what is the formula to find the volume of 5ft radius and 8ft height​

Answer:

number of years = 2002 - 1998 = 4

100 - 15= 85%

85/100=0.85

850000 X 0.85^4= 443705.3125

$443705.31

Answer:

B

Step-by-step explanation:

So we have the function:

\(f(x)=\frac{9}{5}x+32\)

To find the inverse, flip f(x) and x, change f(x) to f⁻¹(x), and solve for it. Thus:

\(x=\frac{9}{5}f^{-1}(x)+32\)

Subtract 32 from both sides:

\(x-32=\frac{9}{5}f^{-1}(x)\)

Multiply both sides by 5/9. The right side will cancel. Thus:

\(f^{-1}(x)=\frac{5}{9}(x-32)\)

Our answer is B.

And we're done!

Answer:

I think A!

If not I'm srry! But i think its A! :)

Yes, a hole in a function is considered a type of discontinuity. A hole occurs when a point is missing from the graph of a function, which causes the graph to have a break in it.

A discontinuity is a break or jump in the graph of a function. A hole in a function is a type of discontinuity where a point is missing from the graph, causing the graph to have a break in it. This type of discontinuity is usually caused by a function having a denominator that is equal to zero, as this creates an undefined point on the graph. This can also occur when two parts of the function are not connected, causing an open gap in the graph. In both cases, the graph is not continuous and has a discontinuity at the point where the hole is present.

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Yes, the function has a hole in discontinuity.

The term function in math is called as a rule that gives value of a dependent variable that corresponds to specified values of one or more independent variables.

Here we to identify is a hole in a function a discontinuity.

the term discontinuity is defined as is discontinuous at a point if it becomes undefined or the limit at that point does not exist. And whether this point is known as the point of discontinuity.

While we looking the hole on a graph looks like a hollow circle. And which  represents the fact that the function approaches the point, here it is not actually defined on that precise value. Where the major reason why this function is not defined at is because is not in the domain of the function.

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Answer:

20

Step-by-step explanation:

Answer:

6.35 x 10^5

This word limit is killing me

The net change in the stock is $1800

Mario has 40 shares of stick that each lost $75 during half of the year

He also had 24 shares of a different stock that gained $50

The net change can be calculated as follows

-40 × 75

= -3000

= 24 × 50

= 1200

Net change

-3000 + 1200

= -1800

Hence the net change in the stocks is $1800

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Answer:

it is 1000x+2000

Step-by-step explanation:

Answer:

The answer is $1.4.

Answer:

2

Step-by-step explanation:

2 is the highest number than multiplies into both 46 and 38

Complement of set A is the set of all elements in the universal set that are not in the set .

If there is a subset of the universal set (U) called A, then the complement of set A, denoted by the symbol A', is different from the elements of set A and contains the elements of the universal set but not the elements of set A.

In this case, A' = x U: x A.

In other words, the complement of a set A is the difference between the universal set and set A.

For example: U = {1, 2, 3, 5, 7, 9, 15 ,14, 13}, A = {1, 2, 3, 5,7,9}, find the complement of A.

A' = U - A = {1, 2, 3, 5, 7, 9, 15,14,13} - {1, 2, 3, 5,7,9} = {15,14, 13}

A set that contains items from all related sets, without any repetition of elements, is known as a universal set (often symbolised by the letter U). If A and B are two sets, for example, A = 1, 2, 3 and B = 1, a, b, c, then U = 1, 2, 3, a, b, c is the universal set that these two sets belong to.

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Answer:

a= g=9.81 m/s square

Mass given to us = 30 kg

Therefore we have to find the acceleration of the object,

As there is no air and mass is irrelevant in free fall, the acceleration the object experiences will be equal to the force of gravity. On our planet, the gravitational pull on an item falling there is approximately:

9.81 m/s square.

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The inverse of the matrix A is:

A^(-1) = [ 0 2/15 0 ]

[ 2/15 -2/15 -2/15 ]

[ -4/15 2/15 1/15 ]

To find the inverse of the matrix A:

A = [ 1 -1 -2 ]

[ 3 -2 -8 ]

[ -2 0 15 ]

We can use the method of row operations to transform the matrix into reduced row-echelon form. We augment the matrix with the identity matrix of the same size and perform row operations until the left side of the augmented matrix becomes the identity matrix. The right side will then be the inverse of the original matrix.

