What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?

The suction pressure at the evaporator (low side) of a properly operating R-134a air conditioning or refrigeration system normally varies from 20 to 40 psi (pounds per square inch), or around 138 to 276 kPa (kilopascals).

Depending on the particular operating circumstances, such as the type of equipment, ambient temperature, and intended cooling capacity, the suction pressure of a refrigerant, such as R-134a, in a refrigeration system might change. However, it can give you an idea of the normal suction pressure range in an R-134a refrigeration system.

The suction pressure at the evaporator (low side) of a properly operating R-134a air conditioning or refrigeration system normally varies from 20 to 40 psi (pounds per square inch), or around 138 to 276 kPa (kilopascals). The proper refrigerant flow and effective cooling operation are ensured by this pressure range.

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The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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Answer:

To find the resonance frequency of a series RLC circuit, we can use the formula:

f = 1 / (2π√(LC))

Where:

f = Resonance frequency

L = Inductance in henries

C = Capacitance in farads

π = 3.14159...

In this case, we are given the resistance and inductive impedance of the coil, but not its inductance. However, we know that the inductive impedance of a coil is given by:

XL = 2πfL

Where:

XL = Inductive impedance

f = Frequency

L = Inductance in henries

π = 3.14159...

At resonance, the inductive impedance of the coil will equal the capacitive reactance of the capacitor:

XL = XC

Where:

XC = Capacitive reactance

XC = 1 / (2πfC)

Substituting XL and XC into the equation above, we get:

2πfL = 1 / (2πfC)

Simplifying this equation, we get:

f = 1 / (2π√(LC))

Where:

L = XL / (2πf) = 65Ω / (2πf)

C = 49µF = 49 × 10^-6F

Substituting these values into the resonance frequency equation, we get:

f = 1 / (2π√(65Ω/(2πf) × 49 × 10^-6F))

Simplifying this equation, we get:

f = 1 / (2π√((3.385 × 10^-6)/f))

Multiplying both sides by 2π√((3.385 × 10^-6)/f), we get:

2π√((3.385 × 10^-6)/f) × f = 1

Squaring both sides, we get:

4π^2(3.385 × 10^-6)/f = 1

Solving for f, we get:

f = √((4π^2 × 3.385 × 10^-6))

f ≈ 1369 Hz.

Therefore, the resonance frequency of the circuit is approximately 1369 Hz.

Complete Question

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Answer:

The value  is \(v  = 3.57 \  m/s \)

Explanation:

From the question we are told that

  The depth  is  \(d =  979 \  m\)

   The time taken for water to fall to below the river is  \(t =  14 \ s\)

   The  horizontal distance from the base of the vertical cliff is  \(h  =  50 \  m\)

     Generally  the horizontal speed at the top is mathematically represented as

         \(v  =  \frac{h}{t}\)

=>      \(v  =  \frac{  50}{ 14 }\)

=>     \(v  = 3.57 \  m/s \)

Answer:

A. positive reinforcement

Explanation:

Assuming Adam dislikes veggies and likes ice cream...

Adam is being conditioned to eat his vegetables via positive reinforcement.

Punishment would be a negative result from eating him vegetables.

Negative reinforement is pretty much the same thing as punishment.

Extinction would mean he stopped getting what he wanted for the action he didn't like (eating veggies) and stopped doing it.

Answer:

The answer is

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

\(m = \frac{p}{v} \\ \)

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

\(m = \frac{280}{10} = 28 \\ \)

We have the final answer as

Hope this helps you

The minimum amount of time for Brandon to reach the point 300 m downstream on the opposite side is approximately 106.25 seconds.

To find the minimum amount of time it takes for Brandon to reach the point 300 m downstream on the opposite side, we need to determine the optimal swimming distance across the river and then calculate the time it takes for each segment of his journey.
Let x be the distance Brandon swims across the river. Since the river is 50 m wide, he will swim \(√(x^2 + 50^2)\)meters diagonally. After swimming, he will run the remaining distance of (300 - x) meters.
The time it takes for Brandon to swim is \((distance_swim / swim_speed)\) and the time it takes for him to run is \((distance_run / run_speed)\). We can write the total time as:
Total time = \((distance_swim / swim_speed)\) + \((distance_run / run_speed)\)
Total time =\((√(x^2 + 50^2) / 2) + ((300 - x) / 4)\)
To minimize the total time, we can differentiate this equation with respect to x and set it equal to 0:
d(Total time) / dx = 0
Using the first derivative, we find the optimal x value:
x ≈ 25 meters

Now, we can plug this value back into the total time equation:
Total time ≈ \((√(25^2 + 50^2) / 2) + ((300 - 25) / 4)\)
Total time ≈ \((75 / 2) + (275 / 4)\)
Total time ≈ \(37.5 + 68.75\)
Total time ≈ \(106.25 seconds\)
So, the minimum amount of time for Brandon to reach the point 300 m downstream on the opposite side is approximately 106.25 seconds.

