What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution?
A)0.17M

B)17.1M

C)0.085M

D)8.5M

Answer:

The Bohr model shows the atom as a central nucleus containing protons and neutrons with the electrons in circular orbitals at specific distances from the nucleus (Figure 1). These orbits form electron shells or energy levels, which are a way of visualizing the number of electrons in the various shells

Answer:

If you ask for water and water immediately appears that very second, this is an example of something instantaneous.

There are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

Calculation ,

Given ; Current ( I ) = 5. 68 A

In \(Fe(NO_{3} )_{2}\) , the valancy of Fe is +2 .

2 moles of \(e^{-}\) are required for the decomposition of 1 mole of Fe .

7. 20 g  of Fe in moles  = 7. 20 g /55.845 g/mol =0.12 mole

x moles of  \(e^{-}\) are required for the decomposition of 0.128 mole of Fe .

moles of   \(e^{-}\) are required = 0.256 moles

Charge on 1 mole  of   \(e^{-}\) = 96500 C

Charge on 0.256  mole  of   \(e^{-}\) = 24704 C

Current ( I )= Q/t  

t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr

Therefore , there are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

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The stronger the acid the weaker the conjugate base  is the correct statement is a) True.

The Strong acids have a weak conjugate base. The example of this is as follows :

The HCl is the  strong acid. If HCl is a strong acid, means it will donate hydrogen ions . The HCl will be a  good proton donor, only if the Cl⁻ ion will be a poor proton acceptor. That means the Cl⁻ ion will be a weak base. The chemical equation is as follows :

HCl        +      H₂O        ⇄         H₃O⁺     +         Cl⁻

strong        strong                  weak                weak

acid             base                 conjugate          conjugate

                                                  acid                 base

This question is incomplete, the complete question is :

The stronger the acid the weaker the conjugate base, this statement is :

a) True

b) False  

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Answer:

a) 0.06 mol K₂(CO₃) and 0.07 mol Al(NO₃)₃

b) The limiting reactant is K₂CO₃

c) 0.03 moles of Al₂(CO₃)₃

Explanation:

The balanced reaction between K₂CO₃ and Al(NO₃)₃ is the following:

3 K₂CO₃ + 2 Al(NO₃)₃ → Al₂(CO₃)₃ + 6 KNO₃

(a) We can calculate the moles for each reactant as the product of the molarity (M) and the volume (V) in liters.

K₂(CO₃): M = 2.4 mol/L , V = 25 mL x 1 L/1000 mL = 0.025 L

⇒ moles K₂(CO₃) = M x V = 2.4 mol/L x 0.025 L = 0.06 mol K₂(CO₃)

Al(NO₃)₃: M = 2.0 mol/L , V = 35 mL x 1 L/1000 mL = 0.035 L

⇒ moles Al(NO₃)₃ = M x V = 2.0 mol/L x 0.035 L = 0.07 mol Al(NO₃)₃

(b) According to the balanced equation, the stoichiometric ratio is 3 moles K₂CO₃/2 moles Al(NO₃)₃. We have 0.07 moles of Al(NO₃)₃, so we multiply the moles of Al(NO₃)₃ by the stiochiometric ratio to calculate how many moles of K₂CO₃ are needed:

0.07 mol Al(NO₃)₃ x 3 mol K₂CO₃/2 mol Al(NO₃)₃ = 0.105 moles of K₂CO₃

We need 0.105 moles of K₂CO₃ but we have only 0.06 moles of K₂CO₃. Therefore, the limiting reactant is K₂CO₃.

(c) We use the limiting reactant to calculate how many moles of product (Al₂(CO₃)₃) are formed. According to the equation, 2 moles of K₂CO₃ produce 1 mol of Al₂(CO₃)₃, thus the stoichiometric ratio is 1 mol Al₂(CO₃)₃/2 moles K₂CO₃. We have 0.06 moles of K₂CO₃, so the number of moles of Al₂(CO₃)₃ will be:

0.06 moles K₂CO₃ x 1 mol Al₂(CO₃)₃/2 moles K₂CO₃ = 0.03 moles of Al₂(CO₃)₃

No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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The chemist should add 2588 mL of water to prepare the 0.200 M aqueous solution with 30.2 g of NaCl.

