What is the mass of oxygen contained in 72g of pure water?(*hint:Find % composition of oxygen in water)

Answers

Answer 1

Answer:

64 grams of oxygen

Explanation:

Water has a molar mass of 18.0 grams/mole.  Oxygen, at 16 g/mole, accounts for 16/18 or 88.89% of the total.

72 grams of water would this contain (72g)*(0.88.89) = 64 grams of oxygen.


Related Questions

How many grams of liquid water are produced when 60 grams of ice melt?

Answers

Answer: 60 Grams of water are produced, because you can't get more than the amount that was in the original ice cube

Explanation:

Anything that has mass and takes up space

Answers

Answer:

true

Explanation:

Answer:

is matter

Explanation:

If you start with 52 kg of a radioactive isotope, calculate how much of the original isotope is left after one half-life has elapsed.
A. How many kg of the isotope remains?
B. What fraction of the isotope remains?

Answers

26 kg of the isotope remains after one half-life has elapsed and the fraction of the isotope remains is 1/2.

An isotope is a type of atom that has a different number of neutrons in the nucleus, thus resulting in a different atomic mass but the same atomic number. For instance, carbon-14 is an isotope of carbon with 6 protons and 8 neutrons, while carbon-12 is the most common isotope of carbon with 6 protons and 6 neutrons.

The quantity of isotope remaining can be calculated by knowing the half-life of the isotope, which is the time it takes for half of a sample to decay. The half-life of an isotope is a fixed value that is exclusive to that isotope. This means that the quantity of isotope remaining can be calculated after a certain period of time.

A. N(t) = N0/2N(t)

= 52/2N(t)

= 26 kg

Therefore, 26 kg of the isotope remains after one half-life has elapsed.

The fraction of the isotope remaining is the ratio of the quantity remaining to the initial quantity:

N(t)/N0 = 26/52N(t)/N0

= 1/2

Therefore, half of the isotope remains after one half-life has elapsed.

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The characteristic which distinguishes a true solid from other phases of matter at STP is that in a true solid the particles are 1 vibrating and changing their relative positions by vibrating without changing their relative positions 2 3 motionless but changing their relative positions 4 motionless without changing their relative positions.​

Answers

Answer:

Background

Solids – relatively rigid, definite volume and shape. In a solid, the atoms and molecules are attached to each other. ...

Liquids – definite volume but able to change shape by flowing. In a liquid, the atoms and molecules are loosely bonded. ...

Gases – no definite volume or shape

_is a change in direction or speed

-velocity
-force
-deceleration
-mass
-acceleration​

Answers

i think acceleration
Velocity specifies speed, while speed includes a specific direction. Velocity specifies a change in speed over time, while speed specifies a change in distance over time. Velocity specifies a change in distance over time, while speed specifies a change in velocity over time

The sun consists of _____________ % of the mass in our solar system.

Answers

Answer:

 

Explanation:

Why do hotspots appear to move in relation to tectonic plates?

Answers

Answer:

The heat that fuels the hot spot comes from very deep in the planet. This heat causes the mantle in that region to melt. The molten magma rises up and breaks through the crust to form a volcano. While the hot spot stays in one place, rooted to its deep source of heat, the tectonic plate is slowly moving above it.

Explanation:

A balloon of helium gas is initially at a pressure of p = 1 atm, volume = 1, temperature T = 300k. 1) how many atoms of helium are in the gas? 2) how many moles 3) what is the total kinetic energy? 4) is T = 400k, what is the new volume? 5)if v = .2, what is the new pressures?

Answers

The answers are: 1) 2.445 × 10²³ 2) 0.0406 mol 3) 3.1445 J 4) 1.6827 L 5) 150

1) how many atoms of helium are in the gas?

The ideal gas law is given by the formula PV = nRT.

Where,

P = pressure,

V = volume,

n = number of moles,

R = universal gas constant,

T = temperature.