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The power dissipated in the wire changes by a factor of 6.8.

When a wire of resistance r is stretched uniformly to 2.6 times its initial length, its cross-sectional area reduces.

Since the wire's volume and density remain constant, the new resistance (R') can be found using the formula R' = (2.6)²* r.

This is because resistance is directly proportional to length and inversely proportional to the cross-sectional area. So, R' = 6.76r (approximately).

Now, the power dissipated (P) in a resistor is given by P = V² / R, where V is the voltage. Since the voltage source remains the same, we can find the factor by which the power changes using the ratio of the new resistance to the original resistance:

Factor = (V² / R') / (V² / r) = r / R' = r / (6.76r) ≈ 1 / 6.8.

Thus, the power dissipated in the wire changes by a factor of 6.8.

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Answer: IT IS TRUE

Explanation:

Hope this helps

Plyometrics can help a person maintain cardiorespiratory fitness T

It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness

Plyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.

Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.

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Answer: 2.7 seconds

Explanation:

We only want to answer: How long until the box reaches a height of 13.1 m?

Then we only must integrate the movement equations.

We know that the velocity of the box increases by 3.6 m/s every second, then the acceleration is constant, and can be written as:

a(t) = 3.6m/s^2

Now, for the velocity, we should integrate over time, and because we know that the box starts from rest, the initial velocity (the constant of integration) will be zero.

v(t) = (3.6m/s^2)*t

For the position equation we should integrate again over time, and if we define the position 0 as the ground, we know that the box starts at the ground, then the initial position (the constant of integration) will be zero.

p(t) = (1/2)*(3.6m/s^2)*t^2.

Now we want to find how long will take until the height of the box is equal to 13.1m

Then we must solve:

p(t) = 13.1m =  (1/2)*(3.6m/s^2)*t^2

Let's solve this for t.

13.1m =  (1/2)*(3.6m/s^2)*t^2

13.1m*2 = (3.6m/s^2)*t^2

26.2m/(3.6m/s^2) = t^2

7.277.... s^2 = t^2

√(7.277.... s^2) = t = 2.7 seconds.

So it will take 2.7 seconds for the box to reach the height of 13.1m

The movement of crustal plates results from circulating currents in the mantle material beneath the crust of Earth. The mantle material is made up of molten rock and solid iron.

Crustal plates are large areas of the Earth's crust that float on the underlying molten mantle. The plates are in constant motion and move a few centimeters each year. Earth's crust is made up of about a dozen of these plates.

The heat causes the molten rock and solid iron to flow, producing convection currents. The movement of the mantle material drives the movement of the crustal plates, causing them to shift and collide with each other.

There are two types of crustal plates: oceanic plates and continental plates. Oceanic plates are thinner and denser than continental plates, and they are found beneath the oceans.

The movement of crustal plates has several effects on the Earth's surface. These include the formation of mountains, the creation of new land, the formation of valleys, and the creation of earthquakes and volcanic activity. When two plates collide, they can form a mountain range.

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1.1×10^8 m^2 is the required surface area of each plate. is this plate size realistic.

The formula C=Ad C = A d, where C is the value of the capacitance, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the plates of the parallel capacitor, gives the capacitance for parallel plate capacitors (dependent on its geometry).

C=εoA /d

∴A= Cd / εo

=(1)(10)^-3  /8.86×10 ^(−12)

=1.1×10^8 m^2

hence the surface area of each plate 1.1×10^8 m^2.

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When an electromagnet is placed nearby, the paper clips move towards it due to magnetic domains within the paper clips aligning with the magnetic field.

Magnetic domains are tiny regions within a material's atoms where the magnetic poles are aligned in the same direction, creating a magnetic field. As the electromagnet produces its own magnetic field, the magnetic domains within the paper clips become attracted to the electromagnet’s field, causing them to move towards it. The paper clips do not become magnetized themselves, as the magnetic field created by the electromagnet is too weak to cause permanent alignment of the magnetic domains within the paper clips.

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To find the time it took for the car to accelerate, you can use the formula:

t = (v - u) / a

where t is the time, v is the final velocity, u is the initial velocity, and a is the acceleration.

Plugging in the given values, you get:

t = (26 m/s - 19 m/s) / (205 m / t^2)

You can then rearrange the equation to solve for t:

t = sqrt(205 m / (26 m/s - 19 m/s))

Solving for t, you get:

t = sqrt(205 m / 7 m/s) = sqrt(29.3 s^2) = 5.4 s

So it took the car approximately 5.4 seconds to accelerate from 19 m/s to 26 m/s.

