What is the mass of an object with a density of 0.3456 g/cm3and a volume of 112.4 cm3?

Answer:

D

Explanation:

Answer:

2 iron atoms in Fe2O3

Answer:

FALSE

Explanation:

they were much more diverse

Answer:

O Scientific theories are the results of many experiments and observations.

Explanation:

Going through the options;

O Scientific theories change over time.

This is true and supports the student's opinion. So wrong option!

O Scientists often do not agree about specific details of scientific theories.

This is true. However, it supports the student's opinion. So wrong option!

O Scientists often propose competing theories.

This is true. However, it supports the student's opinion. So wrong option!

O Scientific theories do not become Scientific Laws.

This is False. Theories that have withstood the test of time and countless experiments become laws. However it support's the student's opinion. So wrong option!

O Scientific theories are the results of many experiments and observations.

This is true and is against the student's opinion. This option is correct!

Answer:

Option D, Index fossil helps scientists to determine the relative ages of rocks by their positions

Explanation:

Index fossils are arranged in layer in such a way that the lowest layer represent the oldest fossil and the top most layer represents the youngest fossil. Scientist use this concept to determine the relative age of the rocks based on their position beneath the earth’s surface

Hence, option D is correct

if the mass of the sample is 272 grams, the number of moles of anhydrate present would be:

moles = 2

Generally, To determine the number of moles of anhydrate present, you would need to know the mass of the sample. If you have that information, you can use the formula:

moles = mass / molar mass

Where

mass is the mass of the sample in grams and

molar mass is the molar mass of the salt (in this case, 136 g/mol).

For example, if the mass of the sample is 272 grams, the number of moles of anhydrate present would be:

moles = 272 / 136

= 2

Please provide me with more information so that I could give you more accurate answer.

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3 g/mL is the density in grams per millititer to three significant figures.

To express the density of a cube of butter in grams per milliliter, we need to convert the weight from pounds to grams and the volume from cubic inches to milliliters.

1 pound is approximately equal to 453.592 grams, so the weight of the cube of butter in grams would be:
0.260 lb * 453.592 g/lb = 117.81992 g (rounded to three significant figures as 118 g)

1 cubic inch is equal to approximately 16.387 milliliters, so the volume of the cube of butter in milliliters would be:
\(1303 cubic inches * 16.387 mL/in^3 = 21,365.861 mL\) (rounded to three significant figures as 21,400 mL)

Therefore, the density of the cube of butter would be:
Density = Mass / Volume

= 118 g / 21,400 mL

= 0.00551 g/mL (rounded to three significant figures as 0.005 g/mL)

For the gem, we already have the mass as 600 g and the volume as 200 mL.

Therefore, the density of the gem would be:
Density = Mass / Volume

= 600 g / 200 mL

= 3 g/mL (rounded to three significant figures)

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Answer:

true this is correct its your econimically

The hydroxide ion concentration [OH-] in the Great Salt Lake with a pH of 8.25 is approximately 0.000 00180 M, which corresponds to option C.

To calculate the [OH-] in a sample of the Great Salt Lake, we can use the equation: pH + pOH = 14. pOH is the negative logarithm of the hydroxide ion concentration [OH-].
First, we need to find the pOH value:
pH + pOH = 14
8.25 + pOH = 14
pOH = 14 - 8.25
pOH = 5.75
Now that we have the pOH value, we can calculate the [OH-]:
pOH = -log[OH-]
5.75 = -log[OH-]
[OH-] = 10^-5.75
[OH-] = 1.78 x 10^-6 M
Therefore, the [OH-] in a sample of the Great Salt Lake if the pH is 8.25 is C. 0.000 00180 M.

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To separate p-toluic acid, p-tert butylphenol, and acetanilide, you can follow the steps outlined in the flowchart below:

Dissolve the mixture in a suitable solvent (such as dichloromethane or ethyl acetate).

Add dilute hydrochloric acid (HCl) to the mixture.

Shake the mixture well and allow it to separate into two layers.

Separate the organic layer (bottom layer) from the aqueous layer (top layer).

Transfer the organic layer to a clean container.

Perform a simple distillation to separate the solvent from the organic compounds. Collect the distillate.

Test the distillate to confirm the absence of any residual solvent.