[ 1 -1 -2 | 1 0 0 ]

[ 3 -2 -8 | 0 1 0 ]

[ -2 0 15 | 0 0 1 ]

Performing row operations:

R2 = R2 - 3R1

R3 = R3 + 2R1

[ 1 -1 -2 | 1 0 0 ]

[ 0 1 2 | -3 1 0 ]

[ 0 -2 11 | 2 0 1 ]

R3 = R3 + 2R2

[ 1 -1 -2 | 1 0 0 ]

[ 0 1 2 | -3 1 0 ]

[ 0 0 15 | -4 2 1 ]

R3 = (1/15)R3

[ 1 -1 -2 | 1 0 0 ]

[ 0 1 2 | -3 1 0 ]

[ 0 0 1 | -4/15 2/15 1/15 ]

R2 = R2 - 2R3

R1 = R1 + 2R3

[ 1 -1 0 | -2/15 4/15 2/15 ]

[ 0 1 0 | 2/15 -2/15 -2/15 ]

[ 0 0 1 | -4/15 2/15 1/15 ]

R1 = R1 + R2

[ 1 0 0 | 0 2/15 0 ]

[ 0 1 0 | 2/15 -2/15 -2/15 ]

[ 0 0 1 | -4/15 2/15 1/15 ]

Therefore, the inverse of the matrix A is:

A^(-1) = [ 0 2/15 0 ]

[ 2/15 -2/15 -2/15 ]

[ -4/15 2/15 1/15 ]

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Answer: 0.2

Step-by-step explanation:

The calculated value of the expression when a = 3 and b = -2 is 1

The expression is given as

(StartFraction 3 a Superscript negative 2 Baseline b Superscript 6 Baseline Over 2 a Superscript negative 1 Baseline b Superscript 5 Baseline EndFraction) squared

Mathematically, this can be expressed as

(3a^-2b^6/2a^-1b^5)^2

The values of a and b are given as

a =3 and b = -2

substitute the known values in the above equation, so, we have the following representation

(3(3)^-2(-2)^6/2(3)^-1(-2)^5)^2

Evaluate

So, we have

1

Hence, the solution is 1

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Answer:

Step-by-step explanation:

Dont do it. Just take the detention

The potential energy of the King Air 200 aircraft is approximately 420,014,400,000 Nm.

To find the potential energy of the King Air 200 aircraft, we need to use the formula:

Potential Energy = Weight * Altitude

Given that the weight of the aircraft is 12,500 lb and the altitude is 25,000 ft, we can calculate the potential energy as follows:

Potential Energy = 12,500 lb * 25,000 ft

Now, let's convert the units to a more suitable form. Since the potential energy is usually measured in joules or foot-pounds, we'll convert the units accordingly.

1 lb = 4.448 N (approximately) 1 ft = 0.3048 m (approximately)

Using these conversion factors, we can convert the units:

Potential Energy = (12,500 lb * 4.448 N/lb) * (25,000 ft * 0.3048 m/ft) Potential Energy ≈ 55,120,000 N * 7,620 m

Finally, we can calculate the potential energy:

Potential Energy ≈ 420,014,400,000 Nm

Therefore, the potential energy of the King Air 200 aircraft is approximately 420,014,400,000 Nm.

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The answer is "Failure of the reproductive structures to survive the frost". It is the most common factor limiting aspen's distribution along with the western edge of range in Canada.

Aspen trees are the one that are adapted to surviving in cold climates or cold weather but reproductive structures, like flowers and fruits are more sensitive to the frost. Cold temperatures at the western end of the shivering Canadian Cottonwood Range can cause frosts that damage and destroy that reproductive structures. This factor is most common factor that is restricting the distribution of aspens along the western edge of their range in Canada.

In addition, the harsh climate of "may" also limit the growth of popular seedlings, thus, aspen's range is limited by a lack of reproductive and growing success in the colder parts of its range.

Full Question:

What is the most common factor limiting aspen’s distribution along the northwestern edge of aspen's range?

A. Failure of fruits to ripen

B. Failure of the reproductive structures to survive the frost

C. Herbivory

D. Failure of seed germination

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The z-scores for the data values 560, 690, 500, 470, and 290 are 0.6, 1.9, 0, -0.3, and -2.1, respectively.

