What is the formula of the compound formed when Beryllium reacts with the sulfate ion?

A. Be(S)2
B. Bes
C. Bez(SO4)2
D. BeSO4

The circuits A and C are forward biased. So, they will work to light up the LED.

Since it shares many electrical properties with a PN junction diode, the Light Emitting Diode, or LED as it is more generally known, is really just a particular kind of diode. This implies that an LED will allow electricity to flow forward but will stop it from going the other way.

Electrons from the semiconductor's conduction band recombine with holes from the valence band when the diode is forward biased, releasing enough energy to create photons that radiate monochromatic (single-color) light. Due to the thin layer, a significant amount of these photons are able to propagate from the p-n junction and produce coloured light.

In the diagram, LEDs in circuits A and C are forward biased and B and D are reverse biased. So, the circuits A and C will work to light up the LED.

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Answer:

These are the two basic forms of energy. The different types of energy include thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy and gravitational energy.

Explanation:

To determine the magnetic field at point P in the given figure, we can use the Biot-Savart Law.

The Biot-Savart Law states that the magnetic field at a point due to a current-carrying element is proportional to the current, the length of the element, and the sine of the angle between the element and the line connecting the element to the point.

In this case, we have two current-carrying arcs and two radial lines. Let's consider each part separately:

1. The circular arcs: Since the circular arcs are concentric, the magnetic fields they produce cancel each other at point P. Therefore, we don't need to consider the circular arcs in our calculation.

2. The radial lines: The radial lines are straight and perpendicular to the line connecting them to point P. The magnetic field produced by a straight current-carrying wire at a point on the wire is given by the equation:

B = (μ₀ * I) / (2π * r)

where μ₀ is the permeability of free space, I is the current, and r is the distance from the wire to the point.

For both radial lines, we can use this equation to calculate the magnetic field at point P. The contribution from each line will have a magnitude of:

B_line = (μ₀ * I) / (2π * r_line)

Since the two lines are parallel and carry the same current, their magnetic fields add up. Therefore, the total magnetic field at point P is:

B_total = 2 * B_line = 2 * (μ₀ * I) / (2π * r_line)

Finally, we can substitute the given values into the equation to calculate the magnetic field at point P.

Note: Without the specific values for the current and distances, we can't provide a numerical answer.

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The distance covered by Mary is 65.60 m

Distance is the length between two points.

To calculate the distance covered by the Mary, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the distance covered by Mary is 65.60 m

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Answer:

50 mile/hr

Explanation:

Vf = Vo + at

Vf = 20  +  10 (3)  = 50 mile/hr

Answer:

50m/s2^

Explanation:

We know , by newton's law of motion .

F=ma

a=f/m

a=25/0.5

a=50m/s2^

Therefore , the acceleration of a softball is  .

Answer:

7 m/s²

Explanation: Force = Mass x acceleration  

Also note that 1 N = 1 kg.m/s²

a=F/ m

a= 35 N/ 5 kg = 35 kg.m/ s²  ÷  kg                 Aside:( so you cross out the kg)

a= 7 m/s²

To determine the resistance in SI units that you need to set the cycle ergometer to, given that you want to have a subject exercise at 125 watts with an RPM of 60 for 3 minutes, follow the steps below:

Step 1: Determine the energy used in Joules during the 3 minutes at 125 watts.

P = W / tWhere:

P = power (125 watts)t = time (3 minutes converted to seconds

= 3 × 60 = 180 seconds)

W = energy used in Joules (to be determined)

Substituting the given values:

P = W / t125

= W / 180W

= 125 × 180W

= 22,500 Joules

Step 2: Determine the work done (in Joules) per revolution (360 degrees).

Work done per revolution = energy used in Joules / number of revolutions per minute / 60

Where:number of revolutions per minute = RPM / 60

Substituting the given values:

Work done per revolution = 22,500 / (60 / 60) / 360

Work done per revolution = 22,500 / 1 / 360

Work done per revolution = 22,500 × 360

Work done per revolution = 8,100,000 Joules

Step 3: Determine the torque needed to perform one revolution (360 degrees) of the pedals in SI units (N-m).Torque = work done per revolution / (2 × π)

Where:

2 × π = 6.2832

Substituting the given values:Torque = 8,100,000 / 6.2832

Torque = 1,288,684.08 N-m

Step 4:

Determine the resistance (force) needed at the pedals in Newtons (N) to produce the required torque.Resistance = Torque / pedal radius

Where:pedal radius = 0.175 m (average for a cycle ergometer)

Substituting the given values:

Resistance = 1,288,684.08 / 0.175

Resistance = 7,358,971.89 N (Newtons)

Therefore, you would need to set the resistance to 7,358,971.89 N (Newtons) on the cycle ergometer to achieve the desired subject exercise at 125 Watts with an RPM of 60 for 3 minutes.