To determine the volume of water needed to prepare the solution, we can use the formula:

mass of solute (g) / molar mass of solute (g/mol) = number of moles of solute

Then, we can use the formula for molarity to find the volume of water needed:

Molarity (M) = number of moles of solute / volume of solution (L)

Given that;

The mass of NaCl = 30.2 g.

Since its molar mass is 58.44 g/mol.

Hence;

30.2 g / 58.44 g/mol = 0.5176 mol of NaCl

Now, to prepare an aqueous solution with a concentration of 0.200 M, we need to determine the volume of solution needed. The formula for molarity can be rearranged to solve for volume:

Volume of solution (L) = number of moles of solute / Molarity (M)

Volume of solution = 0.5176 mol / 0.200 mol/L = 2.588 L

Therefore, we need 2.588 L of solution. Since the density of the solution is assumed to be the same as water, we know that 1 mL of water has a mass of 1 g, and the volume of water needed is:

2.588 L × 1000 mL/L = 2588 mL

Therefore, the total volume required by the chemist is 2588 mL.

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Answer: it is 15

Explanation: i've done it before

Answer:

Explanation:

Using Intersecting Chords Theorem,

AB × CB = BE × BD

The two Archaeal replication initiator proteins that are thought to be the same as in eukaryotes are Cdc6/Cdt1 and Orc1.

In Archaea, Cdc6 (Cell Division Cycle 6) and Cdt1 (Chromatin licensing and DNA replication factor 1) are involved in the initiation of DNA replication, functioning similarly to their eukaryotic counterparts. They both help in the recruitment and assembly of the replicative helicase onto the origin of replication.

Similarly, Orc1 (Origin Recognition Complex 1) is a crucial protein in both Archaea and eukaryotes for recognizing and binding to the origin of replication. In eukaryotes, the ORC complex consists of six subunits (Orc1-6), whereas in Archaea, it is simplified and usually represented by a single Orc1 protein or a few homologs.

Both Cdc6/Cdt1 and Orc1 proteins in Archaea exhibit homology and functional similarity with their eukaryotic counterparts, supporting the idea of a conserved mechanism in the initiation of DNA replication across these domains of life.

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Answer:

CH3COOH is Acetic acid.

Answer:

An environment is a local area of living creatures existing related to the nonliving segments of their current circumstance, interfacing as a framework. These biotic and abiotic segments are connected together through supplement cycles and energy streams.

Explanation:

Answer:

Living organisms require a proper, stable ecosystem/envirornment to function

Explanation:

Answer:

a. The gluing together of any two atoms that don't have full outer shells.

b. The separation of electrons from the main atom.

c. The joining of atoms by a shared interested of valence electrons which ends up

creating new substances.

d. The melting of substances to form new solids.

Explanation:

a. The gluing together of any two atoms that don't have full outer shells refers to chemical bonding, which can occur through different mechanisms such as covalent bonding, ionic bonding, and metallic bonding.

b. The separation of electrons from the main atom refers to ionization, where an atom or molecule loses or gains one or more electrons and becomes charged.

c. The joining of atoms by a shared interest of valence electrons which ends up creating new substances refers to covalent bonding, where atoms share electrons to form a stable molecule.

d. The melting of substances to form new solids does not necessarily create new substances; it is a physical change where a solid is transformed into a liquid due to an increase in temperature. Upon cooling, the liquid may solidify again, either forming the original substance or a different solid phase.

If this atom has one additional neutron but the other subatomic particles remained the same as shown, this slightly different atom would be called an isotope.

An isotope is a variant of an atom that has a different number of neutrons. Because isotopes of the same element have the same number of protons in the nucleus, they all have the same atomic number. However, they can differ in mass number, and therefore in atomic mass. In a neutral atom, the number of protons in the nucleus equals the number of electrons that orbit the nucleus, giving the atom a net electrical charge of zero.

However, the number of neutrons in the nucleus can differ, implying that isotopes of the same element may have different atomic masses.

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Answer:

the answer is diamond and graphite

Answer: The enthalpy of the reaction is -1791.31 kJ.