To calculate the z-scores for the given data values, we use the formula:

z = (x - μ) / σ

where z is the z-score, x is the data value, μ is the mean, and σ is the standard deviation.

Mean (μ) = 500

Standard deviation (σ) = 100

Let's calculate the z-scores for each data value:

For x = 560:

z = (560 - 500) / 100 = 0.6

For x = 690:

z = (690 - 500) / 100 = 1.9

For x = 500:

z = (500 - 500) / 100 = 0

For x = 470:

z = (470 - 500) / 100 = -0.3

For x = 290:

z = (290 - 500) / 100 = -2.1

Therefore, the z-scores for the given data values are:

560: 0.6

690: 1.9

500: 0

470: -0.3

290: -2.1

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Complete Question:

Consider a sample with a mean of 500 and a standard deviation of 100. what are the z-scores for the following data values: 560, 690, 500, 470, and 290?

Answer:

A parabola

Step-by-step explanation:

A parabola is created when you create a quadratic equation, and the highest/lowest value it will reach before it dips down/up again is called the vertex; not sure what exactly you meant by this question so feel free to clarify and I can help you the best I can

The curve created by a quadratic function is called a parabola.

A parabola is a U-shaped curve that is symmetric about a vertical line called the axis of symmetry. It is defined by a quadratic equation in the form of y = ax^2 + bx + c, where "a," "b," and "c" are constants. The coefficient "a" determines whether the parabola opens upwards (if "a" is positive) or downwards (if "a" is negative).

The vertex of the parabola represents its lowest or highest point, depending on the orientation. Parabolas have various applications in mathematics, physics, engineering, and other fields due to their distinctive shape and properties.

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Answer:7³=343

343 × M = 343m

Step-by-step explanation:

7×7×7=343

No, the matrix A is not orthogonal. To determine if a matrix is orthogonal, we need to check if the product of the matrix and its transpose equals the identity matrix.

However, for matrix A, if we calculate A * A^T (where A^T is the transpose of A), we do not obtain the identity matrix.

Let's calculate x' = λx, where x and λ are given quantities. We multiply the matrix λ with the matrix x, resulting in the matrix x'.

Next, we calculate x^T * x, which is the dot product of the matrix x with its transpose. This gives us a scalar value.

Finally, we calculate (x')^T * (x'), which is the dot product of the matrix x' with its transpose. This also gives us a scalar value.

By performing these calculations, we can determine the quantities x', x^T * x, and (x')^T * (x'), which proves the matrix A is not orthogonal.

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Answer:

The vertex is option C: (-6, -2)

Step-by-step explanation:

The equation for a parabola is y = a(x – h)² + k where h and k are the y and x coordinates of the vertex, respectively. Thus, the vertex is (-6,2)

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Fats that are highly unsaturated, such as polyunsaturated fats, are most susceptible to rancidity.

Rancidity refers to the deterioration of fats and oils, resulting in undesirable odors and flavors. The stability of fats, or their resistance to rancidity, is influenced by their degree of unsaturation.

1. Fats are composed of fatty acids, which can be classified as saturated, monounsaturated, or polyunsaturated based on the presence of double bonds between carbon atoms in their chemical structure.

2. Saturated fats have no double bonds and are the most stable, as the absence of double bonds makes them less susceptible to oxidation and rancidity.

3. Monounsaturated fats have one double bond, which introduces some susceptibility to rancidity but to a lesser extent than polyunsaturated fats.

4. Polyunsaturated fats have multiple double bonds, making them the most susceptible to rancidity. The presence of multiple double bonds provides more sites for oxidation, leading to increased chemical reactivity and the potential for rancid flavors and odors to develop.

5. Common examples of polyunsaturated fats include vegetable oils such as soybean oil, corn oil, and sunflower oil. These oils are often stored in dark bottles and refrigerated to slow down the oxidation process and extend their shelf life.

In summary, fats that are highly unsaturated, particularly polyunsaturated fats, are the most susceptible to rancidity due to the presence of multiple double bonds, which increase their susceptibility to oxidation and degradation.

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Answer:

1/2

Step-by-step explanation:

Since there are a total of 14 t shirts and 7 of them were green, the experimental probability that the next one is also green is 7/14=1/2. Hope this  helps!

