What is the mass of an airplane that is flying at 246 m/s and has a momentum of 1.968 x 107 kg-m/s? Show your work.

The slope increases or decreases downstream, are less common and do not accurately represent the typical longitudinal profile of a streambed.

The sketch that best represents the longitudinal profile of the slope of a streambed is option A. In this case, the slope is constant and steep downstream.

This means that the streambed maintains a consistent, steep gradient as it progresses in the downstream direction. This profile is commonly associated with youthful streams or those in mountainous regions, where the force of gravity allows the water to flow rapidly down steep slopes.

Option B, where the slope is constant and shallow downstream, is more characteristic of mature or old-age streams.

Options C and D, where the slope increases or decreases downstream, are less common and do not accurately represent the typical longitudinal profile of a streambed.

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Answer:

1. battery is capable of continuous current, capacitor is not

2. battery maintains a potential, capacitor does not

3. battery stores chemical energy, capacitor stores electric energy

Explanation:

1. battery is capable of continuous current, capacitor is not

This is because the battery maintains a constant current throughout while the capacitor maintains an exponential decaying current.

2. battery maintains a potential, capacitor does not

This is because, the battery has a potential at its terminal due to its emf whereas, the capacitor needs a potential to be applied to its terminals.

3. battery stores chemical energy, capacitor stores electric energy

This is because, the battery converts chemical energy to electrical energy whereas, the capacitor stores electric energy due to its ability to store electric charge.

Answer

battery stores chemical energy, capacitor stores electric energy

battery maintains a potential, capacitor does not

battery is capable of continuous current, capacitor is not

Explanation:

The radial acceleration of the ball during its circular motion is approximately 59.4 m/s^2.

Centripetal acceleration, a = v^2 / r, where v is the speed of the ball and r is the radius of the circle.

The time it takes for the ball to reach the ground,

y = 1/2 g t^2

where y is the initial height of the ball (1.00 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes for the ball to reach the ground.

t = sqrt(2y/g)

= sqrt(2 x 1.00 / 9.81)

≈ 0.45 s

Velocity, v = x/t

= 1.90 / 0.45

≈ 4.22 m/s

The radial acceleration of the ball during its circular motion can now be found using the equation,

a = v^2 / r

a = v^2 / r = (4.22)^2 / 0.300 ≈ 59.4 m/s^2

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The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).

To find the work done in lifting the bucket and rope, we need to consider two parts:

Part 1: Work done lifting the bucket (without the rope) 24 ft:

The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.

Given:

Weight of the bucket = 7 lb

Distance lifted = 24 ft

Work done lifting the bucket = Weight of the bucket x Distance lifted

Work done lifting the bucket = 7 lb x 24 ft

Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).

Part 2: Work done lifting the rope:

Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.

Given:

Weight of the rope = 0.8 lb

Distance lifted = 24 ft

Work done lifting the rope = Weight of the rope x Distance lifted

Work done lifting the rope = 0.8 lb x 24 ft

Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:

Total work done = Work done lifting the bucket + Work done lifting the rope

Please note that the units of work are in foot-pounds (ft-lb).

Now, we can calculate the values:

Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb

Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb

Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb

Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).

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The complete question is:

Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.

Answer: A mixture

Explanation:

A mixture is where 2 or more substances are physically combined, and where you can know what each substance is

Answer: Mixture

Mixture is made up of two or more different substances, which are mixed but not combined chemically.

Explanation:

Hope this helps =)

Answer:

Gravity.

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

This ultimately implies that, this force is a pull between all objects. It is the force that gives us weight here on Earth. And, if we throw a rock off of a cliff, it is the force that causes the rock to fall to Earth.

The water can be raised to a height of approximately 15.7 m above the water surface at point A.

To solve this problem, we need to use the principles of fluid mechanics, specifically the Bernoulli's equation and the continuity equation.