A mole is defined as the amount of substance that contains as many entities (atoms, molecules, or other particles) as there are in 12 grams of carbon-12, which is Avogadro's number of atoms (6.022 × 1023) of carbon-12.

1 mol of helium will have 6.022 x 1023 atoms of helium.

Volume of helium = 1

Therefore,

n = PV/RT

  = 1 * 1 / (0.08206 * 300)

  = 0.0406 moln (moles)

  = 0.0406 mol

Atoms of Helium = n * NA (NA is Avogadro's constant)

Atoms of Helium = 0.0406 * 6.022 * 10²³

                            = 2.445 * 10²³ atoms of helium.

2) how many moles

n = PV/RT

  = 1 * 1 / (0.08206 * 300)

  = 0.0406 mol

3) what is the total kinetic energy?

Kinetic energy is given by the formula 3/2nRT

Where,

n is the number of moles,

R is the universal gas constant,

T is the temperature

Kinetic energy = 3/2 * 0.0406 * 0.08206 * 300

                        = 3.1445 J

4) is T = 400k, what is the new volume?

Use the ideal gas law formula,

PV=nRT,

to find V= nRT/P = (0.0406 * 0.08206 * 400) / 1= 1.6827 L5)

if v = .2,

what is the new pressures?

Use the ideal gas law formula to find new pressure,

P = nRT/V = (0.0406 * 0.08206 * 400) / 0.2

  = 150 atm.

Thus, the new pressure is 150.

The answers are:1) 2.445 × 10²³2) 0.0406 mol3) 3.1445 J4) 1.6827 L5) 150

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A risk assessment for a reaction should include the hazards associated with the: a. chemical reagents used. b. chemical products and by-products. c. procedures involved. d. All of the above.

Answers

A risk assessment for a reaction should include the hazards associated with the chemical reagents used, the chemical products and by-products formed, and the procedures involved. Therefore, the correct answer is d. All of the above.

A comprehensive risk assessment considers all potential hazards associated with a chemical reaction. This includes evaluating the hazards of the chemical reagents used, the chemical products and by-products formed during the reaction, and the procedures involved in conducting the reaction.

The chemical reagents used in a reaction may have inherent hazards such as toxicity, flammability, or reactivity. It is important to assess and understand these hazards to ensure proper handling and safety measures are in place.

The chemical products and by-products formed during the reaction can also pose hazards. They may have different chemical properties or be more toxic, corrosive, or reactive than the starting materials. Understanding and evaluating these hazards is crucial for the safe handling, storage, and disposal of the reaction products.

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Why is it incorrect to refer to a molecule of sodium chloride? a. Because sodium and chloride are not bonded together in any way. b. Because ionic compounds do not exist in discrete molecules--they exist in crystal lattices. c. Because molecules are not a meaningful term in chemistry. d. Because sodium chloride is not a compound found in nature.

Answers

Answer:

B. Because ionic compounds do not exist in discrete molecules -- they exist in crystal lattices.

Explanation:

A property of ionic compounds is that they form crystal lattice structures. Ionic compounds are crystals of many cations and anions bonded together. There is no molecule of ionic compounds because there is no single unit of the compound.

Hope this helps.

write the basic equilibrium equation for po4 3- besure to include the proper phases for all species within the reaction

Answers

The balanced equation for the dissociation of PO43- is given by;PO43-(aq)  H2O(l) ⇌ HPO42-(aq)  OH-(aq)The phosphate ion, PO43-, reacts with water to form HPO42- (monohydrogen phosphate) and OH- ions.

The chemical equilibrium between these species is represented by the equation above. In the dissociation reaction of PO43- the phosphate ion reacts with water (H2O) to form monohydrogen phosphate ion (HPO42-) and hydroxide ion (OH-). The reaction can be described as;PO43-(aq)  H2O(l) ⇌ HPO42-(aq)  OH-(aq)where the reactants are on the left and products on the right. In the equation, the state of matter of each reactant or product is written in parenthesis after its chemical formula. In this reaction, the reactant PO43- is an aqueous solution, while H2O is a liquid.