Explanation:

Enthalpy change is the difference between the enthalpies of products and the enthalpies of reactants each multiplied by its stoichiometric coefficients. It is represented by the symbol \(Delta H^o_{rxn}\)

\(\Delta H^o_{rxn}=\sum (n \times \Delta H^o_{products})-\sum (n \times \Delta H^o_{reactants})\)        .....(1)

For the given chemical reaction:

\(3MnO_2(s)+4Al(s)\rightarrow 2Al_2O_3(s)+3Mn(s)\)

The expression for the enthalpy change of the reaction will be:

\(\Delta H^o_{rxn}=[(2 \times \Delta H^o_f_{(Al_2O_3(s))}) + (3 \times \Delta H^o_f_{(Mn(s))})] - [(3 \times  \Delta H^o_f_{(MnO_2(s))}) + (4 \times \Delta H^o_f_{(Al(s))})]\)

Taking the standard heat of formation values:

\(\Delta H^o_f_{(Al_2O_3(s))}=-1675.7kJ/mol\\\Delta H^o_f_{(Al(s))}=0kJ/mol\\\Delta H^o_f_{(MnO_2(s))}=-520.03kJ/mol\\\Delta H^o_f_{(Mn(s))}=0kJ/mol\)

Plugging values in the above expression:

\(\Delta H^o_{rxn}=[(2 \times (-1675.7))+(3 \times 0)] - [(3 \times (-520.03))+(4 \times 0)]\\\\\Delta H^o_{rxn}=-1791.31 kJ\)

Hence, the enthalpy of the reaction is -1791.31 kJ.

In the design of a new baby diaper, the manufacturer uses two polymers. The polymer that is best suited to the outside of the diaper is polymer I and to the inside is polymer II

Polymers are large molecules made by bonding (chemically linking) a series of building blocks or smaller units called monomers. The word polymer comes from the Greek words for “many parts.”

Polymers don’t have a definite length. They usually don’t form crystals, either. Finally, they usually don’t have a definite melting point

Monomers used to create polymer I is a dicarboxylic acid and for polymer II is an alkene.

They undergo addition polymerization.

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Answer:

c

Explanation:

In science, there is always processing of an item or sample to get an end product. So if the diamond is mined; there is a processing stage used to come out with the final product as Diamond through carbon in the heating process

Answer:

d

Explanation:

The correct answer is option D: all of the above.

Environmental science is a multidisciplinary field of study that encompasses; physical science, biological sciences, social sciences and even aspects of the humanities.

Social sciences like anthropology have a lot of bearing on environmental science.

Physics, chemistry, biology and earth sciences play a key role in understanding important aspects of the natural environment.

Therefore; Physics, chemistry, biology and earth sciences and social sciences are all relevant in environmental science.

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Explanation:

Since we are asked to round all answers to three decimal places, we will use the rounded values in our calculations.

To find the probability for each case, we need to calculate the length of the interval divided by the length of the total range.

1. The probability that the number will be exactly 18 is 0. Since the number is continuous, the probability of selecting a single value is zero.

2. The probability that the number will be between 18 and 20, inclusive, is (20 - 18.3) / (24.3 - 16.3) = 1.7 / 8 = 0.212.

3. The probability that the number will be between 18 and 20, exclusive, is (20 - 18) / (24.3 - 16.3) = 2 / 8 = 0.250.

4. The probability that the number will be less than 18 or greater than 20 is ((16.3 - 18) + (24.3 - 20)) / (24.3 - 16.3) = (-1.7 + 4.3) / 8 = 2.6 / 8 = 0.325.

5. The probability that the number will be less than 20 or greater than 18 is ((16.3 - 18.3) + (24.3 - 20)) / (24.3 - 16.3) = (-2 + 4.3) / 8 = 2.3 / 8 = 0.288.

Therefore, the probabilities are as follows:

- The probability that the number will be exactly 18 is 0.

- The probability that the number will be between 18 and 20, inclusive, is 0.212.

- The probability that the number will be between 18 and 20, exclusive, is 0.250.

- The probability that the number will be less than 18 or greater than 20 is 0.325.

- The probability that the number will be less than 20 or greater than 18 is 0.288.

Answer:

The total energy reaction would be -698 kJ/mol.

Explanation:

The formula to calculate the enthalpy change of a reaction is the following:

Let's calculate the bond energy for each reactant:

- CH4: As we have 4 bonds of H - C, the bond energy is 4 x 412 kJ/mol = 1648 kJ/mol.

- O2: As we have 1 bond of O = O, but we have 2 moles of O2, we just multiply the bond energy of O = O by two: 2 x 496 kJ/mol = 992 kJ/mol.

