what is the molar volume of ch4 gas under the conditions of temperature and pressure where its density is 0.674 g/l?

Answer:

Heterogeneous mixture

Explanation:

A heterogeneous mixture is a mixture of two or more chemical substances (elements or compounds), where the different components can be visually distinguished and easily separated by physical means. Examples include: mixtures of sand and water. mixtures of sand and iron filings.

Answer:

B. P (Phosphorus)

Explanation:

The element is be phosphorus.

This is true because phosphorus has a larger atomic radius than carbon. If you move than the group, elements gain additional electron shell. That additional electron shell keeps electrons far from the nucleus of the atom. This actually increases the atomic radius. Also, phosphorus is more electronegative than aluminum because phosphorus itself is a non-metal and non-metals are generally electronegative while aluminum is a metal and electropositive.  

Phosphorus has a lower ionization energy than argon because the ionization energy across the period (i.e from left to right) increases and across period 3, you will find phosphorus first before argon in the periodic table.

ANSWER

The mass of water is 0.0536 kg

STEP-BY-STEP EXPLANATION;

Given information

The mass of KNO3 = 175g

The molarity of the solution = 32.25 M

The molality formula is given below as

The first step is to find the mole of the solute using the below formula

Recall, the molar mass of KNO3 is 101.1032 g/mol

The second step is to find the mass of water using the molality formula

Hence, the mass of water is 0.0536 kg

Answer:

if the colliding objects have unequal mass, they will have unequal accelerations as a result of the contact force that results during the collision.

Answer:

Mass = 0.008 g

Explanation:

Given data:

Volume of H₂ = 107 mL

Pressure = 104.8 KPa

Temperature = 30°C

Mass of H₂ present = ?

Solution:

Formula:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the units of temperature, pressure and volume.

Temperature  = 30+273 = 303 K

Volume of H₂ = 107 mL (107/1000= 0.107 L)

Pressure = 104.8 KPa (104.8/101 = 1.04 atm)

by putting values,

1.04 atm ×0.107 L = n× 0.0821 atm.L/ mol.K  × 303 K

0.11 atm.L  = n×24.87 atm.L/ mol

n =  0.11 atm.L / 24.87 atm.L/ mol

n = 0.004

Mass of H₂:

Mass = number of moles × molar mass

Mass =   0.004    mol × 2 g/mol

Mass = 0.008 g

Out of the given options, the empirical formula for a hydrocarbon is CH\(_{4}\). This is because the ratio of carbon to hydrogen atoms is 1:4, which is the smallest possible ratio for these elements in a hydrocarbon.

The empirical formula of a hydrocarbon is the simplest whole number ratio of carbon and hydrogen atoms in the molecule. In other words, it is the formula that shows the smallest possible ratio of the elements in the compound.

The other options, C\(_{4}\)H\(_{2}\), C\(_{3}\)H\(_{6}\), and C\(_{4}\)H\(_{10}\), are all molecular formulas, not empirical formulas. These formulas show the actual number of atoms of each element in the molecule, but they do not show the smallest possible ratio of the elements.

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Sample left = 6.25 g

The percentage = 6.25%

Given

t1/2 = half-life = 3.8 days

t = decay time = 15.2 days

No = initial sample = 100 g

Required

Nt = final sample left

The percentage

Solution

General formulas used in decay:  

\(\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}\)

Input the value :

\(\tt N_t=100.\dfrac{1}{2}^{15.2/3.8}\\\\N_t=100.\dfrac{1}{2}^4\\\\N_t=6.25~g\)

The percentage : Nt/No

6.25 : 100 = 6.25%

Answer:

I got u my boy It Ethanol

Explanation:

Light moves from a rare to a denser medium at a slower speed and shorter wavelength. As a result, when light enters water from the air, its wavelength is less in water than in air but its frequency remains the same.

The distance between two identical points (adjacent crests) in consecutive cycles of a waveform signal as it moves through space or over a wire is known as its wavelength.

The distance between two wave crests determines the wavelength, but a wave's trough has a constant wavelength. The term "frequency" refers to the number of vibrations that pass over a specific location in a second and is represented in cycles per second (Hz) (Hertz). We discuss how wavelength and frequency are related.

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The statement describe the transfer of heat is : the ice cubes gains the heat energy and the water looses the heat energy.

The law of mass of conservation mass states that mass neither be created or nor be destroyed. The law of mass of conservation energy states that the heat energy in the isolated system should de constant. if the one thing is loose the energy then the other in will gains the energy in an isolated system. according to the conditions the ice cube is at lower energy .

