It is measured in the airless tube because  there is no air to offer resistance to the fall of the object.

The acceleration due to gravity refers to the acceleration that is imparted to a body because of its movement in the earth's gravitational field. Irrespective of mass, all objects move with the same acceleration in the earth gravitational field.

If air is present, air resistance makes it appear as if different masses are accelerated to different amounts. Thus, the acceleration due to gravity is measured in an airless tube the where there is no air to offer resistance to the fall of the object.

Learn more about acceleration due to gravity:https://brainly.com/question/13860566

#SPJ1

The  acceleration, tension of the cord between the 3.5 and 1 block, and the force excreted on the 2 block from the 1 block is 12.6 N.

To solve this problem, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

We can start by finding the acceleration of the system. Since the surface is frictionless, there are no horizontal forces acting on the blocks except for the tension in the string. Thus, we can write:

F - T = (m1 + m2 + m3) * a

where F is the force acting on the 3.5 kg block, T is the tension in the string between the 3.5 kg and 1 kg blocks, and a is the acceleration of the system. Substituting the values given in the problem, we get:

46 N - T = (1 kg + 2 kg + 3.5 kg) * a

46 N - T = 6.5 kg * a

Next, we need to find the tension in the string between the 3.5 kg and 1 kg blocks. This tension is the same throughout the string, so we can use the same equation we used to find the acceleration:

T - m1 * g = m1 * a

where g is the acceleration due to gravity (9.8 m/s^2). Substituting the values given in the problem, we get:

T - 1 kg * 9.8 m/s^2 = 1 kg * a

T = 1 kg * (a + 9.8 m/s^2)

Now, we can substitute this expression for T into the first equation we derived to get:

46 N - 1 kg * (a + 9.8 m/s^2) = 6.5 kg * a

Simplifying and solving for a, we get:

a = 2.84 m/s^2

Now that we know the acceleration of the system, we can find the force exerted by the 1 kg block on the 2 kg block. Since there are no horizontal forces acting on the 2 kg block, this force is equal in magnitude and opposite in direction to the force exerted by the 2 kg block on the 1 kg block. Thus, we can write:

F1-2 = -m2 * a

where F1-2 is the force exerted by the 1 kg block on the 2 kg block. Substituting the values given in the problem, we get:

F1-2 = -2 kg * 2.84 m/s^2

F1-2 = -5.68 N

Therefore, the force exerted by the 1 kg block on the 2 kg block is 5.68 N, directed to the left.

Finally, we can use the equation we derived earlier for the tension in the string to find the tension between the 3.5 kg and 1 kg blocks. Substituting the value we found for a, we get:

T = 1 kg * (2.84 m/s^2 + 9.8 m/s^2)

T = 12.6 N

Therefore, the tension in the string between the 3.5 kg and 1 kg blocks is 12.6 N.

Learn more about acceleration here:https://brainly.com/question/18320098

#SPJ1

The stone possesses potential energy at the top of the cliff, which is converted to kinetic energy as it falls toward the ground. Using the formula for the distance traveled by a freely falling object, we can calculate that the height of the cliff is 20 meters. The ground height is equal to zero, and when the stone is halfway down, it has a kinetic energy of 100 Joules. Using the formula for the final velocity of a freely falling object, we can calculate that the stone's final velocity as it strikes the ground is 20 m/s.

(a) The form of energy possessed by the stone before it falls is potential energy. When the stone is at the top of the cliff, it has the potential to do work due to its position relative to the ground. This potential energy is converted into kinetic energy as the stone falls towards the ground.

(b) We can use the formula for the distance traveled by a freely falling object to determine the height of the cliff:

d = 1/2 * g * t^2

where d is the distance, g is the acceleration due to gravity, and t is the time taken to fall.

Substituting the given values, we get:

d = 1/2 * 10m/s^2 * (2s)^2

d = 20 meters

Therefore, the height of the cliff is 20 meters.

(c)

(i) The ground height h is equal to zero since it is the reference level.