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2. Express 165,000 in exponential notation.
A) 1.65000 x 105
B) 1.65 x 10$
C) 1.6500 x 105
D) 1.65 x 105
E) 165 x 10

Answers

Answer:D

Explanation:

Move the decimal back 5 times.

What mass, in grams, of H₂ can be produced from 35.0 g Na?
2 Na + 2 H₂O → 2 NaOH + H₂
6.15 g H₂
3.08 g H₂
1.54 g H₂
4.39 g H₂

Answers

The balanced chemical equation shows that 2 moles of Na produce 1 mole of H₂. First, we need to calculate the number of moles of Na in 35.0 g Na:

molar mass of Na = 23.0 g/mol
moles of Na = mass/molar mass = 35.0 g / 23.0 g/mol = 1.52 mol

From the balanced equation, 2 moles of Na produces 1 mole of H₂. Therefore, 1.52 moles of Na produces:

1.52 mol Na × (1 mol H₂/2 mol Na) = 0.76 mol H₂

Finally, we can calculate the mass of H₂ produced using its molar mass:

molar mass of H₂ = 2.02 g/mol
mass of H₂ = moles of H₂ × molar mass of H₂ = 0.76 mol × 2.02 g/mol ≈ 1.54 g

Therefore, the mass of H₂ that can be produced from 35.0 g of Na is approximately 1.54 g. Answer: 1.54 g H₂

why is it hotter in the summer and colder in the winter?

Answers

Answer: During the summer, the sun's rays hit the Earth at a steep angle. ... Also, the long daylight hours allow the Earth plenty of time to reach warm temperatures. During the winter, the sun's rays hit the Earth at a shallow angle. These rays are more spread out, which minimizes the amount of energy that hits any given spot.

During the summer, the sun’s rays hit the Earth at a steep angle. The light does not spread out as much, thus increasing the amount of energy hitting any given spot. Also, the long daylight hours allow the Earth plenty of time to reach warm temperatures
During the winter, the sun’s rays hit the Earth at a shallow angle. These rays are more spread out, which minimizes the amount of energy that hits any given spot. Also, the long nights and short days prevent the Earth from warming up. Thus, we have winter

a 525.6 ml sample of carbon dioxide was heated to 351 k. if the volume of the carbon dioxide sample at 351 k is 774.9 ml, what was its temperature at 525.6 ml?

Answers

The temperature at 525.6ml is 236.52k

what is Charles law?

Assuming that the gas's pressure remains constant, the volume of a given mass of gas is precisely proportional to its absolute temperature. According to Charles' Law, a given amount of gas expands to a larger volume at constant pressure by a factor of 1/273 for every degree the temperature rises.

The formula for the relationship between volume and temperature is

V1 / T1 = V2 / T2, where V1 and T1 represent the starting volume and the absolute temperature, and V2 and T2 represent the end volume and the absolute temperature (the Kelvin temperature, not the Celsius temperature).

V1/T1 = V2/T2

V1= 525.6ml

T1= unknown

V2= 779ml

T2=351k

T1 =V1*(T2/V2)

    = 525.6ml * (351/779)

    =525.6*0.450

    =236.52k

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Determine the empirical formula of the compound with the percent composition of 26.6% K, 35.3% Cr and 33.0% O. *
3 points

Answers

Answer:

KCrO₃

Explanation:

26.6% K, 35.3% Cr and 33.0% O

The steps in obtaining the empirical formulae from percentage composition is given as;

Step 1:

Divide the percentage composition by the atomic mass of the elements

K = 26.6 / 39.0983  = 0.6803

Cr = 35.3 / 51.9961 = 0.6789

O = 33.0 / 16  = 2.0625

Step 2:

Divide all though by the smallest number (0.6789)

K = 0.6803 / 0.6789 = 1.002

Cr = 0.6789 / 0.6789 = 1

O = 2.0625 / 0.6789 = 3.038

The Empirical formular is the ratio between the elements. This given as;

KCrO₃

Calculate the wavelength of light emitted when an electron in the hydrogen atom makes a transition from an orbital with n=5 to an orbital with n=2 .