If the population of New Hampshire is approximately 1.36×\(10^{6}\) people and the population of Vermont is approximately 6.24×\(10^{5}\), then  7.36×\(10^{5}\) more people live in New Hampshire than in Vermont

The approximate population of New Hampshire = 1.36×\(10^{6}\)

The approximate population of Vermont = 6.24×\(10^{5}\)

How many more people live in New Hampshire than in Vermont = The  approximate population of New Hampshire - The approximate population of Vermont

Substitute the values in the equation

= ( 1.36×\(10^{6}\)) - (6.24×\(10^{5}\))

= 736000

= 7.36×\(10^{5}\)

Hence, if the population of New Hampshire is approximately 1.36×\(10^{6}\) people and the population of Vermont is approximately 6.24×\(10^{5}\), then  7.36×\(10^{5}\) more people live in New Hampshire than in Vermont

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x = 1 and x = -7 are the x - intercepts, the vertex is, (-3, -4), and axis of symmetry is x = -3.

What is, axis of symmetry, vertex and x - intercept?

A vertical line that splits the parabola into two equal half is the axis of symmetry. The equation x = - b/2a tells us where the line of symmetry lies. The parabola's vertex, which is a point (x, y), is where it crosses its axis of symmetry.

A line's x-intercept is the location at which the x-axis is crossed.

Consider, the given equation,

\(f(x) = \frac{1}{4}(x - 1)(x + 7)\)

Let,

\(y = \frac{1}{4}(x - 1)(x + 7)\)             ..(1)

To find x - intercept, plug y = 0 in above equation,

\(\frac{1}{4}(x - 1)(x + 7) = 0\\ (x - 1)(x + 7) = 0\\(x - 1) = 0, (x + 7) = 0\\x = 1, x = -7\)

Therefore, x = 1 and x = -7 are the x - intercepts.

Since, the x-coordinate of the vertex is at the midpoint of the x-intercepts.

So,

\(x = \frac{-7+1}{2} = \frac{-6}{2} = -3\)

Plug x = -3 in equation (1)

\(y = \frac{1}{4}(-4)(4) = -4\)

Therefore, the vertex is, (-3, -4).

The x - coordinate of the vertex is the axis of symmetry.

Therefore, axis of symmetry is x = -3.

Hence, x = 1 and x = -7 are the x - intercepts, the vertex is, (-3, -4), and axis of symmetry is x = -3.

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the turning point(s) of a polynomial function by using below steps

To find the turning point of a polynomial function, follow these steps:

1. Determine the degree of the polynomial. The turning point will occur in a polynomial of odd degree (1, 3, 5, etc.) or at most one turning point in a polynomial of even degree (2, 4, 6, etc.).

2. Write the polynomial function in the form f(x) = axⁿ + bxⁿ⁻¹ + ... + cx + d, where n represents the degree of the polynomial and a, b, c, d, etc., are coefficients.

3. Find the derivative of the polynomial function, f'(x), by differentiating each term of the function with respect to x. This will give you a new function that represents the slope of the original polynomial function at any given point.

4. Set f'(x) equal to zero and solve for x to find the x-coordinate(s) of the turning point(s). These are the values where the slope of the polynomial function is zero, indicating a potential turning point.

5. Substitute the x-coordinate(s) obtained in step 4 into the original polynomial function, f(x), to find the corresponding y-coordinate(s) of the turning point(s).

6. The turning point(s) of the polynomial function is given by the coordinates (x, y), where x is the x-coordinate(s) found in step 4 and y is the y-coordinate(s) found in step 5.

By following these steps, you can find the turning point(s) of a polynomial function.

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The blood test for determining coagulation activity defects is called the Prothrombin Time (PT) test.

The blood test for determining coagulation activity defects is called the Prothrombin Time (PT) test. This test measures the time it takes for blood to clot and is used to assess the functioning of the clotting factors in the blood. It is commonly used to evaluate the extrinsic pathway of the coagulation cascade, which involves factors outside of the blood vessels.

The PT test is an important diagnostic tool in hematology and is used to diagnose or monitor conditions that affect blood clotting, such as bleeding disorders or the effectiveness of anticoagulant medications. By measuring the PT, healthcare professionals can determine if there are any abnormalities in the coagulation process and make appropriate treatment decisions.

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