(ii) When the stone is halfway down, it has fallen a distance of d/2 = 10 meters. At this point, all of the potential energy has been converted to kinetic energy. We can use the formula for kinetic energy to calculate the kinetic energy of the stone:

KE = 1/2 * m * v^2

where KE is the kinetic energy, m is the mass of the stone, and v is its velocity.

Substituting the given values, we get:

KE = 1/2 * 2kg * (2 * g * d/2)

KE = 100 Joules

Therefore, the kinetic energy of the stone when halfway down is 100 Joules.

(iii) To find the final velocity of the stone as it strikes the ground, we can use the formula for the final velocity of a freely falling object:

v = sqrt(2 * g * d)

where v is the final velocity, g is the acceleration due to gravity, and d is the distance fallen.

Substituting the given values, we get:

v = sqrt(2 * 10m/s^2 * 20m)

v = sqrt(400)

v = 20 m/s

Therefore, the final velocity of the stone as it strikes the ground is 20 m/s.

To learn more about  Gravitational potential energy click:

brainly.com/question/31096472

#SPJ1

Answer:

21.52

Explanation:

The sample contains 4 atoms of krypton-85 and 12 atoms of rubidium-85 is 21.52 years

Krypton-85 is a radioactive gas found in small quantities in the atmosphere. It is naturally produced when stable Krypton-84 reacts with the incoming cosmic rays. Almost 1 cm3 of Krypton-84 is present per cubic meter of atmosphere. Atmospheric Krypton-85 is mostly produced by volcanoes, earthquakes, nuclear power plants, and nuclear explosions.

Since the mid-1940s, much greater quantities of Krypton-85 than that found in nature have been manufactured as a byproduct of nuclear fission. When Uranium-235 or some other fissile nucleus goes through a fissile reaction, it gets split into two portions or fragments having 2 or 3 neutrons and mass numbers between 90 and 140. The fission yield of Krypton-85 is around 0.3%; i.e., approximately 3 atoms of Krypton-85 are generated per 1000 fissions. Most of the mass of Krypton-85 is converted directly to Rubidium-85 and does not go through the long-standing state of nuclear isomer.

Learn more about Krypton-85

https://brainly.com/question/22409989

#SPJ2

Answer:

Wave Energy and Biomass Energy sources.

Explanation:

The main sources of energy available on earth are Coal, Geothermal, Nuclear, Petroleum, Hydro,  Biomass, and Wave, from which nuclear and geothermal are resultant of radioactive materials whereas Coal and Petroleum are resultant of Fossil Fuels.

Biomass energy is produced by living organisms, for example, corn is used as biomass material, which stores energy through photosynthesis, and the photosynthesis process is only possible with Sun.

Wave energy is resultant of the sun's uneven heating of the ocean which makes tides and then the motion of the waves utilize to harness the energy.

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

For more such information on: DC generator

https://brainly.com/question/23037391

#SPJ8

Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  \(b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }\)

Generally the dispersion relation is mathematically represented as

            \(e(k) =  b_y  *  k\)

=>    \(e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k\)

=>    \(e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }\)

=>    \(e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )\)

Generally the group velocity is mathematically represented as

          \(G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} ) \)

Answer:

37.85 Liters in 10 US gallons

Explanation:

if asking for volume: volume = 3.785liters

Answer:

Δp=-18799.5kg*m/s

Explanation:

Δv=Vf-Vi

Δv=2.9m/s-18m/s

Δv=-15.1m/s

m*Δv=Δp

1245kg*(-15.1m/s)=Δp

Δp=-18799.5kg*m/s

Extra:

Deriving mΔv=Δp

Δp=Pf-Pi

Δp=m*Vf-m*Vi

Δp=m(Vf-Vi)

Vf-Vi=Δv

Δp=m(Δv) or Δp=mΔv

Answer:

a survey

Explanation:

how kids like the playground or they do not like it at all

Answer:

i can explait it with you

Explanation:

When an object exerts a force ona second objects force on a object,force on a second object,the second one exerts a force on the first that is equal in magnitude and apposite in direction