Add sodium hydroxide (NaOH) solution to the remaining aqueous layer obtained in step 5.

Adjust the pH of the solution to basic using additional NaOH if necessary.

The p-toluic acid will convert to its sodium salt and remain in the aqueous layer.

Extract the aqueous layer with a non-polar solvent (such as diethyl ether or ethyl acetate) to remove any remaining organic compounds.

Separate the organic layer from the aqueous layer and transfer it to a clean container.

Add hydrochloric acid (HCl) to the organic layer obtained in step 13 to convert the p-toluic acid sodium salt back to p-toluic acid.

Separate the organic layer from the aqueous layer and transfer it to a clean container.

Perform a simple distillation to separate the p-toluic acid from the other organic compounds. Collect the distillate.

Test the distillate to confirm the presence of p-toluic acid.

The remaining mixture in the organic layer obtained in step 13 contains p-tert butylphenol and acetanilide.

Add sodium hydroxide (NaOH) solution to the organic layer to convert acetanilide to its sodium salt.

Extract the organic layer with a non-polar solvent to remove p-tert butylphenol from the mixture.

Separate the organic layer and transfer it to a clean container.

Add hydrochloric acid (HCl) to the organic layer to convert the acetanilide sodium salt back to acetanilide.

Separate the organic layer from the aqueous layer and transfer it to a clean container.

Perform a simple distillation to separate p-tert butylphenol from acetanilide. Collect the distillate.

Test the distillate to confirm the presence of p-tert butylphenol.

It is important to consider the specific properties of the compounds and adjust the steps accordingly.

Additionally, safety precautions should be followed while handling chemicals, and it is recommended to perform the separation process in a well-ventilated area or under a fume hood.

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Answer:

Yes It Is A Rock

Explanation:

It Is Not A True Mineral

Answer:

Ca + AgNO3 ---> Ca(NO3)2 + Ag

Calcium + silver nitrate ---> Calcium nitrate + silver

also ...reaction type is Single displacement reaction .

hope this answer's your question.

Answer: Most are solid at room temperature (25 degrees Celsius) except mercury

Explanation:

Answer:

The volume of the liquid remaining in the beaker is 0.24615 l

Explanation:

The initial volume of liquid in the beaker = 0.250 l

The volume of liquid the student pours out of the beaker = 0.00385 l

The volume of liquid remaining in the beaker, V, is given as follows;

V = The initial volume of liquid in the beaker - The volume of liquid the student pours out of the beaker

Therefore, we have;

V = 0.250 l - 0.00385 l = 0.24615 l

The volume of the liquid remaining in the beaker is 0.24615 l.

Answer: the answer is A or Tributaries, River system and rivers

Explanation: Its A i had the same question last year for my 10th grade assignment

Answer:

Real, pure gold, when exposed to the flame, will get brighter after a while as it gets hotter, but will not darken. Fake gold pieces, such as fool's gold (actually pyrite, an iron sulfide) and pieces made of brass, iron or copper alloys will darken or otherwise change color when exposed to fire.

Explanation:

Your welcome :)

The answer to your question the equation of the line BC is C \(-7x - 5y = -48\)

Since AB and BC form a right angle at point B, it means that AB is perpendicular to BC.

To find the equation of BC, we first need to find the gradient of BC.

Let m be the gradient of AB and m' be the gradient of BC, since AB is perpendicular to BC, mm' = -1. Thus m' = -1/m

So, we need to find the gradient of AB and thus find the gradient of BC.

To find the gradient of AB, we use the equation for the gradient of a line in slope-point form. Having point A = (x₁, y₁) = (-3, -1) and point B = (x₂, y₂) = (4, 4).

\(m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}\)

Substituting the values of the variables into the equation, we have

\(m = \frac{4 - (-1) }{4 - (-3)}\)

\(m = \frac{4 + 1 }{4 + 3}\)

\(m = \frac{5}{7}\)

Since m' = -1/m

m' = -1 ÷ 5/7

m' = -7/5

Since we know the gradient of the line BC and the line BC passes through the point B = (4, 4) = (x₂, y₂) we find the equation of the line BC using the equation of a line in slope-point form.