The answer choice that would show the motion of the object described is a straight line with a positive slope starting from (0, 2) and ending at (3, 8).

To determine the correct answer choice, we need to consider the characteristics of uniformly accelerated motion and how it would be represented on a velocity-time graph. Uniformly accelerated motion means that the object's velocity increases by a constant amount over equal time intervals. In this case, the object starts with an initial velocity of 2 m/s and accelerates uniformly to a final velocity of 8 m/s in 3 seconds.

On a velocity-time graph, velocity is represented on the y-axis (vertical axis) and time is represented on the x-axis (horizontal axis). The slope of the graph represents the acceleration, while the area under the graph represents the displacement of the object.

To illustrate the motion described, we need a graph that starts at 2 m/s, ends at 8 m/s, and shows a uniform increase in velocity over a period of 3 seconds. The correct answer choice would be a straight line with a positive slope starting from (0, 2) and ending at (3, 8).

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Answer:

Explanation: "Warming up and cooling down are good for your exercise performance — you’ll do better, faster, stronger — and for your heart since the increased work on the heart ‘steps up’ with exercise,” said Richard Stein, M.D., professor of cardiology.

Answer:

when there is uniform velocity the acceleration of a body is zero

The value of the diameter of the hydrogen atom as we have it in this experiment is accurate because it is very close to the true value.

The term accuracy refers to how close the measured value is to the true value. The true value is the same as the accepted value. In this case, the true value of the  diameter of a Hydrogen atom is 10 nm.

The fact that is observed value is obtained to be  10.1 nm implies that the value of the diameter of the hydrogen atom as we have it in this experiment is accurate because it is very close to the true value.

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As it enters Earth's atmosphere from space, sunlight scatters light. Light slants downward as its wave fronts rub against the upper atmosphere. Because of this, the Sun appears to be higher in the sky than it actually is.

This indicates that, as a result of atmospheric refraction, we continue to observe the sun approximately two minutes after sunset. Without the earth's atmosphere, such atmospheric refraction would not have been possible. Earth's atmosphere makes the day longer as a result.

The Sun is visible even when it is just below the horizon due to atmospheric refraction. Because the light rays enter the Earth's atmosphere at a particularly shallow angle, this effect is especially strong for objects that appear close to the horizon, like the rising or setting Sun.

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A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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Answer: C.

Explanation:

Just took quiz

First, let's find the acceleration and the final velocity in the first 20 seconds, using the formula below:

During the 10 seconds with constant speed, the distance he ran is:

Now, in the last 5 seconds, the distance is:

Therefore the total distance is:

Answer:

chemical energy to sound energy Explanation: BATTERY CONSISTS OF CHEMICAL ENERGY.WHEN OUR RADIO IS OPERATED BY INSERTING BATTERY INTO IT,CHEMICAL ENERGY IN BATTERY IS CONVERTED INTO SOUND ENERGY AND THUS WE HEAR SOUND FROM THE RADIO.

Explanation:

Answer:

cell membrane

Explanation:

A cell wall is most commonly known as a cell membrane witch just controls what can go in and out of a cell .

( hope this helped )

Answer:

Yes i could, even you can

Explanation:

Its just practice makes perfect

nothing is impossible

(forget the people say nothing is impossible but I do nothing everyday joke if you know it) /:

Answer:

The static "frictional force" and the "kinetic friction" will act on the box.

Answer:

Sound is produced when an object vibrates, creating a pressure wave.As the particles vibrate, they move nearby particles, transmitting the sound further through the medium. The human ear detects sound waves when vibrating air particles vibrate small parts within the ear.

Answer:

An object creates sound through vibrations! These vibrations create waves which create the sounds we hear everyday from various objects.

Explanation:

-xoxo-

MJ :P

Answer:

1)The connection should be tight.

2)The wire should be connected at the terminals not in between.

3)clean the ends of the wire by sandpaper.

4)Take the voltmeter and ammeter in proper range.

5)The rheostat should be used of low resistant(about 100).

Answer:

it can be present at birth

Answer:

I think it can happen sometimes but not all the time

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

\( E = P*t \)

Where P is the power and t is the time

For the 60 W lightbulb:

\( E_{60} = P*t = 60 W*30 s = 1800 J \)

For the 100 W lightbulb:

\( E_{100} = P*t = 100 W*30 s = 3000 J \)

Hence, the difference in the amount of energy transferred is:

\( E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J \)

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

The difference in the amount of energy transferred by the two bulbs during this time is 1200 J.

We know that

E = P*t

Here

P means the power and T means the time

So for 60W lightbulb, the energy should be

= 60*30

= 1800J

For 100 W, the energy should be

= 100*30

= 3000 J

So, the difference is

= 3000 -1800

= 1200 J

hence, The difference in the amount of energy transferred by the two bulbs during this time is 1200 J.

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