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Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

Answer:

Parisian Scoop

Pocket thermometer

Pasty Bag

sifter

chinois

Rolling Pin

Immersion Blender

Chocolate tempering machine

Robot Coupe

Steam Jacketed kettle

marble table

commercial dough sheeter

Explanation:

Really it could differ dependent on model variety of each item

Answer:

b. an electric current is used to turn the pointer of a galvanometer

Explanation:

well , galvanometer is an important device which is used to detect an electric current through a conductor or circuit.

something special about it is that it can detect very minute current too

Answer:

b

Explanation:

The intensity of solar radiation reaching the Earth is 1,340 W/m 2 . If the sun has a radius of 7.000×10 8 m, is a perfect radiator and is located 1.500×10 11 a from the Earth. Therefore, The temperature of the sun is 6,430 K.

The temperature of the sun can be determined by applying the Stefan-Boltzmann law.

The formula for the Stefan-Boltzmann constant is given byσ = 5.67 × 10-8 W m-2 K-4, and the formula for solar radiation intensity is given byI = σT4.

The intensity of solar radiation reaching the Earth is 1,340 W/m2. If the sun has a radius of 7.000×108m, is a perfect radiator and is located 1.500×1011a from the Earth,

1 The formula for solar radiation intensity is given byI = σT4Where,I = solar radiation intensityσ = Stefan-Boltzmann constantT = temperature of the sun.

2 Rearrange the formula by taking the fourth root of both sides T = (I / σ)1/4.

3 Substitute the values given in the formula: I = 1340 W/m2σ = 5.67 × 10-8 W m-2 K-4.

4 Calculate the distance of the sun from the Earth.

R = 1.5 × 1011 m.

5 Calculate the area of the sun.

A = πr2A

    = π (7.0 × 108 m)2A

    = 1.539 × 1028 m2.

6 Calculate the total radiation from the sun.

P = IA.P = 1,340 W/m2 × 1.539 × 1028 m2P = 2.059 × 1031 W.

7 Substitute the value of the radiation from the sun in the formula.P = σA(T4 - Ts4)2.059 × 1031 W = 5.67 × 10-8 W m-2 K-4 × 1.539 × 1028 m2 (T4 - Ts4)

8 Rearrange the formula.T4 - Ts4 = (2.059 × 1031 W) / (5.67 × 10-8 W m-2 K-4 × 1.539 × 1028 m2)T4 - Ts4 = 2.961.5332722 × 107 K4Step 9Take the fourth root of both sides. T = [(2.961.5332722 × 107 K4)1/4] + TsT = 6,430 K.

Therefore, The temperature of the sun is 6,430 K.

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The formula xy = k or y = kx can be used to represent an inverse variation. If a nonzero constant k exists such that xy = k or y = kx where x≠ 0, y ≠ 0, then y varies inversely as x.

A variable is inversely varying with respect to another variable when the term "inverse variation" is used. It symbolizes how two quantities are inversely related. This means that one variable is inversely proportional to another. Relationship in mathematics between two variables that can be described by an equation in which the sum of the two variables equals a constant.

As one quantity rises, the other falls for two quantities with inverse variation. For instance, as your speed increases while travelling to a specific location, it will take you less time to get there.

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In a live fire exercise, an Army artillery team fires an artillery shell from a howitzer. The barrel of the howitzer makes a 54.0∘ angle above horizontal, and the speed of the shell upon exiting the barrel is 360 m/s. The shell hits a target on the 5 ide of a mountain 32.5 s after firing, the coordinates of the target are approximately (x, y) = (7006.2 m, -7393.175 m).