\(m' = \frac{y - y_{2} }{x - x_{2}}\)

\(-\frac{7}{5} = \frac{y - 4 }{x - 4}\)

cross-multiplying, we have

\(-7(x - 4) = 5(y - 4)\)

Expanding the brackets, we have

\(-7x + 28 = 5y - 20\)

Subtracting 28 from both sides, we have

\(-7x = 5y - 48\)

Subtracting 5y from both sides, we have

\(-7x - 5y = -48\)

So, the equation of the line BC is \(-7x - 5y = -48\)

The answer to your question the equation of the line BC is C \(-7x - 5y = -48\)

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Answer:

its C

Explanation:

Koh reacts with 1-propanol because it is a strong base and 1-propanol contains a good leaving group.

The base, Koh, reacts with the nucleophilic OH group of 1-propanol. This reaction is called an SN2 reaction and involves the substitution of a proton in 1-propanol with the base, Koh. The result is an alcohol, which has a negatively charged oxygen atom and a positively charged hydrogen atom. This is because the leaving group, the OH group, leaves the 1-propanol molecule, which makes the oxygen atom take the hydrogen's place and become negatively charged. Thus, the reaction of Koh and 1-propanol results in the formation of an alcohol.

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Answer:

Explanation:

4,5 diethyl-2 fluoro-3-methylheptanal

Answer:

Copper = Cu

Gold = Ag

Iron = Fe

Potassium = K

Answer: It is possible that the seller's claims about the bone being a genuine dinosaur bone and being 400 million years old are true. However, without additional evidence or verification from independent scientists, it is also possible that the bone is not authentic or that the carbon dating results have been manipulated or misinterpreted. It is important to be skeptical and to conduct further research before making a decision about the authenticity of the bone. Additionally, it is important to consider the source of the bone and the seller's reputation and credentials. It would be wise to seek out additional opinions from experts in the field before making a decision about the authenticity of the bone.

46) The major product of the reaction mechanism between Cl2+ and H2O is HOCl, which is formed through the reaction Cl2+H2O -> HOCl + H+ + Cl-
47) The major product of the reaction mechanism between Br2 and CH2Cl2 is the addition product of Br2 and CH2Cl2, which is formed through the reaction Br2+CH2Cl2 -> BrCH2Cl + HBr
48) The reaction mechanism not needed for the question, therefore no answer can be given.
49) The product of the following reaction between O3 and (CH3)2S is dimethyl sulfide oxide, which is formed through the reaction O3 + (CH3)2S -> (CH3)2SO + O2.
As a text-based AI, I am unable to physically draw the structures of the products for these reactions. However, I can provide you with a brief description of the major products and their formation.
46) In the presence of Cl2 and H2O, an alkene will undergo halohydrin formation. The major product will be a halohydrin, with the Cl atom attached to the less substituted carbon and an OH group attached to the more substituted carbon of the alkene.
47) When an alkene reacts with Br2 and CH2Cl2, it undergoes a halogenation reaction. The major product will be a vicinal dibromide, with Br atoms added across the double bond of the alkene.
48) When CH3CO3H (peracetic acid) is used as a reagent, it typically results in an epoxidation reaction for an alkene. The major product will be an epoxide, with an oxygen atom inserted into the double bond.
49) When an alkene reacts with O3 followed by (CH3)2S (dimethyl sulfide), it undergoes an ozonolysis reaction. The major product will be two carbonyl compounds formed from the cleavage of the double bond in the alkene.

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98.684 ml of 95% ethanol solution and 26.316 ml of water are required to prepare 125 ml of 75% ethanol solution.

What is a solution?

A solution is a uniform mixture of two or more components with particles smaller than one nanometer.

There are many different types of solutions, such as soda water, salt-and-sugar solutions, and others. In a solution, each component appears as a separate phase. The distribution of the particles is uniform, or there is particle homogeneity. This explains why the full contents of a soft drink bottle have the same flavour.

Let x ml of the 95% ethanol solution be the volume.

According to the law of conservation of mass, the amount of ethanol in x millilitres of 95% ethanol solution is equivalent to the amount in 125 millilitres of 75% ethanol solution.

⟹M1 V1 =M 2 V 2

In this instance: M 1 = 0.95, V 1 = x ml, M 2 = 0.75, V 2 = 125 ml, and V 1 = 98.684 ml.

But [V 2] = 125 ml for the ultimate volume.