A1v1 = A2v2

We know that the diameter of the 8.0 in. pipe is 8 in. = 0.6667 ft, so its cross-sectional area is:

A1 = \(π/4 x (0.6667 ft)^2 = 0.349 ft^2\)

Similarly,

A2 = \(π/4 x (0.3333 ft)^2 = 0.0873 ft^2\)

v1 = (A2v2)/A1 = \((0.0873 ft^2 x 12 ft/s)/0.349 ft^2\) = 2.39 ft/s

Next, we can use the Bernoulli's equation between points A and C to relate the pressure difference to the velocity difference:

P/ρ +\(v^2/2g\) + h = constant

h = (P/ρ - Patm)/g + z

We are given that the pump delivers 25 hp with 60% efficiency, so the power input to the pump is:

Pin = 25 hp/0.6 = 41.7 hp = 31.1 kW

Pin = QP/η

The volumetric flow rate can be calculated from the continuity equation:

Q = A1v1 = \(0.349 ft^2 x 2.39 ft/s = 0.834 ft^3/s\)

Substituting this into the above equation, we get:

P = Pinη/Q = \((31.1 kW x 0.6)/0.834 ft^3/s\) = 1773 Pa

Finally, we can substitute the known values into the Bernoulli's equation:

h = \((P/ρ - Patm)/g + z = (1773 Pa/1000 kg/m^3 - 101325 Pa)/9.81 m/s^2 + 0 m\)

h ≈ 15.7 m

Therefore, the water can be raised to a height of approximately 15.7 m above the water surface at point A.

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Answer: Ionisation is the process of an atom gets a negative or a positive charge by gaining or losing electrons. The result is an ion.

Explanation: Thats why

Answer: The cost of using the microwave oven for 30 minutes every day for 9 days is $0.57

Explanation: The GRASS method is used to calculate the cost of using an appliance by multiplying the power rating of the appliance (in kW) by the hours of use, and then multiplying that by the rate per kWh.

Here's the calculation:

Power rating: 0.62 kW

Time of use: 30 minutes/day for 9 days = 30/60*9 = 13.5 hours

Cost per hour = 0.62 * 6.8 / 100 = 0.04236

Total cost = 0.04236 * 13.5 = $0.57

Answer:

Explanation:

The resistance of a material is expressed as R = ρL/A

Volume of the original material V = Area * Length = A*L

ρ is the resistivity of the material

R is the resistance

A is the cross sectional area

L is the length of the wire.

If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.

This means V = V₂

A*L = = A₂*L₂

A*L = A₂*(2 L)

A = 2 A₂

A₂ = A/2

The new resistance of the material Rf = ρL₂/A₂

R₂ = ρ(2 L)/(A/2)

Rf =  2ρL * 2/A

Rf = 4(ρL/A)

Since R = ρL/A

R₂ = 4R

Hence, the resistance of the stretched wire will be four times that of the original wire.

If the wire is stretched to twice its original length, the new resistance would be quadrupled.

The resistance (R) of a wire is given by:

\(R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity\)

Since the wire is stretched, the new length (L₁) is twice its original length, hence:

L₁ = 2L

An increase in length affects the area, the new area (A₁) is:

initial volume = volume after stretch

AL = A₁L₁

AL = A₁(2L)

A₁ = A/2

The resistance of the stretched wire (R₁) is:

\(R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R\)

Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.

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Answer:

22 mins and 30 seconds

Explanation:

2m in 1 min so:

45m in x mins Cross multiply

2x = 45

x = 45/2

x=22.5

Answer:B

Explanation:

The force of gravitation depends on the mass of the object. As the mass increases, the speed of the falling object also increases because it experience more gravitational pull from earth. Thus, option D is correct.

Gravitational force is a kind of force by which an object attracts other objects into its center of mass. We are all standing on the ground because of the gravitational pull of earth.

Gravitational force is directly proportional to the mass of the objects and inversely proportional to the distance from the surface. Therefore, the force exerted by earth on massive body is greater than that on a light body.

Here, the ball with greater  mass hit the ground with less time compared to the one with less mass. Hence, the mass becomes a factor  affecting the speed of a falling object when the object is dropped a great distance from the surface of the earth. Thus, the massive body will be pulled more by earth.

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Answer:

9.45 kWh

Explanation:

Energy = Power × time

E = 900 W × (1.5 h/day × 7 day)

E = 9450 Wh

E = 9.45 kWh

Answer:

The kinetic energy of bocce ball is more.

Explanation:

Given that,

Mass of a bowling ball, m₁ = 4 kg

Speed of the bowling ball, v₁ = 1 m/s

Mass of bocce ball, m₂ = 1 kg

Speed of bocce ball, v₂ = 4 m/s

We need to say which has more kinetic energy.