Thus the ice cube will gains the the heat energy that the water looses the heat energy.

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Perceived control over a stressful event typically results in a. less reported stress.

When an individual believes they have control over a situation, they tend to feel more empowered and confident in their ability to manage or resolve the stressor. This perception of control allows them to develop effective coping strategies and focus on problem-solving rather than being overwhelmed by the stress. Consequently, this sense of control often leads to a reduction in overall stress levels.

Contrary to options b, c, and d, perceived control does not typically lead to more frustration, less motivation to solve the problem, or increased arousal. Instead, having a sense of control often allows individuals to approach the stressful event in a more positive and proactive manner, ultimately reducing the negative impact of the stressor on their mental and emotional well-being. Thus, fostering a sense of control over stressful events can be a crucial factor in managing stress effectively. So therefore the correct answer is a. less reported stress.

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The term rate of reaction, RR, refers to the speed at which the reactants of a chemical reaction are turned into products. A) RR = 0.0047 M/s; B) RR = 0.0038 M/s; C) 0.0019 M/s.

When talking about the rate of reaction we refer to the speed at which a chemical reaction occurs, turning reactants into products.

It can be measured as

The formula to calculate the rate of reaction is the following,

RR = Δ concentration / Δ Time

Where,

In the exposed example, the chemical reaction is

                              NO₂(g) → NO(g) + 12 O₂(g)

So the rate of reaction can be measured according to

Since the collected data was the concentration of NO₂ as a function of time, then the rate of reaction was measured as the speed at which NO₂ was consumed.

A. What is the average rate of the reaction between 10 and 20 s?

Available data

RR = Δ concentration / Δ Time

RR = (0.951 - 0.904) / 20 - 10

RR = 0.074 / 10

RR = 0.0047 M/s

B. What is the average rate of the reaction between 50 and 60 s?

Available data

RR = Δ concentration / Δ Time

RR = (0.778 - 0.740) / 60 - 50

RR = 0.038 / 10

RR = 0.0038 M/s

C. What is the rate of formation of O₂ between 50 and 60 s?

Now, since NO₂ turns into NO and O₂, then

                  RR = Rate of NO₂ consumed = 2x rate of O₂ produced

If RR between 50 and 60 s is 0.0038 M/s, then the rate of formation of O₂ is,

Rate of NO₂ consumed / 2 =  rate of O₂ produced

0.0038 M/s / 2 = rate of O₂ produced

0.0019 M/s = rate of O₂ produced

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Compact fluorescent (CFL) bulbs compared to incandescent bulbs can offer a greater efficiency of lighting by utilizing less electricity. CFL bulbs usually last longer than incandescent bulbs. how CFL bulbs compare to incandescent bulbs is that CFL bulbs are more energy-efficient, last longer, and generate less heat than incandescent bulbs.

CFL bulbs can provide up to 75% energy savings compared to incandescent bulbs. It is because CFL bulbs use less energy to produce the same amount of light.                                                                                                                           how CFL bulbs compare to incandescent bulbs may be: Compact fluorescent bulbs (CFLs) and incandescent bulbs are two types of bulbs that have distinct features and characteristics. CFL bulbs and incandescent bulbs are compared based on their wattage, lifespan, environmental impact, and energy efficiency. When compared to incandescent bulbs, CFL bulbs can be considered to have better energy efficiency. CFL bulbs are considered to be four times more efficient than incandescent bulbs, consuming only 25% of the electricity required for the same amount of light. As a result, CFL bulbs can provide up to 75% energy savings compared to incandescent bulbs. It is because CFL bulbs use less energy to produce the same amount of light. CFL bulbs usually last longer than incandescent bulbs, meaning that they need to be replaced less frequently. CFL bulbs have a lifespan of 6,000 to 15,000 hours, while incandescent bulbs have a lifespan of about 1,000 hours. Due to their long-lasting nature, CFL bulbs are an environmentally friendly option because they reduce the amount of waste generated by light bulbs. CFL bulbs also generate less heat than incandescent bulbs. CFL bulbs are cooler than incandescent bulbs because they release less heat.

Furthermore, the heat generated by incandescent bulbs can cause issues, particularly in confined spaces or areas where the heat is unwanted. In contrast, CFL bulbs produce little heat, making them an excellent alternative for regions where temperature control is crucial. In conclusion, compared to incandescent bulbs, CFL bulbs are more energy-efficient, last longer, and generate less heat.