Therefore, 98.684 ml of 95% ethanol solution and 26.316 ml of water are required to prepare 125 ml of 75% ethanol solution.

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Launching a projectile over a significant distance, such as several hundred miles, presents a range of complex challenges that must be carefully addressed. The success of achieving such a long range relies on accounting for various factors that influence the projectile's trajectory, including aerodynamics, atmospheric conditions, Earth's curvature, and external forces.

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Answer:

Mercury(II) oxide, also called mercuric oxide or simply mercury oxide, has a formula of HgO. It has a red or orange color. Mercury(II) oxide is a solid at room temperature and pressure.

Answer:

Mercury(II) oxide, also called mercuric oxide

Explanation:

simply mercury oxide has a formula of HgO. It has a red or orange color. Mercury(II) oxide is a solid at room temperature and pressure.

D-, L-, and D-allo-threonine isomers of threonine have no nutritional or other advantages. More often than natural proteins, Thr is utilised to synthesise Thr.

Chiral centres are those to which four distinct atom groups are bound. Carbon a cannot be a chiral carbon since it has three hydrogen atoms connected to it. Since it is doubly linked to oxygen, it is not the carboxyl carbon either. Furthermore, because it is bound to three rather than four separate groups of atoms, the amino nitrogen is ineligible in any case.

Due to the two chiral centres in threonine, there are four potential stereoisomers. Other than being rare in nature, the isomers of threonine (D-, L-, and D-allo-threonine) have no nutritional or other benefit. Nowadays, synthetic Thr is used more frequently than natural proteins to make Thr.

The chiral centres of amino acids can be one or many. Except for glycine, the a-carbon is chiral in all amino acids. There are extra chiral centres in some amino acids. Because there are four distinct groups connected to the carbon atom, these are chiral centres.

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The order of the increasing pH of the solution is Hydrochloric acid, Acetic acid, Ammonia, and Sodium hydroxide.  

Molecular formula of compounds:  Ethane: C2H6, 1-Butyne: C4H6, Propene: C3H6 and Cyclooctane: C8H16

Rank of solutions in order of increasing pH:

Hydrochloric acid (HCl) is a strong acid that dissociates completely in water. Its pH is very low (less than 1) and it is strongly acidic. It is an acidic solution.  It's a 1.0 M solution of hydrochloric acid.

Ammonia (NH3) is a weak base that does not completely dissociate in water. It is a weak base with a pH greater than 7 but less than 10. It is a basic solution.  It's a 1.0 M solution of ammonia.

Acetic acid (CH3COOH) is a weak acid that does not completely dissociate in water. It has a pH of around 3.5-4.0, making it a weakly acidic solution. It is an acidic solution.  It's a 1.0 M solution of acetic acid.

Sodium hydroxide (NaOH) is a strong base that dissociates completely in water. It has a very high pH (greater than 14), making it a strongly basic solution. It is a basic solution.  It's a 1.0 M solution of sodium hydroxide.

So, from the above explanation, the order of the increasing pH of the solution is

Hydrochloric acid, Acetic acid, Ammonia, and Sodium hydroxide.  

Step 2: Molecular formula of compounds:

Ethane: C2H6, contains 2 carbon atoms

1-Butyne: C4H6, contains 4 carbon atoms

Propene: C3H6, contains 3 carbon atoms

Cyclooctane: C8H16, contains 8 carbon atoms

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To calculate the molar mass of the unknown substance, we need to use the formula:

Molar mass = (mass of solute) / (number of moles of solute)

First, let's calculate the number of moles of solute in the solution:

Number of moles = (concentration) x (volume in liters)

We know that the concentration of the solution is 0.45 M, and the volume of the solution is 425 mL, which is equivalent to 0.425 L. Substituting these values into the formula, we get:

Number of moles = 0.45 M x 0.425 L

Number of moles = 0.19125 moles

Next, we can calculate the mass of the solute (the unknown substance) by using the formula:

mass = number of moles x molar mass

Rearranging the formula, we get:

molar mass = mass / number of moles

We know that the mass of the solute is 12 grams, and we have already calculated the number of moles as 0.19125 moles. Substituting these values into the formula, we get:

molar mass = 12 g / 0.19125 moles

molar mass = 62.8 g/mol

Therefore, the molar mass of the unknown substance is 62.8 g/mol.