To find the x and y coordinates of the target, we can use the equations of motion in the x and y directions. Let's break down the given information:

Angle of the barrel above horizontal: θ = 54.0°

Exit speed of the shell: v = 360 m/s

Time of flight: t = 32.5 s

First, let's find the x-coordinate of the target. We can use the equation:

x = v × cos(θ) × t

Plugging in the values:

x = 360 m/s × cos(54.0°) × 32.5 s

x ≈ 360 m/s × 0.5878 ×32.5 s

x ≈ 7006.2 m

So, the x-coordinate of the target is approximately 7006.2 meters.

Next, let's find the y-coordinate of the target. We can use the equation:

y = v × sin(θ) × t - (1/2) ×g × t^2

where g is the acceleration due to gravity. Assuming g to be approximately 9.8 m/s²:

y = 360 m/s × sin(54.0°) × 32.5 s - (1/2) × 9.8 m/s² × (32.5 s)^2

y ≈ 360 m/s× 0.8090 × 32.5 s - (1/2) × 9.8 m/s² × (32.5 s)^2

y ≈ 9391.2 m - 16784.375 m

y ≈ -7393.175 m

So, the y-coordinate of the target is approximately -7393.175 meters.

Therefore, the coordinates of the target are approximately (x, y) = (7006.2 m, -7393.175 m).

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Answer:

if g=-10m/s² then the normal force is 20N

if g=-9.8m/s² then the normal force is 19.6N

Explanation:

The force due to gravity (or weight) is mass times the acceleration due to gravity.

I am going to define up as positive so gravity will be negative.

On earth the acceleration due to gravity is -9.8m/s²

We sometimes round this to -10m/s² to make the math easier.

I will do it both ways.

so we have a mass of 2kg

2kg(-10m/s²)

so the force due to gravity is -20N

because the block is not falling through the table, the table must be pushing back with the same amount of force, but in the opposite direction so we change the sign.

using -10m/s² for g, we get a normal force of 20N (Newtons)

if we use -9.8m/s², we have 2kg(-9.8m/s²)

and a force due to gravity of -19.6N

and when we flip the sign we get a normal force of 19.6N

Hope this helps!

When the cold front or wind passes weather station, the pressure increases whereas the temperature increases.

Pressure rises and temperature falls as a cold front passes a New York weather station because wind apply pressure on the objects when they blow. If the wind is cold then the temperature decreases.

So we can conclude that when the cold front or wind passes weather station, the pressure increases whereas the temperature increases.

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Answer:

The velocity of the droplet right before it hits the ground is 40.08 m/s.

Explanation:

To determine the velocity of the droplet right before it hits the ground,

From one of the equations of kinematic for free fall motions,

v = u + gt

Where v is the final velocity

u is the initial velocity

g is acceleration due to gravity (take g = 9.8 m/s²)

and t is time

For the question, v is the velocity of the droplet right before it hits the ground.

u = 0 m/s (Since the molten lead was dropped from rest)

Therefore,

v = gt

First, we will determine the time t

Also, from one of the equations of kinematic for free fall motions,

h = ut + 1/2(gt²)

u = 0 m/s

From the question, the molten lead was dropped from the top of the 82.15 m tall tower, therefore

h = 82.15

Hence,

82.15 = 0×t + 1/2 (9.8 × t²)

82.15 = 1/2 (9.8 × t²)

82.15 = 4.9 t²

t² = 82.15/4.9

∴ t = 4.09 secs

Now, for the velocity v, of the droplet right before it hits the ground,

Recall

v = gt

Then,

v = 9.8 × 4.09

v = 40.08 m/s

Hence, the velocity of the droplet right before it hits the ground is 40.08 m/s.

If an m×n matrix A has a pivot position in every row, then the equation Ax = b has a unique solution for each b in ℝᵐ.

Let's consider an m×n matrix A, where each row contains a pivot position. This implies that each row of the matrix has a leading entry, which is the leftmost nonzero entry in that row.

To determine the solution for the equation Ax = b, we can use the concept of row operations. By performing row operations on matrix A, we can transform it into an equivalent row-echelon form or reduced row-echelon form.

If matrix A is in row-echelon form or reduced row-echelon form and has a pivot position in every row, it means that each row corresponds to a linear equation with a unique leading variable. This guarantees that the system of equations represented by the matrix has a unique solution.

In other words, the presence of a pivot position in every row ensures that each variable in the system of equations has a unique coefficient. Consequently, for any vector b in ℝᵐ, there exists a unique solution x that satisfies the equation Ax = b.

Hence, if an m×n matrix A has a pivot position in every row, the equation Ax = b has a unique solution for each b in ℝᵐ.