Now, let's calculate the bond energy for each product:

- CO2: As we have 2 bonds of C - O (O - C - O), the bond energy would be 2 x 743 kJ/mol = 1486 kJ/mol.

- H2O: As we have 2 bonds of O - H (O - H - O), and 2 moles of H2O, we multiply the bond energy by the number of bonds, and the number of moles: 2 x 2 x 463 kJ/mol = 1852 kJ/mol.

Finally, we just apply the given formula, like this:

The total energy reaction would be -698 kJ/mol.

The most likely result of an accidental spill of copper compounds in an aquatic environment is that the growth of algae and other aquatic plants would be controlled by copper.

Copper interferes with photosynthesis in these organisms, which means that it prevents them from producing energy from the sunlight. This can lead to a reduction in the amount of oxygen produced by aquatic plants, which can affect the overall health of the ecosystem.

Copper is toxic to aquatic organisms, so it can cause harm to fish, invertebrates, and other aquatic life forms that are exposed to it. It can also accumulate in sediments and other organic matter, where it can persist for long periods of time. This can lead to the bioaccumulation of copper in the food chain, which can cause further harm to higher trophic levels.

Overall, an accidental spill of copper compounds in an aquatic environment can have significant impacts on the ecosystem and can take a long time to recover from.

Therefore, it is important to use copper compounds responsibly and carefully and to take appropriate measures to prevent accidental spills and leaks.

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Answer:When a substance undergoes a chemical change some of the chemical changes can be reversed with a chemical change.

Explanation:

A chemical change changes all of the element but some chemical changes but very few can be changed back to its original substance only with a chemical change.

Answer:

MgO.

Explanation:

charges of both satisfy one another (balanced) -- producing a compound MgO.

Answer: 1.45M

Explanation:

The definition of molarity is moles/liter.  The neutralization of NaOH with HI is:

HI + NaOH = NaI  + H2O

One mole of HI reacts with 1 mole of NaOH.  We'll assume this is a titration reaction and that the 10.00ml sample of NaOH contains the same number of moles as the 56.75ml of 0.256M HI.

Moles HI:  (0.256 moles/liter)*(0.05675 L) = 0.01453 moles HI

That means we muct have 0.01453 moles NaOH in 10.0ml of NaOH solution.

(0.01453 moles NaOH)/(0.010L) = 1.45 M

==

Another approach is to use the relationship M1V1 = M2V2, which is useful for titrations (M is concentration and V is volume):

We want M2, so rearrange:  M2 = M1V1/V2

M2 = (0.256M)*(56.75ml)/(10.0ml)

M2 = 1.45M

Answer:

26.3 mol O₂

Explanation:

Step 1: Write the balanced equation

4 FeCl₃ + 3 O₂ ⇒ 2 Fe₂O₃ + 6 Cl₂

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of FeCl₃ to O₂ is 4:3.

Step 3: Calculate how many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

We will use the previously established molar ratio.

35.0 mol FeCl₃ × 3 mol O₂/4 mol FeCl₃ = 26.3 mol O₂

The condensed ground-state electron configuration of the transition metal ion \(Mn^{2+}\) is [Ar] \(3d^{5}\)

The electronic configuration of an element is the symbolic notation of the manner in which the electrons of its atoms are distributed in the periodic table over different atomic orbitals. While writing electron configurations, standardized rules are followed in which the energy level and the type of orbital are generally written first, followed by the number of electrons present in the orbital which is written in superscript.

In case of Manganese atomic number of the atom is 25. When we follow Aufbau principle the electronic configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{5}\) if we have to write it in a compact form we can write as [Ar]\(3d^{5}4s^{2}\). In case of \(Mn^{2+}\) we have to remove electron from the higher most orbital that is 4s so now the electronic configuration will be become [Ar]\(3d^{5}\).

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Answer:

False

Explanation:

It is not correct to assert that a chemical change has occurred if the number of atoms is greater after the reaction than it was before the reaction.

For every chemical reaction, the law of conservation of mass must be strictly adhered.

The law states that "during a chemical reaction, matter is neither created nor destroyed, atoms are simply rearranged".

By the virtue of this law, the number of atoms at the beginning and the end of the reaction must remain the same for this law to be applicable.