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Polonium - 212 when goes through alpha radiation or alpha emission it gives isotope lead - 206 has atomic number 82.

Isotopes are members of a family of an element that all have the exactly same number of protons but they contain different numbers of neutrons in there structure. The number of protons in a nucleus verify  the element's atomic number of the molecule.

Elements having same atomic number but they are differ in mass number are called as isotopes . There are many isotopes present in periodic table. Atomic number is denoted by Z while mass number is denoted by M.

for example ; Carbon have different isotope i.e. C₁₂,C₁₃,C₁₄

Thus , lead - 206 which having atomic number 82 is isotope remains after the decay of alpha radiation of polonium - 212.

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Answer:

all u need to do is this 27 + 30 = 57.

Explanation:

Answer:

Isotopes are forms of a chemical element that have the same atomic number but differ in mass. 16O → 8 protons + 8 neutrons; a “light” oxygen); The relative amounts are expressed as either 18O/16O or δ 18O Oxygen - 18 (aka 18O → 8 protons + 10 neutrons; a “heavy” oxygen).

The molecules of gases and liquids are present far apart from each other. In other words, they have more gaps or intermolecular spaces. Due to the large intermolecular forces, the intermolecular attractions are very less and thus liquids and gases can flow.

An instant cold pack takes advantage of an endothermic dissolution process.

Instant cold packs typically consist of two compartments containing separate substances, usually water and ammonium nitrate or urea. When the pack is activated by breaking a barrier between the compartments, the substances mix, leading to dissolution. The dissolution of ammonium nitrate or urea in water is an endothermic process, meaning it absorbs heat from the surroundings, resulting in a decrease in temperature. This temperature decrease causes the pack to become cold, providing a cooling effect. By utilizing an endothermic dissolution process, the instant cold pack can rapidly lower the temperature for therapeutic or comfort purposes.

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Answer:

I believe wood wood melt it faster. Why, because of how compact it is. It would be warmer. Metal would be a cooler temperature.

Explanation:

The product of the hydration reaction of 2-butene is 2-butanol.The H+ from the water attach to one double bonded carbon and the OH group attaches to the second double bonded carbon atom as shown in the image.

Alkenes are unsaturated hydrocarbons with one or more double bonds between carbon atoms. They are highly reactive due to the electron deficient center.

When alkenes are treated with water, according to rule of Markonikoves, H+ will attach at the most substituted double bonded carbon and OH with least substituted one.

Here in 2- butene it is a symmetric alkene hence both double bonded carbon are singly occupied by one hydrogen. Then , the major product is 2- butanol.

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Answer:

\(V \alpha \frac{1}{P}\)

Explanation:

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

This implies that, if the volume of a gas is halved, its pressure is doubled and vice versa.

This is mathematically represented as; \(V \alpha \frac{1}{P}\) hence \(PV = K\). This is the mathematical statement of Boyle's law.

The rate of the reaction when the fumarate concentration is 1.2 mM and the amount of enzyme is 100 micrograms is approximately 0.975 mmol-min-1 per mg enzyme.

The rate of the reaction can be calculated using the Michaelis-Menten equation:

\(V = (Vm * [S]) / (Km + [S])\)
Where:
V is the rate of the reaction
Vm is the maximum velocity (2.6 mmol-min-1 per mg enzyme)
[S] is the substrate concentration (1.2 mM)
Km is the Michaelis constant (2.0 mM)

By substituting the values into the equation, we can find the rate of the reaction:

V = (2.6 mmol-min-1 per mg enzyme * 1.2 mM) / (2.0 mM + 1.2 mM)
V = (3.12 mmol-min-1 per mg enzyme) / (3.2 mM)
V ≈ 0.975 mmol-min-1 per mg enzyme

Therefore, the rate of the reaction when the fumarate concentration is 1.2 mM and the amount of enzyme is 100 micrograms is approximately 0.975 mmol-min-1 per mg enzyme.

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Answer:

7

Explanation:

Answer:

The metal with the highest melting point is tungsten, which has a melting point of about 3,410 degrees Celsius (6,170 degrees Fahrenheit). Tungsten is known for its high melting point and excellent resistance to wear and corrosion, which makes it a useful material in many industrial applications.

Other metals with high melting points include osmium (3,060 degrees Celsius), rhenium (3,180 degrees Celsius), and tantalum (2,996 degrees Celsius). These metals are also known for their excellent resistance to wear and corrosion, and are used in a variety of industrial and technical applications.