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Planetesimals' orbits were disturbed by orbital resonance with Jupiter, which prevented them from accreting into planets.

Orbital resonance happens when the gravitational forces of celestial bodies that are periodically orbiting one another interact, and this interaction is sometimes expressed as a ratio of tiny integers.

Jupiter has the ability to influence the asteroid belt since it is so large and is located very close to the asteroid belt compared to other planets. Asteroids are literally pushed out of the orbital resonances with Jupiter at the locations where they exist, leaving empty space in their wake.

Since Daniel Kirkwood, an American astronomer, was able to foresee and characterise such occurrences in the middle of the 1800s, the region has been virtually free of asteroids. Kirkwood gaps were later used to describe this paucity of asteroids in the region of Jupiter's orbital resonances.

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Answer:

3 m/s^2

Explanation:

acceleration = vf-vi/t = (30 m/s-0 m/s)/10 s = 3 m/s^2

Answer:

The mass is one of the factors affecting gravitational field strength.

Weight (Force) = mass × gravitational field strength

= 0.10 × 10 (10 is the fixed gravitational field strength on Earth)

= 1.0 N

Answer:

18.0 cm/s2

Explanation:

Answer:

\(V=2.4\times 10^2\ \text{m}^3\)

Explanation:

Given that,

The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high.

We need to find the volume of the room.

The room in the shape of cuboid whose volume is given by :

\(V=L\times B\times H\)

L,B,H are length, breadth and height of the room

So,

\(V=16.4\times 4.5\times 3.26\\\\V=240.588\ \text{m}^3\\\\\text{In scientific notation}\\\\V=2.4\times 10^2\ \text{m}^3\)

Hence, the volume of the room is \(2.4\times 10^2\ \text{m}^3\)

Answer:

14.715

Explanation:

weight = mass x gravity

14.715 = 1.5 x 9.81

N is the total number of full load cycles, and S is the stress change. The area to the left and below the line represents cyclic stress and cycle count combinations for which no fatigue failure is anticipated to happen.

The distribution of forces, often known as stresses, under cyclic stress changes repeatedly throughout time. Imagine one of the huge wheels that propels an aerial lift, like a ski lift, as an illustration.

The plot of every one of these numbers is known as the cyclic stress-strain curve. Following plastic deformation, the material behaves as described by the curve. Typically, this activity differs from the initial action that is assessed in a conventional tensile test.

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Answer:

TRUE

Explanation:

When a wire with a current is placed in a magnetic field, electrical energy is transformed into mechanical energy. The transformation happens when the magnetic field produced by the current causes the wire to move.

Answer:

i put cereal first

Explanation:

cereal

The Landsat satellite takes approximately 99 minutes to orbit the Earth once.

The Landsat series of satellites are in a polar orbit around the Earth, which means they travel from pole to pole as they orbit the planet. To calculate the orbital period of the Landsat satellite, we need to consider the altitude at which it orbits.

The Landsat satellites typically orbit at an altitude of around 705 kilometers (438 miles) above the Earth's surface. We can use Kepler's third law of planetary motion to calculate the orbital period:

T = 2π√(a³/GM)

Where:

T is the orbital period,

π is a mathematical constant (approximately 3.14159),

a is the semi-major axis of the orbit (distance from the center of the Earth to the satellite's orbit),

G is the gravitational constant, and

M is the mass of the Earth.

The average semi-major axis of the Landsat satellite's orbit can be calculated by adding the Earth's radius (6,371 kilometers) to the orbital altitude:

a = 6,371 km + 705 km = 7,076 km = 7,076,000 meters

The mass of the Earth (M) is approximately 5.972 × 10^24 kilograms, and the gravitational constant (G) is approximately 6.67430 × 10^-11 m³/kg/s².

Plugging in the values into the formula, we have:

T = 2π√((7,076,000)³/(6.67430 × 10^-11 × 5.972 × 10^24))

Simplifying the expression and calculating, we find:

T ≈ 5642 seconds

Converting seconds to minutes:

T ≈ 5642 seconds × (1 minute / 60 seconds) ≈ 94.04 minutes

Rounding to the nearest whole number, the orbital period of the Landsat satellite is approximately 94 minutes.

The Landsat satellite takes approximately 99 minutes (rounded to the nearest whole number) to complete one orbit around the Earth.

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