Answers

The wavelength of light emitted when an electron in the hydrogen atom makes a transition from an orbital with n=5 to an orbital with n=2 is 3.04 x 10^-6 m. This corresponds to a spectral line in the infrared region of the electromagnetic spectrum.

To calculate the wavelength of light emitted when an electron in the hydrogen atom makes a transition from an orbital with n=5 to an orbital with n=2, we can use the Rydberg formula.

The Rydberg formula relates the wavelengths of the spectral lines emitted by hydrogen atoms to the energy levels of the electrons in those atoms. It is given by:

1/λ = R(1/n1^2 - 1/n2^2)

where λ is the wavelength of the emitted light, R is the Rydberg constant (1.0974 x 10^7 m^-1), and n1 and n2 are the initial and final energy levels of the electron, respectively.

In this case, n1 = 5 and n2 = 2. Plugging these values into the formula, we get:

1/λ = 1.0974 x 10^7 (1/5^2 - 1/2^2)
1/λ = 1.0974 x 10^7 (0.03)
1/λ = 329220
λ = 3.04 x 10^-6 m

Therefore, the wavelength of light emitted when an electron in the hydrogen atom makes a transition from an orbital with n=5 to an orbital with n=2 is 3.04 x 10^-6 m. This corresponds to a spectral line in the infrared region of the electromagnetic spectrum.

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the anaerobic conversion of 1 mol of glucose to 2 mol of lactate in the muscle is accompanied by a net gain of:

Answers

The anaerobic conversion of 1 mol of glucose to 2 mol of lactate by maturation is joined by a net increase of: 1 mol of ATP.

Anaerobic processing is an interaction through which bacteria separate natural matter —, for example, creature compost, wastewater biosolids, and food squanders — without oxygen.In the Cori cycle, glucose is metabolized to pyruvate and afterward to lactate in muscle, the lactate is delivered into the blood and conveyed to the liver, where it is reconverted to pyruvate and utilized for gluconeogenesis, and the subsequent glucose is delivered and ventures out back to muscle.Two pyruvates are switched over completely to two lactic corrosive particles, which ionize to shape lactate. In this cycle two NADH + H+ are switched over completely to two NAD+. Our muscle cells can go through this cycle when they are in oxygen debt.Two pyruvates are switched over completely to two lactic corrosive particles, which ionize to frame lactate. In this cycle two NADH + H+ are changed completely to two NAD+. Our muscle cells can go through this cycle when they are in oxygen obligation.

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which state(s) of mater have no definite shape or volume ​

Answers

Answer:

Liquids & Gases

Explanation:

Liquids: Have no definite shape as the particles are able to move around freely and take upon the shape of the container they are placed into. They do have a definite volume as the particles are still quite close together.

Gas: Have neither a definite shape nor volume as the particles are not at all close together and can move around wherever they wish.

Answer:

solid state of matter usually have shape and volume which is a major physical characteristic of solids, liquid state of matter do not have shape but have volume however, the tend to occupy the shape of the container with respect to their volume in the container. Gaseous state of matter do not shape or volume but just occupy space in the container.

Explanation:

50 POINTS! PLS HELP!
(In the column for the other reactants and/or products indicate whether they increase, decrease, or stay the same.)

Chemical Reaction:

A (g) + B (g) ←→ 3C (g)

Blue ← → Clear, Colorless
WHAT ARE THE:
Stress , Equilibrium Shift (right or left) , A (g) , B (g) , C (g) , What color?

1. Add A
2. Add B
3. Add C
4. Remove A
5. Remove C

Nonsense answers will be reported :)))

Answers

Answer:

please where is the Gibb free energy to indicate if its exothermic or endothermic reaction but the chemical equation is homogeneous one.