The kinetic energy of an object is given by :

\(E=\dfrac{1}{2}mv^2\)

Kinetic energy of the bowling ball,

\(E_1=\dfrac{1}{2}m_1v_1^2\\\\E_1=\dfrac{1}{2}\times 4\times (1)^2\\\\E_1=2\ J\)

The kinetic energy of the bocce ball,

\(E_2=\dfrac{1}{2}m_2v_2^2\\\\E_2=\dfrac{1}{2}\times 1\times (4)^2\\\\E_2=8\ J\)

So, the kinetic energy of bocce ball is more than that of bowling ball.

Answer:

Thermal Energy. Thermal energy is the internal energy of an object due to the kinetic energy of its atoms and/or molecules. The atoms and/or molecules of a hotter object have greater kinetic energy than those of a colder one, in the form of vibrational, rotational, or, in the case of a gas, translational motion.

Explanation:

The shape that your arm describes is a cone and the shape of your finger sweeping out on the wall is a circle

When you point to a wall with your arm extended at a 42-degree angle to the normal of the wall and rotate your arm in a full circle while maintaining the same angle, the shape that your arm describes is a cone. The cone is formed by the movement of your arm around an axis perpendicular to the wall, with the vertex of the cone at your shoulder and the base at your fingertip.

As your arm rotates, your fingertip sweeps out a circle on the wall. This circle is parallel to the base of the cone and is formed by the intersection of the cone with the wall. The radius of the circle is equal to the distance from your shoulder to your fingertip, and the center of the circle is located at the point where your arm intersects the wall.

The cone that your arm describes is a three-dimensional shape that is formed by rotating a line segment around an axis. In this case, the line segment is your arm, and the axis is perpendicular to the wall. The cone is a familiar shape that appears in many contexts, including the geometry of circles, the construction of paper cups and traffic cones, and the design of loudspeakers. In conclusion, the shape that your arm describes is a cone and the shape of your finger sweeping out on the wall is a circle.

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Gravity The principal factor governing the planets' orbits around the sun is gravity. While each planet has its own gravity that is determined by its size and speed of motion, orbit is determined by the gravity of the sun.

If you were to stand on the surface of any planet in the solar system, or, in the case of the ice giants, float in its atmosphere, you would feel the following gravitational pull: Venus: 0.9 g Mercury: 0.38 g Moon: 0.17 g Mars: 0.38 g Saturn: 1.07 g Jupiter: 2.53 g 0.89 g Uranus Jupiter: 1.14 g The Planets' Gravitational Pull The two driving forces that propel the planets around the sun.

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(a) For the first 50 m:

h1 = 0.5 x a x t12

50 m = 0.5 x 9.8 m/s2 x t12

t1 = 3.19 s

Time to fall first 50 m = 3.19 s

(b) For the full 100 m:

h2 = 0.5 x a x t22

100 m = 0.5 x 9.8 m/s2 x t22

t2 = 4.52 s

Time to fall second 50 m = t2 - t1 = 1.33 s

Dropped rocks and other objects gain speed rapidly as they fall. Velocity defines the direction in which a body or object is moving. Velocity is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance.

If our planet loses gravity for even 5 seconds it means the end of life on Earth as we know it. Gravity pulls objects together. The greater the mass of an object, the stronger its gravitational pull. Any submarine you choose for skydiving should be designed with movement in mind. If the weather is cool on the day of skydiving, you should choose pants that cover the entire leg. We recommend wearing sweatpants or sweatpants.

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The kinetic energy is  8 × 10⁻¹⁵ J , the velocity equals 1.3 × 10⁸  m/s, and the wavelength is 0.248A°, according to the provided statement.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent emblems) in the consecutive cycles. This length is typically specified in wireless systems in metres (m), centimeters (cm), or millimeters (mm) (mm)

The wavelength in the SI system is measured in meters, commonly abbreviated as m. The multiples or decimals of a metre are also used to measure wavelength. Notably, when wavelengths are a significant feature, hyperbolic factors of 10 are used.