It is worth noting that the melting point of a metal can depend on the purity and crystalline structure of the sample, and can vary slightly from one sample to another. However, tungsten is generally considered to have the highest melting point of any pure metal.

The pH of the solution after 21.4 mL of NaOH has been added is 3.75.

HCOOH (formic acid) is a weak acid, so we can use the Henderson-Hasselbalch equation to calculate the pH of the solution at any point during the titration.

The Henderson-Hasselbalch equation is:

pH = pKa + log([A-]/[HA])

where;

At the beginning of the titration, before any NaOH has been added, the solution contains only HCOOH and its conjugate base, HCOO-.

The concentration of HCOOH is 0.125 M, and the concentration of HCOO- is 0.

We can calculate the pH using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

pH = -log(1.8 x 10⁻⁴) + log(0/0.125)

pH = 2.74

At the equivalence point, all of the HCOOH has been converted to HCOO- by the addition of NaOH, so the pH will be determined by the concentration of the resulting salt. Since HCOO- is the conjugate base of a weak acid, it will undergo hydrolysis to a small extent, producing OH- ions and raising the pH.

However, we are not at the equivalence point yet.

To find the pH after 21.4 ml of NaOH has been added, we need to first calculate how many moles of NaOH have been added. We know the concentration of the NaOH solution (0.175 M) and the volume that has been added (21.4 mL = 0.0214 L), so we can calculate the number of moles of NaOH:

moles NaOH = concentration x volume

moles NaOH = 0.175 M x 0.0214 L

moles NaOH = 0.003745

Since NaOH reacts with HCOOH in a 1:1 ratio, we know that 0.003745 moles of HCOOH have been neutralized.

This means that there are 0.125 - 0.003745 = 0.121255 moles of HCOOH remaining in the solution.

We also know that 21.4 mL of NaOH has been added to 30.00 mL of HCOOH, so the total volume of the solution is now 51.4 mL.

We can use the moles of HCOOH and the total volume to calculate the concentration of HCOOH:

concentration = moles/volume

concentration = 0.121255/0.0514

concentration = 2.357 M

We can use this concentration and the concentration of the conjugate base (which is equal to the number of moles of NaOH added divided by the total volume) to calculate the pH using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

pH = -log(1.8 x 10⁻⁴) + log(0.003745/2.357)

pH = 3.75

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The complete question is below:

a 30.00-ml sample of 0.125 m hcooh is being titrated with 0.175 m naoh. what is the ph after 21.4 ml of naoh has been added? ka of hcooh is 1.8 x 10⁻⁴

The molarity when .772 moles are dissolved in .500 Liters of water is 0.0015M. The molarity when .453 moles are dissolved in .450 Liters of water is 0.001M.

The term molarity is defined as the number of moles of solute dissolved in per litre of solution. The unit of molarity is mole, which is denoted by the symbol "M".

M = Number of moles of solute / litre in solution

1. Number of moles of solute = .772 moles

so, 0.772 / 500

= 0.0015 M

2. Number of moles of solute =  .453 moles

so, .453 / 450

= 0.001 M

Thus, The molarity when .772 moles are dissolved in .500 Liters of water is 0.0015M. The molarity when .453 moles are dissolved in .450 Liters of water is 0.001M.

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Answer:

A thermodynamic quantity equivalent to the capacity of a system to do work.

Explanation:

Nitrogen=21.1999%

Hydrogen=6.1023%

Sulfur=24.2660%

The percent composition of nitrogen, hydrogen, sulfur , oxygen in ammonium sulfate is 21.18%, 6.05%,24.21%,48.43% respectively.

The percent composition  is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.It helps in elemental analysis of a given compound by giving proportions in which they are present.

Percent composition of N= 28/132.14×100=21.18%

Percent composition of H=8/132.14×100=6.05%

Percent composition of S=32/132.14×100=24.21%

Percent composition of O=64/132.14×100=48.43%.

Thus, the percent composition of nitrogen, hydrogen, sulfur , oxygen in ammonium sulfate is 21.18%, 6.05%,24.21%,48.43% respectively.

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Answer:

9

Explanation:

Given parameters:

    what is  b² - 4ac  of

 Equation x² - 5x + 4 = 0

Solution:

    x² - 5x + 4 in the form ax + bx + c = 0

  a is the coefficient of x²  = 1

                                      b = -5

                                      c = 4

Input the parameters and solve;

   b² - 4ac = -5² - 4(1)(4)

                 = 25 - 16

                  = 9