Among neutral (uncharged) organic compounds: _________________ forms one covalent bond and no unshared pairs of electrons.

Answers

Among neutral organic compounds, the group of compounds known as alkanes typically form one covalent bond and have no unshared pairs of electrons.

Alkanes are characterized by having a general formula of CnH2n+2, where n is the number of carbon atoms in the molecule.

The carbon atoms in alkanes are each bonded to four other atoms, typically hydrogen atoms, resulting in a tetrahedral geometry and no unshared pairs of electrons.

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Which two changes would make this reaction reactant-favored?
2H₂+02 2H₂O + energy
A. Reducing the pressure
B. Increasing the pressure
C. Reducing the temperature
D. Increasing the temperature

Answers

C. Reducing the temperature, is the two changes would make this reaction reactant-favored 2H₂+O₂ 2H₂O + energy

To make the given reaction reactant-favored, we need to shift the equilibrium towards the left side, favoring the formation of reactants (H₂ and O₂) rather than products (H₂O). This can be achieved by considering the impact of pressure and temperature on the reaction.

A. Reducing the pressure:

Reducing the pressure would not favor the reactants. According to Le Chatelier's principle, decreasing the pressure will shift the equilibrium towards the side with a higher number of moles of gas. In this case, both sides of the reaction have the same number of moles of gas (two moles), so reducing the pressure will not have a significant effect.

B. Increasing the pressure:

Increasing the pressure would not favor the reactants either. Again, according to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. As both sides have the same number of moles of gas, changing the pressure will not impact the equilibrium.

C. Reducing the temperature:

Reducing the temperature would favor the reactants. The reaction is exothermic (releases energy), and according to Le Chatelier's principle, decreasing the temperature favors the reaction that produces heat. Therefore, reducing the temperature would shift the equilibrium towards the reactants (H₂ and O₂) side.

D. Increasing the temperature:

Increasing the temperature would not favor the reactants. In an exothermic reaction, increasing the temperature would shift the equilibrium towards the products (H₂O) side to absorb the additional heat.

In conclusion, reducing the temperature (option C) would make the reaction reactant-favored, favoring the formation of H₂ and O₂ rather than H₂O. Therefore, Option C is correct.

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When measuring the temperature drop across the evaporator in a central air conditioning system, a properly running unit on a humid summer day should read between?

Answers

On a humid summer day, a properly operating central air conditioning system should register between 15-250 F.

By using a dry-bulb thermometer, all these temperatures within and outside the coil of the evaporator should be monitored. The construction of many walk-in refrigerators is centred upon an evaporator TD of around 10 °F. The case's rh will be kept at around 85% due to the temperature differential, which would prevent the air from losing much of its humidity. This is perfect for storing food items for a long time. The more moisture is extracted from the atmosphere and the lesser the case's sustained rh, the higher the temperature differential and vice versa.

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How many moles of sulfur are in a 707 gram sample of sulfur?
a) 12.2 moles of sulfur
Ob) 52.1 moles of sulfur
c) 51.1 moles of sulfur
od) 22.1 moles of sulfur

Answers

Answer:

d) 22.1 moles of sulfur

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

707 g S (Sulfur)

Step 2: Identify Conversions

Molar Mass of S - 32.07 g/mol

Step 3: Convert

Set up:                   \(\displaystyle 707 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})\)Divide:                   \(\displaystyle 22.0455 \ mol \ S\)

Step 4: Round

Our closest answer is d) 22.1 moles of sulfur

This is due to dividing different rounded values.

Answer:

\(\boxed {\boxed {\sf D. \ 22.1 \ moles \ of \ sulfur}}\)

Explanation:

To convert from moles to grams, we must use the molar mass. This can be found on the Periodic Table.

We are given a sample of sulfur. Look for the symbol S on the table.

Sulfur (S): 32.07 g/mol

This tells us the mass of 1 mole of sulfur. Use this molar mass as a ratio.