Kinetic energy = charge × potential difference

Here , charge on electron = 1.6 × 10⁻¹⁸C

Potential difference = 50,000 volts

So, Kinetic energy = 1.6 × 10⁻¹⁹C × 50,000 volts = 8 × 10⁻¹⁵ J

We know,

Kinetic energy = 1/2mv²

8 × 10⁻¹⁵ = 1/2 × 9.1 × 10⁻³¹ × v² [ ∵ m is the mass of electron , e.g., 9.1 × 10⁻³¹ Kg]

v² = 16/9.1× 10¹⁶

v ≈ 1.3 × 10⁸ m/s

As a result, the target is struck by the striking electron with a speed of  1.3 × 10⁸ m/s

Now, wavelength = λ

hc/λ = kinetic energy

1/λ = 8 × 10⁻¹⁵/6.626 × 10⁻³⁴ × 3 × 10⁸

λ = 6.626 × 3 × 10⁻²⁶/8 × 10⁻¹⁵ = 0.248 × 10⁻¹⁰ m

hence, wavelength is 0.248A°

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Answer:

Ptolemy proposed a model, he reference system is centered on the Earth

Copernicus, proposed a deferent system,  this system is centered on the Sun, where it is at the origin of the system

Explanation:

Thousands of years ago, Ptolemy proposed a model to explain the movement of the planets and stars in the sky, in this model the reference system is centered on the Earth, so each body is orbiting in different spheres around the Earth as its center, this system had very complicated calculations and curves to be able to explain the orbits of the planets.

More recently Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system, in this system the movement of the planets are ellipses, which is a much simpler explanation and has been widely accepted, in current systems the reference system is fixed in the bodies more massive, since this simplifies the explanation of the movements.

Answer:

When a branch of a tree is shaken, some of the fruits may fall down. Why? Solution : The fruits fall down due to inertia of rest.

Answer:

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The angular displacement traveled in the first 6 seconds if the final angular speed is 20rad/s and with an angular acceleration of 5 rad /s² would be 90 radians.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

By using the second equation of motion given by Newton,

S = ut + 1/2at²

S = 0 + 0.5 × 5 × 6²

S = 90 radian

Thus, the total angular displacement would be 90 radians.

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Explanation:

Newton second law of motion

Given

The bending ability of a substance is recorded on the index of refraction.

To find

If the statement is true or false

Explanation

While a light is refracted to a denser medium then the light bents towards the normal and if it is refracted to a rarer medium, the light bends away from the normal

Thus the bending ability depends on the refractive index of the medium

Conclusion

The given statement is True

Answer:

Net force/.612=acceleraton

Explanation:

Need more information for a specific answer. I derived this general equation using newton's second law: F=MA. The acceleration of the object is calculated by dividing the net force on the object by its mass.

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

\(C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF\)

Capacitance of capacitor 2,

\(C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF\)

Capacitance of capacitor 3,

\(C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF\)

(b) The equivalent capacitance in series combination is :

\(\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF\)

Hence, this is the required solution.

After canceling out the common units, we can observe that the friction factor (f) is dimensionless, meaning it has no units.

The formula that has been provided for head loss through a straight pipe is commonly known as the Darcy-Weisbach equation, which relates the head loss to the flow rate and properties of the pipe. The friction factor f is a measure of the resistance to flow through the pipe and is determined by the roughness of the pipe wall and the Reynolds number of the flow. A detailed explanation of how to calculate the friction factor is beyond the scope of this answer, but it involves solving the Colebrook-White equation, which is an empirical relation derived from experimental data. The friction factor is an important parameter in many fluid mechanics problems, as it affects the pressure drop and energy losses in the system.

The unit of the friction factor (f) in the equation for head loss (h) through a straight pipe can be determined from the

equation h = (4 * f * l * u²) / (2 * g * d). In this equation, h is the head loss (m), l is the pipe length (m), u is the average flow velocity (m/s), g is the gravitational acceleration (m/s²), and d is the pipe diameter (m).

To find the unit of friction factor (f), we need to rearrange the equation to solve for f. This can be done by multiplying both sides by (2 * g * d) and then dividing by (4 * l * u²):

f = (h * 2 * g * d) / (4 * l * u²)

Now, we can substitute the units of each variable into the equation:

f = [(m) * (m/s²) * (m)] / [(m) * (m/s)²]

Thus, after canceling out the common units, we find that the friction factor (f) is dimensionless, meaning it has no units.

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Answer: the atmospheric pressure is generally expressed in terms of the height of the mercury column.at normal temperature and pressure, the barometric height is 760mm at sea level which is taken as one atmosphere. thus atmospheric pressure is also expressed in a unit atmosphere where 1 atm= 0.76m of hg. 9