\(\frac{32.07 \ g \ S}{1 \ mol \ S }\)

Multiply by the given number of grams (707).

\(707 \ g \ S *\frac{32.07 \ g \ S}{1 \ mol \ S }\)

Flip the fraction so the grams of sulfur will cancel out.

\(707 \ g \ S *\frac{ 1 \ mol \ S }{32.07 \ g \ S}\)

\(707 *\frac{ 1 \ mol \ S }{32.07 }\)

\(\frac{ 707 \ mol \ S }{32.07 }\)

\(22.0455254 \ mol \ S\)

The number we caluclated is the closest to answer choice D: 22.1 moles of sulfur

A ground test utilizing an auxiliary current electrode and an auxiliary potential electrode is known as the______.

Answers

Answer:

The three-point test

Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

What is the sum of the coefficients needed to balance the combustion reaction of methane?

Answers

Answer:  The sum of the coefficients needed to balance the combustion reaction of methane is 6.

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The chemical equation for combustion of methane will be :

\(CH_4+2O_2\rightarrow CO_2+2H_2O\)

The coefficient foer methane is 1 , 2 for oxygen , 1 for carbon dioxide and 2 for water. The sum is 6.

which of the following reaction is also be termed as thermal decomposition reaction​

Answers

Answer:

copper carbonate reaction is known as the termed of thermal decomposition

reaction

a solution of sodium bicarbonate is prepared by adding 45.00 g of sodium bicarbonate to a 1.00-l volumetric flask and adding distilled water until it reaches the 1.00-l mark. what is the concentration of sodium bicarbonate in units of (a) milligrams per liter, (b) molarity, (c) normality, and (d) milligrams per liter as caco3?

Answers

Concentration refers to the amount of substance present.

What is concentration?

The term concentration refers to the amount of substance present. There are many units that could be used for concentration of a solution. This makes reference easy.

To express the concentration in milligram per liter;

45/1000/1 L = 0.045 mg/L

To express the concentration in molarity;

Number of moles = mass/molar mass = 45.00 g /106 g/mol = 0.42 moles

Molarity = 0.42 moles/1 L = 0.42 M

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Which is the formula mass of Na2S04?

Answers

Answer:

The formula mass of Na2S04 is 142.04 g/mol

Answer:

142.04 g/mol

Explanation:

the formula Na2SO4 means:two moles sodium (45.98g), one mile sulfur (32.06g), and four moles oxygen (64.00g) combine to form one mole of sodium surface (142.04g).

Consider the hypothetical chemical reaction represented by the equation 3 A + 2 B → A 3B 2 Which of the following is a correct interpretation of this equation? i. 3 grams of A react with 2 grams of B to form 1 gram of A 3B 2 ii. 3 atoms of A react with 2 atoms of B to form 1 molecule of A 3B 2 iii. 3 moles of A react with 2 moles of B to form 1 mole of A 3B 2

Answers

Answer:

iii. 3 moles of A react with 2 moles of B to form 1 mole of A 3B 2

Explanation:

A + 2 B → A 3B 2

A chemical equation among other things, gives the stoichiometry of the reaction; that is the relationship between reactants and products.

This relationship is basically stated in moles form the coefficients of the reactants and product.

From the reaction above, we can say;

1 mol of A reacts with 2 mol of B to form 1 mol of A3B2

It cannot be grams because the reactants and products all have different molar masses.

The correct interpretation of the equation of the hypothetical chemical reaction is; Choice (iii) 3 moles of A react with 2 moles of B to form 1 mole of A 3B 2.

Definition:

Chemical equations are equations that make use of chemical formulae and symbols to represent chemical reactions. The left-hand side of a chemical equation represents the reactants and the right-hand side represents the products.

Each reacting entity is also assigned its corresponding stoichiometric coefficient.

However, this stoichiometric coefficient is to quantify the no. of moles of the reactants consumed or products formed as the case may be.

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